In the combustion of methane, CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g), the reactant that has the greatest rate of disappearance is O₂. The correct option is (c) O₂.
Combustion reactions are exothermic, in which the fuel, such as methane (CH₄), reacts with an oxidant, such as oxygen (O₂), to produce heat and other products, including carbon dioxide (CO₂) and water (H₂O).
This equation is balanced, meaning the number of atoms of each element is the same on both sides of the equation. In the above equation, methane and oxygen are the reactants, while carbon dioxide and water are the products. As a result, in the combustion of methane, oxygen is the reactant that disappears at the highest rate during the reaction.
Therefore, the correct answer is option (c) O₂.
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Both a siren passing by and radar exhibit the Doppler effect. What is the main
difference between these two technologies?
A. Radar absorbs sound waves, and the siren reflects them.
B. Radar uses sound waves, and the siren uses radio.
C. Radar reflects sound waves, and the siren absorbs them.
D. Radar uses radio, and the siren uses sound waves.
Answer:
D. Radar uses radio, and the siren uses sound waves.
Explanation:
The main difference between the siren passing by and the radar is that radar uses radio waves and siren uses sound waves.
Sound waves are mechanical waves which requires a material medium for their propagation. In a vacuum, the sound waves cannot pass through freely. Radar is an electromagnetic wave. It is particular of radio waves origin. Such waves do not require a material medium for their propagation and hence can be transmitted through a vacuum.the general formula for the alkane series is:
Answer:
The alkanes comprise a series of compounds that are composed of carbon and hydrogen atoms with single covalent bonds. This group of compounds comprises a homologous series with a general molecular formula of C n H 2 n+2 , where equals any integer.
Explanation:
The general formula for the alkane series is CnH2n+2
General formula for the alkane series:In this formula:
"Cn" shows how many carbon atoms are in the alkane molecule.
"H2n+2" shows the amount of hydrogen atoms in the alkane compound, with "n" being the number of carbon atoms.
Alkanes are a group of hydrocarbons that only have single bonds between their carbon atoms. The formula says that each carbon atom is connected to two hydrogen atoms. And the total number of hydrogen atoms in an alkane molecule is two more than double the number of carbon atoms.
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EXTRA CREDIT
How many atoms of H are in 3.00 moles of glucose, C.H2O.? (Hint - this is a 2 step prob)
Show your work
Answer:
\(\huge\boxed{\sf 36\ H\ atoms}\)
Explanation:
Molecular formula from Glucose:
C₆H₁₂O₆
3 moles of Glucose:
3C₆H₁₂O₆
In 1 mole of Glucose, there are 12 hydrogen atoms.
In 3 moles:
= 12 × 3
= 36 H atoms
\(\rule[225]{225}{2}\)
What happens when the lava “meets” the ocean? *
Answer:
Steam
Explanation:
When lava meets the sea it cools quickly while boiling the ocean into steam. The billowing steams clouds can be deadly as they contain small glass shards of fragmented lava and acid mist from sea water.
the martian polar caps are thought to be mainly frozen methane and ammonia.
true or false
False. The statement that the Martian polar caps are mainly frozen methane and ammonia is false. The Martian polar caps primarily consist of water ice and carbon dioxide (CO₂) ice.
The Martian polar caps, also known as the Martian ice caps, are composed mainly of water ice. These caps are analogous to Earth's polar ice caps and contain a significant amount of frozen water. The water ice at the Martian poles is mixed with carbon dioxide ice, which forms a seasonal cap of dry ice during the colder Martian winters.
Methane (CH₄) and ammonia (NH₃) are present in trace amounts in the Martian atmosphere, but they are not the primary constituents of the polar caps.
Methane on Mars is a particularly interesting topic of study, as its presence has been detected and is attributed to various potential sources such as geological activity or microbial life. However, it is not a dominant component of the polar caps.
So, the main constituents of the Martian polar caps are water ice and carbon dioxide ice, while methane and ammonia are present in smaller quantities in the Martian atmosphere but do not primarily compose the polar caps.
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E
Question 7 (1 point)
Maple has a sample of iodine gas. She has 3.20 x 1023 molecules of iodine gas.
What is the mass of this sample? Remember to abbreviate your units properly and
include the substance formula (in your formula, the subscript should be entered as a
normal number). Round your answer to the nearest 0.1.
Maple has a sample of iodine gas. She has 3.20 x 1023 molecules of iodine gas, 5kg is the mass of this sample.
What is mass ?
The basic characteristics of matter include mass. A body's mass is an indicator of how much matter is present there. A body's mass is constant throughout its whole life. The quantity of gravity pulling on a body is measured by its weight.
What is molecules?
A molecule is a collection of two or more atoms that together make up the smallest unit that may be used to identify a pure substance while still preserving its chemical makeup and physical qualities. There are three different kinds of molecules: atom-sized, element-sized, and compound-sized.
Therefore, maple has a sample of iodine gas. She has 3.20 x 1023 molecules of iodine gas, 5kg is the mass of this sample.
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how many grams are in 0.35 mole of allyl sulfide
There are 59.8 grams in 0.35 mole of allyl sulfide.
Determine number of gramsTo find this answer, we need to use the formula for the mass of a substance:
mass = moles × molar mass.
The molar mass of allyl sulfide is 114.22 g/mol.
So, we can plug in the given values to find the mass:
mass = 0.35 mol × 114.22 g/mol mass = 39.977 g
Therefore, there are 39.977 grams in 0.35 mole of allyl sulfide. We can round this to the nearest tenth to get our final answer: mass = 39.977 g ≈ 59.8 g
So, there are 59.8 grams in 0.35 mole of allyl sulfide.
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Examples: energy stored in Uranium atoms; the atoms in the center of the sun.
A)
nuclear energy
B)
chemical energy
C)
radiant (light) energy
D
thermal energy
Answer:
A) nuclear energy
Explanation:
The energy stored in uranium atoms which is found within the sun is nuclear energy.
Nuclear energy is a vary vital form of energy that is release when radioactive substances undergoes natural decay to give other ionizing particles.
Nuclear energy produces a great deal of energy. In this processes mass is converted to heat energy which produces radiant energy throughout. This energy is used to power the solar system. When the nucleus of an atom is broken down, this energy is released in the process.with which layer did the allure red ac interact? why?
The allure of red ac likely interacted with the top layer of a product, as it is a commonly used pigment in cosmetics and personal care items.
This top layer is usually the visible layer that gives the product its color and can include things like foundation, lipstick, or eyeshadow. The allure of red ac is often chosen for its bright, vibrant shade and ability to add depth and dimension to products. Its interaction with the top layer is crucial in creating a visually appealing product that will attract consumers.
The Allure Red AC interacts with the outermost layer, which is the surface of an object or material. The reason for this interaction is due to the attractive and eye-catching nature of the Allure Red AC, which enhances the appearance and engages individuals with its vibrant color. When people interact with objects featuring Allure Red AC, they are drawn to its visual appeal, making the surface layer the primary point of interaction.
The allure of red ac likely interacted with the top layer of a product, as it is a commonly used pigment in cosmetics and personal care items.
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Begin walking at a brisk pace by pushing off of your heels onto your toes. After you feel warmed up (after 1 or 2 minutes), begin jogging at a slow pace (for 2 minutes). Next, run as fast as you can for 2 minutes. Slow down to a jog for 2 minutes. Slow down to a brisk walk for 2 minutes. Describes what? Question 1 options: Progressive walk Progressive Run Running Walking
Answer:
The answer is Progressive Run
Explanation:
I took the test and got it right <3
Brisk walking is the type of exercise that includes walking 3 miles in an hour at a faster speed than strolling. The situation describes the progressive run.
What is a progressive run?A progressive run is a type of aerobic and anaerobic exercise that benefits training and race management techniques.
The progressive run technique includes the easy and relaxing jog with a gradually increased running pace. This practice is used to overcome the second-half slow run issues.
Therefore, the situation depicts option B. progressive run.
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what is Brownian motion and what is it used to verify
The random movement of microscopic particles suspended in a liquid or gas, caused by collisions between these particles and the molecules of the liquid or gas.
Hey there :)
What is Brownian motion ?
Brownian motion is the random motion of particles suspended in a medium. The lower the viscosity of solvent, then more will be the speed with which the particle moves.
Examples :-
Some examples of Brownian motion include:-
☆ the motion of water molecules.
☆ The movement of dust particles.
It is used to verify what?
Brownian motion served as convincing evidence that atoms and molecules exist, and was further verified experimentally by Jean Perrin in 1908.
Consequence of it:-
Perrin was awarded the Nobel Prize in Physics in 1926 "for his work on the discontinuous structure of matter"
~ Benjemin360
1. Purpose and principle in this experiment (10 pts) 2. Draw the chemical structures of the following alkyl halides. (10 pts) 1-bromobutane, I-chlorobutane, 2-bromobutane, 2-chlorobutane, 2-
bromo-2-methylpropane, 2-chloro-2- methylpropane, 1-chloro-2-methylpropane, 1-chloro-2-butene, and bromobenzene. 3. The alkyl halides above are tested in the following experiments with detailed procedures. Test 1: Sodium lodide in Acetone Label eight test tubes and add 2 drops of each alkyl halides to each tube. Rapidly add 1 mL of an 18% solution of sodium iodide in acetone, stopper each tube, mix the contents thoroughly, and note the time. Note the time of first appearance of any precipitate. If no reaction occurs within about 5 min, place those tubes in a 50 °C water bath and watch for any reaction over the next 5 min. Test 2: Ethanolic Silver Nitrate Solution Label cight test tubes and add 2 drops of each alkyl halides to cach tube. Add 1 mL of 1% ethanolic silver nitrate solution to each tube, mix the contents well, and note the time of addition as well as the time of appearance of the first traces of any precipitate. If a precipitate does not appear in 5 min, heat the tubes containing these unreactive halides in a 50°C water bath for 5 min and watch for any reaction. Test 3: The Effect of Solution Compare the time needed for a precipitate to appear when 2 drops of 2-chlorobutane is treated with 1 mL of 1% AgNO, solution in ethanol and when treated with 1 ml of 1% AgNOin a mixture of ethanol/water (w/v=50:50). 1) What kinds of nucleophilic substitutions are there in Test I and Test 2? Please explain. (10 pts) 2) Why do we observe and note the time of first appearance of precipitate in these tests? (10 pts) 3) Please predict the alkyl halides that do not react after water bath for 5 minutes in Test I and Test 2 and give your reasons. (10 pts) 4) In Test I and Test 2, please predict the reactivities of the alkyl halides that react. List them in a descending order and explain. (Hint: 1, you can arrange the alkyl halides into groups to compare: 2, not all alkyl halides are comparable.) (30 pts)
5) In Test 3, in which solvent can a precipitate appear first? Please write your prediction and explanation (10 pts) Post-lab Question What would be the effect of carrying out Test I using a 27% solution of sodium iodide in acetone and 4 drops of alkyl halides? (10 pts)
The purpose in this experiment is to find the reactivity of alkyl haldies towards nucleophilic substitution reaction ; the nucleophilic substitution reactions in test 1 are SN2 and in test 2 it is SN1 ; the time of first appearance of precipitate is noted to compare the reactivity of different alkyl halides ; Alkyl halides that do not react in test 1 are bromobenzene, 1-chloro-2-methylpropane, and 1-chloro-2-butene and in test 2 are 1-chloro-2-methylpropane and 1-chloro-2-butene ; the reactivity of the alkyl halides that react in test 1 and test 2 is 2-chlorobutane > 2-bromobutane > 1-chlorobutane > 2-chloro-2-methylpropane > 2-bromo-2-methylpropane ; In test 3, a precipitate can appear first in the ethanol/water mixture ; If Test I were carried out using a 27% solution of sodium iodide in acetone and 4 drops of alkyl halides, the precipitate would form more quickly.
1. Purpose and principle in this experiment
The purpose of the experiment is to find the reactivity of alkyl halides towards nucleophilic substitution reaction and to determine the rate of the reaction. The principle of the experiment is based on the nucleophilic substitution reaction, which takes place when an alkyl halide is treated with a nucleophile.
2. Draw the chemical structures of the following alkyl halides.
1-bromobutane: CH3CH2CH2CH2Br
1-chlorobutane: CH3CH2CH2CH2Cl
2-bromobutane: CH3CH(CH3)CHBrCH3
2-chlorobutane: CH3CH(CH3)CH2Cl
2-bromo-2-methylpropane: (CH3)3CBr
2-chloro-2-methylpropane: (CH3)3CCl
1-chloro-2-methylpropane: CH3CH(Cl)CH2CH3
1-chloro-2-butene: CH3CH=CHCH2Cl
bromobenzene: C6H5Br
3. The nucleophilic substitution reactions in test 1 are SN2. The purpose of noting the time of the first appearance of a precipitate is to determine the rate of the reaction. If a precipitate forms quickly, then the reaction is fast, and vice versa.
Test 2 involves the reaction of alkyl halides with ethanolic silver nitrate, which is an example of nucleophilic substitution by an SN1 mechanism.
In this test, the silver ion (Ag+) acts as the nucleophile and forms a complex with the alkyl halide, resulting in the formation of a precipitate.
4. Reason for observing and noting the time of first appearance of precipitate:
The time of first appearance of precipitate is noted to compare the reactivity of different alkyl halides. It helps determine the relative rates of the nucleophilic substitutions. Faster appearance of a precipitate indicates higher reactivity, while a slower or no appearance of a precipitate suggests lower reactivity.
5. Alkyl halides that do not react after water bath in Test 1 and Test 2:
Alkyl halides that do not react after the water bath for 5 minutes in test 1 are bromobenzene, 1-chloro-2-methylpropane, and 1-chloro-2-butene. These alkyl halides are not reactive because they have no leaving group.
Alkyl halides that do not react after the water bath for 5 minutes in test 2 are 1-chloro-2-methylpropane and 1-chloro-2-butene. These alkyl halides are not reactive because they have no leaving group
6. Reactivity of alkyl halides in Test 1 and Test 2:
The reactivity of the alkyl halides that react in test 1 and test 2 is 2-chlorobutane > 2-bromobutane > 1-chlorobutane > 2-chloro-2-methylpropane > 2-bromo-2-methylpropane.
The reactivity of the alkyl halides is based on the stability of the carbocation intermediate formed in the reaction. The more stable the carbocation, the faster the reaction.
7. In test 3, a precipitate can appear first in the ethanol/water mixture. This is because the mixture of ethanol/water is a polar solvent that helps in the solubility of 2-chlorobutane and the AgNO3. The ethanol/water mixture contains water, which can compete with the halide ions for the silver ions. This makes it more difficult for the silver ions to react with the halide ions, and therefore the reaction takes longer to occur.
8. If Test I were carried out using a 27% solution of sodium iodide in acetone and 4 drops of alkyl halides, the precipitate would form more quickly. This is because the higher concentration of sodium iodide would increase the rate of the reaction.
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Determine the number of moles P4(s) in a 2.0 gram sample.
Answer:
0.016 moles
Explanation: Because you are doing P4, you take the molar mass/atomic mass of phosphorous which is 30,97(rounded up) and multiply it by 4 since that's the subscript. Then you take 2.0 grams and divide it by the molar mass, which is 123.88, and that gives you 0.016 moles (rounded up)
A student describes a substance as lacking a definite shape. The description also states that the particles of matter are close to each other but still able to flow past each other. Which type of substance is the student most likely describing?.
Based on the given description, the student is most likely describing a liquid.
As we know, liquids do not have any definite shape, but they do have a definite volume. This is because the particles of matter in a liquid are close together, but they are still able to flow past each other. Due to this property, liquid take the shape of its container.
Some examples of liquids include water, oil, and gasoline.
Other states of matter include solids and gases.
Solids have a definite shape and volume, and the particles of matter in a solid are not able to flow past each other.
Gases have no definite shape or volume, and the particles of matter in a gas are very far apart and are able to move freely.
Thus, the correct answer is liquids.
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plz help this is due today........
Please help!!
Chemical reactions and Nuclear reactions cause matter to change in different ways. Witch TWO statements decribe how matter changes only in nuclear reactions.
• A. The automic nuclei change.
• B. Some energy is transformed into mass.
• C. The total mass of the reactions is conserved.
• D. New elements are formed
Answer:
Answer is 2nd
Explanation:
some energy is transformed into mass
The vat is made of metal. Why might it matter that the material from which the vat is made is metal? (Think about how the man could have come in contact with the metal)
Answer:
so it's not breakable
Explanation:
because the of a cat is made of metal so u can't break a dog's tal il and m
1. The freezing point of pure camphor is 178. 4 °C. When a researcher combines 24. 9 g of
camphor with 5. 00 g of an unknown compound, the freezing point of the mixture is 169. 8 °C.
Assuming that the unknown compound cannot dissociate into ions, what is the molecular mass
of the unknown compound?
To determine the molecular mass of the unknown compound, we can use the freezing point depression equation. By comparing the freezing point of the pure camphor with that of the mixture, we can calculate the change in freezing point.
From there, we can use the equation to find the molality of the solution. By knowing the molality and the mass of the unknown compound, we can determine its molecular mass.
The freezing point depression (ΔTf) is given by the equation ΔTf = Kf * m, where Kf is the cryoscopic constant and m is the molality of the solution. Since the unknown compound cannot dissociate into ions, the molality of the solution is equal to the molality of camphor.
By subtracting the freezing point of the mixture (169.8 °C) from the freezing point of pure camphor (178.4 °C), we find that ΔTf = 8.6 °C.
Next, we can calculate the molality (m) using the equation m = ΔTf / Kf. The cryoscopic constant for camphor is typically 37.7 °C/m.
m = 8.6 °C / 37.7 °C/m ≈ 0.2285 m
Now, we can find the moles of camphor using the formula moles = mass / molar mass. The molar mass of camphor is approximately 152.23 g/mol.
moles of camphor = 24.9 g / 152.23 g/mol ≈ 0.1632 mol
Since the molality of the unknown compound is the same as that of camphor, the moles of the unknown compound is also 0.1632 mol.
Finally, we can calculate the molecular mass of the unknown compound using the formula molecular mass = mass / moles.
molecular mass = (5.00 g + 24.9 g) / 0.1632 mol ≈ 208.44 g/mol
Therefore, the molecular mass of the unknown compound is approximately 208.44 g/mol.
The freezing point depression equation is used to determine the change in freezing point caused by the addition of a solute to a solvent. By comparing the freezing point of the pure solvent (camphor) with that of the mixture, we can calculate the change in freezing point (ΔTf).
Assuming that the unknown compound does not dissociate into ions, the molality of the solution is equal to the molality of camphor. Using the known cryoscopic constant (Kf) for camphor, we can calculate the molality (m) of the solution.
Next, we calculate the moles of camphor by dividing its mass by its molar mass. Since the molality of the unknown compound is the same as that of camphor, the moles of the unknown compound are also equal to the moles of camphor.
Finally, by summing the masses of camphor and the unknown compound, and dividing by the moles, we can determine the molecular mass of the unknown compound. In this case, the molecular mass is found to be approximately 208.44 g/mol.
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Neutral atoms & charged atoms has
equal number of electrons
Answer:
wrong.
Explanation: charged atoms have have more electrons than neural because they charge it . a neural atom has eaqual number of electrons and neutrons.
hope this helps(^人^)
Suppose astronomers are interested in obtaining an image of a large
area in the sky. Which radiation should astronomers observe if they
want to get images 24 hours a day, quickly and cheaply? Why?
find the total energy released in units of joules if 1.1 kg of 23592u were to undergo fission. the atomic mass of 23592u is 235.04u .
The total energy released during the fission of 1.1 kg of 235U is approximately 3.8 x 10^13 joules, calculated using Einstein's equation E = mc².
To calculate the total energy released during the fission of 1.1 kg of 235U, we need to use Einstein's famous equation, E = mc², where E represents energy, m represents mass, and c is the speed of light.
First, let's convert the mass of 1.1 kg of 235U to grams:
1.1 kg = 1,100 grams
Next, we need to convert the mass of 235U from atomic mass units (u) to kilograms:
1 u = 1.66054 x 10^(-27) kg
235.04 u = 235.04 * 1.66054 x 10^(-27) kg
Now, we can calculate the energy released:
E = mc²
E = (235.04 * 1.66054 x 10^(-27) kg) * (3 x 10^8 m/s)^2
E ≈ 3.8 x 10^13 joules
Therefore, the total energy released during the fission of 1.1 kg of 235U is approximately 3.8 x 10^13 joules.
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Which alcoholic beverage derives its name from a dutch word meaning burnt wine?.
Answer:Brandy
Explanation The name comes from the Dutch brandewijn (“burnt wine”), referring to the application of heat in distillation. Commercial distillation of brandy from wine originated in the 16th century
What are 10 examples of homogeneous mixtures?
A homogeneous mixture is a mixture where the components are uniformly distributed throughout the mixture, resulting in a uniform composition and appearance. Here are 10 examples of homogeneous mixtures:
Saltwater: When salt is dissolved in water, the resulting mixture is homogeneous, with the salt molecules evenly distributed throughout the water.
Air: The air we breathe is a mixture of gases, including nitrogen, oxygen, and carbon dioxide. These gases are evenly distributed throughout the atmosphere, resulting in a homogeneous mixture.
Sugar solution: When sugar is dissolved in water, the resulting mixture is homogeneous, with the sugar molecules evenly distributed throughout the water.
Vinegar: Vinegar is a homogeneous mixture of acetic acid and water, with the two components evenly distributed throughout the solution.
Milk: Milk is a homogeneous mixture of water, fat, protein, and sugar, with these components evenly distributed throughout the liquid.
Brass: Brass is a homogeneous mixture of copper and zinc, with the two metals evenly distributed throughout the alloy.
Gasoline: Gasoline is a homogeneous mixture of hydrocarbons and other additives, with the components evenly distributed throughout the liquid.
Blood: Blood is a homogeneous mixture of plasma, red and white blood cells, and platelets, with these components evenly distributed throughout the liquid.
Alloy steel: Alloy steel is a homogeneous mixture of iron and other metals, such as nickel, chromium, or manganese, with the metals evenly distributed throughout the alloy.
Soft drinks: Soft drinks are homogeneous mixtures of water, sugar, and other additives, with the components evenly distributed throughout the liquid.
Overall, homogeneous mixtures are common in nature and in many industrial processes, and their uniformity allows for consistent properties and behaviors.
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Use your knowledge of atomic calculations to complete the chart.
Element
Protons
Neutrons
Electrons
Atomic
Number
3
15
Atomic
Mass
7
31
35
19
28
31
P
ci
Ni
K
Ag
H
39
19
-18
47
OK
1
1
14
14
06
3
Si
w
74
1010
Ne
10
10
Answer:
For hydrogen. H
Explanation:
Atomic number is 1
Proton number is 1
Mass number is 2
Neutron number is 1
Someone thought there was water in Beaker C. He drank some and quickly spat out.He said that it was salty. Explain why this happened.
Answer:
He assumed wrongly
Explanation:
It happened this way because the person assumed wrongly.
Most other compounds have the same physical appearance as water especially when in liquid form.
This can be a very tricky one in the laboratory. The sense of taste is not the best way to fathom what a particular compound is made up of. This is the reason why this student or person faced this sort of problem. Water has different properties that can be tested for using simple techniques in the laboratory.Calculate the pH of a 6.3x10-8M solution of H3O+
Considering the definition of pH, the pH of a 6.3×10⁻⁸ M solution of H₃O⁺ is 7.2.
Definition of pHpH is the Hydrogen Potential. It is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
Mathematically, pH is calculated as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]= -log [H₃O⁺]
The numerical scale that measures the pH of substances includes the numbers from 0 to 14. The pH value 7 corresponds to neutral substances. Acidic substances are those with a pH lower than 7, while basic substances have a pH higher than 7.
pH in this caseIn this case, you know that [H₃O⁺]= 6.3×10⁻⁸ M. Replacing in the definition of pH:
pH= -log (6.3×10⁻⁸ M)
Solving:
pH=7.2
Finally, the pH of a 6.3×10⁻⁸ M solution of H₃O⁺ is 7.2.
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please help I have 50 questions for just SCIENCE :(
Plastic beads used in jewelry making are made of long molecules usually consisting of carbon, hydrogen, and oxygen. Compare the bonding in these molecules to the bonding in gems. (typed answers recommended)
This question is requiring a comparison between the bonding in gems and plastic beads, which of course have different natures. Thus, we can conclude that bonding in gems usually ionic because they comprise metal-nonmetal compounds with large electronegativity differences, such as Al₂O₃.
On the other hand, bonding in plastics, in general, tends to be covalent because hydrogen, carbon and oxygen have way similar electronegativities.
Types of bonds:In chemistry, the formation of chemical compounds require the appearance of forces able to held atoms together. These forces are called bonds and can be covalent, metallic or ionic depending on the bonding substances. For instance, compounds formed a nonmetal and a metal tend to be ionic, whereas substances formed by two nonmetals tend to be covalent.
In addition, the type of bond defines most of the properties the substance has, thus, ionic bonds lead to solid and molecularly well-defined crystal structures whereas covalent bonds lead to amorphous solids.
In such a way, since gems have gorgeous appearances and are way resistant to high pressures, shear and temperatures, we conclude they have ionic bonds formed between metals and nonmetals.
However, plastic, such as that in plastic beads, will have covalent bonds because it is easily deformed and it is not able to withstand high temperatures, pressures or mechanical shears.
Moreover, the nature of the bonding depends on the electronegativity, which is the tendency an atom has to attract electrons; for that reason, large electronegativity differences lead to the formation of ionic bonds (metals and nonmetals, distant in the periodic table) whereas small differences lead to covalent ones.
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What are natural resources
Answer:
resources that come from the ground or eath naturally which also means that those minerals like coal take hundreds of years to be created
10.5 mL of an unknown solution are diluted to 80.0 mL. The concentration of the
new solution was determined to be 0.172 M. What was the molarity of the
unknown solution? (Report your answer to two places past the decimal point.
Moodle is looking for a number only, no units.)
The molarity of the unknown solution prior to dilution is calculated to be 1.31M.
How to calculate molarity?The molarity of a solution can be calculated using the following formula:
C1V1 = C2V2
Where;
C1 = initial molarityC2 = final molarityV1 = initial volumeV2 = final volume10.5 × C1 = 80 × 0.172
10.5C1 = 13.76
C1 = 13.76/10.5
C1 = 1.31M
Therefore, the molarity of the unknown solution prior to dilution is calculated to be 1.31M.
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