If an object has zero velocity, does that mean it has zero acceleration? Give an example.

At the highest attitude, the  velocity of  the ball is 0 m/s, so the kinetic energy is 0 as well.

Hence the answer is potential energy because it doesn't depend on velocity .

The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that

p - f = 0

where p and f denote the magnitudes of the pulling force and friction.

So we have

p - 12 N = 0

p = 12 N

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.

Answer: That depends on what other components are in the same circuit

along with the 15-ohm resistor.

If there's nothing else, and the battery is connected across the 15-ohm

resistor, then when you measure the voltage across the 15-ohm resistor,

your voltmeter is also connected straight across the battery, and you read

10 volts.

Explanation:

Newton’s laws explain why scientists could expect this to happen , The mass of the rocket decreases as fuel is burned, so the acceleration increases, therefore the correct answer is option B.

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows

As given in the problem Scientists launch a rocket, and they monitor its acceleration and the force exerted by its engines. As the rocket gets higher, the monitors show that the acceleration of the rocket is increasing but the force exerted stays the same.

Newton's laws clarify why scientists may anticipate this to occur. The right response is option B because as fuel is burnt, the rocket's mass reduces, and its acceleration rises.

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Answer: you are right, its entodermic

Explanation:

The enthalpy of the products in an entodermic reaction is greater than the enthalpy in the reactants.

The height of the object, given that the potential energy of the object doubled will be double (option D)

First, we shall list out the given parameters. Details below:

Potential energy is given as:

PE = mgh

Keeping mg constant, we have

PE₁ / h₁ = PE₂ / h₂

Inputting the given parameters, we have

P / h = 2P / h₂

Cross multiply

P × h₂ = h × 2P

Divide both sides by P

h₂ = (h × 2P) / P

h₂ = h × 2

h₂ = 2h

Thus, we can conclude that the new height of the object will also double (option D)

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Answer:

a force is represented by a vector the choice of a reference frame is necessary​

Explanation:

a. The magnitude of the electric force that one particle exerts on the other is 1.72 millinewtons (mN). and b. the force is repulsive

To calculate the magnitude of the electric force between two charged particles, we can use Coulomb's Law, which states that the magnitude of the electric force (F) between two charged objects is given by:

F = k * (|q1| * |q2|) / r^2

where k is the electrostatic constant (k = 8.99 x 10^9 N·m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.

Given:

q1 = 8.01 nC (nanocoulombs)

q2 = 4.22 nC (nanocoulombs)

r = 1.72 m

Converting the charges to coulombs:

q1 = 8.01 x 10^-9 C

q2 = 4.22 x 10^-9 C

Plugging the values into Coulomb's Law:

F = (8.99 x 10^9 N·m^2/C^2) * ((8.01 x 10^-9 C) * (4.22 x 10^-9 C)) / (1.72 m)^2

Calculating the magnitude of the force:

F ≈ 1.72 x 10^-3 N

Therefore, the magnitude of the electric force that one particle exerts on the other is approximately 1.72 millinewtons (mN).

To determine if the force is attractive or repulsive, we need to consider the signs of the charges. If the charges have opposite signs (one positive and one negative), the force is attractive. If the charges have the same sign (both positive or both negative), the force is repulsive.

In this case, both charges are positive, so the force between them is repulsive. The particles will experience a repelling force due to their like charges, causing them to push away from each other.

The question was incomplete. find the full content below:

Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.  

(a) What is the magnitude (in N) of the electric force that one particle exerts on the other?

(b) Is the force attractive or repulsive?

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The orbital period of the rocks in the asteroid belt is approximately 5.73 years.

What is the average distance, a, between the sun and the asteroid, expressed in astronomical units?

The distance from the Sun to the asteroid belt is between 2-4 AU, or between 300 and 600 million kilometers (186-272 million mi).

Using Kepler's Third Law, we have:

P² = a³

where P is the orbital period of the rocks in years, and a is the semi-major axis of their orbit in astronomical units (AU).

Substituting a = 3.2 AU, we get:

P² = (3.2 AU)³

P² = 32.768 AU³

P = \(\sqrt{32.768}\) years

P ≈ 5.73 years

Therefore, the orbital period of the rocks in the asteroid belt is approximately 5.73 years.

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The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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A. After the collision, the Kauaion has a velocity of 75,000 m/s.

B. After the collision, the Waimeaon has a velocity of 25,000 m/s.

The velocity of the Kauaion and the Waimeaon after the collision is calculated by applying the principle of conservation of linear momentum as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

Let the mass of the Waimeaon = m

3m(50000) + m(100000) = 3mv₁  + mv₂

m(150,000) + m(100000) = m(3v₁  + v₂)

150,000 + 100000 = 3v₁  + v₂

250,000 = 3v₁  + v₂

v₂ = 250,000 - 3v₁  --------(1)

u₁ + v₁ = u₂ + v₂

v₂ = u₁ + v₁  - u₂

v₂ = 50000 + v₁ - 100000

v₂ = v₁ - 50000 ----(2)

Solve (1) and (2) together

v₁ - 50000 = 250,000 - 3v₁

4v₁ = 300,000

v₁  = 300,000/4

v₁  = 75,000 m/s

v₂ = v₁ - 50000

v₂ = 75,000 - 50,000

v₂ = 25,000 m/s

Thus, after the collision, the Kauaion has a velocity of 75,000 m/s.

After the collision, the Waimeaon has a velocity of 25,000 m/s.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

that's true.

Explanation:

that's the reason why oxygen supports burning.

Answer: A solar eclipse occurs when the moon passes in between the Earth and sun, casting a shadow down on the surface of our planet. If you're in the path of the shadow, the moon destroys the sun. No, wait, I mean the moon blocks the sun briefly.A lunar eclipse happens when the moon passes through the Earth's shadow. We see one limb of the moon darken until the entire thing is in shadow.An eclipse does not occur every month, because one month after an eclipse the relative geometry of the Sun, Moon, and Earth has changed. As seen from the Earth, the time it takes for the Moon to return to a node, the draconic month, is less than the time it takes for the Moon to return to the same ecliptic longitude as the Sun.

Explanation:

Answer:

Because the moon's orbit wobbles up and down with respect to the Earth, the satellite's shadow can be too high or too low to cause a solar eclipse. If the moon partially covers the sun for a given location, that area experiences a partial solar eclipse. But if the moon fully covers the sun, it will cause either a total solar eclipse or an annular solar eclipse; that's when a bright ring of light is still visible in the sky around the dark silhouette of the moon.

In physics, a lower fixed point refers to the minimum temperature at which a particular substance or system can reach and below which it cannot be cooled further.

It is a fundamental concept in the study of thermodynamics, specifically in relation to phase transitions and the behavior of substances at low temperatures.

The lower fixed point is often associated with the concept of absolute zero, which is the lowest possible temperature in the Kelvin scale (-273.15 degrees Celsius or -459.67 degrees Fahrenheit).

At absolute zero, particles in a substance possess the minimum amount of energy and their motion ceases, resulting in the absence of thermal energy.

The lower fixed point serves as a reference point for temperature scales, such as the International Temperature Scale of 1990 (ITS-90), which defines temperature measurements based on fixed points like the melting point of certain substances and the triple point of water.

These fixed points provide reproducible and well-defined temperature values for calibration and measurement purposes.

Understanding the lower fixed point is crucial for various scientific and technological applications, such as cryogenics, superconductivity, and the study of quantum phenomena at extremely low temperatures.

By pushing the boundaries of cooling techniques, researchers aim to approach the lower fixed point and explore the fascinating properties and behaviors of matter at such extreme conditions.

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In order to determine which orientation results in a larger depolarization factor for the similar dielectric ellipsoids placed in an electric field, we need to consider the shape and alignment of the ellipsoids with respect to the electric field.

The depolarization factor measures the reduction in the electric polarization of a material due to its shape and alignment in an electric field. It is influenced by the geometry of the material and how it interacts with the electric field.

Qualitatively, if the ellipsoids are aligned in such a way that their major axes are parallel to the electric field lines, the depolarization factor would be smaller. This is because the electric field would act along the long axis of the ellipsoid, resulting in less distortion of the polarized charges inside the material. The polarization would be more effectively aligned with the electric field, minimizing the depolarization effect.

On the other hand, if the ellipsoids are oriented such that their major axes are perpendicular or at an angle to the electric field lines, the depolarization factor would be larger. In this case, the electric field would act in a direction that is not aligned with the major axis of the ellipsoid, causing more distortion and misalignment of the polarized charges inside the material. This results in a larger depolarization effect.

Without a specific diagram or more information about the orientations shown in Figure P5.5, it is difficult to determine the exact orientation with the larger depolarization factor. However, based on the general understanding of the relationship between alignment and the depolarization effect, the orientation where the major axes of the ellipsoids are perpendicular or at an angle to the electric field lines is likely to result in a larger depolarization factor.

Answer:

1. A fossil that is widespread geographically but only occurs in one layer or a small number of layers of rock

2. Sediment deposited into water will spread in a horizontal and continuous sheet

3. Any undisturbed sequence of layered rocks has the oldest rock on the bottom and newest rock on the top

4. Study of fossils

5. Study of rock layers and the process that form them

Sorry if any of these are wrong

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

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When a butane lighter is lit, chemical energy transforms into heat energy.

Energy cannot be created or destroyed, says the law of conservation of energy. However, it has the ability to change its form. The total energy of an isolated system is constant when all sources of energy are taken into account.

The chemical energy is the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.

In butane energy is stored as a chemical energy as  bonds of chemical molecules and when it is lit, the chemical energy of the butane transforms into heat energy.

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Neither Technician A nor Technician B is correct about the

statements they made.

This is referred to as an interface between radio waves and

helps in their propagation through currents moving in metal

conductors. It is mostly used with a transmitter or receiver for

an excellent output.

If an antenna is defective, it can't receive any type of signal If

the resistance is greater than zero then it means the antenna is

defective which is why neither of the technicians are correct.

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Answer:

I believe the answer is that the light with the higher frequency refracts more than light with a lower frequency

Explanation:

The current state of research offers some evidence that life events can cause changes in personality traits and that various life events may connect differently to various trait domains.

What is anecdote?

A brief narrative or account abou life events changet a person or event that is typically humorous, instructive, entertaining, or biographical in nature is known as an anecdote.

How do life events change your personality?

These ideas contend that because life events alter, interrupt, or reroute people's habits of thought, feeling, and action, they have long-lasting consequences on personality traits.

Hence is a changes in personality traits a correct answer.

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Answer:

Five examples of locomotor movements are:

Hopping

Galloping

Walking

Running

Skipping

Explanation:

I hope it helps ❤❤

The distinction among renewable and nonrenewable is substantial. One explanation for why some materials are unique to specific locations is the movement of tectonic plates. On Earth, not every resource can be found.

Huge fragments of the Planet's crust and upper mantle make up tectonic plates. They are composed of both continental and oceanic crust. Along pre ridges and the significant faults that define the plate boundaries, earthquakes happen.

According to the idea of plate tectonics, Earth's crust is made up of enormous solid rock slabs called "plates" that move across the beneath, the rock inner layer above the planet's core. The crust is a part of the solid outer layer of the earth.

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Answer:

P₂ = 4098.96 Pa

Explanation:

For this exercise let's use Bernoulli's equation

Let's use the subscript 1 for the point of the liquid surface and the subscript 2 for the ends (point A)

         P₁ + ½ ρ v₁² + ρ g y₁ = P₂ + ½ ρ v₂² + ρ g y₂

the velocity at the end of the tank

        v₂ = w r₂

the velocity at the surface of the liquid is

        v₁ - w r₁

where r₂ = 1.5 m and r₁ = 1 m

the tank pressure is P₁ = P₀ = 0.1 10³ Pa

         P₂ = P₁ + ½ ρ [w² (r₁² - r₂²)] + ρ g (y₁ -y₂)

We must remember that the pressure measurements the distances are measured from the lowest part to the surface that has zero height

let's reduce the magnitudes to the SI system

         w = 3 rev / min (2π rad / 1rev) (1 min / 60 s) = 0.314159 rad / s

let's calculate

        P₂ = 0.1 10³ + ½ 800 0.314159² |(1² -1.5²)| + 800 9.8 |(1-1.5)|

        P₂ = 0.1 103 +78.96 + 3920

        P₂ = 4098.96 Pa

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

\(K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\\)

the final kinetic energy of the package;

\(K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J\)

the fraction of the initial energy lost;

\(= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71\)