In J, how much heat is required to raise the temperature of 1.23 kg of water from 23.6°C to 84.9°C?

The average rate of reaction for the time interval from 0 s to 155 s is 0.00444 M/s, the average rate of reaction for the time interval from 155 s to 516 s is 0.00371 M/s, and the average rate of reaction for the time interval from 516 s to 735 s is 0.00412 M/s.

To calculate the average rate of reaction for each successive time interval, we will use the formula:

Average rate of reaction = (change in concentration)/(change in time)

The table is derived as follows:

Time interval (s) [N2O4] (M) Change in [N2O4] (M) Average rate of reaction (M/s)

0-155 2.482 2.482 - 1.794 = 0.688 0.688/155 = 0.00444

155-516 1.794 1.794 - 0.735 = 1.059 1.059/(516-155) = 0.00371

516-735 0.735 0.735 - 0.516 = 0.219 0.219/(735-516) = 0.00412

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Answer:

Molarity = 1.28

Explanation:

\(m= n/v\)

M = molar concentration

n = moles of solute

v = liters of solution

Molarity = moles of solute / litres of solution.

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Answer: empirical formula of any compound is the simplest proportion of elements in that compound (i.e. the composition of elements in compound is in simplest ratio ) .It does not provide actual formula of any compound.

molecular formula=n-factor * empirical formula

molecular formula - C6H12O6 (glucose)

empirical formula - CH2O

C6H12O6 * CH2O

Answer: Sodium Hydroxcide.

Explanation:

A teacher told me this answer

The given question is incomplete. The complete question is:

A chemist prepares a solution of mercury(I) chloride \(Hg_2Cl_2\) by weighing out 0.537 mg of mercury(I) chloride into a 400. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in g/dL of the chemist's mercury(I) chloride solution. Round your answer to 3 significant digits

Answer: The concentration in g/dL of the chemist's mercury(I) chloride solution is \(1.34\times 10^{-4}\)

Explanation:

Concentration of a solution is defined as how many grams of solute in=s dissolved in a particular amount of solvent.

Given :  mass of mercury (I) chloride = 0.537 mg = \(5.37\times 10^{-4}g\)      \((1mg=0.001g)\)

Volume of solution = 400 ml = 4 dL     (1ml=0.01dL)

Thus concentration of mercury (I) chloride in g/dL is = \(\frac{5.37\times 10^{-4}g}{4dL}=1.34\times 10^{-4}g/dL\)

The concentration in g/dL of the chemist's mercury(I) chloride solution is \(1.34\times 10^{-4}\)

Answer:

a

Explanation:

Answer:

0.00295M

Explanation:

Mass Concentration = mass/vol

= 0.203 g/ 0.02414 L = 8.409 g/L

But molarity = Mass conc / molar mass

∴ Molar mass(mol/L) = mass conc / molarity

= .84909 / 0.0295

= 285.06 g/mol

If 1 mol of green stock - 285.06g

? mol - 0.203 g

= 0.00071213 g

= 0.00071213 g / .2414L = 0.0095 mol/L.

According to Le Chatelier's principle, the equilibrium will change to raise the reactant concentration. Reactants will grow as the pace of a reverse reaction increases.

The equilibrium will move towards to the opposite side of the response where there are fewer moles when the volume is reduced. The equilibrium will benefit the reactants in this situation since there are less moles of reactants, shifting to the left.

In a sealed container, a reversible reaction cannot occur since neither products nor further reactants may enter. We call this a closed system. If there is a physical or mental balance, there is an equilibrium. This indicates that the forward and reverse motions are balanced in terms of chemistry.

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Answer:

Assign an oxidation state to each element in each reaction and use the change in oxidation state to determine which element is being oxidized and which element is being reduced.

1. C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(g)

2. C2H4(g)+Cl2(g)→C2H4Cl2(g)

Explanation:

1- In the reaction, C6H12O6(s)+6O2(g)→6CO2(g)+6H2O(g), the oxidation state of each element changes as follows:

C6H12O6: C: -1 to +4; H: +1 to +1; O: -2 to -2

O2: O: 0 to -2

CO2: C: +4 to +4; O: -2 to -2

H2O: H: +1 to +1; O: -2 to -2

2- In this reaction, oxygen (O2) is being reduced, since its oxidation state changes from 0 to -2. Carbon (C6H12O6) is being oxidized, since its oxidation state changes from -1 to +4.

In the reaction, C2H4(g)+Cl2(g)→C2H4Cl2(g), the oxidation state of each element changes as follows:

C2H4: C: -3 to -2; H: +1 to +1

Cl2: Cl: 0 to 0

C2H4Cl2: C: -2 to -2; H: +1 to +1; Cl: 0 to -1

In this reaction, chlorine (Cl2) is being reduced, since its oxidation state changes from 0 to -1. Ethene (C2H4) is being oxidized, since its oxidation state changes from -3 to -2.

Answer:

the amount of water vapor in the air compared to the amount it can hold

Explanation:

By definition, relative humidity is equal to the partial pressure of water divided by the total amount of water that the air can hold at that temperature. The last one basically restates the definition. (Partial pressure is the number of particles of a substance divided by the total number of particles.)

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Answer:

Explanation:

ABC Powder: sprays a very fine chemical powder. This acts to blanket the fire and suffocate it. Class A, B, C fires

Carbon dioxide: extinguishes CO2. By doing so, it removes oxygen from the fire, effectively suffocating it of oxygen. Class B fires

Foam: spray a type of foam that expands when it hits the air and blankets the fire. This prevents the vapors from rising off the liquid to feed the fire, thus starving it of fuel. Class A and B

Water: releases microscopic water molecules that fight the fire on a variety of levels. the level of oxygen in the air is decreased, which helps to suffocate the fire. Class: most all

also, your fire classes:

Class A: freely burning, combustible solid materials such as wood or paper

Class B: flammable liquid or gas

Class C: energized electrical fire (energized electrical source serves as the ignitor of a class A or B fire – if electrical source is removed, it is no longer a class C fire)

Class D: metallic fire (titanium, zirconium, magnesium, sodium)

Class K: cooking fires – animal or vegetable oils or fats

In the given reaction, the reactants are hydrochloride acid (HCI) and sodium hydroxide (NaOH). The products are sodium chloride (NaCl) and water.

The chemical equation provided represents a neutralization reaction between hydrochloric acid (HCI) and sodium hydroxide (NaOH) in aqueous solution.

A neutralization reaction is a type of double displacement reaction in which an acid and a base react to form salt and water.

The reactants in this equation are hydrochloric acid (HCI) and sodium hydroxide (NaOH). Hydrochloric acid is a strong acid that dissociates in water to form hydrogen ions (H+) and chloride ions (Cl-). Sodium hydroxide, on the other hand, is a strong base that dissociates in water to form sodium ions (Na+) and hydroxide ions (OH-).

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Answer:

Their energes can have any values

Explanation:

Answer:

48.0 grams

Explanation:

The products of this reaction are nitrogen gas and water. How many grams of sodium hydroxide (NaOH) are needed to completely react with 50.0 grams of sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4) and water? 2NaOH + H2SO4 → Na2SO4 + 2H2O ; 48.0 grams of NaOH are needed.

51.020  grams of sodium hydroxide is needed to completely react with 50 grams of sulfuric acid according to stoichiometry.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining  weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

The reaction between sodium hydroxide and sulfuric acid is as follows,

2 NaOH + H₂SO₄\(\rightarrow\)Na₂SO₄+2 H₂O

From the reaction, it is clear  that 2 oles of sodium hydroxide react with 1 mole of sulfuric acid to give products. According to molar mass concept,

100 g of sodium hydroxide gives 98 g of sulfuric acid

Therefore, 50 gram of sulfuric acid requires 50×100/98=51.020 g

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Answer:

True

Explanation:

Theories are ideas which are used to make predictions

Answer:

c. The waves from the speaker are mechanical waves.

d. The frequency or amplitude of the waves could change.

g. The speaker does not change the wave type.

These statements are true. The waves that come out of the speaker are mechanical waves, meaning they require a medium to travel through, such as air or water. The frequency and amplitude of the waves could change, depending on the characteristics of the sound being played through the speaker. The speaker does not change the type of wave from mechanical to electromagnetic, or vice versa.

Diatomic: Composed of two atoms. Polar: A bond with a negative end and a positive end. Nonpolar: A bond in which neither atom takes more than its share of electrons. Metallic: A type of bond that allows valence electrons to move freely among ions. Electronegativity: Determines what type of bond will form.

The ability of an atom or functional group to draw electrons to itself is known as electronegativity in chemistry.

Diatomic molecules consist only of two atoms, whether they are from the same or distinct chemical elements.

Since charges fluctuate, a momentary dipole moment occurs in a so-called nonpolar molecule at any given time if the charge arrangement is spherically symmetric when averaged across time.

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Answer:

The answer to your question is ⇔ anaphase

So it would be anaphase is the phase where the chromosones pull apart.

Explanation:

The sister chromatids are pairs of identical copies of DNA joined at a point called the centromere. During anaphase, each pair of chromosomes is separated into two identical, independent chromosomes. The chromosomes are separated by a structure called the mitotic spindle.

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Answer:

P₂ = 647 torr

Explanation:

Given data:

Initial pressure = 565 torr

Initial temperature = 27°C

Final temperature = 71°C

Final pressure = ?

Solution:

Initial temperature = 27°C (27+273 = 300 K)

Final temperature = 71°C (71+273 = 344 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

565 torr / 300K = P₂/344 K

P₂ = 565 torr × 344 K / 300 K

P₂ = 194360 torr. K /293 K

P₂ = 647 torr

Answer:

1.71 moles of sodium azide are needed to produce sufficient nitrogen to fill a 50.0 L air bag to a pressure of 1.25 atm at 25 C.

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case, you know:

Replacing:

1.25 atm* 50 L= n* 0.082 \(\frac{atm*L}{mol*K}\) *298 K

Solving:

\(n=\frac{1.25 atm* 50 L}{0.082\frac{atm*L}{mol*K}*298 K}\)

n= 2.56 moles

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

Then you can apply the following rule of three: if by reaction stoichiometry 3 moles of N₂ are produced from 2 moles of NaN₃, 2.56 moles of N₂ are produced from how many moles of NaN₃?

\(moles of NaN_{3} =\frac{2.56 moles of N_{2}* 2 moles of NaN_{3} }{3 moles of N_{2}}\)

moles of NaN₃= 1.71

1.71 moles of sodium azide are needed to produce sufficient nitrogen to fill a 50.0 L air bag to a pressure of 1.25 atm at 25 C.

The equation in which the enthalpy of formation is the same as the enthalpy of reaction is option A.

The term enthalpy has to do with the heat that is giving out or is absorbed in a reaction. We know that the enthalpy of formation would refer strictly to the heat that is given out or absorbed when a substances is formed from its constituents under standard conditions.

We know that when we are looking at the enthalpy of formation of a substance, we are looking at the way that the elements that make up the substance are able to combine and these elements that are becoming combined in the substance would have to do that under standard conditions so as to generate the equation of the enthalpy of formation of the substance.

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Answer:

c

Explanation:

fossil records

The kJ of the energy absorbed for the every mole of the carbon reacted is 104.8 kJ.

The chemical equation is as :

2C + 2H ---> C₂H₄   ,     ΔH = + 52.4 kJ/mol

The ΔH is the enthalpy change that is determined by the subtracting the energy of the reactants to the products.

The  ΔH = energy of the products - energy of the reactants

The expression for the energy is as :

q = n ΔH

Where,

n = number of the moles

ΔH = enthalpy change

The kJ of the energy absorbed for the every mole of the carbon reacted :

q = 2 mol × 52.4 kJ/mol

q = 104.8 kJ

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Answer:

\(\huge\boxed{\sf v = 0.004\ m\³}\)

Explanation:

Mass = m = 4 kg

Density of water = 1000 kg/m³ (Standard)

Volume = v = ?

Density = m/v

1000 = 4 / v

1000 × v = 4

v = 4/1000

v = 0.004 m³

\(\rule[225]{225}{2}\)

Answer:

1s22s22p63s23p4

Explanation:

Sulfur is located in the p block and has 6 valence electrons (the 2 exponent on the 3s and the 4 exponent on the 3p add up to 6)

The location and energy of all the valence electrons of electrically-neutral sulfur ( S ) is 3s₂3p₄.

Chemical element sulfur has the letter S and atomic number 16. It is multivalent, nonmetallic, and plentiful. Sulfur atoms normally combine to create cyclic octatomic molecules, which have the chemical formula S8. At room temperature, elemental sulfur is a crystalline solid that is brilliant yellow.

In addition to being a fungicide and an ingredient in black gunpowder, sulfur is used to vulcanize black rubber. However, the majority of sulfur is utilized in the creation of sulfuric acid, which is arguably the most significant chemical produced by western civilisations.

Sulfur can be found naturally and in metal sulfide ores. Natively, it may be found close to hot springs and volcanoes.

Thus, option B is correct.

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The amount of the sample remaining at 4pm is 0.0625 g

We'll begin by calculating the number of half-lives that has elapsed

Half-life (t½) = 1 hour

Time (t) = 4 hour

n = t / t½

n = 4 / 1

Number of half-lives (n) = 4

Initial amount (N₀) = 1 g

\(N = \frac{N_0}{ {2}^{n}} \\ \\ N = \frac{1}{ {2}^{4}} \\ \\ N = \frac{1}{16} \\ \\ N = 0.0625 \: g\)

Thus, the amount remaining at 4pm is 0.0625 g

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