Investigation of ions and Separation of Mixtures 1- Propose systematic schemes for the identification of the following salts with respect to their anions and cations: NaCl, KNO3, and CuSO4?​

Answers

Answer 1

The cations and anions can be identified using cataloged reactions schemes. For instance, the copper II ion can be identified by reaction with sodium hydroxide.

The sodium cation is easily identified by flame test. sodium imparts a yellow color to a flame. The chloride ion is identified by the use of a mixture of HNO3/AgNO3 solution. The color of the precipitate shows which halide ion is present. A white precipitate indicates the presence of the chloride ion.

The potassium cation is also identified by flame test. The ion imparts a lilac color to flame. Addition of acidified FeSO4 solution is used to confirm the presence of the nitrate ion. Formation of a brown ring is a positive test for the nitrate ion.

For CuSO4, the presence of copper II ion can be confirmed using dilute NaOH. If a light blue precipitate is formed which dissolves in excess NaOH then the copper II ion is confirmed. The presence of the sulfate ion is confirmed using a solution of barium nitrate and dilute nitric acid. Formation of a white precipitate is a positive test for the sulfate ion.

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Related Questions

84.9 g of solid iron reacts with oxygen gas forming iron(III) oxide. How many moles of oxygen will react

Answers

Answer:

1.14 moles of oxygen will react

Explanation:

The balanced equation of reaction between iron and oxygen is  

4 Fe + 3 O₂  → 2 Fe₂O₃

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Fe: 4 molesO₂: 3 molesFe₂O₃: 2 moles

The molar mass of iron being Fe 55.85 g/mole, then the following amount of mass reacts by stoichiometry: 4 moles* 55.85 g/mole=223.4 g

You can apply the following rule of three: if by stoichiometry 223.4 grams of Fe react with 3 moles of O₂, 84.9 grams of Fe react with how many moles of O₂?

\(moles of O_{2} =\frac{84.9 grams of Fe*3 moles ofO_{2} }{223.4 grams of Fe}\)

moles of O₂= 1.14 moles

1.14 moles of oxygen will react

Which of the following are considered to be
part of the study of chemistry?
SELECT ALL THAT APPLY
a
properties of matter
b changes to matter
C
interactions between living things
d composition of matter

Answers

Chemistry deals with elements and compounds. The properties of matter, changes to matter, and composition of matter are studied in chemistry. Thus, options a, b, and d are correct.

What is chemistry?

Chemistry is said to be a scientific field under natural sciences that studies the structure, properties, and composition of matter.  It includes atoms, elements, and compounds.

The chemistry includes topics like the properties of matter, including the volume, density, temperature, etc., changes to a matter involving condensation, freezing, vaporization, melting, etc.

The composition of matter including the sub-atomic levels is studied in chemistry. Whereas, the interactions between living things are studied in biology.

Therefore, options a, b, and d. the properties, changes, and composition are studied in chemistry.

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I need help with this, no links, *extra pints for effort!*



Approximately how long are fossil fuels going to last (at the present level of

consumption)?


A.) forever


B.) a century


C.) 10 years


D.) millenia

Answers

Fossil fuels are not going to last forever,  fossil fuels are not going to last forever, and their reserves are depleting rapidly. Therefore, it is crucial to shift towards renewable energy sources to ensure a sustainable future.

Explanation: Fossil fuels, including coal, oil, and natural gas, are non-renewable resources that are formed over millions of years from the remains of dead plants and animals. As they are being extracted and consumed at an alarming rate, they are depleting rapidly. Therefore, they are not going to last forever.

According to the World Energy Outlook 2020 report, at the present level of consumption, coal and natural gas reserves will last for approximately 150 years, and oil reserves will last for approximately 50 years. However, these estimates are subject to change due to several factors, including increasing demand, technological advancements, and geopolitical events.

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Which fronts are shown?

Which fronts are shown?

Answers

Answer:

the answer is D

Explanation:

In the reclassify transactions screen, which 3 elements of a transaction can be reclassified?

Answers

The 3 elements of a transaction that can be reclassified are:

Account, Location Class

On an account transaction screen, one can see there are different elements that exist and some of them are:

invoices, sales receipts, checks, or bills, etc

What is a Transaction?

This refers to the proof that exists that a person has bought a good or service and can also stand as an agreement.

Hence, we can see that On an account transaction screen, one can see there are different elements that exist and some of them are:

invoices, sales receipts, checks, or bills, etc

However, there are only 3 elements that can be reclassified on the  reclassify transactions screen and they are:

Account, Location Class

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When energy changes from one form to another (for example, chemica
energy - heat — light), it is know as:
Select one:
energy transfer
fossil fuel chang
light heat change
energy transformation

Answers

Answer:

energy transformation

Explanation:

energy transformation is when energy changes from one form to another. like in a hydroelectric dam that transforms the kinetic energy of water into electrical energy.

How do you separate alcohol and water ?

Answers

Answer:

liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.

Explanation:

hope this helps :3

Which orbital is portrayed on the right?

Which orbital is portrayed on the right?

Answers

A maximum of two electrons will be placed in 1s first. With a maximum of two electrons, 2s will then be filled. With a maximum of 6 electrons, 2p will then be filled.

What's the appearance of the p orbital?A maximum of two electrons will be placed in 1s first. With a maximum of two electrons, 2s will then be filled. With a maximum of 6 electrons, 2p will then be filled.A maximum of two electrons will be placed in 1s first. With a maximum of two electrons, 2s will then be filled. With a maximum of 6 electrons, 2p will then be filled.Each shell can only carry a certain amount of electrons: the first shell can hold two electrons, the second shell can hold eight electrons (2 + 6) and so on, the third shell can hold 18 electrons (2 + 6 + 10).        

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what, if any, conclusions can you draw about the phs of the different categories of common substances? a. ph of beverages

Answers

It is difficult to draw a conclusive statement about the pHs of different categories of common substances because the pH of a substance is dependent on its specific composition. However, it is possible to make generalizations about certain categories of substances.

The pH of beverages can vary widely depending on their composition. Some common beverages such as water, milk, and pure fruit juices tend to have a pH close to neutral (pH 7). Other beverages such as carbonated soft drinks, energy drinks, and sports drinks tend to be acidic (pH less than 7) due to the presence of acids such as citric acid, phosphoric acid, and carbonic acid. Alkaline water and some herbal teas may have a pH greater than 7.

For example, acidic beverages are substances often associated with a higher risk of dental erosion and may be more likely to cause stomach discomfort in some individuals. On the other hand, alkaline beverages may have potential health benefits, but further research is needed to fully understand their effects on the body.

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Elements in period 1 are

Answers

Answer:

Hydrogen - - helium..

...

Houston Company borrowed $20,000 from Dallas Company on March 1, Year 1. Houston is to repay the principal and interest on March 1, Year 2. The interest rate is 8%. If the year-end adjustment is properly recorded, what will be the effects of the accrual on Houston's Year 1 financial statements

Answers

The effects of the accrual on Houston's Year 1 financial statements is an increase in Interest Expense by $1,333.33 reducing the Net Income and an increase in Interest Payable by $1,333.33.

When Houston Company borrowed $20,000 from Dallas Company on March 1, Year 1, they agreed to repay the principal and interest on March 1, Year 2, at an interest rate of 8%. To determine the effects of the accrual on Houston's Year 1 financial statements, we need to calculate the interest expense for Year 1 and adjust the financial statements accordingly.

Interest expense = Principal x Interest rate x Time

Interest expense = $20,000 x 8% x (10/12)

Interest expense = $1,333.33

The year-end adjustment for the accrual of interest expense will affect Houston's Year 1 financial statements as follows:

1. An increase in Interest Expense by $1,333.33 in the Income Statement, reducing the Net Income.

2. An increase in Interest Payable (a liability account) by $1,333.33 in the Balance Sheet.

These adjustments ensure that the financial statements accurately reflect the interest expense incurred by Houston Company during Year 1, even though the payment will be made in Year 2.

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1. Take 2-3 crystals of potassium permanganate and dissolve them in 100 mL of water.
2. Take out approximately 10 mL of this solution and put it into 90 mL of clear water.
3. Take out 10 mL of this solution and put it into another 90 mL of clear water.
4. Keep diluting the solution like this 5 to 8 times.
5. Is the water still coloured?

Answers

Answer:

2

Explanation:

1. Take 2-3 crystals of potassium permanganate and dissolve them in 100 mL of water.

2. Take out approximately 10 mL of this solution and put it into 90 mL of clear water.

3. Take out 10 mL of this solution and put it into another 90 mL of clear water.

4. Keep diluting the solution like this 5 to 8 times.

5. Is the water still coloured?

What is the second life cycle stage during complete metamorphosis of insects?

O A) The eggs hatch into larvae.

OB) The eggs hatch into nymphs.

OC) Nymphs stop molting and are adult sized.

OD) Larvae make hard, protective cases around themselves during the pupal stage.​

Answers

Answer:

They hatch into larvae.

Explanation:

Compute the relative speed of diffusion of ethene (mm = 28.0 g/mol) to phosgene (mm = 98.9 g/mol):

Answers

The relative speed of diffusion of ethene to phosgene is approximately 1.878. The relative speed of diffusion can be calculated using Graham's law of diffusion, which states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass.

The formula for Graham's law is:

Rate1/Rate2 = √(MolarMass2/MolarMass1)

Given:

Molar mass of ethene (C2H4) = 28.0 g/mol

Molar mass of phosgene (COCl2) = 98.9 g/mol

Let's calculate the relative speed of diffusion:

Rate of ethene diffusion / Rate of phosgene diffusion = √(Molar mass of phosgene / Molar mass of ethene)

Rate of ethene diffusion / Rate of phosgene diffusion = √(98.9 g/mol / 28.0 g/mol)

Rate of ethene diffusion / Rate of phosgene diffusion = √(3.532)

Rate of ethene diffusion / Rate of phosgene diffusion ≈ 1.878

Therefore, the relative speed of diffusion of ethene to phosgene is approximately 1.878.

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The most common element on Planet Earth is: Aluminum Iron Carbon Oxygen Question 10 Most of the mass of the atmosphere on Earth is: oxygen nitrogen chlorine hydrogen

Answers

The most common element on Planet Earth is: oxygen.
Most of the mass of the atmosphere on Earth is nitrogen.


Oxygen is the most abundant element by mass on Earth. It makes up a significant portion of the Earth's crust, primarily in the form of oxides, such as silicon dioxide (silica) and aluminum oxide. Oxygen also comprises a major part of Earth's atmosphere, where it exists as diatomic oxygen molecules (O2). It plays a crucial role in supporting life and various chemical processes.

Regarding the mass of the Earth's atmosphere, the most abundant gas is nitrogen, not oxygen. Nitrogen makes up approximately 78% of the Earth's atmosphere by volume. Oxygen is the second most abundant gas, accounting for around 21%. Other gases like argon, carbon dioxide, and trace amounts of other gases make up the remaining composition.


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Problem #1 : Radioisotopes are used for a variety of medical purposes including as cancer treatments. Attaching an alpha emitter to an antibody allows for a targeted therapy which can be less damaging to healthy tissue than some other cancer treatments. One such alpha emitter is Astatine 211 (211At) which undergoes LaTeX: \alpha α decay (hence the name, alpha emitter).

1.) What isotope is created by the LaTeX: \alpha α decay of 211At? 2.) How many p+, n0, and e- does it have?

Problem #2 : The grand dream of the protoscience called Alchemy was the transmutation of Lead (Pb) into Gold (Au). Thousands of years later, surely we can do better... after all, Platinum (Pt) is what everyone wants these days. We'll start with an isotope of lead, 209Pb which undergoes LaTeX: \beta β - decay. In reality, that is the end of our tale. However, this is a thought exercise and we can do what we want. Using the different types of radioactive decay described above, but still starting with LaTeX: \beta β - decay, how could we get 209Pb to Pt?

1.) What isotope is created by the LaTeX: \beta β - decay of 209Pb?
2.) Come up with a sequence of radioactive decay steps that would then lead to an isotope of Pt.
3.) What isotope of Pt did you create? How many p+, n0, and e- does it have?

Answers

Answer and Explanation: Many nuclei are radioactive, which means they emit particles to become stable. In the process, they also become a different element. There are 3 types of decay:

Alpha decay: it emits a particle of Helium, i.e., emits a particle with 2 as atomic number (Z) and 4 as atomic mass (A);Beta decay: emits an electron: a particle with 0 mass and -1 as atomic number;Gamma decay: emits a high energy form of electromagnetic radiation and it is extremely dangerous and penetrating;

Problem #1:

1.) Astatine: Z = 85 and  A = 211

Alpha decay: \({{A=211} \atop {Z=85}} \right. At\) ⇒ \({{207} \atop {83}} \right. Bi + {{4} \atop {2}} \right. \alpha\)

The isotope created is Bismuth

Characteristics: Z = 83; e⁻ = 83; n = A - Z = 207 - 83 = 124

The isotope is Bismuth with 83 protons, 83 electrons and 124 neutrons.

Problem #2

1.) Lead: Z = 82 and A = 82

Beta decay: \({{209} \atop {82}} \right. Pb\) ⇒ \({{209} \atop {81}} \right. Tl+{{0} \atop {-1}} \right. \beta\)

The isotope created is talium.

2.) \({{209} \atop {82}} \right. Pb\) ⇒ \({{209} \atop {81}} \right. Tl+{{0} \atop {-1}} \right. \beta\)

\({{209} \atop {81}} \right. Tl\) ⇒ \({{205} \atop {79}} \right. Au+{{4} \atop {2}} \right. \alpha\)

\({{205} \atop {79}} \right. Au\) ⇒ \({{205} \atop {78}} \right. Pt+{{0} \atop {-1}} \right. \beta\)

3.) The isotope created is \({{205} \atop {78}} \right. Pt\).

p⁺ = 78; e⁻ = 78; n = 127

The isotope created ahs 78 protons, 78 electrons and 127 neutrons.

ing Company
More mass
9 Calculate A block of wood has a mass of 120 g
and a volume of 200 cm³. What is the density of
the wood?

Answers

Answer:

Explanation:

The density is measured by: D=mV . Therefore, for the piece of wood in question the density could be calculated by: D=mV=57g125cm3=0.46gcm3 .

A teacher attaches two slinky springs to a fixed support. The springs are moved, as shown in the image. Wave A wave B What property of the wave does the teacher change in the movement of each slinky? amplitude,frequency, speed, or wavelength​

A teacher attaches two slinky springs to a fixed support. The springs are moved, as shown in the image.

Answers

Answer:

a changes more because it going higher

Explanation:

Answer:

They will be the same because amplitude doesn't affect speed. A physics teacher attaches a slinky to the wall and begins introducing pulses with different wavelength. The denser the medium at the compression, the greater the amplitude of the wav

Explanation:

The salt obtained from the combination of the weak acid cyanic acid, hcno, and the weak base ammonia, nh3, is used to make an aqueous solution. is the solution acidic, basic, or neutral?

Answers

The salt obtained from the combination of the weak acid cyanic acid, hcno, and the weak base ammonia, nh3, is used to make an aqueous solution. is the solution basic.

The weak acid of such a buffer system is created when it interacts with both the conjugate base of the buffer system. The pH then just slightly declines, the weak acid concentration rises, and the conjugate base concentration falls.

The acid and base would react to create an acidic solution in a weak base-strong acid titration. During the titration, a conjugate acid would be created, which will subsequently react with water to create hydronium ions. Consequently, a solution with such a pH under 7 is produced.

Therefore, The salt obtained from the combination of the weak acid cyanic acid, hcno, and the weak base ammonia, nh3, is used to make an aqueous solution. is the solution basic.

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How many grams are in 1.5moles of calcium

Answers

Answer: 60.117 g

Explanation: \(1.5 mol Ca = \frac{40.078g/mol}{1mol}\) multiply and quit all "mol" and you get the grams

How many moles of carbon atoms are there in
5g of carbon?

Answers

Answer:

12 atoms of carbon

Explanation:

(6.023X10^23)/12 atoms of Carbon.

There are 0.42 moles of carbon atoms in 5g of carbon.

HOW TO CALCULATE NUMBER OF MOLES:The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass. That is;

no. of moles = mass (g) ÷ molar mass (g/mol)

According to this question, the mass of carbon is 5g. The molar mass of carbon is 12g/mol.

No. of moles = 5g ÷ 12g/mol

No. of moles = 0.42moles

Therefore, there are 0.42 moles of carbon atoms in 5g of carbon.

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please help with this greatly appreciated

please help with this greatly appreciated
please help with this greatly appreciated
please help with this greatly appreciated
please help with this greatly appreciated
please help with this greatly appreciated

Answers

It is true that according to Hubble's law, the farther away a galaxy is, the faster it is moving away from us.

It is true that the formation of a star occurs when nuclear fusion begins to fuse light elements into heavier ones;

The distance to the nearest stars can be determined by parallax, the apparent shift of a start against background stars observed as the earth moves along its orbit. (Option B)

Based on the accompanying H-R Diagram, the type of start that has the greatest temperature is the blue giants (Option C)

Two hydrogen atoms come together in a nuclear fusion reaction to produce Helium Gas. (Option A).

What is Hubble's Law?

Hubble's law, which essentially states that the velocity of a galaxy (or, as it is commonly plotted, its redshift) is precisely proportionate to its distance, also reveals crucial information about the condition of the universe. There should be no relationship between distance and velocity if the cosmos is static and unchanging.

Hubble's law is the physical cosmology observation that galaxies move away from Earth at a rate proportionate to their distance. In other words, the farther they are from Earth, the quicker they are travelling away.

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What happens when potassium forms an ion?

Answers

Answer:

It loses an electron and has an octet in the next-lowest energy level

Explanation:

Four hundred and eighty minutes of production time are available per day. Scheduled production is 120 units per day. What is the required cycle time

Answers

To determine the required cycle time, we can divide the total available production time by the scheduled production units per day.

Total available production time per day: 480 minute Scheduled production units per day: 120 units Required cycle time = Total available production time / Scheduled production units Required cycle time = 480 minutes / 120 units Required cycle time = 4 minutes per unit Therefore, the required cycle time is 4 minutes per unit.

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Is silicon(IV) oxide the same as silicon dioxide

Answers

Answer:

Yes, it is

Explanation:

Silicon (IV) oxide, commonly known as silica is a substance that majorly constitutes SAND. It has the chemical formula, SiO2, which contains a combination of silicon and oxygen.

The IUPAC name of SiO2 is Silicon IV oxide, which can also be referred to as Silicon dioxide because the structure the compound contains two (-di) oxygen atoms. Hence, based on the question, silicon(IV) oxide is the same as silicon dioxide.

If the heat of combustion for a specific compound is −1160.0 kJ/mol and its molar mass is 86.47 g/mol, how many grams of this compound must you burn to release 541.20 kJ of heat?

Answers

Answer:

40.34 g

Explanation:

First, we divide the heat to release by the heat of combustion to obtain the required moles of compound:

541.20 kJ/(1160.00 kJ/mol) = 0.4665 mol

So, we have to burn approximately 0.47 mol of the compound. We convert the moles to mass in grams by using the molar mass:

mass = molar mass x moles = 86.47 g/mol x 0.4665 mol = 40.34 g

Therefore, you must burn 40.34 grams of the compound to release 541.20 kJ of heat.

if each trial started with 10.0 g of tert-butanol, what would have changed? explain your reasoning.

Answers

When each trial is started with 10.0 g of tert-butanol the freezing points would be higher. Hence option A is correct.

Generally the term freezing point is described as the, temperature at which a liquid becomes a solid. Basically with the melting point, increase in the pressure usually increases the normal freezing point. Basically the freezing point is always lower than the melting point in the case of mixtures and also for certain organic compounds such as fats.

When each trial is started with 10.0 g of tert-butanol the freezing points would be higher because there is more tert-butanol present in order to balance out the additives added to the solution. Therefore, when each trial is started with 10.0 g of tert-butanol, the freezing points would be higher. Hence, option A is correct.

The given question is incomplete the complete question is given as,

If each trial started with 10.0 g of tert-butanol, what would have changed? explain your reasoning.

a) the freezing points would be higher

b) the freezing points would be lower

c) the freezing points doesn't change

d) None of the above

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NH3+__0->NO+H20
a) What mass ofNO2 can be produced from 8.46 x 102 molecules of oxygen?

b) 23.7 g ofNH3 would be able to produce how many moles of H0?
c) How many grams of O2 are needed to produce 1.26 x 102 molecules of H20?

d) How many moles of NH3 are needed to react completely with 22.05 L of oxygen?

Answers

a) The mass produced is 6.5 * 10^ -20 g.

b) The amount of water produced is 2.1 moles.

c) The mass of oxygen produced is 7.84 * 10^ -21 g.

d) The moles of ammonia needed is 0.56 moles.

What is stoichiometry?

Let us recall that we can be able to use the principles of stoichiometry to be able to obtain the parameters that we need to solve in this question.

a) Given that;

1 mole of oxygen would contain 6.02 * 10^23 molecules

x moles of oxygen would contain 8.46 x 10^ 2 molecules

x = 1.41 * 10^ -21 moles

If 4 moles of ammonia produces 4 moles of nitrogen IV oxide. Hence the mass of the nitrogen IV oxide produced

= 1.41 * 10^ -21 moles * 46 g/mol

= 6.5 * 10^ -20 g

b) Number of moles of ammonia = 23.7 g/17 g/mol

= 1.39 moles

If 4 moles of ammonia produces 6 moles of water

1.39 moles of ammonia produces 1.39 * 6/4

=2.1 moles

c) 1 mole of water would contain 6.02 * 10^23 molecules

x moles of water would contain  1.26 x 10^ 2 molecules

x = 2.1 * 10^ -22 moles

If 7 moles of oxygen produces 6 moles of water

x moles of oxygen would produce 2.1 * 10^ -22 moles of water

x = 2.45 * 10^-22 moles

Mass of the oxygen = 2.45 * 10^-22 moles * 32 g/mol

= 7.84 * 10^ -21 g

d) If 1 mole of oxygen occupies 22.4 L

x moles of oxygen occupies 22.05 L

x = 0.98 moles

If 4 moles of ammonia reacts with 7 moles of oxygen

x moles of ammonia would reacts with  0.98 moles of oxygen

x = 4 * 0.98/7

= 0.56 moles

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Determine the rate of a reaction that follows the rate law:
rate = k[A]”[B]", where:
k= 1 x 10-2
[A] = 2 M
[B] = 3 M
m = 2
n = 1
A. 0.12 (mol/L)/S
B. 0.36 (mol/L)/S
C. 0.06 (mol/L)/s
D. 6.0 (mol/L)/S

Answers

A. 0.12 (mol/L)/s

rate = 1 x 10-2 • 2^2 • 3

The greater the amount of _____ released, the stronger the acid. H+ OH- Ka pH

Answers

Answer:H+(protons)..

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