In nop, the measure of zp=90°, the measure of zn=39, and pn = 72 feet. find the length of op to the nearest tenth of a foot?​

Answer: 5 banana 3 dollar

Step-by-step explanation:

per dollar"→divide by dollars

15\text{ bananas}:

15 bananas:

\,\,9\text{ dollars}

9 dollars

\frac{15\text{ bananas}}{9}:

9

15 bananas

​

:

\,\,\frac{9\text{ dollars}}{9}

9

9 dollars

​

\frac{5}{3}\text{ bananas}:

3

5

​

 bananas:

\,\,1\text{ dollar}

1 dollar

\frac{5}{3}\text{ bananas for every 1 dollar}

3

5

​

 bananas for every 1 dollar

\mathbf{\frac{5}{3}\text{ bananas per dollar}}

​

 5 bananas per 3 dollar

Unit rate is the quantity of an amount of something at a rate of one of another quantity.

If 15 bananas cost $9.

The cost of one banana is $0.6

The amount of banana per dollar is 5/3 banana

It is the quantity of an amount of something at a rate of one of another quantity.

In 2 hours, a man can walk for 6 miles.

In 1 hour, a man will walk for 3 miles.

If a machine can make 100 bottles in 20 minutes.

In 1 minute the machine can make 100/20 = 5 bottles.

We have,

Cost of 15 banana = $9

This can be written as:

15 banana = $9

Divide 9 on both sides.

15/9 banana = $1

5/3 banana = $1

The cost of one banana:

15 banana = $9

1 banana = 9/15

1 banana = 3/5

1 banana = $0.6

Thus,

If 15 bananas cost $9.

The cost of one banana is $0.6

The amount of banana per dollar is 5/3 banana

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The expression that represents the area of the new field is 400m²-200m+25 (option a)

To begin, let's start by finding the area of the original square field. The formula for the area of a square is the length of one side squared. In this case, the length of one side is 20 meters, so the area is:

Area = (20m)² = 400m²

Now, we need to find the area of the new field, which has one side that is 5 meters longer and one side that is 5 meters shorter than the original square. We can express the new length as (20m + 5m) = 25m, and the new width as (20m - 5m) = 15m.

The area of the new field can be expressed as the product of the new length and the new width:

New area = (25m)(15m)

To simplify this expression, we can use the distributive property of multiplication:

New area = 25m * 15m = (20m + 5m)(20m - 5m)

Expanding the expression using the FOIL method, we get:

New area = (20m)² - (5m)² = 400m² - 25m²

Simplifying this expression further, we get:

New area = 400m² - 25m² = 40m² (10 - m²/16)

Since we don't have any answer options that match this expression exactly, we need to simplify it further. Using the difference of squares, we can write:

New area = 40m² (5 + m/4)(5 - m/4)

Multiplying out the terms inside the parentheses, we get:

New area = 40m² (25 - m²/16)

Distributing the 40m², we get:

New area = 1000m² - 25m⁴/4

Finally, simplifying the expression, we get:

New area = 400m² - 25m + 25

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Answer:

need the graph to know

Step-by-step explanation:

97.04 mg Initial mass = 48 mg, Mass after 7 weeks = 48 mg * (1/2)^(12.25) Half-life of the goo in minutes = 120 / (log(37/296) / log(1/2)) The artifact was made approximately 22920 years ago.

Question 26:

The half-life of Radium-226 is 1590 years. To determine how many milligrams will remain after 3000 years, we can use the formula:

N(t) = N₀ * (1/2)^(t/T),

where:

N(t) is the remaining amount after time t,

N₀ is the initial amount,

t is the elapsed time, and

T is the half-life.

Given that the initial amount is 200 mg, the elapsed time is 3000 years, and the half-life is 1590 years, we can substitute these values into the formula:

N(3000) = 200 * (1/2)^(3000/1590).

Calculating this, we find:

N(3000) ≈ 200 * (1/2)^(1.8862) ≈ 200 * 0.4852 ≈ 97.04.

Therefore, approximately 97.04 mg of Radium-226 will remain after 3000 years.

Question 27:

The half-life of Palladium-100 is 4 days. We can use the half-life formula again to determine the initial mass and the mass after 7 weeks.

1. Initial mass:

After 12 days, the sample of Palladium-100 has been reduced to 6 mg. We need to determine how many half-lives have passed in 12 days to find the initial mass.

t = (12 days) / (4 days/half-life) = 3 half-lives.

Let's denote the initial mass as M₀. We can use the formula:

M(t) = M₀ * (1/2)^(t/T).

Substituting the values, we have:

6 mg = M₀ * (1/2)^(3).

Solving for M₀:

M₀ = 6 mg * 2^3 = 48 mg.

Therefore, the initial mass of the sample was 48 mg.

2. Mass after 7 weeks (49 days):

To find the mass after 7 weeks, we need to determine how many half-lives have passed in 49 days:

t = (49 days) / (4 days/half-life) = 12.25 half-lives.

Using the formula, we can calculate the mass after 7 weeks:

M(49 days) = M₀ * (1/2)^(12.25).

Substituting the initial mass we found earlier:

M(49 days) = 48 mg * (1/2)^(12.25).

Calculating this value will give us the mass after 7 weeks.

Question 28:

To find the half-life of the radioactive goo, we can use the formula:

N(t) = N₀ * (1/2)^(t/T),

where N(t) is the remaining amount at time t, N₀ is the initial amount, t is the elapsed time, and T is the half-life.

Given that the initial amount is 296 grams and the amount after 120 minutes is 37 grams, we can substitute these values into the formula:

37 g = 296 g * (1/2)^(120/T).

To find the half-life T, we can rearrange the equation:

(1/2)^(120/T) = 37/296.

Taking the logarithm of both sides, we have:

120/T * log(1/2) = log(37/296).

Solving for T:

T = 120 / (log(37/296) / log(1/2)).

Calculate the value of T using this equation to find the half-life of the radioactive goo in minutes.

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The value of the probabilities are:

(a) P(X > 0) = 1/2

(b) P(0 < X < 1) = 1/2

We have,

To compute the probabilities, we need to integrate the density function over the given intervals.

(a) P(X > 0):

To find P(X > 0), we need to integrate the density function f(x) = k(1 - x²) from 0 to 1:

P(X > 0) = ∫[0,1] f(x) dx

First, we need to determine the constant k by ensuring that the total area under the density function is equal to 1:

∫[-1,1] f(x) dx = 1

∫[-1,1] k(1 - x²) dx = 1

Solving the integral:

k ∫[-1,1] (1 - x²) dx = 1

k [x - (x³)/3] | [-1,1] = 1

k [(1 - (1³)/3) - (-1 - (-1)³/3)] = 1

k [(1 - 1/3) - (-1  1/3)] = 1

k (2/3 + 2/3) = 1

k = 3/4

Now we can compute P(X > 0):

P(X > 0) = ∫[0,1] (3/4)(1 - x²) dx

P(X > 0) = (3/4) [x - (x³)/3] | [0,1]

P(X > 0) = (3/4) [(1 - (1³)/3) - (0 - (0³)/3)]

P(X > 0) = (3/4) [(2/3) - 0]

P(X > 0) = (3/4) * (2/3) = 1/2

Therefore, P(X > 0) = 1/2.

(b) P(0 < X < 1):

To find P(0 < X < 1), we integrate the density function f(x) = k(1 - x²) from 0 to 1:

P(0 < X < 1) = ∫[0,1] f(x) dx

Using the previously determined value of k (k = 3/4), we can compute P(0 < X < 1):

P(0 < X < 1) = ∫[0,1] (3/4)(1 - x²) dx

P(0 < X < 1) = (3/4) [x - (x³)/3] | [0,1]

P(0 < X < 1) = (3/4) [(1 - (1³)/3) - (0 - (0³)/3)]

P(0 < X < 1) = (3/4) [(2/3) - 0]

P(0 < X < 1) = (3/4) * (2/3) = 1/2

Therefore, P(0 < X < 1) = 1/2.

Thus,

The value of the probabilities are:

(a) P(X > 0) = 1/2

(b) P(0 < X < 1) = 1/2

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The complete question:

Let X be a random variable with the density function f(x) = k(1 - x^2) for -1 ≤ x ≤ 1 and 0 elsewhere.

Compute the following probabilities:

(a) P(X > 0)

(b) P(0 < X < 1)

Answer:

Yes

Step-by-step explanation:

The given integral ∫∫∫ (2ct √(3u^2 + s^2 + u^2)) ds du dt can be evaluated by breaking it down into separate integrals with respect to each variable. The resulting integral involves trigonometric and square root functions, which can be simplified to find the solution.

To evaluate the given integral, we will first integrate with respect to ds, then du, and finally dt. The integration with respect to ds yields s evaluated from 0 to t, the integration with respect to du yields u evaluated from 0 to √3, and the integration with respect to dt yields t evaluated from 0 to 1.

Integrating with respect to ds, we get ∫ (2ct √(3u^2 + s^2 + u^2)) ds = (2ct/2) ∫ √(3u^2 + s^2 + u^2) ds = ct [s√(3u^2 + s^2 + u^2)] evaluated from 0 to t.

Next, integrating with respect to du, we have ∫ ct [s√(3u^2 + s^2 + u^2)] du = cts ∫ √(3u^2 + s^2 + u^2) du = cts [u√(3u^2 + s^2 + u^2)] evaluated from 0 to √3.

Finally, integrating with respect to dt, we obtain ∫ cts [u√(3u^2 + s^2 + u^2)] dt = ct^2s [u√(3u^2 + s^2 + u^2)] evaluated from 0 to 1.

By substituting the limits of integration into the above expression, we can calculate the definite integral and obtain the final result. Please note that the specific values of c and t may affect the final numerical solution.

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Given:

The inequality is:

\(4x+1<5x\leq 3(x+2)\)

To find:

The integer solutions to the given inequality.

Solution:

We have,

\(4x+1<5x\leq 3(x+2)\)

This compound inequality can be written as two separate inequalities \(4x+1<5x\) and \(5x\leq 3(x+2)\).

Now,

\(1<5x-4x\)

\(1<x\)                 ...(i)

And,

\(5x\leq 3(x+2)\)

\(5x\leq 3(x)+3(2)\)

\(5x-3x\leq 6\)

\(2x\leq 6\)

Divide both sides by 2.

\(x\leq \dfrac{6}{2}\)

\(x\leq 3\)               ...(ii)

From (i) and (ii), we get

\(1<x\leq 3\)

Here, 1 is excluded and 3 is included in the solution set. There two integer values 2 and 3 in \(1<x\leq 3\).

Therefore, the integer solution for the given inequality are 2 and 3.

Equating both equations, Nayati and Tatiana will have the same amount of savings after 21 weeks.

Equations are mathematical statements that show that there is equality between two or more mathematical expressions.

Equations are depicted using the equation symbol (=).

                       Nayati   Tatiana

Savings            $240     $450

Weekly savings $40       $30

Nayati total savings = 40w + 240

Tatiana total savings = 30w + 450

To determine the number of weeks when their savings will be equal, the two equations will be equated as follows:

40w + 240 = 30w - 450

10w = 210

w = 21

= 21 weeks

Thus, we expect Nayati and Tatiana to embark on their road trip after 21 weeks.

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The value of x is equal to 15°

In Mathematics and Geometry, the sum of the exterior angles of both a regular and irregular polygon is always equal to 360 degrees.

Note: The given geometric figure (regular polygon) represents a pentagon and it has 5 sides.

By substituting the given parameters, we have the following:

3x + 4x + 8 + 5x + 5 + 6x - 1 + 5x + 3 = 360°.

3x + 4x + 5x + 6x + 5x + 8 + 5 - 1 + 3 = 360°.

23x + 15 = 360°.

23x = 360 - 15

23x = 345

x = 345/23

x = 15°.

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Answer:

31.25

Step-by-step explanation:

25% * 125 = 25/100 * 125 = 1/4 * 125 = 31.25

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

When a graph is reflected along an axis, say x axis, then that leads the graph to go just in the opposite side of the axis as if we're seeing it in a mirror.

If you study it more, you will find that it's symmetric, thus each point is equidistant from the axis of reflection as that of the image of that point.

Thus, if you're reflecting a point (x,y) along the x-axis, then its x abscissa will stay the same but y coordinates will negate.

Thus (x,y) turns to (x, -y)

Similarly, if you're reflecting a point (x,y) along the y -axis, the resultant image of the point will be (-x,y).

The image was formed by a reflection of the letter M would be image A in the second quadrant b the reflection on X-axis. The correct option is A.

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The reflection of letter M is (A)

A figure is said to be a reflection of the other figure, then every point in a figure is at equidistant from each corresponding point in another figure.

According to the graph the reflection of Of letter M is with same coordinates but with x as positive and y as negative.

Hence the reflection is (A).

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Answer:

Suppose that we have two similar figures.

Then if a given side of one of the figures has a measure M, the correspondent side in the other figure has a measure M' = k*M

Where k is the scale factor.

Then if the perimeter of the first figure is P, the perimeter of the other figure will be P' = k*P

And if the area of the first figure is A, then the area of the other figure will be:

A' = k^2*A

Then the quotient between the perimeters is:

P'/P = k

And the ratio between the areas is

A'/A = k^2

So what we need to do, is find the value k.

In the image, we can see that the base of the larger figure is 30 yd, and the base of the smaller figure is 12 yd.

If we define the smaller figure as the original one, then we will have:

M = 12 yd

M' = 30 yd

M' = 30yd = k*12yd = k*M

Solving for k we get:

k = 30yd/12yd = 2.5

Then the ratio between the perimeters is:

P'/P = k = 2.5

And the ratio of the area of the larger figure (A') to the smaller figure (A) is:

A'/A = k^2 = (2.5)^2 = 6.25

A sequence that can be partially defined by a recursive formula is one where each term is determined based on the previous terms.

A recursive formula is a mathematical expression that describes a sequence by relating each term to one or more previous terms. It allows us to generate subsequent terms in the sequence based on the values of earlier terms. The recursive formula typically consists of two components: a base case that defines the initial term(s) of the sequence, and a recursive rule that expresses how to calculate each subsequent term based on the previous term(s).

For example, let's consider a sequence defined by the recursive formula: a(n) = a(n-1) + 3, with a(0) = 1. In this case, the base case is a(0) = 1, which specifies the initial term of the sequence. The recursive rule a(n) = a(n-1) + 3 states that each term is obtained by adding 3 to the previous term. Starting from a(0) = 1, we can calculate subsequent terms as follows: a(1) = a(0) + 3 = 1 + 3 = 4, a(2) = a(1) + 3 = 4 + 3 = 7, and so on.

In summary, a sequence partially defined by a recursive formula allows us to generate terms by using a rule that depends on the previous terms. It provides a systematic way to calculate subsequent values and explore the pattern or behavior of the sequence.

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The nonlinear state equations is \($\bar{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} = \bar{f}(\bar{x}, \bar{u}) = \begin{bmatrix} x_2 \ 2x_1x_2 - 5\sin(x_1)x_2 + \dot{u} \end{bmatrix}$\), the equilibrium points are \($x_2 = 0$\)  and \($\dot{u} = 0$\), the operating point where \($x^* = 0$\), are \(\bar{x}^* = \begin{bmatrix} 0 \ 0 \end{bmatrix}\) and \($u^* = u$\) and the linearized state equation are:

\($\Delta \dot{\bar{x}} = \begin{bmatrix} \Delta \dot{x}_1 \ \Delta \dot{x}_2 \end{bmatrix} = \begin{bmatrix} \Delta x_2 \ 0 \end{bmatrix} + \begin{bmatrix} 0 \ \Delta u \end{bmatrix} = \begin{bmatrix} \Delta x_2 \ \Delta u \end{bmatrix}$\).

a) To write the nonlinear state equations in the form \($\bar{x} = \bar{f}(\bar{x}, \bar{u})$\) , we can express the given second-order differential equation in terms of the state variables \($x_1$\) and \(x_2\).

Let's differentiate \($\ddot{x} = x^2 + 5\cos(x) + u$\) once with respect to time to obtain  \($\dddot{x} = 2x\dot{x} - 5\sin(x)\dot{x} + \dot{u}$\).

Now, let \($\bar{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix}$\) and \($\bar{u} = \begin{bmatrix} u \end{bmatrix}$\) represent the state vector and control input. We can rewrite as follows:

\($\begin{bmatrix} \dot{x}_1 \ \dot{x}_2 \end{bmatrix} = \begin{bmatrix} x_2 \ 2x_1x_2 - 5\sin(x_1)x_2 + \dot{u} \end{bmatrix}$\)

Therefore, the nonlinear state equations in the desired form are:

\($\bar{x} = \begin{bmatrix} x_1 \ x_2 \end{bmatrix} = \bar{f}(\bar{x}, \bar{u}) = \begin{bmatrix} x_2 \ 2x_1x_2 - 5\sin(x_1)x_2 + \dot{u} \end{bmatrix}$\)

b) To find the equilibrium points, we set the derivatives of the state. Let \($\dot{x}_1 = \dot{x}_2 = 0$\).

From the first equation \($\dot{x}_1 = x_2 = 0$\), we obtain \($x_2 = 0$\).

Substituting \($x_2 = 0$\) into the second equation \($2x_1x_2 - 5\sin(x_1)x_2 + \dot{u} = 0$\), we have \($2x_1 \cdot 0 - 5\sin(x_1) \cdot 0 + \dot{u} = 0$\), which implies \($\dot{u} = 0$\).

Therefore, the equilibrium points are given by \($x_2 = 0$\)  and \($\dot{u} = 0$\).

c) From part b, we found that the equilibrium points have \($x_2 = 0$\) and \($\dot{u} = 0$\). Given that , the equilibrium point \($x^* = 0$\).

Therefore, at the operating (equilibrium) point where \($x^* = 0$\), we have \($\bar{x}^* = \begin{bmatrix} 0 \ 0 \end{bmatrix}$\) and \($u^* = u$\).

d) To find the linearized state equations \($\Delta \dot{\bar{x}} = A\Delta \bar{x} + B\Delta \bar{u}$\) at the operating point from part c, we need to linearize the nonlinear state equations.

Let\($\Delta \bar{x} = \bar{x} - \bar{x}^$\) and \($\Delta \bar{u} = \bar{u} - \bar{u}^$\) represent small perturbations around the equilibrium

Linearizing the nonlinear state equations around \($\bar{x}^* = \begin{bmatrix} 0 \ 0 \end{bmatrix}$\) and \($\bar{u}^* = \begin{bmatrix} u^* \end{bmatrix}$\),

\($\Delta \dot{\bar{x}} = \begin{bmatrix} \Delta \dot{x}_1 \ \Delta \dot{x}_2 \end{bmatrix} = A\Delta \bar{x} + B\Delta \bar{u}$\)

To obtain \($A$\) and \($B$\), we need to compute the Jacobian matrices

The Jacobian matrix \($A$\) is :

\($A = \left[\frac{\partial \bar{f}}{\partial \bar{x}}\right]_{\bar{x}=\bar{x}^,\bar{u}=\bar{u}^} = \begin{bmatrix} \frac{\partial \dot{x}_1}{\partial x_1} & \frac{\partial \dot{x}_1}{\partial x_2} \ \frac{\partial \dot{x}_2}{\partial x_1} & \frac{\partial \dot{x}2}{\partial x_2} \end{bmatrix}{\bar{x}=\bar{x}^,\bar{u}=\bar{u}^}$\)

Computing the partial derivatives:

\($A = \begin{bmatrix} 0 & 1 \ 0 & -5\sin(x_1) \end{bmatrix}_{\bar{x}=\bar{x}^,\bar{u}=\bar{u}^} = \begin{bmatrix} 0 & 1 \ 0 & 0 \end{bmatrix}$\)

The Jacobian matrix \($B$\) is:

\($B = \left[\frac{\partial \bar{f}}{\partial \bar{u}}\right]_{\bar{x}=\bar{x}^,\bar{u}=\bar{u}^} = \begin{bmatrix} \frac{\partial \dot{x}_1}{\partial u} \ \frac{\partial \dot{x}2}{\partial u} \end{bmatrix}{\bar{x}=\bar{x}^,\bar{u}=\bar{u}^}$\)

The partial derivatives:

\($\frac{\partial \dot{x}_1}{\partial u} = 0$\), \($\frac{\partial \dot{x}_2}{\partial u} = 1$\). Evaluating the partial derivatives at the equilibrium point, we have:  \($B = \begin{bmatrix} 0 \ 1 \end{bmatrix}_{\bar{x}=\bar{x}^,\bar{u}=\bar{u}^} = \begin{bmatrix} 0 \ 1 \end{bmatrix}$\)

Therefore, the linearized state equations at the operating point are on simplifying further is;

\($\Delta \dot{\bar{x}} = \begin{bmatrix} \Delta \dot{x}_1 \ \Delta \dot{x}_2 \end{bmatrix} = \begin{bmatrix} \Delta x_2 \ 0 \end{bmatrix} + \begin{bmatrix} 0 \ \Delta u \end{bmatrix} = \begin{bmatrix} \Delta x_2 \ \Delta u \end{bmatrix}$\)

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The length of the model car based on the information is 0.8 feet.

It should be noted that scale simply shows the relationship between a measurement on a model as well as the corresponding measurement on the actual object.

From the information, the model car is constructed with a scale of 1:15.

When the actual car is 12 feet long, the length of the model will be illustrated as x. This will be:

= 1/15 = x / 12

Cross multiply

15x = 1 × 12

15x = 12

Divide

x = 12 / 15

x = 0.8

The length is 0.8 feet.

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Answer:

b i took the test

Step-by-step explanation:

Answer:

0.41666666, to round up, the answer is 0.42

Step-by-step explanation:

\( \frac{3}{8} + \frac{1}{8} - \frac{1}{3} + \frac{1}{4} = \frac{4}{8} - \frac{1}{3} = \frac{4}{24} + \frac{1}{4} = \frac{10}{24} = \frac{5}{12} \)

Answer:

108

Step-by-step explanation:

Answer:

The answer is D

Answer: b = 5

Step-by-step explanation:

        The standard form of a quadradic equation is 0 = ax² + bx + c. To do this, we will move all values to one side of the equation.

        Given:

8x + 4 = -2x² + 3x + 1

        Subtract (8x + 4) from both sides of the equation:

0 = -2x² - 5x - 3

        Lastly, we are given that a = 2, so we will divide both sides of the equation by -1.

0 = -2x² - 5x - 3

0 = 2x² + 5x + 3

        We are asked to find the value of b.

0 = ax² + bx + c

0 = 2x² + 5x + 3   ➜   b = 5

Answer:

1,2

Step-by-step explanation:

if this is wrong, pls say so

Answer:

31 friends

Step-by-step explanation:

Raghu has purchased 31/4 m of cloth. Out of this, he wanted to distribute 1/4 m of cloth to each of his friends. Find the number of friends to whom he can distribute the cloth.​

To divide fractions, invert one fraction:

31/4 ÷ 1/4 becomes: 31/4 × 4/1

this can be reduced to by dividing the first denominator by 4 and the second numerator by 4:

31/1 × 1/1

= 31 friends

The percent chance that both dice show an even number on their first toss is 25%.

An experiment consists of tossing two 12-sided dice. The task is to find the percent chance that both dice show an even number on their first toss.
To calculate the probability, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's find the total number of possible outcomes. Each die has 12 sides, so the total number of outcomes for each die is 12. Since we are tossing two dice, we multiply the total number of outcomes for each die by itself: 12 * 12 = 144.
Next, let's find the number of favorable outcomes. In this case, a favorable outcome occurs when both dice show an even number on their first toss. Since there are six even numbers on each die (2, 4, 6, 8, 10, 12), the number of favorable outcomes is 6 * 6 = 36.
Now, we can calculate the probability by dividing the number of favorable outcomes by the total number of possible outcomes: 36 / 144 = 0.25.
To express this probability as a percent, we multiply the decimal by 100: 0.25 * 100 = 25%.

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km to cm: multiply the value of km by 100000

mm to cm: divide the number of mm by 10 to get the number of cm

liters to ml: multiply the volume value by 1000

Answer:

Kilometers to Centimeters (km to cm) Conversion, 1 km is 100000 cm.

The conversion from millimeters to centimeters is done with the help of this formula: mm / 10 = cm.

To convert liters to milliliters, we multiply the given value by 1000 because 1 liter = 1000 m

Step-by-step explanation: Hope this helps!! :))

Based on the variable declarations and initializations you provided:
int a = 2; int b = 6; int c = 3;
An expression that evaluates to false would be one where the conditions are not met. For example:
(a + b == c)
This expression checks if the sum of a and b is equal to c. In this case, (2 + 6) is not equal to 3, so the expression evaluates to false.

One possible solution is:
The given variable declarations and initializations are:
int a = 2;
int b = 6;
int c = 3;

To evaluate which of the following expressions is false, we need to look at each expression and see if it produces a Boolean value of false.
a < b || c > b

This expression is true because 2 is less than 6 and 3 is greater than 6. Therefore, the OR operator (||) returns true because at least one of the operands is true.
a + b > c && c - a < b

This expression is true because 2 + 6 is greater than 3 and 3 - 2 is less than 6. Therefore, the AND operator (&&) returns true because both operands are true.
b % c == a || c * b < a

This expression is false because 6 % 3 is equal to 0, which is not equal to 2. Therefore, the equality operator (==) returns false. Moreover, 3 times 6 is 18, which is not less than 2. Therefore, the second operand is also false. Therefore, the OR operator (||) returns false because both operands are false.

Therefore, the expression "b % c == a || c * b < a" evaluates to false.

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Answer:

i’m not sure good luck

Step-by-step explanation:

The height & speed are mathematically given as

t = 0.2 s

u = 4 m/s

Generally, the equation for height is  mathematically given as

h = 0.2gt^2

Therefore

0.2 = 0.5 * 9.8 *\(t^2\)

0.2 = 4.9 *\(t^2\)

t = 0.2 s

b)

In conclusion, the initial speed is

s = ut

Therefore

u = 0.8 / 0.2

u = 4 m/s

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The level of significance in hypothesis testing is the probability of: c. rejecting a true null hypothesis. In hypothesis testing, the critical value is:
a. a number that establishes the boundary of the rejection region.

Probability is a branch of mathematics in which the chances of experiments occurring are calculated. It is by means of a probability, for example, that we can know from the chance of getting heads or tails in the launch of a coin to the chance of error in research. In statistics , a null hypothesis is a statement that one seeks to nullify with evidence to contrary most commonly it is a statement that the phenomenon being studied produces no effect on makes no difference.

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Answer:

Cheetah A ran at a faster speed than Cheetah B, as it ran 18 miles in 16 minutes while Cheetah B ran 54 miles in 50 minutes.

Step-by-step explanation:

Answer: its A

Step-by-step explanation: