If you double the weight attached to a rubber band that obeys Hooke's Law, the new displacement will be:
Question 3 options:
double its previous displacement
triple its previous displacement
quadruple its previous displacement
one-half of its previous displacement
one-quarter of its previous displacement

Answer:

decrease and neutralize each other

Explanation:

As we go down the earth, we are moving towards the centre of the earth therefore the distance between us and center of the earth reduces and hence there is reduction in force acting on us by earth i.e gravity.

Answer:

Explanation:

Using the equation of motion

v = u+gt

v is the final velocity

u si the initial velocity

g is the acceleration due to gravity

t is the time

Substitute

0 = 4.5-(9.8)t

-4.5 = -9.8t

t = 4.5/9.8

t = 0.459s

ANSWER:

16 N

STEP-BY-STEP EXPLANATION:

The force is given by the multiplication of the mass and the acceleration, like this:

We repalce and calculate the force, like this:

The force is 16 newtons

Answer:

twice as much work

Explanation:

1) The direction it points depends on the direction of the electric current in the wires.

2) The magnetic field lines in the region would form circles around each individual wire carrying current.

3) This is because of the right-hand rule

The magnetic field produced by the electric current forms a circular magnetic field around the wire in accordance with the right-hand rule, which is applicable to conventional current flow.

The current's flow direction determines the direction of the magnetic field lines. The curled fingers of your right hand, which is holding the wire with your thumb pointing in the direction of the current flow, would point in the direction of the magnetic field.

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Answer:

friction

air drag

every thing that opposes the motion affects kinetic energy

Explanation:

kinetic energy is a energy which is increase with increase in motion and potential energy is energy stored while the object is at rest

potential energy ∝ 1/(kinetic energy)

as kinetic energy increases potential energy decreases

The beetle's actual distance beneath the surface is 1.70 cm.

The given information states that the beetle appears to be 1.70 cm within the plastic. This means that the beetle is located at a distance of 1.70 cm from the outer surface of the cube of polystyrene plastic. However, the actual distance of the beetle beneath the surface is also 1.70 cm since it is embedded within the cube.

The phrase "appears to be" suggests that the observation of the beetle's position within the plastic is deceiving. The beetle is not deeper or closer to the surface than the given measurement. Therefore, the beetle's true depth beneath the surface is equivalent to the stated distance of 1.70 cm.

Distances and interpreting spatial relationships within objects like the embedded beetle.

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Answer:

Solution given:

velocity=40cm/s

wave length=5cm

we have

frequency =velocity/wavelength=40/5=8hertz.

the frequency of the wave is 8 hertz.

a) To calculate the curl and divergence of a three-dimensional flow field, we have the flow field given as

\(v = i(y + z) + j(zx) + k(xy).\)

The curl of v is defined as:

curl(v) = ∇ x vWhere ∇ is the vector differential operator.

The curl is evaluated as:

\(curl(v) = i[(∂vz/∂y) - (∂vy/∂z)] + j[(∂vx/∂z) - (∂vz/∂x)] + k[(∂vy/∂x) - (∂vx/∂y)]where vx = y, vy = x, and vz = 1.\)

The above equation can be rewritten as:

curl(v) = - i - j + kDivergence of v is defined as:

div(v) = ∇ . v

This can be written as:

\(div(v) = ∂vx/∂x + ∂vy/∂y + ∂vz/∂z\)

Given v, we can calculate div(v) as follows:

\(div(v) = ∂vx/∂x + ∂vy/∂y + ∂vz/∂z= ∂y(y+z)/∂x + ∂x(zx)/∂y + ∂(xy)/∂z= 0+0+0=0\)

div(v) = 0, and curl(v) = - i - j + k

(b) Given that mg = CLρU^2A/2 and CL = 0.28(ωD/2U)

where \(m = 0.0027 kg, D = 44 mm = 0.044 m, U = 12 m/s, g = 9.81 m/s^2, and ρ = 1.23 kg/m^3\)

We have to derive the formula for CL in terms of the given variables and evaluate for the given values.

substituting the given values in the equation, we get:

\(mg = CLρU^2A/2CL = 2mg/(ρU^2A) = 2*0.0027*9.81/(1.23*12^2*π(0.022)^2) ≈ 0.155\)

Given that CL = 0.28(ωD/2U)

we can equate this with the above formula to obtain:

\(0.155 = 0.28(ωD/2U)ω = 2*0.155*12/(0.28*0.044) ≈ 50.06 radians/s(c)\)

For an offshore wind turbine supported on a vertical cylindrical pile, the vortex shedding frequency can be estimated using the formula:

f = St*U/D

where St is the Strouhal number, U is the velocity of the tidal current, and D is the diameter of the pile. Given that D = 5 m, h = 30 m, H = U = 1 m/s,

St = 0.3 we can evaluate the frequency of vortex shedding as:

f = 0.3*1/5 = 0.06 Hz

(d) The horizontal component of velocity is given as

\(u = ∂ϕ/∂x\)

where ϕ is the velocity potential for simple linear waves given as:

\(ϕ = H cosh(k(z+h))/cosh(kh)cos(kx-ωt)\)

Given that H = 2 m, T = 7 s, λ = 100 m, h = 10 m and g = 9.81 m/s^2, we have:

\(T = 2π/ωλ = gT^2/2π = (9.81*7^2)/(2π) ≈ 193.13 m\)

To calculate k, we use the relation k = 2π/λ.

Therefore\(,k = 2π/λ = 2π/100 = 0.0628\)rad/mSubstituting the given values in the velocity potential, we have:

\(ϕ = 2 cosh(0.0628(z+10))/cosh(0.628)cos(0.0628x - ωt)\)

The horizontal component of velocity is given as:\(u = ∂ϕ/∂x = -0.0628*2 sinh(0.0628(z+10))/cosh(0.628)sin(0.0628x - ωt)At the seabed,\)

z = -10 m

t = 0

\(u = -0.0628*2 sinh(-0.628)/cosh(0.628)sin(0) ≈ 0 m/s\)

Therefore, the maximum horizontal velocity at the seabed is 0 m/s.

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Answer:

The Recovery Principle applies both to immediate rest needed between bouts of exercise, as well as to longer time intervals of several hours to about two days. When you sprint as fast as possible or lift heavy weights, you will notice that your heart still pumps hard and you breathe heavy for a while after you stop.

Explanation:

Hope this helped!

Answer:

S = V0 t + 1/2 a t^2      net distance traveled

5.2 = a/2 * 25

a = 10.4 / 25 = ,416 m / s^2

F = m * a

m = F / a = 24 / .416 = 57.7 N

Answer: Subtractive colors absorb OR subtract some lights causing it to reflect, and creating white.

Explanation:

Subtractive colors are created by completely or partially absorbing (or subtracting) some light wavelengths and reflecting others.

Explanation:

On a position vs time graph (x vs t), displacement is the difference in positions (Δx = x₂ − x₁).

On a velocity vs time graph (v vs t), displacement is the area under the graph (Δx = ∫ v dt).

We will have that the picture that shows the highest average kinetic energy is image B.

The mass m of the block on the left is 16 Kg , correct answer.

What is friction?

Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.

Think about how a 100 kilogramme block would move.

beginning speed (Vi) = 0 m/s

a stands for speed.

d=displacement=1 m

Time taken is t = 0.53 seconds.

Using the formula:

d=Vi t+(0.5)a t2

1 = (0) (0.53) + (0.5) a (0.53) (0.53)

2

a = 7.12 m/s2

Acceleration for an at wood machine is expressed as

7.12 = (100 - m) (9.8)/ (100 + m)

m = 15.84 kg

m = 16 kg

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If the screen in an optical apparatus is large enough to display the entire diffraction pattern from a single slit of width 'a', then the central maximum of the pattern is twice as wide as the secondary maxima.

In a single-slit diffraction experiment, when the width of the slit is small compared to the wavelength of the incident light, the diffracted waves interfere with each other and form a pattern on a screen placed behind the slit. The central maximum of the pattern is the brightest and is located at the center of the screen. The secondary maxima are located on either side of the central maximum and are less bright than the central maximum.

If the screen is large enough to display the entire diffraction pattern, then the central maximum will have a width of approximately twice the width of the secondary maxima. This is because the secondary maxima are located where the light waves interfere constructively and add up to form bright fringes. These fringes are narrower because they occur at angles further from the center of the screen. On the other hand, the central maximum is formed when all the waves from the slit interfere constructively at the center of the screen. This results in a wider fringe. Therefore, the central maximum is twice as wide as the secondary maxima.

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Question: Suppose the screen in an optical apparatus is large enough to display the entire diffraction pattern from a single slit of width a. If a = lambda, what is the width of the central diffraction maximum?

Answer:

29.436 J/g.°C

Explanation:

We are given;

Mass of tungsten; m_t = 215 g

Initial temperature of tungsten; T_ti = 100°C

Final temperature; T_f = 21.5°C

Mass of water; m_w = 450 g

Initial temperature of water; T_tw = 20°C

From tables, specific heat capacity of water; c_w = 4.184 J/g.C

Thus;

Energy lost by tungsten = energy gained by water

Thus;

215 × c_t × (100 - 21.5) = 450 × 4 184 × (21.5 - 20)

Where c_t is specific heat capacity of tungsten

16877.5c_t = 496800

c_t = 496800/16877.5

c_t = 29.436 J/g.C

The work done by the car at the given mass and speed is \(3.1 \times 10^5 \ J\)

The given parameters;

The initial velocity of the car, u = 72 km/h = 20 m/s

The final velocity of the car, v = 90 km/h = 25 m/s

The acceleration of the car is calculated as follows;

\(a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v- u}{t_2 - t_1} \\\\\)

the initial time of motion, t₁ = 1 hour = 3600 s

the second time of motion, t₂ = 1 hour + 1 hour = 2 hours = 7200 s

\(a = \frac{25-20}{7200 - 3600} \\\\a = 0.00138 \ m/s^2\)

The force exerted by the car is calculated as follows;

\(F = ma\\\\F = (2.5 \times 10^3) \times 0.00138 \\\\F = 3.45 \ N\)

The work done by the car is calculated as follows;

\(W = F\times s\)

where;

\(s = (72 - 0) \ k m \ + \ (90 - 72) \ km\\\\s = 90 \ km = 90,000 \ m\)

\(W = 3.45 \times 90,000 \\\\W = 3.1 \times 10^5 \ J\)

Thus, the work done by the car at the given mass and speed is \(3.1 \times 10^5 \ J\).

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When an infrared heater is switched on, a person a few meters away begins to warm up, has moved from the heater to the person is transfer of thermal energy, this occurs through the movement of infrared radiation, which is a form of electromagnetic radiation with longer wavelengths than visible light.

Infrared heaters generate heat by emitting infrared radiation from their heating elements, such as quartz tubes or ceramic plates. This radiation travels through the air and is absorbed by objects and people in its path, including the person who feels the warmth. The absorbed radiation raises the temperature of the object or person, causing them to feel warmer.

Infrared radiation does not rely on direct contact or the movement of air, making it an efficient way of transferring heat over a distance. This type of heating is known as radiant heating, and it is different from convection heating, which relies on the movement of air particles to transfer heat. In summary, when an infrared heater is switched on, thermal energy moves from the heater to a person a few meters away via infrared radiation. This radiation is absorbed by the person, raising their temperature and making them feel warmer.

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The main factor that affects the amount and duration of geological activity on a terrestrial planet is its internal heat. This heat is generated through various processes such as radioactive decay and residual heat from planetary formation.

The presence of a molten core and active mantle circulation contributes to geological activity, including tectonic plate movements, volcanic eruptions, and mountain building. Other factors like the planet's size, composition, and distance from the Sun can also influence geological activity to some extent.

The main factors that affect atmospheric conditions on a terrestrial planet are its distance from the Sun, the composition of its atmosphere, and the presence of greenhouse gases. The proximity to the Sun determines the amount of solar energy received, which affects temperature and weather patterns. The composition of the atmosphere, including the presence of gases like oxygen, nitrogen, carbon dioxide, and water vapor, determines the planet's climate and the ability to support life. Greenhouse gases trap heat in the atmosphere, contributing to the greenhouse effect and influencing temperature regulation.

Based on what we know about the factors that affect geologic activity and atmospheres on terrestrial planets, we can expect that typical Jovian moons, being small rocky-metal bodies, would have limited geological activity and thin atmospheres, if any. The smaller size of these moons compared to terrestrial planets means that they have a lower heat-producing capability and less internal energy. Additionally, their lower gravitational forces make it challenging to retain substantial atmospheres. While some Jovian moons may have evidence of geological activity, such as cryovolcanism or tidal heating, they generally exhibit less dynamic geologic and atmospheric conditions compared to larger terrestrial planets.

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The option that is NOT true is: "The horizontal velocity of the plane is the same as the vertical velocity of the care package when it hits the ground."

When the pilot drops the care package from the airplane, it will experience a vertical acceleration due to gravity, but the horizontal velocity of the care package remains the same as that of the airplane. The horizontal acceleration of the care package is indeed zero, and it travels in a curved path due to the combined effect of its horizontal velocity and the vertical acceleration due to gravity.

However, the vertical velocity of the care package increases while the horizontal velocity remains constant. Therefore, when the care package hits the ground, its horizontal velocity will be the same as the horizontal velocity of the airplane, but the vertical velocities will be different.

Thus, the statement that the horizontal velocity of the plane is the same as the vertical velocity of the care package when it hits the ground is NOT true.

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The final volume of the steam is 0.8 m^3, which is an increase of four times the initial volume. This expansion is due to the heat added to the steam, causing the steam molecules to move faster and occupy a larger volume.

To determine the final state of the steam after it has been heated, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in kelvin.

We can use this equation to solve for the final volume of the steam after it has been heated to 500 degrees celsius. We can assume the steam is an ideal gas.

First, convert the initial temperature of 50 kPa to kelvin:

T1 = 50 + 273.15 = 323.15 K

Next, convert the final temperature of 500 degrees celsius to kelvin:

T2 = 500 + 273.15 = 773.15 K

The ideal gas constant R = 8.314 J/mol.K

We know the mass of steam is 1.8 kg, and we can use the molar mass of water, which is 18 g/mol, to calculate the number of moles of steam n = 1.8 kg / 18 g/mol = 0.1 mol.

Now we can use the ideal gas law to solve for the final volume of the steam, using the information we have:

P1V1 = nRT1

V1 = nRT1/P1 = 0.1 mol * 8.314 J/mol.K * 323.15 K / 50 kPa = 0.200 m^3

P2V2 = nRT2

V2 = nRT2/P2 = 0.1 mol * 8.314 J/mol.K * 773.15 K / 50 kPa = 0.8 m^3

The final volume of the steam is 0.8 m^3, which is an increase of four times the initial volume. This expansion is due to the heat added to the steam, causing the steam molecules to move faster and occupy a larger volume.

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Answer:

a= kinetic energy vs. different masses at same speed, b= kinetic energy vs. same masses at different speeds

Explanation:

graphs are looking at speed so masses don't matter as much. same speed the whole time will equal same kinetic energy the whole time.

Explanation:

A is excretion

B is digestion

so my guess is c

The weight of an object would be the least at the center of the Earth. 2000 miles above earth's surface at the equator at the south pole at the north pole at the center of earth.

The weight of an object depends on the gravitational force acting on it. The gravitational force is inversely proportional to the square of the distance between the object and the center of the Earth. As the object moves farther away from the center of the Earth, the gravitational force decreases.

At the center of the Earth, the distance between the object and the center is at its minimum. Therefore, the gravitational force and consequently the weight of the object would be the least at the center of the Earth.

In contrast, as the object moves further away from the center of the Earth, such as 2000 miles above the Earth's surface, the distance between the object and the center increases, resulting in a stronger gravitational force and a greater weight.

Thus, of the options provided, the weight of an object would be the least at the center of the Earth.

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1,000 pascals is equal to 1 kilopascal.

To convert kilopascal to pascals, multiply by 1,000. To convert pascal to kilopascal, divide by 1,000.

Answer:

d.solid to liquid cause they were once on a fixed and started to slide.liquid particles slide along a container so it is a solid to liquid

Answer: B

Explanation: just did it on a p e x