Evaluate the derivative of f(x) at x = 1. I'll use the limit definition:
\(\displaystyle \lim_{x\to1} \frac{f(x)-f(1)}{x-1} = \lim_{x\to1} \frac{6x^2-x^3-5}{x-1} = \lim_{x\to1}(-x^2+5x+5) = 9\)
Then using the point-slope formula, the equation of the tangent line to f(x) at the point (1, 5) is
y - 5 = 9 (x - 1)
y = 9x - 4
The equation of "tangent-line" to the curve "y = 6x² - x³" at the point (1, 5) is : y = 9x - 4.
To find the derivative of the function f(x) = 6x² - x³, we differentiate each term with respect to x:
f(x) = 6x² - x³,
f'(x) = d/dx (6x²) - d/dx (x³),
f'(x) = 12x - 3x²,
Now, we need to find f'(1), which means evaluating derivative at x = 1;
f'(1) = 12(1) - 3(1)²,
f'(1) = 12 - 3,
f'(1) = 9,
The slope of tangent-line at point (1, 5) is given by f'(1), which is 9;
Using the point-slope form of equation of line (y - y₁ = m(x - x₁)), where m = slope and (x₁, y₁) is the given point (1, 5);
⇒ y - 5 = 9(x - 1),
Simplify the equation:
⇒ y - 5 = 9x - 9,
⇒ y = 9x - 4,
Therefore, the required equation of tangent-line is y = 9x - 4.
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how can i solve -4.6x = -11.04
Answer:
The last one
Step-by-step explanation:
Answer:
D, Divide both sides by -4.6
Step-by-step explanation:
You want to get the x and the regular integers on separate sides of the equals sign, so you divide the -4.6 to get the x on its own side of the equals sign. That's the first step to solving the equation.
A box of corn flakes has a square base with sides that measure 7 centimeters in length and the height of the box is 20 centimeters. If V represents the volume of the box, what is the maximum volume of corn flakes this box can hold?
A. 900
B. 925
C. 950
D. 980
Answer:B
Step-by-step explanation:
Answer:
its B
Step-by-step explanation:
Complete this sequence of numbers such that the difference between any two adjacent numbers is the same : 3/k, _, _, 9/2k.
The completed sequence is: 3/k, 3/k, 3/k, 9/2k.To complete the sequence of numbers with a constant difference between adjacent numbers, we can calculate the common difference by subtracting the first term from the second term.
Let's denote the missing terms as A and B.
The given sequence is: 3/k, A, B, 9/2k.
The common difference can be found by subtracting 3/k from A or B. Therefore:
A - 3/k = B - A = 9/2k - B.
To simplify, we can equate the two expressions for the common difference:
A - 3/k = 9/2k - B.
Next, we can solve for A and B using this equation.
Adding 3/k to both sides gives:
A = 3/k + 9/2k - B.
Now, we can substitute the value of A into the equation:
3/k + 9/2k - B - 3/k = 9/2k - B.
Simplifying further, we have:
9/2k - 3/k = 9/2k - B.
Cancelling out the common terms, we find:
-3/k = -B.
Multiplying both sides by -1, we get:
3/k = B.
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What is the domain of the function f(x) = √(x+3)²?
Answer: Option 1
Step-by-step explanation:
The domain is the set of x values that make the radicand non-negative. Since the radicand is a perfect square, it will always be non-negative for any real value of x.
Try These B-C
Find the solutions of each equation over the interval [0, 2π). a. 8 cos(x)+ √3 = 5√3
The solution of the integral of 8 cos(x)+ √3 = 5√3 is 8π√3.
Solution of the given function
The given function is 8 cos(x)+ √3 = 5√3
The function can be simplified as follows;
8 cos(x) + √3 = 5√3
collect similar terms together;
8 cos(x) + √3 - 5√3 = 0
8 cos(x) - 4√3 = 0
integral of 8 cos(x) - 4√3 = 8 sin(x) - 4√3x
the value of the integral over (0, 2π)
= 8 sin(0) - 4√3(0) - (8 sin(2π) - 4√3(2π))
= 0 + 8π√3
= 8π√3
Thus, the solution of the integral of 8 cos(x)+ √3 = 5√3 is 8π√3.
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Answer:
\(\text{\textit{x}} \ \ = \ \ \displaystyle\frac{\pi}{6} \ \ \ \text{or} \ \ \ \displaystyle\frac{11\pi}{6}\)
Step-by-step explanation:
Given the trigonometric equation
\(8 \ \cos{\left(\textit{x}\right)} \ + \ \sqrt{3} \ = \ 5\sqrt{3}\),
hence solving for \(\textit{x}\) yields
\(8 \ \cos{\left(\textit{x}\right)}\ = \ 5\sqrt{3} \ - \ \sqrt{3} \\ \\ \\ \-\hspace{8px} \cos{\left(x\right)} \ = \ \displaystyle\frac{4\sqrt{3}}{8} \\ \\ \\ \-\hspace{8px} \cos{\left(x\right)} \ = \ \displaystyle\frac{\sqrt{3}}{2} \\ \\ \\ \-\hspace{29px} \textit{x} \ \ \ = \ {\cos}^{-1}\left(\displaystyle\frac{\sqrt{3}}{2}}}\right) \\ \\ \\ \-\hspace{29px} \textit{x} \ \ \ = \ \displaystyle\frac{\pi}{6}\).
Since cosine is positive in both quadrant I and quadrant IV, thus
\(\textit{x} \ \ = \ \ 2\pi \ - \ \displaystyle\frac{\pi}{6} \ \ = \ \ \displaystyle\frac{11\pi}{6}\).
Therefore the solutions are
\(\textit{x} \ \ = \ \ \displaystyle{\frac{\pi}{6}} \ \ \text{or} \ \ \displaystyle{\frac{11\pi}{6}}\).
Which function will cross the y-axis at (0, 7)?
Oy=x+7
Oy=x-7
0y=x+5
Oy=7x
The value of function which cross the y-axis at point (0, 7) will be;
⇒ y = x + 7
What is substitution method?To find the value of any one of the variables from one equation in terms of the other variable is called the substitution method.
Given that;
The point which cross the function = (0, 7)
Now,
Since, The point which cross the function = (0, 7)
Hence, The point must be satisfy the function.
By option (1);
⇒ y = x + 7
Put (x, y) = (0, 7)
⇒ 7 = 0 + 7
⇒ 7 = 7
Thus, The correct function which passes through the point (0, 7) is,
⇒ y = x + 7
Option (i) is true.
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And yet again another algebra question, 8 POINTS
Answer:
green
Step-by-step explanation:
11a^3−4a^2−14a−7
Answer:
11a³-4a²-14a-7
(The light blue/green one)
Step-by-step explanation:
We'll need to combine like terms (terms with the same variables and exponents)
(4a³-8a-4a²)+(7a³-7-6a)
add/subtract
we'll keep -4a² and -7 as is as there aren't any other terms like them
11a³-14a-4a²-7
put into standard form:
11a²-4a²-14a-7
(The light blue/Green one)
Hope this helps!
what is the mid point of (3.5,2,2) (1.5,-4.8)
The above equation's midpoint is represented by the expression Midpoint = (3.5,2,2) (1.5,-4.8). ( 2.5,-1.3 )
What do you meant by mid point ?Midpoint =( 2.5,-1.3 )
The formula for determining the midpoint is
\($\left(x_m, y_m\right)=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$\)
\($\left(x_m, y_m\right)=$\)the midpoint's coordinates
\($\left(x_1, y_1\right)=$\) the first point's coordinates
\($\left(x_2, y_2\right)=$\) the second point's coordinates
Divide the distance between the two endpoints by 2, then multiply it by 3. The middle of that line is at these distances from each end. As an alternative, multiply the sum of the two endpoints' x coordinates by 2. For the y coordinates, repeat the process. the location on a line when the distances to both ends are equal. a period of time midway between the start and finish of an event.
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The radius of circle is8 units what is the diameter of the circle
Answer:
16 units
Step-by-step explanation:
diameter is double the radius
hope it helps!!!
Answer:
16
Step-by-step explanation:
radius = diameter / 2
diameter= radius x 2
=8x 2
= 16
hope it helps you:)
plz mark me as brainliest
Solve for m∠D:
Extra Characters.............
We can notice that this is a quadrilateral with two pairs of equal sides, with that we will see that:
m∠D = 98°
How to find the measure of angle D?In the image we can see a quadrilateral ABCD, on that image we can see that:
AB = CD
AD = BC
You can notice that because of the "arrows" on the sides.
From that, we can conclude that the measures of the angles meet the conditions:
m∠A = m∠C
m∠D = m∠B
On the image we also can see that:
m∠B = 98°
And the measure of angle B is equal to the measure of angle D, then we can conclude that the measure of angle D is also 98°, so:
m∠D = 98°
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PLEASE HELP I HAVE A TIME LIMIT ON THIS!!
If electricity is billed at a rate of $0.75 per KWH and you used on average 120 KWHs per month, what would you expect to pay each month?
You would expect to pay $90 each month for electricity based on an average usage of 120 KWHs per month.
How to find the expected monthly payTo calculate the monthly cost of electricity, you can multiply the average number of kilowatt-hours (KWH) used per month by the cost per KWH.
Given:
Cost per KWH: $0.75
Average monthly usage: 120 KWHs
To find the monthly cost, you can multiply the cost per KWH by the average monthly usage:
Monthly Cost = Cost per KWH * Average monthly usage
Plugging in the values, we have:
Monthly Cost = $0.75/KWH * 120 KWHs
Calculating the result:
Monthly Cost = $90
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Which equation represents Which equation represents the vertical line passing through (1,-9)?
A.
x = -9
B.
x= 1
C.
y=-9
D. y=1
Equation x = 1 represents the vertical line passing through (1 ,-9).
What is equation of line ?" Equation of a line is defined as an algebraic expression which is represented by linear equation in two variables with highest degree 1. Minimum two coordinates required to draw a line."
According to the question,
Coordinates in the plane represented by (x, y)
We have
Line passing through the point = (1 ,-9)
x = 1 for different values of y represents a line perpendicular to x-axis.
Therefore,
Vertical line passing through (1, -9) is equals x = 1.
Hence, Option(B) is the correct answer.
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use cylindrical coordinates. evaluate x2 dv, e where e is the solid that lies within the cylinder x2 y2
The value of the expression on evaluation is 96π / 5.
Here we have to find the value of the expression.
∫∫∫x² dV
E is indeed the solid that exists inside the cylinder x² + y² = 4 above the surface z =0.
E's precession through into xy-plane is x² + y² ≤4 where r≤2 with Ф[0, 2π].
∫∫∫ x² dV = ∫\(\int\limits^2\pi _0 {} \, \int\limits^2_0{} \, \int\limits^3r_0\) r² cos² Фrd dФ
= \(\int\limits^2\pi _0 {} \, \int\limits^2_0 \int\limits^3r_z=0 {} \,\)r³ cos²Ф dz dr dФ
= \(\int\limits^2\pi _0 {} \, \int\limits^2_0 {} \,\) 3\(r^{4}\)cos²Ф dr dФ
= 3 \(\int\limits^2\pi _0 {} \,\) 1/2 \(2^{5}\)/ 5 ( 1 + cos² Ф )dr dФ
= 48 / 5 [( Ф + 1/2 sin 2Ф)\(]^{2\pi } _{0}\)
= 96π / 5
Therefore the value of the expression is 96π/5.
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Suppose that survey is planned to estimate the proportion of population that is left-handed The sample data will be used to form confidence interval: Which one of the following combinations of sample size and confidence leve will give the widest interval? n E 500, confidence level 909 n = 1,000, confidence level 909 n = 500, confidence level 959 n = 1,000, confidence level 959 Explain why this sample size and confidence level will give the widest interval: The Select-- sample size and Select- confidence level will both tend to increase the width of the confidence interval:
The 500 sample size and 95% confidence level will both tend to increase the width of the confidence interval.
In this question, we have been given the combinations of sample size and confidence level.
We need to select a combinations of sample size and confidence level that will give the widest interval.
We know that the confidence level is typically set in the range of 99% to 80%. The 95% confidence interval will be wider than the 90% interval and which will be wider than the 80% interval.
As we know increasing the confidence will increase the margin of error which results in a wider interval.
But increasing the sample size decreases the width of confidence intervals, as it decreases the standard error.
This means, for the widest interval we need to select a high confidence interval and small sample size.
Therefore, the sample size = 500 and the confidence interval = 95% will give the widest interval.
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Write 3 1/2 cups as a multiplication expression using the unit, 1 cup, as a factor.
I ABSOLUTELY NEED HELP BY TOMORROW!!! I AM GIVING 100 POINTS
3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.
How to Write 3 1/2 cups as a multiplication expression using the unit, 1 cup, as a factor.To express 3 1/2 cups as a multiplication expression using the unit "1 cup" as a factor, you can write it as:
3 1/2 cups = (3 + 1/2) cups = 3 cups + 1/2 cup
Since there are 1 cup in each term, we can rewrite it as:
3 cups + (1/2) cup
Now, we can express each term as a multiplication expression:
3 cups = 3 * 1 cup = 3
(1/2) cup = (1/2) * 1 cup = 1/2
Putting it all together, the multiplication expression is:
3 * 1 cup + (1/2) * 1 cup = 3 + 1/2
Therefore, 3 1/2 cups can be expressed as the multiplication expression: 3 + 1/2.
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How tall is the tree?
5ft
35°
-20ft-
[?]ft
Round to the nearest foot.
Answer:
19
Step-by-step explanation:
tan35=x/20
20tan35=x
x=14.0041507641942
x+5=19.0041507641942
The nearest foot is 19
Help pldssssssss………………..
The missing value for the quadratic function is given as follows:
y = -3.
How to obtain the quadratic function?As a function of it's roots x* and x**, the quadratic function is defined as follows:
y = a(x - x*)(x - x**)
In which a is the leading coefficient.
The roots of the function are the values of x when y = 0, hence:
x* = -4, x** = -2.
Thus:
y = a(x + 4)(x + 2)
y = a(x² + 6x + 8).
When x = 0, y = -8, hence the leading coefficient a of the function is given as follows:
8a = -8
a = -1.
Hence:
y = -x² - 6x - 8;
The missing value is the value of y when x = -1, hence:
y = -(-1)² - 6(-1) - 8
y = -3.
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Given the equation y = 2 csc(7π/4x-21π/2)
The horizontal shift is:
units to the Select an answer (right or left)
The exact period (give as an integer or fraction) is:
The horizontal shift is to the right.
The exact period is 8/7.
How to find the the horizontal shiftIn a trigonometric function, written of the form
y = A csc (Bx - C)
the parameters are interpreted as follows
A is the amplitude
B is period / 2π
C is the horizontal shift
comparing with the equation y = 2 csc (7π/4x - 21π/2). we have that
horizontal shift = -21π/2 since it is positive it is to the right
The exact period is
Period = 2π / (7π/4)
= 8/7
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Write all classifications that apply to the real number 11.
Estimate 6769 x 925 by first rounding each number so that it has only 1 nonzero digit.
The resulting value of the the expression 6769 x 925 by first rounding each number so that it has only 1 nonzero digit is 63,000
Round off
Round off refers a number is made simpler by keeping its value intact but closer to the next number. And it is done for whole numbers, and for decimals at various places of hundreds, tens, tenths, etc.
Given,
Here we need to estimate 6769 x 925 by first rounding each number so that it has only 1 nonzero digit.
Here we have to take individual terms to round off then we get,
By rounding 6799 so that it has only one non-zero digit is rounding it to nearest thousand.
6769 rounds to nearest thousand as 7000 as hundreds digit 7 > 5.
Similarly, by rounding 925 so that it has only one non-zero digit is rounding it to nearest hundred.
925 rounds to nearest hundred as 900 as tens digit 2 < 5.
Now, the estimated value after rounding each number so that it has only one non-zero digit is
=> 7000 x 900
=> 63000.
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y=x^2+4x+3? using a table of values-3 to3
The required graph of the function y=x²+4x+3 for the interval -3 ≤ x ≤ 3.
What is the graph?The graph is a demonstration of curves that gives the relationship between the x and y-axis.
Here,
The given function,
y=x²+4x+3
Since we have given the interval for the value of the x, as -3 to 3
By putting value in the above expression we get y,
put x = -3
y = (-3)² + 4(-3) + 3
y = 9 - 12 + 3
y = 0
Similarly, other values are shown through the map.
Thus, the required graph of the function y=x²+4x+3 for the interval -3 ≤ x ≤ 3.
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What is the area of the figure?
Answer: 23.76 sq yds
Step-by-step explanation:
0.5*9.9*4.7=23.76
Area of triangle: 0.5*b*h
What is the domain of the function y = 2√x-5?
THE ANSWER IS IN THE PHOTO
(x+2) (x+3) + (x-3) (x-2)-2x (x+1)=0
Answer:
Step-by-step explanation:
x(x+3) + 2(x+3) + x(x-2) - 3(x-2) - 2x2 - 2x =0
x2 + 3x + 2x + 6 + x2 - 2x - 3x + 6 - 2x2 - 2x = 0
x2 + x2- 2x2 + 3x + 2x - 2x - 3x - 2x + 6 + 6 = 0
2x2 - 2x2 - 2x + 12 =0
-2x = -12
X = -12/-2
X = 6
here, x2 is x squared.
Alvin is 7 years younger than Elgas. The sum of their ages is 63. What is Elgas age?
Answer:
Elgas is 35.
Step-by-step explanation:
Let's set up an equation.
Alvin is 7 years younger than Elgas.
A = E - 7
The sum of their ages is 63.
A + E = 63
Let's use substitution.
Plug in the first equation of A into the second equation.
A + E = 63
(E - 7) + E = 63
Combine like terms.
2E - 7 = 63
Add 7 to both sides.
2E = 70
Divide both sides by 2.
E = 35
Elgas is 35.
Hope this helps!
Algebra transformation
f(x) =
f(x) =
f(x) =
f(x) =
Algebra transformation
for Graph1 f(x)=f(x)+4
for Graph2 f(x)=-f(x-4)
for Graph3 f(x)=f(x-7)
for Graph4 f(x)=f(x-2)-5
Define reflection of graphIn mathematics, the reflection of a graph is a transformation that produces a mirror image of the original graph across a specific line or point. The line or point across which the reflection occurs is called the axis of reflection.
Graph1
Transform the graph by +4 units in y direction.
f(x)=f(x)+4
Graph2
Transform the graph by +4 units in x direction.
f(x)=f(x-4)
Now take the reflection of graph about x axis
f(x)=-f(x-4)
Graph3
Transform the graph by +7 units in x direction.
f(x)=f(x-7)
Graph5
Transform the graph by -5 units in y direction.
f(x)=f(x)-5
Now Transform the graph by -2 units in x direction.
f(x)=f(x-2)-5
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forty percent of participants in a math contest were boys. fifty percent of the boys revived medals. the number of boys who received the medals was equal to the number of girls who received the medals. what percent of the participants were girls who received medal?
20% of the participants are girls and got a medal, and 33% of the girls got a medal.
What percent of the participants were girls who received medal?
First, we know that 40% of the participants were boys, so the other 60% were girls.
We know that 50% of the boys got a medal, so the percentage (in decimal form) of participants that are boys and got a medal is:
P = (0.4)*(0.5) = 0.2
So, 20% of the participants are boys and got a medal.
We know that the number of girls that got a medal is the same as the number of boys, then we also have that 20% of the participants are women who got a medal.
Then if the percentage of girls that got a medal is x (in decimal form), we must have that:
Q = (0.6)*(x) = 0.2
x = 0.2/0.6 = 0.33
x = 0.33
This means that 33% of the girls got a medal.
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2.
Suppose the population of kangaroos in a different province of Australia is modeled by
the following, with t = 0 representing the year 2020:
P() = 76(0.92)
a.) Using a calculator, find P(10) and interpret it in the context of the problem. Be
specific.
b.) What is happening to the population of kangaroos in this problem? What specific value
in the equation causes this? By what percentage is the kangaroo population decreasing
each year?
c.) As the value of t increases to very large numbers, do you think this model will be
realistic? Explain. Using a calculator, find P(100) to help support your answer.
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
use the fundamental identities to find the exact values of the remaining trig function of x
Step-by-step explanation:
Refer to pic..............