In the diagram, q₁, q2, and q3 are in a straight line. Each of these particles has a charge of -2.35 x 10-⁶ C. Particles q₁ and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. What is the net force on particle q₁?​

ANSWERED: -6.21 N

In The Diagram, Q, Q2, And Q3 Are In A Straight Line. Each Of These Particles Has A Charge Of -2.35 X

Answers

Answer 1
To calculate the net force on particle q₁, we can use Coulomb's law to find the magnitude of the force between q₁ and q₂, as well as the force between q₁ and q₃. The force between two charges is given by:

F = k * (q₁ * q₂) / r²

where k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.

Using this formula, we can find that the magnitude of the force between q₁ and q₂ is:

F₁₂ = k * (q₁ * q₂) / r₁₂² = (9 x 10⁹ N m²/C²) * ((-2.35 x 10⁻⁶ C)² / (0.100 m)²) = 5.54 x 10⁻⁴ N

Similarly, the magnitude of the force between q₁ and q₃ is:

F₁₃ = k * (q₁ * q₃) / r₁₃² = (9 x 10⁹ N m²/C²) * ((-2.35 x 10⁻⁶ C)² / (0.100 m)²) = 5.54 x 10⁻⁴ N

Since the charges q₂ and q₃ are equal in magnitude and opposite in sign, they will produce equal and opposite forces on q₁, which cancel each other out. Therefore, the net force on q₁ is:

F_net = F₁₂ + F₁₃ = (5.54 x 10⁻⁴ N) + (5.54 x 10⁻⁴ N) = 1.11 x 10⁻³ N

The direction of this force will be towards q₂, since the force between q₁ and q₂ is attractive. Therefore, the correct answer to the question is that the net force on particle q₁ is -1.11 x 10⁻³ N.

Related Questions

Which equation shows the mathematical relationship between the frequency and the period of a wave?

A. f = T - 1
B. T = 2f
C. f = T
D. T = 1 / f

Answers

Answer:

d,.......just did it in a.pex

Answer:

D. T = 1 / f

Explanation:

A.P.E.X.

B. Write short notes on:
1. Horticulture
2. Pisciculture
3. Aviculture
4. Veterinary science
5. Intensive farming.

Answers

1. Horticulture is the agriculture of plants, mainly for food, materials, comfort and beauty for decoration.

2.Pisciculture also known as fish farming is the rearing of fish for food in enclosures such as fish ponds or tanks.

3.Aviculture is the practice of keeping and breeding birds, especially of wild birds in captivity. Aviculture is generally focused on not only the raising and breeding of birds, but also on preserving avian habitat, and public awareness campaigns.

4. Veterinary medicine is the branch of medicine that deals with the prevention, control, diagnosis, and treatment of disease, disorder, and injury in animals. Along with this, it also deals with animal rearing, husbandry, breeding, research on nutrition and product development.

5. Intensive agriculture, also known as intensive farming and industrial agriculture, is a type of agriculture, both of crop plants and of animals, with higher levels of input and output per cubic unit of agricultural land area.

Hope this helps.

Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 25.0 m above water with an initial speed of 20.0 m/s strikes the water with a final speed of what, independent of the direction thrown.

Answers

Complete question is;

Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 25.0 m above water with an initial speed of 20.0 m/s strikes the water with a final speed of 31.1 m/s, independent of the direction thrown

Answer:

It is proved that the final speed is truly 31.1 m/s

Explanation:

From energy - conservation principle;

E_i = Initial potential energy + Initial Kinetic Energy

Or

E_i = U_i + K_i

Similarly, for final energy

E_f = U_f + K_f

So, expressing the formulas for potential and kinetic energies, we now have;

E_i = (m × g × y_i) + (½ × m × v_i²)

Similarly,

E_f = (m × g × y_f) + (½ × m × v_f²)

We are given;

y_i = 25 m

y_f = 0 m

v_i = 20 m/s

v_f = 31.1 m/s

So, plugging in relevant values;

E_i = m((9.8 × 25) + (½ × 20²))

E_i = 485m

Similarly;

E_f = m((9.8 × 0) + (½ × v_f²)

E_f ≈ ½m•v_f²

From energy conservation principle, E_i = E_f.

Thus;

485m = ½m•v_f²

m will cancel out to give;

½v_f² = 485

v_f² = 485 × 2

v_f² = 970

v_f = √970

v_f ≈ 31.1 m/s

What net force would be required to accelerate a 5 Kg object 2 m/s2? [show all work, including the

equation, substitutions with units, and answer with units]

Answers

Answer:

10 Newtons.

Explanation:

F=MA

F=(5kg)(2 m/s^2)

10 N

People are good at learning to recognize _______________. *
A.stars
B.constellations
C. patterns
D. Orion
E. Casseopia
F.look
G. distance
H.rotates

*Fill in the blank*

help <3 Please and thanks :>

Answers

Answer:

A

Explanation:

I would assume it’s B because we know a lot of constellations and we know how to recognize them

An 12.000 milligram particle is sliding across a friction-less one-dimensional path at 55.000 m/s and collides with a 68.000 milligram particle moving at -48.000 m/s in a perfectly inelastic collision. What are the velocities of the particles after the collision?
answer with correct units​

Answers

Answer:

-3525.000 m/s

Explanation:

In a perfectly inelastic collision, the two particles stick together and move with a common velocity after the collision. We can use the conservation of momentum to solve for this common velocity.

The initial momentum of the system is:

p_initial = m1 * v1 + m2 * v2

= (12.000 mg)(55.000 m/s) + (68.000 mg)(-48.000 m/s)

= -282.000 kg·m/s

Here, we convert the masses to kilograms to match the units of velocity.

Since the particles stick together after the collision, their masses add up:

m_final = m1 + m2

= 12.000 mg + 68.000 mg

= 80.000 mg

= 0.080 g

Now, we can use the conservation of momentum to find the final velocity:

p_final = m_final * v_final

where p_final = p_initial and m_final = 0.080 g.

Therefore:

v_final = p_final / m_final

= -282.000 kg·m/s / 0.080 g

= -3525.000 m/s

How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?

Answers

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

Exercise 3.3 - Enhanced - with FeedbackA web page designer creates an animation in which adot on a computer screen has positionPart Ar = [4.0 cm + (2.5 cm/s^2) t^2] i + (5.0 cm/s) tjFind the magnitude of the dot's average velocity between t = 0 and t = 2.0 s.Express your answer with the appropriate units.КА?pore ValueUnitsSubmitRequest AnswerPart BFind the direction angle of the dot's average velocity between t = 0 and t = 2.0 s. The angle is measured counterclockwise from+x-axis toward the +y-axis.Express your answer in degrees.

Answers

Gievn:

\(r^{\prime}^{\prime}=\lbrack4.0\operatorname{cm}+(2.5\operatorname{cm}/s^2)t^2\rbrack\text{ i +(5.0cm/s)tj}\)

Part A.

Let's find the magnitude of the dot's average velocity between t = 0 and t = 2.0s.

At t = 0:

Substitute 0 for t

\(\begin{gathered} r_1=\lbrack4.0\operatorname{cm}+(2.5\operatorname{cm})0^2\rbrack i+(5.0\operatorname{cm})(0)j \\ \\ r_1=4.0\operatorname{cm}i+0\operatorname{cm}j \end{gathered}\)

At t = 2:

Substitute 2 for t

\(\begin{gathered} r_2=\lbrack4.0\operatorname{cm}+(2.5\operatorname{cm})2^2\rbrack i+(5.0\operatorname{cm})(2)j \\ \\ r_2=\lbrack4.0\operatorname{cm}+10.0\operatorname{cm}\rbrack i+10.0\operatorname{cm}j \\ \\ r_2=14.0\operatorname{cm}i+10.0\operatorname{cm}j \end{gathered}\)

To find the magnitude of the dot's average velocity, apply the formula:

\(\begin{gathered} V_{ar}=|\frac{r_2-r_1}{t_2-t_1}| \\ \\ V_{ar}=|\frac{(14.0\operatorname{cm}i+10.0\operatorname{cm}j)-(4.0\operatorname{cm}i+0\operatorname{cm}j)}{2-0}| \\ \\ V_{ar}=|\frac{14.0\operatorname{cm}i-4.0\operatorname{cm}i+10.0\operatorname{cm}j-0\operatorname{cm}j}{2-0}| \\ _{} \\ \\ V_{ar}=|\frac{10.0\operatorname{cm}i+10.0\operatorname{cm}j}{2}| \\ \\ V_{ar}=|\frac{10.0\operatorname{cm}i}{2}+\frac{10.0\operatorname{cm}j}{2}| \\ \\ V_{ar}=|5.0\operatorname{cm}i+5.0\operatorname{cm}j| \\ \\ V_{ar}=\sqrt[]{5^2+5^2} \\ \\ V_{ar}=\sqrt[]{25+25} \\ \\ V_{ar}=\sqrt[]{50} \\ \\ V_{ar}=7.1\operatorname{cm}\text{ /s} \end{gathered}\)

Therefore, the magnitude of the dot's average velocity is approximately 7.1 cm/s.

Part B.

FInd the direction angle of the dot's average velocity between t = 0s and t = 2.0 s.

To find the direction angle between t = 0s and t = 2.0s, we have:

\(\begin{gathered} \tan V_{ar}=\frac{25}{25} \\ \\ \tan V_{ar}=1 \end{gathered}\)

Take the inverse tangent of both sides:

\(V_{ar}=\tan ^{-1}(1)=45^{\circ}\)

Therefore, the direction of the dot's average velocity between t = 0 and t = 2.0 s is 45 degrees.

ANSWER:

• a) 7.1 cm/s

• b) 45 degrees.

An object experiences a constant change in velocity in free fall.

True False

Answers

false, it experiences a constant change in ACCELERATION in free fall.

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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These three bulbs are powered by the battery. What will happen if the middle light burns out? A. The two other bulbs will go out. B. The two other bulbs will stay on. C. Just the bulb closest to the battery will stay on. D. Just the bulb farthest from the battery will stay on.

Answers

Answer:

C

Explanation:

Can you help me please! Love you​

Can you help me please! Love you

Answers

Answer:

I think its B. wait...U love ME?????

Use the following scenario to answer the question. T'Keyah puts salt in ice water and then in boiling water to see which will dissolve faster. Which dissolving rate factor is she testing in these tests? (1 point) O solubility O agitation O particle size o tellmperature​

Answers

Answer:

O Temperature

Explanation:

To see which would dissolve faster it would have to deal with temperature.

Which vector is the sum of vectors a and ?
b
а
O
A.
B.
C.

Which vector is the sum of vectors a and ?bOA.B.C.

Answers

Answer:

i would say D.

Explanation:

The sum of the given vector is option B as it is showing proper magnitude and direction.

What is a vector?

A Euclidean vector, also known as a geometric vector or spatial vector, is a geometric entity with magnitude (or length) as well as direction in arithmetic, physics, and engineering.

Vector algebra allows vectors to be added to other vectors.

Physical concentrations can be represented using vectors. Vectors are most frequently used in physics to represent displacement, velocity, and acceleration.

Vectors are arrows that represent an amalgamation of magnitude and direction.

The operation of combining two or more vectors into a vector sum is known as vector addition.

The rule for vector addition of two or more vectors is given by the so-called parallelogram law.

Thus, the correct option is B as it is having magnitude and direction.

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A power plant burns coal to generate electricity. Suppose that 1000 J of heat (Q) from the coal fire enters a boiler, which is kept at a constant temperature of 900 C. That 1000 J is used to boil water in a boiler. The steam from the boiler is used to drive a turbine that creates electricity (work). The excess heat is put into a cooling tower at 5 C.
Carnot efficiency If everything is perfectly efficient,
• What is the maximum efficiency that the plant could operate at?
• How much work could be done starting from that 1000 J?

Answers

Answer:

The work done will be "763 J". A further explanation is given below.

Explanation:

The given values are:

\(Q_1=1000 \ J\)

Temperature,

\(T_1=900^{\circ} C\)

i.e,

    \(=1173\)

\(T_2=5^{\circ}C\)

i.e.,

    \(=278\)

As we know,

⇒  \(\eta =1-\frac{T_2}{T_1}\)

On substituting the values, we get

⇒     \(=1-\frac{278}{1173}\)

⇒     \(=\frac{1173-278}{1173}\)

⇒     \(=\frac{895}{1173}\)

⇒     \(=0.763\)

then,

⇒  \(W=\eta Q_1\)

⇒       \(=0.763\times 1000\)

⇒       \(=763 \ J\)

A 3-kg toy cart is moving at 4 m/s. Calculate the kinetic energy of this cart if it were moving TWICE as fast.

Answers

Answer:

96 J

Explanation:

KE = (1/2) mv^2

m= 3kg

v= 4 m/s

(We have to calculate the KE of the cart when it is moving twice as fast, so 4x2=8, v=8m/s.)

KE = (1/2)(3kg)(8^2) = 96J

The kinetic energy of the cart moving with twice speed is 96 Joules.

Kinetic Energy

The kinetic energy of an object of mass m and velocity v is given below.

\(KE = \dfrac {1}{2}mv^2\)

Given that the mass of the toy is 3 kg and velocity is 4 m/s. The kinetic energy of the cart which is moving twice its original speed is given below.

\(KE = \dfrac {1}{2}m\times (2v)^2\)

\(KE = \dfrac {1}{2}\times 3\times (2\times 4)^2\)

\(KE = 96 \;\rm J.\)

Hence we can conclude that the kinetic energy of the cart moving with twice speed is 96 Joules.

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https://brainly.com/question/999862.

A bullet traveling at 5.0 x10^2 meters per is brought to rest by an impulse of 50 Newton*seconds. Find the mass of the bullet.

Answers

The bullet stops moving on hitting on a surface. Hence, the impulse here is equal to the momentum. Therefore, the mass of the bullet is 0.1 Kg.

What is impulse?

Impulse in physics is the change in momentum. It is the product of the force and change in time.

hence, impulse = f. dt

When the bullet is travelling with  a velocity of 500 m/s it has a momentum. When it brought to rest, momentum become zero. Thus, the momentum is equal to the impulse here.

Therefore, f.dt = m. v

f.dt = 50 N s

v = 500 m/s

m = 50 N s/500 m/s = 0.1 Kg

Therefore, the mass of the bullet is 0.1 Kg.

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Question 1 of 25
Two asteroids with masses 3.71 x 10 kg and 1.88 x 104 kg are separated by
a distance of 1,300 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity
Gm, 2 The gravitational
constant Gis 6.67 x 10-11 Nm²/kg?
A. 275 x 10"N
B. 4.13 x 10°N
C. 2.04 x 10°N
O D. 3.58 x 10-N
SUBMIT

Answers

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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A force of 250 N is exerted on a cable wrapped around a drum with a diameter of 20 cm. What is the torque produced about the centre of the drum?​

Answers

The torque that is produced at the center of the drum is 50 Nm.

What is a torque?

The term torque has to do with a force that leads to a turning effect. I can use the example of a tap to show you what is meant by a torque. The force that is exerted on a tap causes the tap to turn and this is what we mean by saying that a torque would produce a turning effect.

We have the following;

Force = 250 N

Distance = 20 cm or 0.2 m

Torque = 250 N  *  0.2 m

= 50 Nm

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why must a laboratory thermometer be left in place to take a reading 

Answers

Answer:

I don't know why?? is this a homework question or a riddle?

Which system regulates involuntary muscles and internal organs?


parasympathetic system

somatic system

autonomic system

sympathetic system

Answers

C, the autonomic system :)

what is the process that creates wind.

Answers

Answer:

Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.

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A ball is launched with a velocity of magnitude 10.0 m/s, at an angle of 50.0° to the horizontal.The launch point is at the base of a ramp of horizontal length d1 6.00 m and height d2 3.60 m. A plateau is located at the top of the ramp.

Required:
a. Does the ball land on the ramp or the plateau? When it lands.
b. What are the magnitude and angle of its displacement from the launch point?

Answers

Answer:

Kindly check explanation

Explanation:

Given the following :

Initial Velocity (u) = 10m/s

Angle (θ) = 50°

Horizontal length d1 = 6m

Height d2 = 3.6m

g = acceleration due to gravity = 9.8m/s²

Horizontal component :

X = U× cosΘ = 10 × cos 50 = 10 × 0.6429 = 6.43t

X = 6.43t

Vertical component :

Y = Usinθ - 1/2gt² = 10 ×sin 50 - 1/2(9.8)t² = 7.66t - 4.9t²

From X :

t = X / 6.43

Hence,

Y = 7.66(X/6.43) - 4.9(X/6.43)²

Y = 1.19X - 0.12X²

Slope of ramp Y':

(3.6 ÷ 6)X = 0.6X

Hence,

Y = Y'

1.19X - 0.12X² = 0.6X

-0.12X² = 0.6X - 1.19X

-0.12X² = - 0.59X

X² / X = 0.59 / 0.12

X = 4.92 m

Ball hits the ramp as X is < 6m

A solid sphere with a diameter of 0.20 m is released from rest; it then rolls without slipping down a ramp, dropping through a vertical height of h1 = 0.49 m. The ball leaves the bottom of the ramp, which is h2 = 1.31 m above the floor, moving horizontally.
(a) Through what horizontal distance d does the ball travel before landing?
answer in m
(b) How many revolutions does the ball make during its fall?
answer in rev

Answers

(a) To find the horizontal distance d that the ball travels before landing, we can use the equation d = (Vx)t, where Vx is the horizontal velocity of the ball and t is the time it takes for the ball to fall from the ramp to the floor.

First, we need to find the horizontal velocity of the ball when it leaves the ramp. Since the ball is rolling without slipping, we can use the equation V = ωR, where V is the linear velocity, ω is the angular velocity, and R is the radius of the ball. The radius of the ball is 0.20 m / 2 = 0.10 m.

Next, we need to find the angular velocity of the ball. We can use the equation ω = √(2gh/R), where g is the acceleration due to gravity (9.8 m/s^2), h is the vertical height that the ball drops (0.49 m), and R is the radius of the ball (0.10 m). Plugging in the values gives us:

ω = √(2(9.8)(0.49)/0.10) = 31.3 rad/s

Now we can find the horizontal velocity of the ball:

V = ωR = (31.3)(0.10) = 3.13 m/s

Finally, we can find the time it takes for the ball to fall from the ramp to the floor using the equation h = 0.5gt^2, where h is the vertical height (1.31 m) and g is the acceleration due to gravity (9.8 m/s^2). Rearranging the equation and plugging in the values gives us:

t = √(2h/g) = √(2(1.31)/9.8) = 0.52 s

Now we can find the horizontal distance d that the ball travels before landing:

d = (Vx)t = (3.13)(0.52) = 1.63 m

Answer: The ball travels 1.63 m before landing.

(b) To find the number of revolutions that the ball makes during its fall, we can use the equation θ = ωt, where θ is the angular displacement, ω is the angular velocity, and t is the time. The angular displacement is equal to the number of revolutions times 2π, so we can rearrange the equation to solve for the number of revolutions:

θ / 2π = ωt / 2π = (31.3)(0.52) / 2π = 2.59 rev

Answer: The ball makes 2.59 revolutions during its fall.

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types of polarization physics

Answers

Answer:

Linear polarization.

Circular polarization.

Elliptical polarization.

What does the atomic number of an atom tell us?

Answers

Answer:

The atomic number uniquely identifies a chemical element. It is identical to the charge number of the nucleus. In an uncharged atom, the atomic number is also equal to the number of electrons. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom.

Explanation:

Answer:

I believe that the atomic number of an atom represents the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element

Explanation:I hope that this is helpful.

Equipotential lines are usually shown in a manner similar to topographical contour lines, in which the difference in the value of consecutive lines is constant. Clear the equipotential lines using the Clear button on the voltage tool. Place the first equipotential line 1 m\rm m away from the charge. It should have a value of roughly 9 V\rm V. Now, produce several additional equipotential lines, increasing and decreasing by an interval of 3 V\rm V (e.g., one with 12 V\rm V, one with 15 V\rm V, and one with 6 V\rm V). Don�t worry about getting these exact values. You can be off by a few tenths of a volt.Which statement best describes the distribution of the equipotential lines?1-The equipotential lines are closer together in regions where the electric field is weaker.2-The equipotential lines are closer together in regions where the electric field is stronger.3-The equipotential lines are equally spaced. The distance between each line is the same for all adjacent lines.

Answers

Answer:

the correct one is 2. the equipotential lines must be closer together where the field has more intensity

Explanation:

The equipotential line concept is a line or surface where a test charge can move without doing work, therefore the potential in this line is constant and they are perpendicular to the electric field lines.

In this exercise we have a charge and a series of equipotential lines, if this is a point charge the lines are circles around the charge, where the potential is given by

           V = k q / r

also the electric field and the electuary potential are related

           E =  \(- \frac{dV}{dr}\)

therefore the equipotential lines must be closer together where the field has more intensity

When checking the answers, the correct one is 2

Draw a graph of velocity vs acceleration in arbitrary path.

Answers

The graph for velocity v/s acceleration in arbitrary path, is attached below.

What is the relation between velocity and acceleration?

Velocity and acceleration are both related to the motion of an object, but they represent different aspects of that motion.

Velocity is a vector quantity that represents the rate of change of an object's displacement over time. It is calculated as the change in position (displacement) divided by the time taken to make that change, and has both magnitude (speed) and direction.

Acceleration, on the other hand, is a vector quantity that represents the rate of change of an object's velocity over time. It is calculated as the change in velocity divided by the time taken to make that change, and also has both magnitude and direction.

The relation between velocity and acceleration is that acceleration is the rate at which an object's velocity is changing. If an object is accelerating, its velocity is changing over time. This means that if the acceleration is positive, the object's velocity is increasing, while if the acceleration is negative, the object's velocity is decreasing.

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Draw a graph of velocity vs acceleration in arbitrary path.
Draw a graph of velocity vs acceleration in arbitrary path.

1. What is Ohm"s law?
2. If you placed a negatively charged hairbrush near your hair, what charge would your hair be?
3. You must change a lightbulb and the new lightbulb has a larger resistance. If the voltage of the battery does not change, what happens to the current going through the flashlight?
HELLPPPP

Answers

1. Ohm's law shows the relationship between:

voltagecurrentresistance

Formula: voltage = current x resistance

2. The negative charge on the hairbrush will induce a positive charge on your hair. As a result, your hair is going to be attracted to the hairbrush (and repelled by other strands of hair.)

3. V = IR, so if the resistance of the current increases, and the voltage of the current stays the same, there is as a result, going to be less current.

Best of Regards!

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