In the Styrofoam ball investigation, it is likely that the charges on the ball and rod are
?
A. the same
B. opposite
C. constantly changing.

If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.

In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.

The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.

As per the given information in the question,

Force, f = 400 N

Displacement, d = 0.2 meters

\(Work done(W)=Force(f)*Displacement(d)\)

W = 400 × 0.2

W = 80 J.

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Answer:

Hello There!!

Explanation:

Work done= force × distance moved

Work done=5000N×15m

Work done=75,000J

hope this helps,have a great day!!

~Pinky~

Answer:

Earth's surface is broken into large pieces that are slowly shifting. ... This movement creates many of Earth's landforms, such as mountains, rift valleys, and volcanoes. According to the theory of plate tectonics, 250 million years ago all of Earth's landmasses were clustered into one supercontinent, known as Pangea.

or

Presently the plates are moving towards each other and will eventually merge into one landmass once again. Presently Africa I moving towards Europe and Asia and will merge with that landmass, closing the Mediterranean Sea. When plates move towards each other extensive fold mountain ranges will form; a modern day example is the Himalayan mountain range. This type of movement will impact ocean currents as we know it and bring about a dramatic change in the climate. Disruption of currents and the closure of some water ways and oceans will lead to the extinction of some species. Leaving only those who are able to adapt to the new climatic conditions.

Explanation:

you can choose either one

Answer:

Based on what I have learned this year and past knowledge, I think they will move in a combination of two. The tectonic plates move around the planet but move very slowly, only a few centimeters per year, which plays a big part in the picture. If you look at California, It's splitting! But who is to say that the continents will not cluster to another land as it spreads out. There's also not enough space on earth for every piece of land. But when they do end up clustered together, mountains will be formed, and if they spread out, faults will be created. So I think in 250 million years we will have another supercontinent like Pangea. I also believe that there will be many new geographical changes, including volcanoes, more mountains, and deeper oceans. This will also cause new Invasive species and the destruction of man-made buildings.

Explanation:

palto users

The average density of a planet is given by:

where m is the mass of the planet and V is its volume. We know the mass of the planet but we don't know its volume, to find it we will need find its radius.

To find the radius of the planet we can use Newton's Law of gravitation:

where G is the gravitational constant, m is the mass of the object, M is the mass of the planet and d is the distance between the planet and the object. Let r be the radius of the planet, and x be the distance from the surface of the planet to the object (x=13660 in this case); then we have:

Plugging the values given we have:

Since the radius of the planet has to be positive we choose the positive solution.

Now, that we know the radius of the planet we can calculate its volume; assuming the planet is spherical we have that:

then we have:

Finally we can calculate the density:

Therefore, the average density is 11398 kg/m^3

Let's check the formula for a focal length:

Since basically the two lenses have the same form, we can conclude that R1,R2 and d are the same. But n ( refractive index) could be different. n depends on the material, so we can conclude that the answer is:

A.

Lens A and lens B are made from two different materials with different optical properties.

Answer:

I don't no the answer sorry

Answer:

(a) W = 882 N

(b) m = 90 kg

(c) Wm = 342 N

Explanation:

(a)

The weight of n object on the surface of earth is given as:

W = mg

where,

W = Weight of Astronaut on Earth = ?

m = mass of astronaut = 90 kg

g = acceleration due to gravity on surface of earth = 9.8 m/s²

Therefore,

W = (90 kg)(9.8 m/s²)

W = 882 N

(b)

Mass of a body is a universal constant. The mass of the body remains same any where in the universe. Therefore, on mars the mass of astronaut will be:

m = 90 kg

(c)

The weight of an object on the surface of Mars is given as:

Wm = m(gm)

where,

Wm = Weight of Astronaut on Mars = ?

m = mass of astronaut = 90 kg

gm = acceleration due to gravity on surface of Mars = 3.8 m/s²

Therefore,

Wm = (90 kg)(3.8 m/s²)

Wm = 342 N

Answer:

1. 100

2. Volume

3. 2 s

4. At Rest

5. Linear

Answer:

5.48 m/s.

Explanation:

Use the formula a=v^2/r.

When the mass of the object is decreased by a factor of 2.2, the acceleration is increased by a factor of 2.2, new acceleration would be of 30.8 m/s/s.

The effect of reducing the mass of an object by a factor of 2.2 on its acceleration is determined by Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

In terms of calculations, the new acceleration can be calculated by multiplying the initial acceleration by the factor by which the mass is decreased. Therefore, the new acceleration of the object with a reduced mass of 2.2 times its original mass would be 2.2 times its initial acceleration of 14 m/s/s. This would result in a new acceleration of 30.8 m/s/s (14 x 2.2 = 30.8).

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Answer:

Net charge inside the cube is 321.6 C

Explanation:

Given charge density function is ρ = \(xy^2 e^{2z}\)

side of cube is 2m

According to the definition of volume charge density total charge is given by

q = total charge = \(\int {\rho} \, dv\) where dv = dxdydz is the volume element

on substututing the respected values we get

q = \(\int\limits^2_0 {x} \, dx \int\limits^2_0 {y^2} \, dy \int\limits^2_0 {e^2^z} \, dz\)  

on solving the above integration we get

q =  \(\frac{x^2}{2}\) x \(\frac{y^3}{3}\) x \(\frac{e^2^z}{2}\)

⇒ q = 321.6 C

Therefore net charge inside the cube is 321.6 C

Answer:

I think you would need too time your friend and know how too divide that time by other racers to see how much faster she needs to get. I THINK.

Answer:

Charging by contact is when the charged object is brought near but never contacted to the object being charged

Explanation:

The power needed to boil the water is divided by the element's power output, and the result is multiplied by 100 to get the efficiency of the kettle as a percentage. The answer is 79 %.

We are informed that

Electric kettle power is 1 kW.

Electric kettle voltage is 230 V.

The time it takes the kettle to bring the water to boiling point is 7.5 minutes.

1 kg = mass of water.

Heat generated equals V x I x t + Pt.

generated heat = 1000 W x 7.5 x 60

Heat absorbed equals (100 - 15) x 1 x 4200 = 4200 x 85

Efficiency is determined by multiplying the heat produced by the heat absorbed by 100.

= 4.2 x 85 x 10^3 / 4.5 x 10^5 x 100

= 357 / 4.5 = 79 %

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Answer:

B

Explanation:

The cost of manufacturing would have to be taken away from your profits becuase its costing you to build and get the materials. I believe this question is hard.

Answer:

there is no model shown

Explanation:

Therefore it can be thousands of different answers

The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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The description of water pollution and it's likely causes in Florida can be found below.

Water pollution is the contamination of water, especially surface water, by sewage effluent, fertilizer runoff, industrial chemical discharge etc.

These contaminants are called pollutants and when released into a body of water can deteriorate water quality and hamper its usage by humans.

Water pollution in Florida or any other developed state/country of the world can be caused by the following:

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Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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The correct statement about the right ascension is "it is 3 hours to the east of zero hours right ascension.

option C is the correct answer

The right ascension of stars is the astronomical equivalent of longitude.

Right ascension is also the angular distance of the star measured eastward from the first point of Aries, also called the Vernal Equinox.

In other words, the right ascension describes how far a star is displaced from a given point towards the eastward direction along the longitude.

Lines of longitude runs from east to west. But the right ascension runs towards the east.

Thus, the correct statement describing the right ascension would measure it towards the east.

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Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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Answer:

The value of g is  \(g =76.2 m/s^2\)

Explanation:

From the question we are told that

     The mass of the weight is \(m = 1.30 kg\)

      The spring  constant  \(k = 1.73 g/m = 1.73 *10^{-3} \ kg/m\)

       The second harmonic frequency is \(f = 100 \ Hz\)

       The number of oscillation is \(N = 200\)

        The time taken is  \(t = 315 \ s\)

Generally the frequency is  mathematically represented as

           \(f = \frac{v}{\lambda}\)

At second harmonic frequency the length of the string vibrating is equal to  the wavelength of the wave generated

         \(l = \lambda\)

Noe from the question the vibrating string is just half of the length of the main string so

Let assume the length of the main string is  \(L\)

So      \(l = \frac{L}{2}\)

The velocity of the vibrating string is mathematically represented as

             \(v = \sqrt{\frac{T}{\mu} }\)

Where T is the tension on the string which can be mathematically represented as

             \(T = mg\)

So  

           \(v = \sqrt{\frac{mg}{k} }\)

Then

          \(f = \frac{v}{\frac{L}{2} }\)

=>       \(v = \frac{fL }{2}\)

=>      \(\sqrt{\frac{mg}{k} } = \frac{fL}{2}\)

=>        \(g = \frac{f^2 L^2 \mu}{4m}\)

substituting values

             \(g = \frac{(100) * (1.73 *10^{-3} )}{(4 * 1.30)} L^2\)

              \(g = 3.326 m^{-1} s^{-2} L^2\)

Generally the period of oscillation is mathematically represented as

       \(T_p = 2 \pi \sqrt{\frac{L}{g} }\)

=>   \(L = \frac{T^2 g}{4 \pi ^2}\)

   The period can be mathematically evaluated as

                \(T_p = \frac{t}{N}\)

 substituting values

             \(T_p = \frac{315}{200}\)

             \(T_p = 1.575 \ s\)

Therefore

          \(L = \frac{1.575^2 * g }{4 \pi ^2}\)

           \(L = 0.0628 ^2 g\)

so

      \(g = 3.326 m^{-1} s^{-2} L^2\)

substituting for L

        \(g = 3.326 ((0.0628) g)^2\)

=>    \(g = \frac{1}{(3.326)* (0.0628)^2}\)

       \(g =76.2 m/s^2\)

The height of the satellite Aldock in orbit is approximately 1,419,288 meters or 1,419.3 kilometers above the Earth's surface.

The height of a satellite in orbit around the Earth can be calculated using the following formula:

h = (GMt/4π²)^(1/3) - Re

where:

To solve for h, we need to know the mass of the satellite and the speed of its orbit. However, we can use the given information that the Earth exerts a force of 5000N on the satellite to calculate the speed of the orbit using the centripetal force equation:

F = mv^2/r

where:

Solving for v, we get:

v = √(Fr/m)

v = √((5000 N) * (6,371,000 m)) = 7919.26 m/s

Now that we know the speed of the orbit, we can use the first formula to solve for the height of the satellite:

h = (GMt/4π²)^(1/3) - Re

Substituting the given values, we get:

h = [(6.67430 × 10^-11 m^3/kg/s^2) * (5.972 × 10^24 kg) / (4π²)]^(1/3) - 6,371,000 m

= 1,419,288 m

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(a) The appropriate boundary conditions for the velocity at the walls are:

Top wall (z=H): u=V, v=w=0 (no slip condition)

Bottom wall (z=0): u=0, v=w=0 (no slip condition)

(b) At the interface between the two immiscible fluids, we assume that the velocity is continuous, i.e., the velocity of the two fluids at the interface is the same. As a result, the interface's boundary conditions are:

u1(z=h) = u2(z=h)

v1(z=h) = v2(z=h)

(c) Assuming only a single fluid system, the continuity equation can be simplified as:

∂u/∂x + ∂v/∂y + ∂w/∂z = 0

since there is no variation in the x and y directions, this simplifies to:

∂w/∂z = 0

(d) Simplifying the X, Y, and Z components of the Navier-Stokes equations assuming a single fluid system:

X-component:

∂(u²)/∂x + ∂(uv)/∂y + ∂(uw)/∂z = -1/ρ ∂p/∂x + ν (∂^2u/∂x² + ∂^2u/∂y² + ∂^2u/∂z²)

Since the flow is parallel in the x-direction, the first term is 0. Since there is no variation in the y-direction, the second term is 0. Simplifying, we get:

∂(uw)/∂z = ν ∂^2u/∂z²

Y-component:

∂(uv)/∂x + ∂(v²)/∂y + ∂(vw)/∂z = -1/ρ ∂p/∂y + ν (∂^2v/∂x² + ∂^2v/∂y² + ∂^2v/∂z²)

Since the flow is parallel in the x-direction, the first term is 0. Since there is no variation in the y-direction, the second term is 0. Simplifying, we get:

∂(vw)/∂z = ν ∂^2v/∂z²

Z-component:

∂(uw)/∂x + ∂(vw)/∂y + ∂(w²)/∂z = -1/ρ ∂p/∂z + ν (∂^2w/∂x² + ∂^2w/∂y² + ∂^2w/∂z²)

Since the flow is parallel in the x-direction, the first two terms are 0. Simplifying, we get:

∂(w²)/∂z = -1/ρ ∂p/∂z + ν ∂^2w/∂z².

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it is easier to thrust a magnet into a wire coil with one loop than one with four loops Because with four loops it becomes more difficult to push the magnet in.

It is the type of field where the magnetic force is obtained. The magnetic force is obtained it is the field felt around a moving electric charge.

The quantity of turns or loops in a coil directly relates to the intensity of the magnetic field within the coil.

As a result, the magnetic field strength has increased fourfold when there are four loops instead of one, making it more difficult to push the magnet in.

A single-looped wire coil is simpler to insert a magnet into than one with four loops. because inserting the magnet gets more challenging when there are four loops.

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Answer:

mass 20 times of an amazing and all its motion

The athlete must leave the ground with a speed of 6.33m/s.

To calculate the initial speed, with the information of height and final speed, we can use the following expression that uses the kinetic energy and potential energy:

                               \(mgh_1 + \frac{1}{2}mv_1^{2}= mgh_2 + \frac{1}{2}mv_2^{2}\)    

Applying the values ​​given by the statement we have:

                           \(9.81\times 0 + \frac{1}{2}v_1^{2} = 9.81 \times 2 + \frac{1}{2}(0.95)^{2}\)      

                                             \(v_1 = 6.33m/s\)

So, the athlete must leave the ground with a speed of 6.33m/s.

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