Answer:
Explanation:
Because we assume the pendulum is a "mathematical pendulum" (neglecting the moment of inertia of the bob), we can find:
\(T=2\pi\sqrt{\frac{L}{g}} \rightarrow 4=2\pi\sqrt{\frac{L}{9.81}} \rightarrow \frac{4}{\pi^{2}}=\frac{L}{9.81} \rightarrow L \approx 3.97 m\)
By using the \(y=A\sin(\omega t) \rightarrow v = \frac{dy}{dt}=\omega A \cos\omega t = \omega\sqrt{A^{2}-y^{2}}\)
The mean position is the position when y = 0, so:
\(\omega = \frac{2\pi}{T}=\frac{2\pi}{4}=0.5\pi\) rad/s
and \(v = \omega A \rightarrow A=\frac{40}{0.5\pi}=\frac{80}{\pi}\) in centimeters (cm).
PLZ Help ASAP
Peter wants to find out which boils faster: salt water or tap water. What procedure should he follow to conduct this experiment?
Answer:
C. Fill two identical pots with equal volumes of salt water and tap water and use a stopwatch to determine the time it takes each pot to boil.
Explanation:
A) is incorrect because Peter should have the same testing environment for both of his experiments.
He should choose the same method of boiling the salt water and tap water because the stovetop and the microwave could also affect the results and make them unreliable.
B) is incorrect because Peter should not estimate the time it takes the salt water and tap water to boil.
Peter should measure and record the amount of time that it takes these substances to boil in order to have an accurate, valid experimental thesis.
C) is correct because Peter uses the same volume of salt water and tap water, fills them into two identical pots, and uses a stopwatch to determine the amount of time it takes each pot to boil.
The stopwatch makes the experiment more valid and accurate compared to the previous methods, and the identical pots and amounts of water help this experiment become even more precise.
D) is incorrect because the variables in the experiment are not controlled amounts and will therefore produce an inaccurate and invalid experiment.
A clown 2 m tall looks at himself in a full-length mirror (floor-to-ceiling). Where in the mirror must he look to see his feet?
Answer:
Around the center of the mirror
Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.
A fox getting its energy from a mouse and a mouse getting its energy from the grass shows evidence of the carbon cycle
What is the carbon cycle?The carbon cycle is a necessary component within the global interchange between living species and the environment.
Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.
Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.
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Mmoon: 0.0123ME
Rmoon: 0.272RE
MMars: 0.107ME
RMars: 0.530RE
Above, the masses and radii of the moon and Mars are given as fractions of the mass and radius of the earth. Calculate their accelerations due to gravity at their surfaces. [Below, the masses and radii of the moon and Mars are given as fractions of the mass and radius of the earth. Calculate their accelerations due to gravity at their surfaces. [The calculation is simplified if you directly substitute in the equation the lunar and Martian fractional factors for mass over radius squared and multiply the answers times 9.8.]
The acceleration due to gravity at the surface of a celestial body can be calculated using the formula:
a = G * M / R^2
where G is the gravitational constant, M is the mass of the celestial body, and R is its radius.
Substituting the lunar and Martian fractional factors for mass over radius squared and multiplying the answers by 9.8, we have:
Acceleration due to gravity at the surface of the Moon:
a = G * Mmoon / Rmoon^2 = G * (0.0123ME) / (0.272RE)^2 = 1.62 m/s^2
Multiplying by 9.8, we have:
a = 1.62 * 9.8 = 15.88 m/s^2
Therefore, the acceleration due to gravity at the surface of the Moon is approximately 1.62 m/s^2, or 15.88 m/s^2 when multiplied by 9.8.
Acceleration due to gravity at the surface of Mars:
a = G * MMars / RMars^2 = G * (0.107ME) / (0.530RE)^2 = 3.71 m/s^2
Multiplying by 9.8, we have:
a = 3.71 * 9.8 = 36.41 m/s^2
Therefore, the acceleration due to gravity at the surface of Mars is approximately 3.71 m/s^2, or 36.41 m/s^2 when multiplied by 9.8.
what is acceleration due to gravity ?Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s2. It has both magnitude and direction, hence, it’s a vector quantity. Acceleration due to gravity is represented by g. The standard value of g on the surface of the earth at sea level is 9.8 m/s2.
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A carbon ion with 10 electrons and 6 protons would have a charge of ?
Answer:
-4
Explanation:
Electrons are negative while protons are positive.
To find the charge, add the number of protons to the number of electrons.
6+(-10)
6-10
-4 is the charge
What is the coefficient of LiCl when the below double replacement reaction is balanced?
LiCl + BeF2 → LiF + BeCl2
2
O4
Answer:2
Explanation:
Two equal and opposite charges are placed 40mm apart,if the force between them is found to be 0.5N Calculate the magnitude of the charge
Any help plz ? ………..
Answer:
-2+4-22--43
Explanation
This is the correct answer
i
e. network executives make hasty
When winding an old clock, it is important not to overwind it. Over-
winding occurs when the mainspring is almost fully wound, but the
operator continues to turn the winding key. This causes the main
spring to coil too tight, and might even break it.
110. This paragraph best supports the statement that
a. clocks have changed over the years.
b. old-fashioned clocks become fragile with age.
c. old-fashioned clocks were operated by an internal spring.
d. overwinding clocks used to be a common mistake.
e. time flies when you're having fun.
The paragraph primarily discusses the concept of overwinding old clocks and its consequences, indicating that overwinding clocks used to be a common mistake. Here option D is the correct answer.
The paragraph explains that overwinding occurs when the mainspring is almost fully wound, but the operator continues to turn the winding key, resulting in the spring coiling too tightly or even breaking.
This suggests that overwinding was a mistake commonly made in the past when operating old-fashioned clocks. The other options, such as clocks changing over the years or clocks becoming fragile with age, are not directly addressed in the paragraph and are therefore less supported.
The option e. "time flies when you're having fun" is unrelated to the paragraph and can be disregarded as an irrelevant answer choice. Hence option D is the correct answer.
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name a type of relationship between current and potental difference for a resistor at constant temperature
Answer:
The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.
Explanation:
I Looked It Up. So It May Be Wrong But I Hope This Helps!
Answer:
The current flowing through a resistor at a constant temperature is directly proportional to the potential difference across it. ... This is called Ohm's law.
How is Newton's second Law of Motion used in the sport Jokgu?
Jogku is a Korean sport similar to football and volleyball.
2 teams face each other and the objective is to return the ball to the opponent, using their feet or shin.
Newton's second law of motion states that Force (F) is equal to mass (m) times acceleration (a)
F= m x a
In Jogku, a hard kick will move the ball farther and faster than a soft kick. The acceleration of the ball depends on how much force (kick) is applied to it.
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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state ohmic conductor
Answer:
An ohmic conductor is defined as one which obeys ohm's law that is V ∝ I where is the voltage and is the current. There must be a linear graph. Silver is an example of an ohmic conductor as the graph for silver is a linear graph. Silver and copper are some examples of ohmic conductor
A 430.0 g mass is being pushed by a 1.1 N net force. What is the acceleration?
Answer:
\(a = 2.56\ m/s^2\)
Explanation:
Mechanical Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
The object has a mass of m=430 g = 0.43 Kg and is pushed by a net force of F=1.1 N. To calculate the acceleration, we solve for a:
\(\displaystyle a=\frac{F}{m}\)
\(\displaystyle a=\frac{1.1}{0.43}\)
\(\mathbf{a = 2.56\ m/s^2}\)
The speed of light in air is 3.00 x 10^8 m/s. If a light wave has a wavelength of 5.80 x 10^-7m, what is its frequency?
Answer:
5.17 x 10^14 1/s
Explanation:
Equation:
c = λ f
c = speed of light
λ = wavelength
f = frequency
Solve:
3.00 x 10^8 m/s = (5.80 x 10^-7m) * f
f = (3.00 x 10^8 m/s) / (5.80 x 10^-7m)
f = 5.17 x 10^14 1/s
mention the device which could be used to carry a heavy load onto onto a truck.
Answer:
A crane is a type of machine, generally equipped with a hoist rope, wire ropes or chains, and sheaves, that can be used both to lift and lower materials and to move them horizontally. It is mainly used for lifting heavy things and transporting them to other places.
Explanation:
Answer:
A crane
Explanation:
Cranes are used move heavy items
How does solar weather affect Earth’s magnetosphere? Select the two correct answers.
It causes geomagnetic storms.
It generates auroras.
It develops solar wind.
It forms radiation belts.
Calculate the acceleration of the object in free fall (picture shown above)
Answer:
Estimate slope= acceleration of -18.75 m/s^2
Explanation:
In the velocity vs time graph, acceleration is the slope
Let's take two points from the line and find the slope
(0,0) (0.8, -15)
slope = -15-0/ 0.8-0 = -18.75 m/s^2
Part A
Playing in the street, a child accidentally tosses a ball (mass m) with a speed of v=18 m/s toward the front of a car (mass M) that is moving directly toward him with a speed of V=20 m/s . Treat this collision as a 1-dimensional elastic collision. After the collision, the ball is moving with speed v′ back toward the child and the car is moving with speed V′ in its original direction.
Part B
When we combine the equation from Part A with the conservation of momentum equation, we can solve for both final speeds. This relationship will involve the masses of the ball and the car, but we can apply a simplifying assumption: the car is so massive compared with the ball that its speed will not change at all as a result of this collision. Translate this sentence into an equation, what is V′ equal to? Now, having made this assumption, it becomes possible to solve the equation from Part A for the final speed of the ball, what is it?
Answer:
v' = -18 m/s
Explanation:
Assuming no external forces acting during the collision, total momentum must be conserved, as follows:\(p_{o} = p_{f} (1)\)
The initial momentum can be expressed as follows (taking as positive the initial direction of the ball):\(m_{b} * v_{b} -M_{c}*V_{c} = m_{b} * 18 m/s + (-M_{c}* 20 m/s) (2)\)
The final momentum can be expressed as follows (since we know that v'b is opposite to the initial vb):\(-(m_{b} * v'_{b}) + M_{c}*V'_{c} (3)\)
If we assume that Mc >> mb, we can assume that the car doesn't change its speed at all as a result of the collision, so we can replace V'c by Vc in (3).So, we can write again (3) as follows:\(-(m_{b} * v'_{b}) +(- M_{c}*V_{c}) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (4)\)
Replacing (2) and (4) in (1), we get:\(m_{b} * 18 m/s + (-M_{c}* 20 m/s) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (5)\)
Simplifying, and rearranging, we can solve for v'b, as follows:\(v'_{b} = -18 m/s (6)\), which is reasonable, because everything happens as if the ball had hit a wall, and the ball simply had inverted its speed after the collision.A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.
The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.
To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.
Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).
According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.
The total momentum before the interaction is given by:
Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)
Mass of the dog (m1) = 24.4 kg
Velocity of the dog (v1) = 2.14 m/s
Mass of the cat (m2) = 5.53 kg
Velocity of the cat (v2) = 3.56 m/s
Mass of the owner (m3) = 78.5 kg
Velocity of the owner (v) = unknown
Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)
The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.
Total momentum after = 0
Equating the two expressions:
(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0
Simplifying the equation:
(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0
71.8648 kg·m/s + (78.5 kg * v) = 0
Solving for v:
78.5 kg * v = -71.8648 kg·m/s
v = -71.8648 kg·m/s / 78.5 kg
v ≈ -0.916 m/s
Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.
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which two options describes behaviors of particles that are related to the chemical properties of the materials
a- forming hydrogen bonds between them
b- reacting quickly with water
c- having a high mass
d- forming bonds with other atoms
The two options describes behaviors of particles that are related to the chemical properties (chemical change) of the materials are b )reacting quickly with water d) forming bonds with other atoms
What is a chemical change ?A chemical change is that change when two or more substance combine to form a new substance . It rearranges the constituent atom of the reactants to create different substances as product .
a) Forming hydrogen bonds between them will not create any new substance , it is just a bond between atoms due to which no chemical change will take place as no new substance is formed
b) Reacting quickly with water is a chemical change as reaction is been taking place and a new substance will form after the reaction .
hence b ) reacting quickly with water is a correct answer
c) Having a high mass : It is a physical quantity hence can't be related to chemical property .
d) Forming bonds with other atoms is a chemical reaction as forming bond with other bond will make a new substance ( product ) and it is a chemical change .
Hence , d) forming bonds with other atoms is a correct option
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For the following, determine the meaning of the bolded word by using
definition and example clues from the text.
The snake wound itself around its prey, entwining the
mouse within its body.
A. The state of being wrapped around something
OB. A force of nature
C. An injury to the body
D. The action of hurting someone
What happens to most of the light waves that strike a clear pane of glass? O A. absorption B. diffraction O C. reflection O D. transmission
Answer:absorption
Explanation:
What is the meaning of eddy currents in electromagnetic series?
Answer:
currents which circulate in conductors like swirling eddies in a stream in electromagnetic series....
You want to use a metal bar as a resistor. Its dimensions are 1 by 3 by 13 units. To get the largest resistance from the bar, you should attach leads to the two opposite sides that have dimensions of 1 by 3 units. All configurations give the same resistance. 3 by 13 units. 1 by 13 units. None of the above.
Answer:
1 by 3 units
Explanation:
The resistance (R) of a conductor is given by the formula:
R = ρL / A
where L is the length of the conductor, ρ is resistivity and A is the cross sectional area.
Let us assume that the metal bar has a resistivity of ρ.
a) If the leads is attached to the two opposite sides that have dimensions of 1 by 3 units.
The length of the bar would be 13 units and the cross sectional area (A) would be = 1 * 3 = 3 units²
R₁ = ρL / A = ρ(13) / 3 = 13ρ / 3
b) If the leads is attached to the two opposite sides that have dimensions of 3 by 13 units.
The length of the bar would be 1 units and the cross sectional area (A) would be = 3 * 13 = 39 units²
R₂ = ρL / A = ρ(1) / 39 = ρ / 39
c) If the leads is attached to the two opposite sides that have dimensions of 1 by 13 units.
The length of the bar would be 3 units and the cross sectional area (A) would be = 1 * 13 = 13 units²
R₃ = ρL / A = ρ(3) / 13 = 3ρ / 13
Therefore we can see that the largest resistance is gotten If the leads is attached to the two opposite sides that have dimensions of 1 by 3 units
A 12 volt power supply is connected
to two 30 Ohm resistors in parallel.
What is the voltage drop across the
resistors?
12 V
30 Ω
30 Ω
[?] volts
24 volts is the voltage drop across each of the resistors in the parallel configuration.
When resistors are connected in parallel, they share the same voltage across them. Therefore, the voltage drop across each resistor in this scenario would be the same.
Given:
Power supply voltage (V) = 12 V
Resistance of each resistor (R) = 30 Ω
Since the resistors are in parallel, the total resistance (R_total) can be calculated using the formula:
1/R_total = 1/R1 + 1/R2
Substituting the values:
1/R_total = 1/30 Ω + 1/30 Ω
1/R_total = 2/30 Ω
R_total = 15 Ω
Now, we can find the current flowing through the resistors (I) using Ohm's Law:
I = V / R_total
I = 12 V / 15 Ω
I = 0.8 A
Since the voltage drop across each resistor is the same, we can find it using Ohm's Law:
V_drop = I * R
V_drop = 0.8 A * 30 Ω
V_drop = 24 V
Therefore, the voltage drop across each of the resistors in the parallel configuration is 24 volts.
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What are 3 artificial and 2 natural sources of electromagnetic radiation?
Answer: its b bro
Explanation:
ajafa'jfbA'FJ
If you have an applied force in the 4th quadrant what direction will the force have to be (what quadrant) to bring the force into equilibrium?
Answer:I’m not sure, but i believe it is the second quadrant.
Explanation: The forces need to add to zero and opposite vectors subtract, so if there is an equal force or vector moving opposite (in the second quadrant), it will sum to zero
Yvette does not understand why her plant is not growing. Through observation of the care she gave it, she decided, if I increase the water from 1 cup a week to 2 cups a week, then it will grow. What has she just proposed?
Answer:
Yvette has just proposed a hypothesis. A hypothesis is a proposed explanation for a phenomenon or observation. In this case, Yvette has observed that her plant is not growing and has proposed that increasing the amount of water it receives will cause it to grow. To test this hypothesis, Yvette could try increasing the amount of water the plant receives and observe whether it starts to grow. If the plant does start to grow, this would provide support for Yvette's hypothesis. However, if the plant does not start to grow, this would suggest that the hypothesis is incorrect and Yvette would need to come up with a new explanation for why the plant is not growing.
block and sphere are connected by a cord that passes over a pulley, as shown. Neglect friction and assume the cord is massless,
m1= 2.00 kg,
m2= 540 kg, and θ= 49.0∘.
What is the tension (in N) in the cord?
Tension is a force along the length of a medium, especially a force carried by a flexible medium, such as a rope or cable.
The tension in the cord is approximately 10624 N.
To solve this problem, we can use the principles of Newton's laws and apply them to each of the objects involved. We will also use the fact that the tension in the cord is the same on both sides of the pulley (neglecting any friction or mass in the pulley).
First, we can consider the forces acting on the block (m1). The only forces acting on the block are its weight (mg) and the tension in the cord (T), which is directed upward. We can resolve these forces into components parallel and perpendicular to the inclined plane:
The weight of the block has a component parallel to the inclined plane given by \(mg*sin(θ)\).
The tension in the cord has a component parallel to the inclined plane given by \(T*sin(θ)\).
Using Newton's second law, we can write:
\(m1 * a = T * sin(θ) - m1 * g * sin(θ)\)
where a is the acceleration of the block down the inclined plane.
Next, we can consider the forces acting on the sphere (\(m2\)). Since the sphere is hanging from the cord, the only force acting on it is its weight (\(mg\)), which is directed downward. Using Newton's second law, we can write:
\(m2 * a = m2 * g - T\)
where a is the acceleration of the sphere downward.
Since the cord is assumed to be massless and the pulley is assumed to be frictionless, the tension in the cord is the same on both sides of the pulley. Therefore, we can set the two expressions for T equal to each other:
\(T * sin(θ) - m1 * g * sin(θ) = m2 * g - T\)
Solving for T, we get:
T = \((m2 + m1) * g / (sin(θ) + 1)\)
Substituting the given values, we get:
T = \((540 kg + 2.00 kg) * 9.81 m/s^2 / (sin(49.0°) + 1)\)
T = 10624 N (to three significant figures)
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