In one of the trailers the characters, narrowly escape the displacer beast by jumping into what?

Answer:

Yes

Explanation: 120 % = 1.2

If Maxine is correct, then she spent  1.2

times the hours she did homework than last week.

15 ⋅ 1.2 = 18.0 = 18

15 hours ⋅ 1.2 = 18.0 hours = 18 hours

This means that Maxine is correct.

Answer:

”an event can have a probability of 0”

Step-by-step explanation:

A probability can not be 0 it has to be more then 0

Answer:

The final balance is $4,353.56.

The total compound interest is $1,153.56.

Step-by-step explanation:

Answer:

See picture & explanation below.

Step-by-step explanation:

The scale is 1:2, so everything is doubled in size.

Count the number of squares each segment is in length and multiply it by 2. Then draw all new segments that are twice as long as the original ones to create a house that is twice as large as the original house.

See the picture below.

There are 15,504 ways to randomly select a team of 5 people from a group of 20 people

If there are 20 people trying out for a team, the number of ways to select a team of n people can be calculated using the formula for combinations, which is:

C(20, n) = 20! / (n! * (20 - n)!)

where C(20, n) represents the number of ways to select n people from a group of 20 people.

For example, if we want to select a team of 5 people, we can plug in n = 5 and calculate:

C(20, 5) = 20! / (5! * (20 - 5)!) = 15,504

Therefore, there are 15,504 ways to randomly select a team of 5 people from a group of 20 people. Similarly, we can calculate the number of ways to select teams of different sizes by plugging different values of n into the formula for combinations.

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Answer:

Step-by-step explanation:

There are a couple of ways you could solve this problem. B is one of them.

The correct answer is going to be Small hypotenuse / Large hypotenuse = tree / building height

Let the tree equal x

100/220 = x / 176           Multiply both sides by 176

100 * 176 / 220 = x

x = 80

Notice that 80 is almost 1/2 of 176 so the answer should be right since 100 is nearly 1/2 of 220

Answer:

x = 11.2

Step-by-step explanation:

\(\frac{6.4}{x}\) = \(\frac{4}{7}\)

4x = 44.8

x = 11.2

Notice that AD is a diameter, therefore,

Furthermore, arcAB=25° and x° is the central angle that defined arcAB; thus, x°=25°.

Finally,

Thus, the answer is y=100

\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 11}}{\left( \cfrac{10}{100} \right)11}\implies 1.1~\hfill \stackrel{\textit{11 bucks plus tax}}{11+1.1\implies 12.1}\)

C-reactive protein (CRP) tiers were measured in a pattern of apparently healthy children elderly 6 to 60 months in Papua New Guinea. Given the presence of many zero values within the facts, the implication may not be a good characterization of the center of this distribution. The median could be an extra suitable degree in this case.

A. In this situation, it is not suitable to apply the imply as an amazing characterization of the middle of the distribution. The cause is that the statistics consist of a large number of 0 values, on the way to heavily have an impact on the suggestion.

Since CRP values increase considerably throughout an infection, the presence of many 0 values suggests that a sizable part of the youngsters within the look-at aren't presently experiencing contamination. Therefore, the implications can be heavily prompted by way of the massive quantity of zeros, resulting in a faulty representation of the center of the distribution.

B. To higher signify the middle of this distribution, it might be extra suitable to use the median. The median is not affected by extreme values or outliers as an awful lot because they imply, and it represents the center fee of the statistics when its miles are organized in ascending or descending order.

In this situation, the median will provide a more robust degree of the principal tendency of the CRP values, specifically considering the presence of many 0 values in the dataset.

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Answer:

c) 7(7 + 4)

Step-by-step explanation:

Given expression,

→ 49 + 28

Then equivalent expression is,

→ 7(7 + 4)

→ (7 × 7) + (7 × 4)

→ 49 + 28

Hence, the answer is 7(7 + 4).

Answer:7(7+4)

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

I would say 4 inches

Step-by-step explanation:

Answer:

360°

Step-by-step explanation:

the sum of the exterior angles of any polygon is 360°

Answer:

3,5,-5

Step-by-step explanation:

because it on y asix

The term for the value that occurs most often in a series of numbers is called the mode.

The mode is one of the three main measures of central tendency, along with the mean and the median. It is a useful descriptive statistic that can provide insights into the characteristics of a dataset.

To find the mode of a set of data, you first need to arrange the data in order, either in increasing or decreasing order. Then, you simply identify the most frequent data point, which is the mode. In some cases, there may be more than one mode if multiple data points occur with the same maximum frequency.

The mode is particularly useful when dealing with categorical or nominal data, where there are distinct categories or values that cannot be ordered in a meaningful way. For example, the mode can help identify the most popular color among a group of people or the most common type of car on a given street. It can also be used for continuous data, although it may be less useful in this case than the mean or median.

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Answer:

He runs a mile in 1/8 of an hour

he can run 8 miles in one hour

Step-by-step explanation:

First thing you need to do is to find out the yearly depreciation amount:

Annual depreciation = (Cost of truck - Residual value) / Useful life

= (28,000 - 3,000) / 5

= $5,000

At the end of 3 years, the value of the truck would be:

= Cost of truck - (Depreciation amount x number of years)

= 28,000 - (5,000 x 3)

= $13,000

If the truck was bought on April 12, only depreciation by the number of days left in that year:

= Annual depreciation / Number of days in a year x Number of days left in the first year

= 5,000 / 365 x 263

= $3,602.74

In conclusion, the truck will be worth $13,000 in 3 years.

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In one sweep, the area covered by the sprinkler is 77.19 sq ft (approx). The area of the lawn, to the nearest square foot, that receives water from this sprinkler is 616 sq ft (approx).

We know that a rotating sprinkler can reach up to 14 feet through a 300-degree angle. Area covered by the sprinkler in one sweep = area of the sector whose radius = 14 feet and angle = 300°Area of sector = (θ / 360) × πr²Where θ = 300°, r = 14 ftArea of sector = (300/360)× π(14)²= 77.19 sq ft (approx) Therefore, the area covered by the sprinkler in one sweep is 77.19 sq ft (approx).

We need to find the total area of the lawn that receives water from this sprinkler. The sprinkler rotates 360 degrees, so it will cover a full circle whose radius is 14 feet. Area of a circle = πr²= π(14)²= 615.752 sq ft (approx) Therefore, the area of the lawn, to the nearest square foot, that receives water from this sprinkler is 616 sq ft (approx).

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The odds of hitting an asteroid in the asteroid belt are quite low.

To explain this further, let's consider the following steps:

In summary, the odds of hitting an asteroid in the asteroid belt are quite low due to the vast distances between individual asteroids and the ability to carefully plan spacecraft trajectories.

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Answer:

19 and 11

Step-by-step explanation:

Answer:

E

Step-by-step explanation:

Its because of Corresponding angles.

The appropriate family of distributions to approximate the probability of rolling a 6 on a fair die is the discrete uniform distribution, which assumes equal probabilities for each outcome. In this case, the probability of rolling a 6 would be approximately 1/6 based on the assumption of fairness.

For the problem of approximating the probability of rolling a 6 on a fair die, an appropriate family of distributions to consider is the discrete uniform distribution.

The discrete uniform distribution is commonly used to model situations where each outcome has an equal probability of occurring. In the case of rolling a fair die, the die has six equally likely outcomes (numbers 1 to 6).

Each outcome has a probability of 1/6 of occurring, making the discrete uniform distribution a suitable choice.

By assuming a discrete uniform distribution, we can assign equal probabilities to each outcome (1/6 for rolling a 6) and approximate the probability of rolling a 6 based on the assumption of fairness.

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Answer:

20/5 = x /4 x = 80/5 = 16

x - 10 / 39 = 5/15 = 1/3

3x - 30 = 39

3x = 69

x = 23

(2x + 10 ) * 4 = 10 *(x + 3)

8x + 40 = 10x + 30

2x = 10

x = 4.

AE = 2(5) + 10 = 20, hope this helped.

Answer:

gbegssgfsss

Step-by-step explanation:

Answer:

its 12

Step-by-step explanation:

jus did it mark brainliest plzz

Answer:

6y

Step-by-step explanation:

The denominators are prime numbers. So, multiply the denominators.

3y * 2 = 6y

6y is the LCD

Answer:

5/2

Step-by-step explanation:

Use PEMDAS to solve the equation in y=mx+b form.

Add 5x on each side of the = sign  (which cancels on left side, and add on right)

Your equation should look like this: 2y=5x+10

Next, you're going to divide the whole equation by 2, to get y by itself

which equals y=5/2x+10

M=slope

B= y-intercept

The resulting relations are:

R1({P, R, Q, U, Z})

R2({P, S, T}, {R → R2})

R3({U, V, W}, {R → R3})

R4({S, X, Y}, {P → R4}) or ({R → R4})

To find the key for R, we need to determine which attribute(s) uniquely identify each tuple in R. We can do this by computing the closure of each attribute set using the given functional dependencies F.

Starting with P, we have {P}+ = {P, R, U, V, W, Z}, since we can derive all other attributes using the given functional dependencies. Similarly, {R}+ = {R, U, V, W, Z}. Therefore, both {P} and {R} are candidate keys for R.

To decompose R into 2NF, we need to identify any partial dependencies in the functional dependencies F. A partial dependency exists when a non-prime attribute depends on only a part of a candidate key. In this case, we can see that {P}→{S, T} is a partial dependency since S and T depend only on P but not on the entire candidate key {P,R}.

To remove the partial dependency, we can create a new relation with schema {P, S, T} and a foreign key referencing R. This preserves the functional dependency {P}→{S,T} while eliminating the partial dependency.

The resulting relations are:

R1({P, R, Q, U, V, W, Z})

R2({P, S, T}, {R → R2})

To decompose R into 3NF, we need to identify any transitive dependencies in the functional dependencies F. A transitive dependency exists when a non-prime attribute depends on another non-prime attribute through a prime attribute.

In this case, we can see that {U}→{V,W} is a transitive dependency since V and W depend on U through the prime attribute R. To eliminate this transitive dependency, we can create a new relation with schema {U, V, W} and a foreign key referencing R.

The resulting relations are:

R1({P, R, Q, U, Z})

R2({P, S, T}, {R → R2})

R3({U, V, W}, {R → R3})

To decompose R into BCNF, we need to identify any non-trivial functional dependencies where the determinant is not a superkey. In this case, we can see that {S}→{X,Y} is such a dependency since S is not a superkey.

To remove this dependency, we can create a new relation with schema {S, X, Y} and a foreign key referencing P (or R). This preserves the functional dependency while ensuring that every determinant is a superkey.

The resulting relations are:

R1({P, R, Q, U, Z})

R2({P, S, T}, {R → R2})

R3({U, V, W}, {R → R3})

R4({S, X, Y}, {P → R4}) or ({R → R4})

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None of the expressions given is equivalent to (2 - ³√24)²..

Mathematical statements must contain a sentence, at least one mathematical operation, and at least two numbers or factors. With this mathematical operation, you can increase, split, add, or take something away. The shape of a phrase is as follows: Expression: (Number/Variable, , Math Operator)

Let's first simplify the expression (2 - ³√24)²:

(2 - ³√24)² = (2 - 24^(1/3))² = (2 - 2.29)² = (-0.29)² = 0.0841

Now we can check which expressions are equivalent to 0.0841 when (2 - ³√24)² is evaluated:

4 = 4.0000... (not equivalent to 0.0841)

04 = 0.04 (not equivalent to 0.0841)

26.2 - 8 = 18.2 (not equivalent to 0.0841)

02 - 5.22 = -3.22 (not equivalent to 0.0841)

Therefore, none of the expressions given is equivalent to (2 - ³√24)².

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