If |a b c d e f g h i| = 5, find | a b c 7d + a 7e + b 7f + c g h i| | a b c 7d + a 7e + b 7f + c g h i| = (Simplify your answer.)

Step-by-step explanation:

Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?

A scale factor of 260:1, if the height of the scale drawing is 1.2 feet, the actual height of the statue is 312.0 feet. This is calculated by multiplying the height of the drawing by the scale factor.

The actual height of the statue, we need to scale up the height of the drawing using the given scale factor of 260:1.

The height of the drawing is 1.2 feet, we can calculate the actual height of the statue by multiplying the height of the drawing by the scale factor:

1.2 feet * 260 = 312 feet

Therefore, the actual height of the statue is 312.0 feet.

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Answer:

Maximum height of the ball = 100 m

Time to reach the maximum height = 2.5 seconds

Step-by-step explanation:

Function that models the height h(t) of the ball and time 't',

h(t) = -16t² + 80t

Convert this equation into vertex form,

h(t) = -16(t²- 5t)

     = -16[t² - 2(2.5t) + (2.5)² - (2.5)²]

     = -16[[t² - 2(2.5t) + (2.5)²] + 16(2.5)²

     = -16(t - 2.5)² + 16(6.25)

     = -16(t - 2.5)² + 100

By comparing this equation with,

g(t) = a(x - h)² + k

Here, (h, k) is the vertex of the parabola.

Vertex of the given parabola will be → (2.5, 100)

Therefore, maximum height of the ball = 100 m

Time taken by the ball to reach the maximum height = 2.5 seconds

Answer:

All quadrilaterals are squares. All rectangles are quadrilaterals.

All quadrilaterals are parallelograms.

Step-by-step explanation:

Answer:

\(78 \frac{5}{8} \)

Step-by-step explanation:

\(for \: the \: width = 8 \tfrac{1}{2} \\ = \frac{17}{2} \\ sine \: the \: width \: is \: 9 \frac{1}{4} a \: long \\ 9 \ \frac{1}{4} = \frac{37}{4} \\ lenht \: of \: the \: plot = \ \frac{17}{2} \times \frac{37}{4} = \frac{629}{8} = 78 \ \frac{5}{8} \\ it \: will \: be78 \ \frac{5}{8}long \)

Answer:

\(x= 3i, -3i\)

Step-by-step explanation:

please mark me brainliest :)

Answer:

\( 2\sqrt{2} \)

Step-by-step explanation:

\( g(x) = \sqrt{x - 4} \)

\( h(x) = 2x - 8 \)

\( h(10) = 2(10) - 8 = 12 \)

\( g(h(10)) = g(12) = \sqrt{12 - 4} \)

\( g(h(10)) = \sqrt{8} = 2\sqrt{2} \)

Answer: \( 2\sqrt{2} \)

Answer:

2 square root 2

Step-by-step explanation:

Answer:

Jose would have accumulated $23,325.21

Step-by-step explanation:

Giving the following information:

The interest rates are not clear. If they are not correct, replace them in the formulas.

Jose:

Initial investment= $8,000

Interest rate= 7.38 compounded daily.

Adam:

Initial investment= $8,000

Interest rate= 7.78% compounded annually.

Future value= 8,000*3= 24,000

First, we need to calculate the time required for Adam to triple its investment.

n= ln(FV/PV) / ln(1+i)

n= ln(24,000/8,000) / ln(1.0778)

n= 14.66 years

It will take Adam 14.66 years to triple the investment.

Now, the future value for Jose:

FV= PV*(1+i)^n

PV= 8,000

i= 0.0738/365= 0.0002

n= 14.66*365= 5,351 days

FV= 8,000*(1.0002^5,351)

FV= $23,325.21

Jose would have accumulated $23,325.21

Answer:

$23294

Step-by-step explanation:

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deltamath gang

Answer: The equation that represents the amount of money Mrs. Espinoza will pay to rent the bounce house for h hours is:

t = 15 + 5h

Step-by-step explanation: From the table, it can be seen that the rental cost is $15 for the first hour and $5 for each additional hour.

The rental cost t can be represented by the equation t = 15 + 5h

The first term, 15, represents the fixed cost of $15 for the first hour.

The second term, 5h, represents the variable cost of $5 for each additional hour.

So if Mrs Espinoza rents the bounce house for h hour, the cost will be 15+5h.

Labeling:

t represents the total amount that Mrs. Espinoza will pay to rent the bounce house

h represents the number of hours that Mrs. Espinoza rents the bounce house.

15 is the fixed cost of renting the bounce house for the first hour.

5 is the variable cost for each additional hour.

The equation t = 15 + 5h represents the total cost of renting the bounce house for h hours.

Three consecutive even integers can be written with difference of two.

The even integers are defined as the numbers that are completely divisible by two. The complete division means that the result of division will be zero. The even integers are always present after a gap of one number in between.

This means that there is a difference of two numbers between integers. Firstly of all, the first even number is two. Following it four. There is a gap of number that is three. Hence, to find the consecutive even integers, add number two to the number.

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The proportion of the class with a midterm grade less than 75 is approximately 0.3085, or 30.85%. This means that 30.85% of the class is expected to have a midterm grade lower than 75.

We can use the cumulative distribution function (CDF) of the normal distribution to find the proportion of the class with a midterm grade less than 75.

The CDF of a normal distribution with mean μ and standard deviation σ evaluated at a point x is given by the formula:

CDF(x) = 0.5 * [1 + erf((x - μ) / (σ * √2))]

where erf is the error function.

For this problem, μ = 78 and σ = 6, and x = 75, so the CDF can be calculated as follows:

CDF(75) = 0.5 * [1 + erf((75 - 78) / (6 * √2))]

= 0.5 * [1 + erf(-0.3536)]

The value of erf(-0.3536) can be looked up in a table or calculated using a software package. The result is approximately -0.383.

CDF(75) = 0.5 * [1 + -0.383] = 0.5 * [0.617] = 0.3085

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Answer:

3, 2

Step-by-step explanation:

In order for the equation to be equal to zero, the following must be true:

x-3 = 0   or,

x-2 = 0

Therefore the 2 solutions are x=3, x=2

Answer: your mom

Step-by-step explanation:  just cause

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data:

9/16 + 1/16 * (2/3)^(-1)

Step 02:

we must apply the algebraic rules to find the solution

The answer is:

21 / 32

The joint PDF which is uniform over the triangle with vertices  is:

f(x,y) = 2, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x.

Since the joint PDF is uniform over the triangle with vertices at (0,0), (0,1), and (1,0), the joint PDF can be expressed as:

f(x,y) = c, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x,

where c is a constant that ensures that the total probability over the entire region is equal to 1. To find c, we can integrate the joint PDF over the entire region:

\(\int \int f(x,y)dydx = \int ^1_0 \int _0^{(1-x)} c dydx\)

\(= \int ^1_0 cx - cx^2/2 dx\)

= c/2

Since the total probability over the entire region must be equal to 1, we have:

∫∫f(x,y)dydx = 1

Thus, we have:

c/2 = 1

c = 2

Therefore, the joint PDF is:

f(x,y) = 2, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x.

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The measure of angles are:

3. <1 = 63, <2= 49, <3= 87, <4= 44

4. <1= 52, <2= 79, <3= 38

The total of a triangle's three internal angles is 180 degrees, as stated by the angle sum feature of a triangle. A closed shape with both inner and exterior angles, a triangle is created by three line segments. When the values of the other two angles are known, one can utilise the angle sum property to determine the measure of an unknown interior angle.

3. <3 + 93=1 80 (linear pair)

<3 = 87

<2 = 49 (Vertical opposite angle)

<3 + <4 + 49= 180  (Angle sum property)

87 + <4 + 49= 180

<4 = 44

and, <2 + <1 + 68= 180  (Angle sum property)

49+ <1 + 68= 180

<1 = 63

4. <3 = 38 (alternate interior angle)

<2 + <3 + 63= 180  (Angle sum property)

38+ <2 + 63= 180

<2 = 79

and, <1 + 90 + 38= 180  (Angle sum property)

<1= 52

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Answer:

Volume of prism: 5,400 cubic feet

Volume of pyramid: 1,800 cubic feet

Volume of composite figure:

3,600 cubic feet

Step-by-step explanation:

Volume of prism:

\(30 \times 12 \times 15 = 5400\)

Volume of pyramid:

Area of base: 30 × 12 = 360 square feet

Height: 15 feet

\( \frac{1}{3} (30 \times 12 \times 15) \)

\( \frac{1}{3} \times 5400 = 1800\)

Volume of composite figure:

\(5400 - 1800 = 3600\)

3,600 cubic feet

Step-by-step explanation: To divide mixed numbers, first rewrite the mixed numbers as improper fractions.

So here, 3/5 is already a fraction and 2 and 1/2 can be written as 5/2.

Remember that dividing by a fractions means the same thing

as multiplying by the reciprocal of that fraction.

In other words, 3/5 ÷ 5/2 can be rewritten as 3/5 · 2/5.

Finally, multiplying across the numerators and the

denominators, we have 6/25.

The result of the division of 3/5 divided by 2 1/2 is: 6/25.

Here, we have,

given that,

3/5 divided by 2 1/2

To divide mixed numbers, first rewrite the mixed numbers as improper fractions.

So here, 3/5 is already a fraction and 2 and 1/2 can be written as 5/2.

Remember that dividing by a fractions means the same thing

as multiplying by the reciprocal of that fraction.

In other words, 3/5 ÷ 5/2 can be rewritten as 3/5 · 2/5.

Finally, multiplying across the numerators and the

denominators,

we have 6/25.

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None of the options (a) 272, (b) 480, (c) 289, or (d) 270 is the correct answer in the repetition.

Repetition is a figure of speech that allows a word to be used several times in the same sentence, verse, paragraph, or stanza.

To solve this problem, we need to determine the number of possibilities for the other three digits of the 4-digit number, given that the digit 4 must be included.

First, let's consider the possibilities for the thousands digit (the leftmost digit) of the 4-digit number. Since the digit 4 must be included, we are left with 6 digits (1, 2, 3, 5, 6, 7) to choose from for this position.

Next, let's consider the possibilities for the hundreds digit (the second leftmost digit) of the 4-digit number. Since we have used one digit (4) for the thousands digit, we are left with 5 digits (1, 2, 3, 5, 6, 7) to choose from for this position.

Similarly, for the tens digit (the second rightmost digit), we have 5 remaining digits to choose from.

Finally, for the units digit (the rightmost digit), we have 4 remaining digits to choose from.

Since we are multiplying the number of possibilities for each position, the total number of 4-digit numbers that can be made using the digits 1 to 7, with the digit 4 included, is:

6 * 5 * 5 * 4 = 600

Therefore, the correct option is not among the given choices. None of the options (a) 272, (b) 480, (c) 289, or (d) 270 is the correct answer.

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Answer:

Step-by-step explanation:

20.

itis not similar as ratio of corresponding sides is not equal.

4/2=2

6/4=3/2

8/6=4/3

2≠3/2≠4/3

Answer: √58 or about 7.6

Step-by-step explanation:

use the distance formula: √((x1 - x2)² + (y1 - y2)²)

√((3 - 0)² + (7 - 0)²)

√((3)² + (7)²)

√(9 + 49)

√58

hope this helps!

Answer:

about 7.6

Step-by-step explanation:

right on edge 2021

Here, we are supposed to find the value of the stock. Let's begin by determining the expected dividends: Expected dividends1st year dividend (D1)

= $1.55(1 + 26.56%)

= $1.96Second-year dividend (D2) = $1.96(1 + 26.56%) = $2.48Third-year dividend (D3)

= $2.48(1 + 26.56%)

= $3.

= D1/(1+r)^1 + D2/(1+r)^2 + D3/(1+r)^3 + D4/(1+r)^4...∞Where r

= required rate of return Let us substitute the values now PV of the future dividends

= $1.96/(1 + 14.40%)^1 + $2.48/(1 + 14.40%)^2 + $3.14/(1 + 14.40%)^3 + $3.25/(1 + 14.40%)^4...∞PV of the future dividends = $1.96/1.1440^1 + $2.48/1.1440^2 + $3.14/1.1440^3 + $3.25/1.1440^4...∞PV of the future dividends

= $1.72 + $1.92 + $2.04 + $1.86...∞PV of the future dividends

= $7.54We know that the value of the stock is the present value of the expected dividends, so we can calculate it as follows: Value of the stock

= PV of the future dividends Value of the stock

= $7.54

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We can extend our definition of the average value over a continuous function to an infinite interval by defining the average value f on the interval [0, ∞) to be      \(\lim_{t \to \infty}\frac{1}{t-a}\int\limits^t_a {f(x)\\} \, dx\)  .

The definition of the average value of a continuous function f(x) can be expanded to include the infinitely long interval [a,∞] as follows:

\(\lim_{t \to \infty}\frac{1}{t-a}\int\limits^t_a {f(x)\\} \, dx\)

Let's assume that f(x) is any continuous function. Assume that the integral \(\int\limits^i_0 {f(x)} \, dx\)   is divergent and that f(x)≥0 in the range [a,∞].

Show that, if this limit exists, \(f_{ave} = \lim_{x \to \infty} f(x)\) .

Hence, We can extend our definition of the average value over a continuous function to an infinite interval by defining the average value f on the interval [0, ∞) to be      \(\lim_{t \to \infty}\frac{1}{t-a}\int\limits^t_a {f(x)\\} \, dx\)  .

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Answer: Three

Step-by-step explanation: The equations touch each other 3 times on the graph, therefore there are three solutions

Yes, larger sample sizes do increase the certainty of a statistical test. This is because as the sample size increases, the sample becomes more representative of the population, leading to more accurate results.

larger sample sizes generally increase the certainty of the statistical test. This is because larger samples provide more information and reduce the likelihood of chance variations affecting the results. The estimated parameter becomes more stable and accurate with a larger sample size. Additionally, larger sample sizes allow for the detection of smaller effect sizes and greater statistical power. However, it is important to note that sample size alone does not guarantee the validity of the statistical test. Other factors such as sampling methods, data quality, and appropriate statistical analysis must also be considered.
Yes, larger sample sizes do increase the certainty of a statistical test. This is because as the sample size increases, the sample becomes more representative of the population, leading to more accurate results. Additionally, larger sample sizes decrease the margin of error and increase the statistical test's power, allowing for better detection of true differences or relationships in the population. Overall, larger sample sizes lead to more reliable and valid conclusions in statistical tests.

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