Answer:
You should tell them that your just not interested in it anymore and that you would like to do something else besides playing guitar you should probably explain to them why you dont want to play anymore. I hoped this helped- Best of luck.
Explanation:
Answer:
You should tell them that your just not interested in it anymore and that you would like to do something else besides playing guitar you should probably explain to them why you dont want to play anymore. I hoped this helped- Best of luck.
Explanation:
Each year at a college, there is a tradition of having a hoop rolling competition. Alex rolls his 0.250 kg hoop down the course. If the hoop has a radius of 50.0 cm, what is the moment of inertia of Alex's rolling hoop?
The moment of inertia of Alex's rolling hoop of mass 0.25 kg and radius of 50 cm is 0.0625 kgm².
What is moment of inertia?Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.
To calculate the moment of inertia of Alex's rolling hoop, we use the formula below.
Formula:
I = mr².............. Equation 1Where:
I = Moment of inertia of Alex's rolling hoopm = Mass of Alex's rolling hoopr = Radius of Alex's rolling hoopFrom the question,
Given:
m = 0.25 kgr = 50 cm = 0.5 mSubstitute these values into equation 1
I = 0.25×0.5²I = 0.0625 kgm²Hence, the moment of inertia of Alex's hoop is 0.0625 kgm².
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What distance in meter can a runner cover in 60 minutes if he/she has an average speed of 2 m/s
Answer:
d = 7200 m
Explanation:
Given that,
Average speed of a runner, v = 2 m/s
Time taken by the runner, t = 60 min = 3600 s
We need to find the distance covered by the runner.
Speed = distance divided by time taken.
v = d/t
Putting all the values,
\(d=v\times t\\\\d=2\times 3600\\\\d=7200\ m\)
So, the distance covered by the runner is 7200 m.
A large air-filled 0.221-kg plastic ball is thrown up into the air with an initial speed of 11.9 m/s. At a height of 2.77 m, the ball's speed is 2.85 m/s. What fraction of its original energy has been lost to air friction?
Answer:
Initial energy = (M/2)*Vo^2 = 12.80 J
Total energy at 4.7 m and V = 5 m/s:
= (M/2)*5^2 + M*g*4.7 = 1.25 + 4.61 J
Fraction of ball's energy LOST = (12.80-5.86)/12.80
= 0.542
Explanation:
I know it's not the real answer, but this will help you find the real one
Hope this helps!!!
Identical metal spheres are initially charged as shown. Spheres P and Q are touched together and then separated. Then spheres Q and R are touched together and separated. Afterward, the charge on sphere R is A)-1 nC or less . B)-0.5 nC C) 0 nC D) +0.5 nC E) +1 nC or more +4 nC-2
The potential of the two aluminum spheres will be equal when they come into contact. identical radius, therefore equal potential results in charges. Hence, sphere C will have a final charge of q c = +1.125q.
Why does a sphere not have a charge?All charges in a circular conductor are at suitable intervals from one another because the energy in a sphere conductor will travel about until it is evenly distributed across its surface. As a result, there's an equal and opposite charge for every charge. Electric fields produced by these charges cancel each other out.
In a spherical, how is the charge distributed?This is just Qr40r if the charge is evenly dispersed throughout the sphere. The charge contained inside radius r in this instance is Qr, and if the charge is Q(r3/a3) is uniformly distributed around the sphere. Hence, Qr240a3 represents that portion of the potential.
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3. As the mass of an object increases, the force of gravity
Answer:
As the mass of an object increases, the force of gravity increases as well.
Explanation:
Objects with more mass have more gravity. They work together.
Please help with all three questions
Answer:
The correct answer is D C A
Forensic Entomology
Forensic Entomology
The study of the life cycle of insects that feed on the flesh to the dead, to establish time of death and occasionally identify chemicals present in a person's body at the time of death.
Time since death
Arrive a few hours after a death and are active through decomposition process. They feed on larvae and other insects rather than the corpse itself.
Larvae that feed on human excrement and remains, and are found late in the decomposition process.
Forensic Entomology is the study of life cycles of insects that feed on the flesh of dead, to establish time of death and occasionally identify chemicals present in a person's body at time of death
What is meant by Forensic Entomology?The scientific study of the colonization of dead body by arthropods is called forensic entomology .
Larvae and adults feed on dry skin and hairs of corpse and arrive later in decomposition process : Carpet Beetles
Time since death : postmortem Interval.
Rove Beetles : Arrive a few hours after death and are active throughout decomposition process. They feed on larvae and other insects rather than the corpse itself.
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Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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In the above example, the 9.012 represents the
The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.
They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.
To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.
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star cluster a has o and b main sequence stars, while cluster b only has g spectral type and cooler main sequence stars. which cluster is younger?
If star Cluster A has O and B main sequence stars, while Cluster B only has G spectral type and cooler main sequence stars, then the younger cluster is Cluster A.
What is an astronomic star cluster?An astronomic star cluster is a group of stars that may be recognized to have a common origin, which is also associated with the age of the stars, and they are gravitationally linked in the universe space due to physical forces that maintain connected them.
The age of a given astronomic star cluster may be measured by determining the spectral type and the temperature (spectral light) of the main sequence.
Therefore, with this data, we can see that an astronomic star cluster is composed of different stars that have a common origin and whose age can be determined by the emission spectra which are indicative of the temperature.
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A fire hose held near the ground shoots water at a speed of 6.8 m/s. At what angle(s) should the nozzle point in order that the water land 2.5 m away
So, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.
IntroductionHi ! This question can be solved using the principle of parabolic motion. Remember ! When the object is moving parabolic, the object has two points, namely the highest point (where the resultant velocity is 0 m/s in a very short time) and the farthest point (has the resultant velocity equal to the initial velocity). At the farthest distance, the object will move with the following equation :
\( \boxed{\sf{\bold{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}}}} \)
With the following condition :
\( \sf{x_{max}} \) = the farthest distance of the parabolic movement (m)\( \sf{v_0} \) = initial speed (m/s)\( \sf{\theta} \) = elevation angle (°)g = acceleration due to gravity (m/s²)Problem Solving :We know that :
\( \sf{x_{max}} \) = the farthest distance of the parabolic movement = 2.5 m\( \sf{v_0} \) = initial speed = 6.8 m/sg = acceleration due to gravity = 9.8 m/s²What was asked :\( \sf{\theta} \) = elevation angle = ... °Step by Step :
Find the equation value \( \sf{\bold{theta}} \) (elevation angle)\( \sf{x_{max} = \frac{(v_0)^2 \cdot \sin(2 \theta)}{g}} \)
\( \sf{x_{max} \cdot g = (v_0)^2 \cdot \sin(2 \theta)} \)
\( \sf{\frac{x_{max} \cdot g}{(v_0)^2} = \sin(2 \theta)} \)
\( \sf{\frac{2.5 \cdot 9.8}{(6.8)^2} = \sin(2 \theta)} \)
\( \sf{\frac{2.5 \cdot 9.8}{(6.8)^2} = \sin(2 \theta)} \)
\( \sf{\frac{24.5}{46.24} = \sin(2 \theta)} \)
\( \sf{\sin(2 \theta) \approx 0.53} \)
\( \sf{\cancel{\sin}(2 \theta) \approx \cancel{\sin}(32^o)} \)
Find the angle value of the equation by using trigonometric equations. Provided that the parabolic motion has an angle of elevation 0° ≤ x ≤ 90°.First Probability
\( \sf{2 \theta = 32^o + k \cdot 360^o} \)
\( \sf{\theta = 16^o + k \cdot 180^o} \)
→ \( \sf{k = 0 \rightarrow 16^o + 0 = 16^o} \) (T)
→ \( \sf{k = 1 \rightarrow 16^o + 180^o = 196^o} \) (F)
Second Probability
\( \sf{2 \theta = (180^o - 32^o) + k \cdot 360^o} \)
\( \sf{2 \theta = 148^o + k \cdot 360^o} \)
\( \sf{\theta = 74^o + k \cdot 180^o} \)
→ \( \sf{k = 0 \rightarrow 74^o + 0 = 74^o} \) (T)
→ \( \sf{k = 1 \rightarrow 74^o + 180^o = 254^o} \) (F)
\( \boxed{\sf{\therefore \theta \{16^o , 74^o\} }}\)
ConclusionSo, based on the angle values that have been found, the angle of elevation of the nozzle can be 16° or 74°.
Which statement about spending the day of January 15th in the cities of
Chicago and Sydney is true?
A Both cities will be experiencing winter.
B Both cities will be experiencing summer.
C Chicago will be experiencing winter, while Sydney is experiencing summer.
D Chicago will be experiencing summer, while Sydney is experiencing winter.
Answer:
C
Explanation:
Winter in North
Summer in south
Which quantities define momentum?
A) how much weight an object has, plus magnitude of its acceleration.
B)how much force is pushing an object, plus it’s speed.
C)how fast can an object travel, plus its weight.
D)how much matter does an object has, plus the magnitude and direction of it’s motion
Answer:D
Explanation: a p e x
Electromagnetic radiation of a specific wavelength or energy is called
A. a photon
B. a speed
C. a threshold
D an optimal length
Electromagnetic radiation of a specific wavelength or energy is called a photon.
Electromagnetic radiation of a specific wavelength or energy is called a photon. A photon is a fundamental particle of light and is the smallest unit of electromagnetic radiation. It has no mass, but carries energy and momentum. Photons travel through space at the speed of light and can exhibit both wave-like and particle-like behaviors.The energy of a photon is directly proportional to its frequency or inversely proportional to its wavelength. This relationship is known as the Planck-Einstein equation and can be expressed as E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the radiation.When a photon interacts with matter, it can be absorbed, reflected, or scattered. The energy of the photon is transferred to the absorbing material, causing an excitation or ionization of the atoms or molecules. This process is the basis for many scientific techniques, such as spectroscopy, where the absorption or emission of photons by a material is used to identify its chemical composition and structure. Understanding the properties of photons and their interactions with matter is essential for many fields of science, including optics, physics, and chemistry.
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Who has the best dog ever!?!?
Answer:
10x10=100
snoopy ofc :)
Answer:
Labrador Retriever.
hope it will help you
Which of the following is not an example of approximate simple harmonic motion
Answer:
where are the options
it's not full question
Two very large parallel metal plates, separated by 0.20 m, have a potential difference of 12V. An electron is released from rest at a location a distance d from the negative plate.
(a) Describe the motion of the electron after its release in as much detail as possible.
(b) At what distance from the positive plate, will the electron have a speed of 1 x 10^6 m/s?
Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.
(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.
(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?
For part (a):
The magnitude of an electric field can be given as \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.
So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)
An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.
For part (b):
We know that...
- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).
- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).
- \(\vec F_e=q\vec E\)
- \(\vec F =m\vec a\)
\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)
\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)
Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)
\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)
\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)
The distance from the positive plate we'll call, "D."
\(D=0.20+\Delta \vec x\)
\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)
Alzheimer's is a bone disease in which the bones become less dense.
Please select the best answer from the choices provided
ΟΤ (True)
OF (False)
Answer:
OF (False)
Explanation:
Alzheimer's is a disease of the brain that causes progressive memory loss. The bone disease in which bones become less dense is known as osteoporosis.
Particles q1, q2, and q3 are in a straight line. Particle q₁ is -28.1 μC, particle q2 is +25.5 μC, and
particle q3 is -47.9 μC. Particles q₁ and q2 are separated by 0.300 m. Particles q2 and q3 are separated by 0.300 m. What is the net force on q₂?
Remember: Negative forces (-F) will point Left Positive forces (+F) will point Right
According to the given statement The net force on q2 will thus be 17.51 N.
What is an example net force?A soccer ball moves off and travels into the air when we kick it. The ball is then being affected by a net force. A net force is also exerted on the ball when it begins to fall back to the earth and ultimately stops.
Briefing:The force ,by the charge q₁ on the q₃;
\($\mathrm{F}_{31}=\frac{\mathrm{Kq}_1 \mathrm{q}_3}{\mathrm{r}^2}$\)
\($\mathrm{F}_{31}=\frac{9 \times 10^9 \times-28.1 \times 10^{-6} \times \times-47.9 \times 10^{-6}}{(0.600)^2}$\)
F₃₁ = 33.64 N
The force, by the charge q₂ on the q₃;
\($\mathrm{F}_{32}=\frac{\mathrm{Kq}_2 \mathrm{q}_3}\)
\($\mathrm{F}_{32}=\frac{9 \times 10^9 \times 25.5 \times 10^{-6} \times \times-74.9 \times 10^{-6}}{(0.300)^2}$\)
F₃₂ = -19.09 N
The total of the two forces is the net force;
\($\mathrm{F}_{\text {net }}=\mathrm{F}_{32}+\mathrm{F}_{31}$\)
\($\mathrm{F}_{\text {net }}=36.6-19.9$\)
Fnet = 17.51 N
The net force on q2 will thus be 17.51 N.
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1. Which distance is the greatest?
O 7000 meters
O 99.99 meters
O 4.5 x 10³ meters
O 9.0 x 10² meters
Answer:
7000 meters
Explanation:
obviously 99.99 is less than 7000
10 cubed is 10 × 10 × 10, 1000, × 4.5 is 4500, which is less than 7000
10 squared is 100, which × 9 is only 900, which is also less than 7000
have a good day
A non-uniform bar of weight W = 30.0 N is suspended at rest in a horizontal position by two massless cords. The angle phi between cord 2 and the vertical is equal to 40.0o. The bar has a length L = 3.0 m and the distance of its center of gravity from the left-hand end of the bar is 2.2 m.
Answer:
12.75N
Explanation:
Let's consider the forces acting on the bar:
Weight of the bar (W = 30.0 N): It acts vertically downward, passing through the center of gravity of the bar.
Tension in cord 1 (T1): It acts horizontally and to the left, making an angle of 90° with the bar. Since cord 1 is massless, it does not contribute to the torque.
Tension in cord 2 (T2): It acts at an angle φ = 40.0° with the vertical.
To find the tension in cord 1 and cord 2, we need to set up torque equilibrium equations. The torque of the weight about the point of suspension must be balanced by the torques of the tensions in cords 1 and 2.
Taking the left end of the bar as the reference point (pivot), the torque equilibrium equation can be written as:
Torque due to weight = Torque due to T1 + Torque due to T2
The torque due to the weight is calculated as follows:
Torque due to weight = Weight of the bar * Perpendicular distance between the weight and the pivot point
The torque due to T1 is zero since it acts along the line of action passing through the pivot point.
The torque due to T2 can be calculated as follows:
Torque due to T2 = T2 * Perpendicular distance between the cord and the pivot point
Using the given values:
Weight of the bar (W) = 30.0 N
Length of the bar (L) = 3.0 m
Distance of the center of gravity from the left-hand end of the bar (d) = 2.2 m
Angle between cord 2 and the vertical (φ) = 40.0°
We can calculate the perpendicular distance between the weight and the pivot point as:
Perpendicular distance = L/2 - d
Using these values, we can solve for T2:
30.0 N * (L/2 - d) = T2 * L * sin(φ)
Let's substitute the given values and solve for T2:
30.0 N * (3.0/2 - 2.2) = T2 * 3.0 * sin(40.0°)
T2 ≈ 12.75 N
Therefore, the tension in cord 2 (T2) is approximately 12.75 N.
A 24.4kg dog is running northward at 2.14m/s, while a 5.53kg cat is running eastward at 3.56m/s. Their 78.5kg owner has the same momentum as the two pets taken together. Find the direction of the owner's velocity. Find the magnitude of the owner's velocity.
The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.
To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.
Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).
According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.
The total momentum before the interaction is given by:
Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)
Mass of the dog (m1) = 24.4 kg
Velocity of the dog (v1) = 2.14 m/s
Mass of the cat (m2) = 5.53 kg
Velocity of the cat (v2) = 3.56 m/s
Mass of the owner (m3) = 78.5 kg
Velocity of the owner (v) = unknown
Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)
The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.
Total momentum after = 0
Equating the two expressions:
(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0
Simplifying the equation:
(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0
71.8648 kg·m/s + (78.5 kg * v) = 0
Solving for v:
78.5 kg * v = -71.8648 kg·m/s
v = -71.8648 kg·m/s / 78.5 kg
v ≈ -0.916 m/s
Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.
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A 2000 kg car moves at a speed of 30 m/s. To reach this speed, it was necessary to burn 0.1 l of gas. Burning gas provides 30 MJ/l of source energy. Determine the energy efficiency (in %) of this car.
The energy efficiency of the car is approximately 16.7%.
The energy efficiency of a car is the ratio of the useful work output (in this case, the kinetic energy of the car) to the total energy input (in this case, the energy released by burning the gasoline). The equation for energy efficiency is:
Efficiency = Useful work output / Total energy inputThe useful work output can be calculated as the kinetic energy of the car using the equation:
KE = 0.5mv²where m is the mass of the car and v is its velocity.
Substituting the given values:
KE = 0.5 x 2000 kg x (30 m/s)² = 900,000 JThe total energy input is the energy released by burning 0.1 L of gasoline, which is:
Total energy input = 0.1 L x 30 MJ/L = 3 MJ = 3,000,000 JSubstituting these values into the equation for efficiency:
Efficiency = (900,000 J / 3,000,000 J) x 100% = 0.3 x 100% = 16.7%Therefore, the energy efficiency of the car is approximately 16.7%.
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"Part B? Question
The total resistance in a circuit with two parallel resistors is 2 ohms and $R_1$ is 6 ohms. Using the equation for R₂, in terms of Rt and R₁, what is R₂ ?
R₂ is ohms."
The value of R₂, given that the total resistance in a circuit with two parallel resistor is 2 ohms, is 3 ohms
How do I determine the value of R₂?The formula to obtain the total resistance in a parallel connection for two resistors is given as folllow:
Rₜ = (R₁ × R₂) / (R₁ + R₂)
With the above formula, we can obtain the value of R₂. Details below:
Total resistance (Rₜ) = 2 ohmsResistor 1 (R₁) = 6 ohms Resistor 2 (R₂) = ?Rₜ = (R₁ × R₂) / (R₁ + R₂)
2 = (6 × R₂) / (6 + R₂)
2 = 6R₂ / (6 + R₂)
Cross multiply
2 × (6 + R₂) = 6R₂
Clear bracket
12 + 2R₂ = 6R₂
Collect like terms
12 = 6R₂ - 2R₂
12 = 4R₂
Divide both sides by 4
R₂ = 12 / 4
R₂ = 3 ohms
Thus, we can conclude that the value of R₂ is 3 ohms
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Can someone help me please?
Ptolemy's and Copernicus' models attempted to explain the observed motion of the planets.
Ptolemy's modelThe sun, moon, and planets were thought to orbit the Earth according to Ptolemy and Copernicus' theories.
In Ptolemy's cosmology, the planets moved in intricate, elliptical orbits around the Earth, which was thought to be the center of the cosmos. The sun was thought to be at the center of the solar system and the planets, including Earth, to orbit it in a circular path according to Copernicus' hypothesis.
In comparison to Ptolemy's model, Copernicus' model predicted planetary positions and motion more precisely. Copernicus' use of more precise observational data contributed to this in part.
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If the truck has a mass of 2,000 kilograms , what's its momentum?(v=35 m/s)
Answer:
\(\boxed {\boxed {\sf 70,000 \ kg*m/s}}\)
Explanation:
Momentum is the product of mass and velocity.
\(p=m*v\)
The mass of the truck is 2,000 kilograms and the velocity is 35 meters per second.
\(m= 2000 \ kg \\v= 35 \ m/s\)
Substitute the values into the formula and multiply.
\(p= 2000 \ kg * 35 \ m/s \\p= 70,000 \ kg*m/s\)
The truck's momentum is 70,000 kilograms meters per second.
Earth has a mass of 5.98 1024 kg and a radius of 6.38 106 m. Assume it is a uniform solid sphere. The distance of Earth from the Sun is 1.50 1011 m. (Assume Earth completes a single rotation in 24.0 hours and orbits the Sun once every 365 Earth days.) (a) What is the rotational kinetic energy of Earth on its axis
Answer:
Explanation
Rotational kinetic energy of the earth = 1/2 Iω²
where I is moment of inertia of the earth and ω is angular velocity .
I = 2/5 m R² , m is mass and R is radius of the earth .
I = 2/5 x 5.98 x 10²⁴ x ( 6.38 x 10⁶ )²
=97.36 x 10³⁶
ω = 1 / T
T = 24 x 60 x 60 = 86400 s
ω = 1 / 86400
= 11.57 x 10⁻⁶ rad / s
Rotational Kinetic energy = 1/2 Iω²
= .5 x 97.36 x 10³⁶ x (11.57 x 10⁻⁶ )²
= 6516.54 x 10²⁴ J
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
To learn more about acceleration
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4
2 points
Which of the following is a vector quantity?
O Velocity
O
Time
Speed
оо
Distance
Answer:
Velocity Has vector Quantity
Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.