If the hydrogen ion concentration of an unknown solution is 7.89E-4, what is its pH and will this form an acid or a base?

Answer:  

I think F

Explanation:

Let's start by balancing the reaction:

As we can see, C appears only on two comopunds, CO and CO₂, and since both have 1 C each, their coefficients have to be the same for C to be balanced. However, CO has 1 O and CO₂ has 2, so there is a difference of 1 O betwee them.

The other source of O is Fe₂O₃, that has 3 O. So, we must choose a coefficient for CO and CO₂ such that the difference between the numbers of O is a multiple of 3, that way we can fix this difference with the O from Fe₂O₃. So, we can put coefficients of 3 on both of them:

That way, we maintained C balanced (3 on each side) and now we have 3 + 3 O on the left side and 6 O on the right side, so the same amount.

Now, we just have to calance Fe, but it is easy since we have it alone in Fe. Since we have 2 on the left side, it is enough to put a coefficient of 2 on Fe to get the balanced reaction:

Now, to convert from mass to number of moles, we need the molar masses of the reactants, which we can calculate from the atomic weights of the elemnts in each of them:

Now, we can convert their masses to number of moles:

Now, to determine the limiting reactant, we need to divide both the number of mole by their coefficients on the balanced reaction, so we can see how many we need per reaction of each:

Now, the limiting reactant is the one we have less number of moles per reaction. We can see that we have less CO than Fe₂O₃, so the limiting reactant is CO.

The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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The pressure inside the tire, converted to pascals, is approximately 8,555 N/m^2, or 8.56 × 10^3 Pa, using the appropriate number of significant figures.

To convert the pressure from pounds per square inch (psi) to pascals (Pa), we need to use the given conversion factors:

1 pound = 4.45 newtons

1 inch^2 = 6.45 centimeters^2 = (6.45/100)^2 square meters

First, let's convert psi to newtons per square inch (N/in^2):

28.0 psi * 4.45 N = 124.6 N/in^2

Now, let's convert newtons per square inch to pascals:

124.6 N/in^2 * ((6.45/100)^2) m^2 = 8,555.4125 N/m^2 (approximately)

To express the answer to the correct number of significant figures, we need to determine the number of significant figures in the given pressure value. Since the pressure is given as "28.0," it implies that there are three significant figures. Therefore, the pressure inside the tire, converted to pascals, is approximately 8,555 N/m^2, or 8.56 × 10^3 Pa, using the appropriate number of significant figures.

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Option D) 180K is the correct answer.

Hence, the temperature of the gas before the pressure changed is 180K

Gay-Lussac's law states that "the pressure exerted by a given mass of gas at constant volume varies directly with its absolute temperature".

It is expressed as;

\(\frac{P_1}{T_1} = \frac{P_2}{T_2}\)

Given the data in the question;

Initial pressure of gas; \(P_1 = 0.5atm\)

Final pressure of gas; \(p_2 = 2.5atm\)

Final temperature; \(T_2 = 900K\)

Initial temperature before pressure change; \(T_1 = \ ?\)

We substitute our given values into the expression above.

\(\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\\frac{0.5atm}{T_1} = \frac{2.5atm}{900K}\\\\T_1 = \frac{0.5atm\ *\ 900K}{2.5atm}\\ \\T_1 = \frac{450K}{2.5}\\\\T_1 = 180K\)

Option D) 180K is the correct answer.

Hence, the temperature of the gas before the pressure changed is 180K.

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Precipitation, evaporation, freezing and melting and condensation are all part of the ... of water circulation from clouds to land, to the ocean, and back to the clouds. ... Water evaporates from the surface of the ocean, mostly in warm, cloud-free ... is a continuous exchange of moisture between the oceans, the atmosphere.

Answer:

The right answer for the question that is being asked and shown above is that: "B. condensation from the ocean and then evaporation into a cloud." a water molecule transfer from the ocean to form part of a cloud in the atmosphere is that condensation from the ocean and then evaporation into a cloud

Explanation:

do you have the specific heat for part 2?

Answer:

Brightness

Explanation:

Answer:

Brightness  is the property that enable the panning of gold possible

Each person should choose 6 items from Column A and 4 items from Column B, ensuring that everyone orders the same number of items from each column. Option B

To divide the items evenly among four people while ensuring that each person orders the same number of items from each column, we need to find the common divisor of the number of items in each column.

Column A has 24 items, and Column B has 16 items. The common divisor of 24 and 16 is 8. Therefore, each person should choose 8 items.

Since there are 24 items in Column A, and each person needs to choose 8 items, the answer is 24 divided by 8, which equals 3. Each person should choose 3 items from Column A.

Similarly, since there are 16 items in Column B, and each person needs to choose 8 items, the answer is 16 divided by 8, which equals 2. Each person should choose 2 items from Column B.

Therefore, the correct answer is:

B) 6 from A, 4 from B

Each person should choose 6 items from Column A and 4 items from Column B, ensuring that everyone orders the same number of items from each column.

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1. A lunar eclipse occurs when the Earth comes between the Sun and the Moon, casting a shadow on the Moon. The main cause of a lunar eclipse is the alignment of the Earth, Moon, and Sun in a straight line. The Earth blocks the direct sunlight from reaching the Moon, causing the Moon to be partially or completely in the Earth's shadow. This can only happen during a full moon when the Sun, Earth, and Moon are in a straight line.

2. A solar eclipse happens when the Moon comes between the Sun and the Earth, blocking the sunlight from reaching certain parts of the Earth. This occurs during a new moon when the Moon is directly between the Sun and Earth. The Moon's shadow falls on a specific region on Earth, creating a temporary darkening of the sky. There are different types of solar eclipses, such as total, partial, and annular, depending on the alignment of the Sun, Moon, and Earth.

3. During a lunar eclipse, when the Moon is in the Earth's shadow, it may appear to turn a reddish color. This phenomenon is known as the "blood moon." The red color is caused by the Earth's atmosphere bending (refracting) sunlight and filtering out shorter wavelengths such as blue and green. The longer wavelengths, such as red and orange, are scattered and make their way onto the Moon's surface, giving it a reddish hue. This effect is similar to the way the atmosphere scatters sunlight during a sunrise or sunset, causing the sky to appear red or orange.

It's important to note that the specific color and intensity of a lunar eclipse can vary based on factors such as the Earth's atmospheric conditions, the amount of dust and pollutants in the atmosphere, and the angle at which sunlight passes through the atmosphere. So, the exact appearance of a lunar eclipse may differ from one event to another.

The mixing of acetic acid with sodium acetate will produce a buffer solution with a pH value is > 7.0, hence option B is correct.

The pH scale determines how acidic or basic water is. The range is 0 to 14, with 7 representing neutrality.

Acidity is indicated by pH values below 7, whereas baseness is shown by pH values above 7. In reality, pH is a measurement of the proportion of free hydrogen and hydroxyl ions in water.

When sodium acetate is added to an acetic acid solution, the pH value rises because the concentration of h+ ions drops as the salt concentration rises in the buffer solution.

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The balanced chemical equation for the reaction between hydrochloric acid (HCI) and sodium hydroxide (NaOH) is:

HCI + NaOH -> NaCl + H2O

From the equation, we can see that 1 mole of HCI reacts with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of water.

First, let's calculate the number of moles of HCI in 250 mL of 0.25 M solution:

Molarity (M) = moles of solute / volume of solution (L)

0.25 M = moles of HCI / 0.25 L

moles of HCI = 0.25 L x 0.25 M = 0.0625 moles

Since 1 mole of NaOH reacts with 1 mole of HCI, we will need 0.0625 moles of NaOH to neutralize the HCI.

Now, let's calculate the volume of 0.9 M NaOH solution needed to provide 0.0625 moles of NaOH:

Molarity (M) = moles of solute / volume of solution (L)

0.9 M = 0.0625 moles of NaOH / volume of NaOH solution (L)

volume of NaOH solution (L) = 0.0625 moles / 0.9 M = 0.0694 L = 69.44 mL

Therefore, 69.44 mL of 0.9 M NaOH solution would be required to titrate 250 mL of 0.25 M HCI solution.

Dalton asserted the indivisible nature of atoms. The mass and chemical characteristics of all atoms of a specific element are the same.

Atoms of two different elements combine to form compounds: Dalton's atomic theory states that atoms of different elements can combine in different proportions to form compounds.

Atoms of an element are identical to atoms of other elements: Dalton's atomic theory states that atoms of the same element have the same properties and composition.

Every element is made of atoms: Dalton's atomic theory states that all elements are made up of atoms, which are the smallest indivisible particles of matter.

In a chemical reaction, some atoms disappear and new atoms appear: Dalton's atomic theory states that in a chemical reaction, atoms are neither created nor destroyed, but simply rearranged into new combinations.

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"Fluorine (F) would have a greater mass than lithium (Li) because it has more protons, neutrons, and electrons than lithium. Specifically, the atomic mass of fluorine is approximately 19 atomic mass units (amu), while the atomic mass of lithium is approximately 7 amu.

On the other hand, lithium would have a larger atomic radius than fluorine. This is because atomic radius tends to increase down a group (column) of the periodic table and decrease across a period (row). Lithium is located in Group 1 (the alkali metals) of the periodic table, while fluorine is located in Group 17 (the halogens). Elements in Group 1 have relatively large atomic radii due to their low effective nuclear charges and the shielding effect of their inner electrons.

In contrast, elements in Group 17 have relatively small atomic radii due to their high effective nuclear charges and the lack of shielding from their inner electrons. Therefore, since lithium is located in a group that has larger atomic radii, it would have a larger atomic radius than fluorine, which is located in a group with smaller atomic radii." (ChatGPT, 2023)

The activity that we would have after 15 minutes would be  0.625 pCi.

The half-life, when referring to radioactive decay, is the amount of time needed for half of the radioactive isotopes in a sample to decay. Because they are unstable, radioactive isotopes spontaneously decay into other isotopes or elements. Each radioactive isotope has a distinctive attribute called a half-life that doesn't change over time.

We know that;

N/No = (1/2)^t/t1/2

N =No(1/2)^t/t1/2

N = 5(1/2)^15/5

N = 0.625 pCi

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Answer:

The cell potential for the given galvanic cell is 0.188 V.

Explanation:

To calculate the cell potential, we can use the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where E°cell is the standard cell potential, R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (25°C = 298 K), n is the number of moles of electrons transferred (in this case, n = 2), F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

First, we need to write the half-reactions and their standard reduction potentials:

Sn4+(aq) + 2e- → Sn2+(aq) E°red = 0.15 V

Fe3+(aq) + e- → Fe2+(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn2+(aq) + 2Fe3+(aq) → Sn4+(aq) + 2Fe2+(aq)

The reaction quotient Q can be expressed as:

Q = [Sn4+][Fe2+]^2 / [Sn2+][Fe3+]^2

Substituting the given concentrations, we get:

Q = (0.00655)(0.01139)^2 / (0.0624)(0.0437)^2 = 0.209

Now we can calculate the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe2+]^2/[Fe3+]) + 0.0592 V log([Sn4+]/[Sn2+])

= 0.15 V + 0.0592 V log(0.01139^2/0.0437^2) + 0.0592 V log(0.00655/0.0624)

= 0.188 V

Therefore, the cell potential for the given galvanic cell is 0.188 V.

The cell potential for the given galvanic cell in which the given reaction occurs at 25 °C is 0.188 V.

To find the cell potential, we take the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

In which R is the gas constant (8.314 J/mol·K) and E° cell is the standard cell potential.

T temperature in Kelvin (25°C = 298 K), and n is the number of moles of electrons transferred (n = 2), Q is the reaction quotient and F is the Faraday constant (96,485 C/mol).

Firstly, write the half-reactions and then their standard reduction potentials:

Sn⁴⁺(aq) + 2e⁻  → Sn²⁺(aq) E°red = 0.15 V

Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E°red = 0.77 V

The overall reaction is the sum of the half-reactions:

Sn²⁺(aq) + 2Fe³⁺(aq) → Sn⁴⁺(aq) + 2Fe²⁺(aq)

The Q reaction quotient can be written as:

Q = [Sn⁴⁺][Fe²⁺]² ÷ [Sn²⁺][Fe²⁺]²

Substituting the given concentrations, we observe:

Q = (0.00655)(0.01139)² ÷ (0.0624)(0.0437)² = 0.209

Next, we can find the cell potential:

Ecell = 0.15 V + 0.0592 V log([Fe²⁺]²/[Fe³⁺]) + 0.0592 V log([Sn⁴⁺]/[Sn²⁺])

= 0.15 V + 0.0592 V log(0.01139²÷0.0437²) + 0.0592 V log(0.00655÷0.0624)

= 0.188 V

Thus, the cell potential for the given galvanic cell is 0.188 V.

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Answer:

0.21 mole of C8H18.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Next, we shall determine the number of mole of C8H18 that reacted and the number of mole water (H2O) produced from the balanced equation.

This is illustrated below:

From the balanced equation above,

2 moles of C8H18 reacted to produce 18 moles of H2O.

Finally, we shall determine the number of mole C8H18 needed to produce 1.90 moles of H2O.

This can be obtained as follow:

From the balanced equation above,

2 moles of C8H18 reacted to produce 18 moles of H2O.

Therefore, Xmol of C8H18 will react to produce 1.90 moles of H2O i.e

Xmol of C8H18 = (2 × 1.90)/18

Xmol of C8H18 = 0.21 mole

Thus, 0.21 mole of C8H18 is needed for the reaction.

Answer: what?

Explanation:

Answer: Huh?

Explanation:

An acetate buffer would be most effective in maintaining pH within a range of approximately 3.76 to 5.76.

The pH range over which an acetate buffer can effectively maintain pH depends on the pKa of the acid used and the concentration ratio of the acid to its conjugate base (acetate ion). Acetate buffer solutions are commonly prepared using acetic acid (CH3COOH) and sodium acetate (CH3COONa).

The pKa of acetic acid is approximately 4.76. In general, a buffer is most effective when the pH is within one unit of its pKa. Therefore, an acetate buffer would be most effective in maintaining pH within a range of approximately 3.76 to 5.76

Outside this pH range, the buffer may not effectively resist changes in pH, as the concentration of the acid and its conjugate base will be significantly imbalanced. At lower pH values, the acid concentration will dominate, while at higher pH values, the concentration of the acetate ion will dominate, leading to a diminished buffering capacity.

However, it's important to note that the exact pH range over which an acetate buffer can maintain pH effectively may vary depending on the specific concentration and preparation of the buffer solution.

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At pOH value  of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

In this question we will apply the formula

      pH +pOH = 14 . . . . . . . . . . . . .(1)

where pH = concentration of [\(H^{+}\) ] ion

pOH = concentration of [\(OH^{-}\) ] ion

As per the question

pOH =6.0

Putting the value of pOH in equation (1) we get the value of pH

              pH + 6.0 =14

             pH = 14 -6.0

             pH  = 8.0

 The value of pH if the pOH value is 6.0 is 8.0

To find the concentration of \(H^{+}\) ion we will use the following formula

This is calculated by the formula

                                 [\(H^{+}\)} = \(10^{-pH}\)

where we will write the values of pH

Hence the concentration of [\(H^{+}\)} ion is \(10^{-8}\)

Therefore at  pOH of 6.0 the pH value of the following solution is 8.0 and the concentration of [\(H^{+}\) ] ion is \(10^{-8}\)

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The complete question is -

What is the pH value and concentration of [\(H^{+}\) ] ion of the following if the pOH value of the solution is 6.0 ?

Answer:

1. Volcanoes and minor earthquakes

2. Volcanoes, earthquakes and fold mountains.

3. Earthquakes and fold mountains.

4. Magma from volcanoes is filled with nutrients that makes land fertile.

Explanation:

The balanced oxidation-reduction equation for the destruction of cyanate ion waste solution from gold-mining operations by treatment with hypochlorite ion in basic solution is:

OCN⁻(aq) + OCl⁻(aq) + 2OH⁻(aq) → CO₂⁻(aq) + N₂(g) + Cl⁻(aq) + H₂O(l)

In this reaction, the cyanate ion (OCN⁻) is oxidized to carbon dioxide (CO₂⁻) and nitrogen gas (N₂), while the hypochlorite ion (OCl⁻) is reduced to chloride ion (Cl⁻). The reaction takes place in basic solution, which provides the hydroxide ions (OH⁻) needed to neutralize the acidic H⁺ ions produced during the oxidation of the cyanate ion.

The reaction is exothermic, releasing heat energy as the products form. This reaction is an effective way to dispose of the cyanate ion waste generated by gold-mining operations, as it converts the hazardous waste into harmless gases and ions.

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Answer:

it has 18 electrons

Explanation:

You have an atom with 17 protons, 18 neutrons, a net charge of -1, and a mass of 35. How many electrons does this atom have?

atomic mass is protons + neutrons

17+18= 35 which is given

8rge of +17

neutrons are NEUTRAL and have no charge

if the species has a charge of -1, it has one more negative electron than protons

so the species has an atomic number of 17, atomic mass of 35, and a charge of -1

it has 18 electrons for -18, 17 protons for +17

-18 +17 = -1

element 17 with a -1 charge is the Cl anion

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

As there is only one mole of calcium chloride, 22.4 L will be one mole of calcium chloride.

A measurement of three-dimensional space is volume. Several imperial or US customary units, as well as SI-derived units (such the cubic meter and liter), are frequently used to quantify it quantitatively.

Volume and length (cubed) have a symbiotic relationship. A container's capacity is typically thought of as being represented by its volume.At STP, a mole of any gas takes up 22.4 L of space. As there is only one mole of calcium chloride, 22.4 L will be one mole of calcium chloride.

Therefore, as there is only one mole of calcium chloride, 22.4 L will be one mole of calcium chloride.

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Answer:

Benedict's test would determine if the sample is a reducing sugar, and Barfoed's test would determine if it is a monosaccharide or disaccharide.