(iii) if a curve with a radius of 95 m is properly banked for a car traveling 65 km/h, what must be the coefficient of static friction for a car not to skid when traveling at 95 km/h?

Answers

Answer 1

The coefficient of static friction for a car not to skid when traveling at 95 km/h is 1.28.

To calculate the coefficient of static friction needed for a car not to skid when traveling at 95 km/h on a banked curve with a radius of 95 m, we can use the equation:

μ = tan(θ)

Where μ is the coefficient of static friction, and θ is the angle of banking. At the maximum speed of 65 km/h, the car will travel at the same speed as the curve is banked, and thus the angle of banking will be given by:

θ = arctan(v² / rg)

θ = arctan[(65 km/h)² / (95 m x 9.81 m/s²)]

θ = 24.5°

At 95 km/h, the angle of banking required for the car not to skid can be calculated as:

θ = arctan(v² / rg)

θ = arctan[(95 km/h)^2 / (95 m x 9.81 m/s^2)]

θ = 45.6°

Therefore, the coefficient of static friction needed for the car, not to skid can be calculated as:

μ = tan(θ)

μ = tan(45.6°)

μ = 1.28

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Related Questions

PLEASE HELP! FOR BRAINLIEST!

PLEASE HELP! FOR BRAINLIEST!

Answers

Answer:

i read the whole thing the answer that matches the most is C

hope this helped :D

Explanation:

If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.8 ss , how far do you travel during this inattentive period

Answers

Answer:

Distance = 70 meters

Explanation:

Given the following data;

Speed = 90 km/h

Time = 2.8 seconds

Conversion:

90 km/h to meters per seconds = 90 * 1000/3600 = 90000/3600 = 25 m/s

To find the distance covered during this inattentive period;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

\(Speed = \frac{distance}{time}\)

Making distance the subject of formula, we have;

\( Distance = speed * time \)

Substituting into the above formula, we have;

\( Distance = 25 * 2.8 \)

Distance = 70 meters

can someone please answer these in the next 20 minutes. ill give you a brainiest. thanks! :)

can someone please answer these in the next 20 minutes. ill give you a brainiest. thanks! :)

Answers

Answer:

1. 2380m

2. 13.6m

3. 132 Hz

What is the origin of all stars?

supernova
dwarfs
protostars
nebulae

Answers

Answer:

Protostars

Explanation:

Calculate the potential at the centre of a square of side √4.5 m which carries at its
four corners and charges of + 5 x 10° C, 2 x 10°C, -5 x 10° C and - 7 x 10°C
respectively

Answers

Thus, the total potential is then V_total = \(-1.2 * 10^9V\)


How to solve

The potential at a point due to a charge is given by V = kQ/r, where k is Coulomb's constant (~\(9x10^9 Nm^2/C^2\)), Q is the charge, and r is the distance from the charge.

The total potential at the center of the square is the sum of the potentials due to each charge.

The distance of each charge to the center is half the diagonal of the square, which is \(\sqrt2 * side/2 = \sqrt2 * \sqrt4.5/2 = 1.5m.\)

The total potential is then V_total

= \(k * [(510^8/1.5) + (210^8/1.5) - (510^8/1.5) - (710^8/1.5)] = -2 * k * 10^8 / 1.5 \\= -1.2 x 10^9 V.\)

Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

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An aircraft executes a horizontal loop of radius 1.00 km with a steady speed of 900 km/h.Compare it's centripetal acceleration with the acceleration due to gravity.​

Answers

Answer:

900 km/hr = 9E5 m / 3600 sec = 250 m/sec

ah = v^2 / R = 250^2 m/s / 1000 m = 62.5 m/s^2   horizontal acceleration

av = 9.8 m/s^2      vertical acceleration (due to gravity)

ah / av = 62.5 / 9.8 = 6.38   centripetal acceleration is greater

Are you gay if you are why?

Answers

Answer:

Because of the chemical makeup of my DNA

Answer:

I'm not gay, but if you play xbox you are,

Explanation:

hehehhehehehehehehhehehehehehehehehehehheheehehhehehehehehheeeeeeeee

when a fullback hits a defensive back, which of the following are true?multiple select question.the force on the fullback is the same magnitude but in the opposite direction as the force on the defensive back.the momentum before and after the collision is the same for the defensive back.the momentum before and after the collision are the same for the fullback.the total momentum before and after the collision are the same.

Answers

The following statements are true: the force on the fullback is the same magnitude but in the opposite direction as the force on the defensive back, and the total momentum before and after the collision are the same.

When a fullback hits a defensive back, the forces exerted on both players are equal in magnitude but opposite in direction according to Newton's third law of motion. This law states that for every action, there is an equal and opposite reaction. Therefore, the force on the fullback is the same magnitude as the force on the defensive back, but they act in opposite directions.

However, according to the law of conservation of momentum, the total momentum of the system (the fullback and the defensive back) remains constant if no external forces are present. Therefore, the total momentum before the collision is the same as the total momentum after the collision.

In summary, the force on the fullback is the same magnitude but in the opposite direction as the force on the defensive back. Additionally, the total momentum before and after the collision remains the same, in accordance with Newton's third law and the law of conservation of momentum.

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An immersion heater is rated 120w. How long does it take the heater to raise the temperature of 1.2kg of water by 15°c.

Answers

Answer:

dmakqkwnwj fddfgdddwsf

3) A 6.1 kg bowling bowl and a 7.2 kg bowling ball rest on a rack. If the force of gravity pulling each
bowling ball toward the other is 3.1 X 10° N, what is the separation between the balls?

Answers

The distance of separation of the balls is 3.07×10⁻⁵ m.

To Solve the question, we use the formula below.

Formula:

F = GMm/r²...................... Equation 1

Where:

F = Force of gravityG = Universal constantM = mass of the bigger bowling ballm = mass of the smaller bowling ballr = Distance of separation between the balls.

Make r the subject of the equation,

r = √(GMm/F)................. Equation 2

From the question,

Given:

F = 3.1 NM = 7.2 kgm = 6.1 kgG = Constant = 6.67×10⁻¹¹ Nm²/kg².

Substitute these values into equation 2

r = √(7.2×6.1×6.67×10⁻¹¹/3.1)r = √(9.45×10⁻¹⁰)r = 3.07×10⁻⁵ m

Hence, the distance of separation of the balls is 3.07×10⁻⁵ m.

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how can a charged object attract an uncharged object made of non-conducting material?

Answers

A charged object can attract an uncharged object made of non-conducting material through the process of electrostatic induction. When a charged object is brought close to an uncharged object, it can polarize the charges within the non-conducting material.

A charged object can attract an uncharged object made of non-conducting material through the process of electrostatic induction. When a charged object is brought close to an uncharged object, it can polarize the charges within the non-conducting material. This means that the charged object can cause the electrons within the uncharged object to shift to one side, creating a temporary separation of charges. This separation of charges creates an electric field that can attract the uncharged object towards the charged object. The attraction between the charged and uncharged objects is a result of the electric field that is created by the polarized charges within the non-conducting material. This phenomenon can be observed in everyday life, such as when a charged balloon is brought close to an uncharged wall, causing the wall to be attracted towards the balloon.

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The gravitational potential energy of a particle of mass m moving under the influence of a fixed mass M is given by - , where G is the universal gravitational constant and r is the distance between the masses. What is the total energy of the mass m if it is in a circular orbit about mass M

Answers

-GMm/2r is the total energy of the mass m if it is in a circular orbit about mass M.

Given

A particle of mass m moving under the influence of a fixed mass's M, gravitational potential energy of formula  -GMm/r, where r is the separation between the masses and G is the gravitational constant of the universe.

As the Gravity Potential energy of particle = -GMm/r

Total energy of particle = Kinetic energy + Potential Energy

As we know that

Kinetic energy = 1/2mv²

Also, v is equals to square root of GM/r

v = √GM/r

Put the value of v in the formula of kinetic energy

We get,

Kinetic Energy = GMm/2r

Total Energy = GMm/2r + (-GMm/r)

                     = GMm/2r - GMm/r

                     = -GMm/2r

Hence, -GMm/2r is the total energy of the mass m if it is in a circular orbit about mass M.

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figure 3 is a diagram of water waves crossing over a shallow area. Do the waves move faster or slower through the second medium? what is happening to the wave at the edges of the shallow area?

Answers

When waves move from deep water to shallow water, the velocity of the waves decreases. The distance between the wave crest and the seabed decreases in shallow water, making it more challenging for the wave to move forward. As a result, the speed of the waves slows down.The waves bend as they come across the shallow water region because the water depth varies.

As a result, the wave front becomes warped resulting in a decrease in speed. As the wave enters shallow water its wavelength becomes shorter and its amplitude increases, but its frequency remains constant.The wave's velocity changes depending on the medium's density.

The denser the medium, the slower the wave travels, and vice versa. Since the speed of sound in water is quicker than that in air, sound waves travel faster through water than they do through air. As a result, the answer to the question is that the waves move slower through the second medium.

In the shallow water area, waves slow down and their shape changes. The energy of the wave is forced upward and outward, causing the wave to break. At the edges of the shallow area, the waves bend and change direction. As the waves come closer to shore, their circular motion causes them to collide with one another and pile up.

As a result, the waves become higher and steeper, resulting in a more turbulent environment for boats and swimmers.

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A box sits on a platform supported by a compressed spring. The box has a mass of 1.0 kg. When the spring is released, the spring gives 14.7 J of energy to the box. What will be the maximum height above the platform reached by the box before it begins to fall

Answers

The maximum height above the platform reached by the box before it begins to fall is 1.5 m.

The given parameters:

Mass of the box, m = 1.0 kgEnergy stored in the spring, E = 14.7 J

The maximum height above the platform reached by the box before it begins to fall is calculated as follows;

\(mgh = E\\\\h = \frac{E}{mg} \\\\h = \frac{14.7}{1 \times 9.8} \\\\h = 1.5 \ m\)

Thus, the maximum height above the platform reached by the box before it begins to fall is 1.5 m.

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what is the difference between the acceleration of his head and feet if the astronaut is 2.00 m tall?

Answers

The difference between the acceleration of his head and feet is 27.745 m/s².

What is Acceleration?

Acceleration of an object is the rate of change of the velocity of an object with respect to the time taken. Acceleration is a vector quantity. The orientation of an object's acceleration is given by the orientation of the net force which is acting on that object.

a. The center seeking acceleration of a body is known as centripetal acceleration. The expression is given as,

a = v²/ r

v = \(\sqrt{ar}\)

v = \(\sqrt{12.5g X 8.84}\)

v = \(\sqrt{12.5g X 9.8 X 8.84}\)

v = 32.92 m/s

Thus, the maximum speed of the astronaut's head is 32.92 m/s.

b. With difference in length between the head and feet, the new length is,

r' = 8.84 - 2.00 = 6.84 m

Then the difference in acceleration is,

a' = a - a''

a'' is the acceleration of astronaut. And its value is,

a'' = ω² × r'

a'' = a/r × r'

a'' = (12.5g/ 8.84) × 6.84

a'' = (12.5×9.8/ 8.84) × 6.84

a'' = 94.88 m/s²

Then, the difference in acceleration is,

a' = 12.5g - 94.88

a' = 12.5×9.8 - 94.88

a' = 27.745 m/s²

Thus, the required difference between the acceleration of the head and the feet of astronaut is 27.745 m/s².

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Your question is incomplete, most probably the complete question is:

At its Ames Research Center, NASA uses its large 20-G centrifuge to test the effects of very large accelerations (hypergravity) on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and the astronaut is strapped in at the other end. Suppose that he is aligned along the arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this machine is typically 12.5 g .Part A How fast must the astronaut's head be moving to experience this maximum acceleration?Part B What is the difference between the acceleration of his head and feet if the astronaut is 2.00 m tall?

You are pushing a 30kg box down the hall. There is 20 N friction force acting against you, but you still manage to accelerate the box at 2.0m/s2 (squared) What force are you applying?

Answers

Answer:

Thrust?

Explanation:

PLEASE HELP!!! I have so much work left to do. PLEASE!!!

PLEASE HELP!!! I have so much work left to do. PLEASE!!!

Answers

Answer:

the answer is C.

Explanation:

you pull yourself through the snow a distance of 510 meters with a horizontal force of 240 newtons. how much work did you do?

Answers

You did 122,400 Joules of work. Work is a measure of energy transfer, and in this case, it represents the energy you exerted to move yourself through the snow by applying a horizontal force.

Work is defined as the product of force and displacement in the direction of the force. In this scenario, you are pulling yourself through the snow with a horizontal force of 240 Newtons over a distance of 510 meters.

To calculate the work done, you multiply the force applied (240 N) by the distance moved in the direction of the force (510 m):

Work = Force × Distance

Work = 240 N × 510 m

Work = 122,400 Joules

Therefore, you did 122,400 Joules of work. Work is a measure of energy transfer, and in this case, it represents the energy you exerted to move yourself through the snow by applying a horizontal force.

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An airplane at 70 m/s in the direction 133 degrees counterclockwise from east. What are the east and north components of the plane's velocity?

Answers

Answer:

See below

Explanation:

East is   70 cos 133 = -47.7 m/s   East

North is  70 sin 133 = 51.2 m/s   North

How much energy will be created if a man 50 kg is destroyed completly

Answers

The question you've posed is a hypothetical one, and involves the concept of mass-energy equivalence, which was first proposed by Albert Einstein.

According to Einstein's famous equation E = mc², energy and mass are interchangeable, and the amount of energy that can be created from a given mass is directly proportional to the square of the speed of light.

In the case of a 50 kg man being completely destroyed, the mass of the man would be converted entirely into energy, as per the equation. The energy that would be created would be equivalent to 4.5 × 10¹⁶ joules. To put that into perspective, that's enough energy to power the entire world for about 14 seconds.
It's worth noting, however, that the scenario you've posed is purely hypothetical, and in reality, it's impossible to destroy a human being completely. Even if it were possible, the ethical implications of such an act would be unfathomable.

In conclusion, if a 50 kg man were completely destroyed, the energy that would be created would be equivalent to 4.5 × 10¹⁶ joules. However, it's important to remember that this scenario is purely hypothetical and has no practical application in the real world.

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does a parallel circuit with 2 resistors have more resistance than a series circuit with 2 resistors

Answers

That depends on the values of the resistors.

If the same two resistors are used in both cases, then the total resistance is more in series and less in parallel.

Here's a catchy little factoid for ya:

-- In series, the total resistance is more than the biggest single one.

-- In parallel, the total resistance is less than the smallest single one.


A body of knowledge must be___
in order to be considered science.

Answers

Answer:

observable and testable

Explanation:

what is the difference between positive and negative work? (no links)​

Answers

Answer:

Positive work is said to be done when the force acting on a body produces a displacement in the direction of the force. Negative work is said to be done when the force acting on a body produces a displacement opposite to the direction of the force

Explanation:

When the displacement of the body the in the direction of the force then the work done is positive. For example :- a man pushing a car in a straight path.

When the displacement is in a direction opposite to the direction of the force then the work done is said to be negative. For example :- work done by the friction.

Which of the below is wrong?

A)Total internal reflection occurs when the incident angle is equal or greater than the critical angle.

B)Total internal reflection only works when light moves from more dense medium to less dense medium.

C)The critical angle is the angle of incidence where the angle of refraction is 90°.​

Answers

The statement that total internal reflection only works when light moves from more dense medium to less dense medium, as mentioned in option B, is incorrect.

The correct statement among the options given is C. The critical angle is the angle of incidence where the angle of refraction is 90°. When light travels from a denser medium to a less dense medium, total internal reflection occurs when the incident angle is equal to or greater than the critical angle. This phenomenon is due to the fact that the light ray cannot bend enough to leave the denser medium and instead reflects back into it. However, total internal reflection can also occur when light travels from a less dense medium to a denser medium, as long as the incident angle is greater than the critical angle. This phenomenon is used in many applications, such as in fiber optics, where total internal reflection is used to transmit light signals over long distances.

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Dark moths began to outnumber white moths in cities after the Industrial Revolution. What is the most likely reason for this change?
answer choices
Light-colored moths mutated into dark colored moths.
Light-colored moths began to die due to overpopulation.
Light-colored moths were less favored for survival in the new environment.
Light-colored moths began to turn black because of factory pollution.

Answers

The most likely reason for the change in moth coloration is that light-colored moths were less favored for survival in the new environment.

What is Industrial Revolution?

In the late 18th and early 19th centuries, there was a huge period of economic and social transformation known as the Industrial Revolution. It started in Britain and later expanded to the rest of Europe and North America. Rapid industrialization and technological advancement throughout the Industrial Revolution changed how things were produced and distributed, spurring the development of new industries and contemporary cities.

A number of events led to the start of the Industrial Revolution in Britain around the middle of the eighteenth century. The abundance of natural resources, such as coal and iron ore, which were used to power the machinery and industries that would propel the Industrial Revolution, was one of the main motivators. Britain also had a solid banking system and a stable administration, which promoted investment and development. Technological advancements like the steam engine and the spinning jenny made it possible to produce items more quickly and effectively, while the construction of new transportation infrastructure like railroads and canals made it simpler to carry finished goods and raw materials.

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infrared light will knock electrons out of an electrode, and then be accelerated to higher energy to produce visible light. if you want it to detect light to wavelengths at least as long as 950 nm, will you need to use an electrode material with a work function greater than or less than a critical value?

Answers

To detect infrared light with wavelengths of at least 950 nm, an electrode material with a work function less than a critical value is needed, to facilitate the ejection of electrons by the incident photons.

When a material is exposed to light, photons can transfer their energy to electrons in the material, causing them to be ejected from the surface. The minimum energy required to remove an electron from the surface of a material is known as the work function. In this case, we want to detect infrared light with wavelengths of at least 950 nm, which have lower energy than visible light. To achieve this, we need to use an electrode material with a work function less than a critical value. This will enable the electrons to be ejected from the electrode by the incident photons, and then be accelerated to higher energies to produce visible light, which can then be detected by a sensor.

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A body oscillates with 25hz what is its time period

Answers

Answer:

4 seconds

Explanation:

The frequency of a body is the number of oscillations in one second. It is the number of cycles per unit time. The S.I unit of frequency is the Hertz (Hz).

The period of a body is the time taken to complete one oscillation. The period is inversely proportional to the frequency of the body. It is the reciprocal of frequency and the S.I unit is second (s).

A body oscillates with 25hz. Therefore the frequency (f) = 25 Hz.

The period (T) is given as:

\(Period (T)=\frac{1}{frequency(f)} \\T=\frac{1}{f} =\frac{1}{0.25}=4\\T=4\ seconds\)

1.
If Jane runs a 6 km race, then the distance ran by her in miles is
a 9.6
b 96.6
C 37.3
d 3.73

Answers

Answer:

9.6

Explanation:

to convert km to miles multiply by 1.609

Answer: 3.73

Explanation:I used my head and converted 6km to miles and it was 3.73

450n 360n 710n 1400n 230n a block is placed in oscillation on a frictionless horizontal surface attached to a spring that is also attached to a wall. If, when stretched away from equilibrium by 15cm and released, it oscillates with a period of 0. 25s, and if the mass of the block is 15kg, what force was required to stretch the spring by the initial 15cm?.

Answers

The force stood needed to stretch the spring by the initial 15cm exists  1420 N.

What is oscillation?

The motion between two positions back and forth, or swinging back and forth like a pendulum exists comprehended as oscillation.

What is equilibrium?

A condition where competing forces or activities exist in balance exists named equilibrium.

What is the stretching force?

Tensional force exists as the force exerted by a stretched item.

It could be a rope, string, elastic band, or wire that exists being extended.

The object's tensional force exists used to the object stretching it.

The stretched object exists subject to tensile force.

Force stood needed to stretch the spring by the initial 15cm exists 1420 N.

Let, m = 15, P = 0.25, x = 0.15

F = -K x for spring

where, F is the force

K be the constant

ω \(= (K/m)^{1/2\)

where, ω be the angular frequency

m b the mass of the block

\($\omega^2 = K / m\)

\(K = m \omega^2\) \(= m (2 \pi f)^2\)  \(= m 4 \pi ^2 / P^2\)

K = 4\(\pi ^2\) m / \(P^2\)

\(F = K x = x * 4 \pi ^2 m / P^2\)

\(F = 0.15 * 4 * \pi ^2 * 15 / 0.25^2\)

F = 1420 N

The force stood needed to stretch the spring by the initial 15cm exists  1420 N.

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Which best compares radiation and conduction?

A. Both transfer thermal energy from warm objects to cooler objects.
B. Both can transfer energy through empty space.
C. Both transfer thermal energy by electromagnetic waves.
D. Both involve the transfer of energy through direct contact.

And also who likes Rick and Morty OwO

Answers

Answer:

A

Explanation:

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