Answer:
which wave sound wave or water wave
Gravity is the attractive pull between two objects that have mass. The strength of the gravitational distance. As distance between the objects increases, the force of gravity decreases. If the distance
one-fourth as strong as before. Which one of the graphs best represents the relationship between
pull is doubled,
gravity and distance. depends
on mass and the force of gravity is
A. A
B. B
C. C
D. D
Sorry for the bad picture right now i dont have to take a nice picture
Graph A best represents the relationship between pull is doubled, gravity and distance. depends on the mass and the force of gravity. Option A is correct.
What is Newton's law of gravity?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
The expression for the gravitational force is given as;
\(\rm F = G\frac{Mm}{r^2}\)
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Decreasing the distance would increase the gravity of the planet.
Gravity is the attraction force that draws two mass-containing objects together. the gravitational distance's strength.
The force of gravity weakens as the distance between the items rises. if the separation is just one-fourth as great as previously. In the graph, the link between pull and doubled is best represented by A.
Hence option A is correct.
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star a has apparent magnitude 1, while star b has apparent magnitude -1. based only on this information, what can be said about these two stars?
The apparent magnitude of a star is a measure of its brightness as observed from Earth. The lower the apparent magnitude, the brighter the star appears.
Given that star A has an apparent magnitude of 1 and star B has an apparent magnitude of -1, it can be inferred that star B is brighter than star A. In fact, star B is about 2.5 times brighter than star A, as each decrease in apparent magnitude by 1 corresponds to a brightness increase of about 2.5 times. However, it's important to note that the apparent magnitude of a star can be affected by factors such as distance and extinction due to interstellar dust.
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Ionizing radiation is radiation of sufficient energy to produce charged atoms. All of these describe ionizing radiation. is radiation of sufficient energy to produce ions. is radiation of sufficient energy to remove electrons from atoms.
Answer:
Is radiation of sufficient energy to produce ions.
Is radiation of sufficient energy to remove electrons from atoms.
Explanation:
Ionization radiation is a radiation that travels at a high speed, and possesses sufficient speed to knock electrons off of an atom or a molecule, ionizing the atom. Ionization radiation can be made of travelling subatomic particles, or an electromagnetic wave with high energy, usually the types found at the end of the electromagnetic spectrum. Some subatomic particles that produce ionization are alpha particle, beta particles, and neutron. The electromagnetic waves with ionization abilities includes Gamma rays. -rays, and high energy ultraviolet rays.
pleaaaaaaaaaaaaaaase help me vvvvvvvvvvvvvvv
Which one, mass or weight, would change if you were to travel to another planet or moon?
Answer:
The answer is weight.
Mass is constant, your mass, height and width won’t change. So that leaves weight.
A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to stop? What distance will it cover before coming to rest?
Answer:
F=-50N
M=200kg
U=15m/s
F=Ma
a=F/M=-50/200=-0.25
V^2-U^2=2aS
0-(15)^2=2(-0.25)S
S=-225/-0.5=450m
V=U+at
0=15-0.25t
t=-15/-0.25=60s
Explanation:
Hope this helps, let me know if you have any questions!
Have a great day.
A student drops a rock off a 5.0 meter cliff. If we ignore air resistance, how long will it take the rock to strike the water below?
Answer:
0.71 s
Explanation:
The formula used will be the formula for a free falling object acted on by gravity.
Time/Period(T) = √[Length/Distance(L)]/[Acc'n due
to gravity(g)]
T = √[5m/9.8m/s²]
T = 0.71 s
Does anyone know how to draw this out?
The Position-Time graph for the given Velocity-Time graph is drawn in the image attached.
From the Velocity-Time graph we can take the information needed.
\(t_{1}\) = 1 s
\(t_{2}\) = 2 s
\(t_{3}\) = 3 s
\(t_{4}\) = 4 s
\(t_{5}\) = 5 s
\(v_{1}\) = 10 m / s
\(v_{2}\) = 20 m / s
\(v_{3}\) = 30 m / s
\(v_{4}\) = 40 m / s
\(v_{5}\) = 50 m / s
v = d / t
d = v * t
\(d_{1}\) = 10 * 1 = 10 m
\(d_{2}\) = 20 * 2 = 40 m
\(d_{3}\) = 30 * 3 = 90 m
\(d_{4}\) = 40 * 4 = 160 m
\(d_{5}\) = 50 * 5 = 250 m
Therefore, the Position-Time graph is drawn in the image attached.
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Ahmad drives from his house to his friend's house averaging 60 miles per hour. On the return trip, he averages 50 miles per hour. His total driving time for the round trip is 11 hours. What is the distance, in miles, between Ahmad's house and his friend's house
Ahmad's average speed on his way to his friend's house is 60 miles per hour, while on the return trip, it is 50 miles per hour. The total time for the round trip is 11 hours.
Let's assume the distance between Ahmad's house and his friend's house is D miles. To find the distance, we can use the formula: Distance = Speed × Time.
On the way to his friend's house, Ahmad travels at an average speed of 60 miles per hour. Let's denote the time taken for this leg of the trip as T1. Using the formula, we have D = 60 × T1.
On the return trip, Ahmad travels at an average speed of 50 miles per hour. The time taken for this leg of the trip can be denoted as T2. Using the formula, we have D = 50 × T2.
According to the problem, the total driving time for the round trip is 11 hours. This can be expressed as T1 + T2 = 11.
Now, we have a system of two equations:
D = 60T1
D = 50T2
T1 + T2 = 11
To solve this system, we can use substitution or elimination. Let's use substitution. From the first equation, we can express T1 in terms of D: T1 = D/60. Substituting this into the third equation, we get D/60 + T2 = 11. Rearranging the equation, we have T2 = 11 - D/60.
Now, substitute the expression for T2 in the second equation: D = 50(11 - D/60).
Simplifying the equation, we have D = 550 - 5D/6.
Multiply both sides by 6 to eliminate the fraction: 6D = 3300 - 5D.
Add 5D to both sides: 11D = 3300.
Divide both sides by 11: D = 300.
Therefore, the distance between Ahmad's house and his friend's house is 300 miles.
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The Round Up carnival ride below has a radius of 3.62 meters and rotates 0.537 times per second. As shown, riders can be held up by only friction. What coefficient of friction is needed to keep the riders from sliding down? Include units in your answer. Answer must be in 3 significant digits.
The free body diagram for the problem is shown below:
If the people don't slide down this means that the friction has to be equal to the Weight, then we have:
\(\begin{gathered} F_f-W=0 \\ F_f=W \\ \mu F_n=W \\ \mu=\frac{W}{F_n} \end{gathered}\)Now, from newton's second law we have that:
\(F_n=ma_c\)but
\(a_c=\frac{4\pi^2r}{T^2}\)then:
\(F_n=\frac{4\pi^2mr}{T^2}\)And then we have:
\(\begin{gathered} \mu=\frac{mg}{\frac{4\pi^2mr}{T^2}} \\ \mu=\frac{gT^2}{4\pi^2r} \end{gathered}\)Plugging the values given we have:
\(\begin{gathered} \mu=\frac{(9.8)(\frac{1}{0.537})^2}{4\pi^2(3.62)} \\ \mu=0.238 \end{gathered}\)Therefore the coefficient of friction is 0.238
1. Which is an example of chemical potential
energy changing to kinetic energy?
A. a flag flapping in the wind
B. logs burning on a fire
C. using a battery in a flashlight
D. burning fuel to move a car
The average distance from Earth to the sun is 9.3 × 107 miles. How many kilometers isthis?A) 1.5 × 108 km D) 1.7 × 10-8 kmB) 1.5 × 105 km E) 1.5 × 1011 kmC) 5.6 × 107 km
The distance from Earth to the sun is approximately 1.5 x 10^8 kilometers.
To convert miles to kilometers, we can use the conversion factor 1 mile = 1.609344 kilometers.
So, to find the distance from Earth to the sun in kilometers, we can multiply the given distance in miles by the conversion factor:
d (km) = 9.3 x 10^7 miles x 1.609344 km/mile
d (km) = 1.496 x 10^8 km
Therefore, the distance from Earth to the sun is approximately 1.5 x 10^8 kilometers.
The closest answer choice is A) 1.5 x 10^8 km, which is the correct answer.
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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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how to find the density of air?
how is oxygen in a container made to be at a high pressure?
Answer:
Oxygen in a container can be made to be at a high pressure through a process called compression. In this process, the oxygen is forced into a smaller volume, which increases the pressure. This can be done using a compressor, which is a machine that uses a piston or other device to compress the oxygen. The compressed oxygen is then stored in a container, such as a cylinder, at high pressure until it is ready to be used. It is important to handle compressed oxygen with care, as it can be dangerous if not handled properly.
how is charged particles related to electric current, electric circuits, and resistance
Charged particles are fundamental to the behavior of electric currents, electric circuits, and resistance. An electric current is the flow of charged particles, typically electrons, through a conductor.
The flow of charged particles generates an electric field that induces a potential difference, or voltage, across the conductor.Electric circuits are constructed by connecting conductors and electrical components, such as resistors, capacitors, and inductors, in a specific configuration. The arrangement of the components determines how the current flows through the circuit.
The flow of current through the circuit depends on the resistance offered by the components in the circuit and the potential difference across the circuit.Resistance is the property of a conductor that opposes the flow of current. The resistance of a conductor is proportional to the number of charged particles in the conductor, the length of the conductor, and the cross-sectional area of the conductor. The resistance can also be affected by the temperature of the conductor and its material properties.
In summary, charged particles are responsible for generating electric currents that flow through electrical circuits. The behavior of the currents is determined by the arrangement of the components in the circuit and the resistance offered by the conductors and components. Resistance is a fundamental property of a conductor that opposes the flow of charged particles and can be affected by various factors.
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2. An airboat with mass 3.50 x 102 kg, including the passenger, has an engine that produces a net horizontal force of 7.70 x 102 N, after accounting for forces resistance. a. Find the acceleration of the airboat b. Starting from rest, how long does it take the airboat to reach a speed of 12.0 m/s
The acceleration of the airboat is 2.2m/s^2 and starting from rest, it take the airboat to reach a speed of 12.0 m/s is 5.45s
Given mass of airboat (m) = 3.50 x 10^2kg
horizontal force of engine (F) = 7.70 x 10^2N
We know that from newtons laws of motion Force = mass x acceleration such that F = ma
(a) Now a = F/m = 7.70 x 10^2 / 3.50 x 10^2 = 2.2m/s^2
(b) Initial speed of airboat (u) = 0m/s
final speed (v) = 12m/s
We have acceleration a = 2.2m/s
Then we have another newtons law as: v = u+ at where t is the time taken
So t = v/a = 12/2.2 = 5.45s
Hence it takes to reach 5.45s a speed of 12m/s
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Will the daylight duration increase as you go north on June 21?
Answer:
Below
Explanation:
Yes ....due to the 23° tilt toward the sun, after the spring equinox and before the autumnal equinox, everyplace NORTH of you will have longer days than your place. ( in the Northern hemisphere)
Change the following as indicated in the brackets.
8m (km,cm)
metres to kilometres = 1/1000
8 m ⇒ 0.008 km
metres to centimetres = × 100
8 m ⇒ 800 cm
Answer:
1000m=1km
so, 8m=8/1000 = 0.008km
1m=100cm
so, 8m=8×100=800
The SI unit used to measure radiation exposure in air is:
A. Gray
B. Coulomb/kg
C. Sievert
D. Curie
The SI unit used to measure radiation exposure in air is (B) Coulomb/kg.
This unit quantifies the amount of ionization produced in the air by radiation. It represents the electric charge generated per kilogram of air due to radiation exposure. This measurement is crucial in assessing the potential health effects of radiation on living organisms, as it provides a quantitative measure of the radiation dose received. The Coulomb per kilogram is widely used in radiation dosimetry and serves as a fundamental unit for evaluating radiation exposure levels and establishing safety guidelines. It enables scientists and medical professionals to accurately monitor and regulate radiation exposure to minimize risks and protect human health.
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The main answer to your question is that the SI unit used to measure radiation exposure in the air is B. Coulomb/kg.
There are various units to measure different aspects of radiation, but when it comes to measuring radiation exposure in air, the International System of Units (SI) recommends using the coulomb per kilogram (C/kg). This unit is specifically used for measuring ionization in the air caused by radiation. It quantifies the charge of ions produced per unit mass of air by incident radiation.
The other options are used as follows:
A. Gray (Gy) is a unit used to measure absorbed dose, which is the amount of energy deposited in a material by radiation.
C. Sievert (Sv) is a unit used to measure the biological effect of ionizing radiation, accounting for the type and energy of the radiation as well as the sensitivity of the exposed tissue.
D. Curie (Ci) is a non-SI unit used to measure the activity of a radioactive substance, indicating the number of radioactive decays per second.
In summary, the SI unit for measuring radiation exposure in the air is Coulomb/kg, while the other units mentioned serve different purposes in the context of radiation measurement.
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14. Reflected ray 30° Fig 6.31 reflection on a plane mirror. In Fig 6.31 the angle between the plane mirror and the incident ray is 30°. Find the a. Angle of incidence b. Angle of reflection Incident ray
A 5kg toy car is pulled with a net force of 25 N. How much does the toy accelerate?
Answer: 5 m/s^2
Explanation:
F=MA
F = 25N
M = 5kg
Plug these into F=MA
25 = 5*A
5 = A
Initial State: A child in a swing is in motion at the lowest point along its arc.
Final State: The child has reached the highest point along its arc.
Notes: The system includes the child and the Earth. Resistance forces are
negligible.
At the lowest point of the swing's arc, the child's mechanical energy is at its maximum. This is because the child has both kinetic energy due to their motion and potential energy due to their height above the ground.
How to explain the informationAs the child swings upward, their kinetic energy decreases while their potential energy increases.
At the highest point of the swing's arc, the child momentarily comes to a stop before reversing direction. At this point, their kinetic energy is zero because they have no motion. The child's potential energy is at its maximum because they have reached the highest point of the swing.
During this transition from the lowest point to the highest point, the energy is conserved, assuming negligible resistance forces.
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Initial State: A child in a swing is in motion at the lowest point along its arc.
Final State: The child has reached the highest point along its arc.
Notes: The system includes the child and the Earth. Resistance forces are negligible.analyze the scenario of a child in a swing transitioning from the lowest point to the highest point along its arc
A weightlifter lifts a set of 1250kg weights a vertical distance of 2m weight lifting contest. what potential energy do the weights now possess
Answer: The potential energy of the weights is 24,500 J
Explanation:
For an object of mass M, that is at a distance H from the ground, the potential energy can be written as:
U = M*H*g
where g is the gravitational acceleration g = 9.8m/s^2
In this case, we have that:
mass of the weights = 1,250 kg
height = 2m
Then the potential energy of the weights is:
U = 2m*1,250kg*9.8m/s^2 = 24,500 J
a small solid sphere is released from rest at the top of an inclined plane as shown. the sphere rolls down without slipping and reaches the bottom of the plane. how would the angular momentum of the sphere at the bottom of the plane change if the coefficient of static friction between the sphere and the plane were increased?
The angular momentum of the solid sphere would remain the same because the net torque would remain the same.
What is angular momentum?The attribute of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.
What does motion's angular momentum mean?A body's rotational inertia and rotational velocity (measured in radians/sec) about a specific axis are combined to form angular momentum, which is a vector quantity (or more correctly, a pseudovector).
What does the vector form of angular momentum mean?An object's angular momentum is calculated by multiplying its moment of inertia by its rotating object's rotational velocity. A body's angular momentum has a magnitude and a direction. It is therefore a vector quantity. The letter "L" stands for it.
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The weight of air in a bathtub (about 1/3 cubic meter) is about the same as the weight of
A) a 10-pound sack of potatoes.
B) a pound of butter.
C) a small apple.
D) a pea.
E) an egg.
The weight of air in a bathtub (about 1/3 cubic meter) is about the same as the weight of a 10-pound sack of potatoes. The correct option is A.
To understand this, we need to consider the mass and weight of air in the given volume.
Air has a density of about 1.2 kg/m³ at standard conditions (room temperature and pressure). Since the volume of air in the bathtub is around 1/3 cubic meter, we can calculate the mass of air using the formula: mass = density × volume. In this case, the mass would be approximately 1.2 kg/m³ × 1/3 m³ ≈ 0.4 kg.
Next, we can convert the mass of air to weight by using the formula: weight = mass × acceleration due to gravity. Assuming the acceleration due to gravity is approximately 9.8 m/s², the weight of air would be 0.4 kg × 9.8 m/s² ≈ 3.92 N (Newtons).
Finally, we can convert the weight from Newtons to pounds. Using the conversion factor of 1 N ≈ 0.225 lbs, we find that the weight of air in the bathtub is around 3.92 N × 0.225 lbs/N ≈ 0.88 lbs, or roughly 10 pounds. Therefore, the weight of air in the bathtub is closest to the weight of a 10-pound sack of potatoes. Thus, the correct option is A.
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State fourth law of Thermodynamics
Answer: The dissipative component of evolution is in a direction of steepest entropy ascent
Explanation:
According to our definition, every non-equilibrium state of a system or local subsystem for which entropy is well defined must be equipped with a metric in state space with respect to which the irreversible component of its time evolution is in the direction of the steepest entropy ascent permissible under the conservation constraints. We derive (nonlinear) expansions of Onsager reciprocity and fluctuation-dissipation relations to the far-non-equilibrium world inside the rate-controlled constrained-equilibrium approximation to demonstrate the force of the fourth law (also known as the quasi-equilibrium approximation).
when a buck-boost transformer has current less than nine amperes, an overcurrent protection device is allowed to be rated at not more than ? of the input current.
When a buck-boost transformer has a current less than nine amperes, an overcurrent protection device is allowed to be rated at not more than 125% of the transformer's primary current.
To calculate the rating of the overcurrent protection device:
1. Determine the primary current of the transformer (let's assume it's less than 9 amperes).
2. Multiply the primary current by 125% (or 1.25) to find the maximum allowed rating for the overcurrent protection device.
For example, if the primary current is 8 amperes, the maximum allowed rating for the overcurrent protection device would be 8 x 1.25 = 10 amperes.
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Determine the magnitude of the resultant force acting on the gate ABC due to hydrostatic pressure. The gate has a width of 1.5 m. rhow = 1.0 Mg/m^3.
The magnitude of the resultant force acting on the gate ABC due to hydrostatic pressure is 14.72 kN.
To determine the magnitude of the resultant force acting on the gate ABC due to hydrostatic pressure, we need to use the formula:
F = (rho * g * A * h)
where:
rho = density of fluid
g = acceleration due to gravity
A = area of the gate
h = depth of fluid
Since the gate has a width of 1.5 m, we can assume that the area of the gate is 1.5 m². The density of water (rhow) is 1000 kg/m³, which is equal to 1.0 Mg/m³. The depth of the water (h) is not given, so we cannot calculate the force without that information.
If we assume a depth of 1 meter, then we can calculate the force as follows:
F = (1.0 Mg/m³ * 9.81 m/s² * 1.5 m² * 1 m)
F = 14.72 Mg or 14.72 kN (to convert to Newtons, multiply by 1000)
Therefore, if the depth of the water is 1 meter, the magnitude of the resultant force acting on the gate ABC due to hydrostatic pressure is 14.72 kN.
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The dimension of auditory experience related to the complexity of a sound wave, that is, to the relative breadth of the range of frequencies, is called
The dimension of auditory experience related to the complexity of a sound wave, that is, to the relative breadth of the range of frequencies, is called Timbre.
Timbre is the dimension of auditory experience related to the complexity of a sound wave, that is, to the relative breadth of the range of frequencies. It is also defined as the quality that distinguishes one sound from another, even when they have the same pitch, loudness, and duration.
Timbre is responsible for allowing people to identify different musical instruments, human voices, and sound effects.
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A crate is sliding down an inclined ramp at a constant speed of 0.55 m/s. The vector sum of all the forces acting on this crate must point down the ramp. True or false?
Answer:
False
Explanation:
Given: A crate is sliding down an inclined ramp at a constant speed of 0.55 m/s.
To find: whether the given statement is true or false
Solution:
As a crate is sliding down an inclined ramp at a constant speed of 0.55 m/s, net force is equal to 0 and so, the vector sum of all the forces acting on the crate can't point anywhere.
So, the given statement is false.