14. A solution is made by dissolving 6.20 g of NaCl, in 228 g of
water, producing a solution with a volume of 249 mL at 21 °C. What
is the expected osmotic pressure (in atm) at21 °C?
15. Calculate t
The expected osmotic pressure at 21 °C is approximately 2.37 atm.
To calculate the expected osmotic pressure, we can use the formula:
osmotic pressure = (n / V) * (R * T)
where n is the number of moles of solute, V is the volume of the solution, R is the ideal gas constant (0.0821 L * atm / (mol * K)), and T is the temperature in Kelvin.
First, let's calculate the number of moles of NaCl:
molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
moles of NaCl = mass / molar mass = 6.20 g / 58.44 g/mol ≈ 0.106 mol
Next, we need to convert the volume of the solution to liters:
V = 249 mL = 0.249 L
Now, we can calculate the osmotic pressure:
osmotic pressure = (0.106 mol / 0.249 L) * (0.0821 L * atm / (mol * K)) * (21 + 273) K ≈ 2.37 atm
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The complete question is:
14. A solution is made by dissolving 6.20 g of NaCl, in 228 g of water, producing a solution with a volume of 249 mL at 21 °C. What is the expected osmotic pressure (in atm) at 21 °C?
HELP HELP HELP HELP
what’s the pressure in a 490.0 mL water bottle that is at 45 °C if the pressure was 772 mm Hg at
19 °C assuming the volume doesn't change?
The final pressure in the water bottle at 45 °C will be 1044 mm Hg, assuming the volume doesn't change using combined gas law.
Thus, the combined gas law can be used to estimate the final pressure which is (P1 x V1) / T1 = (P2 x V2) / T2 where P1 is equal to 772 mm Hg, V1 is equal to 490.0 mL, and T1 is equal to 292.15 K. V2 is equal to V1 = 490.0 mL assuming the volume doesn't change, and the final temperature in Kelvin is equal to 318.15 K.
The equation of combined gas law can be rearranged to solve for P2 which is final pressure:
P2 = (P1 x V1 x T2) / (V2 x T1)
P2 = (772 mm Hg x 490.0 mL x 318.15 K) / (490.0 mL x 292.15 K)
P2 = 1044 mm Hg
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A sphere of radius 0.457 m, temperature 32.2 ∘
C, and emissivity 0.924 is located in an environment of temperature 82.9 ∘
C. At what rate does the sphere (a) emit and (b) absorb thermal radiation? (c) What is the sphere's net rate of energy exchange? (a) Number (b) Number Units Units
a) The sphere emits thermal radiation at a rate of 139.75 Watts.
b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.
c) The sphere's net rate of energy exchange is 102.09 Watts.
What are the rates of thermal radiation emission, absorption, and net energy exchange for the sphere?To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.
a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:
Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))
Plugging in the given values:
Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)
Emitting Rate ≈ 139.75 Watts
b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:
Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))
Plugging in the given values:
Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)
Absorbing Rate ≈ 37.66 Watts
c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:
Net Rate = Emitting Rate - Absorbing Rate
Net Rate = 139.75 Watts - 37.66 Watts
Net Rate ≈ 102.09 Watts
Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.
Note: The units for all the rates are Watts.
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into which category of hazardous materials do weapons of mass destruction, which utilize chlorine gas, fall?
Weapons of mass destruction that utilize chlorine gas fall under the category of chemical hazards or chemical weapons.
Weapons of mass destruction (WMD) are highly destructive devices designed to cause significant harm and casualties on a large scale. Chlorine gas, when used as a chemical weapon, falls under the category of chemical hazards.
Chemical hazards refer to substances that can cause harm or pose risks to human health and the environment due to their chemical properties.
Chlorine gas is a toxic and corrosive substance that, when released in large quantities, can have severe detrimental effects on human respiratory systems and other organs. It can cause respiratory distress, lung damage, and even death.
The use of chlorine gas as a weapon is prohibited under international agreements, such as the Chemical Weapons Convention, due to its destructive and inhumane nature.
It is important to note that weapons of mass destruction encompass various types, including chemical, biological, radiological, and nuclear weapons, each with its specific hazards and risks.
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a solution of cacl2 in water forms a mixture that is 38.5% calcium chloride by mass. if the total mass of the mixture is 263.8 g, what masses of cacl2 and water were used?
In order to prepare a mixture of 263.8g calcium chloride in water, 101.56g of calcium chloride is used and 162.37g of water is used.
We are given with a solution of Calcium chloride that is 38.5% by mass. In chemistry we always tend to see mixture of two or more substances. Here we have the mixture of calcium chloride and water. In any given solution, each of the substances has a fixed mass and proportion. So, we can define a measure called the mass percent for each component for the solution. This is the ratio of each component over the whole mass of the solution.
Mass percent of calcium chloride in solution = 38.5%
Mass percent of water in solution = 100.0 - 38.5 = 61.5%
Mass of the mixture sample = 263.8g
Mass of CaCl₂ in the solution= 0.385 x 263.8g = 101.56g
Mass of water in the solution= 0.615 x 263.8g = 162.37g
Hence, we can see that 101.56g of calcium chloride and 162.37g of water is used to prepare the mixture.
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EXERCISE 3: WHAT DOES pCO2 CHANGE? - When pCO
2
increases, the concentration of total CO
2
dissolved in water - When pCO
2
increases, the concentration of only CO
2
dissolved in water - When pCO
2
increases, the pH - Which form of dissolved CO
2
is most common in water? Ocean acidification is the decrease in pH due to increasing atmospheric CO
2
concentration.
2
. Choose the correct word option in the statements below: - An organism that needs CO
2
is likely to fare better / worse under ocean acidification. - An organism that needs HCO
3
- is likely to fare better/worse under ocean acidification. - An organism that needs CO
3
2−
is likely to fare better/worse under ocean acidification.
pCO2 is an important factor that affects various aspects of water chemistry and the impacts of ocean acidification. When pCO2 increases, the concentration of total CO2 dissolved in water also increases. This leads to changes in pH, which decreases due to increasing atmospheric CO2 concentration.
When pCO2 rises, the concentration of only CO2 dissolved in water increases. The dissolved CO2 forms carbonic acid, which contributes to the acidification of the ocean. This increase in CO2 affects the equilibrium between CO2, HCO3-, and CO3^2-, shifting it towards higher levels of dissolved CO2 and H+ ions, resulting in a lower pH.
In terms of the impacts of ocean acidification on different organisms, the effects can vary depending on their specific needs. An organism that requires CO2 is likely to fare better under ocean acidification since the increase in dissolved CO2 can provide them with a favorable environment. However, organisms that rely on HCO3- or CO3^2- may fare worse under ocean acidification, as the lower pH interferes with the availability of these carbonate ions, which are essential for shell formation and calcification in some marine organisms.
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Iodine- 131 Is a radioactive isotope, and is often used in certain medical treatments. It has a short half life of about 8 days. It a hospital has a 1050 mg sample of it’s available, how much would be absolute after 72 days
After 72 days, a 1050 mg sample of Iodine-131 would have decayed to approximately 46.87 mg.
What is a half-life and how does it relate to the decay of radioactive isotopes?A half-life is the time it takes for half of a sample of a radioactive isotope to decay. It is a characteristic property of each isotope and can be used to predict how long it will take for a given sample to decay to a certain amount. The amount of an isotope remaining after a certain amount of time can be calculated using the half-life and the formula N = N0 * (1/2)^(t/T).
Why is Iodine-131 used in medical treatments and how does its short half-life factor into its use?Iodine-131 is used in medical treatments because it emits beta particles that can destroy cancerous cells. Its short half-life is an advantage because it allows for a higher dose of radiation to be delivered to the tumor while minimizing the amount of radiation exposure to healthy tissues. After a few weeks, the Iodine-131 decays to a negligible amount and the patient is no longer radioactive.
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the fluid component of connective tissue is called ________.
The fluid component of connective tissue is called the extracellular matrix. The extracellular matrix (ECM) is a complex mixture of substances that fills the space between cells in connective tissue.
The extracellular matrix (ECM) is composed of a fluid component and various types of proteins, fibers, and other molecules. It is often referred to as tissue fluid or interstitial fluid. It is a clear, colorless fluid that fills the spaces within the connective tissue and provides a medium for the exchange of nutrients, gases, and waste products between cells and blood vessels.
The fluid in the ECM contains water, ions, small molecules, and dissolved substances such as hormones, enzymes, and nutrients. It also plays a role in maintaining the hydration and structural integrity of the tissue.
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1. (4pts.) (a) In the box provided, write a valid Lewis structure for the molecular formula shown. (b) In the box provided, write the best Lewis structure for the anion molecular formula shown.
(a) C₂H₂O
(b) [CH₂N]
2. (3 pts.) Assuming all second row atom have an octet, complete the following Lewis structure by providing lone pair electrons and formal charges where needed.
3. (2 pts.) In the box provided, draw a condensed formula for the bond-line (skeletal) drawing below.
OH
H-N
1a) The Lewis structure for C2H2O is as follows.
The molecular formula for acetic acid is C2H4O2. The C atom is the central atom, and it is connected to an O atom by a double bond. Two H atoms are connected to the C atom.
(b) The best Lewis structure for the anion molecular formula shown is:
In the structure, the formal charge of the C atom is 0, and the formal charge of the N atom is -1. There are also seven electrons in the structure.
2)The complete Lewis structure of the given compound is as shown below:
One can count the number of valence electrons in the molecule by adding the number of valence electrons in each atom. Two electrons from each bond are removed since the electrons are shared between the two atoms forming the bond. Subtracting these electrons gives the number of valence electrons for the molecule. The Lewis structure is drawn by representing the valence electrons of the atoms by dots and lines. All atoms are connected by single bonds, and all atoms have an octet except the nitrogen atom.
3)The condensed formula for the given bond-line (skeletal) drawing is NH2OH.
This compound is called hydroxylamine. There is a nitrogen atom at the center, which is attached to two H atoms and an OH group. The condensed formula for the compound is NH2OH.
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beers law lab if your unknown copper sulfate solution was produced by diluting 20 ml of a more concentrated copper sulfate solution to a final volume of 100 ml, what was the original concentration of the concentrated solution?
100.0 mL of a solution containing copper was mixed in it. At 620 nm, this solution's absorbance was 0.477.
What does the focused meaning mean?Contained, present, or taking place in a constrained region or area: not dispersed. a light beam that is extremely focused. 3. fervent, fervent a task requiring numerous hours of focused work.
What does liquid concentrated mean?A liquid that has had its water removed has been strengthened by concentration. Use concentrated apple or apricot juice, honey, or both moderately to sweeten food. Condensed, rich, undiluted, and reduced are synonyms for Additional words for concentration.
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How does adaption allow mice with the mutation to survive better in some areas
Answer: Mutations can cause instant adaptations, while natural selection is the process by which adaptations occurs over a series of generations. Adaptations are changes or processes of changes by which an organism or species becomes better suited for its environment. A mutation is an alteration of the DNA sequence.
what is the molecular density of a gas of molecule diameter 3.71e-10 m and mean free path of 8.06e-8 m? type your answer here molecules/l
The molecular density of a gas can be calculated using the formula:
n = P/[(1.3807 × 10^-23) × T]
where n is the molecular density in molecules/m^3, P is the pressure in Pascals, T is the temperature in Kelvin, and 1.3807 × 10^-23 is the Boltzmann constant.
However, in this case, we are given the mean free path (λ) and the diameter (d) of the gas molecules. We can use these values to calculate the molecular density using the formula:
n = (1/4) × (1/πd^2) × (1/λ)
where π is the mathematical constant pi.
Substituting the given values, we get:
n = (1/4) × (1/π(3.71 × 10^-10)^2) × (1/8.06 × 10^-8)
n = 2.74 × 10^19 molecules/m^3
Therefore, the molecular density of the gas is 2.74 × 10^19 molecules/m^3.
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Can someone help me
Answer:the second largest one
Explanation:
both weels are pushing at it
Urgent help please!!
Answer:
1. 2.1 moles of Mg
2. 0.72 mole of Mg(OH)2
Explanation:
1. We'll begin by writing the balanced equation for the reaction. This is given below:
3Mg + 2AlBr3 —> 3MgBr2 + 2Al
From the balanced equation above, 3 moles of Mg reacted to produce 2 moles of Al.
Therefore, Xmol of Mg will react to produce 1.4 moles of Al i.e
Xmol of Mg = (3 x 1.4)/2
Xmol of Mg = 2.1 moles.
Therefore, 2.1 moles of Mg is required to 1.4 moles of Al.
2. We'll begin by calculating the number of mole in 26g of water, H2O.
This is illustrated below:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H2O = 26g
Number of mole of H2O =?
Mole = Mass /Molar Mass
Number of mole of H2O = 26/18
Number of mole of H2O = 1.44 moles
Next, we shall write the balanced equation for the reaction. This is given below:
2HNO3 + Mg(OH)2 —> Mg(NO3)2 + 2H2O
Finally, we can obtain the number of mole of Mg(OH)2 used in the reaction as follow:
From the balanced equation above,
1 mole of Mg(OH)2 reacted to produce 2 mole of H2O.
Therefore, Xmol of Mg(OH)2 will react to produce 1.44 moles of H2O i.e
Xmol of Mg(OH)2 = (1 x 1.44)/2
Xmol of Mg(OH)2 = 0.72 mole.
Therefore, 0.72 mole of Mg(OH)2 was used in the reaction.
What will happen if Zn metal is added to PbCl2 solution
When zinc (Zn) metal is added to a solution of lead chloride (PbCl2), a chemical reaction takes place. The reaction can be represented by the following equation: Zn(s) + PbCl2(aq) → ZnCl2(aq) + Pb(s)
In this reaction, zinc displaces lead from the lead chloride solution, resulting in the formation of zinc chloride (ZnCl2) in the aqueous phase and lead (Pb) as a solid precipitate.
The reaction occurs because zinc is more reactive than lead. It has a higher tendency to lose electrons and undergo oxidation compared to lead. As a result, zinc displaces lead in the compound, forming zinc chloride. The lead ions combine and form solid lead, which appears as a precipitate.
Overall, the addition of zinc metal to a lead chloride solution leads to the displacement of lead by zinc, resulting in the formation of zinc chloride in the solution and lead as a solid precipitate.
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How many grams of carbon are required to produce 0.460 moles of SiC?
SiO2 + C → SiC + CO
Answer:
Sick Core corona +iep =Qurintine
what are intermolecular forces
What is the atomic mass of potassium?
Answer:
39.0983 u.
Explanation:
A buffer resists change in ph when ___________ amount of acid or base is added to it.
A buffered solution will resist changes in pH when small amounts of acid or base are added.
How does a buffer withstand pH changes?Buffers are solutions that resist pH changes when small amounts of acid or base are added. They are able to do so because they contain an acidic component, HA, which neutralises OH- ions, and a basic component, A-, which neutralises H+ ions. Because Ka is a constant, the [H+] will be directly proportional to the [HA]/[A-] ratio. Buffer, as defined, is a conjugate acid-base pair that can withstand pH changes when small amounts of strong acids or bases are added. When a strong base is added, the buffer's acid neutralises the hydroxide ions (OH -start superscript, start text, negative, end text, end superscript).The strong acid reacts with the weak base in the buffer to form a weak acid, which produces few H ions in solution and therefore only a little change in pH.To learn more about A buffer resists change in ph refer to
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A 0.85% saline solution is: a.8.5 mL of saline added to 91.5 mL of water b.85 g of NaCl made up to 1,000 mL of water c.0.85 g NaCl made up to 100 mL of water d.8.5 g NaCl in 100 mL of water
Answer:
c
Explanation:
A 0.85% saline solution would consist of 0.85 g NaCl made up to 100 mL of water.
A 0.85% saline solution contains 0.85% by weight of NaCl. Hence, in order to prepare such a solution, 0.85 g of NaCl is weighed out into a beaker or cylinder and distilled water is added up to the 100 mL mark. On the other hand, 8.5 g of the NaCl can be weighed out and then distilled water added to 1000 mL mark.
The correct option is, therefore, c.
A solution is prepared by dissolving 150. grams of NaCl in 500 milliliters of water. What is the
molarity of the solution?
Answer:
Explanation:
The answer should be .00500M
The molarity of the solution is = 5.12M
Molarity of the solutionThe molarity of a solution is the measures the number of moles of a solute per liter of a solution.
Molarity = moles solute/Liter solution
Molar mass of sodium (Na) = 23g
Molar mass of chlorine (Cl) = 35.5g
Molar mass of NaCl = 23 + 35.5 = 58.5g/mol
To calculate the quantity of moles in 150g of NaCl,
1mol = 58.5g
xmol = 150g
Cross multiply,
xmol= 150×1/58.5
= 2.56mol
To convert 500mL to Liters,
500/1000 = 0.5 Liters
Substituting into the equation, Molarity = moles solute/Liter solution
Molarity= 2.56/ 0.5 = 5.12M
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The noble gas with an atomic mass less than gold, but more than silver?
The noble gas with an atomic mass less than gold, but more than silver, is platinum. Noble gases are found in small amount in earth atmosphere.
What is noble gas ?The noble gases are a group of chemical elements that share several characteristics. They are all monatomic, odorless, and colorless gases with relatively little chemical reactivity under normal conditions. Helium, neon, argon, krypton, xenon, and radioactive radon are the six types of noble gases that are found in nature.
These gases don't receive, lose, or share electrons, making them inert or unreactive. They are also referred to as noble gases due to their rarity in the atmosphere of the earth.
Thus, The noble gas with an atomic mass less than gold, but more than silver, is platinum.
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Explain why alkali metals do not form divalent ions.
he Lewis structure for CO molecule contains Group of answer choices one double bond, one single bond, and twelve nonbonding electrons two double bonds and eight nonbonding electrons one triple bond and four nonbonding electrons two single bonds and twelve nonbonding electrons
Answer:
One triple bond and four non bonding electrons
Explanation:
In considering the lewis structure of carbon monoxide, we must remember that the molecule contains a total of ten valence electrons. Four are the valence electrons that are present on the valence shell of carbon while six are the valence electrons on oxygen. Some of these valence electrons participate in bonding in the CO molecule.
Out of the six valence electrons on oxygen, two valence electrons participate in bonding with carbon while the other four electrons remain localized on the oxygen atom as two lone pairs of electrons.
Hence there are four nonbonding electrons in the lewis structure of CO as well as one triple bond.
Neurons mostly receive signals that are _____; others, however, are _____. inhibitory; excitatory polarizing; depolarizing excitatory; refractory excitatory; inhibitory
Neurons mostly receive signals that are excitatory ; others, however, are inhibitory.
A neuron will generate action potentials more often when it receives more excitatory than inhibitory inputs.A neuron receives both excitatory and inhibitory inputs from the many other neurons it is connected to at synaptic junctions.
For an action potential to be generated in a neuron, the sum of the excitatory inputs must be greater than that of the inhibitory inputs.
Neurotransmitters are the chemical messengers in the body, which are released by the axon terminal of neuron ( also called nerve cell) and transmit nerve impulse to the neighboring cell ( which could be a muscle cell or a nerve cell) .
There are primarily two types of neurotransmitters that are-
1) Excitatory neurotransmitter and 2) Inhibitory neurotransmitter.
Inhibitory neurotransmitter have inhibitory effects on the neuron that is they reduce the chances that a neuron will fire an action potential. In other words, they are responsible for slowing signals between neurons.
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The chemical equation shows iron(III) phosphate reacting with sodium sulfate.
2FePO4 + 3Na2SO4 Right arrow. Fe2(SO4)3 + 2Na3PO4
What is the theoretical yield of Fe2(SO4)3 if 20.00 g of FePO4 reacts with an excess of Na2SO4?
26.52 g
53.04 g
150.8 g
399.9 g
The theoretical yield of Fe2(SO4)3 if 20.00 g of FePO4 reacts with an excess of Na2SO4 is 26.52g.
What is chemical equation?A chemical equation is an expression that represent the chemical reaction between two or more substances. It consists of the chemical formulas of the reactants in and the products along with the physics state of the reactants and the products solid liquid gas etc. And the symbol that denoted the type of reaction that is talking please I'll eat you double arrow of the film visible reaction the number of the atoms of each element in the reactants and products must be the same on the both side of the equation.
1) Chemical equation:
2FePO4 + 3Na2SO4 → Fe2(SO4)3 + 2Na3PO4
2) Theoretical molarity ratios:
2 mol FePO4 : 3 mol Na2SO4 : 1 mol Fe2(SO4)3 : 2 mol Na3PO4
3) Convert 20.00 g of FePO4 into number of moles
number of moles = mass in grams / molar mass
molar mass of FePO4 = 150.82 g/mol
numer of moles = 20.00 g / 150.82 g/mol = 0.1326 mol FePO4
4) Proportionality
1 mol Fe2(SO4)3 x
----------------------- = ------------------------
2 mol FePO4 0.1326 mol FePO4
Solve for x:
x = (0.1326 / 2) * 1 mol Fe2(SO4)3 = 0.0663 mol Fe2(SO4)3
5) Convert 0.0663 mol Fe2(SO4)3 into grams
mass in grams = number of moles * molar mass
molar mass Fe2(SO4)3 = 399.88 g/mol
mass = 0.0663 mol * 399.88 g/mol = 26.51 g
Depending on the numbers of the decimal to digits used by one or otherwise you might obtained 26.52 instead 26.51, that's differences does not count.
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The following data were obtained for the reaction between iodide ion and dibromothane (C_2H_4Br_2) in methanol. Use the initial rate method and the data above to determine the rate law and rate constant for this reaction. Use your answer in (a) to determine the rate of consumption of l when [C_2H_4Br_2]_0=0.74 M and [i]_0=0.52 M? Use the Arrhenius Equation and the data above to determine the activation energy for this reaction.
The rate law for the reaction between iodide ion and dibromothane (C₂H₄Br₂) in methanol is determined to be Rate = k[C₂H₄Br₂][I], indicating that the reaction is first-order with respect to both reactants.
The rate constant (k) for the reaction is calculated to be approximately 4.88 M⁻¹s⁻¹ using the initial rate data from Experiment 1.
The rate of consumption of iodide ion (I) is estimated to be around 1.79 M/s when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M.
The activation energy (Ea) for the reaction is found to be approximately 51.3 kJ/mol using the Arrhenius equation and temperature data from Experiment 4.
To determine the rate law, we need to examine how the initial rates change with respect to the initial concentrations of the reactants. Let's consider the first experiment (Experiment 1) and compare it with the other experiments:
Experiment 1: [C₂H₄Br₂]₀ = 0.127 M, [I]₀ = 0.102 M, Initial rate = 6.45x10⁻² M/s
Experiment 2: [C₂H₄Br₂]₀ = 0.254 M (2 * [C₂H₄Br₂]₀), [I]₀ = 0.127 M (2 * [I]₀), Initial rate = 0.102 M/s (2 * Initial rate)
Experiment 3: [C₂H₄Br₂]₀ = 0.204 M (1.6 * [C₂H₄Br₂]₀), [I]₀ = 1.29x10⁻² M (0.126 * [I]₀), Initial rate = 0.204 M/s (3.16 * Initial rate)
From the comparisons above, we can see that doubling the initial concentrations of both reactants (Experiment 2) doubles the initial rate, indicating that the reaction rate is first-order with respect to both [C₂H₄Br₂] and [I].
The rate law for the reaction can be expressed as:
Rate = k[C₂H₄Br₂]ᵃ [I]ᵇ
Since the reaction is first-order with respect to both reactants, we have a = 1 and b = 1.
Therefore, the rate law for the reaction is:
Rate = k[C₂H₄Br₂][I]
To determine the rate constant (k), we can choose any of the experiments and use the given data. Let's use Experiment 1:
[C₂H₄Br₂]₀ = 0.127 M
[I]₀ = 0.102 M
Initial rate = 6.45x10⁻² M/s
Plugging these values into the rate law equation, we can solve for k:
6.45x10⁻² = k(0.127)(0.102)
k = 6.45x10⁻² / (0.127)(0.102)
k ≈ 4.88 M⁻¹s⁻¹
So, the rate constant for the reaction is approximately 4.88 M^(-1)s^(-1).
Now, to determine the rate of consumption of iodide ion (I) when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M, we can use the rate law:
Rate = k[C₂H₄Br₂][I]
Plugging in the given concentrations and the rate constant we just determined:
Rate = (4.88 M^(-1)s⁻¹)(0.74 M)(0.52 M)
Rate ≈ 1.79 M/s
Therefore, the rate of consumption of iodide ion when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M is approximately 1.79 M/s.
The Arrhenius equation is given as:
k = Ae^(-Ea/RT)
where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin.
From the given data, we have:
Experiment 1: T = 20°C = 293 K
Experiment 2: T = 20°C = 293 K
Experiment 3: T = 20°C = 293 K
Experiment 4: T = 40°C = 313 K
Let's consider Experiment 1:
[C₂H₄Br₂]₀ = 0.127 M
[I]₀ = 0.102 M
Initial rate = 6.45x10⁻² M/s
We can rearrange the rate law equation to solve for the pre-exponential factor (A):
A = k / ([C₂H₄Br₂]₀[I]₀)
Plugging in the values for Experiment 1:
A = (4.88 M⁻¹s⁻¹) / (0.127 M * 0.102 M)
A ≈ 37.80 s⁻¹
Now, we can use the Arrhenius equation with Experiment 4 to determine the activation energy (Ea):
k = Ae^(-Ea/RT)
Rearranging the equation:
ln(k) = ln(A) - (Ea/RT)
Taking the natural logarithm of the rate constant from Experiment 4:
ln(k) = ln(1.79 M/s)
Substituting the values into the equation:
ln(1.79 M/s) = ln(37.80 s^(-1)) - (Ea / (8.314 J/(mol·K) * 313 K))
Simplifying the equation:
ln(1.79) = ln(37.80) - (Ea / (8.314 * 313))
Now, solve for Ea:
Ea = -(ln(1.79) - ln(37.80)) * (8.314 * 313)
Ea ≈ 51,253 J/mol or 51.3 kJ/mol
Therefore, the activation energy for this reaction is approximately 51.3 kJ/mol.
Learn more about activation energy from the link given below.
https://brainly.com/question/28384644
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When is chemical energy released
Explanation:
Chemical energy is energy stored in the bonds of chemical compounds, like atoms and molecules. This energy is released when a chemical reaction takes place. Usually, once chemical energy has been released from a substance, that substance is transformed into a completely new substance.
Answer:
Breaking or making of chemical bonds involves energy, which may be either absorbed or evolved from a chemical system. Energy that can be released or absorbed because of a reaction between a set of chemical substances is equal to the difference between the energy content of the products and the reactants, if the initial and final temperatures are the same.
Explanation:
What is the [OH-] if the pH is 7
Answer:
neutral [H3O+] = [OH−] pH = 7 7.2: pH and pOH
Explanation:
At pH 7, the substance or solution is at neutral and means that the concentration of H+ and OH- ion is the same.
Use the following equation to answer the question below. How many moles of iron are made from 8.25 moles of Fe2O3?(see pic for equation)