in 2000 the population of India was around 1.053 billion , and in 2016 the population hit 1.327 billion people . if India's population continues to grow at this same rate in what year was the population of India reach 3 billion people. ​

\(8^{3} \cdot 8^{-7} =8^{-4}=\boxed{\frac{1}{8^4}}\)

We have the following:

We must calculate the slope through the points:

(x1, y1) = (-9, 7)

(x2, y2) = (-6, -3)

replacing:

for b,

x = -9

y = 7

m = -10/3

replacing:

Therefore, the equation is:

subtracting a positive number

4 - 2 = 2

Adding a negative number

4+ (-2) = 4 - 2 = 2

So they are not completely different operations.

Answer : FALSE

Answer:

the fist one

Step-by-step explanation:

Hope it helps

The quartiles divide a dataset into four equal sections. The quartiles are used to measure the central tendency and variability of a dataset.

The quartiles divide the data into four parts, with each part containing an equal number of values. The quartiles are the first quartile (Q1), the second quartile (Q2), and the third quartile (Q3).

For second quartile:The stem-and-leaf plot for the test scores of 24 students is given below:5|2 4 5 5 7 8 9 6|4 5 6 6 7 7 1|1 2 2 4 8 3|4 6 7 7 7 9

The data must be ordered from least to greatest before calculating the quartiles.1.

Order the data:1 2 2 4 4 5 5 5 6 6 6 7 7 7 7 8 9 9 2.

The median is the middle value in the dataset. The median divides the data into two halves, with half the data on either side of the median. If there is an even number of values in the dataset, the median is the average of the two middle values.

In this case, there are 24 values, so the median is the average of the twelfth and thirteenth values:(6+7)/2=6.5

Therefore, Q2=6.53.

The first quartile (Q1) is the median of the lower half of the dataset. Q1 divides the lower half of the data into two quarters, with half the data on either side of Q1. 12 values are in the lower half of the dataset. Q1 is the median of these values.

Therefore, the values 1 2 2 4 4 5 5 5 6 6 6 7 are used to calculate Q1:(5+5)/2=5

Therefore, Q1=5.4.

The third quartile (Q3) is the median of the upper half of the dataset. Q3 divides the upper half of the data into two quarters, with half the data on either side of Q3.

12 values are in the upper half of the dataset. Q3 is the median of these values.

Therefore, the values 7 7 7 8 9 9 are used to calculate Q3:(7+8)/2=7.5

Therefore, Q3=7.5 .

The median (Q2) is 6.5. The interquartile range (IQR) is the difference between Q3 and Q1.

Therefore, the interquartile range (IQR) is 7.5-5=2.5.

The first quartile (Q1) of the given stem-and-leaf plot is 5, and the third quartile (Q3) is 7.5. The median (Q2) is 6.5. The interquartile range (IQR) is 2.5.

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Answer:

1/10

0.1

Step-by-step explanation:

The given identities can be verified using basic rules of exponentials and algebra. Here are the steps to verify the given identities:

(a) 1 = ∑_(n=1) ^∞▒〖10^(x)+2(-1) ^nln⁡(x)〗0

Rewrite the sum to obtain two series, one for even values of n, and one for odd values of n. ∑_(n=1)^∞▒10^(x) = 10^x+10^x+...= (2/3) (10^x) (odd terms only)∑_(n=1)^∞▒〖(-1)^nln⁡(x)〗= ln(x)-ln(x)+ln(x)-ln(x)+...= (0) (even terms only)

Thus, we have 1= (2/3) (10^x) + (0) = (2/3) (10^x) (b) e^x = ∑_(n=1) ^∞▒〖10^x+2n(x)〗

Rewrite the sum to obtain two series, one for even values of n, and one for odd values of n.

∑_(n=1) ^∞▒10^(x) = 10^x+10^x+...= (1/2) (10^x) (even terms only) ∑_(n=1) ^∞▒〖2n(x)〗= 2(x)+2(2x) +2(3x) +...= 2x (1+2+3+...) = -x/(-1) ^2= -x

Thus, we have e^x= (1/2) (10^x) - x(c) e^(-x) = ∑_(n=1) ^∞▒〖10^x+2(-1) ^nln⁡(x)〗0

We can use the same series from part (a) with x replaced by -x.

Thus, we have e^(-x) = (2/3) (10^(-x)) + (0) = (2/3) (1/10^x)

Similarly, e^x= (2/3) (10^x) Subtracting these two equations, we get: e^x - e^(-x) = (2/3) (10^x + 1/10^x) (answer) (d)

Cosh x = ∑_(n=0) ^∞▒〖10^x+2n(x)〗

Similar to part (b), we have two series, one for even values of n, and one for odd values of n.∑_(n=0)^∞▒10^(x) = 1+10^x+10^x+...= (1/2) (10^x) (even terms only)∑_(n=0)^∞▒〖2n(x)〗= 0+2x+2(2x)+2(3x)+...= 2x (1+2+3+...)= 2x(1/(-1)^2)= 2xThus, we have Cosh(x) = 1 + (1/2) (10^x) + 2x (e^x)(e^x - e^(-x)) / 2= 1 + (1/2) (10^x) + 2x (1 + (2/3) (10^x + 1/10^x)) (answer)(e) Sinh x = ∑_(n=1)^∞▒〖2^(2n-1)(x)〗

Rewrite the sum to obtain two series, one for even values of n, and one for odd values of n.∑_(n=1)^∞▒〖2^(2n-1)(x)〗= 2x+2^3x+2^5x+...= 2x(1+2^2+2^4+...)= 2x(2^0+2^2+2^4+...)= 2x(1/ (1-2^2))= -2x/3Thus, we have Sinh(x) = ∑_(n=1)^∞▒〖2^(2n-1)(x)〗= 2x/3 (answer)

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Answer:

77 inches

Step-by-step explanation:

sector formula = x°/360° × πr^2

=77°/360°×22/7×10.7×10.7

=76.96 in

As it is asked the nearest tenth it's 77 inches.

Answer:

76.9in²

Step-by-step explanation:

A = 77/360 × 22/7 × 10.7²

A = 11/180 × 11 × 114.49

A = 13853.29/180 = 76.9627

A = 76.9in²

Answer:

C.) AFD measures 30°

Step-by-step explanation:

it is 150 degrees

Answer:

the answer is C

Step-by-step explanation:

A)  angle EFC is 80 degrees so a is a true statement

B) angle BFC is 60 degrees and angle DFE is 30 degrees 60+30=90 so that's a true statement

D) angle AFB is 40 degrees and angle CFD is 50 degrees  40+50=90 so that a true statement

that leaves C and angle AFD is more than 30 degrees its 150 degrees

Answer:

5x+2

Step-by-step explanation:

:)

Answer:

16x little 2 on top - 40xy + 25y little 2 on top

Step-by-step explanation:

The formula is \(P(X = k) = (e^(-λ) * λ^k) / k!\), where X is the random variable representing the number of airplanes, λ is the rate parameter (5 per hour in this case), and k is the number of airplanes we want to detect.

To find the probability of detecting 12 airplanes in the next three hours, we can use the Poisson distribution formula.
In this case, we want to find the probability of detecting 12 airplanes in the next three hours. Since the rate is given as 5 per hour, the rate for three hours will be 5 * 3 = 15.
Now, we can plug in these values into the formula:
\(P(X = 12) = (e^(-15) * 15^12) / 12!\)
Using a calculator, we can evaluate this expression:
\(P(X = 12) ≈ 0.072\), the probability of detecting 12 airplanes in the next three hours is approximately 0.072, or 7.2%.

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If you multiply the left side of an equation by 4, what must you multiply the right side of the equation by 4

Here you you multiply the left side of an equation by 4.

According to the solving for unknow rule you must perform same function to both side of the equation. If you multiply the left side of an equation by any integer then you must multiply the same integer on right hand side of the equation

To maintain equality, you must multiply the right side of the equation by 4 as well.

This is because the left side of the equation represents the same quantity as the right side, so any operation that is performed on one side must also be performed on the other side to preserve the equality.

Therefore, you must multiply the right side of the equation by 4

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Answer:

100

Step-by-step explanation:

The relationship between the ratios is multiplying by 10.

Have a splendiferous day!

Hope this helps!

Answer:

Angle y measures 130 degrees

Step-by-step explanation:

Notice that the angles marked as "2x+18", and "4x-14" must be equal angles since they are generated on the same sector (top right) of the parallel lines by the transverse line "b".

Then by finding the value of "x" we can deduce the value of the actual angle these two angles measure:

\(2x+18=4x-14\\18+14=4x-2x\\32=2x\\x=16^o\)

Now, we can find the actual value of these two angles, we use for example the first expression:

Top-right angle = \(2\,(16^o)+18^o=50^o\)

Now, if these two angles measure \(50^o\), then angle "y" (which is the supplementary angle (angle which added renders \(180^o\) )  for them, must equal \(180^o-50^o=130^o\)

Answer:

It's C. 130

Step-by-step explanation:

O just did the math and got it right on the test.

The probability that the age of that student will be 15 years is 0.18.

The probability that the age of that student will be 16 years or older is 0.62.

We know that if frequency of a certain value is f and total number of bservations is n, then relative frequency is f/n. It can be treated as probability of the occurence of that value.

(a) Let X denotes the age of selected student.

(i) P( age of that student will be 15 years)= P(X=15)= 0.18

(ii) P( student is 16 years of age or older)= P(X=16)+P(X=17)+P(X=18)= 0.22+0.27+0.13= 0.62

(b) If 1200 students are selected, then number of students with age 15 years= 1200× 0.18 = 216

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The tables of values for 2cos(3θ) are 2, 0, -1.41, -2 and 0.

When we multiply cos(Theta) by 2 and then take the cosine of 3θ, we get a new trigonometric function that has different values for different values of Theta. To create a table of values for 2cos(3θ), we need to substitute different values of Theta into the function and calculate the corresponding output.

Let's take some values of Theta and calculate the corresponding values of 2cos(3θ):

   • When Theta is 0 degrees, 2cos(3θ) is 2cos(0), which is equal to 2.

   • When Theta is 30 degrees, 2cos(3θ) is 2cos(90), which is equal to 0.

   • When Theta is 45 degrees, 2cos(3θ) is 2cos(135), which is approximately equal to -1.41.

   • When Theta is 60 degrees, 2cos(3θ) is 2cos(180), which is equal to -2.

   • When Theta is 90 degrees, 2cos(3θ) is 2cos(270), which is equal to 0.

We can continue this process to generate more values and create a table of values for 2cos(3θ). By substituting different values of Theta into the function and calculating the corresponding outputs, we can observe patterns and relationships between the input and output values.

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The given expression written in standard form is 4.076008 × 10³

From the question, we are to simplify the given expression in standard form

The given expression is

(4 × 1000) + (7 × 10) + (6 × 1) + (8 × 0.001)

Simplifying

(4 × 1000) + (7 × 10) + (6 × 1) + (8 × 0.001)

(4000) + (70) + (6) + (0.008)

= 4000 + 70 + 6 + 0.008

= 4076.008

In standard form, we get

4.076008 × 10³

Hence, the given expression written in standard form is 4.076008 × 10³

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Answer:

23.64

Step-by-step explanation:

\(\frac{6.6+3.2}{5}\) × (2 - 5)² + 6

= \(\frac{9.8}{5}\) × (- 3)² + 6

= 1.96 × 9 + 6

= 17.64 + 6

= 23.64

The value of the (6.6 + 3.2)/5*(2-5)²+6 is 23.64

An expression is a set of terms combined using the operations +, -, x or ÷, /

Given statement:

The sum of 6.6 and 3.2 all divided by 5 times the quantity of the squared difference of 2 minus 5 plus 6.

Now,

(6.6 + 3.2)/5*(2-5)²+6

=9.8/5*3²+6

=1.96*9+6

=17.64+6

=23.64

Hence, the value is 23.64.

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Answer:

288

Step-by-step explanation:

Do the reverse.

67+5= 72

72*4= 288.

hope this helped :)

The numeric value of ms within is = 19.

To find the numeric value of ms within:

Given: Swithin = 70, sample size = 17 and number of groups = 3.

So, 17 × 3 = 51

70 - 51 = 19

Therefore, the numeric value of ms within is = 19.

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Answer:

y = 2x + 5

Step-by-step explanation:

(-1 , 3) & (2 , 9)

x₁ = -1  ; y₁ = 3    & x₂ = 2 ; y₂ = 9

\(slope=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\dfrac{9-3}{2-[-1]}\\\\=\dfrac{6}{2+1}\\\\=\dfrac{6}{3}\\\\= 2\)

m = 2 & (-1 , 3)

Equation of line:

y - y₁ = m(x - x₁)

y - 3 = 2(x - [-1])

y -3 = 2(x + 1)

y - 3 =2x +2

y = 2x + 2 + 3

y = 2x + 5

The break-even point is the level of output at which total revenue (TR) equals total cost (TC). In this case, with TR(x) = 20x and TC(x) = 120 + 10x, we need to find the value of x where TR(x) = TC(x).

To find the break-even point, we set TR(x) equal to TC(x) and solve for x.
TR(x) = TC(x) can be expressed as:
20x = 120 + 10x
Simplifying the equation, we combine like terms:
20x - 10x = 120
10x = 120
To isolate x, we divide both sides of the equation by 10:
x = 12
Therefore, the break-even point occurs when x is equal to 12. At this level of output, the total revenue is equal to the total cost.

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Answer:

it's (-2) your drawing is correct and that's why i think it's -2 because it's on the negative side

The probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

Probability defines the likelihood of occurrence of an event. There are many real-life situations in which we may have to predict the outcome of an event. We may be sure or not sure of the results of an event. In such cases, we say that there is a probability of this event to occur or not occur. Probability generally has great applications in games, in business to make probability-based predictions, and also probability has extensive applications in this new area of artificial intelligence.

The probability of an event can be calculated by probability formula by simply dividing the favorable number of outcomes by the total number of possible outcomes. The value of the probability of an event to happen can lie between 0 and 1 because the favorable number of outcomes can never cross the total number of outcomes. Also, the favorable number of outcomes cannot be negative.

\(P(50.5 < = X < = 51.25) =\frac{51.25-50.5}{54-49 } = \frac{0.75}{5} = 0.15\)

P = 0.15 means that the probability is 15%.

Thus, the probability that a given class period runs between 50.5 and 51.25 minutes is 15%.

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Answer:        我不知道你好

Step-by-step explanation:

Hey there!

\(Answer:\boxed{x=6}\)

\(Explanation:\)

\(8x+0.2=48.2\)

Let's start with subtracting 0.2 from both sides of the equation.

\(8x+0.2-0.2=48.2-0.2\\8x=48\)

In our second/last step, we will divide both sides by 8.

\(\frac{8x}{8}=\frac{48}{8}\)

Let's simplify by dividing 48 by 8.

\(48/8=6\)

\(\boxed{x=6}\text{ is your answer.}\)

Hope this helps!

\(\text{-TestedHyperr}\)

The method which the surveyor followed was the method of metes and bounds.

The surveyor followed a property's legal description by starting at a point of beginning, then following the indicated directions between natural and artificial landmarks to arrive back at the point of beginning, using the method called metes and bounds.

Metes and bounds are the natural markers that define the limits or boundaries of a piece of property. Rivers, roads, stakes, and other natural or artificial markers are examples of metes and bounds landmarks.

A system or method of representing land, real property (as opposed to personal property), or real estate is known as metes and bounds. The technique has been used in England for centuries and is still used to define general boundaries there.

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Answer:

15+4.50x,    12.50+5x

Step-by-step explanation:

Expressions are mathematical statements represented with the variables

The value of 12x^-3 y-1 for x=-1 and y=5 is - 12/5

The expression is given as:

\(12x^{-3} y^{-1}\)

When x = -1, the expression becomes

\(12 * -1^{-3} y^{-1}\)

Evaluate the exponent

\(- 12 y^{-1}\)

When y = 5, the expression becomes

\(- 12 * 5^{-1}\)

Evaluate the exponent

- 12/5

Hence, the value of 12x^-3 y-1 for x=-1 and y=5 is - 12/5

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