Is atomic spectrum of hydrogen due to the ionization of hydrogen molecules?

Answer: Referring to a solution that does not completely disassociate, the conductivity would be low.

Explanation: Ions that are completely disassociated conduct better than ions that still are connected by bonds.

The kind of conductivity that would you expect insoluble compounds have is very poor or low. Due to this, these compounds do not dissociate to any appreciable extent.

Conductivity is measured through the utilization of salinity measurement. This measurement most frequently determines the parts per thousand or grams per liter.

A Siemen is also referred to as its smaller equivalents, the milli-Siemen, and the micro-Siemen, which are each one-millionth of a Siemen, is a unit used to determine the conductivity of any given solution.

Some solutions like NaCl, HCl, NaOH, etc have high electrical conductivity because they readily dissociate into their ions. While insoluble compounds do not have this capability to dissociation, so they generally have low or poor electrical conductivity.

Therefore, insoluble compounds generally have low or poor electrical conductivity.

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Answer:

78,300 cals.

Explanation:

540 cals of heat reqd to convert1 gm of water at 100 deg C so 540 x 145 = 78,300 cals.

Answer:

The answer is 78,300 calories.

540 calories of heat are required to transform one gram of water at 100 degrees Celsius, so 540 x 145 = 78,300 cal

Explanation:

Brainliest pls:)

Answer:

Elements?

Explanation:

Im not sure but I think its elements because carbon dioxide is, and the others sound like it too

The maximum wavelength of light capable of dissosciating i-i bond in one molecule of iodine is 0.77m.

The energy needed to break a bond and create two atomic or molecular fragments, each containing one of the original shared pair of electrons, is known as the bond dissociation energy.

The energy required to break one i-i bond = bond energy per mol/ avagudro's number.

= 119.255x 10^3/ 6.023 x 10^23 J

Let the wavelength of the photon required to break one i-i bond be lambda .

Lambda = hc/E = 6.6x10^-34x3x10^8 x 6.023 x 10^23/ 153 x 10^3

=119.2554 x 10^-3/ 153 x10^3= 0.77 m

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The vibrational partition function (Q) for chlorine at 25°C, summing over the lowest 4 vibrational levels, is given by the simplified expression: Q = e^(-2.220).

The relative population between the first and second excited vibrational energy levels (N1/N2) of chlorine at 298 K (25°C) can be calculated using the relative Boltzmann factors, taking into account the energies of the levels and the Boltzmann constant.

The vibrational partition function (Q) represents the sum of the Boltzmann factors for all the vibrational energy levels. For a diatomic molecule like chlorine (Cl2), assuming equally spaced vibrational energy levels and a degeneracy (g) of 1 for each level, we can calculate the partition function.

To calculate Q, we sum over the lowest 4 vibrational levels, taking into account the energy spacing between levels.

The energy spacing between levels is given as 558 cm^(-1), which we convert to Joules using the conversion factor of 1 cm^(-1) = 1.986445 × 10^(-23) J.

Using the formula for the partition function:

Q = e^(-E1/(kT)) + e^(-E2/(kT)) + e^(-E3/(kT)) + e^(-E4/(kT))

Substituting the values:

Q = e^(-5581.98644510^(-23)/(1.3806510^(-23)(25+273)))

Simplifying the exponent and performing the calculations:

Q ≈ e^(-2.220)

Therefore, the vibrational partition function (Q) for chlorine at 25°C, summing over the lowest 4 vibrational levels, is approximately e^(-2.220).

The relative population between the first and second excited vibrational energy levels (N1/N2) of chlorine at 298 K (25°C) can be calculated using the relative Boltzmann factors, taking into account the energies of the levels and the Boltzmann constant.

The relative population (N1/N2) between two vibrational energy levels can be determined using the Boltzmann factors, which depend on the energies of the levels and the temperature.

The energy difference between the ground state and the first excited level is given as 558 cm^(-1), which we convert to Joules using the conversion factor of 1 cm^(-1) = 1.986445 × 10^(-23) J.

Using the Boltzmann factor formula:

N1/N2 = e^(-ΔE/(k*T))

Substituting the values:

N1/N2 = e^(-5581.98644510^(-23)/(1.38065*10^(-23)*298))

Simplifying the exponent and performing the calculations:

N1/N2 ≈ e^(-1.524)

Therefore, the relative population between the first and second excited vibrational energy levels (N1/N2) of chlorine at 298 K (25°C) is approximately e^(-1.524).

Note: The relative population is given as a ratio of the populations between the two levels.

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Answer:

Hunds rule is violated here.

Hunds rule : pairing of electrons takes place only if all the orbitals are filled with single electrons each.

Answer:

Computer Models are used to study the complex phenomena in the universe.

Explanation:

The term 'models' can be defined as a representation of something that is real. A model is used to learn the phenomena of the natural world for easy understanding of it.

The computer models are used to study the large and complex data in the universe. These models are used to perform various calculations that, in real, would take years to do. It helps in studying the changes in variables, which in turn helps the scientist to know of any climatic change, or other changes in the nature.

Molecule A should have a higher melting point than Molecule B because it has more opportunities for intermolecular forces to occur due to its larger surface area and ability to participate in Van der Waals forces in addition to hydrogen bonding.

Both molecules have hydroxyl (-OH) groups, which are polar and capable of hydrogen bonding. However, the rest of the structures of the molecules are different. Molecule A has a long carbon chain, which means it has more surface area and more opportunities for Van der Waals forces to occur. Van der Waals forces are weaker than hydrogen bonding, but they can still contribute to the overall strength of the intermolecular forces.

Molecule B, on the other hand, has a cyclic structure, which means it has less surface area than Molecule A. In summary, the melting point of a molecule is dependent on the intermolecular forces between its molecules. In this case, Molecule A has a higher melting point than Molecule B due to its larger surface area and greater potential for intermolecular forces to occur.

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Answer:

\(\boxed {\tt 376.83 \ grams}\)

Explanation:

The density formula is

\(d=\frac{m}{v}\)

Rearrange the formula for mass, m, by multiplying both sides of the equation by v.

\(d*v=\frac{m}{v}*v\)

\(d*v=m\)

The mass can be found by multiplying density and volume.

The density of the sugar is 1.59 grams per milliliter. The volume is 237 milliliters.

\(d= 1.59 \ g/mL \\v= 237 \ mL\)

Substitute the values into the formula.

\(m= 1.59 \ g/mL * 237 \ mL\)

Multiply. Note that the milliliters, or mL will cancel each other out.

\(m=1.59 \ g * 237\)

\(m=376.83 \ g\)

The mass is 376.83 grams.

Answer:

The correct distance traveled by the train in 2 hours, if it travels at a speed of 100 km/h, would be 200 kilometers.

Explanation:

Answer:

traveled at a speed of 50mph

Explanation:

100/2 =50

Answer: 5 moles of NaF would be produced when 550 grams of Sodium bromide are used.

Explanation:

From the question, the balanced chemical formula is illustrated below:

2NaBr + CaF2 → 2NaF + CaBr2

From the equation above;

Molecular mass of NaBr = 23 + 80 = 103g/ mol

Molecular mass of CaF2= 40+ (19×2)= 78g/ mol

Molecular mass of NaF = 23+19 = 42g/ mol

From the balanced chemical equation;

2 moles of NaBr reacted with 1mole of CaF to give 2 moles of NaF.

That is, 2 moles of NaBr= 2× 103 = 206g

2moles of NaF = 2×42= 84g

If 206g of NaBr yielded 84g of NaF

Therefore 550g of NaBr will yield Xg of NaF

X= 550×84/206

X= 224.27g of NaF

But 42g = 1 mole of NaF

Therefore 224.27g = X mole of NaF

X= 224.27 ×1/42

X is approximately 5moles.

The concentration of NO3-N in mg/L = 10 mg/L.

The given water sample contains 10 mg NO3/L.

To find the concentration of NO3 in millimoles/L:

1 mg = 1/1000 g1 mole of NO3 contains 1 + 3x16 = 61 g NO3So, 1 g NO3 = 1/61 mole NO3

Thus, 10 mg NO3 contains (10/1000) * (1/61) mole of NO3= 0.000163934426 mole of NO3

Therefore, the concentration of NO3 in millimoles/L = 0.000163934426 * 1000= 0.163934426 millimoles/L

To find the concentration of NO3-N in mg/L:1 mole of NO3 contains 1 mole of N= 14 g N

Thus, 1 g NO3-N = 1/14 mole of NO3-N

Therefore, 10 mg NO3-N contains (10/1000) * (1/14) mole of NO3-N= 0.000714285714 mol of NO3-N

Therefore, the concentration of NO3-N in mg/L = 0.000714285714 * 14000= 10 mg/L.

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Hazardous gases are those that can cause harm to humans, animals, and the environment. Some of the most dangerous gases include carbon monoxide, sulfur dioxide, nitrogen oxides, and volatile organic compounds.

Gas Name of Gas Effects on Health Effects on the Environment Carbon Monoxide Colorless, odorless gas It can cause headaches, dizziness, nausea, vomiting, and even death in severe cases.

Air pollution, climate change Sulfur Dioxide A colorless gas with a pungent odor Irritation of the eyes, nose, throat, and respiratory system.

It can lead to bronchoconstriction, reduced lung function, and increased risk of respiratory infection.

Acid rain, soil and water pollution Nitrogen Oxides A group of gases including nitrogen monoxide, nitrogen dioxide, and nitrous oxide Respiratory problems, such as coughing, wheezing, and shortness of breath. It can also increase the risk of respiratory infections.

Acid rain, smog, ground-level ozone formationVolatile Organic Compounds (VOCs)A group of chemicals that includes benzene, formaldehyde, and toluene.

Headaches, nausea, and other health effects, including cancer. VOCs contribute to the formation of ozone in the lower atmosphere (troposphere), which can lead to respiratory problems and other health effects.

In conclusion, hazardous gases can have serious effects on human health and the environment.

It is important to take steps to reduce the emission of these gases, such as using clean energy sources, reducing the use of fossil fuels, and adopting environmentally friendly practices.

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Answer:

Explanation:

its b i did this i k its gonna be right

• The balanced equation for the reaction is given by:

• From the above reaction we can see that:

1 mole of ethanol (CH3Ch2OH) produces 1 mol of acetic acid(CH3COOH)

so . x mole of ethanol will produce 0.9mol of acetic acid ....(cross multiply)

xmol ethanol * 1mol acetic = 1mol ethamol* 0.9molacetic

∴ xmol ethanol = 1*0.9 /1

= 0.90 mol

• This means that, 0.90 mol of ethanol, is needed to produce 0.9mol acetic acid,.

The container has a volume of 0.0628 L.

To convert mL (milliliters) to L (liters), we need to divide by 1000 since 1 L is equivalent to 1000 mL.

Therefore, the volume of the container in liters can be calculated as follows:

Volume of container = Volume of water in mL / 1000

Volume of container = 62.8 / 1000

Volume of container = 0.0628 L

Therefore, the volume of the container is 0.0628 L.

It is important to note that when conducting experiments, it is essential to accurately measure the volume of the container as it directly impacts the results of the experiment.

In this case, knowing the volume of the container is crucial as it is one of the variables required for the experiment. Any error or imprecision in the measurement of the volume can lead to inaccurate results and potentially affect the outcome of the experiment.

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Answer: The container has a volume of 0.0628 L.

Explanation:

Answer:

one is across

Explanation:

Mass percentage is a term that represents the concentration, basically mass by mass percentage. It tells about the percentage of a component in a whole component. Thus, the mass percentage of water in given compound is 27.9%.

Mass percentage represents the the percentage of each element that is making a particular compound. Mass percentage does not have any unit as numerator and denominator contains the same unit.

Hydrated compound + Δ\(\rightarrow\) anhydrate compound +water

mass of hydrate compound =mass of anhydrate compound + mass of water

mass of hydrate compound=37.25 g

mass of anhydrate compound=26.81 g

37.25 g =26.81 g+ mass of water

mass of water=10.4g

Percentage of mass of water = (component’s mass ÷ total mass) x 100%

Percentage of mass of water = (10.4g ÷37.25 g) x 100%

                                                 =27.9%

Thus, the mass percentage of water in given compound is 27.9%.

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Answer:

oh no!! I can't do this ;(

Explanation:

oopsie "BrO" I can't do this pleaseee.

don't be selfish next time and maybe people will help you...

Answer:

Right if you think it is.

Answer: b. 14.2%

Explanation: I'm not sure if it's correct but I did it this way. Since we have a 25.0 gram of magnesium oxide by the name of it we should know that the 25.0 gram is composed of magnesium and oxygen. It tells us that we have 10.8 grams of magnesium. Therefore we can subtract 25.0- 10.8 = 14.2 so our answer would be 14.2% of oxygen.

Answer:

The theoretical yield of ammonia is 15 g.

Explanation:

The statements are:

2.8g of hydrogen are left over.

Hydrogen is the excess reactant.

Nitrogen is the limiting reactant.

The theoretical yield of ammonia is 15 g.

To solve this question we must find the moles of each reactant. Thus, we can find the limiting reactant. With limitinf reactant we can find the theoretical yield and the amount in excess of the reactant that is in excess:

Moles Nitrogen -28g/mol-

10.0g * (1mol / 28g) = 0.357 moles

Moles hydrogen -2g/mol-

5.0g * (1mol / 2g) = 2.5 moles

For a complete reaction of 0.357 moles of nitrogen are required:

0.357mol N2 * (3mol H2 / 1molN2) = 1.071 moles hydrogen.

As there are 2.5 moles of hydrogen, hydrogen is the excess reactant and nitrogen is the limiting reactant

The moles of hydrogen that are left over are:

2.5moles - 1.071moles = 1.429moles Hydrogen

The mass is:

1.429moles Hydrogen * (2g / mol) = 2.8g of hydrogen are left over

The moles of ammonia produced are:

0.357mol N2 * (2mol NH3 / 1molN2) = 0.714 moles of ammonia are produced (Theoretical moles)

The theoretical mass is (Molar mass NH3 = 17g/mol):

0.714 moles of ammonia * (17g / mol) =

12g of ammonia is the theoretical mass

The false statement is:

The false statement, when 10 g of nitrogen reacts with 5.0 g of hydrogen to produce ammonia is that the theoretical yield of ammonia is 15g.

Moles of any substance will be calculated as:

n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:
N₂(g) + 3 H₂(g) → 2 NH₃(g)

Moles of 10g of N₂ = 10/28 = 0.357 moles

Moles of 5g of H₂ = 5/2 = 2.5 moles

From the stoichiometry of the reaction:

1 mole of N₂ = react with 3 moles of H₂

0.357 moles of N₂ = react with 3×0.357=1.071 moles of H₂

Here nitrogen is the limiting reactant and hydrogen is excess reactant, and formation of ammonia depends on the limiting reactant.

1 mole of N₂ = react with 2 moles of NH₃

0.357 moles of N₂ = react with 2×0.357=0.714 moles of NH₃

Now we calculate the mass of ammonia from the given moles as:

M = (0.714) (17) = 12 g.

Hence, the false statement is that theoretical yield of ammonia is 15g.

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The correct setup for the equilibrium constant expression for this reaction is:
Kc = [Ag(NH3)2]Cl / [AgCl] x [NH3]2

The equilibrium constant, represented by Kc, is the ratio of the concentrations of products to the concentrations of reactants, all raised to the power of their coefficients in the balanced chemical equation. This equilibrium constant expression can be used to predict the direction of a chemical reaction in a solution.

The formation of silver diamine chloride from solid silver chloride and aqueous ammonia solution can be represented by the following balanced chemical equation:

AgCl(s) + 2NH3(aq) ⇌ [Ag(NH3)2]Cl(aq)

The correct setup for the equilibrium constant expression for this reaction is:

Kc = [Ag(NH3)2]Cl / [AgCl] x [NH3]2

where [Ag(NH3)2]Cl represents the concentration of silver diamine chloride in solution, [AgCl] represents the concentration of solid silver chloride, and [NH3] represents the concentration of aqueous ammonia. The coefficients in the balanced equation are used as exponents in the expression.

The value of the equilibrium constant provides information about the extent of the reaction at equilibrium. A value of Kc greater than 1 indicates that the products are favored at equilibrium, while a value less than 1 indicates that the reactants are favored. A value of Kc equal to 1 indicates that the reactants and products are present in roughly equal amounts at equilibrium.

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Answer:

the last one is the answer

The effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.

1. The class of drugs being investigated in this study is antidepressants. They enter our waterways through excretion by individuals taking the medication, and disposal of unused medication into toilets or sinks that are connected to wastewater treatment plants.

2. C-start is an evasive maneuver that young fish use when they perceive a predator. This is important for larval fish survival because it helps them to avoid being eaten by predators.

3. In this investigation, researchers are testing two hypotheses. The first is that exposure to low levels of antidepressants can affect larval fathead minnows' behavior, and the second is that the effects of exposure will be more pronounced in fish that have been raised in a less stressful environment.

4. The researchers found that exposure to antidepressants at levels found in waterways can have a significant impact on the behavior of larval fathead minnows. Specifically, they found that the fish exposed to antidepressants were less likely to respond to the presence of predators, which could increase their risk of being eaten.

They also found that the effects of exposure were more pronounced in fish that had been raised in a less stressful environment, suggesting that environmental conditions can influence the impact of exposure to antidepressants.

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The carbon–carbon bonds in naphthalene are not of the equal length. The bonds C₁–C₂, C₃–C₄, C₅–C₆ and C₇–C₈ are about 1.36 Å in length, whereas the other carbon–carbon bonds are about 1.42 Å long.

Naphthalene is two benzene rings joined together. It has three resonance structures. The double bonds present in the benzene ring are delocalized by intramolecular electron transfer to achieve stability. This is called resonance and these structures can be called resonance structures.

The C-C bond length in naphthalene is not the same. This is because naphthalene has a fused ring structure in which two benzene rings are fused. Single and double bonds are alternating, so the lengths of single and double bonds are different.

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Since water does not have charged particles, water is a non-conductor. When some solutes dissolve in water they allow an electric current to flow through the water and the solution conducts electricity. These solutes are called electrolytes. ... Non-electrolytes like sugar dissolve to form molecules in solution.

CaF₂ ⇒ Ca²⁺ + 2F⁻

1.75       1.75     3.5

Answer:

proteins carry out most of the life sustaining functions of the human body