If a translation of (x, y) = (x + 6. y-10) is applied to figure
ABCD, what are the coordinates of D'?
0 (-5.-2)
O (1.-12)
O (4, -15)
0 (-9,-6)​

0.8 is greater than 0.3 an image is attached to show the plotting on the number line.

A number line is a one-dimensional horizontal line where we can represent any real number. The origin of the number line is represented by zero left to it are all negative real numbers and right to it are all positive real numbers.

Given, are two decimals 0.3 and 0.8.

We know 0.3 lies between 0 and 0.5 and 0.8 lies between 0.5 and 1.

∴ 0.8 > 0.3.

The plotting of the numbers is attached in the image.

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The pairs of angles that  have equal measures are:

The pairs of angles that do not  have equal measures are:

When two lines or rays converge at the same point, the measurement between them is called a "Angle."

It is given that:

Both MJK and  PJR can be seen as (Unequal angles)

The angle MJK  is ( 90 degrees), then  angle PJR will be ( 48 + 46 )= 94 degrees

Both LJP and NJR  can be seen as ( Equal angles)

The measure of angle LJP = 48 + 46 + 48 = 142 degrees

The measure of angle NJR = 48 + 48 + 46 = 142 degrees

KJR & MJP = Unequal

The angle KJR will now be [ 360 - (46+48+48+46+90) ]

= 82 degrees

The  angle MJP  will be ( 94 degrees)

Both KJL & LJM  are Unequal, then

The angle KJL  will be  42 degrees, then angle LJM  will be ( 90 - 42 )

= 48 degrees

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CHECK THE COMPLETE QUESTION BELOW:

Determine whether each of the following pairs of angles have equal measures. Drag and drop each pair

of angles into the correct catagory to show which pairs have equal measures.

MO

N

46°

42°

48°

46°

R

ZMJK and LPUR

ZLJP and ZNJR

ZKJR and ZMJP

MJP and ZPJR

ZKIL and ZUM

Equal Measures

Unequal Measures

The area of the square is 25ft² and the perimeter is 20ft.

It's important to note that the area of a square is calculated as:

= Side ²

The perimeter is calculated as:

= 4 × Side

From the information given, the side is 5ft. The area will be:.

= 5 × 5

= 25ft²

The perimeter will be:

= 4 × Sode

= 4 × 5ft.

= 20 feet

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The distance that the handler move from the starting point to the return point if he creates an arc of a circle with radius 75 feet is 471 feet

The formula for calculating the circumference of a circle is expressed as:

C = 2πr

r is the radius of the circle

Given the following parameters

r = 75ft

Substitute the parameters to have:

C = 2(3.14)(75)
C = 471feet

Hence the distance that the handler move from the starting point to the return point if he creates an arc of a circle with radius 75 feet is 471 feet

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Answer:

Thus: m=14°, n=28°

Step-by-step explanation:

Angles in a Circle

Let's review some concepts about angles in a circle.

The central angle is formed between two radii and its vertex lie at the center of the circle.

The inscribed angle is formed between two chords whose vertex lies on the circumference of a circle.

The measure of a central angle x formed by the same lines that define an inscribed angle y is:

x = 2y

Following the definitions and relations above, we find that:

The first statement leads to:

98 = 2 (35+m)

Dividing by 2:

49 = 35 + m

m = 49 - 35 = 14

m = 14°

The second statement leads to:

n = 2m = 28°

Thus: m=14°, n=28°

Answer:

64 square centimeters

Step-by-step explanation:

The surface are of a pyramid is found by finding the sum of the area of the four sides and the base.

Finding the triangular face:

Area of triangle = \(\frac{1}{2} b h\) = \(\frac{1}{2}*4*6 = 12\)

12 * 4 (4 sides) = 48 square cm

Finding the Base = \(w * l = 4 * 4 = 16\)

Finally, we add it together. 48 + 16 = 64

The Central Limit Theorem states that for a random sample of n observations drawn from any population with a finite mean μ and a finite standard deviation σ, the sampling distribution of the sample mean approaches a normal distribution as the sample size increases, regardless of the shape of the population distribution.

To apply the Central Limit Theorem, the following condition is necessary:

1. The random sample should be selected from a population that has a finite mean (μ) and a finite standard deviation (σ).

In this case, the population mean is given as $75 and the population standard deviation is given as $5. Since both the mean and standard deviation are finite, the condition for applying the Central Limit Theorem is satisfied.

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The volume of one mole of an ideal gas at 255°C and 1772 mmHg is calculated using the ideal gas law, which gives V1 = 22.4 L. The formula is V2 = (nRT2) / P2, resulting in a volume of 0.0244 L.

Given:One mole of an ideal gas occupies 22.4 L at standard temperature and pressure.Now, we need to calculate the volume of one mole of an ideal gas at 255°C and 1772 mmHg.The volume of the ideal gas can be calculated by using the ideal gas law which is given by:PV = nRT

Where,P = pressure

V = volume of the gas

n = number of moles

R = universal gas constant

T = temperature of the gas

At standard temperature and pressure (STP), T = 273 K and P = 1 atm.

The volume of 1 mole of an ideal gas at STP, V1 = 22.4 L.From the given data, the temperature of the gas is T2 = 255°C = 528 K and the pressure of the gas is P2 = 1772 mmHg.

To calculate the volume of the gas at these conditions, we can use the formula:V2 = (nRT2) / P2Where n = 1 moleR = 0.0821 L atm/K mol

Putting the given values in the above equation we get,

V2 = (1 * 0.0821 * 528) / 1772V2

= 0.0244 L

So, the volume of one mole of an ideal gas at 255°C and 1772 mmHg is 0.0244 L. This is the answer to the given question which includes the given terms in it.

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Answer:

(-4^9)^2 = -4^18

(4^6)^-3 = 1/4^18

(4^0)^-9 = 4^0

(4^-3)^-3 = 4^9

Step-by-step explanation:

Here, we want to match what we have on the left with the expressions on the right.

(-4^9)^2

= -4^18

(4^6)^-3

= 4^-18 = 1/4^18 according to laws of indices

(4^0)^-9 = 4^0

(4^-3)^-3

= 4^9

Answer:

(-4^9)^2 = -4^18

(4^6)^-3 = 1/4^18

(4^0)^-9 = 4^0

(4^-3)^-3 = 4^9

Step-by-step explanation:

Answer:

Leroy ate the most

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

He equation that rightly shows the Commutative Property of addition is

10 x3/10 = 3/10 x 10

The Commutative Property of Multiplication states that changing the order of the factors doesn't change the product. In other words, when you multiply two figures, it doesn't count which number comes first. The equation 10 x3/10 = 3/10 x 10 is an illustration of this property, as both sides of the equation represent the same value, indeed though the order of the factors is different.

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a) The general solution of the DE should include all possible solutions, which may not necessarily take this specific form.

b)  The unique solution to the BVP is:

y = (-16/5)x^3 + (7/5)x^(-2)

A) To verify that y=c1x^3+c2x^2 is a solution of the given DE, we need to find its first and second derivatives and substitute them into the DE:

y = c1x^3 + c2x^2

y' = 3c1x^2 + 2c2x

y'' = 6c1x + 2c2

Substituting these expressions into the DE, we get:

x^2(6c1x + 2c2) - 4x(c1x^3 + c2x^2) + 6(c1x^3 + c2x^2) = 0

Simplifying this equation, we get:

2c2x^4 + 6c1x^4 = 2(c1 + 3c2)x^4

Since this equation holds for any value of x, we can conclude that y=c1x^3+c2x^2 is indeed a solution of the given DE.

However, this solution is not a general solution of the DE because it only represents a particular family of solutions that can be obtained by choosing values for the constants c1 and c2. The general solution of the DE should include all possible solutions, which may not necessarily take this specific form.

B) To find a solution to the BVP: x^2y'' - 4xy' + 6y=0 , y(1)=-3, y'(-1)=2, we can use the method of undetermined coefficients. We assume that the solution takes the form y=x^n, where n is a constant to be determined. Then, we find the first and second derivatives of y:

y = x^n

y' = nx^(n-1)

y'' = n(n-1)x^(n-2)

Substituting these expressions into the DE, we get:

x^2(n(n-1)x^(n-2)) - 4x(nx^(n-1)) + 6x^n = 0

Simplifying this equation, we get:

n(n-3)x^n = 0

Since x^n cannot be zero for all x, we must have n=3 as the only possible value. Therefore, the general solution of the DE can be written as:

y = c1x^3 + c2x^(-2)

To find the particular solution that satisfies the given boundary conditions, we use y(1)=-3 to get:

c1 + c2 = -3

Then, we use y'(-1)=2 to get:

3c1 - 2c2 = 2/(-1)

Solving these two equations simultaneously, we get:

c1 = -16/5

c2 = 7/5

Therefore, the unique solution to the BVP is:

y = (-16/5)x^3 + (7/5)x^(-2)

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Answer:

its C

Step-by-step explanation:

I just took the test

Answer:

point c

Step-by-step explanation:

gimme points and i will give explain

The value of the equation is y = 0.75x , where y is the total cost of the ticket and x is the original cost of the ticket

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the original cost of the ticket be represented as x

Let the discounted price of the ticket be y

Now , the percentage of discount = 35 %

So , the discounted price of the ticket y = original cost of the ticket - ( 35/100 ) x original cost of the ticket

Substituting the values in the equation , we get

The discounted price of the ticket y = x - 0.35x

On simplifying the equation , we get

The discounted price of the ticket y = 0.75x

y = 0.75x   be equation (1)

Now , the cost of the ticket cannot be a negative value so it should lie in the first quadrant

Hence , the equation is y = 0.75x

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Answer:

yes, its a solution

Step-by-step explanation:

6(-2)+5(1)=-7

-12+5=-7   this is correct

2(-2)-4(1)=-8

-4-4=-8     this is also correct

A. In the alternate universe, the p subshell would have 5 orbitals.

B. In the alternate universe, the d subshell would have 10 orbitals.

In the alternate universe where the possible values of mℓ range from -l-1 to l+1, the number of orbitals in each subshell can be determined.

A. For the p subshell, the value of l is 1. Therefore, the range of mℓ would be -1, 0, and 1. Including the additional values of -2 and 2 from the alternate universe, the total number of orbitals in the p subshell would be 5 (mℓ = -2, -1, 0, 1, 2).

B. For the d subshell, the value of l is 2. In the conventional universe, the range of mℓ would be -2, -1, 0, 1, and 2, resulting in 5 orbitals. However, in the alternate universe, the range would extend to -3 and 3. Including these additional values, the total number of orbitals in the d subshell would be 10 (mℓ = -3, -2, -1, 0, 1, 2, 3).

Therefore, in the alternate universe, the p subshell would have 5 orbitals, and the d subshell would have 10 orbitals.

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The VSWR on the 50 Ω line is 2.68.

(a) To calculate the reflection coefficient at the input of the line, we can use the equation:

Γin = (ΓL + e^(j2βL))/(1 + ΓL*e^(j2βL))

where Γin is the reflection coefficient at the input of the line, ΓL is the reflection coefficient of the load, β is the propagation constant of the line, L is the electrical length of the line in radians, and j is the imaginary unit.

In this case, ΓL = 0.5, β = 2π/λ (where λ is the wavelength of the signal on the line), L = 45° = π/4 radians, and the line has a characteristic impedance of 50 Ω.

To find the wavelength, we can use the equation:

λ = v/f

where v is the speed of light and f is the frequency of the signal. Assuming a frequency of 1 GHz, we get:

λ = 3e8 m/s / 1e9 Hz = 0.3 m

So, β = 2π/λ = 20.94 rad/m.

Substituting these values into the equation for Γin, we get:

Γin = (0.5 + e^(j220.94π/4))/(1 + 0.5e^(j220.94*π/4))

Using Euler's formula (e^(jθ) = cos(θ) + j*sin(θ)), we can simplify this expression:

Γin = (0.5 + j0.5)/(1 + 0.5*j)

Multiplying the numerator and denominator by the complex conjugate of the denominator, we get:

Γin = (0.5 + j0.5)(1 - 0.5j)/(1 + 0.25) = (0.75 + j0.25)/1.25

So, the reflection coefficient calculated at the input of the line is:

Γin = 0.6 + j0.2

(b) To calculate the VSWR on the 50 Ω line, we can use the formula:

VSWR = (1 + |Γin|)/(1 - |Γin|)

where |Γin| is the magnitude of the reflection coefficient at the input of the line.

In this case, we calculated that Γin = 0.6 + j0.2. The magnitude of this complex number is:

|Γin| = sqrt(0.6^2 + 0.2^2) = 0.632

So, the VSWR on the 50 Ω line is:

VSWR = (1 + 0.632)/(1 - 0.632) = 2.68

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Answer:

angle qpt equals 125

Step-by-step explanation:

QPT=60,RPS=45, and SPT=90-60=30

so its sum will be 125

The solutions to the systems of equations are x = 30 and y = 54

The correct linear equation is expressed as:

4x+y+6=180 ................1

2x+2y+12=180 .................2

The equations can also be written as:

4x + y = 174 .................... 3 × 2

2x + 2y = 168 ................... 4 × 1

______________________________________

8x + 2y = 348

2x + 2y = 168

Subtract both equations

8x - 2x = 348 - 168

6x = 180

x = 180/6

x = 30

Substitute x = 30 into equation 3:

4x + y = 174

4(30) + y = 174

120 + y = 174

y = 174 - 120

y = 54

Therefore the solutions are x = 30 and y = 54

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The value of x in the chord intersection is 16 units.

The intersecting chord theorem  states that the products of the lengths of the line segments on each chord are equal. In other words, If two chords intersect in a circle , then the products of the measures of the segments of the chords are equal.

Therefore, lets find the value of x in the intersecting chords as follows:

15 × x = 24 × 10

15x = 240

divide both sides of the equation by 15

x = 240 / 15

x = 16

Therefore,

x = 16 units

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Answer:

Step-by-step explanation:

By the Pythagorean Theorem

c^2=a^2+b^2 ( where c is the hypotenuse and a and b are the legs of a right triangle)

c^2=15^2+8^2

c^2=225+64

c^2=289

c=17 feet

Answer:

if its 6² it means 6×6 =36

Answer:

36

Step-by-step explanation:

6² = 6 × 6 = 36

Note any number squared, raised to the power of 2 is the number multiplied by itself.

Answer: its the 2nd one

Step-by-step explanation:

By using standard error, The nurse sampled approximately 100 patients to analyze their exercise time.

To determine the sample size, we can use the formula for the standard error of the mean:

Rearranging this formula to solve for the sample size, we get:

Plugging in the values given in the problem, we get:

However, because the population size is large (i.e. infinite), we can use the rule of thumb that a sample size of at least 30 is sufficient for a normal distribution. Therefore, the nurse should sample at least 30 patients, but she likely sampled around 100 patients to obtain a standard error of 3 minutes with a normal distribution of exercise time.

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It would take 4 days for the surface of the pond to be covered if we start with 8 lily pads.

Since each lily pad doubles in area every day, after 10 days, the single lily pad covers the entire pond. This means that on the first day, the lily pad covers half of the pond's area. If we start with 8 lily pads instead, the combined area of the lily pads on the first day would be 8 times the area of a single lily pad.

Therefore, the combined area of the 8 lily pads would cover 8 times half of the pond's area, which is equivalent to 4 times the pond's area. Since the combined area of the 8 lily pads is four times the pond's area, it would take 4 days for the 8 lily pads to cover the entire pond, assuming each lily pad doubles in area each day.

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