in a chess tournament, each player plays against every other player exactly once. in a total of 36 games are played, how many players are there in the tournament?

The linear equation applicable for the statement is a w = 8m+3.

According to the statement

We have to find that the linear equation related to the statement.

So, For this purpose, we know that the

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

From the given information:

Bill's spelling list is 3 words long at the start of the school year. Each month, his teacher adds 8 words to the list.Let m represent the number of months since school began and w represent the total number of spelling words.

Then

Total number month when words have been added = m

Total number of words after m month = w

At starting the number list = 3

Then

The linear equation become

w = 8m+3

This is the linear equation.

So, The linear equation applicable for the statement is a w = 8m+3.

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Answer:

3 unless you're adding onto the 12 kilograms, then only 1

Step-by-step explanation:

Answer:

try B if not maybe C

Step-by-step explanation:

The correct answer is B. The graph of h is the graph of g vertically shifted up 1 unit.

The correct answer is:

B. The graph of h is the graph of g vertically shifted up 1 unit.

Explanation:

The original function g(x) = x² represents a basic quadratic function, which is a parabola that opens upward and has its vertex at the origin (0, 0).

When we consider the function h(x) = g(x) + 1, we are adding a constant value of 1 to the output (y) values of the function g(x). This results in a vertical shift of the graph of g(x) by 1 unit upward.

In other words, for every x-value, the corresponding y-value of the function h(x) will be 1 unit higher than the corresponding y-value of the function g(x).

Visually, this means that the graph of h(x) will be the same shape as the graph of g(x), but it will be shifted upward by 1 unit. The vertex of the parabola, which was originally at the origin, will now be at (0, 1).

The statement "The graph of h is the graph of g horizontally shifted left 1 unit" (Option A) is incorrect because there is no horizontal shift in this transformation.

The statement "The graph of h is the graph of g vertically shifted down 1 unit" (Option B) is incorrect because the transformation results in a vertical shift upward, not downward.

The statement "The graph of h is the graph of g horizontally shifted right 1 unit" (Option D) is incorrect because there is no horizontal shift in this transformation.

Therefore, the correct answer is B. The graph of h is the graph of g vertically shifted up 1 unit.

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Answer:

degree 2

Step-by-step explanation:

the standard form of a quadratic function is

y = ax² + bx + c (a ≠ 0 )

the degree of a function is determined by the largest value of the exponent of the variable.

in the case of a quadratic the term with the largest exponent is ax²

with exponent 2

then quadratic function is of degree 2

Answer:

Andre has more money in his savings account.

Step-by-step explanation:

We need to have equations for both Andre and Elena. Andre starts with $100 in his savings and adds $5 per week.  Based on this, Andre's equation will be y = 5x + 100. Elena starts with $10 and adds $20 per week. Based on this, Elena's equation will be y = 20x + 10.

Andre: y = 5x + 100

Elena: y = 20x + 10

We have to figure out who will have more money in their account after 4 weeks. To do that, we plug in 4 into x because x is the number of weeks.

Andre: y = 5(4) + 100

           y = 20 + 100

           y = 120

Andre has $120 after 4 weeks.

Elena: y = 20(4) + 10

          y = 80 + 10

          y = 90

Elena has $90 after 4 weeks.

Which is greater? $120 or $90? That's right, its $120. Andre has more money in his savings account. I hope this helps!  

Step-by-step explanation:

5x and -7x are like terms

5x-7x+9=-2x+9 and there's your equivalent expression

Answer:

i want to say 7x is the answer

Step-by-step explanation:

because if you add 5x to 9 = to 14 the -7 = to 7x

Answer:

Step-by-step explanation:

6x-y=-5

-6x+y=5

Adding the 2 equations we have:

0 + 0 = 0

0 = 0

This means there are infinite solutions

- the equations are identical.

System B

x+3y=13

-x+3y=5

Adding:

6y = 18

y = 3.

x = 13 - 3(3) = 4.

The system has a unique solution

(x. y) = (4, 3).

The area of the associated sector is: 120π

A sector is the portion of the area of a circle surrounded by an arc and two radii.

Analysis:

Area of a sector = ∅/360 x π\(r^{2}\)

∅ = 75°

r = 24 units

Area of sector = 75/360 x π\((24)^{2}\) = 120\(\pi\) square units

In conclusion, the area of the associated sector is 120π square units

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Answer:

A

Step-by-step explanation:

I Just Took the Test.

The probability that the first person to say yes is the 7th customer is 0.00005

Here we are given that we need to find the probability of the first person to say yes to extending the automobile insurance beyond three years being the 7th customer.

This clearly follows a Geometric distribution since the variable of interest here is the no. of calls that need to be placed until we get out first "success."

PDF of Geometric distribution is as follows,

P(X = x) = pˣ (1 - p)⁽ˣ ⁻ ¹⁾

where,

x is no. of trials to get the first success

p = probability of a success

here,

p = 37%

=37/100

= 0.37

Therefore,

1 - p = 1 - 0.37

= 0.63

x = 7

Hence we get

P(X = 7) = 0.37⁷ 0.63⁶

= 0.00005

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Answer:

5

Step-by-step explanation:

Answer:

\(x^{\frac{1}{8}}y^8\).

Step-by-step explanation:

The given expression is

\((x^{\frac{1}{4}}y^{16})^{\frac{1}{2}}\)

We need to find the expression, which is equivalent to the given expression.

The given expression can be rewritten as

\((x^{\frac{1}{4}})^{\frac{1}{2}}(y^{16})^{\frac{1}{2}}\)     \([\because (ab)^m=a^mb^m]\)

\((x^{\frac{1}{4}\times \frac{1}{2}})(y^{16\times \frac{1}{2}})\)     \([\because (a^m)^n=a^{mn}]\)

\(x^{\frac{1}{8}}y^8\)

Therefore, the required expression is \(x^{\frac{1}{8}}y^8\).

The simplified form of the indices is \(x^{1/4}y^8\)

Given the expression:

\((x^{1/4}y^{16})^{1/2}\)

Using the law of indices below:

\((a^m)^n = a^{mn}\)

Multiplying the power will give:

\(= (x^{1/4})^{1/2} \cdot (y^{16})^{1/2}\\=x^{1/4}y^8\)

Hence the simplified form of the indices is \(x^{1/4}y^8\)

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:According to the question:You are working with a population of crickets. Before the mating season you check to make sure that the population is in Hardy-Weinberg equilibrium, and you find that the population is in equilibrium.

During the mating season you observe that individuals in the population will only mate with others of the same genotype (for example Dd individuals will only mate with Dd individuals). There are only two alleles at this locus ( D is dominant, d is recessive), and you have determined the frequency of the D allele =0.6 in this population. Selection acts against homozygous dominant individuals and their survivorship per generation is 80%. After one generation the frequency of DD individuals will decrease in the population.

According to the Hardy-Weinberg equilibrium equation p² + 2pq + q² = 1, the frequency of D (p) and d (q) alleles are:p + q = 1Thus, the frequency of q is 0.4. Here are the calculations for the Hardy-Weinberg equilibrium:p² + 2pq + q² = 1(0.6)² + 2(0.6)(0.4) + (0.4)² = 1After simplifying, it becomes:0.36 + 0.48 + 0.16 = 1This means that the population is in Hardy-Weinberg equilibrium. This is confirmed as the frequencies of DD, Dd, and dd genotypes

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Answer:

16

Step-by-step explanation:

just divide 20 by 1  1/4

The limit of the given expression as x approaches 1 from the right is 1.8.

To evaluate the limit of the given expression:

\(lim_{x - > 1} + [ln(x ^ 9 - 1) - ln(x ^ 5 - 1)]\)

We can start by directly substituting x = 1 into the expression:

[ln(1⁹ - 1) - ln(1⁵ - 1)]

= [ln(0) - ln(0)]

However, ln(0) is undefined, so this approach doesn't provide a meaningful answer.

To apply L'Hôpital's Rule, we need to rewrite the expression as a fraction and differentiate the numerator and denominator separately. Let's proceed with this approach:

\(lim_{x - > 1}\)+ [ln(x⁹ - 1) - ln(x⁵ - 1)]

= \(lim_{x - > 1}\)+ [ln((x⁹ - 1)/(x⁵ - 1))]

Now, we can differentiate the numerator and denominator with respect to x:

Numerator:

d/dx[(x⁹ - 1)] = 9x⁸

Denominator:

d/dx[(x⁵ - 1)] = 5x⁴

Taking the limit again:

\(lim_{x - > 1}\)+ [9x⁸ / 5x⁴]

= \(lim_{x - > 1}\)+ (9/5) * (x⁸ / x⁴)

= (9/5) * \(lim_{x - > 1}\)+ (x⁸ / x⁴)

Now, we can substitute x = 1 into the expression:

(9/5) * \(lim_{x - > 1}\)+ (1⁸ / 1⁴)

= (9/5) * \(lim_{x - > 1}\)+ 1

= (9/5) * 1

= 9/5

= 1.8

The complete question is:

Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. \(lim_{x - > 1} + [ln(x ^ 9 - 1) - ln(x ^ 5 - 1)]\)

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Once you have computed the expected value, you can mark your guess on the graph by finding the point where the curve is balanced. This is the point where the area to the left of the point is equal to the area to the right of the point.

A probability density function is a function that describes the likelihood of a random variable taking on a certain value. The area under the curve of a probability density function must be equal to 1. The normalizing constant, denoted by k, is a constant that is multiplied by the probability density function to ensure that the area under the curve is equal to 1. In other words, k is the value that makes the integration of the probability density function equal to 1.

To find the value of k, you would need to integrate the probability density function over its entire range and set the result equal to 1. Once you have found k, you can sketch the density function by plotting the function on the y-axis and the possible values of x on the x-axis.

The expected value of a random variable is a measure of the center of its distribution. It represents the average value that the variable would take if it were repeated many times. To compute the expected value of a continuous random variable, you would need to integrate the product of the random variable and its probability density function over its entire range.

Once you have computed the expected value, you can mark your guess on the graph by finding the point where the curve is balanced. This is the point where the area to the left of the point is equal to the area to the right of the point.

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Answer:(0,8) or 8

I hope this is good enough:

Answer:

(0,8)

Step-by-step explanation:

Step-by-step explanation:

please, write the problem statement properly. it is not clear what you are asking for.

for example, the way how you wrote it, the first expression would be

58 × 5 - 6

and that would be (remember, multiplication and division happen before any additions or subtractions)

58 × 5 - 6 = 290 - 6 = 284

nothing on the right side of numbers fits to that.

so, I am speculating. did you mean

58 × (5-6) ?

in that case we get

58 × (5-6) = 58 × (-1) = -58

and then I assume that the right side of all the numbers includes also operations (like +, -, ...), as I see no -58 in the list of numbers.

and then I just propose that the right side could look like

-2×5 - 48 (which would also be -58).

but again, this could be something completely different.

so, please, write your problem statement again. and carefully.

To determine which set of data most likely has a mean closest to 29.5, we need to analyze the shape and position of the histograms in relation to the value 29.5.

Looking at the histograms described:

The first histogram ranges from 9 to 48, and the upward trend starts from 1 and ends at 33, followed by a downward trend. This histogram suggests that there may be values lower than 29.5, which would bring the mean below 29.5.

The second histogram ranges from 15 to 48, with an upward trend from 1 to 30 and then a downward trend. Similar to the first histogram, it suggests the possibility of values lower than 29.5, indicating a mean below 29.5.

The third histogram ranges from 12 to 56, and the upward trend starts from 1 and ends at 32, followed by a downward trend. This histogram covers a wider range but still suggests the possibility of values below 29.5, indicating a mean below 29.5.

The fourth histogram ranges from 15 to 54 and exhibits multiple trends. While it has fluctuations, it covers a wider range and includes both upward and downward trends. This histogram suggests the possibility of values above and below 29.5, potentially resulting in a mean closer to 29.5.

Based on the descriptions, the fourth histogram, with its more varied trends and wider range, is most likely to have a mean closest to 29.5.

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= 7.211102550928

The distance is 7.21 units.

Answer:

You would get 5.

Step-by-step explanation:

According to the order of operations ( GEMDAS or PEMDAS ), in a problem the first step is grouping.

20 - 5(3) = 20 - 15, because 5 * 3 is 15 and parenthesis is  a sign of multiplication. Then you would get:

20 - 15 = 5.

Here we would not inverse the subtraction sign, because there is an operation before the grouping

Would reverse operation:

20 - ( 5 + 3 )

Would NOT reverse operation:

20 - 5(2) Operation before the subtraction

Answer:

Step-by-step explanation:

x² - 38x + 72 = (x-2)(x-36)

x( -2 + 3x^4) -4 =0

x1 = 0

x2 =

-2 + 3x^4 = 0

3x^4 = 2

x^4 = 2/3

x2 =

\( \sqrt[4]{ \frac{2}{3} } \)

Answer:

People often sort stacks of documents using a recursive method. For example, imagine you are sorting 100 documents with names on them. First place documents into piles by the first letter, then sort each pile. Looking up words in the dictionary is often performed by a binary-search-like technique, which is recursive.

Step-by-step explanation:

This is just an example.

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By using the concept of z-score, the pregnancy length value below which the shortest 5% of pregnancies fall is approximately 243.55 days (rounded to two decimal places).

The pregnancy length that is shorter than 5% is the value at the 5th percentile. The z-score for this value can be calculated as shown:

\($z=\frac{x-\mu}{\sigma}$$\)

Where x is the unknown value, µ is the mean of the distribution and σ is the standard deviation.

Hence, we have that,

\($-1.64=\frac{x-260}{10}$$\)

\($x=260+(-1.64)\cdot10 = 243.6$$\)

Therefore, by using the z-score formula 5% of pregnancy lengths are shorter than 243.6 days.

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After evaluating the integral is \(69x^{6}/2 + 23x^{3} +C\).

Given:

(3x3+1)69x2 dx

= 69\(x^{2}\)*3\(x^{3}\) + \(69x^{2}\)

= 207\(x^{5}\) + \(69x^{2}\)

apply integration

= ∫ 207\(x^{5}\) + \(69x^{2}\)

= 207∫\(x^{5}\) + 69∫\(x^{2}\)

= 207*\(x^{6} /6\) + 69*\(x^{3} /3\)

= 69\(x^{6} /2\) + \(23x^{3}\) + C

Therefore After evaluating the integral is \(69x^{6}/2 + 23x^{3} +C\).

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The calculated value of the surface area of the cube is 294 mm^2

From the question, we have the following parameters that can be used in our computation:

The cube

The side length of the cube is

Length = 7 mm

The surface area of the cube is calculated as

Surface area = 6 * Length^2

Substitute the known values in the above equation, so, we have the following representation

Surface area = 6 * 7^2

Evaluate

Surface area = 294 mm^2

Hence the surface area is 294 mm^2

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Using the properties of multiplication to compare the expressions 3 to the eighth power and 3 to the fifth power x 3 to the third power, it can be seens that that the two expressions are equal to each other.

The properties of multiplication state that when multiplying two expressions with the same base, we can add their exponents together. This means that 3 to the fifth power x 3 to the third power is equal to 3 to the eighth power.

In mathematical notation, this looks like:

3^8 = 3^5 x 3^3

Using the properties of multiplication, we can add the exponents together:

3^8 = 3^(5+3)

Simplifying the exponent:

3^8 = 3^8

This shows that the two expressions are equal to each other. Therefore, we can conclude that 3 to the eighth power and 3 to the fifth power x 3 to the third power are the same value.

Note: The question is incomplete. The complete question probably is: Use the properties of multiplication to compare the expressions 3 to the eighth power and 3 to the fifth power x 3 to the third power.

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