In Figure (a), both batteries have em - 1.20 V and the external resistance R is a variable resistor. Figure (6) gives the electric potentials V between the terminals of each battery as functions of
Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by R, -0.500 . What is the internal resistance of (a) battery 1 and (b) battery 2?
0.60
V(V)
0
-0.350
(
R(0)
(6)

The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.

Acceleration due to gravity is a form of acceleration that is exercised by the gravitational pull of the earth its value is fixed at the surface n is equal to 9.8u.

Aries composed of molecules and their food when an object passes through air strikes the a molecules they are molecules according to Newton's third law strike back at the object therefore reducing its speed. This force by the molecule is known as air friction.

The setup of the given experiment consists of:

A bob of mass m

A stopwatch with high accuracy

An inch tape

A speedometer

Experiment is conducted in the following manner:

Using Newton's first law of motion

i.e. v = u + a × t  

Where,

u is initial velocity

v is final velocity

a is acceleration due to gravity

t is time taken to cover distance

From the data given v = 16.82m/s

t is 2 seconds

Substituting value in Newton's first law of motion we get

Value of acceleration due to the gravity = 8.41

Therefore, The experimental value of the expression due to gravity through the experiment will come out to be 8.41u, the error in the value has Accord because of air friction.

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Answer:

SI is used in most places around the world, so our use of it allows scientists from disparate regions to use a single standard in communicating scientific data without vocabulary confusion

Answer:

2 Pascal (Pa)

Explanation:

Pressure is defined as the force acting per unit area. Mathematically, it is expressed as:

Pressure (P) = Force (F) / Area (A)

Given:

Force exerted by the air inside the balloon (F) = 1 N

Area of the balloon (A) = 0.5 m^2

Plugging in the given values into the formula for pressure, we get:

P = F / A

P = 1 N / 0.5 m^2

Using basic arithmetic, we can calculate the pressure inside the balloon:

P = 2 N/m^2

So, the pressure inside the balloon is 2 N/m^2, which is also commonly referred to as 2 Pascal (Pa) since 1 Pascal is equal to 1 N/m^2.

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

Explanation:

The choices are:

A) IV. This property can only be determined by chemical reacting the sample of sulfur.

B) I and II. These properties can only be determined by chemical reacting the sample of sulfur.

C) III. These properties can be determined by physical measurements. The sulfur does not need to react, chemically, in order to measure these properties.

C) III. These properties can be determined by physical measurements. The sulfur does not need to react, chemically, in order to measure these properties.

The answer is A and B as both characteristics can only be determined by chemical reacting so they are chemical properties.

Answer:

a

Explanation:

i just did this on usatestprep.

The total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

What is Work Done?

Work is a physical quantity that describes the amount of energy transferred when a force acts on an object and causes it to move. When a force acts on an object and causes it to move in the direction of the force, work is said to be done on the object. Mathematically, work is defined as the dot product of force and displacement:

Work = Force x Displacement x cos(theta)

To calculate the total work done on the mass as it moves from position x1 to x2, we need to find the net work done by all the forces on the mass. The net work done by a force is given by the formula:

W = F * d * cos(theta)

where W is the work done, F is the force, d is the displacement of the mass, and theta is the angle between the force and the displacement.

First, we can calculate the work done by each force separately and then add them up to find the total work done.

Work done by F1:

W1 = F1 * (x2 - x1) * cos(0) = 5 N * 40 m * cos(0) = 200 J

Work done by F2:

W2 = F2 * (x2 - x1) * cos(50°) = 6 N * 40 m * cos(50°) ≈ 165.41 J

Work done by F3:

W3 = F3 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

Work done by F4:

W4 = F4 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

The total work done on the mass is the sum of the work done by each force:

W_total = W1 + W2 + W3 + W4 ≈ 515.17 J

Therefore, the total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

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No, the system is not in equilibrium because the forces are not balanced which caused acceleration In system.

In mechanics, a force is any action that seeks to preserve, modify, or deform a body's motion. Isaac Newton's three principles of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the idea of force (1687).

Newton's first law states that unless a force is applied to a body, it will stay in either its resting or uniformly moving condition along a straight path. According to the second law, when an external force applies on a body, the body accelerates (changes velocity) in the force's direction.

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Answer:

The planet on the sun that come from the heat

Answer:

Theres no given?

Explanation:

Well, whatever.

I observed the shift of their sunset time.

Examples like:

January to June = their sunset time increased while

July to December = their sunset time decreased

Answer:

4210 W

Explanation:

We'll begin by calculating the energy required in lifting the water from the depth. This can be obtained as follow:

Mass (m) = 1200 Kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E₁) =?

E₁ = mgh

E₁ = 1200 × 9.8 × 10

E₁ = 117600 J

Next, we shall determine the energy required to project the water at 15 m/s. This can be obtained as follow:

Mass (m) = 1200 Kg

Velocity (v) = 15 m/s

Energy (E₂) =?

E₂ = ½mv²

E₂ = ½ × 1200 × 15²

E₂ = 600 × 225

E₂ = 135000 J

Finally, we shall determine the power of the motor. This can be obtained as follow:

Total energy (E) = E₁ + E₂

= 117600 + 135000

= 252600 J

Time (t) = 1 min = 60 s

Power (P) =?

P = E/t

P = 252600 / 60

P = 4210 W

Therefore, the power of the motor is 4210 W.

If I were an astronaut, the first job I would do on the International Space Station (ISS) would be to familiarize myself with the station and its systems.

I would need to learn how to operate the various equipment and how to maintain the station in good working order. I would also need to learn the procedures for conducting experiments and for performing spacewalks.

Once I had a good understanding of the station and its systems, I would begin working on my assigned tasks. These tasks could include conducting experiments, performing maintenance, or teaching other astronauts new skills. I would also take the opportunity to conduct research on my own and to learn more about the space environment.

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In order to calculate the tension in the pendulum cod, let's start by sketching the problem:

At this point, all the mechanical energy is potential energy, given by:

At position 20°, we will have both kinetic and potential energies:

Now, let's decompose the weight force in the directions along (Wy) and perpendicular (Wx) to the cord:

The sum of the forces along the cord will be equal to the centripetal force:

From the kinetic energy equation, we have:

Using this value of v² in the previous equation, we have:

Answer:

My greatest scientist is David Baltimore.

Explanation:

David Baltimore is an American biologist, university administrator, and 1975 Nobel laureate in Physiology or Medicine. He is currently President Emeritus and Distinguished Professor of Biology at the California Institute of Technology, where he served as president from 1997 to 2006.

Hope I helped! Ask me anything if you have any questions. Brainiest plz!♥ Hope you make a 100%. Have a nice morning! -Amelia♥

Answer:

Monarchy is rule from kings and queens

Explanation:

The change in the displacement is 70 m

Recall that the displacement is obtained as the product of the velocity and time. We have the velocity at two intervals.

At v1, the displacement can be obtained from;

x1 = 0.5 * 20 = 10 m

At v2, the displacement can be obtained as;

x2 = 2 * 40 = 80 m

Now

Δx = 80 m - 10 m = 70m

Thus the change in the displacement is 70 m

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Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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Answer:

yes

Explanation:

The angle of reflection is the angle between the reflected ray and the normal to the surface

The angle of reflection is the angle made by the reflected ray with the surface, measured relative to the normal, and is equal to the angle of incidence, which is the angle between the incident ray and the normal.

The angle of reflection can be determined using the law of reflection, which states that the angle of incidence is equal to the angle of reflection. This law applies to the reflection of light, sound, and other waves from a smooth, flat surface, such as a mirror or a still body of water.

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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The kinetic energy of the brick equal the elastic potential energy at the top of the hill. Using this, the speed of the brick is 14 m/s.

The elastic potential of a spring is directly proportional to the squire of the displacement.

Then,

p = 1/2 k x²

Given that, spring constant k = 500 N/m

height of the hill x = 2 m

weight of the load = 100 N

then mass = 100N/9.8 m/s² =10.20 Kg.

At the top of the hill, kinetic energy of the hill is equal to the elastic potential.

then, 1/2 mv² =  1/2 k x²

speed v of the brick  = √kx²/m

v = √(500 N/m × 2 m²/10.20 kg)

  = 14 m/s.

Therefore, the speed of the brick at the top of the hill is 14 m/s.

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Answer:

About 1200J

(If we take gravity to be 10m/s^2)

Explanation:

U=mgh

m=6kg

g=10m/s^2

h=20m

U=(6)(10(20)=1200J

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

Explanation:

The formula for kinetic energy to be used here is 1/2mv².

If the first particle is "particle a" and the second particle is "particle n"; there kinetic energies (K.E) will be

K.Eₐ = 1/2.m2v² = mv²

K.Eₙ = 1/2.2mv² = mv²

From the above, it can be said that there kinetic energies are the same.

NOTE that the m and v used in the question means mass and velocity respectively.

(a) The tension on the wire when the two charges have opposite signs is 383.5 N.

(b) The tension on the wire if both charges were negative is 3.640.25 N.

The given parameters;

(a)

The attractive force between the charges is calculated as follows;

\(F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N\)

The force on the negative charge due to the electric field is calculated as follows;

\(F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N\)

The tension on the wire is the resultant of the two forces and it is calculated as follows;

\(T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N\)

(b) when the two charges are negative

The repulsive force between the two charges is calculated as follows;

\(F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N\)

The force on the first negative charge due to the electric field is calculated as follows;

\(F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N\)

The force on the second negative charge due to the electric field is calculated as follows;

\(F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N\)

The tension on the wire is the resultant of the three forces and it is calculated as follows;

\(T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N\)

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Answer:

NO

Explanation:

I dont care

By working with percentages, we want to see how many inches is the center of gravity out of the limits. We will find that the CG is 1.45 inches out of limits.

First, we need to find the limits.

We know that the MAC is 58 inches, and the limits are from 26% to 43% MAC.

So if 58 in is the 100%, the 26% and 43% of that are:

But we know that the CG is found to be 45.5% MAC, then it measures:

(45.5%/100%)*58in = 0.455*58in = 26.39 in

We need to compare it with the largest limit, so we get:

26.39 in - 24.94 in = 1.45 in

This means that the CG is 1.45 inches out of limits.

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The statement that is NOT true is "the spaces between the particles increased.

option D.

If we consider the solids and liquids, when the temperature increases the molecules gain energy and start moving in all directions. This expands the substance and the volume of the substance increases.

Similar, when the ball is heated, the volume of the ball increases due to thermal expansion.

As the temperature increases, the average kinetic energy of the particles within the ball also increases, causing them to move faster.

However, the spaces between the particles do not necessarily increase. In fact, the expansion of the ball occurs due to the particles themselves moving farther apart, but the intermolecular spacing within the ball remains relatively constant.

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Answer:True

Explanation:

Answer:

e:10 m   b: -5 m/s b.The object decreases its velocity.

Explanation: