The wavelength in nm for the first harmonic vibration frequency of ethylene double bond is 1500 nm.
To calculate the wavelength in nm for the first harmonic vibration frequency of ethylene double bond, we need to use the formula:
Wavelength = (speed of light) / (frequency)
First, let's convert the vibrational frequency from cm-1 to Hz (cycles per second):
2000 cm-1 = 2 x 10^14 Hz
Now, let's calculate the wavelength:
Wavelength = (3 x 10^8 m/s) / (2 x 10^14 Hz)
Wavelength = 1.5 x 10^-6 m = 1500 nm
Therefore, the wavelength in nm for the first harmonic vibration frequency of ethylene double bond is 1500 nm.
It's important to note that vibrational frequency is a fundamental property of molecules. It describes the frequency at which a molecule vibrates in response to external stimuli, such as light or heat. This frequency is related to the strength of the chemical bonds within the molecule. The higher the vibrational frequency, the stronger the chemical bonds. So, by knowing the vibrational frequency of a molecule, we can gain insights into its molecular structure and properties.
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A comet that has a semi-major axis of 100 AU must have a period of about A. 100 years B. 5000 years C. 10.000 years D. 1000 years
The period of a comet is determined by its semi-major axis, or the average distance between the comet and the Sun. A comet with a semi-major axis of 100 AU would have a period of about 10,000 years. Answer choice C is correct.
Kepler's Third Law of Planetary Motion states that the square of the period of an object orbiting the Sun is proportional to the cube of its semi-major axis. Mathematically, this can be expressed as:
T²= (4π² / GM) ₓ a³
Where T is the period, G is the gravitational constant, M is the mass of the Sun, and a is the semi-major axis.
For a comet with a semi-major axis of 100 AU, plugging in the values gives:
T² = (4π²/GMkg)) ₓ (100 AU ₓ 149.6 x 10⁹ m/AU)³
T²= (\(\frac{4 * 3.14*3.14}{6.67* 10^{^{-11}}* 1.99*10^{30} } *100*149.6* 10^{9}\)
T²=\(\frac{39.4384}{13.2733} *100*149.6*10^{9}\)
Simplifying this equation gives:
T² = 8.91 x 10¹⁶ s²
T = 2.99 x 10³ s, or about 9,465 years.
Therefore, a comet with a semi-major axis of 100 AU would have a period of about 10,000 years. Answer choice C is correct.
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tensile strength tests were carried out on two different grades of wire rod, resulting in the accompanying data. grade sample size sample mean (kg/mm2) sample sd aisi 1064 m
Tensile and flexural tests were done on two distinct grades of wire rod for the alternate and null hypotheses, yielding the data that is included.
What in a material is tensile?The term "tensile strength" describes how much strain or load a material can withstand before stretching and breaking. Tensile strength, as its name suggests, refers to a material's resistance towards tension brought on by external mechanical stresses.
We utilize tensile strength because?Ultimate tensile strength, sometimes known as simply "tensile strength," is a crucial attribute of materials that affects how well they operate mechanically. It is a material's capacity to withstand ripping brought on by stress. All forms of materials, including wires, harnesses, metal beams, etc., are covered by this characteristic.
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A plumber uses a spanner on a tap. She puts a force of 200N on the spanner 30cm from the tap. What is the size of the moment?
Answer:
60Nm
Explanation:
Given data
Applied force= 200N
length of spanner= 30cm to meter
= 30/100= 0.3m
We know that the formula for the moment is
P=Fl
that is
P= force * length
P= 200*0.3
P= 60Nm
Hence the moment is 60Nm
If the harmonic is 66 Hz, find the fundamental frequency
1) A car travels at 40 mph. what distance will it travel in 3 hours ?
distance = ______ × ______ = 4 mph × 3 hours = 120 m / hour
2) An athlete sprints at 10m/s. how long does it take him to complete a 200m race?
Time = DISTANCE ÷ SPEED = ____ = ____
Answer:
60
Explanation:
acar travel 40 kmph 2 hours and the 60 kmph in 3 hours
Question 4 of 10
Which of the following changes occurs naturally in a system over time?
A. Becoming more organized
B. Becoming more efficient
C. Increasing in energy
OD. Increasing in randomness
Answer: D. Increasing in randomness.
Explanation: The concept related to this change is entropy. Entropy is a measure of the randomness or disorder in a system. According to the second law of thermodynamics, the entropy of an isolated system tends to increase over time. This means that natural processes often lead to an increase in randomness or disorder.
For example, imagine a container of gas molecules. Initially, the molecules may be confined to one side of the container, creating a region of higher concentration. However, over time, the gas molecules will naturally spread out and become more evenly distributed throughout the container. This increase in randomness or disorder corresponds to an increase in entropy.
Molly does not have many activities after school, so she has plenty of time to exercise. She has never been very athletic and plans to start by exercising two hours a day five days a week. Is this a good plan?
OPTIONS:
A.
Yes, she should dive right in.
B.
No, no one can exercise that much.
C.
Yes, if she has the time there is no excuse.
D.
No, smaller goals would be better.
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How many protons are needed to produce a total charge of 4.55 · 10-12 C?Calculate the magnitude of the force (in N) between a gold nucleus and an electron on an orbit with radius 4.97·10-12 m around the nucleus. The gold nucleus has a charge of +79e.
(a) To produce a total charge of 4.55 x \(10^-^1^2\) C, we need 2.84 x \(10^7\) protons.
(b) The magnitude of the force between the gold nucleus and the electron is 7.31 x \(10^-^8\) N.
How to calculate the number of protons needed to produce a total charge of 4.55 x 10^-12 C?(a) To calculate the number of protons needed to produce a total charge of 4.55 · 10-12 C, we can use the fact that the charge of a single proton is e=1.60 x \(10^-^1^9\) C:
Number of protons = total charge / charge of one proton = 4.55 x \(10^-^1^2\) C / 1.60 x \(10^-^1^9\) C ≈ 2.84 x \(10^7\) protons
How to calculate the magnitude of the force between a gold nucleus and an electron?(b) To calculate the magnitude of the force between a gold nucleus (+79e) and an electron on an orbit with radius 4.97·10-12 m, we can use Coulomb's law:
F = k * |q1| * |q2| / \(r^2\)
where k is Coulomb's constant (k=8.99 x \(10^9\) N·\(m^2\)/\(C^2\)), q1 and q2 are the charges of the particles, and r is the distance between them.
Here, we have q1=+79e and q2=-e (the charge of an electron), so we can simplify:
F = k * |79e| * |e| / (4.97 x \(10^-^1^2\) m)² ≈ 7.31 x \(10^-^8\) N
Therefore, the magnitude of the force between the gold nucleus and the electron is approximately 7.31 x \(10^-^8\) N.
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ice melts to form liquid water. describe this physical change in terms of the arrangements of the particles
Ice melts to form liquid water. This is a physical change in terms of the arrangements of the particles
A physical change is the melting of ice. Water (H2O) appears to alter when it turns from a liquid state to a solid state (ice). However, this shift is just physical, as the constituent molecules still consist of 11.19% hydrogen and 88.81% oxygen by mass.
A physical change is a sort of the change in which the composition of matter is changed but not transformed. Although matter's size or shape may change, no chemical reaction may place. The majority of physical changes are reversible. When something changes physically but not chemically, it is said to have undergone a physical change.
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Assuming Hardy-Weinberg Equilibrium, calculate the expected allele and genotype frequencies for our classroom PTC tasting data. There are 147 tasters and 98 non-tasters.
Population Genetics Exercise Problem 2 Walk-Through
First, calculate the frequency of each of the two phenotypic variants:
Pr
The expected genotype frequencies for the classroom PTC tasting data would be approximately:TT = 0.36 Tt = 0.48 tt = 0.16.To calculate the expected allele and genotype frequencies assuming Hardy-Weinberg Equilibrium, we need to determine the allele frequencies and use them to calculate the genotype frequencies.
Let's assume the "taster" allele is represented by "T" and the "non-taster" allele is represented by "t".
1. Calculate the allele frequencies:
The total number of individuals in the population is 147 (tasters) + 98 (non-tasters) = 245.
The frequency of the "T" allele (p) can be calculated as the number of "T" alleles divided by the total number of alleles:
p = (2 * number of tasters + number of heterozygotes) / (2 * total number of individuals)
= (2 * 147 + 0) / (2 * 245)
= 294 / 490
= 0.6
The frequency of the "t" allele (q) can be calculated as:
q = 1 - p
= 1 - 0.6
= 0.4
2. Calculate the genotype frequencies:
The expected genotype frequencies can be calculated using the Hardy-Weinberg equation:
TT = p^2
Tt = 2pq
tt = q^2
TT = (0.6)^2
= 0.36
Tt = 2 * 0.6 * 0.4
= 0.48
tt = (0.4)^2
= 0.16
Therefore, the expected genotype frequencies for the classroom PTC tasting data would be approximately:
TT = 0.36
Tt = 0.48
tt = 0.16
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consider the following statement: "if you connect another resistor to an existing network of resistors, the total equivalent resistance will decrease." is this true?
When you connect another resistor to an existing network of resistors, the total equivalent resistance may not necessarily decrease. It depends on the values of the new and existing resistors, as well as the arrangement of the network.
In a series circuit, where resistors are connected in a line, the total equivalent resistance increases as more resistors are added. This is because the current must flow through each resistor, and the total resistance is the sum of all the individual resistances. Therefore, adding another resistor increases the total resistance and decreases the current flow.
In a parallel circuit, where resistors are connected side-by-side, the total equivalent resistance decreases as more resistors are added. This is because each resistor provides a new path for current flow, reducing the total resistance and increasing the current flow.
Overall, it is important to consider the type of circuit and the values of the resistors when determining the effect of adding a new resistor to an existing network. The statement "if you connect another resistor to an existing network of resistors, the total equivalent resistance will decrease" is not always true and requires further analysis.
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whats the average velocity
Answer:
A velocity is a vector unit, and average velocity can be described as the displacement divided by the time. The units for velocity can be understood from the definition to be meters/second or in common any distance unit over any time unit. The average speed of a body is described as the distance covered divided by the time elapsed.
Explanation:
the force of speed
Answer:
10 m/s
Explanation:
The average velocity is the slope of the graph.
m = (10 - 0)/(1 - 0)
m = 10/1
m = 10 m/s
if the voltage drop is less than 0.5 volts, then measure the voltage drop on the starter ground circuit.
If the voltage drop is less than 0.5 volts, then measure the voltage drop on the starter ground circuit.When troubleshooting electrical systems, it is important to identify potential issues with voltage drops.
A voltage drop occurs when there is a loss of voltage across a circuit or component due to resistance. If the voltage drop is less than 0.5 volts, it suggests that the circuit is functioning properly and there is minimal resistance.
In the case of the starter ground circuit, it is crucial for the starter motor to have a reliable ground connection to function efficiently. By measuring the voltage drop on the starter ground circuit, we can determine if there are any excessive resistances that might be hindering the starter motor's performance.
If the voltage drop on the starter ground circuit is greater than 0.5 volts, it indicates a potential problem with the ground connection. This could be due to corroded terminals, loose connections, or damaged wiring. In such cases, it is necessary to inspect and repair the ground circuit to ensure proper functioning of the starter motor.
To summarize, if the voltage drop is less than 0.5 volts, measuring the voltage drop on the starter ground circuit is necessary to ensure the ground connection is optimal. This helps in identifying any potential issues with excessive resistance and allows for appropriate troubleshooting and repairs if needed.
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Develop and describe a method to predict the force exerted by the expelled CO2 on the system using Newton's Saved second law.
1) Determine the mass of the expelled CO2, 2) Calculate the acceleration of the CO2 using Newton's second law, and 3) Multiply the mass by the acceleration to obtain the force exerted by the CO2 on the system.
Newton's second law states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration. To apply this principle to predict the force exerted by expelled CO2 on a system, the following steps can be followed:
Determine the mass of the expelled CO2: This can be achieved by measuring the mass of the CO2 or using known properties such as the molar mass of CO2 and the quantity of CO2 expelled.
Calculate the acceleration of the CO2: The acceleration can be determined by considering the forces acting on the CO2. In this case, the main force acting on the CO2 would be the expulsion force. Other factors such as air resistance can be taken into account if necessary.
Multiply the mass by the acceleration: Once the mass and acceleration are determined, multiply them together to obtain the force exerted by the CO2 on the system. The unit of force is typically Newtons (N).
By following this method and applying Newton's second law, it is possible to predict the force exerted by the expelled CO2 on the system. It is important to ensure accurate measurements and consider all relevant forces to obtain a reliable prediction.
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The Milky Way Galaxy is (a) another name for our solar system; (b) a small group of stars visible in our night sky; (c) a collection of more than 100 billion stars, of which our Sun is one
Answer:
C
Explanation:
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How much power does Ivan have if he does 600 joules of work pushing a box 10 meters across the floor in 5 seconds?
The amount of power Ivan has if he does 600 joules of work pushing a box 10 meters across the floor is 120 watts.
How to determine amount of power?Power is defined as the rate at which work is done, which is equal to work divided by time. So:
Power = Work / Time (W/T)
where,
work = 600 joules and time = 5 seconds.
Substituting the given values:
Power = 600 J / 5 s = 120 W
Therefore, Ivan has a power of 120 watts.
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How do we know that a star contains certain elements?
Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre hasta que llega al suelo y con qué velocidad llega en cada uno de los casos: a) Si se lanza verticalmente hacia arriba. b) Si se lanza verticalmente hacia abajo. c) Si se lanza horizontalmente (En este caso calcular también la distancia al edificio cuando llega al suelo) d) Si se lanza con un ángulo de 30o (Calcular también distancia al edificio)
Answer:
a) t = 14.2 s , v = -92 m / s , b) v = - 59.16 m / s , t = 0.916 s
c) t = 7.75 s , x = 387.5 m
d) t = 10.64 s , x = 463.9 m , v = 92.2 m / s
Explanation:
This is an exercise in kinematics, suppose we take the upward direction as positive
a) is thrown up vertically.
Let's use the equation
y = y₀ + v₀ t - ½ g t²
When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²
0 = y₀ + v₀t - ½ g t²
½ 10 t² - 50 t - 300 = 0
Let's solve the quadratic equation
t² - 10 t - 60 = 0
t = [10 ±√ (10² + 4 60)] / 2
t = [10 ± 18.4] / 2
t₁ = 14.2 s
t₂ = -4.2 s
since time must be a positive quantity, the correctors result t = 14.2 s
the speed at this point is
v = v₀ - g t
v = 50 - 10 14.2
v = -92 m / s
the sign indicates that the body is going down
b) in this case the initial velocity is vo = -50 m / s
let's calculate the velocity on the ground
v² = v₀² - 2g (y-y₀)
v² = 50 2 - 2 10 ((0- 300)
v² = 3500
v = + - 59.16 m / s
as the body is going down the correct sign is the negative
v = - 59.16 m / s
the time it takes to arrive is
v = v₀ - g t
t = (v₀ - v) / g
t = (-50 + 59.16) / 10
t = 0.916 s
c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0
y = y₀ + v₀ t - ½ g t²
0 = 300 + 0 - ½ 10 t²
t = √ (2 300/10)
t = 7.75 s
the horizontal displacement at this time is
x = v₀ₓ t
x = 50 7.75
x = 387.5 m
d) as it is thrown with an angle let's find each component of the velocities
v₀ₓ = v₀ cos 30
\(v_{oy}\) = v₀ sin 30
v₀ₓ = 50 cos 30 = 43.3 m / s
v_{oy} = 50 sin 30 = 25 m / s
we look for the time of descent
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + v_{oy} t - ½ g t²
0 = 300 + 25 t - ½ 10 t²
t² - 5t - 60 = 0
we solve the second degree equation
t = [5 ±√ (5² + 4 60)] / 2
t = [5 ± 16.28] / 2
t₁ = 10.64 s
t₂ = -5.64 s
since the time must be positive the result is t = 10.64 s
the range on the x axis is
x = v₀ₓ t
x = 43.6 10.64
x = 463.9 m
the ground speed is
v_{y} = \(v_{oy}\) - g t
v_{y} = 25 - 10 10.64
v_{y} = -81.4 m / s
speed is
v = √ (v₀ₓ² + v_{y}²)
v = √ (43.3² + 81.4²)
v = 92.2 m / s
Classify Earth's layers based on their physical properties.
There are three layers of Earth:
Crust, mantle, and core.
Crust: The crust is that the outmost layer of the earth, the cooled and hardened part of the planet that ranges comprehensive from more or less 5-70 klick (~3-44 miles).
This layer makes up only one of the whole volume of the planet, although it makes up the whole surface (the continents and also the ocean floor).The dilutant elements are the oceanic crust, which underlies the ocean basins at a depth of 5-10 klick (~3-6 miles), whereas the thicker crust is that of the continental crust.
Mantle: The mantle is present between the Earth's crust and its super - heated inner layer and is almost 2900 km thick.
This layer makes up 84% of Earth's total volume.
Core: The innermost and the hottest layer of Earth is known as the core.
Most liquid metals reside in this specific layer like Iron and Nickel.
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PLS HELP I NEED THIS BY TONIGHT PLS
Answer:
GET GOOD
Explanation:
Hurry need help ASAP
Answer:
last one
Explanation:
Where in the galaxy are the most stars born?
Answer: Stars are formed in dust clouds and are found in most galaxies.
Explanation:
Answer: Stars form inside relatively dense concentrations of interstellar gas and dust known as molecular clouds.
Explanation:
You throw a 0.5 kg ball with a force of 10 N. What is the acceleration of the ball?
Answer:
20m/s^2
Explanation:
F=ma, therefore 10N = 0.5kg * a. Solve for a.
Which of the following is not a density-dependent factor limiting a population growth?
a) intra-specific competition
b) switching behavior of a predator
c) a stress syndrome that alters hormone levels
d) a limited number of available nesting site
Answer:A.
i know its a, i did quiz
An 0. 80-kg block is held in place against the spring by a 67-n horizontal external force (see the figure. The external force is removed, and the block is projected with a velocityv1 = 1. 2 m/s upon separation from the spring. The block descends a ramp and has a velocity v2 = 1. 9 m/s at the bottom. The track is frictionless between points a andb. The block enters a rough section atb, extending toe. The coefficient of kinetic friction over this section is 0. 39. The velocity of the block isv3 = 1. 4 m/s atc. The block moves on tod, where it stops. The spring constant of the spring is closest to
The spring constant of the spring is closest to 210 N/m.
First, let's calculate the potential energy stored in the spring:
PE = 1/2 k x^2
Therefore:
x = F_ext / k = 67 N / k
and:
\(PE = 1/2 k (67 N / k)^2 = 2244.5 J/k\)
Next, let's calculate the kinetic energy of the block at point b:
\(KE\_b = 1/2 m v2^2 = 0.5 * 0.8 kg * (1.9 m/s)^2 = 1.216 J\)
The work done by friction over the rough section is given by:
\(W\_f = f\_k * d\)
The frictional force is:
f_k = μ_k * m * g
Substituting the given values, we get:
\(f\_k = 0.39 * 0.8 kg * 9.81 m/s^2 = 3.06 N\)
The distance traveled over the rough section is:
\(d = h\_b - h\_c = 0.3 m - 0.1 m = 0.2 m\)
Therefore:
\(W\_f = 3.06 N * 0.2 m = 0.612 J\)
Finally, let's calculate the kinetic energy of the block at point c:
\(KE\_c = 1/2 m v3^2 = 0.5 * 0.8 kg * (1.4 m/s)^2 = 0.392 J\)
Using the principle of conservation of mechanical energy:
\(PE = KE\_b + KE\_c + W_f\)
Solving for k, we get:
\(k = 2 * (KE\_b + KE\_c + W_f) / (67 N / k)^2\)
Substituting the given values, we get:
\(k = 2 * (1.216 J + 0.392 J + 0.612 J) / (67 N / k)^2 = 210 N/m\)
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The magnitude of electric field intensity just above the surface of a sheet measured from its midpoint is 5.1*10^5 N/C. Calculate the surface charge density is the sheet .
If the magnitude of electric field intensity just above the surface of a sheet measured from its midpoint is 5.1*10^5 N/C. the surface charge density is the sheet is 9.2 x 10^-7 C/m^2.
How to find the surface charge?The electric field just above the surface of an infinite sheet of charge is given by:
E = σ/2ε₀
where E is the electric field intensity, σ is the surface charge density, and ε₀ is the permittivity of free space.
We are given that the electric field intensity just above the surface of the sheet is 5.1*10^5 N/C. Therefore, we can write:
5.1*10^5 = σ/2ε₀
We can rearrange this equation to solve for σ:
σ = 2ε₀ * 5.1*10^5
Now we need to substitute the value of ε₀, which is:
ε₀ = 8.85 * 10^-12 C^2/(N.m^2)
So, plugging in the values we get:
σ = 2 * 8.85 * 10^-12 * 5.1*10^5
σ = 9.0 * 10^-6 C/m^2
Therefore, the surface charge density of the sheet is 9.0 * 10^-6 C/m^2.
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Ren runs a hamburger stand and needs to clean up a season’s worth of grease buildup on the range hood over his griddle. explain what he should look for in a cleaning product that can handle a layer of grease
Answer:
A cleaning product that contains a base.
Explanation:
Ren should use a cleaning product that contains a base. This is because bases readily react with lipids (fats), the kind of compound that makes up grease. A base would break down the grease, forming soap, which would then easily wash away.
which of these events signals the beginning of winter in the northern hemisphere?
The beginning of winter in the northern hemisphere is typically signaled by the winter solstice, which occurs around December 21st each year.
The winter solstice is an astronomical event that marks the shortest day and longest night of the year in the northern hemisphere. It usually occurs around December 21st, although the exact date may vary slightly. During the winter solstice, the tilt of the Earth's axis is farthest away from the Sun, resulting in the least amount of daylight hours.
The winter solstice is a significant event as it marks the official start of winter in the northern hemisphere. After the winter solstice, the days gradually start getting longer, although temperatures may continue to drop as winter progresses. The solstice has been recognized and celebrated by various cultures throughout history, often with festivals and rituals symbolizing the return of light and the promise of renewal.
While other factors such as weather patterns and regional variations can contribute to the perception of winter, the winter solstice is a key astronomical event that signals the beginning of winter in the northern hemisphere.
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What is the equivalent resistance between terminals A and B, measured in ohms?
Answer:
c. 0.80
Explanation:
they will choose the path that has not resistance
10. If a wave has a frequency of 12 Hz and a wavelength of 3 meters,
what is its wave speed?
Answer: 36 m/s
Explanation:
Wave speed = Wavelength * Frequency
12 * 3 = 36 m/s
Answer: 36 m/s
Explanation: