In the figure, two blocks, of masses 2. 00 kg and 3. 00 kg, are connected by a light string that passes over a frictionless pulley of moment of inertia 0. 00400 kg · m2 and radius 5. 00 cm. The coefficient of friction for the tabletop is 0. 300. The blocks are released from rest. Using energy methods, find the speed of the upper block just as it has moved 0. 600 m.

Answer:

Below

Explanation:

To find how fast the bullet is travelling you can use this formula :

     Vf^2 = Vi^2 + 2ad

     Vf^2 = 37.4^2 + 2 (-9.8)(69.9)

              = 1398.76 -1370.04

              = 28.72 m/s

Square this number

     = 5.3591044027897

Therefore the bullet is travelling at 5.36 m/s when it is 69.9 m in the air.

Hope this helps! Best of luck <3  

Answer:

Heat capacity is the ratio of the amount of heat energy transferred to an object to the resulting increase in its temperature. Molar heat capacity is a measure of the amount of heat necessary to raise the temperature of one mole of a pure substance by one degree K.

Explanation:

hope this helps <3

Answer:

Emphasis on public safety can surely reduce the risk for various groups of population

1. Proper education and training must be provided to make them aware of the risks and how they can manage those risks.

2. Proper rules and regulation must be made and strictly followed for example traffic rules so as to avoid accidents.

3. Disaster management teams should to formed to ensure minimal loss of humans and resources during any natural calamity.

4.Eradication of poverty and illiteracy should be priority so as to ensure people focus on more important issues in life rather than involve themselves in trivial things.

Explanation:

The speed v(c) of the center of mass of the system after the pod is launched is equal to v(f).

Mass of the pod, m₁ = m

Mass of the spaceship, m₂ = 6m

The conservation of momentum principle states that, within a given domain, the amount of momentum is constant such that, momentum is never created nor destroyed, but only modified by the application of forces.

So, according to the conservation of momentum, the momentum before launch and before launch must be equal. Therefore, the speed of the center of mass of the system becomes equal to the speed with which the spaceship is moving towards the right.

Therefore,

v(c) = v(f)

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The basic difference is that the motion of object remain unchanged in case of balanced forces while it changes when an object experiences unbalanced forces

When the forces experienced by an object have equal strength and are acting in opposite directions, they are known as balanced forces while the forces those differ in strength and are probably acting in any direction except opposite, they are known as unbalanced forces.

The balanced forces cancel out each other, and the motion of the object remains unchanged but unbalanced forces can change the velocity or direction of a moving object

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Answer: find the answer in the explanation.

Explanation:

From the experiment set up in the diagram, the pointer is resting on the drinking straw while the rod is resting on the drinking straw.

When the rod is being heated through the bursen burner, there will be linear expansion in the rod. As the rod increases its length, this causes the drinking straw to roll and thereby causing the pointer to rotate.

The pointer therefore rotates because of the thermer expansion that happen in the rod due to the heat from the bursen burner.

Answer: 25

Explanation ;)

The energy of the photons emitted by this station is 4171.30eV.

Given -

The frequency is 1010 KHz.

Principle & calculations-

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The displacement of Curiosity is 2.334 m

The given parameter:

maximum speed of Curiosity, v = 0.14 km/hr

time of motion of Curiosity = 60 s

To find:

The displacement of Curiosity is calculated as follows;

The displacement of Curiosity = speed x time

The displacement of Curiosity = 0.0389 m/s x 60 s

The displacement of Curiosity = 2.334 m

Thus, the displacement of Curiosity is 2.334 m

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The acceleration of the train during the first two seconds is 10 m / s², between second and tenth second is zero and during the last 2 seconds is - 10 m / s².

a = v - u / t

a = Acceleration

v = Final velocity

u = Initial velocity

t = Time

(a) During first 2 seconds,

u = 0

v = 20 m / s

t = 2 s

a = 20 - 0 / 2

a = 10 m / s²

(b) Between second and tenth second

u = 20 m / s

v = 20 m / s

t = 8 s

a - 0 -0 / 8

a = 0 m / s²

(c) During last 2 seconds,

u = 20 m / s

v = 0

t = 2 s

a = 0 - 20 / 2

a = - 10 m / s²

Therefore, the acceleration of the train

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Answer:Joe's velocity leaving the ground is 1.00 m/s.

Explanation: The velocity of Joe immediately after leaving the ground can be calculated using the formula v = at, where a is the acceleration and t is the time. Joe's acceleration can be found using the equation F = ma, where F is the net force and m is the mass.So, Joe's acceleration can be calculated as a = F/m = 100N / 90kg = 1.11 m/s^2.Then, using v = at, we can calculate Joe's velocity as v = 1.11 m/s^2 x 0.9 s = 1.00 m/s. Therefore, Joe's velocity immediately after leaving the ground is 1.00 m/s.

The best estimate of the acceleration of the object 2.5 m/sec².

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Force due to gravity = mg

                                  = 8*9.8 = 78.4 N

Net force on object = 78.4 - 60 = 18.4 N

Acceleration = 18.4/8 = 2.5 m/sec²

The best estimate of the acceleration of the object 2.5 m/sec².

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Answer:

Work out the change in velocity for you given time.

Calculate the change in time for the period you are considering.

Divide the change in velocity by the change in time.

can increase the velocity of the object, decrease the velocity of the object, or change the direction of the velocity of the object.

Explanation:

hope this helped have a great day!

Known :

S = 205 m

t = 0.6 s

Solution :

Sound speed

v = S/t

v = (205 m)/(0.6 s)

v = 341.67 m/s

Air Temperature

v² = γRT

(341.67 m/s)² = (1.4)(286 m²/s²·K)(T)

T = 291.5 K

The velocity of the rower relative to the shore is the sum of her velocity relative to the water and the velocity of the water relative to the shore:

\(\vec v_{R/S} = \vec v_{R/W} + \vec v_{W/S}\)

Then

\(\vec v_{R/S} = \left(4.5\dfrac{\rm km}{\rm h},0\right) + \left(0,3.5\dfrac{\rm km}{\rm h}\right) = (4.5,3.5)\dfrac{\rm km}{\rm h}\)

The magnitude of this velocity is

√(4.5² + 3.5²) m/s ≈ 5.7 m/s

Answer:

It's B C D E are maintaining a constant velocity

Wavelength of the waves in meters is 4m.

Wavelength is the distances between identically any points (adjacent cresta) in the adjacent cycles of a wave form signals propagates in spaces or along side a wire. In wireless system's, this lengths is usually specifies in meters (m), centimetres (cm) or millimetres (mm).

To solve this equation first we have to use the wave formulation -

V= fλ

As we know

v= velocity

f= frequency

λ=wavelength

We know the frequency and the velocity of the  both elements which have good unit's. All we have to do is rearranged the equations and solve for λ.

λ= v/f

Let's calculate both the value to get our main answer-

λ= 7m/s / 28s^-1

λ= 4m

Thus, the wavelength is 4m.

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Answer:

moving up positive acceleration

Explanation:

when moving up as you bounce the ball

the speed changes gradually increasing so according to the equation

acceleration =[speed change ] ÷ period when speed change is positive acceleration is also positive , and an greater value

example speed changes 5m/s within 2 seconds throwing the ball upward

(these are assuming values to explain)

acceleration is 5/2 = + 2.5 m/s^2

so this is an positive acceleration

if negative we call deceleration

When a basketball is bouncing and moving up, it has a negative acceleration.

Acceleration is the rate of change of velocity with respect to time. If the velocity of the basketball is increasing in the upward direction as it bounces, the acceleration is directed downward (negative). This might seem counterintuitive at first, but it is essential to understand that acceleration is a vector quantity, which means it has both magnitude and direction.

When the basketball moves upward during its bounce, its velocity is slowing down due to the opposing force of gravity. As it moves against gravity, the magnitude of its velocity decreases until it reaches the highest point (apex) of its bounce, where its velocity momentarily becomes zero. At the apex, the basketball changes direction and starts moving downward, and its velocity increases in the downward direction.

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Answer:

Speed of sound ways in railroad = 6,135.8 m/s

Explanation:

Given:

Distance cover by sound wave = 2,350 meter

Time taken by sound wave to cover distance = 0.383 seconds

Find:

Speed of sound ways in railroad

Computation:

Speed = Distance / Time

Speed of sound ways in railroad = Distance cover by sound wave / Time taken by sound wave to cover distance

Speed of sound ways in railroad = 2,350 / 0.383

Speed of sound ways in railroad = 6,135.77

Speed of sound ways in railroad = 6,135.8 m/s

To shoot a swimming fish with an intense light beam from a laser gun, you should aim slightly below the actual position.

The answer to this question lies in the physics of light and the refraction that occurs when light travels from one medium to another. When light passes through water, it is refracted or bent due to the difference in the refractive indices of water and air.Therefore, to shoot a swimming fish with an intense light beam from a laser gun, you should aim slightly below the image of the fish. This is because the laser beam will also be refracted upon entering the water, and aiming slightly below the image compensates for the refraction and ensures that the laser beam hits the actual position of the fish. It is also important to note that shooting a swimming fish with a laser gun is not only illegal in most places but also unethical and harmful to the environment. Therefore, it is essential to prioritize the safety and conservation of aquatic life over any personal desires or interests.

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As the force of gravity pulls gas particles closer together, the density and pressure of the gas will increase. This is because the gas particles become more closely packed, occupying a smaller volume, which leads to an increase in density. The increased density results in more frequent collisions between gas particles, causing an increase in pressure.

The temperature of the gas, however, does not necessarily increase as a direct result of the force of gravity pulling the gas particles closer together. Temperature is a measure of the average kinetic energy of the gas particles, and it is related to their speed of motion. While the compression of the gas by gravity can potentially increase the average kinetic energy of the gas particles, it does not necessarily imply an increase in temperature. Other factors, such as the addition or removal of heat from the system, can influence the gas temperature.

Therefore, in the given scenario, only density and pressure are directly increased by the force of gravity acting on the gas particles.

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Answer:

Approximately \(0.033\; {\rm m\cdot min^{-1}}\) (meters per minute.)

Explanation:

Let \(A\) and \(B\) denote the bottom and top width of the trough, respectively. It is given that \(A = 30\; {\rm cm} = 0.30\; {\rm m}\) and \(B = 80\; {\rm cm} = 0.80\; {\rm m}\). Let \(H\) denote the height of this trough; \(H = 50\; {\rm cm} = 0.50\; {\rm m}\).

Let \(h\) denote the current depth of the water in this trough.

Let \(b\) denote the current width of the surface of the water. As water fills the trough, this width increases from \(A = 0.30\; {\rm m}\) (width of bottom of trough) to \(B = 0.80\; {\rm m}\) (width of top of trough.)

The relationship between \(b\) and \(h\) is linear:

\(\displaystyle b = \frac{h}{H}\, (B - A) + A\).

Cross-section area of water in this trough:

\(\begin{aligned}(\text{area}) &= \frac{1}{2}\, (A + b) \, h \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h \\ &= A\, h + \frac{1}{2\, H} (B - A)\, h^{2}\end{aligned}\).

Let \(L\) denote the length of this trough; \(L = 10\; {\rm m}\).

Let \(v\) denote the volume of water in this trough:

\(\begin{aligned}v &= (\text{area})\, L \\ &= \frac{1}{2}\, (A + b) \, h\, L \\ &= \frac{1}{2}\, \left(A + \frac{h}{H}\, (B - A) + A\right)\, h\, L \\ &= A\, L\, h + \frac{L}{2\, H} (B - A)\, h^{2}\end{aligned}\).

Differentiate both sides implicitly with respect to \(v\):

\(\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}\left[A\, L\, h + \frac{L}{2\, H}\, (B - A)\, h^{2}\right]\).

\(\displaystyle \frac{d}{dv}[v] = \frac{d}{dv}[A\, L\, h] + \frac{d}{dv}\left[\frac{L}{2\, H}\, (B - A)\, h^{2}\right]\).

\(\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{2\, H}\, (B - A)\, 2\, h\, \frac{dh}{dv}\).

(Note that \(A\), \(B\), \(L\), and \(H\) are constants.)

Rearrange this equation to obtain:

\(\displaystyle 1 = A\, L\, \frac{dh}{dv} + \frac{L}{H}\, (B - A)\, h\, \frac{dh}{dv}\).

\(\displaystyle 1 = \left(A\, L + \frac{L}{H}\, (B - A)\, h \right)\, \frac{dh}{dv}\).

\(\displaystyle \frac{dh}{dv} = \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\).

Let \(t\) denote time. It is given that the trough is being filled at a rate of \(0.2\; {\rm m^{3}\cdot min^{-1}}\). In other words:

\(\displaystyle \frac{dv}{dt} = 0.2\; {\rm m^{3}\cdot min^{-1}}\).

Apply the chain rule to find the rate at which \(h\) is changing with respect to time \(t\):

\(\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \end{aligned}\).

Substitute in \(A = 0.30\; {\rm m}\), \(L = 10\; {\rm m}\), \(H = 0.50\; {\rm m}\), \(B = 0.80\; {\rm m}\), \(h = 0.30\; {\rm m}\) (converted from \(30\; {\rm cm}\)), and that the rate of change in \(v\) is \(0.2\; {\rm m^{3}\cdot min^{-1}}\):

\(\begin{aligned} \frac{dh}{dt} &= \frac{dh}{dv}\cdot \frac{dv}{dt} \\ &= \frac{1}{\displaystyle A\, L + \frac{L}{H}\, (B - A)\, h}\cdot \frac{dv}{dt} \\ &= \frac{0.2\; {\rm m^{3}\cdot min^{-1}}}{\displaystyle 0.30\; {\rm m} \times 10\; {\rm m} + \frac{10\; {\rm m}}{0.60\; {\rm m}}\, (0.80\; {\rm m} - 0.30\; {\rm m}) \, 0.30\; {\rm m}} \\ &=0.033\; {\rm m\cdot min^{-1}} \end{aligned}\).

In other words, the depth of the water in this trough increases at a rate of approximately \(0.033\; {\rm m \cdot min^{-1}}\) (meters per minute.)

To calculate the height of the cliff and the time it takes for the rock to reach the ground when thrown straight down, we can use the equations of motion.

(a) Height of the cliff:

When the rock is thrown straight up, it reaches its highest point before falling back down. The time it takes for the rock to reach its highest point is equal to the time it takes for the rock to fall back down to the ground.

Using the equation:

s = ut + (1/2)at^2

Where:

s is the distance traveled (height of the cliff),

u is the initial velocity (8.19 m/s),

t is the time (2.32 s),

a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).

Rearranging the equation:

s = ut + (1/2)at^2

s = (8.19)(2.32) + (1/2)(-9.8)(2.32)^2

s = 19.004 - 25.798

s = -6.794 m

Since the height of a cliff cannot be negative, we take the absolute value of the result:

Height of the cliff = |s| = 6.794 m

So, the height of the cliff is approximately 6.794 meters.

(b) Time to reach the ground when thrown straight down:

When the rock is thrown straight down with the same speed, the initial velocity (u) is still 8.19 m/s, but the acceleration due to gravity (a) remains -9.8 m/s^2.

Using the equation:

s = ut + (1/2)at^2

Where:

s is the distance traveled (height of the cliff, which is now negative),

u is the initial velocity (8.19 m/s),

t is the time we want to find,

a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).

Substituting the known values:

-6.794 = (8.19)t + (1/2)(-9.8)t^2

Rearranging the equation:

-6.794 = 8.19t - 4.9t^2

Rearranging further:

4.9t^2 - 8.19t - 6.794 = 0

Solving this quadratic equation, we find two possible values for t: 0.828 seconds and 1.303 seconds. Since we are considering the time it takes to reach the ground, the valid solution is t = 0.828 seconds.

Therefore, when the rock is thrown straight down, it takes approximately 0.828 seconds to reach the ground.

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The initial center mass of the two bricks is 2 kg.

The center mass of the two bricks is determined by combining the momentum of the two bricks, with one as the reference point.

The initial center mass of the two bricks is calculated as follows;

\(M_{cm} = \frac{M_0 + M_1}{v_1 + v_2} \\\\M_{cm} = \frac{5(0) \ + \ 2(3)}{0 + 3} \\\\M_{cm} = 2 \ kg\)

Thus, the initial center mass of the two bricks is 2 kg.

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The following values indicates the amount of work the net force acts on a 5 kg object, speeding the object up from 2.0 m/s to 6.0 m/s that performs on the object = 80 J (option C)

The amount of work performed by the net force on the object can be calculated using the formula:

W = F x d

Where:

W is the work (J)

F is the net force (N) and

d is the displacement of the object (m)

We can also use the formula for kinetic energy to find the amount of work performed.

KE = ½ mv²

The change in kinetic energy of the object is equal to the work done on it.

Initial kinetic energy

=  ½ x 5 kg x (2.0 m/s)²

= 10 J
Final kinetic energy

= ½ x 5 kg x (6.0 m/s)²

= 90 J
Hence, the change in kinetic energy (work done) = Final kinetic energy - Initial kinetic energy

= 90 J - 10 J

= 80 J

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Answer:

Explanation:

The elastic potential energy equation is EPE = (1/2) k x2, where k is the spring constant and x the distance from equilibrium. EPE = (0.5)*(26.6 N/m)*(0.0600 m)2 = 0.0479 Joules.

Answer:

No

Explanation:

They aren't because 99% molecules that ARE the same all LOOK the same, and some of them have 2 white things, some have 1, and some i see even have 3. so i would definitely say that no, they aren't all the same