i need help with the, Mia profit or loss for the money January account everfi

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Here's your Answer :

18.134 after rounding off - 18.1

2.28 after rounding off - 2.3

let's perform subtraction to get the required Answer :

The product of 6√8 and 3√24 in simplest radical form is 144√3

We can solve this problem by using the distributive property and simplifying the radicals.

6√8 * 3√24 = (6 * 3) * √(8 * 24)

Evaluate the products

6√8 * 3√24 = 18 * √(8 * 24)

Evaluate the products of radicals

6√8 * 3√24 = 18 * √(192)

Simplify the radical

6√8 * 3√24 = 18 * 4 * √12

So, we have

6√8 * 3√24 = 72√12

Now to simplify the radical, we can divide the radicand by the greatest perfect square that is a factor of it.

So, we have

72√12 =  72 * 2 * √3

= 144√3

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Answer:

12.

Step-by-step explanation:

if to re-write the given condition, then

\(\frac{3}{0.25} =\frac{18}{1.5} =\frac{30}{2.5} =\frac{36}{3} ;\)

it is clear, the required constant is 12 (12 per hour).

A whole number is a number that has no fractional representation.

Let's test all the options for the value of x.

When dividing a fraction by another fraction, the divisor will be in its reciprocal form.

1. 3/4  × 2/3

= 6/12 = 1/2

1/2 isn't a whole number.

2. 3/4 × 2/1

= 6/4 = 3/2

3/2 isn't a whole number.

3. 3/4 × 6/1

= 18/4 = 9/2

9/2 isn't a whole number.

4. 3/4 × 8/1

= 24/4 = 6

6 is a whole number.

Hence the answer is 1/8.

Hope it helps. :)

The algebraic rule for translating the figure 3 units left and 2 units up is (x-3, y+2).  Option B.

To translate a figure 3 units to the left and 2 units up, we need to adjust the coordinates of the figure accordingly. The algebraic rule that represents this translation can be determined by examining the changes in the x and y coordinates.

When we move a figure to the left, we subtract a certain value from the x coordinates. In this case, we want to move the figure 3 units to the left, so we subtract 3 from the x coordinates.

Similarly, when we move a figure up, we add a certain value to the y coordinates. In this case, we want to move the figure 2 units up, so we add 2 to the y coordinates.

Taking these changes into account, we can conclude that the algebraic rule for translating the figure 3 units left and 2 units up is (x-3, y+2). The x coordinates are shifted by subtracting 3, and the y coordinates are shifted by adding 2. SO Option B is correct.

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For this problem, we know that the line's function is equal to 3 if X isn't 0. That means that for every X that isn't 0, we'll have a line at y = 3 (since we know that g(x) is just fancy for y!). We're also given that if X is equal to 0, it must be at y = 4.

Therefore, your graph should have a straight line through y = 3 EXCEPT at x = 0! At x = 0 you should just have a shaded dot at y = 4.

Answer: 138.557

Step-by-step explanation:

Answer:

hey :( so just wondering hru ummm and u were right and umm ig i am just gonna f my life up always umm hru ?

Step-by-step explanation:

The amount insurance company will pay is $700000.

We are given that

Age of Mr. lewis= 63

Policy value= $700,000

Now,

If Mr. Lewis dies after paying for the policy for 24 months, he would have paid a total of 24 * $72 = $1728 in premiums. Since he has a five-year level-term life insurance policy with a face value of $700,000, his beneficiaries would receive the full face value of the policy if he dies within the five-year term.

Therefore, by algebra the answer will be $700000.

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the fraction of the class that did not participate in any of these activities is 1 - n * (151/60).

What is the fraction?

A fraction represents a part of a number or any number of equal parts. There is a fraction, containing a numerator(upper value) and denominator(lower value).

Let's call the number of students in the class "n".

2/3 of the class played in the band, so:

n * 2/3 participated in the band

1/6 of the class sang in the chorus, so:

n * 1/6 participated in the chorus

1/10 of the class played football, so:

n * 1/10 played football

1/60 of the class played basketball, so:

n * 1/60 played basketball

The fraction of the class that participated in one of these activities is the sum of these fractions:

n * (2/3 + 1/6 + 1/10 + 1/60) = n * (7/6 + 1/10 + 1/60)

So, the fraction of the class that did not participate in any of these activities is:

1 - n * (7/6 + 1/10 + 1/60) = 1 - (7/6 + 1/10 + 1/60) * n = 1 - n * (151/60)

Therefore, the fraction of the class that did not participate in any of these activities is 1 - n * (151/60).

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Answer:

 Table B -

Step-by-step explanation:

You want to know which of the four offered tables represents a linear function.

A linear function will have differences in y that have the same ratio to differences in x for all pairs of values in the table.

Table A has x-differences that are 1 between adjacent terms. The y-differences are negative for the first pair of table values, but positive for the last pair (2 -5 vs 5 -2).

Table B has x-differences that are 1 between adjacent terms. The y-differences are -2 between any pair of adjacent terms, so their ratio to x-differences is -2/1 = -2, a constant. Table B represents a linear function.

Table C has x-differences that change from 0 to -3 to +3 while y-differences are constant at +1. The ratios of differences are not constant.

Table D has x-differences of +1, and y-differences that alternate in sign and magnitude.

Only Table B represents a linear function.

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Answer:

\(b\) isn't a linear combination of the vectors formed from the columns of the matrix \(A.\)

Step-by-step explanation:

The question is misspelled. The correct \(A\) matrix and \(b\) vector are :

\(A=\left[\begin{array}{ccc}1&-4&2\\0&3&5\\-2&8&-4\end{array}\right]\)

\(b=\left[\begin{array}{c}3&-7&-3\end{array}\right]\)

In order to determine if \(b\) is a linear combination of the vectors formed from the columns of the \(A\) matrix we write the following linear combination with the columns from \(A\) :

\(\left[\begin{array}{c}1&0&-2\end{array}\right]x_{1}+\left[\begin{array}{c}-4&3&8\end{array}\right]x_{2}+\left[\begin{array}{c}2&5&-4\end{array}\right]x_{3}=\left[\begin{array}{c}3&-7&-3\end{array}\right]\)         (I)

This can be also written as :

\(AX=b\)

Where \(X\) is the following vector : \(X=\left[\begin{array}{c}x_{1}&x_{2}&x_{3}\end{array}\right]\)

The matrix from the system (I) is :

\(\left[\begin{array}{cccc}1&-4&2&3\\0&3&5&-7\\-2&8&-4&-3\\\end{array}\right]\)

Applying matrix operations to the system matrix we obtain this equivalent matrix :

\(\left[\begin{array}{cccc}1&-4&2&3\\0&3&5&-7\\0&0&0&3\end{array}\right]\)

From the third row we obtain that

\(0x_{1}+0x_{2}+0x_{3}=3\)

Which is an absurd. Therefore the system has no solution and it doesn't exist a linear combination of the vectors formed from the columns of the matrix \(A\) to obtain the vector \(b\).

Finally, \(b\) isn't a linear combination of the vectors formed from the columns of the matrix \(A.\)

Correction in point 1: Purchases of supplies for cash during December were $3,300. Supplies on hand at the end of December equal $2,800.

What is Journal Entry?

The act of recording any economic transactions is called a journal entry. An accounting journal lists transactions and displays a company's debit and credit balances. Each recording in the journal entry can be either a debit or a credit, and it can be made up of multiple recordings. The way an accounting transaction is entered into a company's accounting records is through an accounting journal entry.

This question is related to the account and finance subject.

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Complete Question:

Last year Mr. Petersen’s rectangular garden had a width of 5 meters and an area of 20 square meters.  This year he wants to make the garden three times as long and two times as wide.  

Last year, Mr. Petersen had a fence all the way around his garden. He can reuse all of the fence he had around the garden last year, but he needs to buy more fencing to go around this year’s garden.  

How many more meters of fencing is needed for this year’s garden than last year’s?

Answer:

26 meters of fencing needed

Step-by-step explanation:

Given

Last Year:

\(Width = 5m\)

\(Area = 20m^2\)

This Year:

\(Length = 3\ times\ longer\)

\(Width = 2\ times\ wider\)

Required

Determine how many more meters is needed

Represent last year's length of Fence with L and last year's width with W

First, we need to calculate L

\(Area = L * W\)

Where

\(Area = 20m^2\)

\(W = 5m\)

\(20m^2 = L * 5m\)

Divide both sides by 5m

\(\frac{20m^2}{5m} = \frac{L * 5m}{5m}\)

\(\frac{20m^2}{5m} = L\)

\(L = \frac{20m^2}{5m}\)

\(L = 4m\)

So, we have that:

For Last Year

\(Length = 4m\) and \(Width = 5m\)

For this year:

\(Length = 3\ times\ longer\)

\(Length = 3 * 4m\)

\(Length = 12m\)

\(Width = 2\ times\ wider\)

\(Width = 2 * 5m\)

\(Width = 10m\)

So, for this year, we have:

\(Length = 12m\) and \(Width = 10m\)

Next, we calculate perimeter of fencing in both years.

\(Perimeter = 2 * (Length + Width)\)

Last Year:

\(Perimeter = 2 * (4m + 5m)\)

\(Perimeter = 2 * 9m\)

\(Perimeter = 18m\)

This Year:

\(Perimeter = 2 * (12m + 10m)\)

\(Perimeter = 2 * 22m\)

\(Perimeter = 44m\)

To get the meters of fencing needed this year, we simply calculate the difference in the calculated perimeters.

\(Difference = 44m - 18m\)

\(Difference = 26m\)

Hence, there are 26 meters of fencing needed

As a result, choice C is the equation that best represents the algebraic tiles since we only need to determine the total or difference.

It is possible either multiply, distribute, add, or negate in mathematics. The trying to follow is how a expression is put together: Number, expression, and scientific operator The ingredients of a mathematical expression include numbers, variables, and operations (such as addition, subtraction, multiplication or division etc.) It is possible to combine expressions and phrases. An expressions, often known as an arithmetic operation, is any mathematical statement that contains variables, numerals, and a numerical operation between them. That instance, the word m there in given equation is separated from the terms 4m and 5 by the arithmetic symbol +, as is the variable m in the phrase 4m + 5.

given

To address this issue, we just need to determine the total or difference that yields 2x2 + 2x + 2

Option A: ( x2 + 4x -2) + (x2 - 2x - 4) = 2x2 + 2x - 6

Option B: ( x2 + 4x - 2 ) + ( x2 + 2x + 4 ) = 2x2 + 6x + 2

Option C: ( x2 + 4x - 2) - ( -x2 + 2x - 4)= x2 + 4x - 2 + x2 - 2x + 4

= 2x2 + 2x + 2

As a result, choice C is the equation that best represents the algebraic tiles since we only need to determine the total or difference.

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The complete question is:-

Select the correct answer.

Which sum or difference is modeled by the algebra tiles?

A. (-x2 + 2x + 3) − (x2 − 2x − 1) = -2x2 + 2

B. (-x2 + 2x + 3) − (-x2 + 2x + 1) = -2x2 + 2

C. (-x2 + 2x + 3) + (-x2 + 2x + 1) = -2x2 + 2

D. (-x2 + 2x + 3) + (-x2 − 2x − 1) = -2x2 + 2

Answer:

60

Step-by-step explanation:

Arc \(RMP\) has a measure of \(360^{\circ}-120^{\circ}=\boxed{240^{\circ}}\).

Using the tangent-tangent theorem,

\(m\angle RQP=\frac{240^{\circ}-120^{\circ}}{2}=\boxed{60^{\circ}}\)

Answer:

the correct answer would be B

Answer:

B

Step-by-step explanation:

I just did this problem

Option D, which is the closest choice to 933.33, is 930. As a result, 930 fraction acres is a plausible estimate of the amount of acres on which Mr. Bailey will plant soybeans

A fraction is a number that represents a portion of a whole or a ratio between two quantities in mathematics. It is represented as a top number (numerator) over a bottom number (denominator) divided by a horizontal line, also known as a vinculum. The fraction 3/4, for example, represents three-quarters of a whole that has been divided into four equal parts. Proper fractions, improper fractions, and mixed numbers are all ways to express a fraction. A suitable fraction is one in which the numerator is less than the denominator, for example, 2/5.

Mr. Bailey intends to plant soybeans on 4 of every 9 acres, which equates to (4/9) of the total acres he farms.

If he intends to cultivate 2,100 acres, the number of acres planted with soybeans is:

(4/9) x 2,100 = 933.33

We must round this amount to the next whole number because he cannot plant soybeans on a fraction of an acre.

Option D, which is the closest choice to 933.33, is 930. As a result, 930 acres is a plausible estimate of the amount of acres on which Mr. Bailey will plant soybeans.

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ANSWER:

A. 2,250 feet

STEP-BY-STEP EXPLANATION:

We can calculate the value of the height thanks to the tangent trigonometric function, which relates the opposite leg (altitude) and the adjacent leg (horizontal), as follows:

Replacing and solving for x:

The altitude value is 2250 feet

The surface area of the wooden structure is approximately 1012 cm².

To calculate the surface area of the wooden structure, we need to find the surface area of the cone and the surface area of the hemispherical base, and then add them together.

Surface Area of the Cone:

The surface area of a cone is given by the formula:

A_{cone = \(\pi \times r_{cone} \times (r_{cone} + s_{cone})\), \(r_{cone\) is the radius of the base of the cone and \(s_{cone\) is the slant height of the cone.

The vertical height of the cone is 24 cm, and the base radius is 7 cm, we can calculate the slant height using the Pythagorean theorem:

\(s_{cone\) = \(\sqrt{(r_{cone}^2 + h_{cone}^2).\)

Using the given measurements:

\(s_{cone\) = √(7² + 24²) cm

\(s_{cone\) ≈ √(49 + 576) cm

\(s_{cone\) ≈ √625 cm

\(s_{cone\) ≈ 25 cm

Now, we can calculate the surface area of the cone:

\(A_{cone\) = π × 7 cm × (7 cm + 25 cm)

\(A_{cone\) = (22/7) × 7 cm × 32 cm

\(A_{cone\) = 704 cm²

Surface Area of the Hemispherical Base:

The surface area of a hemisphere is given by the formula:

\(A_{hemisphere\) = \(2 \times \pi \times r_{base}^2\), \(r_{base\) is the radius of the base of the hemisphere.

Given that the base radius is 7 cm, we can calculate the surface area of the hemispherical base:

\(A_{hemisphere\) = 2 × (22/7) × (7 cm)²

\(A_{hemisphere\) = (22/7) × 2 × 49 cm²

\(A_{hemisphere\) = 308 cm²

Total Surface Area:

To calculate the total surface area, we add the surface area of the cone and the surface area of the hemispherical base:

Total Surface Area = \(A_{cone} + A_{hemisphere}\)

Total Surface Area = 704 cm² + 308 cm²

Total Surface Area = 1012 cm²

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Answer:

14.86606875 or

\( \sqrt{221} \)

Step-by-step explanation:

\( {5}^{2} + {14}^{2} = 221\)

\( \sqrt{221} \)

use the pythagorean theorem

497 divided by 3 gives decimal numbers

Which has repeating decimals.

Using long division, we have

Answer:

480 units ^3

Step-by-step explanation:

it was on the key but im not sure how to solve it

Answer:

O B. f(x) = 2^x

i think its true but iam not sure

hope it helps

Simplifying the equations will give 3x -1 = 4x, 3x + 18 = 4x + 7 and 7x = 1

Lets simplify each of the equations in order to match with the  equivalent equation from the second set

3x+6=4x+7

Collecting like terms

3x +6 - 7 = 4x

3x -1 = 4x

The second equation

3(x+6)=4x+7

expanding the bracket

3x + 18 = 4x + 7

The third equation

4x+3x=7-6

simplifying the equation

7x = 1

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The area of the triangle, when a = 2 and c = 3, is 1512 square centimeters.

We must apply the formula for the area of a triangle, which is provided by: to determine the triangle's area.

(1/2) * Base * Height = Area

We can enter the values of a = 2 and c = 3 into the formula given that the base length is 3ac2 and the height is 2 centimetres greater than the base length.

Base length =\(3ac^2 = 3 * 2 * (3^2) = 3 * 2 * 9 = 54\) centimeters

Height is calculated as Base Length + 2 (54 + 2 = 56 centimetres).

Using these values as a substitute in the formula, we obtain:

Area =\((1/2) * 54 * 56 = 1512\) square centimeters

centimetres square

It's crucial to understand that the calculation assumes the triangle is a right triangle with the specified base and height and that the given values of a and c are accurately used in the formula.

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Answer:

\(x=-2(y+3)^2-4:\)

Vertex: (-4, -3)

Focus: (-33/8, -3)

\(x=2(y-3)^2+4:\)

Vertex: (4, 3)

Directrix: (x=31/8)

Step-by-step explanation:

Due to the formula being squared, you know it's going to be a parabola. The 4 at the end is to shift the parabola (-4 = left 4, 4 = right 4). From there you can deduce the vertex and from there the focus and directrix.

Answer:

She ran 1/4 of a mile

Step-by-step explanation:

Multiply 1/3 by the distance

1/3 * 3/4

Canceling the 3's

1/4

She ran 1/4 of a mile

The general form of a trigonometric function is:

Where B is the frequency of the function.

In our problem, A=1, C=D=0.

Then, as the value of B increases, so the frequency does. The answer to the second gap is 'increases'.

On the other hand, let P be the period and f the frequency. Those two quantities are related by the formula:

Then, if the frequency increases, the period decreases. The answer to the first gap is 'decreases'.

Finally, if B is negative we have that:

Therefore, the function is reflected over the x-axis.