In order to shoot a bow and arrow, you must pull back on the bow, stretching the band to various degrees depending on the location of the target. The tension of the
stretched bow is an example of which type of energy?

O thermal energy
O chemical energy
O nuclear energy
O elastic potential energy

Answer:

  15√2 N

Explanation:

The acceleration is given by ...

  a = F/m = 5t/5 = t . . . . meters/second^2

The velocity is the integral of acceleration:

  v = ∫a·dt = (1/2)t^2

This will be 9 m/s when ...

  9 = (1/2)t^2

  t = √18 . . . . seconds

And the force at that time is ...

  F = 5(√18) = 15√2 . . . . newtons

The expansion volume of the metal cube is determined as 2.2 cm³.

The volume of expansion of the metal cube is calculated as follows;

ΔV = V₀αΔT

where;

ΔV = (10 cm)³ x (0.000011)(227 - 27)

ΔV = 2.2 cm³

Thus, the expansion volume of the metal cube is determined as 2.2 cm³.

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Answer:

1 mole = 6.02E23  molecules

2 moles = 12.04E24 molecules

This is a molecular count (assuming 1 atom per molecule) that will be # atoms)

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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The rate of heat loss, in watts, does this achieve is 37.66 W

It leads in cooling since water absorbs heat equivalent to mass times latent heat of evaporation to get converted into vapor .

So,

latent heat of evaporation of water = 2260 x 10³ J / kg or 2260 J / g

Now

in the evaporation of 1 g of water , heat lost = 2260 J

And,

heat lost per minute = 2260 J

So,

heat lost per second = 2260 / 60

= 37.66 J /s

= 37.66 W

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Answer: ionosphere

Explanation: aurora boreal is is caused by the ionosphere which is a part of the thermosphere

There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

The density of a binary alloy can be calculated using the following equation:

ρ = w1ρ1 + w2ρ2

where,

ρ = density of the alloy

w1 and w2 = weight fractions of the two components (in this case, gold and silver)

ρ1 and ρ2 = densities of the pure components.

We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:

\(w_{Au}\) = 0.10

\(w_{Ag}\) = 0.90

We are also given the densities of pure gold and silver as:

ρ_Au = 19.32 g/\(cm^{3}\)

ρ_Ag = 10.49 g/\(cm^{3}\)

Now we can substitute these values into the density equation to find the density of the alloy:

ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag

ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))

ρ = 11.08 g/\(cm^{3}\)

Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.

To do this, we can use Avogadro's number and the atomic weights of gold and silver:

\(N_A\) = 6.022 × \(10^{23}\) atoms/mol

Aum = 196.97 g/mol

Agm = 107.87 g/mol

The number of gold atoms:

\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)

Substituting the values, we get:

\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol

\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)

Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

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Answer:

Hello! Your answer would be, A) True

Explanation:

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Complete Question

The complete question is  shown on the first uploaded image (reference for Photobucket )

Answer:

The  electric field is  \(E = -1.3 *10^{-4} \ N/C\)

Explanation:

 From the question we are told that

    The linear charge density on the inner conductor is  \(\lambda _i = -26.8 nC/m = -26.8 *10^{-9} C/m\)

    The linear charge density on the outer conductor is

  \(\lambda_o = -60.0 nC/m = -60.0 *10^{-9} \ C/m\)

     The position of interest is r =  37.3 mm =0.0373 m

Now this position we are considering is within the outer conductor so the electric field  at this point is due to the inner conductor (This is because the charges on the conductor a taken to be on the surface of the conductor according to Gauss Law )

Generally according to Gauss Law

         \(E (2 \pi r l) = \frac{ \lambda_i }{\epsilon_o}\)

=>    \(E = \frac{\lambda _i }{2 \pi * \epsilon_o * r}\)

substituting values  

       \(E = \frac{ -26 *10^{-9} }{2 * 3.142 * 8.85 *10^{-12} * 0.0373}\)

       \(E = -1.3 *10^{-4} \ N/C\)

The  negative  sign tell us that the direction of the electric field is radially inwards

    =>   \(|E| = 1.3 *10^{-4} \ N/C\)

Answer:

Calcium is an essential mineral that is important in the diet of many living things as it plays several important roles in the body:

1. Bone and teeth formation: Calcium is a key component of bones and teeth, making them strong and healthy.

2. Muscle function: Calcium plays a critical role in muscle contraction and relaxation, helping muscles function properly.

3. Nerve function: Calcium is involved in the transmission of nerve impulses, which allows for proper communication between nerve cells.

4. Blood clotting: Calcium is required for blood clotting, which is important for preventing excessive bleeding after an injury.

5. Cellular signaling: Calcium is involved in many cellular signaling pathways, helping to regulate various physiological processes in the body.

Therefore, having an adequate amount of calcium in the diet is crucial for the overall health and well-being of many living organisms.

Answer:

31,2 + 38,02 + 45 = 114.22lbs

The combined weight of all the samples can simply be calculated by the arithmetic sum of all the individual weights of each sample.

The total combined weight of all the samples is "114.22 lb".

Adding the individual weights of each sample we get:

Combined weight = Weight of sample 1 + Weight of sample 2 + Weight of sample 3

Combined Weight = 31.2 lb + 38.02 lb + 45 lb

Combined Weight = 114.22 lb

The attached picture shows weight addition.

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Given:

The charge at x=0 is,

The other charge is,

The second charge is at,

To find:

The electric field at,

Explanation:

The diagram of the charges is shown below:

The electric field at the given point due to the first charge is,

The electric field due to the first charge is,

The electric field due to the second charge is,

The electric fields are opposite each other. So, the net electric field is,

Hence, the magnitude of the electric field is

Answer:

Explanation:

It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.

Answer:

Explanation:

d

A rock, a book and a can of soda all have the same mass. They each contain the same amount of matter.

Hence, the correct option is D.

Since the rock, book, and can of soda all have the same mass, it means that they contain the same amount of matter, regardless of their size or the material they are made of.

Mass is a measure of the amount of matter in an object, so if their masses are equal, it implies that the quantity of matter is the same in each of them.

The size, shape, and material composition can be different for each object, but their masses remain the same in this scenario.

Hence, A rock, a book and a can of soda all have the same mass. They each contain the same amount of matter.

Hence, the correct option is D.

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Answer:

About 1200J

(If we take gravity to be 10m/s^2)

Explanation:

U=mgh

m=6kg

g=10m/s^2

h=20m

U=(6)(10(20)=1200J

The density of mercury can be calculated using the formula:

Density = (mass of mercury) / (volume of mercury)

To calculate the volume of the mercury, we need to subtract the volume of the bottle from the volume of the bottle filled with mercury.

Volume of bottle = Volume of bottle filled with mercury - Volume of mercury

Let's assume that the volume of the bottle filled with mercury is V1 and the volume of the bottle is V2. We can then write:

Density of mercury = (mass of mercury) / (V1 - V2)

Given that the mass of the empty bottle is 20g, we can calculate the mass of the mercury as follows:

Mass of mercury = (mass of bottle filled with mercury) - (mass of empty bottle)

= 360g - 20g

= 340g

The mass of the bottle filled with water is 45g. Therefore, the mass of the mercury in the bottle is:

Mass of mercury = 360g - 45g = 315g

Let's assume that the density of the bottle is negligible. We can then calculate the volume of the mercury as follows:

Volume of mercury = (mass of mercury) / (density of mercury)

Substituting the values we have:

315g / (density of mercury) = (V1 - V2)

We know that the mass of the water in the bottle is 45g, which means that the mass of the mercury is (360g - 45g) = 315g. Therefore, the volume of the mercury is equal to the volume of the water. We can then write:

Volume of mercury = Volume of water = (mass of water) / (density of water)

The density of water is 1 g/cm³. Substituting the values we have:

315g / (density of mercury) = 45g / 1 g/cm³

Solving for the density of mercury, we get:

Density of mercury = (315g * 1 g/cm³) / 45g

= 7 g/cm³

Therefore, the density of mercury is 7 g/cm³.

The order in which the readings will be taken is as follows:

1. Mass of empty bottle

2. Mass of bottle filled with mercury

3. Mass of bottle filled with water (or the mass of the bottle filled with mercury and the mass of the empty bottle, from which we can calculate the mass of the mercury)

4. Volume

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The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon

We'll begin by obtaining the mass of the gold bar. This is given below:

Density = mass / volume

Cross multiply

Mass = Density × Volume

Mass of gold bar = 19300 × 0.00003

Mass of gold bar = 0.579 Kg

Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:

Volume = mass / density

Volume of water = 0.579 / 1000

Volume of water = 0.000579 m³

Multiply by 264.172 to express in gallon

Volume of water = 0.000579 × 264.172

Volume of water = 0.153 gallon

Thus, we can conclude that the volume of the water is 0.153 gallon

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Answer:

Explanation:

The answer is **(c) 9.39 m/s** for the velocity of the bullet-block system after it's hit, and **(g) 209.39 m/s** for the bullet's velocity before it hit the box.

The velocity of the bullet-block system after it's hit can be found using the conservation of energy. The potential energy of the box before it was hit is mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height that the box was displaced. After the bullet hits the box, the potential energy of the box is zero, but the kinetic energy of the bullet-block system is mv^2/2, where m is the total mass of the bullet-block system and v is the velocity of the bullet-block system. Setting these two expressions equal to each other, we get:

```

mgh = mv^2/2

```

Solving for v, we get:

```

v = sqrt(2mgh)

```

In this case, we have:

* m = 0.05 kg + 1.3 kg = 1.35 kg

* g = 9.8 m/s^2

* h = 4.5 m

So, the velocity of the bullet-block system after it's hit is:

```

v = sqrt(2 * 1.35 kg * 9.8 m/s^2 * 4.5 m) = 9.39 m/s

```

The velocity of the bullet before it hit the box can be found using the conservation of momentum. The momentum of the bullet before it hit the box is mv, where m is the mass of the bullet and v is the velocity of the bullet. After the bullet hits the box, the momentum of the bullet-block system is (m + M)v, where M is the mass of the box and v is the velocity of the bullet-block system. Setting these two expressions equal to each other, we get:

```

mv = (m + M)v

```

Solving for v, we get:

```

v = mv/(m + M)

```

In this case, we have:

* m = 0.05 kg

* M = 1.3 kg

* v = 9.39 m/s

So, the velocity of the bullet before it hit the box is:

```

v = 0.05 kg * 9.39 m/s / (0.05 kg + 1.3 kg) = 209.39 m/s

```

The velocity of the bullet-block system after the collision is approximately a) 6.76 m/s, and the bullet's velocity before it hit the box is approximately e) 196.76 m/s.

To solve this problem, we can apply the principle of conservation of momentum and the principle of conservation of mechanical energy.

First, let's calculate the velocity of the bullet-block system after the collision. We can use the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Let m1 be the mass of the bullet (0.05 kg) and m2 be the mass of the box (1.3 kg). Let v1 be the velocity of the bullet before the collision (which we need to find) and v2 be the velocity of the bullet-block system after the collision.

Using the conservation of momentum:

m1 * v1 = (m1 + m2) * v2

0.05 kg * v1 = (0.05 kg + 1.3 kg) * v2

0.05 kg * v1 = 1.35 kg * v2

Now, let's calculate the velocity of the bullet-block system (v2). Since the system goes up by a height of 4.5 m, we can use the principle of conservation of mechanical energy.

m1 * v1^2 = (m1 + m2) * v2^2 + m2 * g * h

0.05 kg * v1^2 = 1.35 kg * v2^2 + 1.3 kg * 9.8 m/s^2 * 4.5 m

Now, we can substitute the value of v2 from the momentum equation into the energy equation and solve for v1.

By solving these equations, we find that v1 is approximately 196.76 m/s.

Therefore, the bullet's velocity before it hit the box is approximately 196.76 m/s. (e) 196.76 m/s

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The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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An example of convection currents is the movement of air in a room when a heater is turned on. When the heater warms the air in the room, the warm air becomes less dense and rises, creating a convection current. As the warm air rises, cooler air from other parts of the room moves in to replace it, creating a continuous circulation of air. This process is known as natural convection.

Convection currents occur when there is a transfer of heat through the movement of a fluid, either liquid or gas. Here is a step-by-step explanation of convection currents:

Heating: In the example of a room with a heater, the heating element of the heater warms the air in the vicinity.

Expansion: As the air near the heater gets heated, it expands and becomes less dense. This decrease in density makes the warm air rise.

Rising: The warm air rises upward due to its buoyancy. This upward movement creates an area of low pressure near the heater.

Replacement: As the warm air rises, cooler air from other parts of the room moves in to fill the space left by the rising warm air. This cooler air is denser and moves downward.

Circulation: The cycle continues as the warm air rises, cools down, and then descends to be heated again by the heater. This creates a continuous circulation of air, forming convection currents.

Other examples of convection currents include the movement of boiling water in a pot, the circulation of air in the atmosphere resulting in wind patterns, and the movement of magma in the Earth's mantle leading to plate tectonics. Convection currents play a significant role in distributing heat energy and maintaining fluid movements in various natural and artificial systems.

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Answer: The concept of a "life zone" on Earth can be interpreted in various ways, but assuming you're referring to habitable regions for life as we know it, there isn't a specific place that is completely outside the life zone. Life has shown remarkable adaptability and can be found in a wide range of environments, including extreme cold, hot, acidic, or high-pressure conditions. However, there are certain places on Earth where life is less likely or where it is more challenging for organisms to thrive, such as:

High-altitude mountaintops: As you move higher in elevation, the conditions become harsher, with lower temperatures, reduced oxygen levels, and increased UV radiation. While some organisms can survive at high altitudes, the number and diversity of species tend to decrease.

Deserts: Deserts are characterized by low precipitation and extreme temperatures. While there are desert-adapted plants and animals that can survive in these environments, the scarcity of water and extreme aridity make it challenging for many organisms to thrive.

Polar regions: The Arctic and Antarctic regions have extremely cold temperatures, limited sunlight during winter months, and harsh conditions. However, even in these extreme environments, life can be found, such as cold-adapted organisms like polar bears, penguins, and specialized bacteria.

it's important to note that even in these challenging environments, life can still exist in various forms, showcasing the resilience and adaptability of organisms.

Answer:

the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.

Explanation:

A conductor that does not obey Ohm's law is described as non - ohmic. An example is a filament lamp. It glows as the current passes through it.

How does the resistance of the light bulbs differ when the bulbs are cold and when the bulbs are hot ?

The resistance of the light bulbs increase gradually as its temperature is increased.

So, the hot bulb will have high resistance to the flow of current. While the cold bulb will have a low resistance to the flow of current.

Because the resistance of an impure metal wire is greater than the resistance of a pure metal wire of the same dimension.

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Answer:

B Gravitational potential energy

Explanation:

Answer:

All of the objects in the solar system orbit the

Explanation:

sun