In another version of the "Giant Swing", the seat is connected to two cables as shown in the figure (Figure ), one of which is horizontal. The seat swings in a horizontal circle at a rate of 39.3 rev / m * i * n
If the seat weighs 268 N and a 896-N person is sitting in it, find the tension in the horizontal cable
If the seat weighs 268 N and a 896-N person is sitting in it, find the tension in the inclined cable
Answers
Answer:Solution to 47E Step 1 Angular velocity of the swing=32rpm Weight of the seat =255N Weight of the person =825N Total weight =255+825=1080N Radius =7.5m
Explanation:
Related Questions
A runner starts from rest and attains a speed of 8.00ft/s after 2.00s. What's the runner's acceleration? (keep the answer in ft/s^2)
Answers
Answer:
4 ft/s^2
Explanation:
If the velocity is 8ft/s after 2s then to find the acceleration you would use the formula:
\(\frac{v_f - v_{i} {}}{t} =a\)
sooooooooo
\(\frac{8 ft/s - 0 ft/s }{2 s} = \frac{8 ft/s }{2 s} = 4 ft/s^{2}\)
A runner starts from rest and attains a speed of 8.00ft/s after 2.00s. The runner's acceleration obtained is 4.00 ft/s².
Given:
Final velocity (v) = 8.00 ft/s
Initial velocity (u) = 0 ft/s (starting from rest)
Time (t) = 2.00 s
Acceleration (a) can be calculated using the formula:
Acceleration (a) = Change in velocity / Time
Change in velocity = Final velocity - Initial velocity
Substitute the values:
Change in velocity = 8.00 - 0
Change in velocity = 8.00 ft/s
The acceleration is calculated as:
Acceleration (a) = Change in velocity / Time
Acceleration (a) = 8.00 / 2.00
Acceleration (a) = 4.00 ft/s²
Hence, the runner's acceleration is 4.00 ft/s².
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Why is the pressure so high deep inside the outer planets?
Answers
Answer:
Due to its larger size
Explanation:
This is due to those planets being much larger than Earth. The larger a planet is, the more gravity that planet has, since gravity is mainly calculated based on the mass and radius of the planet. Also since the pressure deep inside of the planet depends mainly on the gravity of that planet on the surface, this is calculated as the square of the planet's surface gravity. Ultimately, the bigger the planet is the higher the pressure deep inside the planet will be.
A storage tank 20 m high is filled with pure water. (Assume the tank is open and exposed to the atmosphere at the top.)
(a) Find the gauge pressure at the bottom of the tank.
(b) Calculate the magnitude of the net force that acts on a square access hatch at the bottom of the tank that measures 0.6 m by 0.6 m.
PLEASE HELP ASAP!!!
Answers
A. The overpressure at the bottom of the tank is 297500 N/m².
B. The magnitude of the net force acting on the square access hatch at the bottom of the tank is 107100 N.
Multiplying the flow rate by the minimum operating time of the pump gives the descending capacity. As a rule of thumb for a minimum run time, a pump operating at 10 gallons per minute GPM or less should produce a run time of 1 gallon per minute. For example, 10 GPM flow rate x 1 = 10 gallon drawdown capacity.
This means that the gauge pressure is equal to the absolute pressure minus the atmospheric ambient pressure. If the absolute pressure is greater than the atmospheric pressure it is called positive overpressure. If the absolute pressure is lower than atmospheric pressure it is called negative overpressure. The hydrostatic pressure at any height below water is calculated by P = hdg. where h is the height below open water.
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The wave equation says that a waves __ is equal to its wavelength times is frequency.
Answers
Answer:
speed
Explanation:
The wave equation says that a waves speed is equal to its wavelength times is frequency.
(12 points, suggested time 25 minutes)
A block of mass me can be attached to a parachute of negligible mass and radius T, as shown in the two views
above. When falling, the parachute experiences an upward force of air resistance. This force increases as the speed
of the parachute increases. The falling block and parachute
speed up at first but eventually reach a constant speed
called terminal speed
(a) The dot below represents the block-parachute system when it has reached its terminal speed and is falling at
this constant speed. On the dot, draw and label the forces (not components) acting on the system. Represent each
force by a distinct arrow starting on, and pointing away from the dot.
Note: Draw the relative lengths of all vectors to reflect the relative magnitudes of all the forces.
Answers
Answer:
Explanation:
Please follow the directions here and draw out the answer yourself.
Draw two arrows of the same length. Both start on the dot but one points up and the other points down.
Label the up arrow as "Air resistance" and the down arrow as "Weight, Me*g". Make sure the two arrows have the same length and are directly opposite each other.
The free-response to the question based on the given diagram is:
Draw two arrows of the same length. Both start on the dot but one points up and the other points down.Label the up arrow as "Air resistance" and the down arrow as "Weight, Me*g". Make sure the two arrows have the same length and are directly opposite each other.What is a Parachute?This refers to the apparatus or equipment that is used to help a person to descend slowly from a high altitude.
Hence, given that a block of mass is attached to a parachute and while descending, it encounters air resistance, then to show the relative length of all vectors:
Two arrows of the same length needs to be drawn.One of them points in an upwards direction.The other points in the downwards direction.The arrow pointing upwards would be labeled as "Air Resistance", the other would be labeled as "Weight" and they are opposite each other.Read more about air resistance here:
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an 8.3 kg mass is attached to a string that has a breaking strength of 1500 N. If the mass is whirled in a horizontal circle of radius 80 cm, what maximum speed can it have?
Answers
Answer:
To determine the maximum speed that the 8.3 kg mass can have without breaking the string, we need to consider the tension in the string when it reaches its maximum. At maximum speed, the tension in the string will be equal to the breaking strength of the string.
Given:
Mass (m) = 8.3 kg
Breaking strength of the string (Tension) = 1500 N
Radius of the circle (r) = 80 cm = 0.8 m
The centripetal force required to keep an object moving in a circular path is given by the formula:
F = m * v² / r
Where:
F = Centripetal force
m = Mass
v = Velocity
r = Radius
In this case, the centripetal force is provided by the tension in the string. So we have:
Tension = m * v² / r
Plugging in the values:
1500 N = (8.3 kg) * v² / 0.8 m
To find the maximum speed (v), we can rearrange the equation and solve for it:
v² = (1500 N * 0.8 m) / 8.3 kg
v² ≈ 144.58 m²/s²
v ≈ √(144.58 m²/s²)
v ≈ 12.03 m/s
Therefore, the maximum speed that the 8.3 kg mass can have without breaking the string is approximately 12.03 m/s.
Explanation:
A 6.35 kg bowling ball moving 8.49 m/s strikes
a 1.59 kg bowling pin at rest. After, the pin moves 20.1 m/s at a -77.0° angle. What is
the x and y component of the ball's final velocity?
Answers
The x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Mass of the ball: M = 6.35 kg.
Initial velocity of ball: U = 8.49 m/s.
Mass of the pin at rest: m = 1.59 kg.
Final velocity of pin: v = 20.1 m/s at a -77.0° angle.
Let the x and y component of the ball's final velocity are respectively V₁ m/s and V₂ m/s.
Appling conservation of momentum along x axis:
MU + m.0 = MV₁ + mvcos(-77.0°)
⇒ V₁ = u - (m/M) v cos(-77.0°)
After putting the values we get:
V₁ = 7.35 m/s.
Appling conservation of momentum along y-axis:
M.0 + m.0 = MV₂ + mvsin(-77.0°)
⇒ V₂ = - (m/M) vsin(-77.0°)
After putting the values we get:
V₂ = 4.90 m/s.
Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
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How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.A cylindrical solenoid with radius 1.00 cm
and length 10.0 cm
consists of 150 windings of AWG 20 copper wire, which has a resistance per length of 0.0333 Ω/m
. This solenoid is connected in series with a 10.0 μF
capacitor, which is initially uncharged. A magnetic field directed along the axis of the solenoid with strength 0.160 T
is switched on abruptly.
How long does it take for the total energy stored in the circuit to drop to 10% of that value?
Express your answer with the appropriate units.
Answers
The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.
The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.
Initially, the capacitor is uncharged, so the second term is zero.
Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.
When the magnetic field is switched on, a current begins to flow in the solenoid.
This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.
Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.
The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.
Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.
This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.
The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)
The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)
The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)
This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.
The solution is t = 1.74 ms.
The units are in seconds.
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To measure the heat capacity of an object, all you usually have to do is put it in thermal contact with another object whose heat capacity you know. As an example, suppose that a chunk of metal is immersed in boiling water (100°C), then is quickly transferred into a Styrofoam cup containing 250 g of water at 20°C. After a minute or so, the temperature of the contents of the cup is 24°C. Assume that during this time no significant energy is transferred between the contents of the cup and the surroundings. The heat capacity of the cup itself is negligible.
What is the heat capacity of this chunk of metal?
Answers
Answer:
The answer is "\(55.05 \ \frac{J}{K}\)"
Explanation:
Given value:
\(Q_m=4.184 \times 10^3 \ J\\T_0=100^{\circ}\\T_1=24^{\circ}\)
Calculating the heat capacity of this chunk of metal:
Using formula:
\(C_m=\frac{Q_m}{T_0-T_1}\\\)
\(=\frac{4.184 \times 10^3}{100 -24}\\\\=\frac{4.184 \times 10^3}{76}\\\\=55.05 \ \frac{J}{K}\)
Explain what happens with the 0.25 days each year
Answers
Answer:
leap year
Explanation:
Which chart correctly describes the properties of magnets and electromagnets?
Answers
Answer:
The second chart seems to be correct
Explanation:
Finding the density without having the mass having only volume
Answers
.............................................
Why does Earth have a liquid water supply and Mars does not?
A. Mars is too cold.
B. Mars has no magnetic field.
C. Earth was never bombarded with comets.
D. Mars is much larger than Earth.
Answers
Answer:
Earth have a liquid water supply and Mars does not because of the difference in their magnetic fields. Therefore the option B is correct.
Explanation:
The atmosphere of Earth is shielded from solar winds and radiation by a potent magnetic field, which keeps the atmosphere from being torn away. This enables water to remain liquid on the surface of the planet.
Mars, in contrast, has a weaker magnetic field, which results in a thinner atmosphere that is unable to support liquid water. Mars is hence more colder and drier than Earth.
One of the main reasons that Mars has no life as we know it is because it lacks a magnetic field, whereas the magnetic field of Earth is crucial in fostering the conditions necessary for life to flourish.
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A bus with a maximum speed of 20m/s takes 21sec to travel 270m from stop to stop. Its acceleration is twice as great as its deceleration.
Find
1. The acceleration
2. The distance travelled at maximum speed
Answers
The acceleration can be calculated using the formula:
Acceleration = (Final velocity - Initial velocity) / Time taken
Given that the bus starts from rest, the initial velocity is 0 m/s.
Acceleration = (20 m/s - 0 m/s) / 21 sec = 20/21 m/s².
The distance travelled at maximum speed can be calculated by subtracting the distances covered during acceleration and deceleration from the total distance.
Distance during acceleration = (1/2) * acceleration * time² = (1/2) * (20/21 m/s²) * (21 sec)² = 210 m.
Distance during deceleration is the same as distance during acceleration.
Distance travelled at maximum speed = Total distance - 2 * distance during acceleration = 270 m - 2 * 210 m = -150 m.
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explain why the ray does not bend when it enters the semi circular glass block
Answers
The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.
Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.
Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.
Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.
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how does Math work in periodic Tables like protons neutrons and electrons
Answers
Answer:
The stability of isotopes is affected by the ratio of protons to neutrons and also by the presence of certain “magic” numbers of protons or neutrons that represent closed and filled quantum shells. These quantum shells correspond to the shell model of the nucleus. Filled shells confer unusual stability on a nuclide. A magic number for the atomic number (with filled shells) tends to increase the number of stable isotopes of an element.
Explanation:
how much heat is needed to raise 30g of water from 20°c to 50°c
Answers
Answer:
Q = C M ΔT (C = spec. heat, M = mass, ΔT = change in abs temp)
Q = 1 cal/gm-deg C * 30 gm * (50 - 20) deg C = 900 cal
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.00 ✕ 105 kg on springs that have adjustable force constants. Its function is to dampen wind-driven oscillations of the building by oscillating at the same frequency as the building is being driven—the driving force is transferred to the object, which oscillates instead of the entire building.(a) What effective force constant (in N/m) should the springs have to make the object oscillate with a period of 2.10 s? N/m(b) What energy (in J) is stored in the springs for a 1.80 m displacement from equilibrium? J
Answers
ANSWERS
(a) 3.58 x 10⁶ N/m
(b) 5.8 x 10⁶ J
EXPLANATION
Given:
• The mass of the object hanging from the spring, m = 4.00 x 10⁵ kg
Find:
• (a), The force constant the springs should have to make the object oscillate with a period of 2.10 s
,• (b), The energy stored in the springs for a 1.80 m displacement from equilibrium.
(a) The period of an object in a spring is,
\(T=2\pi\sqrt{\frac{m}{k}}\)Where m is the mass of the object and k is the spring constant.
We want to find k for T = 2.10 s, so we have to solve this equation for k, which gives us,
\(k=m\cdot\left(\frac{2\pi}{T}\right)^2\)Replace the known values and solve,
\(k=4\cdot10^5\cdot\frac{4\pi^2}{(2.1)^2}\approx3,580,808.85N/m\approx3.58\cdot10^^6N/m\)Hence, the force constant is 3.58 x 10⁶ N/m.
(b) The energy stored in a spring with force constant k when the mass is displaced x meters from equilibrium is,
\(U_s=\frac{1}{2}kx^2\)Replace the known values and solve to find the energy stored in this spring,
\(U_s=\frac{1}{2}\cdot3.58\cdot10^6N/m\cdot1.8^2m^2\approx5.8\cdot10^6J\)Hence, the energy stored in the spring for a 1.80 m displacement from equilibrium is 5.8 x 10⁶ J.
An object traveling at 1.5 rad
accelerates at 0.75d for 12
S
seconds. What is the object's final
velocity?
Answers
The object's final velocity, given the data is 10.5 rad/s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocityThe following data were obtained from the question
Initial velocity (u) = 1.5 rad/sAcceleration (a) = 0.75 rad/s²Time (t) = 12 sFinal velocity (v) = ?The final velocity can be obtained as follow:
a = (v – u) / t
0.75 = (v – 1.5) / 12
Cross multiply
v – 1.5 = 0.75 × 12
v – 1.5 = 9
Collect like terms
v = 9 + 1.5
v = 10.5 rad/s
Thus, the final velocity of the object is 10.5 rad/s
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please help me asappppp!!
Answers
Answer:
10.1
3.5
40.25
4.8
70
4.5
10.2
80
101.25
330. respectively
A car starts from rest and accelerates at a steady 6.00 m/s2. How far does it travel in the first 3.00 s?
Answers
mark me brainiest if this helped!
A 70 g autographed baseball rolls off of a 1.4 m high table and strikes the floor a horizontal distance of 1 m away from the table. How fast was it rolling on the table before it fell off? The acceleration due to gravity is 9.81 m/s^2. Answer in units of m/s.
Answers
The velocity of the autographed baseball before it fell off the table is 1.89 m/s
We'll begin by obtainig the time taken for the autographed baseball to strike the floor. This can be obtained as follow:
Acceleration due to gravity (g) = 9.8 m/s²Height (h) = 1.4 mTime (t) = ?h = ½gt²
1.4 = ½ × 9.8 × t²
1.4 = 4.9 × t²
Divide both side by 4.9
t² = 1.4 / 4.9
Take the square root of both side
t = √(1.4 / 4.9)
t = 0.53 s
How do I determine the initial velocity?The initial velocity of the ball can be obatined as illustrated below:
Horizontal distance (s) = 1 mTime (t) = 0.53 sInitial velocity (u) = ?s = ut
1 = u × 0.53
Divide both sides by 0.53
u = 1 / 0.53
u = 1.89 m/s
Thus, we can conclude that the velocity of the ball before it fell off the table is 1.89 m/s
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when a pure water is heated , it increases in volume
Answers
As water freezes below 4°C, the volume of the liquid shrinks and water molecule motion slows. When the temperature rises over 4 °C, the water molecules spread out and take up more space, increasing the volume.
How does cooling water from 4 C to 0 C affect its volume?Due to the peculiar property of water known as "Anomalous Expansion of Water," when 1 liter of water is cooled from 4°C to 0°C, the volume of the water starts to grow. Between 4°C and 0°C, water expands abnormally.
What happens to water's specific volume when it is heated from 0 degrees Celsius?Water volume reduces as it is heated from 0°C to 4°C because the water's density will be maximum
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Calculate the quantity of heat energy which must be transferred to 2.25 kg of brass to raise its temperature from 20°C to 240°C if the specific heat of brass is 394 J/kgK.
Answers
The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J
How do i determine the quantity of heat energy?First, we shall list out the given parameters from the question. This is shown below:
Mass of brass (M) = 2.25 Kg Initial temperature of brass (T₁) = 20 °CFinal temperature of brass (T₂) = 240 °CChange in temperature of brass (ΔT) = 240 - 20 = 220 °CSpecific heat capacity of brass (C) = 394 J/kgKQuantity of heat energy (Q) =?The quantity of heat energy that must be transferred can be obtained as follow:
Q = MCΔT
= 2.25 × 394 × 220
= 195030 J
Thus, we can conclude quantity of heat energy that must be transferred is 195030 J
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Suppose three positively charged particles are constrained to move on a fixed circular track. If the charges were all equal, an equilibrium arrangement would obviously be a symmetrical one with the particles spaced 120o apart around the circle. Suppose that two of the charges are equal and the equilibrium arrangement is such that these two charges are 90o apart rather than 120o. What is the relative magnitude of the third charge?
Answers
The relative magnitude of the third charge would be greater than the other two charges.
This is because the system needs to be in equilibrium, and the forces on each of the particles need to balance out. Since two of the charges are equal and the equilibrium arrangement is such that they are 90° apart, this would mean that the repulsive force that they exert on each other is greater than if they were 120° apart.
Therefore, since their repulsive forces are greater, the magnitude of the third charge needs to be greater in order to balance out the repulsive forces of the two equal charges. This is because the third charge needs to exert a greater attractive force on the two equal charges in order to offset the greater repulsive force that they exert on each other.
Thus, the relative magnitude of the third charge needs to be greater than the other two charges in order to maintain equilibrium.
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1. For the masses shown with the indicated velocities. Consider the increasing
direction of the x-axis toward the right.
9.0 kg 4.0 m/s
8.0 m/s
6.0 kg
a) Find the magnitude of the momentum of the system. (Do not include the units
in the answer)
Your answer
b) What is the direction of the momentum of the system?
Choose
c) Determine the total kinetic Energy of the System. (Do not include the units in
the answer)
Your answer
Answers
=8x6=48
Nami conducts an investigation on plants. She places a grow light on a timer to give the plants different amounts of light to see if this would affect their growth. Which term describes the amount of light in this investigation?
Answers
Answer:
It is independent variable
Explanation:
Answer:
D!!!!!
Explanation:
edge 2021!
What is the role of
electrons within an
atom?
Answers
Answer:
Electrons are the negatively charged particles of atom. Together, all of the electrons of an atom create a negative charge that balances the positive charge of the protons in the atomic nucleus. Electrons are extremely small compared to all of the other parts of the atom.
Explanation:
Answer:
negative
Explanation:
electrons=negative particle
The star Mintaka in the Orion constellation is about 30x larger than our sun with a radius of 5.74 x 10^9 m. It's surface temperature is about 29,500 K. Consider the spherical surface to behave as a blackbody radiator. What is the rate at which energy is radiated from this star, to 3 sig fig?
Answers
Due to the body is a blackbody e=1
\(\begin{gathered} P=5.6703\cdot10^{-8}\cdot(\pi\cdot(5.74\cdot10^9)^2)\cdot(29500^4-2.7^4) \\ P=4.445\cdot10^{30}W \end{gathered}\)This is the rate of energy over time that this star radiates
Sketch the pattern of the lines of forces around two positive charge separated from each other
Answers
The pattern of lines of force around two positive charges separated from each other demonstrates the repulsive nature of like charges and the direction and strength of the electric field between them.
When two positive charges are separated from each other, the lines of force (also known as electric field lines) originate from one positive charge and terminate on the other positive charge. The lines of force follow a pattern that reflects the repulsion between the positive charges.
Here's a verbal description of the pattern:
From each positive charge, the lines of force radiate outward in all directions.
The lines of force are evenly spaced and radially symmetric around each charge, indicating that the electric field strength is the same at all points along a given line.
As the lines of force move away from each charge, they curve away from each other, reflecting the repulsion between the positive charges.
The density of lines of force is higher near the charges and decreases as they move further apart.
The lines of force never cross each other, maintaining their continuous and unbroken nature.
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