If f(x)=-2x+3then f(3)-f(4)

Answer:

4760

Step-by-step explanation:

First you find out how many are in a dollar so you do

119*4 which is 476

Then because there is $10 you need to do

476 * 10 which would be 4760

Answer:

4,760 ridges

Step-by-step explanation:

10(119x4)

(pemdas)

119x4=476x10=4760

Ax + By = C is the standard form of the line equation, where A and B are constants.

As a result, a linear equation with x and y variables has the standard form: Ax + By = C, in which A, C and B are constant.

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Answer:

y = 10x + 66

Step-by-step explanation:

I don't know if this is how you wanted me to do it, there was not enough information for me to conclude if this was the correct way to do it. but I added 9x + x and whenever there is a variable without a number in front of it the variable = 1x or whatever the variable is. So 9x + 1x= 10x and 17+49= 66 so put it together and you get y= 10x +66

Answer:

y-9x=17-----1

y-x. =49----2

2-1

y-x-(y-9x)=49-17

y-x-y+9x.= 32

8x =32

x=4

y=4+49

=53

x=4

y=53

Answer:

82 years

Step-by-step explanation:

J. Carter age at first inauguration = 52 ---- (missing details)

Required

Determine his age when he died.

Represent his age when he died with x.

So, we have the following expression:

\(2 * Age\ at\ First\ Inauguration - x = 22\)

[Substitute 52 for age at first inauguration]

\(2 * 52 - x = 22\)

[Multiply 2 by 52]

\(104 - x = 22\)

[Collect Like Terms]

\(-x = 22 - 104\)

[Make x the subject]

\(x = 104 - 22\)

\(x = 82\)

Hence, he died at 82 years old.

To stretch a spring 1 ft. from its natural length, a 15 ft-lb work is needed. To stretch a spring 6 in. from its natural length, the required work is 3.75 ft-lb

The work done on a spring is given by the formula:

W = 1/2 . kx²

Where:

k = spring constant

x = spring displacement

From the formula, we know that the work is directly proportional to the square of displacement, or mathematically:

                W ∝ x²

Therefore,

W₁ : W₂ = x₁² : x₂²

Data from the problem

W₁ = 15 ft-lb

x₁ = 1 ft

x₂ = 6 in. = 0.5 ft

Hence,

15 : W₂ = 1² : 0.5²

W₂ = 0.25 x 15 = 3.75 ft-lb

Hence, the required work to stretch the spring 6 in beyond its natural length is 3.75 ft-lb

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Result of the problem   is  f = u + iv is a constant function on D.

To show that f is a constant function, we can use the Cauchy-Riemann equations. Since f is analytic on D, we know that it satisfies the Cauchy-Riemann equations, which state that u_x = v_y and u_y = -v_x.

Taking the partial derivative of u with respect to x and v with respect to y, we get:

u_xx = v_yx
and
v_yy = -u_xy

Since f is analytic, its second partial derivatives exist and are continuous. Therefore, we can substitute these equations into each other and get:

u_xx = -u_xy

Using the mixed partial derivative theorem, we know that u_xy = u_yx, so we can rewrite the above equation as:

u_xx = -u_yx

Since u and v are both real-valued functions, they are continuous on D. Therefore, we can apply the mean value theorem for partial derivatives to both sides of the above equation to get:

0 = u_xx(x,y) + u_yx(x,y) / 2

Since this holds for all (x,y) in D, we can conclude that u is a harmonic function on D. By Liouville's theorem, since u is a bounded harmonic function, it must be constant.

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Adriena's strategy of using function machines to check whether two functions are inverses is a good starting point,

but it is not always sufficient to ensure that two functions are indeed inverses. One additional thing she should test is whether the composition of g(x) and f(x) also yields the identity function.

In other words, she should check whether g(f(x)) = x and f(g(x)) = x for all values of x in the domain of the two functions.

Testing the composition of the two functions is important because it ensures that the inverse relationship between f(x) and g(x) holds for all values of x, not just for the one value that Adriena tests with her function machine strategy.

By testing the composition, Adriena can ensure that the two functions undo each other's actions for all inputs and outputs, and that the inverse relationship holds throughout their domains.

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Answer:

y = mx + b

so its

y = 2x + 5

Answer:4

Step-by-step explanation:22-4=18-4=14-4=10-4=6=2

It will take 8.8 years for the initial deposit to reach $7,500.

The formula to calculate the number of years it takes for an initial deposit to reach a certain amount with compounding interest is A = P(1+r/n)^nt, where A is the final amount, P is the principal, r is the interest rate, n is the number of times interest is compounded per year, and t is the number of years. In this example, P = $6,000, r = 3, n = 12 (monthly compounding of interest) and A = $7,500. We can solve for t, the number of years, by rearranging the equation to t = log(A/P)/log(1+r/n). When we plug in the numbers, we find that it will take 8.8 years for the initial deposit to reach $7,500.

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The algebraic expression which would not have the same meaning if the number and variable were reversed is; m-k.

It follows from the associative property of real numbers that changing the grouping of adding or multiplying real numbers does not change the result.

Hence, only the expression with the subtraction sign will change as a result of reversing the number and variable.

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For the simple harmonic motion equation d=2 sin(pi/3t), the period is 6 seconds.

The period of a simple harmonic motion is the time taken for one complete cycle of the motion. In this equation, d represents the displacement or position of the object at time t. The equation is in the form of sin function with the argument (pi/3)t. The general form of the equation for simple harmonic motion is d=A sin(ωt+φ), where A is the amplitude, ω is the angular frequency, and φ is the phase angle. To determine the period of this motion, we can use the formula T=2π/ω, where T is the period and ω is the angular frequency. In this case, ω=pi/3, so the period is T=2π/(pi/3)=6 seconds (rounded to the nearest second). Therefore, the object completes one full cycle of motion every 6 seconds.

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Answer:

144

Step-by-step explanation:

The combined area of the two triangular faces is \((4)(3)=12\) cm².

The area of the back rectangular face is \((3)(11)=33\) cm².

The area of the bottom rectangular face is \((11)(4)=44\) cm².

The area of the slanted rectangular face is \((5)(11)=55\) cm².

Taking the sum of these areas, the total surface area is \(12+33+44+55=144\) cm².

Answer:

Its C

Step-by-step explanation:

The statement "The height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is 1/(a-b)" is False.

In a uniform distribution, the probability density function (PDF) is constant within the interval [a, b]. The height of the PDF represents the density of the probability distribution at any given point within the interval. Since the PDF is constant, the height remains the same throughout the interval.

To determine the height of the PDF, we need to consider the interval length. In a uniform distribution defined on the interval [a, b], the height of the PDF is 1/(b - a) for the PDF to integrate to 1 over the entire interval. This means that the total area under the PDF curve is equal to 1, representing the total probability within the interval [a, b].

Therefore, the correct statement is that the height of the probability density function f(x) of the uniform distribution defined on the interval [a, b] is not 1/(a - b), but rather it is a constant value necessary for the PDF to integrate to 1 over the interval, i.e., 1/(b - a).

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Answer:

necesitas pensar profesor porque todavía no entiendo bien si quieres

Answer:

the answer

Step-by-step explanation:

y=77 since I am smart

Answer:

8820.26 yd

Explanation:

the formula for finding the area of a circle is π × radius². since the diameter of the circle is given, we can simply divide it by 2 to find the radius.

106 ÷ 2 = 53

now, we can substitute this into the formula:

π × radius²

= 3.14 × 53²

= 8820.26 yd

i hope this helps! :D

The equation of the osculating circle to \(y = x^4 - 2x^2 at x = 1\) is: \((x - 1/2)^2 + (y + 1)^2 = (1/8)^2\)

The first step in finding the equation of the osculating circle to \(y = x^4 - 2x^2\) at x = 1 is to find the values of the first and second derivatives of y with respect to x at x = 1.

\(y = x^4 - 2x^2\)

\(y' = 4x^3 - 4x\)

\(y'' = 12x^2 - 4\)

Evaluate y', y'', and y at x = 1:

\(y(1) = 1^4 - 2(1)^2 = -1\)

\(y'(1) = 4(1)^3 - 4(1) = 0\)

\(y''(1) = 12(1)^2 - 4 = 8\)

The equation of the osculating circle can be expressed as:

\((x - a)^2 + (y - b)^2 = r^2\)

where (a, b) is the center of the circle and r is its radius. To find (a, b) and r, we use the following formulas:

\(a = x - [(y')^2 + 1]^(^3^/^2^)^/ ^|^y''^|\)

\(b = y + y'[(y')^2 + 1]^(^1^/^2^) ^/ ^|^y^''|\)

\(r = [(1 + (y')^2)^(^3^/^2^)^] ^/ ^|^y''^|\)

Substituting the values of x, y, y', and y'' at x = 1, we get:

\(a = 1 - [0^2 + 1]^(^3^/^2^) ^/ ^|^8^| = 1 - 1/2 = 1/2\)

\(b = -1 + 0[0^2 + 1]^(^1^/^2) ^/ ^|^8^| = -1\)

\(r = [(1 + 0^2)^(^3^/^2^)^] ^/ ^|^8^| = 1/8\)

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A residual is the difference between "the measured and predicted values of the quantity of interest".

In regression analysis, a residual would be the difference between an observable and anticipated value.

The formula is;

Residual = Observed value – Predicted value

Some key features regarding the residuals are-

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Answer:

Step-by-step explanation:

ITS RATIONAL!

Answer:

Rational

Explanation:

0.8 can be expressed as the ratio of two integers which is the definition of a rational number.

.................... :)) equation->>> y=-1-4

Answer: y = -7

Step-by-step explanation:

y = mx  +  b

y = -1(3) + -4

y = -3  - 4

y =  -7

Charles will owe A = 2500\(e^{0.12t}\) on his card after t years. The solution has been obtained by using compound interest.

What is compound interest?

Contrary to simple interest, which does not take the principal into account when calculating the interest for the following month, compound interest does. Compound interest is commonly represented in algebra by the letter C.I.

We know that compound interest is given by

A = P\(e^{rt}\)

We are given the following information:

P = $2500

r = 0.12

So, from this we get

A = 2500\(e^{0.12t}\)  

Hence, Charles will owe A = 2500\(e^{0.12t}\) on his card after t years.

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cX(n) is an unbiased estimator of theta when c = (n+1)/n.

To find the constant c that makes cX(n) an unbiased estimator of theta, we need to solve for E[cX(n)] = theta. Using the fact that X(n) follows the distribution F(x) = (x/theta)^n, we have:

E[cX(n)] = ∫0^theta cx(n)(x/theta)^n dx

= c/ (n+1) * theta * [(n+1)/(n+2)]^(n+1)

Setting this equal to theta and solving for c, we get:

c = (n+1)/n

Therefore, cX(n) is an unbiased estimator of theta when c = (n+1)/n.

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Answer:

5/6 cups all together

Step-by-step explanation:

1/3 + 1/3 + 1/6 = 5/6

(a) The 90% confidence interval for the mean weight of Allens Party Mix Lollies,is approximately 180.38 grams to 182.02 grams.(b) Convenience sampling was used in this scenario, where inspectors conveniently selected 30 packets of Allens Party Mix Lollies from a shop. (c) It is not possible to retain 90% confidence while reducing the margin of error in the confidence interval. (d)To estimate the mean weight of Allens Party Mix Lollies within ±1 gram with 90% confidence, a sample size of approximately 55 packets would be required.(e) The probability that the mean weight exceeds 182 grams is approximately 25.14%.

(a)To construct the confidence interval, we use the formula for the confidence interval, which incorporates the sample mean, standard deviation, and critical value. By calculating the values, we can determine a range within which we are 90% confident that the true mean weight of the packets falls.

(b)Convenience sampling involves selecting items or individuals that are readily available and easily accessible. While it can be quick and convenient, it may lead to a non-representative sample. In this case, a random or systematic sampling method would have been a better choice to ensure a more representative sample.

(c) The margin of error in a confidence interval is influenced by the standard deviation, critical value, and sample size. To reduce the margin of error and have a narrower confidence interval, a larger sample size would be required. This trade-off between confidence level, margin of error, and sample size is inherent in statistical analysis.

(d): To determine the required sample size, we use the formula for sample size calculation, which takes into account the desired margin of error, standard deviation, and confidence level. By plugging in the given values, we can calculate the sample size needed to achieve the desired level of confidence.

(e) By assuming a normal distribution for the sample mean, we can calculate the Z-score and use a Z-table or calculator to find the probability that the mean weight exceeds a certain value. In this case, we find the probability that the Z-score is greater than 0.67, indicating the likelihood of the mean weight exceeding 182 grams.

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The critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:  θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.

To find the critical numbers of g(θ) = 4θ - tan(θ) on the interval 0 ≤ θ < 2π, we need to find the values of θ where the derivative of g(θ) is equal to 0 or undefined.

First, we find the derivative of g(θ) using the chain rule and quotient rule:

g'(θ) = 4 - sec²(θ)

To find where g'(θ) is equal to 0, we set the derivative equal to 0 and solve for θ:

4 - sec²(θ) = 0

sec²(θ) = 4

Taking the square root of both sides, we get:

sec(θ) = ±2

Since sec(θ) = 1/cos(θ), we can rewrite this as:

cos(θ) = ±1/2

We know that on the interval 0 ≤ θ < 2π, the cosine function is positive in the first and fourth quadrants and negative in the second and third quadrants.

Therefore, we need to find the values of θ in the first and fourth quadrants where cos(θ) = 1/2, and the values of θ in the second and third quadrants where cos(θ) = -1/2.

For cos(θ) = 1/2, we have:

θ = π/3 or 5π/3 in the first quadrant
θ = 7π/3 or 11π/3 in the fourth quadrant

For cos(θ) = -1/2, we have:

θ = 2π/3 or 4π/3 in the second quadrant
θ = 8π/3 or 10π/3 in the third quadrant

Therefore, the critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:

θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.

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9514 1404 393

Answer:

  48 minutes

Step-by-step explanation:

Each minute, F can build 1/120 of a speaker box, and T can build 1/80 of a speaker box. Working together, in 1 minute, they can complete ...

  1/120 + 1/80  . . . . .  speaker boxes

  = 2/240 +3/240 = 5/240 = 1/48 . . . . speaker boxes

Then there will be 1 complete speaker box after 48 minutes.

Answer:The opposite sides are parallel.

They have four right angles.

Step-by-step explanation: I know it because we all learn it in 5 grade.