If QRS is dilated by a scale factor of 6 through the origin, which of the following points represent the coordinates of R?
OA. (-12,-24)
OB. (-24,-12)
OC. (12.24)
OD. (24,12)

Answers

Answer 1

Answer:

OD. (24,12) This is the right answer ok

Answer 2

Answer:

oopp

Step-by-step explanation:


Related Questions

Part B


Based on your construction, what do you know about ΔABD and ΔBCD?

Answers

The construction and the resulting triangles are interesting because they allow us to explore the properties of perpendicular lines and the angles they form.

Now, let's look at the two triangles that are formed as a result of this construction - ΔABD and ΔBCD. Since line BD is perpendicular to line AC, we know that angle ABD and angle CBD are both right angles. This is because any line that is perpendicular to another line forms a right angle with that line.

Now, let's look at the other sides of the triangles. In ΔABD, we have side AB, which is different from side BC in ΔBCD. Similarly, in ΔBCD, we have side CD, which is different from side AD in ΔABD.

So, although the two triangles share a common side (BD), they have different lengths for their other sides. This means that the two triangles are not congruent, since congruent triangles must have the same length for all their sides.

However, we can still find some similarities between the two triangles. For example, since angle ABD and angle CBD are both right angles, we know that they are congruent. Additionally, we can use the fact that angle ADB is congruent to angle CDB, since they are alternate interior angles formed by a transversal (line BD) intersecting two parallel lines (line AC and the line perpendicular to it passing through point B).

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Complete Question:

Draw a line through point B that is perpendicular to line AC Label the intersection of the line and line AC as point D. Take a screenshot of your work, save it, and insert the image in the space below.

Part B

Based on your construction, what do you know about ΔABD and ΔBCD?

An office building has the same number and size of offices on each floor. If there are 21 offices on the first 3 floors, then what is the total number of offices in the 10 story building?

Answers

Answer:

70 offices

Step-by-step explanation:

21 ÷ 3 to get amount per floor, 7 per floor, 7 × 10 = 70, 70 offices

Express each percent as a decimal:
7 1/2%

Answers

Answer:

0.075

Step-by-step explanation:

To represent 7 1/2 as a decimal, it would be 0.075 since there are 7 hundredths and half a hundredth.


the answer is 0.075.

to convert a percent to decimal you must move the decimal point two places to the left. so for 7.5% you would move the decimal spot two places to the left leaving you with 0.075. think about it this way: a percent is out of 100 and 0.07 read out loud is “seven hundredths” (7 out of 100).

Help me with 2 and 3

Help me with 2 and 3

Answers

Answer:

no idea anyone else got it??

Step-by-step explanation:

true or false
The region D between y=x∧3,y=x∧3+1,x=0 and x=1 is Type I. The ∭(x+yz∧2)dxdydz;xε[−1,5];yε[2,4];zε[0,1] equals 36 . The Divergence Theorem gives the relationship between a triple integral over a solid region Q and a surface integral over the surface of Q.

Answers

The statement "The region D between y=x³, y=x³+1, x=0 and x=1 is Type I" is true using Divergence Theorem.

Type I regions have a simple, flat, constant boundary. A type I area is one where, given x = a and x = b, the limits for y and z are the following: lower boundary ≤ y ≤ upper boundary, lower boundary ≤ z ≤ upper boundary. Since the boundaries in this scenario are as follows:

y = x³, y = x³ + 1, x = 0, x = 1

The limits are as follows:

\($$\int_0^1\int_{x^3}^{x^3+1}\int_{g_1(x,y)}^{g_2(x,y)}f(x,y,z)dzdydx$$\)

where \($g_1(x,y)=0$\)

\($g_2(x,y)=1$\)

The given triple integral c is taken over the region R defined by -1 ≤ x ≤ 5, 2 ≤ y ≤ 4 and 0 ≤ z ≤ 1.  

So, we have:

\($$\begin{aligned}\iiint (x+yz^2) dV&=\int_{-1}^{5}\int_2^4\int_0^1(x+yz^2)\; dz\; dy\; dx\\ &=\int_{-1}^{5}\int_2^4\left(\frac{x}{2}+y\right)\; dy\; dx\\ &=\int_{-1}^{5}\left(\frac{xy}{2}+2y\right)\; dx\\ &=36\end{aligned}$$\)

The Divergence Theorem gives the relationship between a triple integral over a solid region Q and a surface integral over the surface of Q. This statement is true.

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1 individuals in a tetrahybrid cross is AaB-bCcDd. Assuming independent assortment of these four genes, what are the probabilities that F2 offspring will have the following genotypes?

Answers

1. AABBCCDD: The probability of this happening is \(1/16\), since each parent would need to contribute a dominant allele for each gene.

2. AABBCcDD:  This genotype can be produced in two ways:

a) If both parents are homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D.

The probability of this happening is  = 1/128.

b) If one parent is homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A and B, homozygous dominant for C, and heterozygous for D.

3. The probability of this happening is 1/32.

AaBbCcDd : The probability of this happening is  1/256.

4. aaBBCcDD - This genotype can be produced in two ways:

a) If both parents are homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D. The probability of this happening is  1/128.

b) If one parent is homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A, homozygous dominant for B, homozygous dominant for C, and heterozygous for D.

The probability of this happening is  1/32.

To solve this problem, we need to use the principles of probability and Punnett squares.

For a tetrahybrid cross, we need to consider the four genes independently and combine the probabilities of each gene's alleles.

Assuming that A, B, C, and D are dominant alleles, and a, b, c, and d are recessive alleles, we can create a Punnett square for each gene, which would look like this:

A  |  A  |  a  |  a  

---|-----|-----|----

B  |  B  |  b  |  b  

---|-----|-----|----

C  |  C  |  c  |  c  

---|-----|-----|----

D  |  D  |  d  |  d  

Each box in the Punnett square represents a possible combination of alleles from the two parents.

For example, the top-left box represents offspring that inherit an A allele from the mother and an A allele from the father.

We can use these Punnett squares to calculate the probabilities of each genotype in the F2 offspring.

AABBCCDD - This genotype can only be produced if both parents are homozygous dominant for all four genes.

The probability of this happening is \((1/2)^4 = 1/16\) , since each parent would need to contribute a dominant allele for each gene.

AABBCcDD - This genotype can be produced in two ways:

a) If both parents are homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D.

The probability of this happening is\((1/2)^4 * 1/2 * (1/2)^3 = 1/128\)

b) If one parent is homozygous dominant for A and B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A and B, homozygous dominant for C, and heterozygous for D.

The probability of this happening is\(2 * (1/2)^4 * 1/2 * 1/2 * 1/2 = 1/32\)

AaBbCcDd - This genotype can be produced in 16 ways, since each gene can be inherited in two different ways (dominant or recessive).

The probability of this happening is \((1/2)^8 = 1/256.\)

aaBBCcDD - This genotype can be produced in two ways:

a) If both parents are homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D. The probability of this happening is\((1/2)^4 * 1/2 * (1/2)^3 = 1/128.\)

b) If one parent is homozygous recessive for A, homozygous dominant for B, heterozygous for C, and homozygous dominant for D, and the other parent is heterozygous for A, homozygous dominant for B, homozygous dominant for C, and heterozygous for D.

The probability of this happening is \(2 * (1/2)^4 * 1/2 * 1/2 * 1/2 = 1/32.\)

Note that we have assumed independent assortment of the four genes, which means that the inheritance of one gene does not affect the inheritance of another gene.

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Find the area of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate pi. 8ft by 10ft

Find the area of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate pi.

Answers

Answer:

\( \large \bf \implies{105.12 \: {ft}^{2} }\)

Step-by-step explanation:

\( \bf{Semi \: rectangle \: = \: length \: × \: width }\\ \\ \bf{Semi \: circle \: = \: \pi{r}^{2} } \: \: \: \: \: \: \: \bigg [r = \frac{d}{2} \bigg ] \\ \\ \bf{ S \: = \: 8 \times 10 + \frac{1}{2} \times \pi \times \bigg( \frac{8}{2} \bigg)^{2} } \\ \\ \bf{= 80 + \frac{1}{2} \times 3.14 \times {4}^{2} }\: \: \: \: \: \: \\ \\ \bf{= 105.12 \: {ft}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \)

\( \: \: \:\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf{OR}\)

We can divide the area in two parts :

The left part is a rectangle with length 10ft and width 8ft The right part is a semicircle with diameter 8ft.

So, Area of the left rectangular part

= length x width

= 10 × 8 ft²

= 80 ft²

Now, diameter of the semicircular part = 8 ft

So, radius

= \(\bf\frac{diameter}{2}\)

= \(\bf\frac{8}{2}\) ft

= 4 ft

So, area of the right semicircular part

\(\bf{= \frac{1}{2} \times \pi \times radius^2}\)

\(\bf{= \frac{1}{2} \times 3.14 × 4^2 ft^2}\)

\(\bf{= 25.12 \: ft^2}\)

Total area ,

= Area of the left rectangular part + Area of the right semicircular part

\( \bf{= 80 \: {ft}^{2} + 25.12 \: {ft}^{2}} \)

\( \bf{= 105.12 \: {ft}^{2} }\)

6.4 divided by 43.52

Answers

Answer:

0.14705882352

Step-by-Step:

Just use a calculator and your answer should pop up.

What is the next fraction in this sequence? Simplify your answer. 1 /88 , 1 /44 , 1 /22 , 1 /11 , ...

Answers

1/1.1 and 1/0.11 and so on

Add.

(6x³ + 3x² − 2) + (x³ - 5x² − 3)

Express the answer in standard form. (Please and thank you)

Answers

Answer:

\(\\\sf7x^3 - 2x^2 - 5\)

Step-by-step explanation:

\(\\\sf(6x^3 + 3x^2 - 2) + (x^3 - 5x^2 - 3)\)

Remove parenthesis.

6x^3 + 3x^2 - 2 + x^3 - 5x^2 - 3

Rearrange:

6x^3 + x^3 + 3x^2 - 5x^2 - 2 - 3

Combine like terms to get:

7x^3 - 2x^2 - 5

----------------------------------------

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Answer:

7x³ - 2x² - 5

Step-by-step explanation:

(6x³ + 3x² - 2) + (x³ - 5x² - 3)

Remove the round brackets.

= 6x³ + 3x² - 2 + x³ - 5x² - 3

Put like terms together.

= 6x³ + x³ + 3x² - 5x² - 2 - 3

Do the operations.

= 7x³ - 2x² - 5

____________

hope this helps!

A card is selected from a standard deck of cards. What is the probability that the card is a diamond and is a seven?

Answers

There are 52 cards in a deck, and only one 7 of diamonds. So the answer is 1/52

The selling price of a suit is $560

The discount on the suit is 12%

What is the new selling price

Answers

The new selling price of the suit after a 12% discount is $492.80 with initial selling price of a suit of $560.

A discount is a reduction or deduction in the price or cost of a product or service. It is a marketing strategy commonly used to incentivize customers to make a purchase or to promote sales.

We know that the selling price of a suit is $560. The discount on the suit is 12%.

We need to find the new selling price.

We can calculate the discount on the suit first.

Discount = (12/100) x 560

Discount = 0.12 x 560

Discount = $67.2

Now, we can find the new selling price of the suit.

New selling price = Selling price - Discount

New selling price = $560 - $67.2

New selling price = $492.8

Therefore, the new selling price of the suit is $492.8.

To calculate the new selling price after applying a discount, you need to subtract the discount amount from the original selling price.

Discount = 12% of the selling price

Discount amount = 12% × $560

= 0.12 × $560

= $67.20

New Selling Price = Selling Price - Discount Amount

New Selling Price = $560 - $67.20

= $492.80

Therefore, the new selling price of the suit after a 12% discount is $492.80.

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can someone help me pls?

can someone help me pls?

Answers

Answer:

decreasing:   (-2, -1)∪(-1, 0)

Step-by-step explanation:

From  x = -2 to x = 0 function is decreasing, but for x= -1 function doesn't exist, so we need to exclude x = -1 from (-2, 0)

Which expression is equivalent to -15x + 39?

Answers

Answer:

56x

Step-by-step explanation:

i think

56x I hope this helps you

Tomás wants to tile a rectangular floor with square tiles that measure 12 inches on a side. The floor measures 10 feet 6 inches long by 8 feet 6 inches wide. If he is able to cut the tiles without waste, what is the minimum whole number of tiles Tomás needs to completely cover the floor?​

Answers

There are 1176 is the minimum whole number of tiles Tomás needs to completely cover the rectangular floor.

Rectangle:

Rectangle means a four sided-polygon, having all the internal angles equal to 90 degrees. The two sides at each corner or vertex, meet at right angles.

Given,

Tomás wants to tile a rectangular floor with square tiles that measure 12 inches on a side. The floor measures 10 feet 6 inches long by 8 feet 6 inches wide.

Here we need to find if he is able to cut the tiles without waste, what is the minimum whole number of tiles Tomás needs to completely cover the floor.

Here we have to convert the feet into inches for easy calculation,

1 feet = 12 inches

So, the length is ,

l = 120 + 6 = 126 inches

w = 96 + 6 = 112 inches

So, the area of the floor is,

=> l x w

=> 126 x 112

=> 14,112

Here we need to use 12inches square tile,

So,

=> 14112 / 12

=> 1176.

Therefore, there are 1176 tiles are need to cover the floor.

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A movie theater charges $15 for adults and children and $10 for seniors. The theater collected a total of $1,270 for movie ticket sales one night for a selected movie. The total number of tickets sold for that movie was 93.
Part A: Write a system of equations that represents the situation. Let a represent the number of adult and child tickets sold and s represent the number of senior tickets sold.
Part B: Solve the system you wrote in part (a) using the substitution method.
Part C: Check your solution in the original system.
Part D: Interpret your solution in the context of the problem.

Answers

In conclusion  the number of adult and child tickets sold was 68, and the number of senior tickets sold was 25. The solution tells us that 68 adult and child tickets and 25 senior tickets were sold for the movie. The total amount collected was $1270.

How to solve?

Part A:

The system of equations that represents the situation is:

a + s = 93 (total number of tickets sold)

15a + 10s = 1270 (total amount collected in dollars)

Part B:

Using the substitution method, we can solve for one variable in terms of the other in the first equation and substitute it in the second equation, then solve for the remaining variable.

From the first equation, we get:

a = 93 - s

Substituting this in the second equation, we get:

15(93-s) + 10s = 1270

Simplifying the above equation, we get:

1395 - 5s = 1270

Subtracting 1395 from both sides, we get:

-5s = -125

Dividing both sides by -5, we get:

s = 25

Substituting s=25 in the equation a + s = 93, we get:

a + 25 = 93

Subtracting 25 from both sides, we get:

a = 68

Therefore, the number of adult and child tickets sold was 68, and the number of senior tickets sold was 25.

Part C:

To check our solution, we can substitute a=68 and s=25 in both equations and verify if they are true.

a + s = 93

68 + 25 = 93 (true)

15a + 10s = 1270

15(68) + 10(25) = 1270 (true)

Part D:

The solution tells us that 68 adult and child tickets and 25 senior tickets were sold for the movie. The total amount collected was $1270.

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if my class starts at 11:45 am and ends at 1:15 pm but I leave early at 12:30 pm how much time have I spent in class?

Answers

Answer:

45 minutes

Step-by-step explanation:

you can disregard the 1:15 pm time

Answer:

45 minutes.

Step-by-step explanation:

You can ignore the 1:15 pm, as it's not relevant to the question of how much time you have spent in class.

11:45am to 12:30pm

Adding 15 minutes turns 11:45 am to 12:00 pm

Add another 30 minutes, it becomes 12:30 pm.

Calculate the sum of the minutes:

15+30 = 45 minutes.

sewing a border of ribbon onto her rectangular picnic blanket. The long side of the blanket is 70cm and the short side is 40cm. How much ribbon will she need?

Answers

Answer:

\(220\) cm

Step-by-step explanation:

We need to find the perimeter of the rectangular blanket in this case because a border is being sewn onto the blanket. The perimeter of a rectangle can be calculated by multiplying the sum of the rectangle's length and width by 2. As an algebraic expression, that would be \(2(l+w)\), where \(l\) is the rectangle's length and \(w\) is the rectangle's width. We are given that \(l=70\) and \(w=40\). Therefore, \(2(70+40)=2*110=220\) cm of ribbon will be needed. Hope this helps!

What number makes the equation true? 27 +_ = 46 ​

Answers

27 + x = 46

x = 46 - 27

x = 19 Ans .

Answer:

19

Step-by-step explanation:

Subtract- 46-26=19

Therefore, 27+19=46

The maximum acceptable concentration of lead in Alberta tap water is 0.0050 mg/L. 49 random samples of Calgary tap water are taken and the mean amount of lead in the tap water is 0.0055 mg/L. Assume the population standard deviation is assumed to be 0.002mg/L. At the 1 percent significance level is there enough evidence to conclude that mean lead levels in Calgary tap water exceed the maximum acceptable concentration?

(a) State the null and alternative hypothesis and significance level.

Answers

The significance level is given as 1 percent, which means α = 0.01.

The null hypothesis is that the mean lead levels in Calgary tap water are equal to or less than the maximum acceptable concentration of 0.0050 mg/L:

H0: μ ≤ 0.0050

The alternative hypothesis is that the mean lead levels in Calgary tap water exceed the maximum acceptable concentration of 0.0050 mg/L:

Ha: μ > 0.0050

The significance level is given as 1 percent, which means α = 0.01.

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please help me with this!!

Answers

you have to attach a picture or type the question so we can solve it :)

you have to attach a pic or problem so we can help

a sample of 400 observations has mean 95 and standard deviation 12. can we conclude it be a random sample from a population with mean 98 ? (at 5% level of significant)

Answers

We reject the null hypothesis that a sample of 400 observations with mean 95 and standard deviation 12 was randomly drawn from a population with mean 98 at a 5% level of significance.

To test whether a sample of 400 observations has been randomly drawn from a population with a mean of 98, we can use a one-sample t-test. The null hypothesis for this test is that the sample was drawn from a population with a mean of 98, while the alternative hypothesis is that the sample was not drawn from a population with a mean of 98

To perform the t-test, we can first calculate the t-statistic

t = (X - μ) / (s / sqrt(n))

where X is the sample mean, μ is the population mean (which is given as 98), s is the sample standard deviation, and n is the sample size.

Plugging in the values, we get

t = (95 - 98) / (12 / sqrt(400)) = -5

The degrees of freedom for this test are (n - 1) = 399. Using a t-table with 399 degrees of freedom and a significance level of 0.05, we find that the critical t-value is -1.965 (assuming a two-tailed test).

Since our calculated t-value of -5 is less than the critical t-value of -1.965, we can reject the null hypothesis and conclude that the sample was not drawn from a population with a mean of 98 at a significance level of 0.05. Therefore, we can conclude that the mean of the population from which the sample was drawn is unlikely to be 98.

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What is the present value of a cash inflow of 1250 four years from now if the required rate of return is 8% (Rounded to 2 decimal places)?
a. 992.50
b. 938.75
c. 918.79
d. 835.75

Answers

The present value of a cash inflow of 1250 four years from now, given a required rate of return of 8%, is 918.79, rounded to 2 decimal places. Therefore, option (c) is the correct answer.

To find the present value of a future cash inflow, we need to discount the future value by a factor that takes into account the time value of money, or the opportunity cost of waiting for the money.

This factor is determined by the required rate of return, which is the minimum rate of return that an investor expects to earn on an investment with a similar level of risk.

In this case, we have a cash inflow of 1250 that will be received four years from now, and a required rate of return of 8%. To find the present value, we can use the formula for the present value of a single cash flow:

PV = FV / (1 + r)^n

where PV is the present value, FV is the future value, r is the required rate of return, and n is the number of years.

Plugging in the values, we get:

PV = 1250 / (1 + 0.08)^4

PV = 918.79

Therefore option (c) is the correct answer.

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what is the probability of rolling a 6?

what is the probability of rolling a 6?

Answers

The total dots outta 6

What is the coordinate of R

What is the coordinate of R

Answers

Answer:

if you go into your reading lessone on one of the sentences in page 2 or 4 there is the answer hope this helped

Step-by-step explanation:

The stochastic variables X and Y describe the outcome of two tosses with a dice. Let Z =X+Y be the sum of the results. How do you calculate P (X|Z=z) (probability of X given Z) and P (Z|X=x) probability of Z given X?

Answers

To calculate the probability of X given Z (P(X|Z=z)), you can use Bayes' theorem. Bayes' theorem states:

P(X|Z=z) = (P(Z=z|X) * P(X)) / P(Z=z)

Here's how you can calculate P(X|Z=z) step by step:

1. Calculate P(Z=z): This is the probability of the sum of the results being z. To calculate this, you would need to consider all possible combinations of X and Y that result in Z=z and sum up their probabilities. Since X and Y are outcomes of a fair dice toss, each has a probability of 1/6. For example, if z=7, the possible combinations are (X=1, Y=6), (X=2, Y=5), (X=3, Y=4), (X=4, Y=3), (X=5, Y=2), and (X=6, Y=1). Summing up their probabilities, P(Z=7) = (1/6) * (1/6) + (1/6) * (1/6) + (1/6) * (1/6) + (1/6) * (1/6) + (1/6) * (1/6) + (1/6) * (1/6) = 1/6.

2. Calculate P(Z=z|X): This is the probability of Z being z given that X takes a particular value. Since the outcomes of Y are independent of X, P(Z=z|X) would be the same as the probability of Y being z-X. For example, if x=3, then P(Z=7|X=3) would be the same as the probability of Y being 7-3=4. Since Y is also a fair dice toss, the probability would be 1/6.

3. Calculate P(X): This is the probability of X taking a particular value. Since X is the outcome of a fair dice toss, each value has a probability of 1/6.

Plug in the calculated values into Bayes' theorem:

P(X|Z=z) = (P(Z=z|X) * P(X)) / P(Z=z)

P(X|Z=z) = (1/6 * 1/6) / (1/6)

Simplifying, P(X|Z=z) = 1/6

Therefore, for any value of z, the probability of X taking any specific value is 1/6.

To calculate the probability of Z given X (P(Z|X=x)), you can use the fact that X and Y are independent tosses. In this case, since X=x is known, the probability of Z being z is simply the probability of Y being z-x. Since Y is also a fair dice toss, each value has a probability of 1/6. Therefore, P(Z|X=x) = 1/6 for any value of z.

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Find a monic cubic polynomial with integer coefficients such that (A polynomial is monic if its leading coefficient is 1.)

Answers

The monic cubic polynomial with integer coefficients is x³ - 3x² + 3x + 2 with the leading coefficient as 1.

In order to find a monic cubic polynomial with integer coefficients, we can use the following method:

Let us assume that the cubic polynomial is of the form:x³ + bx² + cx + d

We need to find the values of b, c, and d such that the polynomial is monic and has integer coefficients.

Since the polynomial is monic, the coefficient of x³ is 1.

Therefore, we can write the polynomial as:x³ + bx² + cx + d = (x - r)(x² + px + q)

Where r is the root of the cubic polynomial, and p and q are constants to be determined.

We know that the sum of the roots of a cubic polynomial is equal to -b/1 = -b.

Therefore, the sum of the roots of our cubic polynomial is equal to:r - p/1 = -bOr,r + p = -b ...(1)

Also, we know that the product of the roots of a cubic polynomial is equal to -d/1 = -d.

Therefore, the product of the roots of our cubic polynomial is equal to r(q - r).

Thus,r(q - r) = -d ...(2)

Solving equations (1) and (2) for r and q, we get:

r = -b/3q = b²/3 - d

Hence, we can write the cubic polynomial as:

x³ + bx² + cx + d = (x + b/3)(x² + (b²/3 - d)x + r(b²/3 - d))

Let us choose d = 2 and r = 1, then we have:b = -3

Substituting these values, we get:x³ - 3x² + 3x + 2 = (x - 1)(x² - 2x - 2)

Therefore, the monic cubic polynomial with integer coefficients is x³ - 3x² + 3x + 2.

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Morgan makes a deposit of $2,000 into a savings account at the end of the 1st year and another one in the same amount at the end of the 3rd year. Manuel makes a deposit of $2,000 at the end of the 2nd year and another one in the same amount at the end of the 4th year. The effective annual interest rate on both investments is 10%. Determine by how much the accumulated amount in Natalia’s account exceeds the accumulated amount in Manuel’s account at the end of 5 years right after interests have been applied.

Answers

At the end of 5 years, the accumulated amount in Natalia's account exceeds the accumulated amount in Manuel's account by $1,468.27.

To calculate the accumulated amount in each account, we can use the formula for compound interest:

\(A = P(1 + r/n)^{nt}\)

Where:

A is the accumulated amount

P is the principal amount (deposit)

r is the annual interest rate

n is the number of times interest is compounded per year

t is the number of years

For both Morgan and Manuel, the principal amount is $2,000, the interest rate is 10%, and the interest is compounded annually. Let's calculate the accumulated amount for each account separately.

For Morgan's account:

- At the end of the 1st year, the accumulated amount is $2,000.

- At the end of the 3rd year, the accumulated amount is $2,000 + $2,000\((1 + 0.1)^2\) = $2,000 + $2,000(1.1)^2 = $4,420.

For Manuel's account:

- At the end of the 2nd year, the accumulated amount is $2,000(1 + 0.1)^2 = $2,000\((1.1)^2\) = $2,420.

- At the end of the 4th year, the accumulated amount is $2,000 + $2,000\((1 + 0.1)^2\) = $2,000 + $2,000(1.1)^4 = $4,847.20.

At the end of 5 years, both Morgan and Manuel will have made their final deposits. Therefore, the accumulated amount in Morgan's account remains $4,420, while the accumulated amount in Manuel's account is $4,847.20 + $2,000\((1 + 0.1)^1\) = $4,847.20 + $2,000\((1.1)^1\) = $6,847.20.

The difference between the accumulated amounts in Natalia's and Manuel's accounts is $6,847.20 - $4,420 = $1,427.20.

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At Camp Sunshine, 4 kids went home sick. Of the remaining campers, 18 kids went hiking and the other 41 kids spent the day swimming. How many kids started the day at Camp Sunshine?

Answers

Answer:

63 kids

Step-by-step explanation:

We can add up the number of students who went home sick, hiked, and swam to find the total amount of people.

\(4+18+41 = 63\)

Therefore, 63 kids started their day at Camp Sunshine.

I get that feeling I oversimplified this one, let me know if I did. I'm not sure if this is right.

Answer:

63 kids

Step-by-step explanation:

We know that there are some kids who went home sick, some went hiking and some went swimming.

The total number of kids that started the day at Camp Sunshine can be found by adding the number who went home sick, went hiking and went swimming.

sick + hiking + swimming

4 went home sick, 18 went hiking and 41 went swimming.

4+ 18 + 41

Add the numbers together

22+ 41

63

63 kids started the day at Camp Sunshine.

Find the exact value of each of the remaining trigonometric functions of θ.
sin⁡ θ =12/13, θ in quadrant I
(Simplify your answer, including any radicals. Use integers or fractions for any numbers in the expression.)

Answers

The exact values of the remaining trigonometric functions of θ are:

cos θ = 5/13

tan θ = 12/5

csc θ = 13/12

sec θ = 13/5

cot θ = 5/12

Given that sin θ = 12/13 and θ is in quadrant I, we can determine the values of the remaining trigonometric functions as follows:

cos θ:

In quadrant I, cos θ is positive. We can use the Pythagorean identity \(sin^2 θ + cos^2 θ = 1\) to find the value of cos θ:

\(cos^2 θ = 1 - sin^2 θcos^2 θ = 1 - (12/13)^2cos^2 θ = 1 - 144/169cos^2 θ = (169 - 144)/169cos^2 θ = 25/169\)

Since cos θ is positive in quadrant I, we take the positive square root:

cos θ = √(25/169)

cos θ = 5/13

tan θ:

tan θ is the ratio of sin θ to cos θ:

tan θ = sin θ / cos θ

tan θ = (12/13) / (5/13)

tan θ = 12/5

csc θ:

csc θ is the reciprocal of sin θ:

csc θ = 1 / sin θ

csc θ = 1 / (12/13)

csc θ = 13/12

sec θ:

sec θ is the reciprocal of cos θ:

sec θ = 1 / cos θ

sec θ = 1 / (5/13)

sec θ = 13/5

cot θ:

cot θ is the reciprocal of tan θ:

cot θ = 1 / tan θ

cot θ = 1 / (12/5)

cot θ = 5/12

Therefore, the exact values of the remaining trigonometric functions of θ are:

cos θ = 5/13

tan θ = 12/5

csc θ = 13/12

sec θ = 13/5

cot θ = 5/12

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