If the force of gravity suddenly stopped acting on planets, they would

A.) spiral slowly towards the sun

B.) continue to orbit the sun

C.) move in straight lines tangent to thier orbits

D.) spiral slowly away from the sun

E.) fly straight away from the sun

Answer:

Explanation:

We can use the inverse-square law of universal gravitation to determine the weight of the missile at an altitude of 6.4 x 10^6 m. The law states that the force of gravity between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Let M be the mass of the Earth and m be the mass of the missile. At the Earth's surface, the weight of the missile is:

F1 = mg

where g is the acceleration due to gravity on the Earth's surface, which we assume to be 9.81 m/s^2.

At an altitude of 6.4 x 10^6 m, the distance between the center of the Earth and the missile is:

r = R + h

where R is the radius of the Earth (6.4 x 10^6 m) and h is the altitude of the missile (6.4 x 10^6 m).

The weight of the missile at this altitude can be calculated using the inverse-square law of universal gravitation:

F2 = G * M * m / r^2

where G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2).

Substituting the given values, we get:

F2 = (6.6743 x 10^-11 N * m^2 / kg^2) * (5.97 x 10^24 kg) * (400 N) / (6.4 x 10^6 m + 6.4 x 10^6 m)^2

F2 = 39.61 N

Therefore, the weight of the missile at an altitude of 6.4 x 10^6 m is approximately 39.61 N.

Wind velocity:

25 m/h with a direction angle of 190°.

Vertical component:

25 sin 190 = -4.34 m/s = - 4 m/s

The heat released in the whole process in which a sample of water is cooled and frozen is 4.64 * 10⁸ J.

The problem is to be divided into two steps. This process releases a certain quantity of heat,

Step 1) Solidification of the water at 0°C into ice.

Q = m* Lf

where,

m is the mass of the water

Lf stands for the latent heat of ice fusion

Substituting numbers, we find

Q₁ = (1271 kg)* (334 kJ/kg) = 424514 kJ = 4.2* 10⁸ J

step 2) The water became ice, now we need to cool it down to -36°C . This process releases a certain quantity of heat, which is

Q₂ = m* Cs* ΔT

where,

m is the mass of ice

Cs is the specific heat of ice

ΔT is the variation of temperature

By placing the numbers in the formula, we have,

Q₂ = (1271 kg)* (2050 J/kg K) (-17-0) = 44294350 J = - 0.44 * 10⁸ J

The negative sign means the heat is released by the system.

Thus, the overall process produces heat that is

Q = Q₁ + Q₂ = 4.2* 10⁸ J + 0.44 * 10⁸ J = 4.64 * 10⁸ J

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The primary means by which heat is transferred through fluids is convection currents (option D).

Convection is the transmission of heat in a fluid by the circulation of currents.

Heat can be transferred by different methods depending on the medium. Fluids like gases and liquids transfer heat through the process of convection.

Therefore, the primary means by which heat is transferred through fluids is convection currents.

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Answer:

a

\(P_G  = 14.03 \  psig \)  

b

\(h_m = 0.148 \ m \)

Explanation:

From the question we are told that

The pressure of the manometer when there is no gas flow is \(P_{m} = 15.5 \ psig = 15.5 * 6894.76 = 106868.78 \ N/m^2\)

The level of mercury is \(h = 950 \ mm = 0.950 \ m\)

The drop in the mercury level at the visible arm is \(d = 39.0 = 0.039 \ m \)

Generally when there is no gas flow the pressure of the manometer is equal to the gauge pressure which is mathematically represented as

\(P_g = P_m = g * \delta h * \rho\)

Here \( \rho \) is the density of mercury with value \( \rho = 13.6 *10^{3} kg/m^3 \)

and \(\delta h\) is the difference in the level of gas in arm one and two

So

\(\delta h = \frac{106868.78}{ 13.6 *10^{3} * 9.8 }\)

\(\delta h = 0.802 \ m \)

Generally the height of the mercury at the arm connected to the pipe is mathematically represented as

\(h_m = 0.950 - 0.802\)

=> \(h_m = 0.148 \ m \)

Generally from manometry principle we have that

\(P_G + \rho * g * d - \rho * g * [h - (h_m + d)] = 0\)

Here \(P_G\) is the pressure of the gas

\(P_G +13.6 *10^{3} * 9.8 * 0.039 - 13.6 *10^{3} * 9.8 * [0.950 - (0.148 + 0.039)] = 0\)

\(P_G = 9.6724 04 *10^{4} \ N/m^2\)

converting to  psig

\(P_G = \frac{ 9.6724 04 *10^{4} }{6894.76}\)

\(P_G = 14.03 \ psig \)

Answer:

Heat is flowing into the metal.

Explanation:

From the question given above, the following data were obtained:

Mass (M) of iron = 150 g

Initial temperature (T₁) = 25.0°C

Final temperature (T₂) = 73.3°C

Direction of heat flow =?

Next, we shall determine the change in the temperature of iron. This can be obtained as follow:

Initial temperature (T₁) = 25.0 °C

Final temperature (T₂) = 73.3 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 73.3 – 25

ΔT = 48.3 °C

Next, we shall determine the heat transfered. This can be obtained as follow:

Mass (M) of iron = 150 g

Change in temperature (ΔT) = 48.3 °C

Specific heat capacity (C) of iron = 0.450 J/gºC

Heat (Q) transfered =?

Q = MCΔT

Q = 150 × 0.450 × 48.3

Q = 3260.25 J

Since the heat transferred is positive, it means the iron metal is absorbing the heat. Thus, heat is flowing into the metal.

Answer:

1-steal an inhaler 2-use it 3-your good

orrrr

1-swallow air(preferably air from space)

Answer:

then breath

Explanation:

c. a natural process

It is a natural process

Answer:

You take the derivative of the velocity equation!

Explanation:

The acceleration basically refers to how the velocity changes over time. To find that, you need to take the derivative of the velocity equation. Comment if you would like me to show you what that looks like. Once you find the derivative you can plug your time value into the equation and get the acceleration at that time!

Answer:

find the rate of change of the velocity equation

Answer:

  2.38 mW

Explanation:

Power is work per unit time. Work is the product of force and distance. That means ...

  \(\text{power}=\dfrac{\text{force}\times\text{distance}}{\text{time}}=\text{force}\times\dfrac{\text{distance}}{\text{time}}\\\\\text{power}=\text{force}\times\text{velocity}\)

Using the given values of force and velocity, the tadpole's power output is ...

  P = (0.028 N)(0.085 m/s) = 0.00238 W = 2.38 mW

The tadpole's power output is about 2.38 mW.

The velocity of the running back is 8 m/s.

To calculate the velocity of the running back, we can use the work-energy principle. The work-energy principle states that the work done on an object will be equal to the change in its kinetic energy.

Given; Mass of the running back (m); 80 kg

Work done (W); 2560 Joules

We can use the formula for kinetic energy;

KE = 0.5 × m × v²

where KE is the kinetic energy, m is the mass, and v is the velocity of the running back.

According to the work-energy principle, the work done is equal to the change in kinetic energy;

W = KE - KE0

where KE0 is the initial kinetic energy.

Rearranging the formula for kinetic energy, we get;

KE = 0.5 × m × v²

Substituting the given values, we get;

2560 = 0.5 × 80 × v²

Solving for v;

v² = (2 × 2560) / 80

v² = 64

v = √(64)

v = 8 m/s

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Answer:

Gravity

Explanation:

Answer:

t = 26.8 s

Explanation:

Here, we can use the second equation of motion to calculate the required time:

\(s = v_it + \frac{1}{2}at^2\)

where,

s = distance = 1800 m

vi = initial speed = 0 m/s

t = time needed = ?

a = acceleration = 5 m/s²

Therefore,

\(1800\ m = (0\ m/s)t+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(1800\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{720\ s^2}\)

t = 26.8 s

The speed of the roller coaster at the bottom of the hill is 33.9 m/s.

The conservation of mechanical energy is used to determine the speed of the roller coaster at the bottom of the hill, as there is no friction. According to the law of conservation of energy, mechanical energy is constant at all points in a frictionless environment.Let's look at the equation below:PEg + KE = PEg + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe kinetic energy is maximum and the gravitational potential energy is zero when the roller coaster is at the bottom of the hill. The gravitational potential energy is highest when the roller coaster is at the top of the hill, with its potential energy equal to its kinetic energy when it reaches the bottom of the hill.Initially, the roller coaster is at rest at the top of the hill. The gravitational potential energy of the roller coaster is transformed into kinetic energy as it descends the hill. We can calculate the speed of the roller coaster using the law of conservation of energy.Solution:Given,Height of the hill, h = 59.3 mGravitational acceleration, g = 9.8 m/s²Mass of roller coaster, m = 2000 kgWe need to find the speed of the roller coaster at the bottom of the hill, v.To begin, calculate the potential energy at the top of the hill.Potential energy at the top of the hill = mgh Where m is the mass of the roller coaster, g is the acceleration due to gravity, and h is the height of the hill.

The potential energy at the top of the hill is given by:PEg = mgh= 2000 kg × 9.8 m/s² × 59.3 m= 1.15 × 10⁶ JNow, let's figure out the velocity at the bottom of the hill.Using the conservation of energy, we can write,PEg = KE + KEwhere PEg is gravitational potential energy and KE is kinetic energyThe gravitational potential energy is equal to the kinetic energy.KE = PEg= 1.15 × 10⁶ JKE = 1/2 × mv²Where m is the mass of the roller coaster and v is the velocity of the roller coaster.Substituting the given values in the above equation, we get;1.15 × 10⁶ = 1/2 × 2000 × v²v² = (2 × 1.15 × 10⁶) / 2000v² = 1150v = √1150v = 33.9 m/s.

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Answer:

The pedal is an application tool that applies the force over a short distance on the axle to move the wheel a greater distance with less force.

Explanation:

hope this helped

Answer:

It defines a criterion that evaluates to true or false and specifies actions to take if it is true.

Explanation:

EDGE2020

Answer:

D

Explanation:

a) Work done by the tension force is obtained as 3.45 * 10^4  J

b) Work done by gravity is obtained as  2.94 * 10^4 J

In physics, the work done is referred to as the product of the force and the distance that have been covered by the force. We know that the work done by the tension force is the work that is done as the string is stretched across the distance as we have been given.

The work done by gravity is the work that is done as the mass is lifted across a height. Thus the work done is the work done when we lift the mass from one point to another.

In order to find the work done in each case;

a) Work done by the tension force = 1.38 ✕ 10^4 N * 2.50 m

= 3.45 * 10^4  J

b) Work done by the gravity = 1.20 ✕ 10^3 kg * 9.8 m/s^2 *  2.50 m

= 2.94 * 10^4 J

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Answer:

C 1 degree

Explanation:

Answer:

Explanation:

d

A rock, a book and a can of soda all have the same mass. They each contain the same amount of matter.

Hence, the correct option is D.

Since the rock, book, and can of soda all have the same mass, it means that they contain the same amount of matter, regardless of their size or the material they are made of.

Mass is a measure of the amount of matter in an object, so if their masses are equal, it implies that the quantity of matter is the same in each of them.

The size, shape, and material composition can be different for each object, but their masses remain the same in this scenario.

Hence, A rock, a book and a can of soda all have the same mass. They each contain the same amount of matter.

Hence, the correct option is D.

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Answer:

air and oxygen makes in bigger

Explanation:

We can use currency as a medium of exchange in transactions because of its easy availability.

Currency is the most common medium of exchange accepted as a standard by all parties for settling economic transactions because every region or country has its specific type of currency in which they do transactions and carried out their economic activities world wide.  Currency is also considered as a medium of exchange for goods and services. It is money that is present in the form of paper and coins which is issued by a government. Currency is generally accepted because of high value as a method of payment. U.S. dollars ($), euros (€), Japanese yen (¥), and pounds sterling (£) are the examples of currencies of different countries around the world.

So we can conclude that We can use currency as a medium of exchange in transactions because of its easy availability.

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Okay, here are the steps to solve this problem:

1) The seesaw is balanced when the sum of moments is 0.

2) The moment created by a force depends on the force and the perpendicular distance from the pivot point.

3) The 20 kg child sits 1 meter from the pivot. So its moment is 20 * 1 = 20 kg*m.

4) We want to find the distance for the 40 kg child to create a moment that balances the 20 kg child's moment.

5) So the moment of the 40 kg child must be 20 kg*m.

6) The moment depends on force and distance. We know the force is 40 kg.

7) So we set: 40 kg * distance = 20 kg*m

8) And solve for the distance: distance = 20 / 40 = 0.5 meters

Therefore, for the seesaw to balance with a 20 kg child 1 meter from the pivot and a 40 kg child on the other side, the 40 kg child should sit 0.5 meters from the pivot point.

Let me know if you have any other questions!

Answer:

Explanation:

The electric flux through a surface is given by the equation:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

We are given Φ = 4.44 N⋅m2/C, A = 6.66×10−4 m2, and θ = 60.0∘. Substituting these values into the equation above and solving for E, we get:

E = Φ / (Acos(θ))

= 4.44 N⋅m2/C / (6.66×10−4 m2cos(60.0∘))

= 1.62×10^4 N/C

Therefore, the magnitude of the electric field is 1.62×10^4 N/C.

The magnitude of the electric field is 13,320 N/C.

The electric flux through a surface is defined as the product of the electric field and the area of the surface projected perpendicular to the electric field. Mathematically, we can write:

Φ = EAcos(θ)

where Φ is the electric flux, E is the electric field, A is the area of the surface, and θ is the angle between the electric field and the surface normal.

Here in the Question,

We are given the electric flux Φ = 4.44 N·m^2/C, the area A = 6.66×10^-4 m^2, and the angle θ = 60.0°. We can solve for the magnitude of the electric field E by rearranging the equation as follows:

E = Φ / (A*cos(θ))

Substituting the given values, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*cos(60.0°))

Simplifying the denominator, we get:

E = 4.44 N·m^2/C / (6.66×10^-4 m^2*0.5)

E = 13,320 N/C

Therefore, 13,320 N/C is the magnitude of the electric field.

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The efficiency of the engine is 17%.

Given the following data:

To find the efficiency of the engine:

Mathematically, the efficiency of an engine is calculated by using the formula:

\(Efficiency = \frac{E_O}{E_I}\) × \(100\)

Where:

Substituting the given parameters into the formula, we have;

\(Efficiency = \frac{201}{1176}\) × \(100\)

\(Efficiency = 0.171\) × \(100\)

Efficiency = 17%

Therefore, the efficiency of the engine is 17%.

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Answer:

capacitive reactance equals inductive reactance

Equivalent resistance: If a single resistance can substitute a mixture of resistances while keeping the current in the circuit unaltered, that single resistance is referred to as the equivalent resistance.

Ideal resistors, capacitors, and inductors are considered to add only resistance, capacitance, or inductance to the circuit in electrical circuit theory. All components, however, have a non-zero number for each of these factors. All physical devices, in particular, are made of materials with limited electrical resistance, so physical components have some resistance in addition to their other characteristics.

The physical sources of ESR vary depending on the instrument. In circuit analysis, one method for dealing with these intrinsic resistances is to use a lumped element model to describe each physical component as a mix of an ideal component and a tiny resistor in series, the ESR.

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The corresponding resistance of the circuit in the image is 15 ohms. Option is the required response to the posed query (A).

The equivalent resistance of a circuit is the total electrical resistance that it encounters as a consequence of all of its resistors cooperating against its voltage source.

A circuit with more resistance will have less electricity flowing through it. Finding the total resistance value of all the linked resistances in an electrical circuit is necessary. As a result, another method of expressing overall resistance is the equivalent resistance. The entire resistance connected either in parallel or in series is said to have an equivalent resistance.

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