Answer:
First) X-ray
Second) I think sound waves
Explanation:
Jason hits a volleyball so that it moves with an initial velocity of 6.0 m/s
straight upward. If the volleyball starts from 2.0 m above the floor,
how long will it be in the air before it strikes the floor?
Answer:
Approximately \(1.5\; {\rm s}\).
(Assumptions: \(g = 9.81\; {\rm m\cdot s^{-2}}\); air resistance on the volleyball is negligible.)
Explanation:
Under the assumptions, acceleration of the volleyball would be \(a = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}\) during the entire flight. (This value is negative since the ball is accelerating downwards- toward the ground.)
By the time the volleyball hits the ground, the volleyball would be at a position \(2.0\; {\rm m}\) below where it was launched. In other words, the (vertical) displacement of the volleyball during the entire flight would be \(x = (-2.0)\; {\rm m}\). (Negative since the ball is below where it was launched.)
Apply the SUVAT equation \((v^{2} - u^{2}) = 2\, a\, x\) to find the velocity of the volleyball right before hitting the ground. In this equation:
\(v\) is the velocity of the volleyball right before hitting the ground,\(u = 6.0\; {\rm m\cdot s^{-1}}\) is the initial velocity of the volleyball,\(a = (-9.81)\; {\rm m\cdot s^{-2}}\) is the acceleration of the volleyball, and\(x = (-2.0)\; {\rm m\cdot s^{-1}}\) is the displacement of the volleyball during the flight.Rearrange this equation and solve for the velocity right before landing, \(v\). Note that because \(v\!\) is raised to the power of \(2\) in \((v^{2} - u^{2}) = 2\, a\, x\), both \(v = \sqrt{u^{2} + 2\, a\, x}\) and \(v = -\sqrt{u^{2} + 2\, a\, x}\) could satisfy this equation. However, \(v\!\!\) needs to be negative since the volleyball would be travelling downwards before reaching the ground.
Therefore, right before reaching the ground, velocity of the volleyball would be:
\(\begin{aligned} v &= -\sqrt{u^{2} + 2\, a\, x \\ &= -\sqrt{(6.0)^{2} + 2\, (-9.81)\, (-2.0)} \; {\rm m\cdot s^{-1}} \\ &\approx (-8.67)\; {\rm m\cdot s^{-1}}\end{aligned}\).
In other words, velocity of this volleyball has changed from \(u = 6.0\; {\rm m\cdot s^{-1}}\) (upwards) to \(v \approx (-8.67)\; {\rm m\cdot s^{-1}}\) (downwards) during this flight. Divide the change in the velocity \((v - u)\) by the rate of change in velocity \(a = (-9.81)\; {\rm m \cdot s^{-2}}\) to find the duration of this flight:
\(\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{(-8.67) - 6.0}{(-9.81)}\; {\rm s} \\ &\approx 1.5\; {\rm s}\end{aligned}\).
Someone give me 3 paragraphs why professional athletes are getting paid too much (language arts)
Answer: some may argue that while teacher’s only provide service to a single classroom, superstar athletes are entertaining fans all around the world, enticing people with a feeling of relaxation and excitement. Obviously, what these individuals must not be aware of is the most important man in our nation, the president, who makes critical decisions that affect the entire world every day, only makes $400,000 a year. While President Obama is hard at work reviving the economy, the unproven rookie in the MLB is earning way over that figure. Furthermore, police officers, firefighters, and doctors save lives while risking their own for a fraction of what sports stars make. People in the military leave their families at home to defend and protect the country knowing they may never return. It's truly a pity that none of these true heroes are given the same recognition by society as athletes such as Brett Favre or Michael Jordan are given. While I do understand that making it into the pros is not an easy thing to do, and that it takes a tremendous number of hours of hard work and dedication every day to earn a job in professional sports, these people do nothing more than entertain the general public.
Explanation:
Answer:
Wouldn't it be great to make nearly $111 million a year simply to play a game? Tiger Woods, along with many other professional athletes, certainly think so. But do these athletes really deserve all that money?
In my mind, absolutely not. Professional athletes are making too much money in a society where salaries and wages are traditionally based on the value of one's work. In today's society, one should be paid according to the job’s economic importance and their value to society.
Teaching is one of the most economically important occupations because our future economy relies on the education of its youth, yet teachers are paid astronomically less than the average professional athlete is. In fact, each basket Kobe Bryant scores earns him equivalent to the average classroom teacher’s yearly salary.
However, some may argue that while teacher’s only provide service to a single classroom, superstar athletes are entertaining fans all around the world, enticing people with a feeling of relaxation and excitement.
Obviously, what these individuals must not be aware of is the most important man in our nation, the president, who makes critical decisions that affect the entire world every day, only makes $400,000 a year. While President Obama is hard at work reviving the economy, the unproven rookie in the MLB is earning way over that figure.
Furthermore, police officers, firefighters, and doctors save lives while risking their own for a fraction of what sports stars make. People in the military leave their families at home to defend and protect the country knowing they may never return. It's truly a pity that none of these true heroes are given the same recognition by society as athletes such as Brett Favre or Michael Jordan are given.
While I do understand that making it into the pros is not an easy thing to do, and that it takes a tremendous number of hours of hard work and dedication every day to earn a job in professional sports, these people do nothing more than entertain the general public.
Moreover, in my mind, if these athletes want to continue to be rewarded with the fame and fortune that is unfairly bestowed upon them, they must prove to the world that they are going to be positive role models for future athletes, and those who admire them.
Explanation:
found if off some website lol hope it helps! <3
What information about an axon is required to calculate the current associated with an NCV pulse?A. Conductivity, resistivity, and lengthB. Potential, conductivity, and radiusC. Potential, resistivity, and radiusD. Potential, resistance per unit length, and length
An axon requires three pieces of information to calculate the current associated with an NCV pulse: potential, resistance per unit length, and length. So, the correct answer is option D.
Potential is the difference in voltage between two places, while resistance per unit length is the amount of resistance present along an axon's length.
The voltage difference is multiplied by the axon resistance to determine the current. By dividing the resistance per unit length by the axon's length, the resistance of the axon is determined.
We can determine the current associated with an NCV pulse by knowing the potential, resistance per unit length, and length of an axon.
Complete Question:
What information about an axon is required to calculate the current associated with an NCV pulse?
A. Conductivity, resistivity, and length
B. Potential, conductivity, and radius
C. Potential, resistivity, and radius
D. Potential, resistance per unit length, and length
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differentiate between the properties and examples of conductors and insulators
Conductors are materials that allow electrical charges to flow through them easily, such as metals, while insulators are materials that resist the flow of electrical charges and do not conduct electricity, such as rubber or plastic.
Conductors and insulators are two types of materials with very different electrical properties. Conductors allow electricity to flow freely through them, while insulators prevent the flow of electricity. Conductors have a low resistance to electrical flow, while insulators have a high resistance.
Examples of conductors include metals like copper and aluminum, as well as water and human tissue. Examples of insulators include rubber, plastic, glass, and air. Conductors are commonly used in electrical wiring and circuits, while insulators are used to protect people and equipment from electric shocks and to prevent electrical interference.
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Solue the Selmultaneous equations:
3y +2x =5 and y-5x = 13
Answer:
x=-2 and y=3
Explanation:
Isolate y and then x to get: y=13+5(-2)
Simplify to get y=3 then plug it back in to get x=-2
We can check, 9+ (-4)=5 hope this helps
4. Describe how the density of an object less dense than water can be determined using Archimedes' principle.
An object less dense than water will float, and the amount of water displaced will equal its volume and mass.
Archimedes' principle states that the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object.
Therefore, if an object is less dense than water, it will float, and the amount of water displaced will equal its volume and mass.
To determine the density of the object, the volume of water displaced is measured and the mass of the object is divided by this volume.
This will give the density of the object in comparison to the density of water.
This principle is used in many applications, such as in the design of ships and submarines, as well as in determining the purity of precious metals.
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The decibel level of a sound is given by the equation where I is the sound's intensity and corresponds to the intensity of the weakest sound that can be detected by the human ear. A sound of 140 decibels produces pain in the average human ear. Approximately how many times greater than must the intensity I of a sound be to reach this decibel level?
The decibel level (dB) of a sound is given by the equation dB = 10 * log10(I/I0), where I is the sound's intensity, and I0 corresponds to the intensity of the weakest sound that can be detected by the human ear. A sound of 140 decibels produces pain in the average human ear.
To find out how many times greater the intensity I of a sound must be to reach a decibel level of 140, follow these steps:
1. Set the decibel level to 140 in the equation: 140 = 10 * log10(I/I0).
2. Divide both sides by 10: 14 = log10(I/I0).
3. Apply the antilog (10^x) to both sides: 10^14 = I/I0.
4. Rearrange the equation to find I: I = 10^14 * I0.
The intensity I of a sound must be 10^14 times greater than I0, the intensity of the weakest sound detectable by the human ear, to reach a decibel level of 140.
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What is the latent heat of vaporization for water
When a material in liquid state is given energy, it changes its phase from liquid to vapor; the energy absorbed in this process is called heat of vaporization. The heat of vaporization of water is about 2,260 kJ/kg, which is equal to 40.8 kJ/mol. The vaporization is the opposite process of condensation.
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Easy Guided Online Tutorial A special electronic sensor is embedded in the seat of a car that takes riders around a circular loop-the-loop ride at an amusement park. The sensor measures the magnitude of the normal force that the seat exerts on a rider. The loop-the-loop ride is in the vertical plane and its radius is 21 m. Sitting on the seat before the ride starts, a rider is level and stationary, and the electronic sensor reads 770 N. At the top of the loop, the rider is upside down and moving, and the sensor reads 350 N. What is the speed of the rider at the top of the loop?
Answer:
v = 17.30 m / s
Explanation:
For this exercise we will use Newton's second law
at the bottom of the loop and stopped
∑ F = 0
N-W = 0
N = W
W = 770 N
the mass of the body is
W = mg
m = W / g
m = 770 / 9.8
m = 78.6 kg
on top of the loop and moving
∑ F = m a
N + W = m a
note that the three vectors go in the same vertical direction down
the centripetal acceleration is
a = v² / r
we substitute
N + W = m v² / r
v = \(\sqrt{(N+W) \frac{r}{m} }\)
let's calculate
v = \(\sqrt{ (350+770) \frac{21}{78.6} }\)
v = 17.30 m / s
The __________ is located under the forebrain and midbrain. A. forebrain B. midbrain C. hindbrain D. brainstem
Answer is the hind brain
The brainstem is located under the forebrain and midbrain. Therefore option D is correct.
The brainstem is located under both the forebrain and midbrain. It is a vital component of the central nervous system that connects the brain to the spinal cord and controls many essential functions such as breathing, heart rate, and digestion.
It consists of three main regions: the medulla oblongata, pons, and midbrain. The forebrain, midbrain, and hindbrain together constitute the major divisions of the brain.
The hindbrain is positioned below the midbrain and includes structures like the cerebellum, pons, and medulla oblongata.
The brainstem, specifically its lower regions, is responsible for relaying information between the brain and the rest of the body while regulating critical bodily functions.
Therefore option D is correct.
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a metal block measures 10cm×2cm×2cm. What is its volume? How many blocks each 2cm×2cm×2cm have the same total volume?
40cm³ is volume of a metal block measures 10cm×2cm×2cm and 5 blocks have the same total volume.
volume=l×b×h
volume=10cm×2cm×2cm= 40cm³
volume=l×b×h
volume= 2cm×2cm×2cm=8cm³
blocks have the same total volume= 40cm³/8cm³= 5
The space occupied inside an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity. Finding an object's volume can help us calculate the quantity needed to fill it, such as the volume of water needed to fill a bottle, aquarium, or water tank.
A sphere is the most basic and typical form of a three-dimensional shape. We see spheres on a regular basis in the form of balls, globes, ornamental lights, oranges, etc.
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A 100 kg ball is pushed up a 50 m ramp to a height of 10 m. How much force must be exerted to push the ball up the ramp
Therefore, a force of 196.2 N must be exerted to push the 100 kg ball up the 50 m ramp to a height of 10 m.
To determine the force needed to push the ball up the ramp, we need to consider the work-energy principle. The work done by the force pushing the ball up the ramp must be equal to the change in the ball's potential energy.
The potential energy gained by the ball is given by:
ΔPE = mgh
here m is the mass of the ball, g is the acceleration due to gravity, and h is the height gained by the ball.
ΔPE = (100 kg)(9.81 m/s^2)(10 m - 0 m) = 9810 J
The work done by the force pushing the ball up the ramp is given by:
W = Fd
here F is the force exerted on the ball, and d is the distance over which the force is applied (in this case, the length of the ramp, 50 m).
The force required to push the ball up the ramp is then:
F = W/d = ΔPE/d = (9810 J)/(50 m) = 196.2 N
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A force of 196.2 N must be exerted to push the 100 kg ball up the 50 m ramp to a height of 10 m.
To calculate the force needed to push a 100 kg ball up a 50 m ramp to a height of 10 m, we will use the concept of work-energy theorem and the equation for work done against gravity. The work-energy theorem states that the work done on an object is equal to the change in its potential energy.
First, let's determine the change in potential energy (ΔPE). The potential energy is given by the equation
PE = m * g * h
where m is the mass, g is the gravitational acceleration (9.81 m/s²), and h is the height.
In this case,
m = 100 kg and h = 10 m.
Thus,
ΔPE = 100 kg * 9.81 m/s² * 10 m
= 9810 J (Joules).
Now, let's calculate the work done (W) to push the ball up the ramp. Work is defined as the force (F) applied to an object multiplied by the distance (d) over which the force is applied. In this case, the distance is the length of the ramp (50 m).
The equation for work is
W = F * d.
Since the work done equals the change in potential energy, we can write the equation as
9810 J = F * 50 m.
To solve for the force (F), we can divide both sides of the equation by 50 m:
F = 9810 J / 50 m
= 196.2 N (Newtons).
Therefore, a force of 196.2 N must be exerted to push the 100 kg ball up the 50 m ramp to a height of 10 m.
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Determine the resultant moment of the forces acting about the x, y, and z axes. Suppose that f1 = 200 n, f2 = 60 n, f3 = 115 n, and f4 = 300 n. (figure 1).
Based on the forces acting on the axes, the resultant moments will be (345, 400, 600 N·m)
What would be resultant moment about x-axis?= F₃ x 3
= -115 x 3
= -345 N·m
What would be resultant moment about y-axis?= F₁ x 2
= -200 x 2
= -400 N·m
What would be the resultant moment about z-axis?= F₄ x 2
= -300 x 2
= - 600 N·m
In conclusion, the resultant moment about x, y, and z axes is (345, 400, 600 N·m)
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A hover board is moving at 6 m/s . If it slows down at a rate of -3 m/s per second, how long is the board in the air before coming to rest? Round to 4 decimal places if necessary
Explanation
a uniformly accelerated motion is the one in which the acceleration of the particle throughout the motion is uniform,to fidn the time take we can use the formula:
\(\begin{gathered} t=\frac{v_f-v_1}{a} \\ where \\ v_f\text{ is the final velocity} \\ v_{i\text{ }}\text{ is the initail velocity} \\ a\text{ is the acceleration, so} \end{gathered}\)Step 1
a)Let
\(\begin{gathered} v_i=6\text{ }\frac{m}{s} \\ v_f=0(\text{ rest\rparen} \\ a=-3\frac{m}{s^2} \end{gathered}\)b) now, replace
\(\begin{gathered} t=\frac{v_{f}-v_{1}}{a} \\ t=\frac{0-(-6\frac{m}{s})}{3\frac{m}{s}} \\ t=2\text{ seconds} \end{gathered}\)therefore, the answer is 2 seconds
I
which type of radioactivity has a negative charge?
a. alpharays
b. x-rays
c. beta rays
d.gamma rays
The type of radioactivity that has a negative charge is beta rays.
Are alpha rays negatively charged?Alpha rays consist of particles which have two protons and two neutrons identical to a positively charged helium nucleus. They get attracted towards the negatively charged plate as they possess a charge of +2. They have very high ionization power.
Why beta rays are negatively charged?
Beta radiation has a negative charge because it contains particles similar to an electron. It contains the same mass as an electron, and the mass is lower than proton and neutron masses. Also, each particle contains a single negative charge, making the radiation negatively charged.
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Which statement describes a surface wave?
A surface wave is a type of electromagnetic wave.
Hello o/
A surface wave is a wave that moves along the interface of two different materials, like air and water.
A surface wave is a wave that travels through space.
Answer: A surface wave is a wave that moves along the interface of two different materials, like air and water.
A 7.0 kg cannonball flying rightward at 12 hits a stationary rock. The cannonball keeps moving in the same
S
m
m
direction at 2.0 after the collision but sends the rock flying at 14 towards right
S
S
What is the mass of the rock?
Answer:
5.0 kg
Explanation:
use the equation; (m1v1i) + (m2v2i) = (m1v1f) + (m2v2f)
lab during a -84 kPa, the 5.9. Assume the following information was obtained in cavitation test on an orifice: C,-0.10, P" = 620 kPa, Pug v, =2.69 m/s. Calculate σ (Eq 5.1). Answer: σ=0.97
To calculate the value of σ using Equation 5.1, we need the following information:
C: Cavitation coefficient
P" (P double prime): Pressure at the vena contracta (location of lowest pressure in the orifice)
Pug: Upstream gauge pressure
v: Velocity of the fluid at the vena contracta
Given:
C = -0.10
P" = 620 kPa
Pug = -84 kPa (negative sign indicates it's below atmospheric pressure)
v = 2.69 m/s
The equation for σ is as follows:
σ = (P" - Pug) / (0.5 * ρ * v^2)
Where:
ρ is the density of the fluid.
Now, we need the density of the fluid to complete the calculation. Since the density is not provided in the information given, I am unable to calculate the value of σ accurately. Please provide the density of the fluid, and I will be able to calculate σ for you.
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Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)
The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
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What happens when a proton is placed directly in the path of the proton cannon?
Answer:
Proton is positively charged and is thus, attracted to the negative plate. Hence, it will take the path D after leaving the region between the charged plates.When a proton is placed directly in the path of the proton cannon, it will experience a strong electromagnetic force. The proton cannon emits a beam of protons at high energy and velocity. When the proton in the path of the cannon interacts with the beam, there will be a collision between the two protons.
During the collision, the protons may undergo a process called scattering, where they change direction and momentum. The exact outcome of the collision depends on the energy and angle of the incoming proton, as well as the properties of the target proton. It is possible that the protons may scatter off each other, transferring energy and momentum in the process.
In some cases, the collision may result in the absorption of the incoming proton by the target proton. This can lead to the formation of a more massive particle or the emission of other particles. The specifics of the interaction will depend on the energy and conditions of the proton cannon and the characteristics of the protons involved.
Overall, placing a proton directly in the path of a proton cannon will result in a collision and potential scattering or absorption of the protons, causing changes in their momentum and possibly leading to the creation of other particles.
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A lunar eclipse occurs when _______ shadow falls on _______.a. Earth's; the Moonb. the Moon's; Earthc. the Sun's; the Moond. the Sun's; Earth
A lunar eclipse occurs when earth's shadow fall on moon.
A lunar eclipse occurs when the Moon passes through the Earth's shadow. During a lunar eclipse, the Sun, Earth, and Moon are aligned such that the Earth is positioned between the Sun and the Moon. The Earth's shadow falls on the Moon, causing it to become partially or fully darkened. The type of lunar eclipse depends on how much of the Moon is obscured by the Earth's shadow, with a total lunar eclipse occurring when the Moon is completely surrounded by the Earth's shadow. Lunar eclipses are relatively common, with a few occurring each year, and are visible from a large portion of the Earth's surface. They are a popular event for astronomers and stargazers, providing a unique opportunity to observe the Moon in a different light.To know more about eclipse visit:
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Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?
The speed of the moving train is approximately 33.5 m/s.
The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:
\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)
where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.
We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.
Solving for \(v_s\), we get:
\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)
\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s
\(v_s\) = 33.5 m/s
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What is the minimum diameter of a steel wire if it is to support a mass of 80 kg?
The minimum diameter of a steel wire if it is to support a mass of 80 kg is 1.41 * 10⁻³ m.
What will be the minimum diameter of a steel wire if it is to support a mass of 80 kg?The minimum diameter, d of the steel wire can be calculated thus:
Stress, α = Force/areaα = 5.0 × 10⁸ Pa.
mass, m = 80 kg
Force = 80 * 98 = 784 N
Area = force/α
area = 784/5.0 × 10⁸
area = 1.57 * 10⁻⁶
Area = πd²/4
d = √(4 * area/π)
d = √(4 * 1.57 * 10⁻⁶ * 7/22)
diameter = 1.41 * 10⁻³ m
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Note that the complete question is given below:
What is the minimum diameter of a steel wire if it is to support a mass of 80 kg? The elastic limit of steel is 5.0 × 10⁸ Pa.
If a rock traveling at 1.4 m/s has a kinetic energy of 12 J, what is its mass
Answer:
Mass of the rock is 12.25kg
Explanation:
Kinetic energy can be defined as the energy possessed by an object as a result of its motion. Simply stated, it is the energy due to motion.
Mathematically, it is given by;
\(K = \frac{1}{2}mv^{2}\)
Given the following data;
Velocity, V = 1.4m/s
Kinetic energy, K = 12J
Mass, m = ?
The formula for calculating the kinetic energy of an object is;
\(K = \frac{1}{2}mv^{2}\)
Substituting into the equation, we have;
12 = ½*m*(1.4)²
We cross-multiply;
24 = 1. 96m
m = 24/1.96
m = 12.25kg.
Hence, the mass of the rock is 12.25kg.
A block of wood has density 0.500 g/cm3 and mass 2 000 g. It floats in a container of oil (the oil's density is 0.750 g/cm3). What volume of oil does the wood displace
Answer:
2,666.67cm^3
Explanation:
All we need to do in this problem is divide the mass of the wooden block to the oil's density.
2000/0.750 ≈ 2,666.67cm^3
Best of Luck!
A car tart from ret and travel for 3. 4 with a uniform acceleration for 17. 0 m/. What i the final velocity of the car?
Final velocity = 57.8m/s
What is acceleration?
In mechanics, acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by the orientation of the net force acting on that object
Acceleration = (Initial velocity - Final velocity) /time
Given,
time = 3.4s
Acceleration = 17 m/s^2
17 = (0-v)/3.4
final velocity = 17 X 3.4 = 57.8 m/s
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Match each scenario to the form of energy it represents.
a man jogging in the park
a stove burner that's turned on
an apple on a tree
a fully charged camera battery
A. gravitational potential energy
B. motion energy
C. electric potential energy
D. radiant energy
Answer: and apple on the tree is gravitational and potential
fully charged camera battery is electric/ potential energy a man jogging is motion energy and a stove burner that is turned on is radiation energy
Explanation:
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PLEASE ANSWER AS FAST AS YOU CAN How would an observer on train A, which is moving close to the speed of light, view a clock in train B, which is stationary at the train station
A. the clock in train B appears to be the same width and to run at the same rate.
B. the clock in train B appears narrower and runs faster
C. the clock in train B appears narrower and runs more slowly
D. the clock in train B appears wider and runs more slowly
Answer:
If the trains are moving at the same speed, the answer is A.
The clock in train B appears to be the same width and to run at the same rate. Option A is correct.
It is given that an observer on train A, which is moving close to the speed of light, views a clock in train B, which is stationary at the train station.
It is required to find how an observer would observe a clock in train B.
What would an observer on train A, which is in motion, view a clock in train B?If a person is in a moving train, then his body is also in a state of motion with respect to the train at the same rate. When the observer observes any object that is at rest then it does not change the shape or size of an object. Also an object appears to run a=t the same rate due to the relative velocity attain by the observer's train.
Relative Motion is
Relative motion is the speed or the motion of an object with respect to the moving or the stationary object.
Thus the clock in train B appears to be the same width and to run at the same rate.
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A box is on the side of a hill inclined at 30°. The weight of the box is 40 pounds. What is the magnitude of the force required to keep the box from sliding down the hill?
We will have that the magnitude of the force required is:
\(F=(20kg\ast9.8m/s^2)sin(30)\Rightarrow F=98N\)So, it will need at least 98 N to keep it from moving downwards.
use your previous results to find an expression for the terminal speed. express your answer in terms of the variables b , rhor , rhom , and the constant g .
The expression for the terminal speed, \(V_{term\), can be given by:
\(V_{term\) = sqrt((2 * g * (rhor - rhom)) / (b * rhor))
The expression for the terminal speed (\(V_{term\)) can be derived by considering the forces acting on the object at terminal velocity.
At this point, the gravitational force (mg) and the drag force (F_drag) balance each other out.
The drag force is proportional to the velocity (v) of the object,
and its equation can be written as F_drag = -b * v, where b is the drag coefficient.
By equating the gravitational force and drag force,
we obtain b * \(V_{term\) = m * g.
Considering the object's mass (m) as the product of its density (ρ) and volume (V), and simplifying the equation,
we arrive at \(V_{term\) = sqrt((2 * g * (rhor - rhom)) / (b * rhor)),
where rhor is the density of the medium and rhom is the object's density.
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Terminal speed refers to the maximum velocity achieved by an object when the forces acting on it balance out. In this case, we can use the formula for terminal speed to find an expression in terms of the given variables.
The formula for terminal speed is: v = \(\sqrt{((2mg) / (rhor * A * C))}\), Where v is the terminal speed, m is the mass of the object, g is the acceleration due to gravity, rhor is the density of the surrounding medium, A is the cross-sectional area of the object, and C is the drag coefficient. In this case, we can assume that the object is a sphere with density rhom. Therefore, the mass of the object can be expressed as: m = (4/3) * pi * \(r^{3}\) * rhom. where r is the radius of the sphere. The cross-sectional area of the sphere can be expressed as: A = pi * \(r^{2}\). The drag coefficient can be expressed as: C = 6 * pi * b. where b is a constant that depends on the shape of the object and the properties of the surrounding medium. Substituting these expressions into the formula for terminal speed, we get: v = \(\sqrt{((8/3) * (rhom - rhor) * g * r^{3}) / b}\). Therefore, the expression for terminal speed in terms of the given variables is: v = \(\sqrt{((8/3) * (rhom - rhor) * g * r^{3}) / (6 * pi * b)}\)
In summary, we can use the formula for terminal speed to find an expression in terms of the given variables. The expression for terminal speed can be derived by substituting the expressions for mass, cross-sectional area, and drag coefficient into the formula for terminal speed. The resulting expression involves the variables b, rhor, rhom, and the constant g. The formula can be used to calculate the terminal speed of a sphere in a given medium.
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