Ill give brainliest! Sorry its sideways.​

Answer:

19 students per teacher and 10 students per tutor

Step-by-step explanation:

To find the amount of students per teacher and per tutor you have to divide

95 students /5 teachers

19 students per teacher

40 students /4 tutors

10 studetns pet tutor

Answer:

(2/2)*(2/2)=1

(2/2)+(2/2)=2

(2*2)-(2/2)=3

2*2*2/2=4, or 2+2+2-2=4

I hope this helps!

The correct option is option a) Yes, this is plausible for the population mean because the upper boundary of the 95% confidence interval is below 7 minutes.

A confidence interval is a range of values, derived from a sample of data, that is used to estimate an unknown population parameter. The interval has an associated confidence level, such as 90%, 95%, or 99%, which indicates the level of confidence that the interval contains the true population parameter.

The most commonly used method to calculate a confidence interval is the method of maximum likelihood estimation. The wider the interval, the less certain the estimate, and the narrower the interval, the more certain the estimate.

It is plausible that the true mean number of times for all mice to complete the maze may be less than 7 minutes, as the interval provided by the researcher (2.9 minutes to 6.83 minutes) does not include 7 minutes as an upper bound.

A 95% confidence interval indicates that if the study were to be repeated multiple times, 95% of the intervals created would contain the true mean, so there is a 5% chance that the true mean falls outside of the interval provided.

Therefore, The correct option is option a) Yes, this is plausible for the population mean because the upper boundary of the 95% confidence interval is below 7 minutes.

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Answer:Yes, this is plausible for the population mean because the upper boundary of the 95% confidence interval is below 7 minutes

Step-by-step explanation:

i took the quiz

\(\\ \sf\longmapsto f(x-1)=2x+3\)

How?

\(\\ \sf\Rrightarrow f(-3)=f(-2-1)\)

Let's find x then

\(\\ \sf\Rrightarrow x-1=-3\)

\(\\ \sf\Rrightarrow x=-3+1\)

\(\\ \sf\Rrightarrow x=-2\)

\(\\ \sf\longmapsto f(-2-1)=2(-2)+3\)

\(\\ \sf\longmapsto f(-3)=-4+3\)

\(\\ \sf\longmapsto f(-3)=-1\)

Answer:

9.42 ft

Step-by-step explanation:

We know the diameter is equal to 1.5 ft.

The equation for circumference is \(2\)πr.

Let's insert the numbers we already have.

2(3.14)(1.5)

= 9.42 ft

There are a total of 126 ways to distribute the 10 identical candies among the 5 distinct kids.

A combination is also called a selection. A combination corresponds to a selection of things from a given set of things. It is Denoted by

ⁿCᵣ = n!/r!(n-r)!

the number of unique r selections fromaset of n objects.

We have given that,

Total number of candies for distribution = 10

number of kids who take the candies = 5

Candies are distributed among the kids such that each kid has atleast one candy.

Here, candies are identical and kids are distinct.

Number of ways in which 10 identical candies can be divided among 5 kids if each kid must get at least one candy. The problem can be solved using the combination formula with

n = 5, k = 10.

= ⁽ᵏ⁻¹⁾Cₙ₋₁· = ⁹C₄ = 126 ways to do this.

So, there are 126 ways to distribute the candies among the five kids.

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The average number of viewers over the two weeks is  4. 85  x 10^5. Option D

Average is simply a number taken as the representative of a list of numbers.

It is determined by taking the sum of the numbers divided by the number of listed numbers.

Given the number of viewers as;

5.6 x 105 viewers  and 4.1 x 105 viewers

Average = 5. 6 x 10^5 + 4.1 x 10^5 / 2

Average = 9. 7  x 10^5 / 2

Average = 4. 85  x 10^5

The average number of viewers over the two weeks is  4. 85  x 10^5

Thus, the average number of viewers over the two weeks is  4. 85  x 10^5. Option D

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The integer would be -250, since it is a decrease.

a. Integral of xe^-x dxWe can solve the integral of xe^-x dx by using the integration by parts method.

Integration by parts is the method of integration that is used for the product of two functions such as \(udv = uv - vdu.\)

The integrals of the functions u and v can be differentiated and integrated, respectively. As a result, we have a formula for evaluating integrals of products.

Using the above formula, we can write the integral of xe^-x as: ∫xe^-x dx = -xe^-x - ∫(-e^-x) dx=-xe^-x + e^-x + C, where C is the constant of integration.

b. \(Integral of sinx cos^5xdx\)\(We can solve the integral of sinx cos^5xdx\)by using integration by substitution method.

Integration by substitution is a method of integration that is used when we have to replace a function with another, for example, when we have a function u that is part of a larger function g(u).

\(Using the above formula, we can write the integral of sinx cos^5xdx as:-∫cos^5x d(cosx)/6=-1/6 * (cos^6x / 6) + C, where C is the constant of integration.c.\)

\(Integral of (2x+4)/(x^3-2x^2) dx\)\(To solve the integral of (2x+4)/(x^3-2x^2) dx,\) we can use partial fraction method.Partial fraction is the method that is used to split a rational function into simpler components that can be easily integrated by using standard integration formulas.

Using the above formula, we can write the integral of \((2x+4)/(x^3-2x^2) dx as:∫[(2x+4)/(x^3-2x^2)]dx = ∫[1/x^2]dx + ∫[1/(x-2)]dx + ∫[-1/x]dx= -1/x + ln|x-2| - 1/x^2 + C,\) where C is the constant of integration.

d. \(Integral of ∫dx / x^2√4-x^2 dx\)We can solve the integral of \(∫dx / x^2√4-x^2 dx\)by using the trigonometric substitution method.

Trigonometric substitution is a method of integration that is used when we have an expression of the form √a^2-x^2 and we replace x with a sin θ or x = a cos θ, respectively.

\(Using the above formula, we can write the integral of ∫dx / x^2√4-x^2 dx as:-∫secθ dθ = ln|secθ + tanθ| + C= ln|x/√4-x^2| + C, where C is the constant of integration.\)

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The number of $1, $5 and $10 are 49, 44 and 22 respectively.

There are 3 denominations of bills in a wallet: $1, $5, and $10.

There are 5 fewer $5-bills than $1-bills.

let

x = number of $1 bills

Hence,

number of $5 bills = x - 5

There are half as many $10-bills as $5-bills.

number of $10 bills = 1 / 2 (x - 5)

Therefore,

x + x - 5 + 1 / 2 (x - 5) = 115

2x - 5  + 1 / 2 x - 5 / 2 = 115

2x + 1 / 2 x - 5 - 5 / 2 = 115

5 / 2 x  - 7.5 = 115

2.5x  = 115 + 7.5

x = 122.5 / 2.5

x = 49

Number of $1 bills = 49

Number of $5 bills = 49 - 5 = 44

Number of $10 bills = 1 / 2 (49 - 5) = 22

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Answer:

-3.6

Step-by-step explanation:

The general equation of a straight line formula is represented as y = mx + c, where m is the gradient or slope of the line and c is called the intercept on the y-axis.

The equation of the line in the question above is y= −3.6x + 59 ,

Therefore comparing both equations together,

y = mx + c = y = −3.6x + 59

m = -3.6

Therefore, the slope of the equation represent in this scenario is -3.6

Answer:

the flag of miscronesia represent:

Step-by-step explanation:

the light blue field represents the Pacific Ocean whereas the four stars represent the states in the federation.

The correct expression which can be used to find AC is,

⇒ 7.8 (cos 23°)

We have to given that;

A triangle ABC shown in figure.

Now, We can formulate;

cos 23° = AC / AB

cos 23° = AC / 7.8

AC = 7.8 (cos 23°)

Thus, The correct expression which can be used to find AC is,

⇒ 7.8 (cos 23°)

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f(n) = ϴ(g(n)) is not true in cases B(sqrt(n)log(n), C(\(3^n 5^n\)), and D(sin(n)+3 cos(n)+1).

A) \(log(n^200) log(n^2)\)

Here, f(n) = \(log(n^200)\) and g(n) = \(log(n^2)\). Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = \([log(n^200) / log(n^2)]\) = 100

This means that as n approaches infinity, the ratio f(n) / g(n) is constant, and so we can say that f(n) = ϴ(g(n)). Therefore, f(n) = ϴ(g(n)) is true in this case.

B) sqrt(n) log(n) Here, f(n) = sqrt(n) and g(n) = log(n). Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = [sqrt(n) / log(n)]

As log(n) grows much slower than sqrt(n) as n approaches infinity, this limit approaches infinity. Therefore, we cannot say that f(n) = ϴ(g(n)) is true in this case.

C) 3^n 5^n

Here, f(n) = \(3^n\) and g(n) = \(5^n\) . Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = \([3^n / 5^n]\)

As \(3^n\) grows much slower than \(5^n\) as n approaches infinity, this limit approaches zero. Therefore, we cannot say that f(n) = ϴ(g(n)) is true in this case.

D) sin(n) + 3 cos(n) + 1

Here, f(n) = sin(n) + 3 and g(n) = cos(n) + 1. Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = [sin(n) + 3] / [cos(n) + 1]

As this limit oscillates between positive and negative infinity as n approaches infinity, we cannot say that f(n) = ϴ(g(n)) is true in this case.

Therefore, f(n) = ϴ(g(n)) is not true in cases B, C, and D.

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The vertex form which is equivalent to the provided quadratic function of variable x is (x-1)²+3.

Vertex form of parabola is the equation form of quadratic equation, which is used to find the coordinate of vertex points at which the parabola crosses its symmetry.

The standard equation of the vertex form of parabola is given as,

\(y=a(x-h)^2+k\)

Here, (h, k) is the vertex point.

The function given in the problem is,

\(f(x) = 4+x^2 - 2x\\f(x) = x^2 - 2x+4\)

Add and subtract (-1)² in the above function,

\(f(x) = x^2 - 2x+4+(-1)^2-(-1)^2\\f(x) = x^2 - 2x+(-1)^2+4-1\)

Use the formula of whole square,

\(f(x)=(x-1)^2+3\)

This is the required vertex form.

Hence, the vertex form which is equivalent to the provided quadratic function is (x-1)²+3.

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if I did it right then it's $32.38.

The graph of inequality x < −2 is as shown below.

In this question we need to graph x is less than or equal to negative 2.

i.e., we need to graph an inequality x < −2

First we draw a straight vertical line x = -2.

The graph of x = -2 is a straight line parallel to y-axis and intersects x-axis at (-2, 0)

We represent the graph of x = −2 by the dashed line.

The dashed line indicates that the line is the boundary of the inequality but not part of it. Shade in the left side of the line to indicate the inequality x<−2.

Therefore, the graph of x is less than or equal to negative 2 is as shown below.

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Answer:

2. 7 + 4

3. 21 - 27

4. 8 - 28

Step-by-step explanation:

2. 1 (7+4) = 1×7 + 1×4 = 7 + 4

3. 3 (7-9) = 3×7 - 3×9 = 21 - 27

4. 4 (2-7) = 4×2 - 4×7 = 8 - 28

hope this helps :)

Answer:

1. the answer is 7+4

2. the answer is 21-9.

3. the answer is 8-7.

Hope this helps, have a great day/night, and stay safe!

Answer:

\(x + 2x = 120 \\ 3x = 120 \\ x = 40 \\ a = 2x = 80\)

In hypothesis testing, data miners develop a model prior to the analysis and apply statistical techniques to data to estimate the parameters of the model.

In hypothesis testing, data miners formulate a hypothesis or a model about a population parameter based on prior knowledge or assumptions. This model specifies the relationship between variables and the expected values of the parameters. The next step is to collect data and analyze it using statistical techniques to estimate the parameters of the model.

The estimation of parameters involves using the available data to make inferences about the unknown population parameters. This can be done using various statistical methods such as maximum likelihood estimation, least squares estimation, or Bayesian estimation. These techniques aim to find the best estimates of the parameters that are consistent with the observed data and the assumptions of the model.

Once the parameters are estimated, data miners can then evaluate the goodness of fit of the model and draw conclusions about the population based on the estimated parameters. This process allows for hypothesis testing and making inferences about the population based on the sample data and the estimated parameters of the model.

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Answer:

V = s³

Step-by-step explanation:

You multiply all sides together (L×W×H)

Answer:

After 10 months, both salespersons will sell 160 cars.

Step-by-step explanation:

We are given two different salesperson's statistics of sales. We can use this information to set up a system of equations and solve for our variable.

Let us name the first salesperson Person 1 and the other salesperson Person 2.

Now, for Person 2:

Now, because we have these equations, we can set up a table that will determine the number of months that will elapse before the salespersons will sell the same amount of cars.

For Person 1, the equation will be the increase of the y-value by 13 cars after an initial sale of 30 vehicles. Therefore, we can create a table of values.

\(\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 30 \\ \cline{1-2} 1 & 43 \\ \cline{1-2} 2 & 56 \\ \cline{1-2} 3 & 69 \\ \cline{1-2} 4 & 82 \\ \cline{1-2} 5 & 95 \\ \cline{1-2} 6 & 108 \\ \cline{1-2} 7 & 121 \\ \cline{1-2} 8 & 134 \\ \cline{1-2} 9 & 147 \\ \cline{1-2} 10 & 160 \\ \cline{1-2} \end{array}\)

For Person 2, we can use the same formatting to create a table. However, the rule changes - we must start at 50 cars being sold and increase it by only 11 cars a month.

\(\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 50 \\ \cline{1-2} 1 & 61 \\ \cline{1-2} 2 & 72 \\ \cline{1-2} 3 & 83 \\ \cline{1-2} 4 & 94 \\ \cline{1-2} 5 & 105 \\ \cline{1-2} 6 & 116 \\ \cline{1-2} 7 & 127 \\ \cline{1-2} 8 & 138 \\ \cline{1-2} 9 & 149 \\ \cline{1-2} 10 & 160 \\ \cline{1-2} \end{array}\)

Now, we need to see where the y-values are the same in both tables. We can see that we have a value of (10, 160) in both tables, so after 10 months, the salespersons will sell the same amount of cars.

There is an alternative method of solving the problem that is much quicker and will require much less work.

We are given two equations that are both equal to y. Therefore, we can set them equal to each other (dropping the y) and solving for x.

Our value of x will be the amount of months in which the sales are equal.

\(\displaystyle{13x+30=11x+50}\\\\2x + 30 = 50\\\\2x = 20\\\\\boxed{x = 10}\)

Therefore, after 10 months of sales, the salespersons will have sold the same amount of cars. We can plug this information into one of the equations to see how many cars will be sold at that point.

\(y = 13(10) + 30\\\\y = 130 + 30 \\\\y = 160\)

In 10 months, 160 cars will be sold. If we set the equations equal to each other and substitute x, we should get a true statement.

\(13(10)+30=11(10)+50\\\\130 + 30 = 110 + 50\\\\160 = 160\)

Because we get a true statement, each salesperson will sell 160 cars after 10 months of initial sales.

9514 1404 393

Answer:

  all real numbers

Step-by-step explanation:

Basically, you look for any values of x for which the function is not defined. There are none. So, the domain is "all real numbers."

__

The function is the product of a polynomial (x) and an exponential function (e^x). Each of those kinds of functions has a domain of "all real numbers". Multiplication is also defined for all real numbers, so there is nothing about this product that would restrict the domain.

Logarithm (a) log2(64) = 6

The definition of a logarithm states that for any base "b" and a positive number "x", if bx = y, then logb(y) = x. In other words, the logarithm tells us the exponent to which the base must be raised to obtain a given number.

In this case, we are asked to find log2(64), which means we need to determine the exponent to which 2 must be raised to obtain 64.

To find this exponent, we can think of 2^6 = 64. This means that log2(64) = 6, since the exponent 6 is required to get 64 as the result when 2 is raised to that power.

Therefore, log2(64) = 6.

Using the definition of logarithm, we can find the exponent needed to obtain a given number when raised to a certain base. In this case, applying the definition of logarithm allows us to determine that log2(64) is equal to 6, indicating that 2 must be raised to the power of 6 to yield 64.

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The difference between exponential and quadratic function is variable exponent and base, shape of graph, y-intercept and rate of change of function of both.

The most basic difference evident in the equation is exponential function has variable exponent while quadratic function has base as variable. In this equation, the variable exponent is x written as power 1.03. The quadratic function has base x written with exponent 2. The exponential and quadratic function differ in exponential and parabolic growth.

Also, the rate of change in exponential function will increase with x. The quadratic function will alter according to the value x. The y-intercept is 2 for stated exponential function and 0 for given quadratic function f(x) = 2x².

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