In 0.5hours, a supersonic jet flew 1,000kilometers to the east at a constant velocity. During the flight, the jet passed an airplane that was moving at 903 kilometers per hour. What was the jet's velocity?

We have that the new speed after she picks up her child is mathematically given as

V2=3m/s

The speed of a body is simply the rate at which the body moves or functions, the speed of a body is measured with an SI unit of m/s.

Generally the equation for the  Velocity is mathematically given as

m1v1=m2v2

Therefore

\(v2=\frac{60*4}{60+20}\)

V2=3m/s

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The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer

due to balanced forces, an object in motion cannot change its direction or speed, and also the net forces act a zero in balanced forces.

Explanation:

Unbalanced forces have a change in motion and they have a resultant force in a direction. Whereas, a balanced force does not change in direction and the resultant force is zero.

Force is an external agent acting on  a body to make it changed in its state of motion or rest or to deform it. There are various kinds of forces such as magnetic force, nuclear force, gravitational force, frictional force etc.

If there are two or more forces acting on a body from the same direction, then the net force will be the sum of all the forces. If the two forces are equal in magnitude and if act from the opposite directions they will cancel each other and will not make a displacement. Such forces are called balanced forces.

The imbalance in force on a body is made by the change in direction or in magnitude of the forces. Then there will be a net force and will make the body a change in its motion.

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If a child pulls a waxed wooden sled across dry snow at a constant speed with a 2.6 N force, the mass of the sled is 6.63 kg

Since the waxed wooden sled is pulled across dry snow at a constant speed,

a = 0

∑ Fx = m ax

F - f = 0

2.6 - f = 0

f = 2.6 N

f = μ N

N = m g

f = Frictional force

μ = Co-efficient of friction

N = Normal force

m = Mass

g = Acceleration due to gravity

μ = 0.04

f = μ m g

2.6 = 0.04 * m * 9.8

0.392 m = 2.6

m = 6.63 kg

Therefore, the mass of the sled is 6.63 kg

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a. Time that the first player took to catch his opponent is 14.1 s after he makes up his mind to chase his opponent.

b. The player has traveled 31.8 m to catch his opponent.

According to uniform motion remains the same and the distance will increase with time. The formula to calculate distance

d = v × t

According to non-uniform motion, the speed will increase with time when the object has acceleration. The formula to calculate distance

d = (v₁ × t) + (0.5 × a ×t²)

Two players didn't move at the same time. The second player moves first. After 1.80 s the first player just move.

When the first player catches his opponent, the distance between the two is the same.

d first player = d second player

(v₁ × t) + (0.5 × a × t²) = v × t

(0 × t) + (0.5 × 0.32 × t²) = 2.0 × (t + 1.80)

0 + 0.16t² = 2.0t + 3.60

0.16t² - 2.0t - 3.60 = 0

multiply by 100

16.0t² - 200.0 - 360.0 = 0

divided by 8

2.0t² - 25.0t - 45.0 = 0

Using quadratic formula

The distance

d = (v₁ × t) + (0.5 × a × t²)

d = (0 × 14.1) + (0.5 × 0.32 × 14.1²)

d = 0 + (0.16 × 198.81)

d = 31.8 m

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The needle moves to one point and then  to another. Option C

A galvanometer is an instrument used for detecting and measuring small electric currents. It works based on the principle of the magnetic effect of an electric current.

The basic mechanism of a galvanometer involves a coil of wire suspended between the poles of a permanent magnet. When an electric current passes through the coil, it generates a magnetic field around it. The magnetic field interacts with the magnetic field of the permanent magnet, causing the coil to rotate.

A  galvanometer deflects due to the interaction between the magnetic field generated by the electric current passing through the coil and the magnetic field of the permanent magnet.

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Explanation:

arn core concepts.

See Answer

1) For a P wave with velocity of 8 km/s (typical upper mantle speed) in a Poisson solid,compute the wavelength for waves with periods of:

a) 15 sec

b) 1 sec

c) 0.1 sec (100 Hz)

2) Repeat question 2 for an S wave in the same medium (Hint: you have to determine the S wave speed).

First option is correct.Larry the Rock is going through Static Equilibrium.

In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.

Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.

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Answer:

\(20m/s^2\)

Explanation:

Solution is attached. I apologize if it is a little messy.

Answer:

hopefully alex quackity hahhaa

Explanation:

i hope this was free points and not an actual thing

Answer:

cool, cool for alex .....

Machine 1 has the greatest mechanical advantage among the given machines. To determine the machine with the greatest mechanical advantage, we need to calculate the mechanical advantage for each machine.

Machine 1: Mechanical Advantage = Output Force / Input Force = 50 N / 5 N = 10

Machine 2: Mechanical Advantage = Output Force / Input Force = 50 N / 10 N = 5

Machine 3: Mechanical Advantage = Output Force / Input Force = 50 N / 25 N = 2

Machine 4: Mechanical Advantage = Output Force / Input Force = 50 N / 50 N = 1

Comparing the mechanical advantages, we can see that Machine 1 has the highest mechanical advantage of 10. This means that Machine 1 can multiply the input force by 10 to produce the output force. It provides the greatest amplification of force among the four machines.

Machine 2 has a mechanical advantage of 5, Machine 3 has a mechanical advantage of 2, and Machine 4 has a mechanical advantage of 1. Therefore, Machine 1 has the greatest mechanical advantage among the given machines.

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Beta decay is seen in the nuclear reaction: ⁹⁰₃₉Y → ⁹⁰₄₀Zr + ⁰₋₁e. Hence, option (A) is correct.

A proton can change into a neutron or vice versa inside the radioactive sample's nucleus through a process known as beta decay.

The radioactive sample's nucleus can approach the ideal neutron/proton ratio as closely as feasible through processes like beta decay and alpha decay. The nucleus releases a beta particle during this process, which can either be an electron or a positron.

As electron releases here, it is a Beta (β) decay.

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Kinematics is the study of the motion of a system of bodies without directly considering the forces or potential fields affecting the motion. In other words, kinematics examines how momentum and energy are shared among interacting bodies.

Answer:

B- just took the quiz

Explanation:

Answer:

B - Plasma can have lots of space between its particles, so it naturally expands and compresses.

Explanation:

The position of the center of mass of the system remains constant during the experiment.

The principle of conservation of linear momentum states that the total momentum of the system before after collision is always conserved for both elastic and inelastic collision.

\(m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\ \ (elastic)\\\\m_1 u_1 + m_2 u_2 = v(m_1 + m_2 ) \ (inelastic)\)

The total kinetic energy of the system is conserved for perfectly elastic collision BUT not conserved for inelastic collision.

The center mass of the system is always constant.

Thus, the position of the center of mass of the system remains constant during the experiment.

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Answer:

66

Explanation:

Answer:

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Explanation:

Volume of a Sphere

The volume of a sphere of radius r is given by:

\(\displaystyle V=\frac{4}{3}\cdot \pi\cdot r^3\)

The volume of each little sphere is:

\(\displaystyle V_l=\frac{4}{3}\cdot \pi\cdot 2^3\)

\(V_l=33.51\ mm^3\)

When the seven little spheres coalesce, they form a single bigger sphere of volume:

\(V_b=7*V_l=234.57\ mm^3\)

Knowing the volume, we can find the radius rb by solving the formula for r:

\(\displaystyle V_b=\frac{4}{3}\cdot \pi\cdot r_b^3\)

Multiplying by 3:

\(3V_b=4\cdot \pi\cdot r_b^3\)

Dividing by 4π:

\(\displaystyle \frac{3V_b}{4\cdot \pi}= r_b^3\)

Taking the cubic root:

\(\displaystyle r_b=\sqrt[3]{\frac{3V_b}{4\cdot \pi}}\)

Substituting:

\(\displaystyle r_b=\sqrt[3]{\frac{3*234.57}{4\cdot \pi}}\)

\(r_b=3.83\ mm\)

The surface area of the seven little spheres is:

\(A_l=7*(4\pi r^2)=7*(4\pi 2^2)=351.86\ mm^2\)

The surface area of the bigger sphere is:

\(A_b=4\pi r_b^2=4\pi (3.83)^2=184.33\ mm^2\)

The ratio between them is:

\(\displaystyle \frac{351.86\ mm^2}{184.33\ mm^2}=1.91\)

The total surface area of the seven little spheres is 1.91 times the total surface area of the bigger sphere.

Answer:

1) c.

2) a.)

Explanation:

1)

2)

       \(v = \lambda * f (1)\)

Answer:

Potential difference \(V=1.6\times 10^{-10}\ V\)

Explanation:

Capacitance of capacitor, C = 0.9 MF

Charge, \(Q=1.4\times 10^{-4}\ C\)

We need to find the amount of potential difference. We know that,

\(Q=CV\)

V is potential difference

So,

\(V=\dfrac{Q}{C}\\\\V=\dfrac{1.4\times 10^{-4}}{0.9\times 10^6}\\\\V=1.6\times 10^{-10}\ V\)

So, the required potential difference is \(1.6\times 10^{-10}\ V\).

Answer:

13 hz

Explanation:

Speed of sound = 1522

Dolphin swims off at 8.0 = Cs

Frequency of clicks = Fo = 2500

Fo = fs(c/c+cs)

2500 = fs(1522/1522+8)

2500 = fs(1522/1530)

2500 = 0.99477fs

Fs = 2500/0.99477

= 2513.1

From here, we find the difference between this frequency and the number of clicks per second

= 2513.1 - 2500

= 13.1 hz

Approximately 13 Hz

Answer:

0.5417

Explanation:

The frictional force is equal to the coefficient of kinetic friction times the normal force, so

Then, solving for the coefficient of kinetic friction, we get:

Now, we can replace the frictional force Ff by 65 N and the normal force Fn by 120 N

Therefore, the coefficient of kinetic friction is 0.5417

To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.

We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.

a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:

F1 = k x q¹ x q³/ r1²

F2 = k x q² x q³ / r2²

where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.

Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:

F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N

F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N

The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.

The net electric force on q3 is the vector sum of the forces due to q1 and q2:

Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N

The electric field at the location of q³ is then:

E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C

The negative sign of the electric field indicates that the field is directed towards q².

b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:

Fnet = ma

where m is the mass of q³ and a is its initial acceleration.

Substituting the given values, we get:

-3.6 N = (2.0 x 10⁻⁶ kg) x a

Solving for a, we get:

a = -1.8 x 10³ m/s²

The negative sign of the acceleration indicates that it is directed towards q².

c) The direction of the initial acceleration of q³ is towards q².

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The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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Answer:

static and current electricity

The velocity of the third piece 2/11. (13 j - 15i)

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The gauge pressure inside the bubble. is -101310.4 Pa.

The negative sign shows  that the pressure inside the bubble is lower than the atmospheric pressure. Hence, the bubble will rise to the surface of the water.

We apply Laplace's law to find the absolute pressure inside the bubble:

ΔP = 2γ/r

where ΔP is the pressure difference across the curved surface of the bubble, γ is the coefficient of surface tension of water, and r is the radius of curvature of the bubble.

r = 0.5 mm = 0.0005 m

Substituting the given values, we have:

ΔP = 2 × 0.073 N/m ÷ 0.0005 m

ΔP = 14.6 × 10^(-3) Pa

The atmospheric pressure at sea level is approximately 101325 Pa. Therefore, the gauge pressure inside the bubble is:

P_gauge = ΔP - P_atm

P_gauge = 14.6 × 10^(-3) Pa - 101325 Pa

P_gauge = -101310.4 Pa

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Answer:

5m

Explanation:

The area under the curve of velocity is the displacement. So From 0 to 5 there's a rectangle with height 1.

A parallel plate capacitor is connected to a battery that maintains a constant potential difference.

If the sepration between the plates is doubled. The electrical energy stored on the capacitor change. It will be cut in half.

If the battery remains connected, the potential difference between the plates remains constant.

In this case the energy is inversely proportional to the separation between the plates.

Hence, if the distance between the plates is doubled enrgy becomes halved.

Thus, the given option (3) is correct.

The x-component of the net external force F→ is 41.299 N to the right,

The y-component of the net external force F→ is -17.965 N downward.

External forces are described as those forces caused by external agent outside of the system.

F_left_y = F_left * cos(20.0°) = 60.0 N * cos(20.0°) = 56.310 N (upward)

F_left_x = F_left * sin(70.0°) = 60.0 N * sin(70.0°) = 55.184 N (to the right)

F_drag_y = F_drag * sin(70.0°) = 15.0 N * sin(70.0°) = 14.275 N (upward)

F_drag_x = F_drag * cos(20.0°) = 15.0 N * cos(20.0°) = 13.885 N (to the left)

Adding  up the x- and y-components of all the forces, we have :

F_net_y = F_left_y - F_drag_y - 60.0 N = 56.310 N - 14.275 N - 60.0 N

= -17.965 N (which is downward)

F_net_x = F_left_x - F_drag_x = 55.184 N - 13.885 N = 41.299 N (that goes to the right)

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Answer:

the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

Explanation:

A)

If we have two circular plate supported by a cable at a fixed distance, then the electric field formed between the two plate of the capacitor can be represented by the equation.

\(\mathbf{E = \frac{voltage \ \ V}{distance \ \ d}}\)

However; the net electric field i.e the sum of the electric filed produced is represented as:

\(\mathbf{E' = \frac{E}{2}} \\ \\ \mathbf{E' = \frac{V}{2d}}\)

So, if we assume that the lower plate and the upper plate possess the charge +q and -q respectively. Then, the tension of the cable which is the same as Force F can be written as:

\(\mathbf{F = q* E'}\)

\(\mathbf{F = \frac{q*v}{2d}}\) -----    equation (1)

Also ; we know that

\(\mathbf{C = \frac{q}{v}= \frac{E_oA}{d}}\)

\(\mathbf{\frac{q}{v}= \frac{E_o \pi r^2}{d}} \ \ \ \ \ \mathbf{since \ A = \pi r^2}\)

\(\mathbf{{q}= \frac{\pi E_o {v} r^2}{d}}\)    -----   equation (2)

Replacing equation 3 into equation (2); we have:

\(\mathbf{F = \frac{\pi E_o vr^2}{d}* \frac{v}{2d}}\)

\(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

Therefore,  the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

B)

Assume that the upper plate is displaced by dz in an upward direction ; Then we can express the workdone by the tension as :

\(\mathbf{dW = T *dz} \\ \\ \mathbf{dW = F*dz} \\ \\ \mathbf{dW = \frac{\pi E_o v^2r^2}{2z^2}dz }\)

The net workdone to raise the plate from separation d to 2d is:

\(\mathbf{W = \int\limits^{2d}_{2zd} {dw} = \frac{\pi E_ov^2r^2}{2} \int\limits^{2d}_d \frac{dz}{z^2} }\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{2} [-\frac{1}{z}]^{2d}_d }\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{1}{2d}-\frac{1}{d}]}\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{-1}{2d}]}\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

C) To calculate the energy stored in the Electrical energy Capacitor before the top plate is raised ; we have:

\(\mathbf{U_i = \frac{1}{2}Cv^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_oA}{d})v^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_o \pi r^2}{d})v^2} \\ \\ \mathbf{U_i = \frac{E_o \pi r^2 v^2}{2d}} }\)

D) The energy stored in the plate after the  the top plate was raised is as follows:  

\(\mathbf{U_f = \frac{1}{2}C'v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_oA}{2d})v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_o \pi r^2}{2d})v^2} \\ \\ \mathbf{U_f = \frac{E_o \pi r^2 v^2}{4d}} }\)

E) Yes,  work done by the cable equal to the change in the stored electrical energy. The Difference in energy stored before and after the top plate is raised:

\(\mathbf{U_i-U_f} = \mathbf{\frac{E_o \pi r^2 v^2}{2d}} }} - \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

\(\mathbf{U_i-U_f}= \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

Thus;

b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates.