Answer:
575786
Step-by-step explanation:
3/8 + 2/3 as a mixed number
Please explain your answer to the question in the picture with steps.
Find the measure of angle A.
60x
O 60°
O 30°
O 23°
O 37°
30x
A
Answer:
Step-by-step explanation:
sum of angles in a triangle=180º
90+60x+30x=180
90+90x=180
90(1+x)=180
1+x=2
x=1
angle A=30º
15.3
21. A squirrel is standing on the branch of a tree. The angle of elevation from a point on the ground to the squirrel
is 48°. The ground distance from the point to the tree is 28ft. How high above the ground is the squirrel?
Round your answer to the nearest foot.
48⁰
28 ft
21
Answer:
The height of the squirrel is 31 feet.
Step-by-step explanation:
You need to know your Right Triangle Trigonometry to do this problem.
Rt Triangle trig is all about ratios. Angles and ratios.
In your question, there is a rt triangle. The side measure given, 28 is next to the angle. The math word for "next to" is "adjacent" You know the adjacent side. The squirrel's height is the opposite side. The ratio that puts together adjacent and opposite is tangent.
tan Angle = opposite/adjacent
tan 48° = x/28
multiply both sides by 28
28•tan48° = x
You have to use a calculator that has trig functions. It will have buttons that say "sin", "cos", and "tan"
Enter 28 × tan48° =
It will return 31.0971504152
Your question asks you to round to the nearest whole.
x = 31
The squirrel's height in the tree is 31ft.
40,512 rounded to the nearest thousand
Answer: 41,000
Step-by-step explanation:
If the hundreds column 5 or more than it rounds up if it is lower it rounds down
.
Type the correct answer in the box.
Simplify this expression:
-2x + 3 - (5 - 6x)
Answer:
4x-2
Step-by-step explanation:
-2x + 3 - (5 - 6x)
-2x+3-5+6x
Collect Like Terms
4x+3-5
Calculate the difference, you should end up with 4x-2
In need of some Science help! If you can please go help me out! :)
Find the values of X and Z
Answer:
x = 12, z = 109
Step-by-step explanation:
12x - 73 = 71
12x = 71 + 73 = 144
x = 144/12 = 12
z = 180 - 71 = 109
. Suppose a government agency has a monopoly in the provision of internet connections.
The marginal cost of providing internet connections is 1
2
, whereas the inverse demand
function is given by: p = 1
The government agency as a monopolist will produce and sell internet connections up to the point where the marginal cost is 1/2. The price will be set at 1, given the perfectly elastic demand function.
In the scenario where a government agency has a monopoly in the provision of internet connections and the inverse demand function is given by p = 1, we can analyze the market equilibrium and the implications for pricing and quantity.
The inverse demand function, p = 1, implies that the market demand for internet connections is perfectly elastic, meaning consumers are willing to purchase any quantity of internet connections at a price of 1. As a monopolist, the government agency has control over the supply of internet connections and can set the price to maximize its profits.
To determine the optimal pricing and quantity, the monopolist needs to consider the marginal cost of providing internet connections. In this case, the marginal cost is given as 1/2. The monopolist will aim to maximize its profits by equating marginal cost with marginal revenue.
Since the inverse demand function is p = 1, the revenue received by the monopolist for each unit sold is also 1. Therefore, the marginal revenue is also 1. The monopolist will produce up to the point where marginal cost equals marginal revenue, which in this case is 1/2.
As a result, the monopolist will produce and sell internet connections up to the quantity where the marginal cost is 1/2. The monopolist will set the price at 1 since consumers are willing to pay that price.
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Choices:
A. 0.38
B. 0.64
C. 0.69
D. 2.00
Answer I think it is a
Step-by-step explanation: A
I need the answers for the table below.
The values of f(x) for the given x - values rounded to 4 decimal places are 0.0078, 0.0078, 0.0020, 0.0020, 0.0019 and 0.0013 respectively
Given the function :
tan(πx)/7xSubstitute the given value of x to obtain the corresponding f(x) values :
x = -0.6
f(x) = (tanπ(-0.6))/7(-0.6) = 0.0078358
x = -0.51
f(x) = (tanπ(-0.51))/7(-0.51) = 0.0078350
x = -0.501
f(x) = (tanπ(-0.501))/7(-0.501) = 0.001967
x = -0.5
f(x) = (tanπ(-0.5))/7(-0.5) = 0.001959
x = -0.4999
f(x) = (tanπ(-0.4999))/7(-0.4999) = 0.001958
x = 0.499
f(x) = (tanπ(-0.499))/7(-0.499) = 0.001951
x = -0.49
f(x) = (tanπ(-0.49))/7(-0.49) = 0.00188
x = -0.4
f(x) = (tanπ(-0.4))/7(-0.4) = 0.00125
Therefore, values which complete the table are 0.0078, 0.0078, 0.0020, 0.0020, 0.0019 and 0.0013
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Based on recent experience, ten-year-old passenger cars going through a motor vehicle inspection station have an 80% chance of passing the emissions test. Suppose that two hundred such cars will be checked out next week. Find the number of cars that are expected to pass.
Answer:
160
Step-by-step explanation:
The chance/probability of 10-year-old passenger cars passing an emission test is 80%.
200 10-year-old passenger cars will be tested next week.
How many of the 200 cars are expected to pass the emission test?
If there is an 80% chance of them passing the test then it means that 80% of the cars pass the test at any given time.
80% of 200 = 0.8 × 200 = 160
Hence, 160 (of the 200) cars are expected to pass the test.
The sound wave of two music notes can be represented by the function y = 2sin2x and y = −sin x, where x represents the time since the note is played. At what times will the frequencies of the sound waves be the same in the interval [0°, 360°)?
x = 0°, 30°, 90°, 150°
x = 0°, 90°, 210°, 330°
x = 30°, 150°, 180°, 270°
x = 180°, 210°, 270°, 330°
Based on the general form of a wave function, the times the frequencies of the sound waves be the same in the interval [0°, 360°) is x = 180°, 210°, 270°, 330°.
What is the frequency and Period of a wave?Frequency is the number of vibrations of a wave per second.
The period of a wave is the time taken for one complete vibration.
Frequency and Period are inversely related.
Frequency = 1/PeriodUsing the general form of a wave function:
Asin(bx-c)+dwhere;
A = amplitude period = 2π/bc = phase shiftd = vertical shiftFrom the two wave functions:
y = 2sin2x
b = 2
period = 2π/2
period = π = 180°
Frequency =
y = −sin x
b = 1
Period = 2π/1
Period = 2π = 360°
Therefore, the times the frequencies of the sound waves be the same in the interval [0°, 360°) is x = 180°, 210°, 270°, 330°.
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Answer:
x = 0°, 180°, 210°, 330°
If you were to graph the two functions those would be the intersection points (after converting from radians to degrees)
What is the measure of Z in the parallelogram shown?
A.190
B.90
C.150
D.30
In order to solve this exercise it is important to know that a Parallelogram is.
A Parallelogram is a Quadrilateral. It is a closed flat shape that has four sides.
By definition, some of the properties of a Parallelogram are:
1. The lengths of its opposite sides are equal.
2. Its opposite sides are parallel.
3. The opposite angles are congruent (which means that they have equal measure).
In this case you have the Parallelogram WXYZ. You can identify that the angle X and the angle Z are opposite. Therefore:
\(m\angle X=m\angle Z\)Knowing the measure of the angle X, you can determine that:
\(m\angle Z=30\degree\)The answer is: Option B.
Graph the solution to the following system of inequalities in the coordinate plane.
y>1/4x+6
y>2x-1
Answer:
The solution is any point in the common part of red and blue
The two lines intersect each other at (4 , 7)
Step-by-step explanation:
∵ y > 1/4 x + 6 ⇒ y = 1/4 x + 6
∵ y > 2x - 1 ⇒ y = 2x - 1
∴ 2x - 1 = 1/4 x + 6
∴ 2x - 1/4 x = 6 + 1
∴ 7/4 x = 7 ⇒ x = 7 ÷ 7/4
∴ x = 4
∴ y = 2(4) - 1 = 7
∴ The two lines intersect each other at (4 , 7)
∴ The solution is any point in the common part of red and blue
if the number of data observations is even, the median is generally considered to be the average of the first and last values
False, that is if the number of data observations is even, the median is generally considered to be the average of middle values not the first and last values.
The median is a simple measure of central tendency. To find the median, we arrange the observations in order from smallest to largest value. If there is an odd number of observations, the median is the middle value. If there is an even number of observations, the median is the average of the two middle values.
At least half of the observations are equal to or smaller than the median, and at least half of the measurements are equal to or greater than the median. The median divides the bottom half of observations from the upper half.
Even Number of Observations :
Suppose we have the monthly wages of 4 employees of a company. How would you find the median wage?
wages are 120,240,500,400
we have arranged their wages above from lowest to highest. This ranking will help us to determine the median. Using the method introduced earlier, the median is computed by taking the simple average of the (n/2)ᵗʰ = (4/2)ᵗʰ = 2ⁿᵈ and
(n/2 + 1)ᵗʰ = (2+1)ᵗʰ = 3ʳᵈ observations.
Therefore, the median is 240+500/2
= 370.
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Complete question
True/false
if the number of data observations is even, the median is generally considered to be the average of the first and last values
a survyer was conducted amount 25 young adults to determine how many of them exercised during the week four people they exercised four days a week five people said they excersized five days a week what percentage exercised four or five days per week
The percentage of young adults who exercised four or five days a week is 36%
Out of the 25 young adults surveyed, a total of 4 people exercised four days a week and 5 people exercised five days a week. To calculate the percentage of young adults who exercised four or five days a week, we add the number of people who exercised four days a week to the number of people who exercised five days a week, which gives us a total of 9.
We then divide this by the total number of people surveyed (25) and multiply by 100 to get the percentage.
So the percentage of young adults who exercised four or five days a week is
(9/25) x 100 = 36%
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There is 14 feet of fencing available to enclose a rectangular region. For what
The maximum area is 12.25 square feet
How to determine the maximum areaFrom the question, we have the following parameters that can be used in our computation:
Perimeter = 14 feet
This means that
P = 2(l + w)
So, we have
2(l + w) = 14
Divide by 2
l + w = 7
Make l the subject
l = 7 - w
The area is calculated as
A = lw
So, we have
A = (7 - w)w
Expand
A = 7w - w²
Differentiate and set to 0
7 - 2w = 0
So, we have
w = 3.5
Substitute w = 3.5 in A = (7 - w)w
A = (7 - 3.5) * 3.5
Evaluate
A = 12.25
Hence, the area is 12.25 square feet
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Complete question
There is 14 feet of fencing available to enclose a rectangular region. For what value of area is the area maximum
X = 3/4. Y = -1/2.
What is x + y?
you are sent to the local tea shop to pick up 9 drinks. You purchase 3 sweet teas and 6 unsweetened teas. Unfortunately, you forgot to label them. If you pick 3 drinks at random, find the probability of each event below. Give your answers as simplified fractions.
The probability of the four events are: Event 1: 1/84Event 2: 3/14Event 3: 15/28 Event 4: 5/21
The total number of drinks = 9The number of sweet teas = 3The number of unsweetened teas = 6If you select 3 drinks at random, the following events can take place:
Event 1: All three drinks are sweet teas. The probability of event 1 = (Number of ways in which all three drinks can be sweet teas) / (Number of ways to select 3 drinks)The number of ways in which all three drinks can be sweet teas = 3C3 = 1 (because all three sweet teas are already fixed)The number of ways to select 3 drinks = 9C3 = (9 × 8 × 7)/(3 × 2 × 1) = 84Therefore, the probability of event 1 = 1/84 = 1/84
Event 2: Exactly two drinks are sweet teas. The probability of event 2 = (Number of ways in which two drinks are sweet teas and one is an unsweetened tea) / (Number of ways to select 3 drinks)The number of ways in which two drinks are sweet teas and one is an unsweetened tea = (3C2 × 6C1) = 18 (because you can choose 2 sweet teas from 3 and 1 unsweetened tea from 6)The number of ways to select 3 drinks = 9C3 = (9 × 8 × 7)/(3 × 2 × 1) = 84Therefore, the probability of event 2 = 18/84 = 3/14
Event 3: Exactly one drink is a sweet tea. The probability of event 3 = (Number of ways in which one drink is a sweet tea and the other two are unsweetened teas) / (Number of ways to select 3 drinks)The number of ways in which one drink is a sweet tea and the other two are unsweetened teas = (3C1 × 6C2) = 45 (because you can choose 1 sweet tea from 3 and 2 unsweetened teas from 6)The number of ways to select 3 drinks = 9C3 = (9 × 8 × 7)/(3 × 2 × 1) = 84Therefore, the probability of event 3 = 45/84 = 15/28
Event 4: All three drinks are unsweetened teas. The probability of event 4 = (Number of ways in which all three drinks can be unsweetened teas) / (Number of ways to select 3 drinks)The number of ways in which all three drinks can be unsweetened teas = 6C3 = 20 (because you can choose 3 unsweetened teas from 6)The number of ways to select 3 drinks = 9C3 = (9 × 8 × 7)/(3 × 2 × 1) = 84 Therefore, the probability of event 4 = 20/84 = 5/21
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find the quantity if v=5i-7j and w=3i+2j ||v||-||w||
\(\begin{cases} v=5i-7j\\\\ w=3i+2j \end{cases}\qquad \begin{cases} < \stackrel{a}{5}~~,~~\stackrel{b}{-7} > \\\\ < \stackrel{a}{3}~~,~~\stackrel{b}{2} > \end{cases}\qquad \qquad \stackrel{magnitude}{\sqrt{a^2 + b^2}} \\\\[-0.35em] ~\dotfill\\\\ ||v||~~ - ~~||w||\implies \sqrt{5^2+(-7)^2}~~ - ~~\sqrt{3^2 + 2^2}\implies \sqrt{74}-\sqrt{13} ~~ \approx ~~ 5\)
5 grams = centigigrams
Answer:
500
Step-by-step explanation:
In an arithmetic progression of 21 terms, the sum of the first 2 terms is −26 and that of the middle 3 is 75. Find the first term and the common difference. Hence, determine the total sum of the arithmetic progression.
100 points!!!
Solve the following equation:
8x + 3 = 2x + 9
Answer:
\(\Huge \boxed{\boxed{ x = 1}}\)
Step-by-step explanation:
Isolate the variable on one side of the equation before trying to solve it. It means that you should only have constants (numbers) on the other side of the equal sign and the variable alone on the one side.
To do this, you can add, subtract, multiply, divide, or use any other operation to both sides of the equation as long as you do the same thing on both sides.
Your final step depends on the equation and how you've simplified it. In general, you want to figure out how you arrived at the final equation by working backwards from it. You'll isolate the variable in the last action you took.
-------------------------------------------------------------------------------------------------------------
SolutionStep1: Subtract \(\bold{2x}\) from both sides
\(8x + 3 = 2x + 9\)\(8x - 2x + 3 = 2x - 2x + 9\)\(6x + 3 = 9\)Step 2: Subtract 3 from both sides
\(6x + 3 - 3 = 9 - 3\)\(6x = 6\)Step 3: Divide both sides of the equation by 6
\(\frac{6x}{6} = \frac{6}{6}\)\(x = 1\)So the solution to the equation \(\bold{8x + 3 = 2x + 9}\) is \(\bold{x = 1}\).
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(c) Let A and B be two sets. Determine which of the following statements are true and which are false. Prove each statement that is true and give a counter-example for each statement that is false. i. P(AՈB) = P(A)ՈP(B) ii. P(AՍB) = P(A)UP(B) iii. P(A) U P(B) ⊆ CP(AUB)
i) The statement P(A Ո B) = P(A) Ո P(B) is false.
ii) The statement P(A Ս B) = P(A) U P(B) is false.
iii) The statement P(A) U P(B) ⊆ P(A U B) is true.
Sets are groups of well-defined objects or components in mathematics. A set is denoted by a capital letter, and the cardinal number of a set is enclosed in a curly bracket to indicate how many members there are in a finite set. For example, set A is a collection of all the natural numbers, such as A = {1,2,3,4,5,6,7,8,…..∞}.
i) Let A ={0,1} and B ={1,2}
Thus, A Ո B = {1}
P(A Ո B) = {∅, {0}, {1}, {2}, {0,1} , {1,2}, {0,2}}
P(A) = {∅, {0}, {1}, {0,1}}
P(B) = {∅, {1}, {2},{1,2}}
P(A) Ո P(B) = {∅, {1}}
∴ P(A Ո B) ≠ P(A) Ո P(B)
So, the given statement is false.
ii) Let A ={0,1} and B ={1,2}
Thus, A Ս B = {0,1,2}
P(A Ս B) = {∅, {0}, {1}, {2}, {0,1} , {1,2}, {0,2}, {0,1,2}}
P(A) = {∅, {0}, {1}, {0,1}}
P(B) = {∅, {1}, {2},{1,2}}
P(A) U P(B) = {∅, {0}, {1}, {2}, {0,1} , {1,2}}
∴ P(A Ս B) ≠ P(A) U P(B)
So, the given statement is false.
iii)
If X⊆Y then P(X)⊆P(Y) (1)
If X⊆Z and Y⊆Z then X∪Y⊆Z. (2)
Necessarily A⊆A∪B,
P(A)⊆P(A∪B); (a)
similarly, B⊆A∪B,
P(B)⊆P(A∪B). (b)
From (a) and (b), using (2), we conclude:
P(A) ∪ P(B) ⊆ P(A ∪ B).
So, the given statement is true.
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The difference in hours between full timers and part timers who work 6 hours a day is 4 working hours. How many more hours per day do full timers work? And what is the number of full time hours?
Let the number of hours worked by full timers be x
The difference between hours worked by the full timers and part timers is 4 hours
The hours worked by full timers can be expressed as
\(x-6=4\)Hence, full timers work 4 hours more than the part timers.
The number of full time hours is
\(\begin{gathered} x-6=4 \\ \text{Collect like terms} \\ x=4+6=10\text{ hours} \\ x=10\text{ hours} \end{gathered}\)Hence, the number of full time hours, x, is 10 hours
PLEASE HELP ME RN PLEASE
Answer:
1.
\( \frac{n^{2} - 1 }{2} \)
2.
\( \sqrt{29} \)
Step-by-step explanation:
Area of triangle=1/2×b×h
=
\( \frac{1}{2} \times (n - 1)(n + 1)\)
\( \frac{( {n}^{2} + n - n - 1) }{2 } \)
\( \frac{ {n}^{2} - 1 }{2} \)
2. Area of triangle=14
\( \frac{ {n}^{2} - 1 }{2} = 14\)
\( {n}^{2} - 1 = 28\)
\( {n}^{2} = 29\)
\(n = \sqrt{29} \)
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Evaluate 3x2 + 3x - 9, when x = 2
Answer:
9
Step-by-step explanation:
3x^2 + 3x - 9
Substitute x = 2 into the equation.
3(2)^2 + 3(2) - 9
3(4) + 6 - 9
12 + 6 - 9
18 - 9 =
9
first principle derivative of √cosecx
Answer:
• from first principles rule:
\({ \boxed{ \bf{ \frac{ \delta y}{ \delta x} = {}^{lim _{x} } _{h \dashrightarrow0} \: \frac{f(x + h) - f(x)}{h} }}}\)
• f(x) → (csc x)^½
• f(x + h) → {csc (x + h)}^½
\({ \rm{ \frac{ \delta y}{ \delta x} = {}^{lim _{x} } _{h \dashrightarrow0} \: \frac{ \{\csc(x + h) \} {}^{ \frac{1}{2} } - (\csc x ) {}^{ \frac{1}{2} } }{h} }} \\ \\ \hookrightarrow \: { \tt{rationalise : }} \\ \\ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{ \csc(x + h) - \csc x }{h \{ \{\csc(x + h) \} {}^{ \frac{1}{2} } + ( \csc x) {}^{ \frac{1}{2} } \} } }} \\ \\ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{1 - (\sin (x + h))( \csc x)}{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } }}} \\ \\ = { \rm{ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{1 - ( \sin(x) \cos(h) + \cos(x) \sin(h)) \csc x }{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } }}} }} \\ \\ = { \rm{ = { \rm{{}^{lim _{x} } _{h \dashrightarrow0} \: \frac{1 - \cos(h) + \cot(x) \sin(h) }{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } }}} }} \\ \\ { \tt{but : \sin(h) \approx h}} \\ { \tt{ : \cos(h) \approx 1 }} \\ \\ = { \rm{{{}^{lim _{x} } _{h \dashrightarrow0 \: } \: \frac{h \cot(x) }{h \{ \sin(x + h) \} \{ \csc(x + h) \} {}^{ \frac{1}{2} } \{ \csc x \} {}^{ \frac{1}{2} } } }}} \\ \\ { \tt{h \: tends \: to \: 0}} \\ \\ { \boxed{ \rm{ \frac{dy}{dx} = - \frac{1}{2 \sqrt{ \cot(x) \csc(x) } } }}}\)
A dairy farmer wants to mix a 70% protein supplement and a standard 20% protein ratio to make 1900 pounds of a high grade 55% protein ration how many pounds of each should he use
The dairy farmer should use 1330 pounds of the 70% protein supplement and 570 pounds of the 20% protein ratio to make a 1900-pound high-grade 55% protein ration.
To determine the amounts of the 70% protein supplement and the 20% protein ratio needed to make a 1900-pound high-grade 55% protein ration, we can set up a system of equations.
Let's assume x represents the pounds of the 70% protein supplement and y represents the pounds of the 20% protein ratio.
The total weight equation is given by:
x + y = 1900
The protein content equation is given by:
(0.70x + 0.20y) / 1900 = 0.55
Simplifying the second equation, we get:
0.70x + 0.20y = 0.55 × 1900
0.70x + 0.20y = 1045
Now, we can solve this system of equations to find the values of x and y.
Rearrange the first equation to solve for x:
x = 1900 - y
Substitute this expression for x in the second equation:
0.70(1900 - y) + 0.20y = 1045
1330 - 0.70y + 0.20y = 1045
1330 - 0.50y = 1045
-0.50y = 1045 - 1330
-0.50y = -285
y = -285 / -0.50
y = 570
Now substitute this value of y back into the first equation to find x:
x + 570 = 1900
x = 1900 - 570
x = 1330
Therefore, the dairy farmer should use 1330 pounds of the 70% protein supplement and 570 pounds of the 20% protein ratio to make a 1900-pound high-grade 55% protein ratio.
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Please help by tomorrow
The equation shows that the number of toys that must be bought for them to have equal profit will be 212 toys.
How to calculate the value?From the information, it should be noted that the equation that can be used to represent the information about Jaclyn company will be:
= 2125 + (49.99 × x)
= 2125 + 49.99x
The equation that can be used to represent the information about Richie company will be:
= (39.95 × x)
= 39.95x
Therefore, we will equate both equations:
2125 + 49.99x = 39.95x
49.99x - 39.95x =2125
10.04x = 2125
x = 212
Therefore, the number of toys that must be bought for them to have equal profit will be 212 toys.
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