If the Moon were 1 mile from Earth, how far from Earth would Mars be?
o 200 miles
o 10 miles
o 1300 miles
o 43 miles
Answers
The options provided (200 miles, 10 miles, 1300 miles, or 43 miles) are all incorrect.
Calculation-Due to the Moon's elliptical orbit, the distance between the Earth and the Moon changes throughout the month, but on average it is roughly 238,855 miles (384,400 kilometres). The Moon would be approximately 238,854 miles closer to Earth if it were only 1 mile away.
Mars, on the other hand, is typically 140 million miles away from Earth (225 million kilometres). Consequently, the separation of the Moon from Earth has no bearing on the distance between Earth and Mars.
Hence, if the Moon is 1 mile or 238,855 miles distant from Earth, the distance between them would still be about 140 million miles.
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Related Questions
help pls
1.How do electromagnets cause a maglev train to levitate above the track? (1 point)
Responses
Magnets in the sides of the tracks constantly repel and attract magnets in the sides of the train.
Magnets in the track and magnets in the bottom of the train repel each other.
Magnets in the track and magnets in the bottom of the train attract each other.
Batteries provide electric energy to the electromagnets in the train.
2.What happens to sound waves from an object as it moves toward you?(1 point)
Responses
The pitch gets higher because of an increase in frequency.
The pitch gets lower because of an increase in wavelength.
The pitch gets higher because of an increase in wavelength.
The pitch gets lower because of an increase in frequency.
3.Which combination of frequencies would produce the lowest beat frequency?(1 point)
Responses
10 Hz and 20 Hz
10 Hz and 15 Hz
500 Hz and 600 Hz
500 Hz and 501 Hz
4.A student is using a weak computer to design a logo. If the weak computer is the only constraint, should the student use the online version or downloaded version of a graphic design software?(1 point)
Responses
The online version, because the downloaded version usually requires better equipment than the online version.
The downloaded version, because the online version usually requires better equipment than the downloaded version.
The downloaded version, because the online version may have limited bandwidth that limits how quickly the designer can work.
The online version, because the downloaded version may have limited bandwidth that limits how quickly the designer can work.
5. A student explains that the behavior of EM radiation is wave-like. Which explanation correctly evaluates the wave-like properties of EM radiation? (1 point)
Responses
EM radiation has a well-defined mass.
EM radiation has a well-defined frequency.
EM radiation has a well-defined energy value.
EM radiation has a well-defined location.
6.Which observation is evidence that electromagnetic radiation (EMR) has particle-like properties?(1 point)
Responses
EMR refracts as it moves into a different medium.
A diffraction pattern is observed when EMR passes through a narrow slit.
EMR with energy above a certain value can eject electrons out of a metal.
Some EMR is blocked when it passes through a polarized lens.
7. Which statement about the double-slit experiment is true?(1 point)
Responses
The double-slit experiment proves that electromagnetic radiation consists of particles.
The double-slit experiment provides evidence that electromagnetic radiation has both wave-like and particle-like properties.
The double-slit experiment provides evidence that electromagnetic radiation has wave-like properties.
The double-slit experiment proves that electromagnetic radiation consists of waves.\
8. The image shows hydrogen's emission and absorption spectrum. This is compatible with which kind of model?
(1 point)
Responses
wave model because the lines in the emission spectrum continue in the absorption spectrum.
particle model because the atom's electron absorbs and emits energy in discrete wavelengths.
wave model because the spectrum is a continuum.
particle model because only this model can explain energy transfer.
9. A sunburn is a familiar example of the effect of ionizing radiation, like ultraviolet light, where longer exposure harms the skin and tissues. At the atomic level, what is being produced by ionizing radiation on skin?(1 point)
Responses
light
neutrons
protons
ions
10. Which factor makes the biggest difference when studying the effects of radiation on an organism?(1 point)
Responses
the size of the organism
the frequency of the radiation
the duration of exposure
the number of cells exposed to the radiation
Answers
Electromagnet causes Magnets in the track and train repel and attract to levitate maglev train. Pitch of sound waves increases as an object moves towards you. 500 Hz and 501 Hz would produce the lowest beat frequency.
1. Magnets in the sides of the tracks continually repulse and draw in magnets in the sides of the train, making the train suspend over the track utilizing electromagnets.
2. The pitch of sound waves from an article increments as it pushes toward you because of an expansion in recurrence.
3. The blend of 500 Hz and 501 Hz frequencies would create the most minimal beat recurrence.
4. The understudy ought to utilize the web-based adaptation of the visual depiction programming, as the downloaded variant normally requires preferable hardware over the internet based rendition.
5. EM radiation has a clear cut recurrence and showcases wave-like properties. EMR with energy over a specific worth can launch electrons out of a metal, which is proof of its molecule like properties.
6. The twofold cut try gives proof that electromagnetic radiation has both wave-like and molecule like properties. Molecule model in light of the fact that the particle's electron retains and radiates energy in discrete frequencies, as shown by the outflow and retention spectra.
7. The double-slit experiment provides evidence that electromagnetic radiation has both wave-like and particle-like properties.
8. wave model because the lines in the emission spectrum continue in the absorption spectrum.
9. ions is sunburn is a familiar example of the effect of ionizing radiation.
10. the duration of exposure makes the biggest difference when studying the effects of radiation on an organism.
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An 8000 kg satellite is launched from the surface of the Earth into outer space. What initial kinetic energy is needed by the satellite in order to reach a great (i.e., infinite) distance from the Earth, neglecting the effects of air resistance in the atmosphere? (G = 6.67 × 10−11 N·m2/kg2, ME = 5.97 × 1024 kg, RE = 6.37 × 106 m.)
Answers
3.96 × 1011 J is the initial kinetic energy is needed by the satellite in order to reach a great (i.e., infinite) distance from the Earth, neglecting the effects of air resistance in the atmosphere.
In order to calculate the initial kinetic energy needed for the satellite to reach an infinite distance from Earth, we need to use the equation
K = 0.5\(mv^2\), where K is the kinetic energy, m is the mass of the satellite, and v is its velocity.
Using the given values of the satellite's mass (8000 kg) and the gravitational constant (6.67 × 10−11 N·m2/kg2), we can calculate the initial velocity needed:
v = √[(2GME)/RE] = √[(2 × 6.67 × 10−11 × 5.97 × 1024) / 6.37 × 106] = √[9.8 × 107] = 9.9 × 103 m/s
Using the velocity and mass values, we can calculate the initial kinetic energy needed for the satellite to reach an infinite distance from Earth:
K = 0.5\(mv^2\) = 0.5 × 8000 kg × (9.9 × 103)2 = 3.96 × 1011 J.
Therefore, the initial kinetic energy needed for the 8000 kg satellite to reach an infinite distance from Earth, neglecting the effects of air resistance in the atmosphere, is 3.96 × 1011 J.
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Elect the correct answer. Two identical projectiles, A and B, are launched with the same initial velocity, but the angle of launch is 75.0° and 15.0° respectively. Which statement is true for the two projectiles? A. The range of A and B is equal. B. The height of A is less than the height of B. C. The height of A and B is equal. D. The range of A is more than the range of B. E. The range of B is more than the range of A.
Answers
Answer:
A. The range of A and B are equal.
Explanation:
Let u be the initial speed of both the projectile.
The gravitational force acting in the projectile is in the downward direction, sp the speed of the projectile in the horizontal direction remains constant and equals to the initial horizontal speed.
For projectile, a projectile having initial velocity u at an angle \theta with the horizontal direction,
The speed in the horizontal direction \(= u\cos\theta\)
and the speed in the vertical direction is \(= u\sin\theta\) upward.
For A:
The speed in the horizontal direction \(= u\cos75^{\circ}\)
and the speed in the vertical direction is \(= u\sin75^{\circ}\) upward.
For B:
The speed in the horizontal direction \(= u\cos15^{\circ}\)
and the speed in the vertical direction is \(= u\sin15^{\circ}\) upward.
Let \(t_A\) and \(t_B\) are the time of flight for projectile A and B respectively.
As the range is the horizontal distance traveled by the projectile, so
The range for the projectile A \(= u\cos75^{\circ}\times t_A\cdots(i)\)
The range for the projectile B = \(u\cos15^{\circ}\times t_B\cdots(ii)\)
At the highest point, the vertical velocity is 0.
Bu using the equation of motion \(v^2=u^2 +2a s.\)
Here, the final velocity v=0, the initial velocity \(u = u \sin \theta\) , h= vertical distance up to the highest point, and \(a= -g\) (as per sign convention).
So, \(s= \frac{u^2\sin^2 \theta}{2g}\)
For projectile A: The maximum height attained.
\(s_A= \frac{u^2\sin^2 75^{\circ}}{2g}\)
For projectile B: The maximum height attained.
\(s_B= \frac{u^2\sin^2 15^{\circ}}{2g}\)
As \(\sin^2 75^{\circ} > \sin^2 15^{\circ}\), the height of A is attained by A is more than the heigHt attained by B.
Now, the times required to reach the highest point from the ground and again form the highest point to the ground are the same.
So, the total time of flight = 2 x (Time to reach the highest point)
In a similar way, by using the equation of motion v=u+at,
The time to reach the highest point \(=\frac {u\sin\theta}{g}\)
where g is the acceleration due to gravity.
So, the total time of flight
\(= 2 \times \frac {u\sin\theta}{g}\)
The total time of flight for A
\(=2 \times \frac {u\sin75^{\circ}}{g}\)
The total time of flight for A
\(=2 \times \frac {u\sin15^{\circ}}{g}\)
Now, from equations (i) and (ii),
The range for the projectile A =
\(u\cos75^{\circ}\times \frac {2u\sin75^{\circ}}{g}=\frac {u^2 \sin 150^{\circ}}{g}= \frac {u^2 \sin 30^{\circ}}{g}\)
The range for the projectile B =
\(u\cos15^{\circ}\times \frac {2u\sin15^{\circ}}{g}=\frac {u^2 \sin 30^{\circ}}{g}.\)
Both the projectile have the same range.
Hence, option (A) is correct.
How are density and buoyancy related to each other?
Answers
Answer:
Buoyant force is directly proportional to the density of the fluid in which an object is immersed. Buoyancy is the tendency to rise or float in a fluid. The upward force exerted on objects submerged in fluids is called the buoyant force. where ρ is the density, V is the volume, and m is the mass of the displaced fluid.
Explanation:
Answer:
well It means the plant cells inside of a organism
I'm willing to give a lot of points if u can help me out.
A. 50 ohm
B. 33 ohm
C. 20 ohm
D. 14 ohm
Answers
Answer:
i have absolutly no idea how to do it but i looked it up and your answer should be B. i could be wrong but thats what the web told me
6.(2) When X = 0.70, Y = 0.30, Z = 0.00, calculate the mean atomic mass, μ and He
Answers
To calculate the mean atomic mass, μ and He when X = 0.70, Y = 0.30, Z = 0.00, the following steps should be taken. The first step is to calculate the average atomic mass of the element.
This can be calculated using the following equation:μ = (X × mX) + (Y × mY) + (Z × mZ)where:X = the mass fraction of the first isotope Y = the mass fraction of the second isotopeZ = the mass fraction of the third isotopem X = the mass of the first isotope in atomic mass units (amu)mY = the mass of the second isotope in amumZ = the mass of the third isotope in amu The second step is to calculate the mass of He produced in the reaction. This can be done using the following equation:Mass of He = (Y × mHe) / 2where:mHe = the mass of helium in amuTo calculate the mean atomic mass, μ and He when X = 0.70, Y = 0.30, Z = 0.00, we can use the following values:X = 0.70Y = 0.30Z = 0.00mX = 12.00 amumY = 13.01 amumZ = 14.01 amumHe = 4.00 amu Using the equation above, we can calculate the average atomic mass as follows:μ = (0.70 × 12.00) + (0.30 × 13.01) + (0.00 × 14.01)= 8.40 + 3.90 + 0= 12.30 amu The mass of He produced can be calculated as follows:Mass of He = (0.30 × 4.00) / 2= 0.60 / 2= 0.30 amu Therefore, when X = 0.70, Y = 0.30, Z = 0.00, the mean atomic mass is 12.30 amu and the mass of He produced is 0.30 amu.For such more question on average
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48) During an experiment in physics class, a student places a large block on a plank.
The student raises one end of the plank to form an incline until just before the
block starts to slide down. The block experiences a force of 26 N parallel to the
incline and 42 N perpendicular to the incline. What is the coefficient of static
friction such that the block stays at rest?
Answers
Answer:
Below
Explanation:
The block does not slide, so the force of friction equals the down the slope force. Ff = 26 n the Fn is given as 42 N
Definition of static coefficient of friction = Ff/Fn = 26/42 = .62
how much does a change in mass affect the kinetic energy of two balls of comparable diameter?
Answers
Answer:
Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant.
In this state, Kinetic energy is equal to half of the product mass and velocity. SI unit is joules. So it's if the mass is doubled then the kinetic energy also gets doubled.
Which of the following
is FALSE about forces?
A. Forces can cause change.
B. Forces act in pairs.
C. Forces cannot be quantified.
Answers
Forces always act in pairs and are subject to change
A wheel with radius r rotates freely about its axle with initial angular speed ωi. A point on the wheel's rim moves at linear speed v.
Suddenly, the wheel accelerates so the point moves at linear speed 3v. The final angular speed is ωf.
How does the angular speed of the wheel change?
Answers
Answer:
\(\dfrac{2\omega_i}{t}\)
Explanation:
r = Radius of wheel
v = Initial linear speed
3v = Final linear speed
Initial angular speed is given by
\(\omega_i=\dfrac{v}{r}\)
Final angular speed after time \(t\) is given by
\(\omega_f=\dfrac{3v}{r}\\\Rightarrow \omega_f=3\dfrac{v}{r}=3\omega_i\)
The angular acceleration of the wheel will give us how the angular speed of the wheel changes.
From the equations of rotational motion we have
\(\omega_f=\omega_i+\alpha t\\\Rightarrow 3\omega_i=\omega_i+\alpha t\\\Rightarrow \alpha=\dfrac{3\omega_i-\omega_i}{t}\\\Rightarrow \alpha=\dfrac{2\omega_i}{t}\)
The acceleration wheel is \(\dfrac{2\omega_i}{t}\).
Answer:increases by a factor of 3
Explanation: just trust me bro
a binary star that varies in apparent brightness as one member of the binary passes in front of the other is group of answer choices an astrometric binary a visual binary an eclipsing binary a spectroscopy binary impossible, unless at least one of the two stars itself is intrinsically variable
Answers
A binary star that varies in apparent brightness as one member of the binary passes in front of the other is a group of an eclipsing binary.
An eclipsing binary is a group of binary stars that varies in apparent brightness as one member of the binary passes in front of the other. This phenomenon is known as an eclipse, where the eclipsing star partially or completely blocks the light from the other star, resulting in a decrease in apparent brightness.
Eclipsing binaries are characterized by periodic variations in their light curves, which can provide valuable information about the stars' physical properties, such as their sizes, masses, and orbital parameters. The variations in brightness observed in an eclipsing binary are caused by the alignment and relative positions of the stars in their orbit, making it a distinct category among binary star systems.
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A car with a mass of 1600 kg is towing a trailer with a mass of 420 kg. The car
provides a forward thrust of 3300 N. What is the acceleration of the trailer?
Answers
Answer:
1.63366
Explanation:
I got this answer from calculator soups physics calculators. I really recommend their website for formulas.
An aircraft engine takes in an amount 9200 J of heat and discards an amount 6600 J each cycle. What is the mechanical work output of the engine during one cycle? What is the thermal efficiency of the engine? Express your answer as a percentage.
Answers
Work output is 2600 J, Thermal efficiency is 28.26%.
What is the mechanical work output and thermal efficiency of the engine during one cycle?To determine the mechanical work output and thermal efficiency of the engine, we need to use the first law of thermodynamics, which states that energy input equals the sum of energy output and work done.
Given:
Heat input (Qin) = 9200 J
Heat output (Qout) = 6600 J
Mechanical work output (W) can be calculated using the equation:
W = Qin - Qout
Substituting the given values:
W = 9200 J - 6600 J
W = 2600 J
The mechanical work output of the engine during one cycle is 2600 J.
Thermal efficiency (η) can be calculated using the equation:
η = (W / Qin) * 100
Substituting the values:
η = (2600 J / 9200 J) * 100
η ≈ 28.26%
Therefore, the thermal efficiency of the engine is approximately 28.26%.
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23 and 24 only please help!
Answers
Answer:
23: Acceleration 24:1m/s^2
Explanation:
\(a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2\)
Q3) Find the heat energy required to increase the temperature of 3.5 kg of steel from 500 °C to 600 °C.
Answers
Answer:
157.5 KJ
Explanation:of
Specific heat capacity of steel is 450 J/ kg-°C.
So to raise temperature of 3.5 kg of steel from 500°C to 600°C is
= ( 450 * 3.5 * ( 600-500 ) )
= 157500
when was the Hubble telescope launched
Answers
What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2
Answers
Answer:
5 m/s²
Explanation:
Acceleration = change in speed/time taken
20-5=15
15/3= 5 m/s²
Which of the following scenarios is best matched by the velocity-time graph shown?
Select one:
a. The object is slowing down.
b. The object is not moving.
c. The object is speeding up.
d. The object has a constant speed.
Answers
The scenario best matched by the velocity-time graph shown is:
d. The object has a constant speed.
What is Velocity ?
Velocity is a vector quantity that describes the rate of change of an object's position with respect to time, in a particular direction. It is a measure of how fast and in which direction an object is moving. Velocity is typically measured in meters per second (m/s) or other units of distance per unit of time, such as feet per second (ft/s) or kilometers per hour (km/h).
In physics, velocity is often used in the context of describing the motion of objects, such as cars, airplanes, and planets. It is also an important concept in calculus and other areas of mathematics, where it is used to describe the rate of change of a function with respect to its input.
The reason for this is that the velocity-time graph shows a straight line with a constant slope, which means that the velocity (speed and direction) of the object is not changing over time. In other words, the object is moving at a constant speed.
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
Answers
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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how many types of classifications are there for a lunar eclipse?
Answers
There are three types of lunar eclipses: total, partial, and penumbral.
During a total lunar eclipse, the moon is completely shadowed by the Earth, resulting in a reddish-brown color. In a partial lunar eclipse, only a portion of the moon is shadowed, while in a penumbral lunar eclipse, the moon passes through the Earth's outer shadow, resulting in a subtle darkening of the moon's surface. These classifications are based on the degree to which the moon passes through the Earth's shadow during the eclipse.
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Which statement correctly compares sound and light waves?
A.Both light and sound waves need matter to carry energy from one place to another.
B.Neither light nor sound waves need matter to carry energy from one place to another.
C.Light waves carry energy parallel to the motion of the wave, while sound waves carry energy perpendicular to it.
D.Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
Answers
Answer:
The correct answer is D.Sound waves carry energy parallel to the motion of the wave, while light waves carry energy perpendicular to it.
Explanation:
Just got the answer correct.
Materials that hold electrons very tightly, and thus don't allow much static electricity to occur around them, are called
Answers
with aid of diagrams state the laws of reflection and refraction.
Answers
Light reflects from surfaces in such a way that the angle of incidence equals the angle of reflection. Both angles are measured from the normal line perpendicular to the reflecting surface, as shown in the diagram:
Law of refraction (Snell's Law)Light is refracted when it travels through the frontier between two media. If the medium 1 has an index of refraction n₁ and the medium 2 has an index of refraction n₂, then the angle of incidence θ₁ and the angle of refraction θ₂ satisfy the following equation:
\(n_1\sin\theta_1=n_2\sin\theta_2\)
A student is building a model of a lens that will spread light over the biggest space. Which best describes the type of model the student should make?
O A The student should make a convex lens model because it directs light away from the center of the lens.
OB. The student should make a concave lens model because it breaks light down into bands of color
c. The student should make a concave lens model because it directs light away from the center of the lens
D. The student should make a convex lens model because it breaks light down into bands of color.
Answers
Answer:
C. The student should make a concave lens model because it directs light away from the center of the lens
Explanation:
The student should make a concave lens model because it directs light away from the center of the lens.
What is Concave lens?A lens that has at least one inward-curving surface is said to be concave. Since it is a divergent lens, light rays that have been bent by it are dispersed. Short-sightedness is treated by concave lenses, which are thinner in the center than the borders (myopia).
The earliest known usage of a corrective lens is mentioned in Pliny the Elder's writings (23–79). Pliny claims that Emperor Nero used an emerald, perhaps concave formed to adjust for myopia, to watch gladiatorial matches.
After passing through the lens, light beams appear to originate from a spot known as the primary focus.
Therefore, The student should make a concave lens model because it directs light away from the center of the lens.
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the two forces shown acting on square . determine the magnitude of F, which will cause zero moment at point 0
Answers
Answer: u excited for the super bowl?
Explanation:
What is the magnitude of the net force F on a 1.4 kg bathroom scale when a 75 kg person stands on it? ΣF =
Answers
The magnitude of the net force F on a 1.4 kg bathroom scale when a 75 kg person stands on it is 735 N.
When a person stands on a bathroom scale, the scale measures the force exerted by the person's weight. The weight of an object is the force exerted on it due to gravity. In this case, the weight of the person is given as 75 kg.
The net force acting on the bathroom scale is equal to the force exerted by the person's weight. According to Newton's second law of motion, force (F) is equal to mass (m) multiplied by acceleration (a). In this scenario, the person is standing still, so the acceleration is zero. Therefore, the net force is simply the weight of the person.
To calculate the weight, we use the formula weight = mass × gravitational acceleration. The gravitational acceleration on Earth is approximately 9.8 m/s². Plugging in the values, we have:
Weight = 75 kg × 9.8 m/s² = 735 N
Therefore, the magnitude of the net force F on the 1.4 kg bathroom scale when a 75 kg person stands on it is 735 N.
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Susie rolls a bowling ball down the alley and knocks over most of the pins. Explain why fewer pins were knocked over when her little brother rolled a basketball, at the same velocity, down the alley.
Answers
Answer:
The force used
Explanation:
This has to be because of the force used. Both Susie and her younger brother might have hit the ball with the same velocity, but they surely couldn't have hit it with the same force. The force with which Susie hurts it is heavier than that with which her younger brother hits it, and as such, Susie gets to fall down more pins than her brother will be able to. The ball has to have a lot of force in it for it to be able to knock off all the pins there. So basically, the more the force, the higher it's chances of hitting all the pins
Which type of mirror causes beams of light to spread apart?.
Answers
The edges of the mirror curve away from you. A convex mirror makes reflected light rays spread out.
Explanation:
Hope it helps you!!A cube measures 3cm on each side has a mass of 25 grams. what it its density and relative density.
Answers
Answer:
Density= 2.78 g/cm³
Relative density=2.8
Explanation:
To calculate the density of the cube we have to use the formula ρ=mass/volume
ρ stands for density.
So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³
3³= 9 cm³
Now plug in the values. ρ= 25 g/9 cm³
ρ= 2.78 g/cm³
To find the relative density, we have to use the formula ρsample/ρH20
The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.
Now we have to make the units same so you change the unit of the density of cube to kg/m³
So, 25/1000= 0.025 kg
9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)
=0.000009 m³
The new density= 0.025 kg/ 0.000009 m³
= 2777.78 kg/m³
Now plug the values into the formula:
relative density= 2.777.78 kg/m³ / 997 kg/m³
=2.8
There is no unit since kg/m³ and kg/m³ cancels
The density of silver is 10.49 g/cm3. If a sample of pure silver has a volume of 12.993 cm3, what is the mass?
Answers
Explanation:
Density=mass/volume
mass=x
10.49=X/12.99
X=10.49 X12.99
X=136.29657
mass=136.3g/cm^3
I hope it helped.