I need help please :((((((

I Need Help Please :((((((

Answers

Answer 1

Suppose you walk across a carpet with socks on your feet. When you touch a metal door handle, you feel a shock because, c. Excess negative charges build up in your body while walking across the carpet, then jump when attracted to the positive charges in the door handle.

When you walk across a carpet with socks on your feet, the friction between the carpet and your socks causes the transfer of electrons. Electrons are negatively charged particles. As you move, the carpet rubs against your socks, stripping some electrons from the atoms in the carpet and transferring them to your socks. This results in your body gaining an excess of negative charges.

The metal door handle, on the other hand, contains positive charges. When you touch the metal door handle, there is a sudden flow of electrons from your body to the door handle. This movement of electrons is known as an electric discharge or a static shock. The excess negative charges in your body are attracted to the positive charges in the door handle, and this attraction causes the sudden discharge of electrons, resulting in the shock that you feel.

It's important to note that the shock occurs due to the difference in charges between your body and the metal door handle. The friction between your socks and the carpet allows for the buildup of static electricity, and the shock is a result of the equalization of charges when you touch the metal object. Therefore, Option E is correct.

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Related Questions

A company wishes to produce two types of souvenirs: Type A and Type B. Each Type A souvenir will result in a profit of $0.80, and each Type B souvenir will result in a profit of $1.60. To manufacture a Type A souvenir requires 2 minutes on Machine I and 1 minute on Machine II. A Type B souvenir requires 1 minute on Machine 1 and 3 minutes on Machine II. There are 2 hours available on Machine I and 5 hours available on Machine 11. (a) For a meaningful solution, the time available on Machine II must lie between 90 X and x min. (Enter your answers from smallest to largest.) (b) If the time available on Machine II is changed from 300 min to (300 + k) min, with no change in the maximum (150 - A) capacity for Machine 1, then Ace Novelty's profit is maximized by producing Type A souvenirs 540 5 and 2(223+ *). 3 Type B souvenirs, where -225 1x ** $ 150 X X (c) Find the shadow price for Resource 2 (associated with constraint 2). (Round your answer to the nearest cent.)

Answers

The time available on Machine II must lie between 1 minute and 3 minutes. The shadow price for Resource 2 (associated with constraint 2) is $3 per minute.

(a) To determine the range of available time on Machine II, we need to consider the constraints provided. The time available on Machine II must be between the time required for Type A souvenirs and the time required for Type B souvenirs.

Time required for Type A souvenir on Machine II: 1 minute

Time required for Type B souvenir on Machine II: 3 minutes

Therefore, the time available on Machine II must lie between 1 minute and 3 minutes.

The meaningful solution for the available time on Machine II is 1 min ≤ Machine II ≤ 3 min.

(b) To maximize the profit, we need to determine the optimal production quantities for Type A and Type B souvenirs given a change in the available time on Machine II.

Let's assume the change in available time on Machine II is represented by k.

To maximize the profit, we need to find the production quantities that maximize the total profit. Let's denote the production quantity for Type A souvenirs as x and the production quantity for Type B souvenirs as y.

The objective function for the profit can be expressed as:

Profit = 0.80x + 1.60y

Subject to the following constraints:

2x + y ≤ 120 (Machine I constraint)

x + 3y ≤ (300 + k) (Machine II constraint)

Using linear programming techniques, the optimal solution will depend on the value of k.

The statement "Ace Novelty's profit is maximized by producing Type A souvenirs 540 5 and 2(223+ *). 3 Type B souvenirs, where -225 1x ** $ 150 X X" seems to be incomplete and unclear. The specific production quantities and profit cannot be determined without knowing the value of k.

(c) To find the shadow price for Resource 2 (associated with constraint 2), we can perform sensitivity analysis.

The shadow price represents the change in the objective function's value per unit increase in the availability of Resource 2 (Machine II in this case). We can determine it by evaluating the sensitivity of the objective function to changes in the constraint.

Since the constraint is x + 3y ≤ (300 + k), the shadow price associated with Resource 2 is the coefficient of the Machine II term, which is 3.

Therefore, the shadow price for Resource 2 (associated with constraint 2) is $3 per minute.

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A tight knot can be easily opens by using a longer spanner. Give reasons

Answers

It is because the effort distance is greater than the load distance

Explanation:

As we know, Effort×effort distance = load × load distance

So when effort distance is increases,

The effort decreases

So when the spanner’s handle is long

A tight knot can easily be opened by less effrot

I hope it helped

The type of remote sensing which penetrates clouds at night for accurate terrain representation is ___.a. sonarb. thermal infraredc. passive microwaved. Landsate. radar

Answers

The type of remote sensing which penetrates clouds at night for accurate terrain representation is radar.

Radar uses radio waves to detect objects and their properties, and can penetrate clouds and other obstacles that might obscure the view.

By bouncing radio waves off of the surface and measuring the time it takes for them to return, radar can create accurate representations of terrain and objects, including those hidden from view by clouds or darkness.

This makes radar an invaluable tool for a wide range of applications, including military, meteorological, and scientific uses.

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A website is having a sale, and all items are 25% off the original price, p
Which expressions can be used to find the price of an item after the discount?
Select all that apply
Α.
0.75
B
1.25
CP_25
DP - 0.25
E 001P x 75

Answers

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Write a set of turtle instructions to draw an AND gate.

Answers

The turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.

To draw an AND gate using turtle graphics, you can use the following set of instructions:

Set up the turtle:

a. Set the turtle's initial position.

b. Set the turtle's pen color and size.

Draw the first input line:

a. Move the turtle forward to the starting point of the line.

b. Draw a straight line segment to represent the first input.

Draw the second input line:

a. Move the turtle to the starting point of the second line.

b. Draw a straight line segment to represent the second input.

Draw the output line:

a. Move the turtle to the starting point of the output line.

b. Draw a straight line segment to represent the output.

Draw the logic gate shape:

a. Move the turtle to the starting point of the gate.

b. Draw a rectangle to represent the gate.

c. Add any necessary labels or symbols to indicate it as an AND gate.

Add connections between lines and gate:

a. Move the turtle to the intersection point of the first input line and the gate.

b. Draw a small line segment to connect the input line to the gate.

c. Repeat the above step for the second input line and the gate.

d. Draw a small line segment to connect the output line to the gate.

Repeat the above steps as necessary to draw multiple AND gates or any additional components.

Remember to adjust the turtle's position and direction appropriately after each instruction to ensure accurate drawing. You can also customize the colors, sizes, and shapes to enhance the visual appearance of the AND gate.

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A conductor carries a current of 10A at right-angles to a magnetic field having a flux density of 500mT. If the length of the conductor in the field is 20 cm, the force on the conductor is: Select one: oa 1 N ob. 100 KN O € 100 N o d. 10 kN

Answers

The force on the conductor is 1 Newton.

The force on a conductor carrying a current and placed in a magnetic field can be calculated using the formula F = BIL, where F is the force, B is the magnetic flux density, I is the current, and L is the length of the conductor in the field.

In this case, the current is 10A, the flux density is 500mT (or 0.5T), and the length of the conductor is 20 cm (or 0.2m). Let's calculate the force.

Using the formula F = BIL, we substitute the given values:

F = (0.5T) * (10A) * (0.2m)

Calculating this expression, we find:

F = 1N

Therefore, the force on the conductor is 1 Newton.

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a stone is dropped from the top of a tower 400 m high and at the same time another stone is projected upward vertically from the ground with a velocity of 100 m/s. find where and when the two stones will meet.

Answers

Answer:The stones will be at the same height of 62.59 feets 4.4 seconds later.

Explanation:

Pls help me ill give brainliest

Pls help me ill give brainliest

Answers

Answer:

c

Explanation:

a, b, and d are examples of moving forward

while c is moving backwards.

I’m pretty sure that your answer is C

a quadruple axel (in figure skating) involves how much angulardisplacement?

Answers

A quadruple axel in figure skating involves 4.5 revolutions, which corresponds to 1440 degrees of angular displacement.

In figure skating, an axel jump is a jump that takes off from a forward outside edge and lands on the backward outside edge of the opposite foot. A quadruple axel, also known as a "quad axel," is an incredibly difficult and highly advanced jump performed by only a few skaters. It involves four and a half rotations in the air. Each full rotation in figure skating corresponds to 360 degrees of angular displacement. Therefore, a quadruple axel, with four and a half rotations, involves an angular displacement of 4.5 x 360 = 1440 degrees.

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An astronaut of mass 70 kg weighs 700 n on earth's surface. his weight on the surface of mars, where the acceleration due to gravity is 3.7 m/s2, would be about?

Answers

The astronaut's weight on the surface of Mars is 259 N

To solve this exercise, the formula and procedure to be applied is:

W = m * g

Where:

W = weightm = massg = gravity

Information about the problem:

g= 3.7 m/s2m = 70 kgW=?1 N = kg * m/s²

Applying the weight formula, we get:

W = m * g

W = 70 kg * 3.7 m/s2

W = 259 N

What is gravity?

In physics, gravity is the force of attraction that the earth exerts on all bodies possessing mass by pulling them toward its center.

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An astronaut of mass 70 kg weighs 700 n on earth's surface. his weight on the surface of mars, where

Hello! I am taking physics H on edge 2021 and if someone could give me the completed Electromagnetic Fields Plan an Investigation student guide/lab report I would be eternally grateful!!!

Answers

To create an electromagnetic field, a magnetic and electric field is involved.

An Electromagnetic field plan

Electromagnetic field consists of both electric and magnetic fields which are produced by human activities through the use of electricity.

With the above definition of electromagnetic field, it's production will involve:

Magnetic field: These fields are created by the magnets.

Electric field: These fields are created by electric charges.

These fields oscillate in perpendicular planes with respect to each other, and are in phase.

Therefore, to create an electromagnetic field, a magnetic and electric field is involved.

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Answer:

I need this as well

Explanation:

If the poster got the project, please let me know. I'm struggling on this unit and if you don't want to give out the project, help is appreciated too! thanks

Roshan makes the table below to describe how to draw a ray diagram for a convex lens.

A 2-column table with 3 rows. The first column labeled Ray from Object to Lens has entries draw through the focal point on the same side of the lens as the object, draw parallel with the main axis, draw to the center of the lens. The second column labeled After passing through the lens has entries the ray goes parallel to the main axis, the ray goes away from the main axis as though it came from the focal point near the object, the ray goes straight through and does not bend.

What error did Roshan make?

The ray that goes through the center should bend and go through the focal point on the other side.
The ray that starts out parallel with the main axis should bend toward the axis and go through the focal point on the other side.
The ray that goes parallel to the main axis after passing through the lens should also be parallel from the object to the lens.
The rays in the table describe how rays are drawn for a concave lens rather than for a convex lens.
Mark this and return

Answers

Roshan made an error in the second column of the table, because the ray goes away from the main axis as though it came from the focal point near the object is wrong.

What error did Roshan make?

The error Roshan made is analyzed as follows;

The entry "the ray goes away from the main axis as though it came from the focal point near the object" should be "the ray goes through the focal point on the other side".

This is because for a convex lens, a ray that starts out parallel with the main axis should bend toward the axis and go through the focal point on the other side.

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a sample o aluminum is put in 10.5 mL of water. if the water rises to 13.5 mL when the aluminum is added, what is the density of the aluminum if it has a mass of 8.1 g

Answers

Answer:

The answer is 2.7 g/mL

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\ \)

volume = final volume of water - initial volume of water

volume = 13.5 - 10.5 = 3 mL

From the question we have

\(density = \frac{8.1}{3} \\ \)

We have the final answer as

2.7 g/mL

Hope this helps you

Use the inteediate value theorem to prove the following claim. There is at least one number that is three greater than twice its fifth power. (Remember, whenever you apply a theorem, you must explain why its hypotheses are satisfied; it is not sufficient to merely assert that they are satisfied.)

Answers

The claim that there is at least one number that is three greater than twice its fifth power can be proven using the Intermediate Value Theorem.

To apply the Intermediate Value Theorem, we need to show that the function f(x) = \(2x^5\)+ 3 is continuous on a closed interval [a, b] and takes on both positive and negative values.

1. Continuity:

The function f(x) = \(2x^5\) + 3 is a polynomial function, and polynomial functions are continuous for all real numbers. Therefore, f(x) is continuous on the entire real number line.

2. Positive and Negative Values:

To show that f(x) takes on both positive and negative values, we can consider the limits of f(x) as x approaches positive and negative infinity:

- As x approaches positive infinity, the term \(2x^5\) dominates the function, and f(x) approaches positive infinity.

- As x approaches negative infinity, the term \(2x^5\) dominates the function, and f(x) approaches negative infinity.

Since f(x) approaches both positive and negative infinity as x approaches infinity and negative infinity respectively, it must take on all values in between, including positive and negative values.

By the Intermediate Value Theorem, since f(x) is continuous on the real number line and takes on both positive and negative values, there must exist at least one number c for which f(c) = 0. In other words, there is at least one number that is three greater than twice its fifth power.

In conclusion, by satisfying the hypotheses of the Intermediate Value Theorem, we can prove the claim that there is at least one number that is three greater than twice its fifth power.

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A pitcher throws a curveball that reaches the catcher in 0.60s. Theball curves because it is spinning at an average angular velocityof 330 rev/min (assumed constant) on its way to the catcher's mitt.What is the angular displacement of the baseball ( in radians ) asit travels from the pitcher to the catcher?

Answers

The angular displacement of the baseball as it travels from the pitcher to the catcher is 13.2π radians.

To determine the angular displacement of the curveball as it travels from the pitcher to the catcher, we need to consider the given angular velocity and time.

1. First, we need to convert the angular velocity from revolutions per minute (rev/min) to radians per second (rad/s):
Angular velocity (ω) = 330 rev/min ×(2π rad/rev) × (1 min/60 s) = 22π rad/s

2. Now, we can find the angular displacement (θ) using the formula:
θ = ω × t
where t is the time it takes for the ball to reach the catcher.

3. Plug in the given values:
θ = (22π rad/s) × (0.60 s) = 13.2π rad

The angular displacement of the baseball as it travels from the pitcher to the catcher is 13.2π radians.

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A mouse eats 20 kJ of energy. The mouse uses 8 kJ of energy moving around. What would most of the leftover energy be turned into? ant is the leftover energy useful or wasted?

Answers

Answer:

to be turned into glycogen not wasted

Explanation:

Since the body has a lot of energy left it will turn that energy into glycogen which is a storage form of glucose which will when neccassary will be converted into glucose from the horomone glucagon and be given to the body to be used as energy so the energy is never wasted

The speed of sound in a particular gas is 675 m/s. A sound wave propagating in this material has a wavelength offifteen meters. What is the frequency of this sound?knowns and unknownsolveright answer

Answers

Given, Speed of the sound, v=675 m/s

The wavelength of the wave, λ=15 m

Relation between speed, wavelength, and frequency of a wave is given by

\(v=f\lambda\)

Where f is the frequency of the sound.

On substituting the known values,

\(675=f\times15\)

Which gives us,

\(f=\frac{675}{15}=45\text{ Hz}\)

Therefore the frequency of the sound in the given medium is 45 Hz.

Help please!!!

Do you think we always see the same side of the Moon?

Answers

Answer:

yess

Explanation:

"The Moon orbits Earth once every 27.3 days and spins on its axis once every 27.3 days. This means that although the Moon is rotating, it always keeps one face toward us. Known as “synchronous rotation,” this is why we only ever see the Moon's nearside from Earth."

A 20 cm square frame that can rotate about the 00' axis is placed in a homogeneous magnetic field with 0.5T induction directed vertically downwards.
a) Draw vectors of forces acting on the sides of the frame.
b) calculate the values of these forces and the resultant force acting on the frame.
c) calculate the torque of the frame.

Answers

The solution to this task is f00king Dis.

9. CALCULATE: How much more power is used to move a weight of 500 N a distance of 20 m in 5 s than is used to move a weight of 1,000 N a distance of 30 m in 30 sec?​

Answers

Answer:

work = 500*3 = 1500 J

1500J in 5 sec = 300 watts

Explanation:

Answer:

it is using the same power

Explanation:

it is using the same power because it has to move longer and a farther distance while the other one has double the power but less the distance

The diameter of a copper wire is thought to be approximately 0.3mm. Which instrument should be used to obtain a more accurate measurement of the diameter of the wire? A measuring tape B metre rule C micrometer D ruler 2

Answers

Answer:

C

Explanation:

The correct answer should be the micrometer.

The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.

In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.

The correct option is C.

Stan walks 10km west to the grocery store. He shops then walks back 10 km east back to his house. What distance did he cover? What was his displacement?

Answers

Stan’s displaceent is 0 km because he ends his walk where he started.

which fbd would most likely represent a car driving on a level surface with a constant velocity

Answers

Thus,  the FBD that most likely represents a car driving on a level surface with a constant velocity would show the force of gravity and normal force acting in opposite directions and balanced out vertically. Additionally, the force of friction would act opposite to the direction of motion and balance out the horizontal forces.

When a car is driving on a level surface with a constant velocity, the most likely Free Body Diagram (FBD) that would represent it is one where the force of gravity acts vertically downwards while the normal force acts upwards perpendicular to the level surface.

Since the car is driving at a constant velocity, there is no net force acting on it. This means that the forces acting in the horizontal direction must be balanced. This can be represented by a force of friction acting opposite to the direction of motion. The magnitude of this force of friction must be equal to the driving force of the car.The FBD would show that the force of gravity is equal in magnitude and opposite in direction to the normal force acting on the car. These two forces will balance each other out in the vertical direction. Meanwhile, the force of friction will be acting on the car in the opposite direction to the driving force. This will balance out the forces in the horizontal direction and allow the car to maintain its constant velocity.

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Is there any formula to calculate the height a ball will reach depending on the bounce number and it’s initial height? Alternatively, can any formula calculate the amount of times a ball will bounce without going into infinity?

Answers

Answer:

yeas

Explanation:

beac×high ×sides and after you fins tims you need to add beac+high and add the sides together and add what did you got from beac,high and sides and thin you will add every thing together

A 2.72 A current flows through a wire for
9.88 s. How much charge flows past a point
in the wire in that time?

Answers

Current=2.72A=ITime=t=9.88sCharge=Q

\(\\ \rm\longmapsto I=\dfrac{Q}{t}\)

\(\\ \rm\longmapsto Q=It\)

\(\\ \rm\longmapsto Q=2.72\times 9.88\)

\(\\ \rm\longmapsto Q=26.87C\)

The amount of charge that flows past a point in the wire during that time is approximately 26.8976 Coulombs.

Electric charge is quantized, meaning it exists in discrete amounts and is measured in coulombs (C). The elementary charge, represented by the symbol "e," is the charge of a single proton or electron, approximately equal to 1.602 x 10^-19 coulombs. Protons carry a positive charge, while electrons carry an equal but opposite negative charge.

When electric charges are stationary, they create an electric field around them. When charges are in motion, they produce a magnetic field in addition to the electric field, leading to electromagnetic effects.

Charge is a fundamental property of matter that determines its interaction with electric and magnetic fields and is crucial to understanding and explaining various electrical and electromagnetic phenomena in the natural world.

To calculate the amount of charge that flows past a point in the wire use the equation:

Q = I * t

Where:

Q is the charge (in Coulombs)

I is the current (in Amperes)

t is the time (in seconds)

Given:

Current (I) = 2.72 A

Time (t) = 9.88 s

Substitute these values into the equation to find the charge:

Q = I t

Q = 2.72 A * 9.88 s

Calculating the product:

Q = 26.8976 C

Therefore, the amount of charge that flows past a point in the wire during that time is approximately 26.8976 Coulombs.

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The width of a rail is 15 cm. The dimensions of a railway sleeper are 2.5m x 25 cm. If 1600
evenly spaced sleepers are placed for every kilometer of rail, by what factor is the pressure
exerted by the trains on the ground lessened?

Answers

The pressure put on the ground by trains has decreased by a ratio of 62.5.

The sleeper spacing formula, what is it?

The n + x is used to represent sleeper density. The number of sleepers needed for one rail length is shown by the symbol n + x in this case. A rail's length is given by n. The necessary number of sleepers is 17 13 multiplied by 1000, which comes to 1307.69 x 1308 Numbers.

It is the quantity of sleepers necessary to support a rail-length of railroad track. Its formula is (n + x), where n is the length of a rail in meters and x is a constant with a range of 3 to 6 (the length of a rail for broad gauge (B.G.) track is 13 meters, while that for meter gauge (M.G.) track is 12 meters).

2.5 * 25 = 62.5.

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A small rock bounces off the windshield of a moving car and experiences a large change in velocity. How does the car's momentum
change?

Answers

The car will slow down. If the rock is big enough and moving fast enough, the kinetic energy from the rock will transfer to the car. And because of that, the car will slow down (and the windshield will most likely shatter)

the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?

Answers

Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

1. In order for an object to begin to move, stop moving, or change direction, which of the following
must be present?

Answers

Answer:

Friction, Power or an External or Internal force

Explanation:

a car travels in a circle with constant speed. the net force on the car is

Answers

The net force on the car is zero because the car is not accelerating

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