If the molal concentration in water is the same for the following substances, rank these solutions in decreasing melting point. Highest placed in the rank will have the highest melting point.


calcium phosphate, Ca3(PO4)2


glucose, c6h12o6


sodium chloride, NaCl


magnesium chloride, MgCl2

Polar molecules have an uneven distribution of electron density due to the presence of polar bonds and/or lone pairs of electrons.

In PF3, the phosphorus atom is bonded to three fluorine atoms and has one lone pair of electrons, causing an asymmetrical electron distribution and making it polar. Similarly, in SO2, the sulfur atom is bonded to two oxygen atoms and has one lone pair of electrons, resulting in a bent molecular shape and making it polar.

In OCl2, the central chlorine atom is bonded to two oxygen atoms, and it also has two lone pairs of electrons. The bent molecular geometry and the presence of lone pairs lead to an uneven distribution of electron density, making OCl2 a polar molecule.

On the other hand, CCl4 (carbon tetrachloride) has a symmetrical tetrahedral molecular geometry, with the four chlorine atoms surrounding the central carbon atom.

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Answer: 2.62 moles

Explanation:

For every 2 moles of ammonia that are produced, 1 mole of nitrogen is consumed.

This means that if 5.24 moles of ammonia are produced, 5.24/2=2.62 moles of nitrogen are consumed.

Answer:

As a rough rule, five pounds of dry ice will turn from a solid to a gas in 24 hours. It's best to pick up the block of ice just a few hours before your party so it's as frozen as possible when the bash starts.

Explanation:

Given;At t = 0 seconds, the concentration of S2O8^-2 is 0.010 MThe half-life for the decomposition of S2O8^-2 is 75 seconds. The concentration of S2O8^-2 remaining at 1600 s is___3.635 x 10^-7 ___ M.

To solve this, we need to use the first-order reaction equation, which is:k = 0.693/t1/2Wherek is the rate constantt1/2 is the half-life of the reaction from the equation, the rate constant (k) can be calculated by;k = 0.693/t1/2 = 0.693/75 = 0.00924s^-1Let's find the concentration of S2O8^-2 after 1600 s using the first-order rate law equation. The equation is;ln([S2O8^-2]t/[S2O8^-2]0) = -ktWhere[S2O8^-2]t is the concentration at the remaining time[S2O8^-2]0 is the initial concentration oft = the remaining timek = the rate constantln = natural logSubstituting the given values in the equation;ln([S2O8^-2]t/0.010) = -0.00924 x 1600ln([S2O8^-2]t) = -14.784[S2O8^-2]t = e^-14.784[S2O8^-2]t = 3.635 x 10^-7 MConsequently, the concentration of S2O8^-2 remaining at 1600 s is 3.635 x 10^-7 M.

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The final temperature of the gas is approximately 40.96 Kelvin.

To determine the final temperature of the gas, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the given temperatures to Kelvin. We have:

Initial temperature: -125 degrees Celsius = 148 K (approximate)

Final temperature: Unknown

The initial conditions of the gas are as follows:

Initial pressure (P1) = 1.25 atm

Initial volume (V1) = 1250 mL = 1.25 L (since 1 L = 1000 mL)

Initial temperature (T1) = 148 K

The final conditions of the gas are as follows:

Final pressure (P2) = 50.0 atm

Final volume (V2) = 325 mL = 0.325 L

Final temperature (T2) = Unknown

Using the ideal gas law, we can set up the following equation:

(P1 * V1) / T1 = (P2 * V2) / T2

Substituting the known values:

(1.25 atm * 1.25 L) / 148 K = (50.0 atm * 0.325 L) / T2

Simplifying the equation:

T2 = (50.0 atm * 0.325 L * 148 K) / (1.25 atm * 1.25 L)

T2 = 40.96 K

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Scientist are able to see smaller cells due to the large scale of magnification of new microscopes.

The term cell refers to the simplest or the smallest unit of an organism. All organisms are composed of cells and cells come from cells. This implies that cells come from the replication of cells in the body.

Now, there are several kinds of microscopes that are in existence such as;

The scale of microscopes continue to improve as technology improves. Thus we have larger magnification and scientist are able to see smaller cells due to the large scale of magnification of new microscopes.

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Enamines are a class of nitrogen-containing compounds that include both nitrogen and carbon. A primary amine and a carbonyl compound are used to form enamines. The enamine structure of the product formed between acetophenone and dimethylamine is shown below:

     H                       H

      |                         |

  H3C-C          C-N(CH3)2

      |      + H2O ->    |

  C=O                     C

     |                          |

   Ph                       H

The product is N,N-dimethylcinnamamide.

In this process, an imine intermediate is produced first, which is then converted into an enamine. In this reaction, dimethylamine is used as a primary amine and acetophenone is used as a carbonyl compound. The nitrogen atom of dimethylamine is nucleophilic, and it can donate electrons to the carbonyl carbon of acetophenone.

This causes a pi bond to form between the carbon and the nitrogen atoms. The nitrogen atom also has a lone pair of electrons that can bond to a hydrogen atom. The enamine formed as a result of this reaction is shown above. The enamine has a double bond between the nitrogen and carbon atoms and a hydrogen atom bonded to the nitrogen atom.

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The hindbrain consists of the brain stem which encompasses the medulla oblongata, pons, and cerebellum. The Option B.

These structures are located at the base of the brain and are responsible for essential functions such as regulating vital autonomic processes, controlling balance and coordination .

It also relays sensory and motor information between the brain and the rest of the body. The hindbrain plays a crucial role in maintaining basic bodily functions and facilitating smooth movement. Therefore, the Option B is correct.

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Here are three steps Madison can take to molten manage her debt in the most responsible way possible:1. Create a budget: The first thing Madison should do is create a budget.

Madison should start by listing all of her monthly expenses, including rent, utilities, groceries, transportation, and any debt payments. She should also include her monthly income.2. Prioritize her debt: Madison should prioritize her debt by paying off the debt with the highest interest rate first. This will help her save money in the long run by reducing the amount of interest she has to pay. Madison should also consider consolidating her debt to simplify her payments and potentially lower her interest rates.

Madison should prioritize her debt by paying off the debt with the highest interest rate first. This will help her save money in the long run by reducing the amount of interest she has to pay. Madison should also consider consolidating her debt to simplify her payments and potentially lower her interest rates.3. Build an emergency fund: Finally, Madison should build an emergency fund. This will help her avoid relying on credit cards or other forms of debt in case of unexpected expenses, such as a car repair or medical bill. Madison should aim to save at least three to six months’ worth of expenses in her emergency fund.

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The first one appear to be a pan with some liquid heating up.

The beginning state is liquid, the phase change type is a vaporization and its ending state is gas.

The second one seems to be a ice cube melting.

Its beginning phase is solid, the phase change type is fusion, and its ending state is liquid.

The third one is water, or other liquid, making clouds.

The beginning state is liquid, the phase change type is a vaporization and its ending state is gas.

The fourth illustration seems to be an aluminium can. There aren't really a phase change happening, but when we open the aluminium can containing gaseous drink, there are molecules of gas diluted into the liquid and some of it encouter each other to make a bubble of the gas and is released. It is not an actually phase change, it is the reverse process of diluting gas into liquid. Initially it is diluted gas, it gets released and in the end it is in gas phase.

The activation energy of the reaction is approximately 71.46 kJ/mol, rounded to 2 decimal places.

To find the activation energy (Ea) of the reaction, we can use the Arrhenius equation, which relates the rate constant (k) to the temperature (T) and activation energy. The Arrhenius equation is given by:

k = A * e^(-Ea/RT)

Where:

k is the rate constant

A is the pre-exponential factor (frequency factor)

Ea is the activation energy

R is the gas constant (8.314 J/(mol·K))

T is the temperature in Kelvin

We have two sets of data:

At 600 K, k1 = 3.4 m^(-1)s^(-1)

At 750 K, k2 = 31.0 m^(-1)s^(-1)

Taking the natural logarithm (ln) of both sides of the Arrhenius equation, we can rearrange the equation to solve for the activation energy:

ln(k) = ln(A) - (Ea/RT)

We can create two equations using the given data:

ln(k1) = ln(A) - (Ea/(R * 600))

ln(k2) = ln(A) - (Ea/(R * 750))

Subtracting the second equation from the first eliminates the ln(A) term:

ln(k1) - ln(k2) = (Ea/R) * ((1/600) - (1/750))

Simplifying further:

ln(k1/k2) = (Ea/R) * ((750 - 600) / (600 * 750))

Now we can solve for Ea:

Ea = (R * (ln(k1/k2))) / ((750 - 600) / (600 * 750))

Using the given values and the appropriate units:

Ea = (8.314 J/(mol·K) * ln(3.4/31.0)) / ((750 - 600) / (600 * 750))

Converting the units from J to kJ:

Ea = (8.314 × 10^(-3) kJ/(mol·K) * ln(3.4/31.0)) / ((750 - 600) / (600 * 750))

Ea ≈ 71.46 kJ/mol

Therefore, the activation energy of the reaction is approximately 71.46 kJ/mol, rounded to 2 decimal places.

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Whereas physical changes entail a change in a substance's physical attributes without the creation of new substances, chemical changes involve the rearranging of atoms and the creation of new substances.

According to the concept of "The Lost Isle of Change," once a material experiences a chemical shift, it is difficult to restore it to its previous condition, much like an island that vanishes after it has sunk. Nonetheless, substances that are changing physically are frequently simple to reverse, much like an island that may reemerge as the sea recedes. In conclusion, physical changes frequently entail a change in physical attributes, whereas chemical changes involve the synthesis of new substances and are reversible. The irreversibility of chemical changes is symbolised by "The Lost Island of Change."

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Full Question

What is the difference between chemical and physical changes, and how do they relate to the concept of "The Lost Isle of change"?

Answer:

10 L

Explanation:

Boyle's Law

Our values

Using the equation

Answer:

0.25L

Explanation:

Answer:

B: Atomic size

Explanation:

I just guess for the points

Answer: hydrogen + oxygen Right arrow .water

Explanation:

The exact equation for this reaction is;

2H2  +  O2 ------------->   2H2O

hydrogen + oxygen Right arrow. water is the correct option.

The equation shows hydrogen reacting with oxygen to form water is as follows:-

\(2H_2+O_2\rightarrow2H_2O\)

The above reaction in word form is written as follows:-

\(hydrogen+Oxygen \rightarrow water\)

So, hydrogen + oxygen Right arrow. water is the correct option.

Hydrogen-H

Oxyden-O

Water-\(H_2O\)

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Energy consumption in the cloud refers to the amount of energy used by data centers and other infrastructure that provide cloud computing services.

This includes the energy used to power servers, cooling systems, and networking equipment, as well as the energy used to transport data over networks.

As cloud computing has become increasingly popular, energy consumption has become a significant concern for both cloud providers and users, as the energy required to run data centers can be substantial. To mitigate this, cloud providers are investing in more energy-efficient technologies and practices, such as using renewable energy sources and implementing more efficient cooling systems.

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The pH of the solution in the lead-acid battery to produce its standard cell potential of 2.05 V is: 0.

To find the pH at which the lead-acid battery produces its standard cell potential of 2.05 V, we will use the Nernst equation. The Nernst equation is given as:
E_cell = E°_cell - (RT/nF) * ln(Q)
where E_cell is the cell potential,
E°_cell is the standard cell potential,
R is the gas constant,
T is the temperature in Kelvin,
n is the number of electrons transferred in the redox reaction,
F is the Faraday's constant, and
Q is the reaction quotient.

For a lead-acid cell at standard conditions, we have:
E°_cell = +2.05 V (given)
Q = [H+]² / [Pb²+] * [SO₄²-] (since H₂SO₄ dissociates completely)

We can assume that the concentrations of Pb²+ and SO₄²- ions are constant, so we only need to find [H+], which will allow us to calculate the pH of the solution. To do this, we can rewrite the Nernst equation:
2.05 V = 2.05 V - (RT/2F) * ln([H+]²)

Since E_cell = E°_cell under standard conditions, the right side of the equation simplifies to zero:
0 = - (RT/2F) * ln([H+]²)

Next, we can solve for [H+]:
ln([H+]²) = 0
[H+]² = 1
[H+] = 1

Now, we can calculate the pH using the definition of pH:
pH = -log([H+])
pH = -log(1)
pH = 0

So, the pH of the solution in the lead-acid battery must be 0 to produce its standard cell potential of 2.05 V.

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Answer:

1. (put in simpler words so no one knows you got it off of brainly)

The electricity that flows to our homes is generated in power stations. From here, it flows through large transmission lines, which carry it to substations. Finally, distribution lines carry electricity from substations to houses, businesses, and schools.

2.  (put in simpler words so no one knows you got it off of brainly)

The transmission over long distances creates power losses. The major part of the energy losses comes from Joule effect in transformers and power lines. The energy is lost as heat in the conductors. This can be minimized by

answer choice 1: reducing technical losses including: replacing incorrectly sized transformers, improving the connection quality of conductors (power lines), and increasing the availability of reactive power by installing capacitor banks along transmission lines.

answer choice 2: (just in case answer choice 1 isn't what you're looking for)

You can reduce losses in your home by spreading out your electricity use evenly throughout the day, instead of running all your appliances at once.

Explanation:

hope this helped <3

Answer:

Explanation:

Here, we want to check if the equation of the reaction is balanced or not

Now, for a balanced equation of reaction, the number of atoms of the individual elements on both sides of the equation is equal

Now, let us check the atoms:

We have 1 Sr on both sides

We have 1 SO4 on both sides

We have 1 Mg on both sides

We have 2 OH on both sides

From what we can see, the equation of the reaction is balanced

Thus, the correct answer choice is B

The pair that is not a conjugate base-acid pair is: HSO₄⁻ : SO₂⁻⁴. Option 4 is correct.

HSO₄⁻ is the conjugate base of H₂SO₄ (sulfuric acid), and SO₂⁻⁴ is not a valid acid because it has a charge of -2 and cannot donate a proton (H⁺). Therefore, HSO₄⁻ and SO₂⁻⁴ do not form a conjugate base-acid pair.

A conjugate base is the species that remains after a Bronsted-Lowry acid has donated a proton (H⁺). It is formed when an acid loses a proton and the resulting species has one less positive charge.

For example, in the reaction;

HA + H₂O ↔ A⁻ + H₃O⁺

HA is the acid and donates a proton to H₂O, which acts as a base to form the conjugate base A-. The species A⁻ is the conjugate base of the acid HA.

Hence, 4. is the correct option.

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cleaning up and disposing of broken glass.

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

Put the given values into the formula and calculate for n:

The number of moles of the gas sample is 1.0 mol.

75% dominant and 25% resistive

a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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The standard enthalpy change for the dehydration of 2-methylpropene is + 32 kJ mol-1. It can be calculated using the formula of standard enthalpies of formation of the reactants and products.

The equation for this reaction is:
(CH3)2CHCH2OH(l) → (CH3)2C=CH2(g) + H2O(l)

The standard enthalpy change for this reaction is:

ΔH° = ΣΔHf°(products) - ΣΔHf°(reactants)

ΔH° = [(ΔHf°(2-methylpropene) + ΔHf°(water)] - [ΔHf°(2-methylpropan-1-ol)]

ΔH° = [(-17 kJ mol-1) + (-286 kJ mol-1)] - [(-335 kJ mol-1)]

ΔH° = (-303 kJ mol-1) - (-335 kJ mol-1)

ΔH° = 32 kJ mol-1

Therefore, the standard enthalpy change for the dehydration of 2-methylpropene is +32 kJ mol-1.

The correct answer is option D.

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When 32.0 g of NaCl are dissolved in water and diluted to 0.500 L, 1.10 M of NaCl is the formal concentration (expressed as mol/L or M).

To find the formal concentration, we need to determine the number of moles of NaCl present in the solution. The molar mass of NaCl is 58.44 g/mol, so to find the number of moles, we divide the mass of NaCl by its molar mass:

Number of moles = Mass / Molar mass of sodium chloride (NaCl)

Number of moles = 32.0 g / 58.44 g/mol = 0.548 mol

Next, we need to calculate the formal concentration by dividing the number of moles by the volume of the solution in liters:

Formal concentration = Number of moles / Volume of solution

Formal concentration = 0.548 mol / 0.500 L = 1.10 M.

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A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, chlorine gas reacts with pottasium iodide to produce iodine and pottasium chloride as follows:

Cl₂ + 2KI → 2KCl + I₂

Therefore, the answers to the questions are as indicated in the main answer part.

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Answer: 164.09 g/mol

Explanation:

In the given reaction  ₉₆²⁴⁶Cm + ₆¹²C ---> 4 ¹on + X  it shows an example of an artificial transmutation reaction.

An artificial transmutation reaction may resemble this. The method of causing nuclear reactions by blasting atomic nuclei with high-energy particles like ions or neutrons is referred to as artificial transmutation.

In this instance, the transmutation is induced by bombarding the carbon nucleus (C) with additional particles or a high-energy beam, resulting in the production of the following products: Element X and 4 1on (Helium-4)

Blasting an element with a basic particle, an element can be artificially transmuted into a different element.

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Answer:

V  = 65.81 L

Explanation:

En este caso, debemos usar la expresión para los gases ideales, la cual es la siguiente:

PV = nRT  (1)

Donde:

P: Presion (atm)

V: Volumen (L)

n: moles

R: constante de gases (0.082 L atm / mol K)

T: Temperatura (K)

De ahí, despejando el volumen tenemos:

V = nRT / P   (2)

Sin embargo como estamos hablando de condiciones normales de temperatura y presión, significa que estamos trabajando a 0° C (o 273 K) y 1 atm de presión. Lo que debemos hacer primero, es calcular los moles que hay en 50 g de amoníaco, usando su masa molar de 17 g/mol:

n = 50 / 17 = 2.94 moles

Con estos moles, reemplazamos en la expresión (2) y calculamos el volumen:

V = 2.94 * 0.082 * 273 / 1