Is it possible to have ""too much"" security in a network design? What are some trade-offs between ""too much"" and ""too little""?
Answers
Yes, it is possible to have "too much" security in a network design. While security is essential for protecting sensitive data and preventing unauthorized access, an excessive focus on security can lead to certain trade-offs and challenges. Here are some trade-offs between having "too much" security and "too little" security:
1. Usability and Productivity: Implementing stringent security measures can sometimes hinder usability and productivity. Excessive security controls, such as complex authentication processes or frequent password changes, may create inconvenience and slow down users' ability to perform their tasks efficiently.
2. Cost: Enhanced security often requires additional investments in terms of hardware, software, and maintenance. Organizations need to strike a balance between the level of security required and the cost implications. Allocating excessive resources to security may strain the budget, impacting other important areas of the network design.
3. Complexity: Implementing numerous security measures can increase the complexity of the network design. This complexity can make it harder to manage and troubleshoot the network infrastructure. It may also introduce potential vulnerabilities due to misconfigurations or difficulties in keeping up with security patches and updates.
4. User Experience: Excessive security measures can negatively impact the user experience. For example, frequent authentication prompts or excessive restrictions on accessing resources may frustrate users and lead to circumvention of security measures, potentially compromising the network's integrity.
5. Interoperability: Introducing excessive security measures may hinder interoperability with external systems or partners. In certain cases, security protocols or configurations may conflict with those of other organizations, making it difficult to establish connections or share information securely.
6. False Sense of Security: Paradoxically, having "too much" security can lead to a false sense of security. Organizations may believe that they are adequately protected due to the extensive security measures in place, but these measures may not effectively address all potential risks or vulnerabilities.
It is important to find the right balance between security and usability, considering factors such as the sensitivity of the data, the risk profile of the organization, and the specific requirements of the network design. A comprehensive risk assessment and security analysis can help identify the appropriate level of security measures without unnecessarily impeding productivity or incurring excessive costs.
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Related Questions
What is not a condition under which the malfunction indicator light or service engine light is turned off ?
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The malfunction indicator light or service engine light is not switched off when the Powertrain Control Module Link is grounded.
A power-train control module (PCM), sometimes known as a control unit, is a motor vehicle component. The engine control unit (ECU) and transmission control unit are typically combined into one controller (TCU). On some vehicles, including many Chryslers, there are three different computers: the PCM, the TCU, and the Body Control Module (BCM). In general, these car computers are very dependable. In a car or truck, the PCM frequently regulates more than 100 variables. There are hundreds of different error codes that may appear and signify that a specific component of the car isn't working properly. The "check engine" light on the dashboard typically illuminates when one of these errors occurs.
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Which level of the economy would be most directly impacted by a music festival?
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Answer:
local. It is a very popular
Calculate the steady state flux of atomic hydrogen at 25°C through a steel vessel of wall thickness 4 mm given that the inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, the outside surface is exposed to the atmosphere. (The diffusivity of hydrogen in steel D0 = 0.1 mm2 s-1, Q = 13.5 kJ mol-1) A steady-state flux allows the application of Fick’s first law: J = -D(dC/dx)
If the vessel contains 20 moles of hydrogen, calculate the time taken to dissipate all of the hydrogen of that the vessel has a surface area of 3 m2.
Answers
Answer:
To calculate the steady state flux of atomic hydrogen through a steel vessel, we need to use Fick's first law, which states that the flux (J) is equal to the diffusivity (D) multiplied by the concentration gradient (dC/dx).
First, we need to calculate the concentration gradient by dividing the difference in hydrogen concentration between the inside and outside surfaces by the wall thickness of the vessel. The inside surface is kept saturated with hydrogen at a concentration of 4.5 moles/m3, and the outside surface is exposed to the atmosphere, which has a hydrogen concentration of 0 moles/m3. Therefore, the concentration gradient is (4.5 - 0) moles/m3 / (4 mm) = 1.125 moles/m3 mm.
Next, we need to substitute this value into Fick's first law along with the diffusivity of hydrogen in steel, which is given as 0.1 mm2/s. This gives us the steady state flux as J = (-0.1 mm2/s) * (1.125 moles/m3 mm) = -0.01125 moles/s mm2.
Finally, we need to convert the units of the flux from moles/s mm2 to moles/s m2. To do this, we can multiply the flux by 1,000 to convert the units of millimeters to meters, giving us a final steady state flux of -0.01125 moles/s mm2 * 1,000 = -1.125 moles/s m2.
IF THE VESSEL CONTAINS 20 MOLES OF HYDROGEN, CALCULATE THE TIME TAKEN TO DISSIPATE ALL OF THE HYDROGEN OF THAT THE VESSEL HAS A SURFACE AREA OF 3 M2.
To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:
J = -D(dC/dx)
where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.
Given that the diffusivity of hydrogen in steel is 0.1 mm2/s, the inside concentration is 4.5 moles/m3, and the outside concentration is 0, the concentration gradient is 4.5 moles/m3.
Plugging these values into the equation above, we get:
J = -0.1 mm2/s * 4.5 moles/m3 = -0.45 moles/s-m2
Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:
t = 20 moles / (-0.45 moles/s-m2) = 44.44 s
So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.
Explanation:
SELF EXPLANATORY
The time taken is 44.44 seconds to dissipate all of the hydrogens from the vessel.
How to calculate the time?To solve this problem, we need to first calculate the flux of atomic hydrogen through the vessel using Fick's first law:
J = -D(dC/dx)
where J is the flux, D is the diffusivity of hydrogen in steel, and dC/dx is the concentration gradient.
Given that the diffusivity of hydrogen in steel is 0.1 mm²/s, the inside concentration is 4.5 moles/m³ and the outside concentration is 0, the concentration gradient is 4.5 moles/m³.
Plugging these values into the equation above, we get:
J = -0.1 mm²/s * 4.5 moles/m³ = -0.45 moles/s-m²
Next, we need to calculate the time it takes to dissipate all 20 moles of hydrogen from the vessel. We can do this by dividing the total number of moles of hydrogen by the flux:
t = 20 moles / (-0.45 moles/s-m2) = 44.44 s
So it would take approximately 44.44 seconds to dissipate all of the hydrogen from the vessel.
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An electrical current of 700 A flows through a stainlesssteel cable having a diameter of 5 mm and an electricalresistance of 6104/m (i.e., per meter of cablelength). The cable is in an environment having a tem-perature of 30C, and the total coefficient associatedwith convection and radiation between the cable andthe environment is approximately 25 W/m2K.(a) If the cable is bare, what is its surface temperature
Answers
Answer:
778.4°C
Explanation:
I = 700
R = 6x10⁻⁴
we first calculate the rate of heat that is being transferred by the current
q = I²R
q = 700²(6x10⁻⁴)
= 490000x0.0006
= 294 W/M
we calculate the surface temperature
Ts = T∞ + \(\frac{q}{h\pi Di}\)
Ts = \(30+\frac{294}{25*\frac{22}{7}*\frac{5}{1000} }\)
\(Ts=30+\frac{294}{0.3928} \\\)
\(Ts =30+748.4\\Ts = 778.4\)
The surface temperature is therefore 778.4°C if the cable is bare
current attempt in progress a counterflow heat exchanger operates with the flow rates and temperatures as shown. the maximum amount of heat transfer would occur if the hot fluid were cooled to the cold fluid inlet temperature, and the cold fluid were heated to the hot fluid inlet temperature. the cold fluid were heated to the hot fluid inlet temperature. the hot fluid were cooled to the cold fluid inlet temperature. etextbook and media save for laterattempts: 0 of 2 usedsubmit answer
Answers
Although in practice this is very challenging to achieve, the cold fluid can exit the heat exchanger at a temperature higher than the temperature of the hot fluid outlet.
What are the types of heat transfer?There are numerous ways to transmit heat, including evaporative cooling, thermal radiation, convection, and conduction.
Heat transfer is any or all of a variety of processes that are thought to function as mechanisms to move energy and entropy from one place to another. Common names for the specific mechanisms include convection, heat radiation, and conduction (see thermal conduction).
Every time there is a temperature difference between states of matter, heat transfer takes place. Heat transfer only happens in the direction of decreasing temperature, or from a hot object to a cold item.
Conduction of heat through solids, convection of liquids and gases, and electromagnetic waves.
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As an R & D engineer you are assigned by your supervisor to conduct a laboratory testing which involve designing a circuit using multiplexer to be implemented as two bit adder. The conditions are to add two bit number to produce sum, assuming no input carry, ignore end carry and inverted input is available. Unfortunately there are only two multiplexer available. Can you do the design? If yes show details of your work. Score Truth Table-7 pts Simplification K-Map/Implemetation Table- 6pts Logic Circuit
Answers
Therefore, we can design the circuit using two 2:1 multiplexers as a two-bit adder under the given conditions.
Yes, I can design the circuit using the given conditions. Here are the details of the work:
Truth Table:
Let's use A and B as inputs, S as sum, and C as the carry. The truth table is given below:
A B S C0 0 0 00 1 1 00 1 0 11 0 1 01 1 0 1
Simplification K-Map/Implementation Table
:From the truth table, we can get the following equations:
S = A'BC' + AB'C + ABC' + ABC = AB + AC + BC'
Implementation table is given below:
AB C S000010011001101111
Logic Circuit:
We can use the two available 2:1 multiplexers to implement the circuit. Here is the logic circuit diagram:
Therefore, we can design the circuit using two 2:1 multiplexers as a two-bit adder under the given conditions.
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2. determine the average power dissipated by the circuit if vi(t) = 200 sin(5000t)
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The average power dissipated by a circuit can be determined by finding the average value of the instantaneous power over a complete cycle of the input waveform. Given vi(t) = 200 sin(5000t), the average power can be calculated using the formula Pavg = (Vrms^2)/R, where Vrms is the root mean square value of the voltage and R is the resistance in the circuit.
To determine the average power dissipated by the circuit, we need to find the average value of the instantaneous power over a complete cycle of the input waveform. The instantaneous power is given by the product of the instantaneous voltage (vi(t)) and the instantaneous current (i(t)) flowing through the circuit. Since the voltage waveform is vi(t) = 200 sin(5000t), the current waveform will depend on the circuit elements and their relationship with the voltage.
To calculate the average power, we use the formula Pavg = (Vrms^2)/R, where Vrms is the root mean square value of the voltage and R is the resistance in the circuit. In this case, since the voltage waveform is sinusoidal, we can determine the Vrms value as the peak value (200) divided by the square root of 2 (approximately 1.414).
However, to calculate the exact average power, we need additional information about the circuit configuration, such as the presence of resistors, capacitors, or inductors, and their values. With this information, we can determine the current waveform and calculate the average power dissipated by the circuit using the appropriate formulas for power calculations based on the circuit elements present.
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Imagine that you are given a large budget and a team of competent sysadmins/devops engineers. Your boss has requested that you develop a plan to deploy the company's latest web application in their on-site datacenter. You have the freedom to recommend servers, extra components (RAM, HDDs, SSDs, network cards, etc), and additional hardware purchases as needed. The primary goal is to design the overall system so that it can provide high levels of uptime even in the presence of minor maintenance (OS reboots, HDD hot-swaps) or major issues (motherboard failures, network card failure, power outages). Write a ½ page report (12pt font, double spaced, 1" margins) that provides your recommendations for creating a robust deployment which can attempt to mitigate the various failures that were mentioned. It's perfectly fine to discuss software architecture choices along with your suggested hardware design considerations.
Answers
One can write the report under the title Deploying a Robust Web Application in an On-Site Datacenter by Design.
This report's recommendations for deploying the most recent web application of the business in the local datacenter are intended to guarantee high levels of uptime and reduce potential failures.
We can create a strong system that can resist both routine maintenance and significant problems while sustaining uninterrupted service if we have a sizable budget and a skilled staff of sysadmins and devops engineers.
We can develop a reliable deployment for the company's web application in the on-site datacenter by putting the suggested hardware and software design considerations into practise.
Thus, hardware failures will be less damaging because to redundant servers, RAID storage, network redundancy, and power backup systems.
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Write a Python program named DataByteConvert that asks the user to enter a Data in
MegaBytes (MB) Data is entered only in MegaBytes. The program will then present the
following menu of selections:
1. Convert to Bytes
2. Convert to KiloBytes (KB)
3. Convert to GigaBytes(GB)
4. Convert to TerraBytes(TB)
5. Quit the program
The program will convert the data in MegaBytes(MB) to bytes, kilobytes(KB), GigaBytes(MB),
or TerraBytes(TB), depending on the user's selection rounded to six decimals. Here are the
specific requirements:
• Write a void method named showKiloBytes, which accepts the number of
MegaBytes(MB) as an argument. The method should display the argument
converted to kilobytes(KB). Convert the MB to KB.
• Write a void method named showGigaBytes, which accepts the number of
MegaBytes(MB) as an argument. The method should display the argument
converted to Gigabytes(GB).
• Write a void method named show TerraBytes, which accepts the number of
MegaBytes(MB) as an argument. The method should display the argument
converted to TerraBytes(TB). Convert the MB to TB.
• Write a void method named showBytes, which accepts the number of MegaBytes
(MB) as an argument. The method should display the argument converted to
Bytes(B). Convert the MB to B
• Write a void method named menu that displays the menu of selections. This
method should not accept any arguments.
1. The program should continue to display the menu until the user enters 5 to quit the
program.
2. The program should not accept negative numbers for the data in MegaBytes.
3. If the user selects an invalid choice from the menu, the program should display an error
message.
4. Use Exponential format if needed when converted {:e) formats ...)
5. Use
6. Add comments to show what each function does.
Answers
The program to convert MegaBytes to either Bytes, KiloBytes, GigaBytes, or TeraBytes is found in the attached image.
The program defines five helper functions to help the program do its work. The functions are:
showBytes: Accepts an argument in megabytes, converts it by multiplying by 1048576, and prints the resultshowKiloBytes: Accepts an argument in megabytes, converts it by multiplying by 1024, and prints the resultshowGigaBytes: Accepts an argument in megabytes, converts it by dividing by 1024, and prints the resultshowTeraBytes: Accepts an argument in megabytes, converts it by dividing by 1048576, and prints the resultmenu: Displays the menu of options to either convert or quit the programWithin the Main Program, a while loop is used to make sure the menu continues to be presented to the user until the user selects the option to quit.
The inner while loop makes sure the user enters an option within the menu.
Once the user enters an option to convert, the program requests the value to be be converted, in MegaBytes. then an if statement selects the correct conversion function.
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Identify the following example as a fragment or a run-on. Then, rewrite the sentence(s), correcting the error.
John and Mary just broke up so you will not be seeing them together this afternoon.
Answers
All of these are true about aluminum EXCEPT that it:
A) has a self-healing, corrosion-resistant coating,
B) is resistant to galvanic corrosion
C) is a nonferrous metal,
D) is easy to be initially formed,
Answers
The option which is not a property of the metal aluminium is; Option B; is resistant to galvanic corrosion
What are the properties of aluminum metal?Aluminum is a non - ferrous metal that is lightweight, durable, malleable and corrosion-resistant (not galvanic) which is widely used for components in the transportation and construction industries. Its's properties includes;
Non-corrosive.Easily machined and cast.Lightweight yet durable.Non-magnetic and non-sparking.Good heat and electrical conductor.From all the listed properties and explanations, it is clear that the only option among those given that is not a property of aluminum is Option B
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Both copper and stainless steel are being considered as a wall material for a liquid cooled rocket nozzle. The cooled exterior of the wall is maintained at 150°C, while the combustion gases within the nozzle are at 2750°C. The gas side heat transfer coefficient is known to be hᵢ = 2×10⁴ W/m²-K, and the radius of the nozzle is much larger than the wall thickness. Thermal limitations dictate that the temperature of copper must not exceed 540°C, while that of the steel must not exceed 980°C. What is the maximum wall thickness that could be employed for each of the two materials? For Cu, ρ = 8933 kg/m³, k = 378 W/m-K and for stainless steel, ρ = 7900 kg/m³, k = 23.2 W/m-K
Answers
a. The maximum thickness of the copper nozzle is 3.3 mm
b. The maximum thickness of the steel nozzle is 0.054 mm
The question has to do with heat transfer
What is heat transfer?Heat transfer is the movement of heat energy from one body to anotrher.
How to calculate the maximum wall thickness?Since the rate of heat loss by the gas equal rate of heat gain by the metal.
Rate of heat loss by gasThe rate of heat loss by gas is P = -hA(T - T') where
h = heat transfer coefficient of gas = 2 × 10⁴ W/m²-K, A = surface area of nozzle, T = maximum temperature of metal and T = Temperature of gas = 2750°CRate of heat gain by metalThe rate of heat gain by metal is given by P' = kA(T - T")/t where
k = thermal coefficient of metal, A = surface area of nozzle, T = maximum temperature of metal, T" = temperature of exterior wall of nozzle = 150°C and t = thickness of nozzle. Maximum thickness of nozzle.Since P = P', we have that
-hA(T - T') = kA(T - T")/t
Making t subject of the formula, we have
t = -k(T - T")/h(T - T')
a. Maximum thickness for copper nozzleGiven that for copper
T = 540°C and k = 378 W/m-KSubstituting the values of the variables into t, we have
t = -k(T - T")/h(T - T')
t = -378 W/m-K(540°C - 150°C)/[2 × 10⁴ W/m²-K(540°C - 2750°C)]
t = -378 W/m-K(390°C)/[2 × 10⁴ W/m²-K(-2210°C)]
t = 147420 W/m/4420 × 10⁴ W/m²
t = 147420 W/m/44200000 W/m²
t = 0.0033 m
t = 3.3 mm
So, the maximum thickness of the copper nozzle is 10.71 cm
b. Maximum thickness for steel nozzleGiven that for steel
T = 980°C and k = 23.2 W/m-KSubstituting the values of the variables into t, we have
t = -k(T - T")/h(T - T')
t = -23.2 W/m-K(980°C - 150°C)/[2 × 10⁴ W/m²-K(980°C - 2750°C)]
t = -23.2 W/m-K(830°C)/[2 × 10⁴ W/m²-K(-1770°C)]
t = 19256 W/m/3540 × 10⁴ W/m²
t = 19256 W/m/35400000 W/m²
t = 0.0000544 m
t = 0.0544 mm
t ≅ 0.054 mm
So, the maximum thickness of the steel nozzle is 0.054 mm
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Example 2: a second class highway, slope change point survey point k2+360.00, elevation is 780m, i+=+6%,
i2=-4%, the radius of vertical curve is 2500m.
(1) calculate geometric element of vertical curve.
(2) design elevation for k2+300.00 and k2+400.
Answers
As per the details given, the design elevation for k2+300.00 is approximately 942.29 m and for k2+400.00 is approximately 941.84 m.
To calculate the geometric elements of the vertical curve, we'll use the given information:
(1) Geometric Elements of Vertical Curve:
(a) Elevation at the PVC (Point of Vertical Curvature):
Elevation at PVC (E_PVC) = Elevation at k2+360.00 = 780 m
(b) Elevation at the PVI
Elevation at PVI (E_PVI) = Elevation at PVC + (R * i1/100)
E_PVI = 780 + (2500 * 6/100)
E_PVI = 930 m
(c) Elevation at the PVT:
Elevation at PVT (E_PVT) = Elevation at PVI + (R * (i2 - i1)/100)
E_PVT = 930 + (2500 * (-4 - 6)/100)
E_PVT = 730 m
(2) Design Elevation for k2+300.00 and k2+400.00:
Elevation (E) = E_PVI + [(\(R^2\) / 2) * ((1 / X) - (1 / (L - X)))] + [(i1 / 100) * X * (L - X)]
(a) Design Elevation for k2+300.00:
Distance from PVI to k2+300.00 = 300.00 - 360.00 = -60.00 m
Elevation at k2+300.00:
E = E_PVI + [(\(R^2\) / 2) * ((1 / X) - (1 / (L - X)))] + [(i1 / 100) * X * (L - X)]
E = 930 + [(\(2500^2\) / 2) * ((1 / -60) - (1 / (2500 - (-60))))] + [(6 / 100) * (-60) * (2500 - (-60))]
E ≈ 942.29 m
(b) Design Elevation for k2+400.00:
Distance from PVI to k2+400.00 = 400.00 - 360.00 = 40.00 m
Elevation at k2+400.00:
E = E_PVI + [(\(R^2\) / 2) * ((1 / X) - (1 / (L - X)))] + [(i1 / 100) * X * (L - X)]
E = 930 + [(\(2500^2\) / 2) * ((1 / 40) - (1 / (2500 - 40)))] + [(6 / 100) * 40 * (2500 - 40)]
E ≈ 941.84 m
Therefore, the design elevation for k2+300.00 is approximately 942.29 m and for k2+400.00 is approximately 941.84 m.
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Q-) please give me a reference about Tack coat? Pleae i need it please??!!
Answers
Answer:
Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.
Explanation:
Prove that in a 2’s complement number system addition overflows if and only if the carry from the sign position does not equal the carry into the sign position. Consider the three cases: adding two positive numbers, adding two negative numbers, and adding two numbers of opposite sign.
Answers
Consider the four sub-cases for each of those three cases two positives, two negatives, one of each . Show that some of those sub-cases are not possible in each case. Then examine each sub-case to see if it indicates overflow.
What is 2's complement system?Two's complement is a mathematical operation that converts a positive binary number with equivalent value reversibly into a negative binary number with equivalent value.
it occurs using the binary digit with the greatest place value to indicate whether the binary number is positive or negative.
Consider each of those three cases' four sub-cases. There are two positives and two negatives, with one of each.
Demonstrate that some of the sub-cases are not feasible in each case. Then, for each sub-case, determine whether it indicates overflow.
Thus, by this it can be proved that in a 2’s complement number system addition overflows if and only if the carry from the sign position does not equal the carry into the sign position.
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What does efficiency measure?
Answers
Answer:
Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.
Explanation:
What is the maximum number of outgoing flows a merge can have?A. OneB. TwoC. NoneD. Unlimited
Answers
It is correct to state that within the context of computer science, th e maximum number of outgoing flows a merge can have is Two (Option B)
What are outgoing flows in Computer Science?Outgoing flows in computer science refer to the flow of data or control from a specific node in a system or process to other nodes or systems.
It refers to the movement of data or control signals out of a specific component or module and towards other components or modules within the same system or to other systems. Outgoing flows are a fundamental aspect of many computer systems and processes and are used to control and coordinate the actions of different components and systems.
They help to ensure that data and control signals are transmitted between different components of a system in an efficient and controlled manner.
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Cite another example of information technology companies pushing the boundaries of privacy issues; apologizing, and then pushing again once scandal dies down. As long as the controversy fades, is there anything unethical about such a strategy?
Answers
Answer:
Explanation:
Tech Social Media giant FB is one of those companies. Not long ago the ceo was brought to court to accusations that his company was selling user data. Turns out this is true and they are selling their users private data to companies all over the word. Once the news turned to something else, people focused on something new but the company still continues to sell it's users data the same as before. This is completely unethical as the information belongs to the user and they are not getting anything while the corporation is profiting.
this is it dont anwser this is for my other account
Answers
Answer:
thanks for the poiunts
Explanation:
If Scheduler is designed to allow a process to run 7 milliseconds, what should be maximum Scheduler execution time (Tsc)?
0.5 milliseconds
1.3 milliseconds
07 milliseconds
0.9 miltseconds
Answers
If Scheduler is designed to allow a process to run 7 milliseconds, the maximum Scheduler execution time (Tsc) should be 0.5 milliseconds.
A scheduler is a component of an operating system (OS) that determines the execution priority of processes. It enables processes to use resources fairly, which is crucial in a multitasking environment where processes share resources (such as a CPU).
A scheduling algorithm is a mechanism for deciding which process to execute next after a process has finished or paused. The time needed for the system to determine which process to run next is referred to as scheduler overhead. In general, the scheduler overhead should be as short as possible.
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Alex loves to build things and wants to study robotics. He needs to get a job over the summer but the only one he can find is at a fast food restaurant. Does taking the job mean that Alex cannot pursue a career in robotics? Explain your answer.
Answers
Answer:
He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.
A _______________________________ system utilizes a carbon canister that is connected to both the engine vacuum line and the air space in the fuel tank. The carbon canister collects fuel vapors from the fuel tank during storage and operation. When the engine is operating, intake vacuum draws the fuel vapors from the carbon canister into the engine intake system and the engine consumes them.
Answers
An evaporative emissions control fuel system utilizes a carbon canister that is connected to both the engine vacuum line and the air space in the fuel tank.
What emission is gas?
Nitrous oxide, methane, and carbon dioxide are released when natural gas and petroleum products are burned for cooking and heating (N2O). In the residential and commercial sectors in 2020, emissions from the use of natural gas account for 79% of the direct emissions from fossil fuels. Because it lessens the effects of global climate change, enhances public health, strengthens the world economy, and preserves biodiversity, lowering your carbon footprint is crucial. By reducing carbon emissions, we contribute to the protection of future generations' access to healthier food, water, and air. Using renewable energy sources and other environmentally friendly energy sources to generate electricity on-site can minimize greenhouse gas emissions.To learn more about emissions refer to:
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You're servicing an SUV with a lift-kit and custom running boards and your adapters don't quite reach the lifting points. It's okay to use wood blocks to get the clearance you need.
Answers
This is a true or false question.
It is TRUE to state that when you're servicing an SUV with a lift-kit and custom running boards and your adapters don't quite reach the lifting points, that It's okay to use wood blocks to get the clearance you need.
This however is subject to the vehicle manufacturers recommended lift points. Following Manufacturer's instructions ensures the safety of the vehicle/lift-kit user.
What is a lift-kit?A lift kit is a method of raising the body of a vehicle to provide additional space between the body and the axles.
The vehicle is usually a truck or SUV. Lift kits are classified as leveling kits, body lift kits, or suspension lift kits.
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Some full-time 4WD sedans use a front engine and transaxle, with a drive shaft connected to drive the rear wheels.
Select one:
True
O False
Answers
Answer:true
Explanation:
All of the following are properties of a refrigerant EXCEPT:
A. It has a super low boiling point.
B. It changes its state without breaking down.
C. It vaporizes and condenses at the correct temperature and pressure.
D. Its pressure remains unchanged during the cooling cycle.
Answers
The option that is not a property of refrigerants is;
D: Its pressure remains unchanged during the cooling cycle.
Properties of Refrigerants
A refrigerant is defined as a working fluid that is used in the refrigeration cycle of air conditioning systems and heat pumps.
Now, there are a couple of desirable properties of refrigerants and they are;
They must have low boiling Point.They must have high critical Temperature.They must have high latent heat of vaporization.Low specific heat of liquid.Low specific volume of vapor.Non-corrosive to metal.Non-flammable.Non-explosive.Non-toxicLow costEasy to liquify at moderate pressure and temperatureEasy to locating leaks by odour or suitable indicatorMixes well with oil.Lokking at the given options, the only one that is not a property of a refrigerant is that Its pressure remains unchanged during the cooling cycle.
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A shell-and tube heat exchanger (two shells, four tube passes) is used to heat 10,000 kg/h of pressurized water from 35 to 120 oC with 5000 kg/h pressurized water entering the exchanger at 300 oC. If the overall heat transfer coefficient is 1500 W/m^2-K, determine the required heat exchanger area.
Answers
Answer:
4.75m^2
Explanation:
Given:-
- Temperature of hot fluid at inlet: \(T_h_i = 300\) °C
- Temperature of cold fluid at outlet: \(T_c_o = 120\) °C
- Temperature of cold fluid at inlet: \(T_c_i = 35\) °C
- The overall heat transfer coefficient: U = 1500 W / m^2 K
- The flow rate of cold fluid: m_c = 10,00 kg/ h
- The flow rate of hot fluid: m_h = 5,000 kg/h
Solution:-
- We will evaluate water properties at median temperatures of each fluid using table A-4.
Cold fluid: Tci = 35°C , Tco = 35°C
Tcm = 77.5 °C ≈ 350 K --- > \(C_p_c = 4195 \frac{J}{kg.K}\)
Hot fluid: Thi = 300°C , Tho = 150°C ( assumed )
Thm = 225 °C ≈ 500 K --- > \(C_p_h = 4660 \frac{J}{kg.K}\)
- We will use logarithmic - mean temperature rate equation as follows:
\(A_s = \frac{q}{U*dT_l_m}\)
Where,
A_s : The surface area of heat exchange
ΔT_lm: the logarithmic differential mean temperature
q: The rate of heat transfer
- Apply the energy balance on cold fluid as follows:
\(q = m_c * C_p_c * ( T_c_o - T_c_i )\\\\q = \frac{10,000}{3600} * 4195 * ( 120 - 35 )\\\\q = 9.905*10^5 W\)
- Similarly, apply the heat balance on hot fluid and evaluate the outlet temperature ( Tho ) :
\(T_h_o = T_h_i - \frac{q}{m_h * C_p_h} \\\\T_h_o = 300 - \frac{9.905*10^5}{\frac{5000}{3600} * 4660} \\\\T_h_o = 147 C\)
- We will use the experimental results of counter flow ( unmixed - unmixed ) plotted as figure ( Fig . 11.11 ) of the " The fundamentals to heat transfer" and determine the value of ( P , R , F ).
- So the relations from the figure 11.11 are:
\(P = \frac{T_c_o - T_c_i}{T_h_i - T_c_i} \\\\P = \frac{120 - 35}{300 - 35} \\\\P = 0.32\)
\(R = \frac{T_h_i - T_h_o}{T_c_o - T_c_i} \\\\R = \frac{300 - 147}{120 - 35} \\\\R = 1.8\)
Therefore, P = 0.32 , R = 1.8 ---- > F ≈ 0.97
- The log-mean temperature ( ΔT_lm - cf ) for counter-flow heat exchange can be determined from the relation:
\(dT_l_m = \frac{( T_h_i - T_c_o ) - ( T_h_o - T_c_i ) }{Ln ( \frac{( T_h_i - T_c_o )}{( T_h_o - T_c_i )} ) } \\\\dT_l_m = \frac{( 300 - 120 ) - ( 147 - 35 ) }{Ln ( \frac{( 300-120 )}{( 147-35)} ) } \\\\dT_l_m = 143.3 K\)
- The log - mean differential temperature for counter flow is multiplied by the factor of ( F ) to get the standardized value of log - mean differential temperature:
\(dT_l = F*dT_l_m = 0.97*143.3 = 139 K\)
- The required heat exchange area ( A_s ) can now be calculated:
\(A_s = \frac{9.905*10^5 }{1500*139} \\\\A_s = 4.75 m^2\)
A sleeve, spacer, or bumper ring is incorporated in a landing gear oleo shock strut to
A. limit the extension of the torque arm
B. limit the extension stroke
C. reduce the rebound effect
Answers
The correct answer is B. A sleeve, spacer, or bumper ring is incorporated in a landing gear oleo shock strut to limit the extension stroke.
A sleeve, spacer, or bumper ring is used in a landing gear oleo shock strut to limit the extension stroke. These components are designed to absorb and dissipate the energy during the extension phase of the landing gear's movement. By limiting the extension stroke, they help control the maximum extension length of the landing gear and prevent excessive extension that could potentially damage the aircraft or the landing gear system.
The purpose of the torque arm in a landing gear oleo shock strut is to transmit the forces and torques between the landing gear and the aircraft structure. It is not directly related to the use of a sleeve, spacer, or bumper ring.
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Can space debris take out a whole state
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what is a geometric parameter that, as a structural engineer, we can modify to reduce the bending stress for a given moment? explain your answer.
Answers
These transversal loads will result in a base shear V and a tension force M that both induce normal stress and shear stress, respectively.
What makes it a moment?It can seem like to use the term "a brief duration" in addition to referring to physical motion because the word minute appears to have Latin roots that signify movement, change, or alteration.
What unit of time is a moment?Units of due to the force distance are used to express the moment's size. The normal English measures for a momentary are feet pounds, but the standard unit units for moment magnitude are newton meters.
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Problem 3 The exothermic reaction of stillbene (A) to form the economically important trospophene (B) and methane (C), i. E. , A B+C was carried out adiabatically and the following data recorded: X 0 0. 2 0. 4 0. 45 0. 5 0. 6 0. 8 0. 9 -ra (mol/dm3-min) 1. 0 1. 67 5. 0 5. 0 5. 0 5. 0 1. 25 0. 91 The entering molar flow rate of A was 300 mol/min. Answer and draw the Levenspiel plots for the followings. (a) What are the PFR and CSTR volumes necessary to achieve 40% conversion? (VPFR 72 dm3, VCSTR = 24 dm3) (b) Over what range of conversions would the CSTR and PFR reactor volumes be identical? (c) What is the maximum conversion that can be achieved in a 105-dm3 CSTR?
(d) What conversion can be achieved if a 72-dm3 PFR is followed in series by a 24-dm CSTR? (e) What conversion can be achieved if a 24-dm3 CSTR is followed in a series by a 72-dm² PFR?
Answers
According to the proposed statement about the exothermic reaction of stillbene, we answer the questions:
a) The PFR volume necessary to achieve 40% conversion is 72 dm³, and the CSTR volume necessary to achieve 40% conversion is 24 dm³. This can be determined by using the Levenspiel plot and finding the intersection of the conversion line at 40% with the PFR and CSTR curves.
(b) The CSTR and PFR reactor volumes would be identical over the range of conversions from approximately 0.2 to 0.45. This can be determined by finding the intersection of the PFR and CSTR curves on the Levenspiel plot.
(c) The maximum conversion that can be achieved in a 105-dm³ CSTR is approximately 0.8. This can be determined by finding the intersection of the CSTR curve with the vertical line at 105 dm³ on the Levenspiel plot.
(d) The conversion that can be achieved if a 72-dm³ PFR is followed in series by a 24-dm³ CSTR is approximately 0.7. This can be determined by finding the intersection of the PFR curve with the vertical line at 72 dm³, then finding the intersection of the CSTR curve with the vertical line at 24 dm³, and finally finding the intersection of these two points on the conversion axis.
(e) The conversion that can be achieved if a 24-dm³ CSTR is followed in series by a 72-dm³ PFR is approximately 0.85. This can be determined by finding the intersection of the CSTR curve with the vertical line at 24 dm³, then finding the intersection of the PFR curve with the vertical line at 72 dm³, and finally finding the intersection of these two points on the conversion axis.
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