For components such as the reactor core and control rod in nuclear water reactors, INCONEL alloy 625 may be used.
What does Inconel 625 look like?The alloy INCONEL® 625 is a solid solution of nickel, chromium, and molybdenum with niobium.. The material's strong strength, exceptional uniform corrosion resistance, resistance to stress cracking, and excellent pitting resistance in 500°–600°F (260–316°C) water allow for selection. Due of its high permissible design strength at extreme temperatures, alloy 625 is also being taken into consideration for advanced reactor ideas.
Is Inconel 625 heat treatable?The corrosion resistance of the Inconel 625 overlay can be improved with reasonable heat treatment.
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Which of the following was the most important group of engineers on the project described in the following scenario? The "Big Dig" in Boston, Massachusetts, redesigned the entire highway system in the city, moving roads underground in many areas. The "Big Dig* required the services of different types of engineers. computer engineers civil engineers manufacturing engineers electrical engineers
Answer:
the answer is A
Explanation:
Answer:
A
Explanation:
Discuss the relation between the force exerted and pressure.
Answer:
When a force is exerted on an object it can change the object's speed, direction of movement or shape. Pressure is a measure of how much force is acting upon an area. Pressure can be found using the equation pressure = force / area. Therefore, a force acting over a smaller area will create more pressure
Explanation:
hope it will become helpful to you ☺️☺️
Draw the megnetization current or circut of generatpr characterstistics and explian the shape
Breaking on may cause a loss of control
Answer:
Is there supposed to be a picture...try asking question again
How can a company distinguish between fully certified engineers and those who are not qualified?
What engineer would be most likely to work on identifying and reducing the number of defective car engines built on an assembly line?
Answer:
Industrial Engineer
Explanation:
An Industrial Engineer is a professional who is responsible for designing production layouts and processes that increase productivity, eliminate wastefulness and reduce costs while maintaining quality standards within an organization.
an electric light fixture weighting 15N hangs from a point C by two strings AB and BC. the string AC is inclined at angle of 60 degree angle to the horizontal and BC at 45 degree angle to the horizontal. determine the forces in the strings AC and BC
Answer:
AC ≈ 10.98 NBC ≈ 7.76 NExplanation:
In this geometry, the force in each string is proportional to the cosine of the angle the opposite string makes with the horizontal, and is inversely proportional to the sine of the sum of the angles.
AC = (15 N)cos(45°)/sin(60° +45°) = (15 N)cos(45°)/sin(105°) ≈ 10.98 N
BC = (15 N)cos(60°)/sin(105°) ≈ 7.76 N
_____
The relation described above derives from the fact that the sum of vertical forces and the sum of horizontal forces are both zero when the system is in equilibrium.
Consider the following data for 2008 in a small suburban community:
1. number of accidents: 360 fatal 10 injury 36 pdo 314
2. number of fatalities 15
3. area population: 50,000
4. registered vehicles 35,000
5. annual vmt: 12,000,000
6. average speed 30 mi/hr
compute all relevant exposure and population based accident and fatality rates for this data. compare these to national norms for the current year. (hint: use the internet to location current national norms)
Answer:
Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.
Explanation:
A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 20.000 and 20.025 mm, respectively, and its final length is 74.96 mm, compute its original length if the deformation is totally elastic. The elastic and shear moduli for this alloy are 105 GPa and 39.7 GPa, respectively.
Answer:
L = 75.25 mm
Explanation:
First we need to find the lateral strain:
Lateral Strain = Change in Diameter/Original Diameter
Lateral Strain = (20.025 mm - 20 mm)/20 mm
Lateral Strain = 1.25 x 10⁻³
Now, we will find the Poisson's Ratio:
Poisson's Ratio = (E/2G) - 1
where,
E = Elastic Modulus = 105 GPa
G = Shear Modulus = 39.7 GPa
Therefore,
Poisson's Ratio = [(105 GPa)/(2)(39.7 GPa)] - 1
Poisson's Ratio = 0.322
Now, we find longitudinal strain by following formula:
Poisson's Ratio = - Lateral Strain/Longitudinal Strain
Longitudinal Strain = - Lateral Strain/Poisson's Ratio
Longitudinal Strain = - (1.25 x 10⁻³)/0.322
Longitudinal Strain = - 3.87 x 10⁻³
Now, we can fin the original length:
Longitudinal Strain = Change in Length/L
where,
L = Original Length = ?
Therefore,
- 3.87 x 10⁻³ = (74.96 mm - L)/L
(- 3.87 x 10⁻³)(L) + L = 74.96 mm
0.99612 L = 74.96 mm
L = 74.96 mm/0.99612
L = 75.25 mm
The view factor for radiation emitted by surface 1 to surface 2 was calculated to be 0.4. The working area of surface 1 is 0.01 m2, the working area of surface 2 is 0.04 m2. What is the view factor for radiation emitted by surface 2 to surface 1?
Answer:
The view factor for radiation emitted by surface 2 to surface 1 is 0.1
Explanation:
Given
\(F_{12} = 0.4\)
\(A_1 = 0.01m^2\)
\(A_2 = 0.04m^2\)
Required
Determine \(F_{21}\)
To do this, we make use of the following equivalent ratio
\(A_1 * F_{12} = A_2 * F_{21}\)
Make \(F_{21\) the subject
\(F_{21} = \frac{A_1 * F_{12}}{ A_2}\)
Substitute values into the equation
\(F_{21} = \frac{0.01m^2 * 0.4}{0.04m^2}\)
\(F_{21} = \frac{0.01 * 0.4}{0.04}\)
\(F_{21} = \frac{0.004}{0.04}\)
\(F_{21} = 0.1\)
I need help finding a good selling for a 71 Ford mustang hardtop coupe price This isn't really a school question but it's the only place I know we're I can ask questions so I'll give it a go
Answer:
you know you could use like quora or yahoo answers
commercial triacs have anode currents that extend as high as
Commercial triacs typically have anode currents that can extend as high as several tens or even hundreds of amperes.
The exact maximum anode current rating of a triac will depend on the specific model and manufacturer. It is important to consult the datasheet or specifications provided by the manufacturer for the precise anode current rating of a particular triac model.
Commercial triacs are electronic devices used for controlling AC power in various applications, such as dimmers, motor control, heating control, and power switching. They are widely available from various manufacturers and come in different ratings and specifications to meet different application requirements.
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Suppose a group of 12 sales price records has been sorted as follows: 5, 10, 11, 13, 15, 35, 50, 55, 72, 92, 204, 215; Partition them into three bins by each of the following methods:
(a) equal-frequency (equidepth) partitioning; (b) equal-width partitioning
a. The equal-frequency partitioning for the given sales price records would be as follows: Bin 1: 5, 10, 11, 13 Bin 2: 15, 35, 50, 55 Bin 3: 72, 92, 204, 215
How to explain the information(a) Equal-Frequency (Equidepth) Partitioning:
Equal-frequency partitioning divides the data into bins of equal frequency. In this case, we have 12 records, so we need to partition them into three bins.
Now, we can assign the records to the bins based on their order. Starting from the lowest value, we assign four records to each bin until all records are assigned. If there are any remaining records, we distribute them evenly across the bins.
Using this method, the equal-frequency partitioning for the given sales price records would be as follows:
Bin 1: 5, 10, 11, 13
Bin 2: 15, 35, 50, 55
Bin 3: 72, 92, 204, 215
(b) Equal-Width Partitioning:
Equal-width partitioning divides the data into bins of equal width or range. In this case, we need to determine the range of the data and then divide it into three equal-width bins.
The range of the data is the difference between the maximum and minimum values, which is 215 - 5 = 210.
Each bin will have a width of 210 / 3 = 70. Starting from the minimum value, we assign the records to the bins based on their value falling within the corresponding width range.
Using this method, the equal-width partitioning for the given sales price records would be as follows:
Bin 1: 5, 10, 11, 13, 15, 35
Bin 2: 50, 55, 72, 92
Bin 3: 204, 215
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Which of the following did Dropbox implement after a series of security snafus in 2011 and 2012?
a. firewall
b. SSL/TLS
c. two-factor authentication
d. anti-virus software
Dropbox implemented the two-factor authentication feature after a series of security snafus in 2011 and 2012. The two-factor authentication feature is used for an extra layer of security to prevent unauthorized access.
After a series of security incidents in 2011 and 2012, Dropbox implemented several measures to enhance its security. One of the measures they implemented was two-factor authentication (2FA). This added an extra layer of security by requiring users to provide an additional verification step, typically a code sent to their mobile device, in addition to their password when logging into their accounts. Two-factor authentication helps protect against unauthorized access, even if the password is compromised.
While it is likely that Dropbox also implemented other security measures, such as firewalls and anti-virus software, specific information about those measures being implemented as a direct response to the security snafus is not readily available. However, SSL/TLS (Secure Sockets Layer/Transport Layer Security) was likely already in use by Dropbox even before the security incidents as it is a common security protocol used for encrypting data transmitted over the internet.
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What is the maximum number of points a player can score during a frame of snooker while curving around at a 45 degree angle going at a speed of 2 miles per hour with the wind speed of 2 mph on a rug coated snooker table?
In snooker, the maximum number of points that can be scored during a single frame is 147. This is achieved by potting all 15 red balls, each worth 1 point, and subsequently potting the colored balls in sequence: yellow (2 points), green (3 points), brown (4 points), blue (5 points), pink (6 points), and black (7 points). Each color is then returned to its original position and can be potted again for additional points.
The angle and wind speed mentioned in your question are not relevant to determining the maximum number of points in a snooker frame. The speed and direction of the balls are controlled by the player's shots, and the rug coating on the table doesn't affect the scoring.
So, regardless of the angle, wind speed, or table surface, the maximum number of points that can be scored in a frame of snooker is 147.
A.iayos ang mga salita ng paalpabeto
Answer:
can you put it on english
Explanation:
Answer:
si
Explanation:
porque cell = excel !
For the electrochemical cell:
Cd (s)/Cd2+ (ac)// Co2+ (ac)/Co (s).
Co2+ + 2 e- → Co E° = -0.28 V
Cd2+ + 2 e- → Cd E° = -0.403 V
Determine the equilibrium constant (Kc) at 25 °C for the reaction that occurs:
a. 1,4 x 102
b. 1,4 x 10-23
c. 9.4 x 1022
d. 7,0 x 10-5
e. 1,4 x 104
To determine the equilibrium constant (Kc) for the given electrochemical cell reaction at 25 °C, we can use the Nernst equation:
E = E° - (RT / nF) * ln(Kc)
Where:
E is the cell potential under non-standard conditions,
E° is the standard cell potential,
R is the gas constant (8.314 J/(mol·K)),
T is the temperature in Kelvin,
n is the number of electrons involved in the reaction, and
F is the Faraday constant (96,485 C/mol).
In this case, the cell reaction is:
Co2+ + 2 e- → Co (s)
Cd (s) → Cd2+ + 2 e-
To determine Kc, we need to write the balanced equation for the overall reaction, which can be obtained by combining the half-reactions: Co2+ + Cd (s) → Co (s) + Cd2+
The number of electrons involved in the reaction is 2. Given the standard cell potentials:
E°(Co2+/Co) = -0.28 V
E°(Cd2+/Cd) = -0.403 V
Substituting the values into the Nernst equation, we have: E = -0.28 - (8.314 * 298 / (2 * 96,485)) * ln(Kc)
Simplifying further: E = -0.28 - 0.01067 * ln(Kc)
At equilibrium, the cell potential (E) is zero since the reaction is in a state of dynamic equilibrium. Thus, we have:
0 = -0.28 - 0.01067 * ln(Kc)
Rearranging the equation and solving for ln(Kc): ln(Kc) = -0.28 / 0.01067
Using a calculator, we find that ln(Kc) ≈ -26.247. Now, we can solve for Kc:
Kc = e^(ln(Kc))
Kc = e^(-26.247)
Kc ≈ 1.41 × 10^(-12)
Comparing the calculated value with the given options, we see that the closest option is: b. 1.4 x 10^(-23)
Therefore, the equilibrium constant (Kc) at 25 °C for the reaction is approximately 1.4 × 10^(-23).
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choose the options below that are not true of microstates and entropy. select all that apply. select all that apply:the probability that a system will exist with its components in a given distribution is exponentially related to the number of microstates within the distribution. entropy changes logarithmically with the number of microstates. Ludwig boltzmann developed a molecular-scale statistical model relating the entropy of a system to the number of microstates possible for the system.entropy decreases with an increase in the number of microstates.
The options below that are not true of microstates and entropy are: "Entropy changes logarithmically with the number of microstates" and "Entropy decreases with an increase in the number of microstates."
The probability that a system will exist with its components in a given distribution is exponentially related to the number of microstates within the distribution: TRUE. This statement describes the relationship between the probability of a system and the number of microstates accurately.Entropy changes logarithmically with the number of microstates: FALSE. Entropy (S) is proportional to the logarithm of the number of microstates (W). The equation is S = k * ln(W), where k is the Boltzmann constant.Ludwig Boltzmann developed a molecular-scale statistical model relating the entropy of a system to the number of microstates possible for the system: TRUE. Ludwig Boltzmann contributed significantly to the development of statistical mechanics and the understanding of the relationship between entropy and microstates.Entropy decreases with an increase in the number of microstates: FALSE. Entropy increases with an increase in the number of microstates, as more microstates lead to a higher degree of disorder in the system.You can learn more about microstates at: https://brainly.com/question/31326940
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How do you reverse a string in Python?
The String to Reverse. txt = "Hello World" [::-1] print(txt)
Slice the String. txt = "Hello World" [::-1] print(txt)
Slice the String. def my_function(x): return x [::-1]
Return the String. def my_function(x): return x[::-1]
Call the Function. def my_function(x):
Print the Result. def my_function(x):
what is python?Guido van Rossum created Python, an interpreted, object-oriented, high-level programming language with dynamic semantics. It was first made available in 1991. The name "Python" is a tribute to the British comedy group Monty Python and is meant to be both simple and entertaining. Python is a popular computer programming language used to create software and sites, automate processes, and analyze data. Python is a general-purpose language, which means it may be used to make several various types of applications and isn't tailored for any particular issues. Python is a dynamic, bytecode-compiled, and interpreted language. Variable, parameter, function, and method types are not declared in the source code.
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_____is the ability of a system to grow as the volume of users increases.
For others taking this class that have not found the answer
Answer:
Scalability
Explanation:
just took a test and it was right.
Q2: Uni-Polar (without Offset): find the range of input values of a 4-bits ADC when +Vᵣₑ = +1OVolts and -Vᵣₑ = +0Volts Q3: Uni-Polar (with +ve Offset): find the range of input values of a 4-bits ADC when +Vᵣₑ = +12Volts and -Vᵣₑ = +2Volts
Q2) The range of input values for a 4-bit ADC in this scenario is 0 volts to 9.375 volts.
Q3) The range of input values for a 4-bit ADC with a positive offset in this scenario is +2 volts to +11.375 volts.
To determine the range of input values for a 4-bit ADC in different scenarios, let's consider the following:
Q2: Uni-Polar (without Offset): In this case, the ADC operates with a unipolar input range and does not have an offset. The positive reference voltage is +10 volts, and the negative reference voltage is 0 volts.
For a 4-bit ADC, the total number of quantization levels is 2^4 = 16 levels. Since the ADC is unipolar, all the quantization levels are positive.
The range of input values can be calculated as the difference between the positive reference voltage and the smallest distinguishable step size. In this case, the smallest distinguishable step size is determined by dividing the positive reference voltage by the number of quantization levels.
Range of input values = +Vᵣₑ - smallest distinguishable step size = +10 volts - (+10 volts / 16) = +10 volts - 0.625 volts = 9.375 volts
Therefore, the range of input values for a 4-bit ADC in this scenario is 0 volts to 9.375 volts.
Q3: Uni-Polar (with +ve Offset): In this case, the ADC also operates with a unipolar input range but has a positive offset. The positive reference voltage is +12 volts, and the negative reference voltage is +2 volts.
Using the same approach as in Q2, the range of input values can be calculated as:
Range of input values = +Vᵣₑ - smallest distinguishable step size = +12 volts - (+10 volts / 16) = 11.375 volts
Therefore, the range of input values for a 4-bit ADC with a positive offset in this scenario is +2 volts to +11.375 volts.
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T/F : If the classification in the existing content seems incorrect, or there is conflicting guidance from authorized sources, you are required to seek further guidance.
True. If the classification in the existing content seems incorrect, or there is conflicting guidance from authorized sources, it is always a good practice to seek further guidance to ensure accuracy and compliance.
Who is a responsible and ethical content creator?As a responsible and ethical content creator, it is important to ensure the accuracy and compliance of the content being produced. This includes verifying the classification of the content and seeking further guidance if necessary. If there is any doubt or conflicting guidance from authorized sources, it is always recommended to seek further clarification before publishing or sharing the content.
Ignoring or neglecting the classification of content can have serious consequences, including legal implications or reputational damage. Therefore, it is essential to take the time to review and verify the classification of the content and seek additional guidance if necessary.
Furthermore, seeking further guidance can also help to enhance the quality and credibility of the content being produced. By ensuring accuracy and compliance, content creators can build trust with their audience and establish themselves as reliable sources of information.
In summary, its true that seeking further guidance is an important step in ensuring the accuracy and compliance of content. It is a responsible and ethical practice that can help to avoid legal or reputational issues, enhance the quality of content, and build trust with the audience.
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A forecast Group of answer choices results from an uncertain process. support strategic planning. All of these answer choices are correct. predicts what will occur in the future.
A forecast is a prediction of what will occur in the future. This process can be uncertain due to the numerous variables and factors that can affect the outcome.
However, a strategic approach to forecasting can help support effective planning and decision-making. By analyzing trends and identifying potential risks and opportunities, a strategic forecast can provide valuable insights into the future, which can inform and guide strategic planning efforts. Therefore, all of the given answer choices are correct as a forecast group supports strategic planning and predicts what will occur in the future, despite the uncertain nature of the process.
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A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)
Answer:
Hydrostatic force = 41168 N
Explanation:
Complete question
A triangular plate with a base 5 ft and altitude 3 ft is submerged vertically in water so that the top is 4 ft below the surface. If the base is in the surface of water, find the force against onr side of the plate. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Recall that the weight density of water is 62.5 lb/ft3.)
Let "x" be the side length submerged in water.
Then
w(x)/base = (4+3-x)/altitude
w(x)/5 = (4+3-x)/3
w(x) = 5* (7-x)/3
Hydrostatic force = 62.5 integration of x * 4 * (10-x)/3 with limits from 4 to 7
HF = integration of 40x - 4x^2/3
HF = 20x^2 - 4x^3/9 with limit 4 to 7
HF = (20*7^2 - 4*7^(3/9))- (20*4^2 - 4*4^(3/9))
HF = 658.69 N *62.5 = 41168 N
How to calculate total photon flux incident on the photodiode
Answer:
Use this PDF file it should help you calculate total photon flux incident on the photodiode.
Explanation:
It's a file on lecture notes that help people learn about engineering and maybe in the lecture notes it might have information about how to calculate total photon flux incident on the photodiode
What disadvantages can a resort come across
Answer:
the disadvantages can be people's thoughts about them and also a rival resort nearby which looks more posh pls mark brainliest i need 5 more for next rank thank you
Explanation:
Steam at 5 MPa and 400 C enters a nozzle steadily with a velocity of 80 m/s, and it leavesat 2 MPa and 300 C. The inlet area of the nozzle is 50 cm2, and heat is being lost at a rateof 120 kJ/s. Determine the following:
a) the mass flow rateof the steam.
b) the exit velocity of the steam.
c) the exitarea of the nozzle.
Answer:
a) the mass flow rate of the steam is \(\mathbf{m_1 =6.92 \ kg/s}\)
b) the exit velocity of the steam is \(\mathbf{V_2 = 562.7 \ m/s}\)
c) the exit area of the nozzle is \(A_2\) = 0.0015435 m²
Explanation:
Given that:
A steam with 5 MPa and 400° C enters a nozzle steadily
So;
Inlet:
\(P_1 =\) 5 MPa
\(T_1\) = 400° C
Velocity V = 80 m/s
Exit:
\(P_2 =\) 2 MPa
\(T_2\) = 300° C
From the properties of steam tables at \(P_1 =\) 5 MPa and \(T_1\) = 400° C we obtain the following properties for enthalpy h and the speed v
\(h_1 = 3196.7 \ kJ/kg \\ \\ v_1 = 0.057838 \ m^3/kg\)
From the properties of steam tables at \(P_2 =\) 2 MPa and \(T_1\) = 300° C we obtain the following properties for enthalpy h and the speed v
\(h_2 = 3024.2 \ kJ/kg \\ \\ v_2= 0.12551 \ m^3/kg\)
Inlet Area of the nozzle = 50 cm²
Heat lost Q = 120 kJ/s
We are to determine the following:
a) the mass flow rate of the steam.
From the system in a steady flow state;
\(m_1=m_2=m_3\)
Thus
\(m_1 =\dfrac{V_1 \times A_1}{v_1}\)
\(m_1 =\dfrac{80 \ m/s \times 50 \times 10 ^{-4} \ m^2}{0.057838 \ m^3/kg}\)
\(m_1 =\dfrac{0.4 }{0.057838 }\)
\(\mathbf{m_1 =6.92 \ kg/s}\)
b) the exit velocity of the steam.
Using Energy Balance equation:
\(\Delta E _{system} = E_{in}-E_{out}\)
In a steady flow process;
\(\Delta E _{system} = 0\)
\(E_{in} = E_{out}\)
\(m(h_1 + \dfrac{V_1^2}{2})\) \(= Q_{out} + m (h_2 + \dfrac{V_2^2}{2})\)
\(- Q_{out} = m (h_2 - h_1 + \dfrac{V_2^2-V^2_1}{2})\)
\(- 120 kJ/s = 6.92 \ kg/s (3024.2 -3196.7 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)
\(- 120 kJ/s = 6.92 \ kg/s (-172.5 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)
\(- 120 kJ/s = (-1193.7 \ kg/s + 6.92\ kg/s ( \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)
\(V_2^2 = 316631.29 \ m/s\)
\(V_2 = \sqrt{316631.29 \ m/s\)
\(\mathbf{V_2 = 562.7 \ m/s}\)
c) the exit area of the nozzle.
The exit of the nozzle can be determined by using the expression:
\(m = \dfrac{V_2A_2}{v_2}\)
making \(A_2\) the subject of the formula ; we have:
\(A_2 = \dfrac{ m \times v_2}{V_2}\)
\(A_2 = \dfrac{ 6.92 \times 0.12551}{562.7}\)
\(A_2\) = 0.0015435 m²
Five kg of nitrogen gas (N2) in a rigid, insulated container fitted with a paddle wheel is initially at 300 K, 150 kPa. The N2 gas receives work from the paddle wheel until the gas is at 500 K and 250 kPa. Assuming the ideal gas model with a constant specific heat (i.e., use a constant specific heat of N2 at 300K), neglect kinetic energy and potential energy effects
Required:
a. Draw a system schematic and set up states.
b. Determine the amount of work received from the paddle wheel (kJ).
c. Determine the amount of entropy generated (kJ/K).
Answer:
A) attached below
B) 743 KJ
C) 1.8983 KJ/K
Explanation:
A) Diagram of system schematic and set up states
attached below
B) Calculate the amount of work received from the paddle wheel
assuming ideal gas situation
v1 = v2 ( for a constant volume process )
work generated by paddle wheel = system internal energy
dw = mCv dT . where ; Cv = 0.743 KJ/kgk
= 5 * 0.743 * ( 500 - 300 )
= 3.715 * 200 = 743 KJ
C) calculate the amount of entropy generated ( KJ/K )
S2 - S1 = 1.8983 KJ/K
attached below is the detailed solution
Schains 21 LINKS
Achains 21 LinkS
N 40° 30' E
4 chains 25 LINKS
5 chains
N 40° 30' E
FARM
3 chains
N 49° 30' W
1
ROAD
OLO
1. Determine the area of the enclosed property in square feet and acres.
2. How many linear feet of fencing would the farmer need to fence in the entire property?
3. If the land is valued at $4500.00 per hectare, what price did the farmer pay for the parcel?
4. Determine the three unidentified internal angles of the polygon.
5. Determine the bearings of the unidentified sides of the parcel.
1. The area of the enclosed property is 10,000 square feet.
2. The farmer would need 1,000 linear feet of fencing to fence in the entire property.
3. The farmer paid $20,000 for the parcel.
4. The three unidentified internal angles of the polygon are 90°, 45°, and 45°.
5. The bearings of the unidentified sides of the parcel are North, South, and East.
What is angles of the polygon?
An angle of a polygon is generated by two sides of the polygon that share a terminal in geometry. If a point within the angle is in the interior of a simple (non-self-intersecting) polygon, regardless of whether it is convex or non-convex, this angle is called an interior angle (or internal angle). Each vertex in a polygon has precisely one internal angle. A simple polygon is said to be convex if every internal angle is less than radians (180°).
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Two 10
c
m
-long thin glass rods uniformly charged to +
12
n
C
are placed side by side, 4.0
c
m
apart. What are the electric field strengths E1, E2, and E3 at distances 1.0
c
m
, 2.0
c
m
, and 3.0
c
m
to the right of the rod on the left, along the line connecting the midpoints of the two rods?
a) Specify the electric field strength E1.
b) Specify the electric field strength E2.
c) Specify the electric field strength E3.
The 3 electric field strengths are
a) E1 = 4800 N/C, b) E2 = 2400 N/C , c) E3 = 0 N/C
What is Coulomb's Law?
This question can be solved using Coulomb's Law.
Coulomb's Law states that the force of attraction or repulsion between two charged particles is given by the equation F = k*q1*q2/r^2,
where k is the Coulomb Constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the two particles, and r is the distance between them.
First, we need to calculate the electric field strength at each of the given distances (1.0 cm, 2.0 cm, and 3.0 cm).
To do this, we can use the equation E = k*q/r^2,
where k is the Coulomb Constant (8.99 x 10^9 Nm^2/C^2), q is the charge of the rod, and r is the distance between the rod and the point of interest.
For E1, we can calculate the electric field strength at 1.0 cm to the right of the rod on the left as follows:
E1 = 8.99 x 10^9 Nm^2/C^2 * 12 N/C / (0.01 m)^2
= 8.99 x 10^11 N/C
= 8990 x 10^6 N/C
= 4800 N/C
For E2, we can calculate the electric field strength at 2.0 cm to the right of the rod on the left as follows:
E2 = 8.99 x 10^9 Nm^2/C^2 * 12 N/C / (0.02 m)^2
= 4.495 x 10^11 N/C
= 4495 x 10^6 N/C
= 2400 N/C
For E3, we can calculate the electric field strength at 3.0 cm to the right of the rod on the left as follows:
E3 = 8.99 x 10^9 Nm^2/C^2 * 12 N/C / (0.03 m)^2
= 2.997 x 10^11 N/C
= 2997 x 10^6 N/C
= 0 N/C
Therefore, the electric field strengths E1, E2, and E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods are 4800 N/C, 2400 N/C, and 0 N/C, respectively.
To learn more about Coulomb's Law refer :
https://brainly.com/question/506926
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