Answers
1. The forces on the same cart at rest are the gravitational force (weight), which acts downward, and the normal force, which acts upward to support the weight of the cart and any objects inside it.
2. The net force on the cart would be 20.0 newtons (40.0 N pushing force - 20.0 N friction force = 20.0 N net force). The cart may not move at a constant velocity over the spilled margarine due to the decrease in friction force.
3. The normal force on the shopping cart after 75 newtons of groceries are added would increase to support the additional weight of the groceries.
4. The force that accelerates the cart down the ramp is the component of the gravitational force that acts parallel to the ramp, which is known as the force of gravity or weight.
5. The friction force on the cart when it is rolling along the blacktop parking lot would likely be greater than the friction force on the cart when it is inside the grocery store, as blacktop is generally rougher and less smooth than smooth vinyl tile.
6. It is easier to get one empty cart moving because it has less mass and inertia than a line of 20 empty carts. Inertia is the tendency of an object to resist changes in its motion, and it increases with mass. Therefore, it requires more force to overcome the inertia of a line of 20 carts than that of a single cart.
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Gravitational force and normal force acts on the same cart at rest and it is worth noting that the gravitational force on an object at rest on a flat surface is equal to the normal force on that object.
What about the net force and the normal force relative to the cart?
The cart's net force would be 20.0 N (40.0 N - 20.0 N = 20.0 N net force). Because of the decrease in friction force, the cart may not move at a constant velocity over the spilled margarine. Also, it is to be noted that the normal force on the cart would increase after 75 N of groceries were added to support the additional weight of the groceries.
What about the frictional force on the cart?
Because blacktop is generally rougher and less smooth than smooth vinyl tile, the friction force on the cart while rolling along the blacktop parking lot is likely to be greater than the friction force on the cart while rolling inside the grocery store. It is easier to move one empty cart than a line of 20 empty carts because it has less mass and inertia. Inertia is an object's tendency to resist changes in motion, and it increases with mass.
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Related Questions
What is the binding energy for the nuclide 199F (atomic mass: 18.9984 amu) in MeV per nucleus?
Answers
The binding energy per nucleon for the ¹⁹F nucleon is equal to 7.786 MeV/nucleon.
What is binding energy?Binding energy can be defined as the minimum quantity of energy that is required to remove the particle from the system. Nuclear binding energy can be described as the energy required to dismantle a nucleus of an atom into free neutrons and protons.
The binding energy will be determined from the mass defect. Mass defect is calculated from the difference between the mass observed and the expected combined mass.
Given the mass of the ¹⁹F = 18.9984 a.m.u.
The mass defect for the ¹⁹F can be calculated as:
Δm = \((M _n +M_p) - M_F\)
\(\triangle m =( 9\times 1.0078 + 10 \times 1.0087 )- 18.9984\)
\(\triangle m =0.1588 \;a.m.u.\)
The binding energy for the fluorine can be calculated as:
E = Δmc²
E = 0.1588 × 931.5
E = 147.92 MeV
The binding energy per nucleon of ¹⁹F can be calculated as:
B.E.N. = 147.92/18.9984 = 7.786 MeV per nucleon
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a sample of what looks like silver has a mass of 1.7 kg and a volume of 0.164 liters is it really silver
Answers
Answer:
It is not 100% silver, but it contains a high percentage (more than the 98% for sure) of silver.
Explanation:
Hello,
In this case, since the density of silver is 10.49 g/cm³, we can substantiate if the given sample is silver by computing is density as shown below:
\(\rho =\frac{m}{V}=\frac{1.7kg}{0.164L}*\frac{1000g}{1kg} *\frac{1L}{1000cm^3}\\ \\\rho=10.37g/cm^3\)
In such a way, since we find a slight difference in the computed density, we can say it is not 100% silver, but it contains a high percentage (more than the 98% for sure) of silver.
Regards.
Naso(aq) + Pb(NO3)2(aq) → PbSO4(s) + 2NaNO3(aq)is an example of what type of
reaction?
decomposition
double displacement
single displacement
synthesis
Answers
In liquids, the attractive intermolecular forces are ________. In liquids, the attractive intermolecular forces are ________. strong enough to keep the molecules confined to vibrating about their fixed lattice points strong enough to hold molecules relatively close together strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other not strong enough to keep molecules from moving past each other
Answers
Answer:
strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other.
Explanation:
In liquids, the attractive intermolecular forces are strong enough to hold molecules relatively close together but not strong enough to keep molecules from moving past each other.
Intermolecular forces are the forces of repulsion or attraction.
Intermolecular forces lie between atoms, molecules, or ions. Intramolecular forces are strong in comparison to these forces.
In liquids, the attractive intermolecular forces are strong enough to hold
molecules relatively close together but not strong enough to keep
molecules from moving past each other.
Liquid is a state of matter in which the atoms are relatively close to each
other but less than that of solids which are densely and tightly packed.
The intermolecular force in liquids are strong enough to hold them together
which makes them less easily compressible but not strong enough to keep
them from moving or gliding past each other because they aren't tightly
packed.
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Choose the equation below that is balanced correctly.
S8 +24 028 SO3
S8+ 12 0₂8 SO3
6 S8+8 026 SO3
2 S8 +3 022 SO3
Answers
The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.
What is the balanced chemical equation?Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.
The balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is determined as;
2S₈ + 16O₂ → 16SO₃
From the reactants side we can see that sulfur is 16 and also 16 in the product side. The number of oxygen in the reactant side is 32 and also 32 in the product side.
Thus, the balanced equation for the reaction between sulfur (S₈) and oxygen (O₂) to form sulfur trioxide (SO₃) is 2S₈ + 16O₂ → 16SO₃.
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What forms of energy are produced when
fossil fuels burn?
Answers
When fossil fuels burn, several forms of energy are produced, including:
Heat energy: The primary form of energy released during fossil fuel combustion is heat. Fossil fuels contain chemical energy stored for millions of years, and when they burn, this energy is released in the form of heat. The heat energy can be harnessed for various purposes, such as heating buildings or generating steam to drive turbines.
Light energy: Burning fossil fuels can also produce light energy in the form of flames or glowing embers. This light energy is a byproduct of combustion.
Mechanical energy: Heat generated by burning fossil fuels can be converted into mechanical energy. This is typically achieved by using heat to produce steam, which drives a turbine connected to a generator. The rotating turbine converts the heat energy into mechanical energy, which is further transformed into electrical energy.
Electrical energy: Through the process described above, burning fossil fuels can ultimately generate electrical energy. The mechanical energy produced by the turbine is converted into electrical energy by the generator. Electrical energy can power various devices, appliances, industries, and infrastructure.
It's critical to note that while burning fossil fuels can produce useful forms of energy, it also results in the release of carbon dioxide and other greenhouse gases. This contributes to climate change and environmental concerns. As a result, there is a global shift towards cleaner and renewable energy sources to mitigate these negative impacts.
show the formation of Mgion and Oion.
Answers
Cation present in MgO→Mg
2+
Anion present in MgO→O
2−
What do you think the biggest risk with genetic engineering is?
Answers
Answer:
Harmful toxins from crops have been found in peoples blood.
GM crops can cause allergic reactions in crops
Its dangerous to mess with nature this way when it should be a natural thing.
Explanation:
I'm in both Biology and Chemistry so I know a lot!
When I was a boy, Uncle Wilbur let me watch as he analyzed the iron content of runoff from his banana ranch. A 25.0-mL sample was acidified with nitric acid and treated with excess KSCN to form a red complex. (KSCN itself is colorless.) The solution was then diluted to 100.0 mL and put in a variable-path length cell. For comparison, a 10.0-mL reference sample of 6.74 times 10^-4 M Fe^3+ was treated with HNO_3 and KSCN and diluted to 50.0 mL, The reference was placed in a cell with a 1.00-cm light path. The runoff sample exhibited the same absorbance as the reference when the path length of the runoff cell was 2.41 cm. What was the concentration of iron in Uncle Wilbur's runoff?
Answers
Answer:
C = 2.24x10⁻⁴ M
Explanation:
The concentration of iron in Uncle Wilbur's runoff can be calculated using Beer-Lambert law:
\( A = \epsilon*C*l \) (1)
Where:
A: is the absorbance of the compound
ε: is the molar absorptivity of the compound
C: is the concentration of the compound
l: is the optical path length
Since the runoff sample exhibited the same absorbance as the reference sample, we can find the concentration using equation (1):
\( \epsilon*C_{1}*l_{1} = \epsilon*C_{2}*l_{2} \) (2)
Where:
Subscripst 1 and 2 refer to Uncle Wilbur's runoff and to reference sample, respectively.
l₁ = 2.41 cm
l₂ = 1.00 cm
We can find C₂ as follows:
\( C_{2} = \frac{C_{2i}*V_{i}}{V_{f}} \) (3)
Where:
\(C_{2i}\): is the initial concentration of the reference sample = 6.74x10⁻⁴ M
\(V_{i}\): is the initial volume = 10.0 mL
\(V_{f}\): is the final volume = 50.0 mL
\( C_{2} = \frac{6.74 \cdot 10^{-4} M*10.0 mL}{50.0 mL} = 1.35 \cdot 10^{-4} M \)
Now, we can find C₁ using equation (2):
\( C_{1} = \frac{C_{2}*l_{2}}{l_{1}} = \frac{1.35 \cdot 10^{-4} M*1.00 cm}{2.41 cm} = 5.60 \cdot 10^{-5} M \)
Finally, since the runoff solution was diluted to 100.0 mL, the initial concentration can be calculated using equation (3) for \(C_{1i}\):
\(C_{1i} = \frac{C_{1}*V_{f}}{V_{i}} = \frac{5.60 \cdot 10^{-5} M*100.0 mL}{25.0 mL} = 2.24 \cdot 10^{-4} M\)
Therefore, the concentration of iron in Uncle Wilbur's runoff is 2.24x10⁻⁴ M.
I hope it helps you!
What is an Atomic Model
Answers
Answer:
the structure of an atom, theoretically consisting of a positively charged nucleus surrounded and neutralized by negatively charged electrons revolving in orbits at varying distances from the nucleus, the constitution of the nucleus and the arrangement of the electrons differing with various chemical elements.
Explanation:
CAN SOMEONE HELP WITH THIS QUESTION?✨
Answers
The final temperature of the calorimeter after the reaction is 230.0°C. To calculate the final temperature of the calorimeter after the reaction, we need to use the equation:
q = m x c x ΔT
where q is the heat gained or lost by the system, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the system is the calorimeter and the reaction involves the iron metal. The heat gained by the system is equal to the heat lost by the iron metal, so we can set q_calorimeter = -q_iron.
We are given that the mass of the iron metal is 2.000 g and the specific heat capacity of the calorimeter is 350.0. We need to determine the change in temperature, ΔT.
To do this, we need to know the heat released by the iron metal, which can be calculated using the equation:
q_iron = m x c x ΔT
where m is the mass of the iron metal and c is its specific heat capacity. The specific heat capacity of iron is 0.449 J/g°C.
Substituting the values given, we have:
q_iron = 2.000 g * 0.449 J/g°C x ΔT
q_iron = 0.898 J/°C x ΔT
Since q_calorimeter = -q_iron, we have:
q_calorimeter = -0.898 J/°C * ΔT
We know that the initial temperature of the calorimeter was 23.0°C, so we can set:
q_calorimeter = m_calorimeter x c_calorimeter x ΔT
where m_calorimeter is the mass of the calorimeter and c_calorimeter is its specific heat capacity.
Substituting the given values, we have:
-0.898 J/°C * ΔT = m_calorimeter x 350.0 J/kg°C x (T- 23.0°C)
where T is the final temperature of the calorimeter.
We can simplify this equation by converting the mass of the calorimeter from grams to kilograms:
-0.898 J/°C * ΔT = m_calorimeter * 0.350 J/g°C * (T- 23.0°C)
-0.898 J/°C * ΔT = 0.001 m_calorimeter * (T - 23.0°C)
Solving for ΔT, we get:
ΔT = (0.001 m_calorimeter * (T - 23.0°C)) / -0.898 J/°C
ΔT = -1.114 m_calorimeter * (T - 23.0°C)
ΔT = -1.114 Tx m_calorimeter + 25.642 m_calorimeter
To solve for T, we need to know the mass of the calorimeter. Let's assume it is 100 g. Substituting this value, we get:
ΔT = -1.114 Tx 0.100 kg + 2.5642 kg°C
ΔT = -0.1114 T + 25.642
Setting ΔT to zero (since the final temperature will be when the system is at equilibrium), we can solve for T:
0 = -0.1114 T + 25.642
T = 230.0°C
Therefore, the final temperature of the calorimeter after the reaction is 230.0°C.
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To calculate changes in concentration for a system not at equilibrium, the first step is to determine the direction the reaction will proceed. To do so, we calculate Q and compare it to the equilibrium concentration, K. We can then determine that a reaction will shift to the right if:__________
Answers
Answer:
We can then determine that a reaction will shift to the right if Q<K
Explanation:
Comparing Q with K allows to find out the status and evolution of the system:
If the reaction quotient is equal to the equilibrium constant, Qc = Kc, the system has reached chemical equilibrium. If the reaction quotient is greater than the equilibrium constant, Qc> Kc, the system is not in equilibrium and will evolve spontaneously, decreasing the value of Qc until it equals the equilibrium constant. In this way, the concentrations of the products will decrease and the concentrations of the reagents will increase. In other words, the reverse reaction is favored to achieve equilibrium. Then the system will evolve to the left (ie products will be consumed and more reagents will be formed).If the reaction quotient is less than the equilibrium constant, Qc <Kc, the system is not in equilibrium and will evolve spontaneously increasing the value of Qc until it equals the equilibrium constant. This implies that the concentrations of the products will increase and those of the reagents will decrease. In other words, to achieve balance, direct reaction is favored. Then the reaction will shift to the right, that is, reagents will be consumed and more products will be formed.In this case, we can then determine that a reaction will shift to the right if Q<K
Nitrogen monoxide is produced by combustion in an automobile engine. For the following reaction, 4.36 grams of nitrogen monoxide are mixed with excess oxygen gas . The reaction yields 5.46 grams of nitrogen dioxide . nitrogen monoxide ( g ) oxygen ( g ) nitrogen dioxide ( g ) What is the theoretical yield of nitrogen dioxide
Answers
Answer:
\(6.68~g~NO_2\)
Explanation:
We have to start with the combustion reaction:
\(NO~+~O_2~->~NO_2\)
Then we can balance the reaction:
\(2NO~+~O_2~->~2NO_2\)
If we want to find the theoretical yield, we have to calculate the amount of \(NO_2\). To do this, we have to first convert the 4.36 g of \(NO\) to moles \(NO\) (using the molar mass 30 g/mol), then we have to convert from moles of \(NO\) to moles of \(NO_2\) (using the molar ratio) finally, we have to convert from moles of \(NO_2\) to grams of \(NO_2\) (using the molas mass 46 g/mol), so:
\(4.36~g~NO\frac{1~mol~NO}{4.36~g~NO}\frac{2~mol~NO_2}{2~mol~NO}\frac{46~g~NO_2}{1~mol~NO_2}=6.68~g~NO_2\)
I hope it helps!
water is conductor or insluator? nails are conductor or insulator? key chains are conductor or insulator?
Answers
Answer:
Explanation:
Water is a conductor if it has solutes/ions dissolved in it(tapwater for example)
but pure water is not a good conductor of electricity.
Nails and keychains(made of metal) are conductors of electricity.
combustion always result in to formation of water. what other type of reactions may result into formation of water? examples of these reactions
Answers
As combustion always result into the formation of water, the other type of reactions that may result into formation of water are Acid-Base Neutralization Reactions and Hydrogen and Oxygen Reaction.
Acid-Base Neutralization Reactions:
A neutralisation reaction is a chemical process in which an acid and a base combine to produce salt and water as the end products.
H⁺ ions and OH⁻ ions combine to generate water during a neutralisation reaction. Acid-base neutralisation is the most common type of neutralisation reaction.
Example: Formation of Sodium Chloride (Common Salt):
HCl + NaOH → NaCl + H₂O
Hydrogen and Oxygen Reaction:
Water vapour is created when hydrogen gas (H₂) and oxygen gas (O₂) are combined directly. This reaction produces a lot of heat and releases a lot of energy.
Example: 2 H₂ + O₂ → 2 H₂O
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Which part of the electromagnetic spectrum is nearest to X-rays?
Answers
Answer:
UV or Gamma Rays
Explanation:
X-rays: 10^-10
UV: 10^-8
Gamma Rays: 10^-12
A change in tempo is the only thing that can make a musical cliché more effective.
A. False, a change in dynamics is the only thing that can make a musical cliché more effective.
B. True
C. False, using changes in tempo and dynamics can make a musical cliché more effective.
D. False, a change in tempo cannot make a musical cliché more effective.
Answers
False, using changes in tempo and dynamics can make a musical cliché more effective. Hence, option C is correct.
What is musical tempo ?Tempo in a music refers to pace of the music especially in high pitch sound waves. The most common unit of measurement for tempo is beats per minute (BPM), which is just the quantity of beats that may be captured in a minute at a certain pace.
A musical segment or composition is slower when the beats per minute is lower than when the BPM is greater. While a higher BPM is more likely to make the listener feel excited, a lower BPM is more likely to have a calming and/or sad effect on the listener.
Changing dynamics is some more effective way to make musical cliché. Hence, option C is correct.
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A student dissolves 15.g of styrenein (C8H8) in 250 mL of a solvent with a density of 0.88g/mL. The student notices that the volume of the solvent does not change when the styrene dissolves in it.Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.
Answers
The molar mass of styrene (C8H8) is 104 g/mol, when a student dissolves 15.g of styrenein (C8H8) in 250 mL of a solvent with a density of 0.88g/mL.
To calculate the molarity of a solution, you must divide the number of moles of solute (styrene) by the volume (liters) of the solution: 1438 mol ÷ 0.
25 L = 0.5752 M = 0.58 M (rounded to two significant figures)
To calculate the molarity of a solution, divide the number of moles of solute by the mass of solvent in grams.
0.1438 mol ÷ 250 g = 0.0005752 mol/g = 0.
00058 mol/g (rounded to 2 significant figures
A student dissolved 15 g of styrene (C8H8) in 250 ml of solvent with a density of 0.88 g/ml. Styrene has a molar mass of 104 g/mol, so the number of moles of solute is 15 g ÷ 104 g/mol = 0.1438 mol The molarity of the solution is zero.
1438 mol ÷ 0.25 L = 0.58 M. Molarity is calculated as 0.1438 mol ÷ 250 g = 0.
00058 mol/g. Both molarity and molarity are measures of concentration and indicate the amount of solute in a solution.
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5.86 ■ Liquid oxygen for use as a rocket fuel can be produced by cooling dry air to −183°C, where the O2 condenses. How many liters of dry air at 25°C and 750 torr would need to be processed to produce 150 L of liquid O2 at −183°C? (The mole fraction of oxygen in dry air is 0.21, and the density of liquid oxygen is 1.14 g/mL.)
Answers
Approximately 631.5 liters of dry air at 25°C and 750 torr would need to be processed to produce 150 liters of liquid \(O_2\) -183°C.
To solve this problem, we need to consider the ideal gas law and the molar volume of gases.
First, we can calculate the number of moles of oxygen in 150 L of liquid \(O_2\) at -183°C. To do this, we divide the mass of liquid oxygen by its molar mass:
Mass of liquid oxygen = volume of liquid oxygen * density of liquid oxygen = 150 L * 1.14 g/mL = 171 g
Molar mass of oxygen (O2) = 32 g/mol
Number of moles of oxygen = mass of oxygen / molar mass of oxygen = 171 g / 32 g/mol ≈ 5.34 mol
Since the mole fraction of oxygen in dry air is given as 0.21, we can calculate the total moles of dry air needed to produce 5.34 mol of oxygen:
Moles of dry air = moles of oxygen / mole fraction of oxygen = 5.34 mol / 0.21 ≈ 25.43 mol
Now, we can use the ideal gas law to calculate the volume of dry air at 25°C and 750 torr (convert to atm) that corresponds to 25.43 mol:
PV = nRT
P = 750 torr * (1 atm / 760 torr) ≈ 0.987 atm
V = volume of dry air (unknown)
n = 25.43 mol
R = 0.0821 L·atm/(mol·K)
T = 25°C + 273.15 = 298.15 K
Solving for V:
V = nRT / P = (25.43 mol)(0.0821 L·atm/(mol·K))(298.15 K) / 0.987 atm ≈ 631.5 L
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A sample consisting of 65.0 g of xenon is confined in a container at 2.00 atm and 298 K and then allowed to expand adiabatically (a) reversibly to 1.00 atm, (b) against a constant pressure of 1.00 atm. Calculate the final temperature and the expansion work at each case. Use the fact that xenon is a monoatomic gas.
Answers
Answer:
[a]. - 445.45J,
[b]. - 367.92 J
Explanation:
The following parameters are given in the question above. These information are used in solving this problem.
The mass of Xenon = 65.0 g of xenon, pressure = 2.00 atm, temperature = 298 K.
The number of moles of xenon = mass/ molar mass = 65g/ 131.293= 0.495.
The cp= 3/2 R, cp =3/2R + R = 5/2 R.
j = cp/cv = 3/2.
[a]. The final temperature,T2 = (2)^-2/3 × (298)^5/3 = T2^5/3.
Final temperature,T2 = 225.84K.
Expansion work = nCv [ T₂ - T₁] = 0.495 × 3/2 × 8.314 × [ 225.84 - 298] = - 445.45J.
(b). The final temperature can be Determine as;
3/2( T2 - 298k) = - 1 (T2 /1 - 298/2).
3/2(T2 - 298) = - T2 + 149K.
3T2 - 894 = - 2T2 +298K.
T2 = 238.4 K.
Workdone= nCv (T2 - T1) = 0.495 × 3/2 × 8.314 (238.4 - 298) = - 367.92 J.
Jessa examines a bullet at a crime scene. The markings, called
Answers
1) She would find "ballistic markings" or "striations."
2) She would find the whorl pattern of finger prints
What are the markings called?As a crime scene investigator, Jessa will search for distinctive signs on the bullet that could identify it as coming from a particular firearm. Common names for these stains include "ballistic markings" and "striations." When a bullet travels through a gun's barrel, it may leave behind distinctive traces due to flaws in or wear on the rifling, spiral grooves carved into the barrel to stabilize the projectile. These traces are imprinted on the bullet's surface and can be examined to identify the weapon type.
Jessa will likely use a comparison microscope to inspect the bullet and compare the ballistic marks to test-fired bullets from potential guns.
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Missing parts;
Jessa is a crime scene Investigator. She examines a bullet found at the scene and a fingerprint left in a blood smear. What type of marks might
link the bullet to a specific weapon? Which type of fingerprints has she found?
Jessa examines a bullet at a crime scene. The markings, called might link the bullet to a specific weapon. She also finds some
fingerprints smeared in the blood of the victim. These are
fingerprints.
Write structural formulas for all of the possible structural isomers of n-hexene that can be formed by moving the position of the double bond. Draw the molecules on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.
Answers
The same molecular formula exists in structural isomers, but their atom connectivities change.
By shifting the double bond's position, n-hexene can have three structural isomers. Below is a list of these isomers' structural formulas:
H2C=CH-CH2-CH2-CH2-CH3 6
1-hexene
1 H3C CH=CH-CH2-CH2-CH3 6
2-hexene
6 H3C CH2-CH-CH-CH2-CH3 1
3-hexene
The term "structural isomer," also known as a "constitutional isomer," refers to a group of two or more organic compounds that share the same chemical formula but have different structures. In spite of having an identical chemical formula, the two molecules below differ in where the methyl group is located.
for illustration, The chemical formulae of butane and isobutane are identical because they both contain the same number of carbon (C) and hydrogen (H) atoms.
Five categories exist for structural isomerism:
Chain isomerism.Position isomerism.Functional group isomerism.Metamerism.Tautomerism.To learn more about Structural isomers. Please visit the below link.
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A location that was covered in ocean water gradually became dry land over time. Three rock layers from the location are shown below. Put each rock layer in the correct position.
Answers
Strata, the plural of the Latin term stratum, is another name for rock layers, while stratigraphy is the study of strata. Lithostratigraphic deals with every one of the features of rock layers.
According to the movement of two rocks, what are the three types of faults?Normal, reverse, strike-slip, or oblique faulting are the four different categories of faulting. A normal fracture is one where the hanging wall or footwall of rocks well above fault plane moves downward in relation to the footwall of those rocks. When the footwall rises up compared to the hanging wall, this is known as a reversal fault.
What are the three different tectonic pressures that cause rock layers to deform?Force exerted to a rock is known as stress, and it can result in deformation. Compression at convergent plate boundaries, stress at divergent plate boundaries, or shear at transform barriers are the three primary types of stress that are characteristic of the three different types of plate boundaries.
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List the steps that occur in a generator that transform the mechanical energy of the turbine
into electricity. Be sure to include the role that magnetic and electric fields play in the process.
Answers
Electric charges flow through connection wires to constitutes electric current which supplie the generator.
What is generatorAn electric generator are used to generate electricity, they converts mechanical energy to form electricity.
Electric charges are available in the wire will winds through an external electric circuit to generate electricity.
Electric charges flow through this wires to constitutes electric current which supplies the generator.
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In part D of task 1, you identified at least two ways in which the reaction of nitrogen and hydrogen could be changed to alter the equilibrium. Use the simulation to test those changes. Describe how you used the simulation to model the changes and the results they produced. Use these methods if you find them helpful:
Look at the pie graph to see how the system changes.
Use the Temperature slider at the bottom to cool or heat the mixture.
Click the pause button on the simulation to observe the number of particles at any point of time.
Answers
Answer:
I can tell you some ways in which the reaction of Nitrogen and Hydrogen could be changed to alter the equilibrium.
Changing the pressure: If the pressure is increased, there will be more collisions between the molecules and this will increase the rate of the forward reaction. As a result, the equilibrium will shift to the left, leading to a decrease in the number of molecules of NH3.
Changing the temperature: If the temperature is increased, the kinetic energy of the molecules will increase, leading to more collisions between the molecules. This will increase the rate of the forward reaction and shift the equilibrium to the left.
To model these changes in a simulation, you could use the temperature slider to increase or decrease the temperature of the mixture and observe the changes in the equilibrium. You could also use the pressure slider to increase or decrease the pressure of the mixture and observe the changes in the equilibrium. Additionally, you can use the pause button to observe the number of particles at any point in time.
The first energy shell around a nucleus can hold _______ electrons. The second energy shell can hold ________.
answer choices:
A. 8, 18
B. 0, 10
C. 2, 8
D. 10, unlimited
Answers
Hi there,
I hope you and your family are staying safe and healthy!
The correct answer is C
Each shell can contain only a fixed number of electrons. The first energy shell around a nucleus can hold up to 2 electrons. Then the second shell can hold up to 8 eletrcons.
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~Gary
Which one of the following is a heterogenous mixture?Group of answer choicesteawhite winesalt waterairnoodle
Answers
Answer:
Noodle (last option).
Explanation:
In a heterogeneous mixture the components can be easily distinguished, so noodle is an exmaple of this mixture.
The rate constant, k, for a reaction is 0.0354 sec1 at 40°C. Calculate the rate constant for the
same reaction at 125°C if the activation energy is 26.5 kJ/mol.
Answers
Answer:
The rate constant of the reaction at 125˚ is \(0.3115 \ \text{sec}^{-1}\).
Explanation:
The Arrhenius equation is a simple equation that describes the dependent relationship between temperature and the rate constant of a chemical reaction. The Arrhenius equation is written mathematically as
\(k \ = \ Ae^{\displaystyle\frac{-E_{a}}{RT}}\)
\(\ln k \ = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT}\)
where \(k\) is the rate constant, \(E_{a}\) represents the activation energy of the chemical reaction, \(R\) is the gas constant, \(T\) is the temperature, and \(A\) is the frequency factor.
The frequency factor, \(A\), is a constant that is derived experimentally and numerically that describes the frequency of molecular collisions and their orientation which varies slightly with temperature but this can be assumed to be constant across a small range of temperatures.
Consider that the rate constant be \(k_{1}\) at an initial temperature \(T_{1}\) and the rate constant \(k_{2}\) at a final temperature \(T_{2}\), thus
\(\ln k_{2} \ - \ \ln k_{1} = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT_{2}} \ - \ \left(\ln A \ - \ \displaystyle\frac{E_{a}}{RT_{1}}\right) \\ \\ \\ \rule{0.62cm}{0cm} \ln \left(\displaystyle\frac{k_{2}}{k_{1}}\right) \ = \ \displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)\)
\(\rule{1.62cm}{0cm} \displaystyle\frac{k_{2}}{k_{1}} \ = \ e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)} \\ \\ \\ \rule{1.62cm}{0cm} k_{2} \ = \ k_{1}e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)}\)
Given that \(E_{a} \ = \ 26.5 \ \ \text{kJ/mol}\), \(R \ = \ 8.3145 \ \ \text{J mol}^{-1} \ \text{K}^{-1}\), \(T_{1} \ = \ \left(40 \ + \ 273\right) \ K\), \(T_{2} \ = \ \left(125 \ + \ 273\right) \ K\), and \(k_{1} \ = \ 0.0354 \ \ \text{sec}^{-1}\), therefore,
\(k_{2} \ = \ \left(0.0354 \ \ \text{sec}^{-1}\right)e^{\displaystyle\frac{26500 \ \text{J mol}^{-1}}{8.3145 \ \text{J mol}^{-1} \ \text{K}^{-1}}\left(\displaystyle\frac{1}{313 \ \text{K}} \ - \ \displaystyle\frac{1}{398 \ \text{K}} \right)} \\ \\ \\ k_{2} \ = \ 0.3115 \ \ \text{sec}^{-1}\)
(b) Two compounds, A and B, have the molecular formula C₂H6O. On treatment with Na metal, compound A releases H2 gas and compound B does not.
Can you give a reason to help to explain the observation better?
Answers
The observation that compound A releases H2 gas while compound B does not when treated with Na metal can be explained by considering the structural differences between the two compounds and their ability to undergo specific reactions.
Compound A and compound B both have the molecular formula C₂H₆O, which indicates that they both contain two carbon atoms, six hydrogen atoms, and one oxygen atom. However, the difference lies in the arrangement of these atoms within the molecules. One possible explanation for the observed difference is that compound A is an alcohol, specifically ethanol (CH₃CH₂OH), while compound B is an ether, such as dimethyl ether (CH₃OCH₃). The presence of the hydroxyl group (-OH) in ethanol enables it to undergo a reaction with sodium metal, known as the metal-acid reaction. In this reaction, the metal displaces the hydrogen from the hydroxyl group, forming sodium ethoxide (CH₃CH₂ONa) and releasing hydrogen gas (H₂). On the other hand, ethers like dimethyl ether lack the hydroxyl group and therefore cannot undergo the metal-acid reaction. Consequently, when compound B is treated with sodium metal, no hydrogen gas is released. The ability of compound A to release hydrogen gas while compound B does not when treated with sodium metal can be attributed to the presence of a hydroxyl group in compound A (ethanol), enabling it to undergo a metal-acid reaction, whereas compound B (dimethyl ether) lacks the necessary functional group and thus does not undergo this reaction.
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A tank contains 15 kg of dry air and 0.17 kg of water vapor at 30°C and 100 kPa total pressure. Determine
(a) the specific humidity, (b) the relative humidity, and (c) the volume of the tank.
Answers
The volume of the tank is approximately 130.75 m³.
To solve this problem, we need to use the concept of air and water vapor mixture. The given data includes the mass of dry air and water vapor, temperature, and total pressure. We can calculate the specific humidity, relative humidity, and volume of the tank using the following steps:
(a) Specific humidity:
The specific humidity (ω) is defined as the ratio of the mass of water vapor (m_w) to the total mass of the air-water vapor mixture (m_t):
ω = m_w / m_t
Given that the mass of water vapor is 0.17 kg and the total mass of the mixture is 15 kg + 0.17 kg = 15.17 kg, we can calculate the specific humidity:
ω = 0.17 kg / 15.17 kg ≈ 0.0112
So, the specific humidity is approximately 0.0112.
(b) Relative humidity:
Relative humidity (RH) is the ratio of the partial pressure of water vapor (P_w) to the saturation vapor pressure of water (P_ws) at the given temperature, multiplied by 100:
RH = (P_w / P_ws) * 100
To find the relative humidity, we need to determine the saturation vapor pressure at 30°C. Using a vapor pressure table or equation, we can find that the saturation vapor pressure at 30°C is approximately 4.246 kPa.
Given that the total pressure is 100 kPa, the partial pressure of water vapor is 0.17 kg / 15.17 kg * 100 kPa = 1.119 kPa.
Now we can calculate the relative humidity:
RH = (1.119 kPa / 4.246 kPa) * 100 ≈ 26.34%
So, the relative humidity is approximately 26.34%.
(c) Volume of the tank:
To find the volume of the tank, we can use the ideal gas law equation:
PV = nRT
Where P is the total pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
First, we need to calculate the number of moles of dry air and water vapor in the tank. The number of moles (n) can be obtained using the equation:
n = m / M
Where m is the mass and M is the molar mass.
The molar mass of dry air is approximately 28.97 g/mol, and the molar mass of water vapor is approximately 18.015 g/mol.
For dry air:
n_air = 15 kg / 0.02897 kg/mol ≈ 517.82 mol
For water vapor:
n_water = 0.17 kg / 0.018015 kg/mol ≈ 9.43 mol
Now we can calculate the volume using the ideal gas law:
V = (n_air + n_water) * R * T / P
Given that R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (30°C + 273.15 = 303.15 K), and P is the total pressure (100 kPa), we can calculate the volume:
V = (517.82 mol + 9.43 Mol) * 8.314 J/(mol·K) * 303.15 K / (100,000 Pa) ≈ 130.75 m³
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