ILL GIVE BRAINIEST TO WHO EVER IS CORRECT!! PLEASE HELP ASAP!!
Write an equation of a line in standard form that passes through points A(-3,4) and B(1,-2)

The 90% confidence interval for the population mean, the correct option is 2.81, 15.49.

Given that: A = (18.68, 17.24, 20.23), B = (10.27, 8.65, 7.79).

The population mean of paired observations, mu_d is given by

μd=μA−μB

Where, μA is the mean of observations in A and μB is the mean of observations in B.

Substituting the given values,

μd=19.05−8.57=10.48

To calculate the 90% confidence interval for the population mean mu_d, we use the following formula:

CI=¯d±tα/2*sd/√n

Where, ¯d is the sample mean of the paired differences,

tα/2 is the critical value of t for the given level of significance (α) and degrees of freedom (n-1),

sd is the standard deviation of the paired differences and

n is the sample size of the paired differences.

The sample mean of the paired differences, ¯d is given by:¯d=∑di/n

Where, di = Ai - Bi

Let us calculate di for each pair of observations:

d1 = 18.68 - 10.27 = 8.41d2 = 17.24 - 8.65 = 8.59d3 = 20.23 - 7.79 = 12.44

Therefore, the sample mean of the paired differences is:

¯d = (d1 + d2 + d3)/3 = (8.41 + 8.59 + 12.44)/3 = 9.15

The standard deviation of the paired differences is given by:

sd=∑(d−¯d)^2/n−1

Substituting the values, we get:

sd = √[((8.41 - 9.15)^2 + (8.59 - 9.15)^2 + (12.44 - 9.15)^2)/2] ≈ 3.38

Using a t-table with n - 1 = 2 degrees of freedom and a level of significance of 0.10 (90% confidence interval), we get a critical value of tα/2 = 2.920.

Therefore, the 90% confidence interval for the population mean mu_d is:

CI = 9.15 ± 2.920(3.38/√3) ≈ (2.81, 15.49)

Hence, the correct option is 2.81, 15.49.

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Answer:

mueva la variable al lado izquierdo y cambie su signo, (5 + 2x-5x = -7)

Reúna términos semejantes (-3x = -7-5), luego divida ambos lados de la ecuación por -3

Entonces obtienes x = 4

In english:

Answer: x=4

move the variable to the left side and change its sign, (5 + 2x-5x = -7)

Collect like terms (-3x = -7-5), then divide both sides of the equation by -3

So you get x = 4

The graph of the function f(x)=3(2)^x -4 passes through the points (0,-1), (1,2), (2,8) and (3,20)

When the expression of function is such that it involves the input to be present as exponent (power) of some constant, then such function is called exponential function.

here usual form is specified below. They are written in several such equivalent forms.

The equation of the function is given as:

\(f(x)=3(2)^x -4\)

Set x = 0, 1, 2 and 3

\(f(0)=3(2)^0 -4 = -1\\f(1) = 3(2)^1 - 4 = 2\\f(2) = 3(2)^2- 4 = 8\\\\f(3) = 3(2)^3 - 4 = 20\)

This means that the graph of the function f(x) = 3(2)^x -4 passes through the points (0,-1), (1,2), (2,8) and (3,20).

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Answer: 21

Step-by-step explanation: Evaluate the first expression which is the cube root of 216. 6^3 equals 216 so the cube root of it is equal to six. Multiply it by 4 because thats what's its there for and you get 24. Subtract by 3 to get the final answer, 21.

Answer:

1

Step-by-step explanation:

Is the correct way to do it

Answer:

d.y=x/3+4

Step-by-step explanation:

we have

slope=(y-b)÷(x-a)

1/3=(y-2)÷(x--6)

(x+6)=3(y-2)

x+6=3y-6

x+6+6=3y

(x+12)÷3=y

y=x/3+4

The population of Cityville in 2020 will be 60000, if the population increases exponentially.

According to the given question.

The population of Cityville in 1990 was 7500.

Population of Cityville in 2000 was 15000.

And the population of cityville in 2010 was 30000.

Also, the population of Cityville increasing exponentially.

So, let the function which represents the Population of Cityville increasing exponentially be \(P = P_{o} b^{x}\)

Where, P be the final population of Cityville in x years.

b be the growth factor

And, \(P_{o}\) be the intial population.

So, according to the given condition.

Population in 1990 and 2000

\(15000= 7500(b)^{10}\)

⇒ \(b^{10} = 2\)

Therefore, the population in 2020 is given by

\(P = 30000(b)^{10}\)

⇒ P = 30000(2)      (because b^10 = 2)

⇒ P = 60000

Hence, the population of Cityville in 2020 will be 60000, if the population increases exponentially.

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To determine the coordinates of the vertices of the reflected figure, we can use a reflection matrix that represents reflection over the x-axis. The reflection matrix is:

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix} \\\)

Let's apply this reflection matrix to each vertex of the triangle RST to find the coordinates of the reflected vertices:

For vertex R(-3, 7):

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix} \begin{bmatrix} -3 \\ 7 \\ \end{bmatrix} = \begin{bmatrix} -3 \\ -7 \\ \end{bmatrix} \\\)

So the reflected coordinates for vertex R are (-3, -7).

For vertex S(5, 3):

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix} \begin{bmatrix} 5 \\ 3 \\ \end{bmatrix} = \begin{bmatrix} 5 \\ -3 \\ \end{bmatrix} \\\)

So the reflected coordinates for vertex S are (5, -3).

For vertex T(6, -5):

\(\sf\:\begin{bmatrix} 1 & 0 \\ 0 & -1 \\ \end{bmatrix}\begin{bmatrix} 6 \\ -5 \\ \end{bmatrix} = \begin{bmatrix} 6 \\ 5 \\ \end{bmatrix} \\\)

So the reflected coordinates for vertex T are (6, 5).

Now, let's graph the pre-image (triangle RST) and the image (reflected triangle) on the same coordinate grid:

Pre-image (Triangle RST):

Image (Reflected Triangle):

You can plot these points on a coordinate grid and connect them to form the triangles.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

False. The weight of a variable in a standardized predictor environment does not necessarily indicate that the variable has a higher discriminating power.

Discriminating power is determined by the correlation of a predictor variable with the outcome variable. We can calculate the correlation between a predictor variable and an outcome variable using Pearson's correlation coefficient, which is represented by the formula:

r = (NΣXY - (ΣX)(ΣY)) / √[(NΣX2 - (ΣX)2)(NΣY2 - (ΣY)2)].

In this formula, N is the sample size, ΣX is the sum of the predictor variable, ΣY is the sum of the outcome variable, ΣXY is the sum of the products of the predictor and outcome variables, and ΣX2 and ΣY2 are the sums of the squares of the predictor and outcome variables, respectively. The Pearson's correlation coefficient ranges from -1 to +1, with +1 indicating perfect positive correlation, 0 indicating no correlation, and -1 indicating perfect negative correlation. A higher correlation coefficient indicates a higher discriminating power.

Therefore, the weight of a variable in a standardized predictor environment does not indicate whether or not the variable has a higher discriminating power; this is determined by the correlation between the predictor and outcome variables.

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Answer:

-2 or -14/7 (they're the same)

Step-by-step explanation:

I hope this helps!

Answer:

Step-by-step explanation:

-3 ²/₇ - ( - ⁵/₇)

- 23 / 7  + 5 / 7

_  23 + 5

       7

_ 18

    7

- 2 ⁴/₇  

Answer:

HL (Hypotenuse Leg)

Step-by-step explanation:

You have BC=CD (Because of reflexive property), AC=DC, and measure of BAC is equal to the measure of BDC, which is 90 degrees. Since these triangles are right and they have a hypotenuse and a leg congruent, you can say that they are congruent because of HL.

Answer:

B, C, and F

Step-by-step explanation:

y = 1/2x

y = 1/2(4)

y = 2

y = 1/2x

y = 1/2(-2)

y = -1

y = 1/2x

y = 1/2(2)

y = 1

The measure of the angle F is 33.69° to the nearest hundredth using the trigonometric ratio of tangent.

The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.

The basic trigonometric ratios includes;

sine, cosine and tangent.

tan x° = 4/ {opposite/adjacent}

tan x° = 2/3

x° = tan⁻¹(2/3) {cross multiplication}

x° = 33.6901°

Therefore, the measure of the angle F is 33.69° to the nearest hundredth using the trigonometric ratio of tangent.

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Step-by-step explanation:

remember, a probability is always the ratio of

desired cases / totally possible cases

it starts with all the combinations of 4 out of 12 (= 8 + 4) choices

C(12, 4) = 12! / (4! × (12-4)!) = 12! / (4! × 8!) =

= 12×11×10×9 / 24 = 11×5×9 = 495

these are our totally possible outcomes.

the desired outcomes with only 4 men in the selected group out of 12 people is the same amount as the possible selections of 4 men out of the available 8 men :

C(8, 4) = 8! / (4! × (8-4)!) = 8! / (4! × 4!) =

= 8×7×6×5 / 24 = 2×7×5 = 70

any other combination of C(12, 4) must contain at least 1 woman.

so the probability of getting 4 men out of the random pull is

70/495 = 0.1414141414...

we could get that also by saying the probability to get a man on the first pull is (12 people in total, 8 "desired" period with the right gender)

8/12 = 2/3 = 0.666666666...

now, we have 7 men out of 11 total people for the second pull. the probability here is

7/11 = 0.636363636...

then we have 6 men out of 10 total people for the third pull. the probability here is

6/10 = 3/5 = 0.6

and lastly, we have 5 men out of total 9 people for the fourth pull. the probability is

5/9 = 0.555555555...

the probability to get 4 men out of the random pulling is the combination of these 4 individual probabilities :

2/3 × 7/11 × 3/5 × 5/9 = 210 / 1485 = 70/495 =

= 0.1414141414...

it is confirmed.

Answer:

x=20

Step-by-step explanation:

Answer:

  102,476

Step-by-step explanation:

If a population grows linearly from 55556 in 2000 to 72760 in 2011, you want the predicted value in 2030 assuming growth continues to be linear.

The change in population is proportional to the change in years:

  (72760 -55556)/(2011 -2000) = (p -55556)/(2030 -2000)

  p = 30(17204)/11 +55556 . . . . . . solve for p

  p = 46920 +55556 = 102,476 . . . . . . do the arithmetic

The population in 2030 will be $102,476.

Using the distance formula, the length of bc is found to be 2a, while the length of de simplifies to a. Therefore, bc is twice de, proving that de is half the length of bc.


The distance formula calculates the distance between two points in a Cartesian coordinate system. By applying this formula to the points involved in the problem, we can determine the lengths of bc and de. Using the coordinates given, we find that the length of bc is equal to 2a.

By substituting the coordinates of points d and e into the distance formula, we find that the length of de simplifies to a. Comparing the two lengths, we see that bc is twice the length of de, demonstrating that de is half the length of bc. This proof relies on the properties of midpoints, which divide a line segment into two equal parts, leading to the proportional relationship between bc and de.

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Answer:

\(\large\boxed{\textsf{ t = 484.}}\)

Step-by-step explanation:

\(\textsf{We are asked to solve for the value of t. We should first begin with a review of}\)

\(\textsf{what the \underline{Properties of Equality} are.}\)

\(\large\underline{\textsf{What are Properties of Equality?}}\)

\(\textsf{Properties of Equality are properties that allows us to manipulate an equation}\)

\(\textsf{stating whenever a constant is added, removed, squared, square rooted... then}\)

\(\textsf{both expressions will still show equality to each other.}\)

\(\underline{\textsf{Example;}}\)

\(\textsf{The Addition Property of Equality. This Property states that whenever a constant,}\)

\(\textsf{or the same term is added to both sides of an equation, the equation remains}\)

\(\textsf{equal. Say we were given this equation;}\)

\(\tt a - 7 = 9\)

\(\textsf{We would use the Addition Property of Equality to isolate a.}\)

\(\textsf{This is done by adding 7 to both sides of the equation.}\)

\(\tt a \ -\not{7} + \not{7} = 9 + 7\)

\(\boxed{\tt a=16.}\)

\(\large\underline{\textsf{For Our Problem;}}\)

\(\textsf{We should use the Multiplication Property of Equality, which states that whenever}\)

\(\textsf{both sides of the equation are multiplied by a constant, then they are still equal.}\)

\(\textsf{Let's use the Multiplication Property of Equality to multiply both sides of the}\)

\(\textsf{equation by 11 in order to remove the fraction.}\)

\(\tt \frac{\not{11} \times t}{\not{11}} = 44 \times 11\)

\(\underline{\textsf{We are left with our final answer;}}\)

\(\large\boxed{\textsf{ t = 484.}}\)

Answer:

t = 484

Step-by-step explanation:

\(\frac{44}{1} = \frac{t}{11}\)

\(44*11 = 484\)

Hence,  t = 484

[RevyBreeze]

Answer:

Dependent

Step-by-step explanation:

Two events are said to be dependent when the outcome of the first event is  related to the other.

When two events, A and B are dependent, the probability of occurrence of A and B is:

P(A and B) = P(A) · P(B|A)

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Two events are dependent if the occurrence of one is related to the probability of the occurrence of the other.

If two events A and B depend on each other, then the probability  of A and B occurring is

P(A and B) = P(A)  P(B|A)

Two events are dependent if the occurrence of one is related to the probability of the occurrence of the other.

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a. The tree diagram that summarizes the given probabilities is attached.

b.  The probability that the individual does not participate in sports, given that he graduate sis  0.2 =  20%.

We apply Bayes' theorem to calculate:

Probability (Does not participate in sports if graduates)  = (P(Does not participate in sports) * P(Graduates | Does not participate in sports)) / P(Graduates)

The given data include: probability of not participating in sports = 0.02 probability of graduating given no participation in sports = 0.82 probability of graduating  = 0.18

Probability (Does not participate in sports if graduates)  = (0.02 * 0.82) / 0.18 = 0.036 / 0.18=  0.2

| Sports | No Sports |

                          |-------|--------|

Student participates | 0.18  | 0.62  |

                          |-------|--------|

Student does not participate | 0.02  | 0.78  |

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a. There are no real solutions to the equation. Therefore, there is no value of α for which P(-1 < X < 2) = 0.75.

b. The value of parameter α for  P(|X| < 1) = P(|X| > 2) is 4

a. We know that for a uniform distribution over (−α,α), the probability density function is given by f(x) = 1/(2α) for −α ≤ x ≤ α and zero otherwise. Thus, the probability of the event (-1 < X < 2) can be computed as:

P(-1 < X < 2) = ∫(-1)²/(2α) dx + ∫2²/(2α) dx

= (1/2α) ∫(-1)² dx + (1/2α) ∫2² dx

= (1/2α) [x]₋₁¹ + (1/2α) [x]²₂

= (1/2α) (2α - 1) + (1/2α) (4 - α²)

= (3 + α²)/(4α)

We want this probability to be 0.75. So, we solve the equation (3 + α²)/(4α) = 0.75 for α:

(3 + α²)/(4α) = 0.75

=> 3 + α² = 3α

=> α² - 3α + 3 = 0

This is a quadratic equation in α with discriminant:

Δ = b² - 4ac

= (-3)² - 4(1)(3)

= 9 - 12

= -3

Since Δ is negative, there are no real solutions to the equation. Therefore, there is no value of α for which P(-1 < X < 2) = 0.75.

b. The pdf of a uniform distribution is given by:

f(x) = 1/(b-a), for a ≤ x ≤ b

In this case, a = -α and b = α. Therefore,

f(x) = 1/(2α), for -α ≤ x ≤ α

Now we can calculate the probabilities as follows:

P(|X| < 1) = P(-1 < X < 1) = ∫(-1 to 1) f(x) dx = ∫(-1 to 1) 1/(2α) dx = 1/(2α) * [x]_(-1 to 1) = 1/α

P(|X| > 2) = P(X < -2 or X > 2) = P(X > 2) + P(X < -2) = ∫(2 to α) f(x) dx + ∫(-α to -2) f(x) dx = ∫(2 to α) 1/(2α) dx + ∫(-α to -2) 1/(2α) dx = 1/4

Therefore, we need to find α such that P(|X| < 1) = P(|X| > 2) = 1/4.

From P(|X| < 1) = 1/α, we get α = 1/P(|X| < 1) = 1/(1/4) = 4.

From P(|X| > 2) = 1/4, we get the same value of α = 4.

Hence, α = 4 satisfies both conditions.

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Step-by-step explanation:

Factoring using the quadratic form involves using the quadratic formula to find the two values that, when multiplied together, give the original quadratic equation. The quadratic formula is as follows:

x = (-b ± √(b^2 - 4ac)) / 2a

To use the quadratic formula to factor a quadratic equation, first rewrite the equation in the form of ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable. Then, plug the values of a, b, and c into the quadratic formula to solve for x. The two values of x that you find are the factors of the original quadratic equation.

Here's an example:

Suppose you want to factor the quadratic equation 2x^2 + 7x + 3 = 0. In this case, a is 2, b is 7, and c is 3. Plugging these values into the quadratic formula, we get:

x = (-7 ± √(7^2 - 4 * 2 * 3)) / 2 * 2

Solving this equation, we get x = (-7 ± √(49 - 24)) / 4, which simplifies to x = (-7 ± √(25)) / 4. Since the square root of 25 is 5, we can further simplify this to x = (-7 ± 5) / 4, which gives us the solutions x = -1 and x = -3/2.

Therefore, the two factors of the original equation 2x^2 + 7x + 3 = 0 are x + 1 and x + 3/2.

Answer:

B

Step-by-step explanation:

B is the right answer

The required equation is \(x^2y^4 + 4x^3y^3 - 4x^2y^2 - 12x^2y\) + 25 = 0

The direction of fastest change of a function at a point is given by the gradient of the function at that point. Therefore, to find the points at which the direction of fastest change of the function f(x, y) = \(x^2 y^2\) − 6x − 8y is in the direction of the vector i j, we need to find the gradient of f(x, y) and then find the points where the gradient is parallel to the vector i j.

The gradient of f(x, y) is given by:

∇f(x, y) = <∂f/∂x, ∂f/∂y> =\(< 2xy^2 - 6, 2x^2y - 8 >\)

To find the points at which the direction of fastest change is in the direction of i j, we need to find the points where the gradient is parallel to i j. This means that the dot product of the gradient and i j should be equal to the product of their magnitudes:

∇f(x, y) · i j = ||∇f(x, y)|| ||i j||

Substituting the values, we get:

\((2xy^2 - 6, 2x^2y - 8)\)· (1, 0) = sqrt((\(2xy^2 - 6)^2 + (2x^2y - 8)^2\)) * sqrt(\(1^2 + 0^2\))

Simplifying this equation, we get:

\(2xy^2\)- 6 = sqrt((\(2xy^2 - 6)^2\) + (\(2x^2y - 8)^2\))

Squaring both sides and simplifying, we get:

\(x^2y^4 + 4x^3y^3 - 4x^2y^2 - 12x^2y + 25 = 0\)

Therefore, the points at which the direction of fastest change of f(x, y) is in the direction of i j are given by the solution of the quartic equation above.

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Thus, the test for homogeneity follows the same procedures as the test for independence because the assumptions for performing the chi-square test for independence and chi-square test for homogeneity are the same.

The procedures for the chi-square test of homogeneity are the same as for the chi-square test of independence. The data is different for both tests. Tests of independence are used to determine whether there is a significant relationship between two categorical variables from the same population. One population is segmented based on the value of two variables. So there will be a column variable and a row variable.

The chi-square test of homogeneity of proportions can be used to compare population proportions from two or more independent samples, determining whether the frequency counts are distributed identically among different populations.

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Step-by-step explanation:

The GCF of these numbers is 3 i did found it by prime Factorization 12 prime Factorization is 3x2x2 and for 12 is 3x3x3 so 3 it is the same of both so us it and bye have a good day

Answer:

Since u got this answer could u mark me and thank you

Step-by-step explanation:

A function assigns the values. The value of f(1.6) and f(-3.3) is -2.2 and -16.9, respectively.

A function assigns the value of each element of one set to the other specific element of another set.

Given the function f(x) = 3(x-3) + 2, now to know the value of f(1.6) and f(-3.3), subtitute the value of x as 1.6 and -3.3, respectively.

f(x) = 3(x-3) + 2

f(1.6) = 3(x-3) + 2

        = 3(1.6 - 3) + 2

        = 3(-1.4) + 2

        = -2.2

f(-3.3) = 3(x-3) + 2

          = 3(-3.3 - 3) + 2

          = 3(-6.3) + 2

          = -18.9 + 2

          = -16.9

Hence, the value of f(1.6) and f(-3.3) is -2.2 and -16.9, respectively.

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Answer:

x = 15

Step-by-step explanation:

12x + 7 = -8 + 13x

15 = x