in a haplodiploid system, calculate the relatedness of a son to a maternal aunt.

The equation of the line parallel to the given line that contains C is obtained as y = x + 6.

For the given question;

The equation of the line is given as;

y = x + 4

The standard form of the equation of line in slope intercept form is;

y = m x + c

where, m is the slope and c is the y intercept.

On comparing;

m₁ = 1

Now, the other lien is parallel to the given line.

Thus, slopes of both lines will be equal.

m₁ = m₂ = 1

The passing points of the line are;

(x₁, y₁) = C(1, 7)

Now, the equation of lien will be;

y - y₁ = m₂(x - x₁)

Put the values;

y - 7 = 1(x - 1)

Simplifying.

y = x + 6

Thus, the equation of the line parallel to the given line that contains C is obtained as y = x + 6.

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Answer:

it will option A it is correct answer

The required algebraic expression is c+4

An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation. This math operation can be addition, subtraction, multiplication, or division.

Given that a statement 4 plus c as an algebraic expression

We need to convert it into an expression,

4 = 4

plus = +

c = c

Therefore, arranging it = c+4

Hence, the required algebraic expression is c+4

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Outliers are any observations that fall more than 1.5 IQR below Q1 or more than 1.5 IQR above Q3.

Outliers:

While observing the data in the observations some of data may fall outside the general scope of the other observations. Such observations are called outliers.

Given,

An outlier is an observation which is less than IQR or greater than Q3 times IQR.

Here we need to find in Q1 and Q3 place variations.

When we use the IQR method of identifying outliers to set up a “fence” outside of Q1 and Q3.  Any values which fall outside of the identified  fence are considered outliers.

To build this fence we take 1.5 times the IQR and then subtract this value from Q1 and add this value to Q3.

Like,

IQR = (1.5 - Q1)

IQR = (1.5 + Q3)

This gives us the minimum and maximum fence posts that we compare each observation to.

Therefore, any observations that are more than 1.5 IQR below Q1 or more than 1.5 IQR above Q3 are considered outliers.

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To send Kred to a Krew member, you can follow the steps provided by the Kred platform. These steps typically involve accessing your Kred account, selecting the desired recipient, specifying the amount of Kred to send, and confirming the transaction.

Sending Kred to a Krew member usually requires using the features and functionalities provided by the specific Kred platform or service. The process may vary depending on the platform, so it is recommended to refer to the official documentation or guidelines provided by the platform. Typically, you would need to log in to your Kred account, navigate to the appropriate section for sending Kred, select the intended recipient from the list of Krew members, enter the desired amount of Kred to send, review the transaction details, and confirm the transfer. The platform may also offer additional options or settings for customizing the transfer process.

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Answer:

check the attached file

Step-by-step explanation:

The parametric inferential statistical test for a single sample with a known population variance is the one-sample z-test.The null hypothesis in this test is that the sample mean is equal to the population mean.

The one-sample z-test is a parametric test used to determine whether a sample mean is significantly different from a known population mean when the population variance is also known. This test assumes that the data are normally distributed and the sample is a random sample from the population.

The one-sample z-test is a statistical test used to test a hypothesis about a population mean when the population variance is known. It is a parametric test, which means that it makes assumptions about the population distribution and sample size. Specifically, it assumes that the data are normally distributed and that the sample is a random sample from the population. The test is called a z-test because it uses the standard normal distribution to calculate the test statistic. The test statistic is calculated by taking the difference between the sample mean and the population mean, and dividing it by the standard error of the mean. The standard error of the mean is calculated by dividing the population standard deviation by the square root of the sample size.

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The value of point estimate is 90. The margin of error of the point estimate is 5.9 minutes. The minimum sample size needed to obtain this amount of precision is 60.

(a) The point estimate is 90 as the sample mean amount of time spent watching sports by those in the sample is 90 minutes per day.

(b) Margin of error (ME) can be calculated asME = (z-score) × (standard deviation / √sample size)The formula for 95% confidence interval is z = 1.96, the standard deviation (SD) = 15, and sample size (n) = 25.ME = 1.96 × (15 / √25) = 5.88 ≈ 5.9 minutes

Therefore, the margin of error is 5.9 minutes.

(c) The maximum error of the point estimate that the researcher wants to allow is 4 minutes and the researcher knows that college students tend to watch sports between 0 and 120 minutes per day.

The formula for sample size (n) can be used to find the minimum sample size required to obtain this amount of precision.

n = (z-score / ME)² × p × (1 - p)where p = 0.5 (since we do not know the value of p).

z-score = 1.96 and ME = 4.n = (1.96 / 4)² × 0.5 × (1 - 0.5)n = 59.53 ≈ 60

Therefore, a minimum sample size of 60 college students is required to obtain the desired level of precision with 95% confidence.

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Answer:

2 dimes and 5 pennies

Step-by-step explanation:

2 dimes (d) is 10 and 5 pennies (p) is 5

75+p+d=100

75+p=80

80+d=100

Answer: 3 quarters, 2 dimes, 1 nickel.

Step-by-step explanation: 3 quarters are worth 75 cents, 2 dimes are worth 20 cents, and 1 nickel is worth 5 cents! Hope this helps

Load vs deformation behavior of wet-mix and dry-mix shotcrete with different reinforcement can be summarized as follows:

Load vs Deformation Behavior of Wet-mix Shotcrete:

- Wet-mix shotcrete exhibits a gradual increase in load with deformation.

- The initial stiffness is relatively low, allowing for greater deformation before reaching its peak load.

- Wet-mix shotcrete tends to exhibit more ductile behavior, with a gradual post-peak load decline.

- The reinforcement in wet-mix shotcrete helps in controlling crack propagation and enhancing overall structural integrity.

Load vs Deformation Behavior of Dry-mix Shotcrete:

- Dry-mix shotcrete exhibits a relatively higher initial stiffness, resulting in less deformation before reaching the peak load.

- It typically shows a brittle behavior with a rapid drop in load after reaching the peak.

- The reinforcement in dry-mix shotcrete primarily helps in preventing the formation and propagation of cracks.

When to Use Wet-mix Shotcrete:

- Wet-mix shotcrete is commonly used in underground construction, such as tunnel linings and underground mines.

- It is suitable for applications where greater flexibility and ductility are required, such as seismic zones or areas with ground movement.

When to Use Dry-mix Shotcrete:

- Dry-mix shotcrete is often used in above-ground applications, such as architectural finishes, structural repairs, and protective coatings.

- It is preferred in situations where rapid strength development is required, as it typically achieves higher early strength than wet-mix shotcrete.

- Dry-mix shotcrete can be used in areas where a more rigid and less deformable material is desired, such as in structural elements subjected to high loads.

Therefore, wet-mix and dry-mix shotcrete exhibit different load vs deformation behavior due to their distinct mixing and application methods. Wet-mix shotcrete offers greater ductility and deformation capacity, making it suitable for applications with dynamic loading or ground movement.

On the other hand, dry-mix shotcrete provides higher early strength and is preferred for applications requiring rapid strength development or where rigidity is essential. The choice between wet-mix and dry-mix shotcrete depends on the specific project requirements, structural considerations, and the anticipated loading conditions.

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Answer:

40 and 100

Step-by-step explanation:

The value of y when x = 24 is 272.

Proportionality indicates that two quantities or variables are related linearly.

Given that, y varies directly with x when y = 68 and x = 6

y/x = 68/6 = 34/3

Therefore, the proportion is 34/3

when x = 24

34/3 = y/24

y = 272

Hence, y = 272 when x = 24

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The answer is

w + c ≤ 32

w < 11

w - the number of acres of wheat

c - the number of acres of corn

Johanna will plant up to 32 acres on her farm with wheat and corn:

w + c ≤ 32

Fewer than 11 acres will be planted with wheat:

w < 11

The two inequalities are:

w + c ≤ 32

w < 11

Answer:

Here we do not have the options, so I will answer in a general way.

We have two statements:

p = A number is greater than 25

q = A number is less than 35

We want to have:

p ^ q is true

This means:

p and q are true.

So, we need to find a number such that both conditions are meet, so we need to find a number N such that

The number N is greater than 25  (from p)

The number N is less than 35 (from q)

So N can be any number between 25 and 35

So, some of the possible values of N are:

N = 26

N = 27

N = 28.6

N = 33

N = 34

Concluding, any number N ∈ (25, 35) can be a solution.

(Note that N = 25 and N = 35 are not solutions)

Answer:

y-mx=b

Step-by-step explanation:

y is the combined result of mx + b, minusing mx from y will give you a remaining amount (that being b)

Answer:

Step-by-step explanation:

you can use the slide divide bottoms up method for this.

slide the 2 over to the 1 which gives:

x²+7x+2=0

then apply the quadratic formula to get

-7±√7²-4(1)(2)

______________

2

then we have

-7±√41÷2

Answer:

103

Step-by-step explanation:

A12=a1+(12-1)d

A12=4+(11)9

A12=4+99

A12=103

Answer:

(I'll leave cm out to save space and time in the answer)

the perimeter is 500, there are 5 sides. so on average a side will be 100.

that's already the important key idea.

it's indeed 100 for the third side, the second will be 10 less, the fourth 10 more (making the 2and and the 4th side 200 in sum, and therefore still 100 on average).

repeat this for the 1. and 5. side and we get:

80

90

100

110

120

The 1st box: 14.3

second box: 2.052

Third box: 2

fourth box: 28

fifth box: 13.5

sixth box: 15.1

The 1st box: 14.3

second box: 2.052

Third box: 2

fourth box: 28

fifth box: 13.5

sixth box: 15.1

Answer: column A= temperature column B= wind speed. Label A= wind speed label B= Temperature

Step-by-step explanation:

Answer:

Column A =  

✔ temperature

Column B =  

✔ wind speed

Label A =  

✔ wind speed

Label B =  

✔ temperature

Step-by-step explanation: Just did it in the assignment of edge :)

Answer: 36.87 degrees.

Step-by-step explanation:

In a right-angle triangle, the length of the opposite side of an angle and the length of the hypotenuse can be used to find the value of the angle using the trigonometric ratios.

If we let the angle in question be denoted as "theta" and the length of the opposite side be "opp" and the length of the hypotenuse be "hyp", we can use the trigonometric ratio "sine" to find the value of the angle.

sin(theta) = opp/hyp

We are given that opp = 3 cm and hyp = 5 cm, so we can substitute these values into the equation:

sin(theta) = 3/5

We can now use an inverse trigonometric function, such as arcsin, to find the value of theta:

theta = arcsin(3/5)

The result of this calculation is theta = approximately 36.87 degrees. Therefore, the value of the angle is 36.87 degrees.

Answer:

30 mm

Step-by-step explanation:

3 x 10 mm ? hopefully its the right answer for you

Answer:

28 sq units

Step-by-step explanation:

to find the area of a triangle you multiply the base and height together and then divide by 2

in this problem, i counted and found the base = 7 units and

the height = 8 units

A = 7x8÷2

A = 56/2 = 28

Answer:

question 1: answer is 4

question 2: answer is 1

Step-by-step explanation:

The solution to the given IVP is.\($i(t)-\frac{E}{R}+\left(i_0-\frac{E}{R}\right) e^{-\frac{R}{L}}$\)

Initial value problems describe a type of problem in calculus. Initial value problems in calculus concern differential equations with a known initial condition that specifies the value of the function at some point. The purpose of these problems is to find the function that describes the system, which can be done by integrating the differential equation.

Consider the initial value problem,

L \(\frac{d i}{d t}+R i=E \text {. }\)

The initial condition is. \($i(0)=i_0$\)

Rewrite the DE as,

\(\begin{gathered}L \frac{d i}{d t}+R i=E \\\frac{d i}{d t}+\frac{R}{L} i=\frac{E}{L}\end{gathered}$$\)

This is a linear DE.

Compare the DE  \(\frac{d i}{d t}+\frac{R}{L} i=\frac{E}{L}$\) with the general DE \(\frac{d i}{d t}+P(t) i=Q(t)$\). Then \($P(t)=\frac{R}{L}$\) and \($Q(t)=\frac{E}{L}$\).

Find the integrating factor (IF).

                                     \($$\begin{aligned}I F & =e^{\int P(t) \vec{t}} \\& =e^{\int\left(\frac{\pi}{\mathrm{I}}\right) \mathrm{A}} \\& =e^{\frac{\pi}{l^2}}\end{aligned}$$\)

Thus, the integrating factor is \($I F=e^{\frac{R^2}{2^2}}$\).

Now multiply both sides of the DE with the IF.

                                   \($$\begin{array}{r}e^{\frac{R}{\bar{L}^t}}\left(\frac{d i}{d t}+\frac{R}{L} i\right)=\frac{E}{L} e^{\frac{R}{L^t}} \\\frac{d i}{d t} e^{\frac{\pi}{L^t}}+\frac{R}{L} e^{\frac{R}{\bar{L}^t}} i=\frac{E}{L} e^{\frac{\pi}{\bar{L}^t}} \\{\left[i e^{\frac{R}{L^2}}\right]=\frac{E}{L} e^{\frac{R^L}{L^t}}}\end{array}$$\)

Integrate on both sides.

        \($$\begin{aligned}& \int\left[i e^{\frac{R}{L}}\right] d t=\int \frac{E}{L} e^{\frac{R}{L^t}} d t \\& i e^{\frac{R}{L^{\mathrm{r}}}}=\frac{E}{L} \int e^{\frac{\pi}{L^t}} d t \\& i e^{\frac{R}{\perp} r}=\frac{E}{L}\left[\frac{e^{\frac{R}{2}}}{\frac{R}{L}}\right]+C \\& i e^{\frac{R}{\Gamma}+}=\frac{E}{R} e^{\frac{R^2}{I^{+}}}+C \\& i(t)=\frac{\frac{E}{R} e^{\frac{R}{L^2}}+C}{e^{\frac{R}{D^2}}} \\& t(t)=\frac{E}{R}+C e^{-\frac{R}{L^t}} \\&\end{aligned}$$\)

Thus, the general solution to the \(\mathrm{DE}\) is \($i(t)=\frac{E}{R}+C e^{-\frac{R}{t^*}}$\).

Use the initial condition. \($i(0)=i_0$\)

Substitute \($t=0$\) and \($i(0)=i_0$\) in \($i(t)=\frac{E}{R}+C e^{-\frac{R}{I^t}}$\).

\($$\begin{aligned}& i(0)=\frac{E}{R}+C e^{-\frac{R}{I}(0)} \\& i_0=\frac{E}{R}+C e^0 \\& i_0=\frac{E}{R}+C \quad \text { use } e^0=1 \\& C=i_0-\frac{E}{R}\end{aligned}$$\)

Substitute  \($C=i_0-\frac{E}{R}$\) in \($i(t)=\frac{E}{R}+C e^{-\frac{R}{L^1}}$\).

\($$\begin{aligned}& i(t)=\frac{E}{R}+C e^{-\frac{R}{I}} \\& i(t)=\frac{E}{R}+\left(i_0-\frac{E}{R}\right) e^{-\frac{\pi}{t^t}}\end{aligned}$$\)

Therefore, the solution to the given IVP is. \($i(t)-\frac{E}{R}+\left(i_0-\frac{E}{R}\right) e^{-\frac{R}{L}}$\).

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The sum of the numbers between, and including, 551-600 is 28,775.

Using the formula:

Sn = n/2 * (a1 + an)

where

Sn is the sum of the numbers,

n is the number of terms,

a1 is the first term, and

an is the last term.

From the question,

n = 50 (since there are 50 numbers between 551 and 600, inclusive),

a1 = 551, and

an = 600.

So we have:

Sn = 50/2 * (551 + 600)

= 25 * 1151

= 28,775

Therefore, the sum of the numbers between and including 551-600 is 28,775.

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