in the above problem involving 1200 kg car a moving at 70 km/h rear ending 900 kg car b moving at 60 km/h, when car b accelerates to 70 km/h, what fraction of ke is lost by car a?

The right answer is (d). Static friction can cause a system to do positive, negative, or even zero work.

Does static friction ever produce zero work?

At essence, static friction can also be active when a body is in equilibrium, when there is no movement and no static frictional work to be done.

Can static friction provide useful results?

This is because our force is opposed by the force of static friction. However, since the block stays there, there is no displacement. Therefore, friction produces no work. Friction can therefore produce positive, negative, or no work.

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Answer:

C. 4.0 J

Explanation:

Work is equal to the change in kinetic energy or kinetic energy final - kinetic energy initial. 1/2 mv^2 is the equation for kinetic energy. SInce the mass is the same, you don't have to include it when solving. 1/2 times 1^2 = 1/2. 1/2 times 3^2 = 4.5. 4.5 - 0.5 = 4 J

Answer:

kinetic energy

Explanation:

Answer:

D

Explanation:

because the slope decreases

Answer:

Should be D the correct answer

Explanation:

Answer:

I gonna give you the number so but you need to round 6.19047619048

Explanation:

A 65-year-old man's energy intake should focus on meals c.) with a lower caloric density and increased nutrient density

Calorie density represents a metric that is employed to determine how many calories are contained in a given amount of food. For a 65-year-old male, meals with a lower calorie density and a higher nutritional density would be ideal. People's metabolisms tend to slow down as they become older, so they need fewer calories.

To preserve their health, they still require enough nourishment, though. By choosing foods that are high in nutrients yet low in calories, such as fruits, vegetables, whole grains, lean proteins, and healthy fats, one may meet nutritional needs while limiting calorie intake. Adding more fibre to your diet can also help ya person to lose weight and maintain good digestive health.

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Answer:

An example would be, “If I grow grass seeds under green light bulbs, then they will grow faster than plants growing under red light bulbs.” Experiment – The fun part!

Explanation:

have a nice day.

Answer:

Explanation:

As a seismologist studying earthquakes in a particular region, you might expect to find certain features of the earth's crust in that region that are indicative of tectonic activity. Some examples of these features include:

Fault lines: These are fractures in the earth's crust where two tectonic plates have moved relative to each other, often resulting in earthquakes when the movement is sudden and violent.

Folded mountain ranges: When tectonic plates collide, the resulting pressure can cause the earth's crust to fold and form mountain ranges.

Volcanoes: Many earthquakes occur in regions with volcanic activity, as the movement of magma beneath the earth's surface can cause the ground to shake.

Plate boundaries: The boundary between two tectonic plates is often a zone of high seismic activity, as the plates grind against each other and cause earthquakes.

Seismic gaps: Some areas along a fault line may have experienced few or no earthquakes in recent history, and are therefore considered "seismic gaps." These areas may be more prone to earthquakes in the future as the pressure builds up.

By studying these and other features of the earth's crust, you can gain a better understanding of the underlying tectonic processes that contribute to earthquakes in the region.

Based on the above illustration, the required function is `x(t) = t²e⁻ᵗ / 2`.

Given: The equation is, `d²x/dt² + dx/dt = te⁻ᵗ`.

Required:

Find `x(t)` using Laplace Transforms.

Let us apply the Laplace transform to both sides of the equation.

d²x/dt² → s² X(s) - s x(0) - x'(0)dx/dt → s X(s) - x(0)x(0) is 0 as the object starts from rest.

Putting the given value, `d²x/dt² + dx/dt = te⁻ᵗ` in the Laplace transform of the equation, we get (s² X(s) - s x(0) - x'(0)) + (s X(s) - x(0)) = 1 / (s + 1)²

On solving the above equation for `X(s)`, we get `X(s) = 1 / (s + 1)³`

On taking the inverse Laplace transform, we get, `x(t) = t²e⁻ᵗ / 2`

Hence, the required function is `x(t) = t²e⁻ᵗ / 2`.

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Because the acceleration caused by gravity affects escape velocity. Therefore, the moon's escape velocity must be lower than that of the earth. Moreover, due to a lower escape velocity.

Ve therefore equals 11.2 km/s x 103 m/s. On Mars, the escape speed is approximately 40,270 kmph, or 11,186 m/s. For instance, when a rocket is used to propel a spacecraft into orbit, the velocity obtained must be higher than the orbital speed to prevent the rocket from returning to Earth.

Escape velocity is indeed the bare minimum speed at which a body must be propelled in order to escape the earth's gravitational pull. The smallest speed at which an object must move in order to escape the gravity field is.

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The current in the circuit would be approximately 13.33 Amps.

To find the current in the circuit, we can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R).

In this case, the resistance of each element is 36 ohms, and they are connected in parallel. When resistors are connected in parallel, the total resistance (Rt) can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3 + ...

1/Rt = 1/36 + 1/36

1/Rt = 2/36

1/Rt = 1/18

Rt = 18 ohms

To calculate the current (I) in the circuit, we can use Ohm's law:

I = V / Rt

I = 240 V / 18 ohms

I ≈ 13.33 Amps

The correct option is d. 13.3 Amps.

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Opera singer Caruso is said to have a made a crystal chandelier shatter with his voice. This is a demonstration of resonance.

The shattering of a crystal chandelier with a voice is an example of resonance. Resonance occurs when an object is forced to vibrate at its natural frequency by a sound wave with the same frequency. In this case, Caruso's voice produced sound waves that matched the natural frequency of the chandelier, causing it to vibrate and eventually shatter. Therefore, the answer is C. resonance.

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Answer:

Q = 8608.8 J

Explanation:

Given that,

The mass of ice, m = 34 g

The temperature changes from -2°C to 118°C​.

The specific heat of ice, c = 2.11 J/g°C

The heat energy needed,

\(Q=mc\delata T\\\\Q=34\times 2.11\times (118-(-2))\\Q=8608.8\ J\)

So, 8608.8 J of energy is needed.

To calculate the average deceleration of the bus, we can use the following formula:

Here, the initial velocity (v1) is 60 km/h, the final velocity (v2) is 40 km/h, and the time taken (t) is 8 seconds. To make the units consistent, we'll convert the velocities from km/h to m/s.

Now, we can plug the values into the formula:

Now, we'll find a common denominator for the fractions and simplify:

So, the average deceleration of the bus is approximately -150/216 m/s².

Answer:

It is located at the point where circles intersect on a map.

Explanation:

The name 'EPICENTER' was formed by a seismologist from Ireland can Robert Mallet.

An epicenter of an earthquake can be defined as the exact point in the center where as earthquake originated from.

An epicenter of an earthquake can also be defined as the point that is located directly above the focal point of an earthquake.

In other to be able to accurately determine the exact place where an earthquake happens, seismologist try to find out the distance of the earthquake from at least three seismic recording stations. The distance of the earthquake is obtained from a an equipment used by seismologist called seismograph. After obtaining the values if this distance, circles with the right radius are then drawn around each station. The point where the three circles meet or intersect shows us the earthquake's epicenter.

The statement which describes the location of an earthquake’s epicenter is: D. It is located at the point where circles intersect on a map.

An earthquake can be defined as a sudden, natural shaking of the ground, as a result of movements within the Earth's crust and upper mantle (lithosphere) that typically creates seismic waves.

A seismograph refers to an instrument that is designed and developed for detecting, monitoring and recording the direction, duration and magnitude (intensity) of an earthquake in a geographical location on planet Earth.

An epicenter is the point on the surface of planet Earth, which is perpendicular to the hypocenter (focus) and it indicates where the seismic waves from an earthquake are most intense.

On a map, an earthquake’s epicenter is located at the point where the three (3) circles intersect because earthquake are generally shallow.

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When two freely-falling objects with different masses are in free fall, their acceleration is the same due to gravity.

This occurs because gravity acts uniformly on all objects, regardless of their mass. In this context, the acceleration due to gravity is approximately 9.81 m/s² on Earth.

The relationship between mass, acceleration, and force can be explained using Newton's second law of motion, which states that the force (F) acting on an object is equal to its mass (m) multiplied by its acceleration (a):

F = m * a

Although the acceleration is the same for both objects, the force on each mass is not the same. Since the two objects have different masses, the force acting on each object will also be different, as per the equation above.

The object with the larger mass will experience a greater force due to gravity, while the object with the smaller mass will experience a lesser force.

In summary:

1. The acceleration of two freely-falling objects with different masses is the same because gravity acts uniformly on all objects.

2. The force on each mass is not the same, as it depends on the mass of the object according to Newton's second law of motion (F = m * a).

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Answer:

200 J

Explanation:

Given that,

Force, F = 20 N

Distance covered in the direction of force, d = 10 m

We need to find the effort made by Mrs. Lasarati. It  will be given by :

W = Fd

W = 20 N × 10 m

W = 200 J

So, the required effort made by Mrs. Lasarati is 200 J.

We can use the principle of conservation of energy to find the energy dissipated by friction.So the amount of energy dissipated by friction is approximately 610 J.

The energy dissipated by friction can be calculated using the work-energy principle, which states that the work done by all forces on an object is equal to the change in its kinetic energy. Since the kid starts from rest at the top of the slide and reaches a speed of 1.3 m/s at the bottom, the change in kinetic energy o find the work done by friction, we need to subtract the work done by gravity from the total work done:W_friction = W_total - W_gravity where W_gravity = mgh is the work done by gravity, m is the mass of the kid, g is the acceleration due to gravity, and h is the height of the slide.

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Answer:

The bowling ball has greater kinetic energy.

Explanation:

Kinetic energy is given by:

\( K = \frac{1}{2}mv^{2} \)

Where:

m: is the mass

v: is the speed

For the bowling ball we have:

\(K = \frac{1}{2}mv^{2} = \frac{1}{2}5 kg*(6 m/s)^{2} = 90 J\)

And for the ship:

\(K = \frac{1}{2}mv^{2} = \frac{1}{2}120000 kg*(0.02 m/s)^{2} = 24 J\)

Therefore, the bowling ball has greater kinetic energy.

I hope it helps you!

The average rate at which the cable does work is 294,000 J/s.

The given parameters:

The average rate at which the cable does work is calculated as follows;

\(P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{3000 \times 9.8 \times 200}{20} \\\\P = 294,000 \ J/s\)

Thus, the average rate at which the cable does work is 294,000 J/s.

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Answer:

whattt

Explanation:

Answer:

D

Explanation:

At the other end of the spectrum toward red, the wavelengths are longer and have lower energy.

Answer:

D

Explanation:

because the glaciers melt adding more water into the sea which make the sea levels rise.

Answer:

500m

Explanation:

100x5=500

then add the m

A The kinetic energy of particle A is 96.8 J.

b- The kinetic energy of particle B is 24.2 J.

The mass of particle A is 2.00 times the mass of particle B, we can represent the masses as mA = 2mB.

mA = 2mB

Total energy stored in the spring = 121 J

Let KA be the kinetic energy of particle A and KB be the kinetic energy of particle B.

From the mass ratio:

KA = (mA/mB)² × KB

KA = (2)² × KB = 4KB

Energy conservation equation:

KA + KB = 121 J

Substituting the value of KA:

4KB + KB = 121 J

5KB = 121 J

KB = 121 J / 5 = 24.2 J

Substituting this value back into the equation for KA:

KA = 4KB = 4 × 24.2 J = 96.8 J

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To determine the electric field at a point between two point charges, we can use Coulomb's law. Coulomb's law states that the electric field at a point due to a point charge is given by the equation:

E = k * (q /\(r^2\)),

where E is the electric field, k is the electrostatic constant (9 x\(10^9\)\(N·m^2/C^2\)), q is the charge, and r is the distance between the point charge and the point where the electric field is being measured.

In this case, we have two point charges: q1 = -25 μC and q2 = -50 μC, and they are placed 1.0 m apart. We want to find the electric field at a point midway between them.

First, let's calculate the electric field due to q1 at the midpoint. Using Coulomb's law, we have:

E1 = k * (q1 /\(r^2)\) = (9 x\(10^9\) N·m^2/C^2) * (-25 x\(10^{-6}\)C) / (0.5 m)^2 = -2.70 x 10^6 N/C towards q1.

Next, let's calculate the electric field due to q2 at the midpoint. Since q2 is twice the charge of q1, we expect the electric field to be twice as strong as that of q1:

E2 = 2 * E1 = 2 * (-2.70 x \(10^6\)N/C) = -5.40 x \(10^6\) N/C towards q1.

To find the total electric field at the midpoint, we add the electric fields due to q1 and q2:

\(E_total\) = E1 + E2 = -2.70 x \(10^6\)N/C + (-5.40 x \(10^6\) N/C) = -8.10 x\(10^6\) N/C towards q1.

Therefore, the correct answer is -8.10 x \(10^6\) N/C towards q1.

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Answer:

Approximately 26.33 m/s.

Explanation:

We can apply one of the four kinematic equations:

\(\displaystyle \Delta d = \frac{1}{2}\left( v_f + v_i\right)t\)

Since the car slides to a stop after traveling 7.9 meters in 0.6 seconds, Δd = 7.9, t = 0.6, and v_f = 0. Substitute and solve for v_i:

\(\displaystyle \begin{aligned} (7.9 \text{ m}) &= \frac{1}{2}\left((0\text{ m/s}) + v_i)(0.6\text{ s}) \\ \\ v_i &=\frac{79}{3} \text{ m/s} \approx 26.33 \text{ m/s} \end{aligned}\)

In conclusion, the initial velocity of the car is about 26.33 m/s.

Answer:

Action: Gravity pulls on the ball.

Reaction: The ball falls to the ground.

Explanation: