According to the given statement the strong acid will be HX.
What do you mean by "strong acid"?A strong acid is one that is completely dissociated in aqueous solution. It is a chemical species with a high capacity to lose a proton, H+. A strong acid loses one proton in water, which is captured by water to form the hydronium ion: HA(aq) + H2O H3O+(aq) + A (aq)
According to the given information:Given:
MM\(_H_X\) = 150.g/mol
MM\(_H_Y\) = 50.0 g/mol)
HX = 12 g/L
HY = 6 g/L
Now the concentration of each acid:
HX
\([H X]=\frac{12.0 \mathrm{~g} \times \frac{1 \mathrm{~mol}}{150 \mathrm{~g}}}{L}\)
= 0.08M
HY
\([H Y]=\frac{6.00 \mathrm{~g} \times \frac{1 \mathrm{~mol}}{50 \mathrm{~g}}}{L}\)
= .12M
Comparing HX < HY
The have the pH so they produce same amount of \(\left[\mathrm{H}_3 \mathrm{O}^{+}\right]\) .
The strong acid must have lower concentration so it dissociated large amount of \(\left[\mathrm{H}_3 \mathrm{O}^{+}\right]\) compared to initial concentration.
so the strong acid will be HX
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Questions 7-10 refer to the following types of energy. (A) Activation energy (B) Free energy (C) Ionization energy (D) Kinetic energy (E) Lattice energy 7. The energy required to convert a ground-state atom in the gas phase to a gaseous positive ion __________ 8. The energy change that occurs in the conversion of an ionic solid to widely separated gaseous ions ___________ 9. The energy in a chemical or physical change that is available to do useful work ___________ 10. The energy required to form the transition state in a chemical reaction ___________
Answer:
7. Ionization energy
8. Lattice energy
9. Free energy
10. Activation energy
Explanation:
I. Ionization energy: The energy required to convert a ground-state atom in the gas phase to a gaseous positive ion. Thus, it is the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state. Generally, atoms with relatively large atomic radii tend to have a low ionization energy.
II. Lattice energy: The energy change that occurs in the conversion of an ionic solid to widely separated gaseous ions. This ultimately implies that, it is the energy generated during the conversion of an ionic solid into gaseous ions and as such is a measure of the cohesive force binding the ions of an ionic compound using the Born-Haber cycle.
III. Free energy: the energy in a chemical or physical change that is available to do useful work. Thus, it is a thermodynamic quantity that measures the maximum capacity of a system to do work at constant temperature and pressure.
IV. Activation energy: The energy required to form the transition state in a chemical reaction. When the activation energy of a reaction is low, the rate of the reaction would be faster. Therefore, an enzyme speeds or catalyzes the rate of a reaction by lowering its activation energy.
based on the law of multiple proportions, how many grams of hydrogen would you expect 2.58 g of nitrogen to combine with to yield ammonia?
Based on the law of multiple proportions, there are 0.55 grams of hydrogen.
Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers.
In one molecule of the ammonia, there are three hydrogen atoms and one nitrogen atom
In a molecule of ammonia (NH3), proportion of the masses of nitrogen and hydrogen is:
m(N) : m(H) = 14 : (3·1) = 14 : 3
Mass of nitrogen is 2.58 grams
2.58 g : m(H) = 14 : 3
m(H) = 0.55 g; mass of hydrogen needed to react with nitrogen
Balanced chemical reaction: N₂ + 3H₂ ⇄ 2NH₃
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use the tabulated half-cell potentials to calculate δg° for the following balanced redox reaction. 3 i2(s) 2 fe(s) → 2 fe3 (aq) 6 i⁻(aq)
The ΔG° for the given redox reaction is +29,068 J/mol. The positive value indicates that the reaction is not spontaneous under standard conditions (1 atm and 25°C).
The standard Gibbs free energy change (ΔG°) for the given balanced redox reaction: 3I₂(s) + 2Fe(s) → 2Fe³⁺(aq) + 6I⁻(aq).Can be calculated using the tabulated half-cell potentials. The ΔG° of a reaction is related to the cell potential (E°) by the equation ΔG° = -nFE°, where n is the number of electrons transferred and F is the Faraday constant (96,485 C/mol).
The half-cell reactions involved in this redox reaction are:
Fe³⁺(aq) + e⁻ → Fe²⁺(aq) E° = +0.77 V
I₂(s) + 2e⁻ → 2I⁻(aq) E° = +0.62 V
To calculate the ΔG° for the overall reaction, we need to multiply the Fe reaction by 3 and the I₂ reaction by 2 to balance the electrons:
3Fe³⁺(aq) + 3e⁻ → 3Fe²⁺(aq) (multiply by 3)
I₂(s) + 2e⁻ → 2I⁻(aq) (multiply by 2)
Adding these half-cell reactions gives:
3Fe³⁺(aq) + 2I₂(s) → 3Fe²⁺(aq) + 6I⁻(aq)
The cell potential (E°cell) for the overall reaction can be calculated by subtracting the reduction potential of the anode (Fe³⁺/Fe²⁺) from the reduction potential of the cathode (I₂/I⁻): E°cell = E°cathode - E°anode
E°cell = (+0.62 V) - (+0.77 V)
E°cell = -0.15 V
Using the equation ΔG° = -nFE°cell and plugging in the values, we get:
ΔG° = -nFE°cell
ΔG° = -(2 mol)(96,485 C/mol)(-0.15 V)
ΔG° = +29,068 J/mol
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1. Consider the reaction below. Which of these forms an acid-conjugate base
pair?
HNO3 + CO32- → HCO3¹+ NO3¹-
A. HNO3 and HCO3 1-
B. HNO3 and NO3 1-
C. CO3 2- and HCO3 1-
D. HCO3 1- and NO3 1-
CO₃⁻² and HCO₃⁻¹ are acid-conjugate base pair.
What is acid-conjugate base pair?A conjugate acid-base pair, according to the Brnsted-Lowry definition of acids and bases, consists of two substances that are distinct only in that they contain a proton (H⁺). A proton given to a base creates a conjugate acid, while a proton taken away from an acid creates a conjugate base.
A conjugate base differs from the forming acid in that it has one additional (-) ve charge and one fewer H atom. It is an acidic residue left over after the hydrogen ion has been removed.
The reaction becomes:
HNO₃ + CO₃⁻² → HCO₃⁻¹+ NO₃⁻¹
In the above reaction, it is observe that,
CO₃⁻² and HCO₃⁻¹ are acid-conjugate base pair.
correct option is: D
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Someone please answer the question attached.
Answer:
Option ( 1 )
Explanation:
This atom has a cub close pack structure, and therefore - the number of edge center present in X atoms = 4,
Number of unit cells present in X atoms = 6
____________________________________________________
Now the 6th coordination number of X atom = 6 * 4 = 24,
So respectively, the 3rd coordination number of X = 8 -
And thus the ratio between the 6th coordination number and the 3rd coordination number = 24 / 8 = 3,
Option ( 1 )
Hope that helps!
What is the chemical formula for disulfur difluoride?
A. 252F
B. 2SF
C. S2F2
D. SZF
its C
All-seeing eyes:
my eyes see all, every answer so it is C
Explanation:
my eyes only speak the truth
What effect would increasing the amount of lauric acid present in the test tube have on the freezing point and the shape/ features of the graph?
(This is a freezing point of lauric acid lab question require at least five sentences)
Lauric acid, 300 g
Benzoic acid, 30 g
Paper towels
Advance Preparation
It is important that you do the laboratory yourself beforehand. Time may be saved by pre-filling the test-tubes with about 25 g of lauric acid and having the hot and warm water baths ready. [NOTE: The mass of the lauric acid in the test-tubes must be determined to the nearest gram.]
a 5.08 g mixture contains both lithium fluoride, lif, and potassium fluoride, kf. if the mixture contains 3.26 g fluorine, what is the mass of the kf in the mixture?
The mass of KF in the mixture is 1.067 grams
As per the details provided in the question are as follow,
Total weight of mixture (LiF+KF)= 5.08 grams
Mixture contains 3.26 grams of fluorine
Molar mass K = 39.10 g/mol
Molar mass F = 19.00 g/mol
Molar mass KF = 58.10 g/mol
Molar mass of lithium = 6.94 g/mol
mass of KF and LiF
Mass KF = X grams
Mass LiF = 5.08 -X grams
Now Calculate the moles
Moles KF = x grams / 58.10 g/mol
Moles LiF = (5.08-X grams) / 25.94 g/mol
1 mol of KF contains 1 mol of F atoms.
1 mol of LiF contains 1 mol of F atoms.
moles of F in KF= moles of KF= x/58.10 g/mol
moles of F in LiF = moles of LiF= (5.08-x)/25.94g/mol
Total moles of Fluorine =(x/58.10)+((5.08-x)/25.94)
Calculate mass
The total weight of Fluorine in sample
3.26 grams =((x/58.10)+((5.08-x)/25.94))*19g/mol
x = 1.067 grams
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calculate the concentration of silver in a 100.0 mL solution of silver bromide at 25oC (298 K) when the Ksp is 5.0 x 10-13
Answer:
Concentration AgBr at saturation = 7.07 x 10⁻⁷M
Explanation:
Given AgBr(s) => Ag⁺(aq) + Br⁻(aq) ; Ksp = 5 x 10⁻¹³ = [Ag⁺][Br⁻]
I --- 0 0
C --- +x +x
E --- x x
[Ag⁺][Br⁻] = (x)(x) = x² = 5 x 10⁻¹³ => x = SqrRt(5 x 10⁻¹³) = 7.07 x 10⁻⁷M
Two different cars, the Model S and Model T, use different substances in their engines. The image above shows the two substances. At room temperature, both substances are liquids. A car mechanic transferred the same amount of energy out of the two containers, but only one substance changed phase. Which car’s substance changed phase, and how did it change?
Answer:
The Model T’s substance changed phase because the attraction of the molecules was able to overcome their slower movement. Its molecules now move in place.
A. A sample of copper goes from an initial temperature of 65.2 °C to a final temperature
of 24.5 °C. If -1960 J of heat were released. Copper has a specific heat of 0.385
J/g °C. What is the mass of the copper sample?
Explanation:
Formula
H= mC∆∅
where H= -1960J
C= 0.385J/g/°C
ع= 65.2°C
∅² = 24.5°C
m= ?
-1960= m x 0.385x(65.2-24.5)
-1960= m x0.385 x 40.7
-1960= 15.6695m
m= -1960/15.6695
m= 125g
11. A student must make a solution that contains 0.0465 moles of carbon dioxide (CO2). How may
grams of carbon dioxide should the student measure out to make the solution
Answer:
whats the answer i been trying to find it please
Explanation:
thanksss
Fill in the blanks to balance the following chemical equation.
__P +__02 - P406
Answer:
4P + 3O2 → P4O6
Explanation:
Chemical Equation Balancer Online!
The balanced chemical equation can be represented for the given reaction as:
\(4\;P + 3\;O_2\longrightarrow P_4O_6\)
What is a balanced chemical equation?A chemical equation for a chemical reaction can be represented in terms of chemical symbols of the reactants and products. A balanced chemical equation in which the number of atoms of reactants and products is equal on either side of the equation.
The law of conservation of mass gives the idea that the total mass of both the reactant side and the product side is equal in a balanced chemical equation.
The given chemical equation has the given reaction:
\(4\;P + 3\;O_2\longrightarrow P_4O_6\)
The number of phosphorous and oxygen atoms are equal on both sides of the arrow therefore it is a balanced chemical equation. Therefore, the mass of the phosphorus and oxygen elements will be equal on the reactant as well as product side.
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Which behavior is both territorial and used for courtship? (1 point)
Answer:
Display behavior or engaging in physical combats with other males
Explanation:
The behavior that both territorial and used for courtship is engaging in physical combats with other males because the male display and engage in physical combats with other males in order to attracts females as their mating partner or for courtship and also the male do this so as to secure their territories from Intruders and others taking over their own found territories. This normally occur in male lizards. The male like lizards have variants color on their skin, they display to attracts females and also to secure their territory.
True or false, The mass of an electron is equal to the mass of a neutron.
Answer:
False
Explanation:
No, the mass of an electron is not equal to the mass of a neutron. Mass of neutron is greater than the mass of an electron.
What element does beryllium resemble (in terms of electrons) when it loses 2 electrons?
Answer: Helium
Explanation: Beryllium (Be) has an electron configuration of 2-2. Losing two electrons will leave it with two electrons in the first shell, resembling Helium.
How many milliliters of 4.24 M KCl must be diluted to make 825 milliliters of a 0.705 M KCl solution?
Answer:
137.18mL
Explanations:
To get the required volume, we will use the dilution formula expressed as:
\(C_1V_1=C_2V_2_{}\)C1 and C2 are the concentration of the solution
V1 and V2 are the corresponding volumes
Given the following parameters:
\(\begin{gathered} C_1=4.24M \\ C_2=0.705M \\ V_2=825mL \\ V_1=\text{?} \end{gathered}\)Substitute the given parameters into the formula:
\(\begin{gathered} V_1=\frac{C_2V_2}{C_1} \\ V_1=\frac{0.705\cancel{M}\times825mL}{4.24\cancel{M}} \\ V_1=\frac{581.625mL}{4.24} \\ V_1=137.18mL \end{gathered}\)Hence the required volume of KCL that must be diluted to make 825 milliliters of a 0.705 M KCl solution is 137.18mL
HELP I NEED THIS ASAP
ON THE IMAGE
Answer:
hope you find it helpful
Explanation:
This is the answer--------
How many moles of methane gas are in 44.8 L of CH at STP?
Answer:
2 mol CH 4
Explanation:
43.8 x L
---------------- = 2 mol CH 4
22.4 x L x mol - 1
What type of bond would form silicon and bromine
Answer: If you're looking for the type of bond, you need to find the difference in electromagnetically. The electromagnetically of Br is 2.96 and Si is 1.9. Subtracting the two will give you the difference of the previously mentioned (1.06).
For the bond to be POLAR the difference should fall between 0.5 and 1.6
For the bond to be NON-POLAR the difference should be 1.6
A 5. 000 g sample of an unknown insecticide made up of C, O, and Cl is analyzed by combustion analysis. 8. 692 g of CO2 and 1. 142 g of H2O are recovered. A second 5. 000 g sample in another analysis gave 2. 571 g of HCl. What is the empirical formula? What is the molecular formula if the unknown’s molar mass is around 354 g/mol
a. The empirical formula of a 5.000 g sample of an unknown insecticide made up of C, O, and Cl is analyzed by combustion analysis. 8.692 g of CO₂ and 1.142 g of H₂O are recovered. A second 5.000 g sample in another analysis gave 2.571 g of HCl is C₅H₆ClO₃.
b. The molecular formula of the unknown’s molar mass around 354 g/mol is C₂₅H₃₀Cl₆O₁₅.
How to find empirical formula of a compound?The empirical formula of a compound can be determined by combustion analysis. Combustion analysis is an experimental technique that determines the elemental composition of a compound. This technique involves burning a known quantity of a substance in excess oxygen and analyzing the products formed. The products of combustion are typically carbon dioxide and water vapor.
The first step in determining the empirical formula of the compound is to determine the masses of carbon, hydrogen, and oxygen present in the sample. Here's how you can do this:
1. Carbon: The mass of carbon dioxide produced in the combustion of the sample is 8.692 g. Carbon dioxide is made up of one carbon atom and two oxygen atoms. Therefore, the mass of carbon present in the sample is:
mass of carbon = (mass of CO₂ × 1 mol CO₂) / (44.01 g CO₂/mol CO₂)
mass of carbon = (8.692 g × 1 mol CO₂) / (44.01 g/mol CO₂)
mass of carbon = 1.707 g
2.Hydrogen: The mass of water produced in the combustion of the sample is 1.142 g. Water is made up of two hydrogen atoms and one oxygen atom. Therefore, the mass of hydrogen present in the sample is:
mass of hydrogen = (mass of H₂O × 2 mol H₂O) / (18.02 g H₂O/mol H₂O)
mass of hydrogen = (1.142 g × 2 mol H₂O) / (18.02 g/mol H₂O)
mass of hydrogen = 0.127 g
3. Oxygen: The mass of oxygen in the sample can be calculated by subtracting the mass of carbon and hydrogen from the total mass of the sample.
mass of oxygen = (mass of sample - mass of carbon - mass of hydrogen)
mass of oxygen = (5.000 g - 1.707 g - 0.127 g)
mass of oxygen = 3.166 g
The next step is to convert the masses of carbon, hydrogen, and oxygen into moles by dividing each mass by its respective molar mass. The molar mass of carbon is 12.01 g/mol, the molar mass of hydrogen is 1.008 g/mol, and the molar mass of oxygen is 16.00 g/mol. The number of moles of each element is as follows:
moles of carbon = 1.707 g / 12.01 g/mol = 0.142 moles
moles of hydrogen = 0.127 g / 1.008 g/mol = 0.126 moles
moles of oxygen = 3.166 g / 16.00 g/mol = 0.198 moles
The final step is to determine the simplest whole-number ratio of the atoms present in the compound. To do this, divide each of the moles by the smallest number of moles (in this case, 0.126 moles):
moles of carbon = 0.142 / 0.126 = 1.13 ≈ 1
moles of hydrogen = 0.126 / 0.126 = 1
moles of oxygen = 0.198 / 0.126 = 1.57 ≈ 2
Therefore, the empirical formula of the unknown insecticide is C₁H₁.57O1 or C₅H₆ClO₃.
The molecular formula of a compound is a multiple of its empirical formula. To find the molecular formula of the compound, you need to know its molar mass. In this case, the molar mass of the unknown insecticide is around 354 g/mol. To find the molecular formula, you need to divide the molar mass by the empirical formula mass (the sum of the atomic masses in the empirical formula).The empirical formula mass of C₅H₆ClO₃ is:
1(12.01) + 1(1.01) + 3(16.00) + 1(35.45) = 154.47 g/mol
The molecular formula mass is 354 g/mol. Therefore, the ratio of the molecular formula mass to the empirical formula mass is:
ratio = molecular formula mass / empirical formula mass
ratio = 354 g/mol / 154.47 g/mol
ratio = 2.29
The molecular formula is the empirical formula multiplied by the ratio. Therefore, the molecular formula of the unknown insecticide is:
C₅H₆ClO₃ × 2.29 = C₂₅H₃₀Cl₆O₁₅
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Scientists have found that most greenhouse gases continue to have an exponential growth pattern in emissions. The one exception to these trends is a man-made greenhouse gas which has been shown to be decreasing in its emissions since the early 2000 s. This greenhouse gas is known as:
PCBs
nitrous oxides
CFCS
dioxins
The man-made greenhouse gas that has been shown to be decreasing in emissions since the early 2000s is CFCS (chlorofluorocarbons).
CFCS (chlorofluorocarbons) are a type of man-made greenhouse gas that were widely used in various industries, including refrigeration, aerosol propellants, and foam manufacturing. However, due to their harmful effects on the ozone layer, their production and use have been significantly reduced through international agreements such as the Montreal Protocol.
While most greenhouse gases, such as carbon dioxide and methane, continue to exhibit an exponential growth pattern in emissions, CFCS are an exception. The successful implementation of global regulations and efforts to phase out CFCS has led to a decline in their emissions since the early 2000s.
This reduction in CFCS emissions is a positive environmental outcome as these gases contribute to ozone depletion and have a significant global warming potential. The decrease in CFCS emissions showcases the effectiveness of international agreements and the commitment to mitigating their impact on the environment.
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1. How do you think the kinetic energy of a snowboarder as he goes downhill is affected by his mass? How is kinetic energy affected by his speed? Explain your reasoning
Both the mass and speed of a snowboarder affect their kinetic energy. An increase in mass or speed will result in an increase in kinetic energy, according to the equation KE = (1/2)mv².
What is Kinetic Energy?
It is a scalar quantity that depends on the mass and speed of the object. The formula for calculating the kinetic energy of an object is KE = (1/2)mv², where KE is the kinetic energy, m is the mass of the object, and v is the velocity or speed of the object.
Kinetic energy can be understood as the work required to bring an object from rest to its current state of motion. When an object is in motion, it has the ability to do work on other objects it comes into contact with. For example, a moving billiard ball can collide with another billiard ball and transfer its kinetic energy to the other ball, causing it to move.
The kinetic energy of a snowboarder as he goes downhill is directly proportional to both his mass and speed. The kinetic energy of an object is given by the equation KE = (1/2)mv², where KE is the kinetic energy, m is the mass of the object, and v is the velocity of the object.
As the mass of the snowboarder increases, the kinetic energy of the snowboarder also increases. This is because the mass of the snowboarder determines how much matter is in motion, and therefore, how much energy is being transferred. For example, if two snowboarders of different masses start at the same height and speed down a slope, the snowboarder with the greater mass will have more kinetic energy than the one with the smaller mass.
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What is the temperature of a gas if the container has a volume of 2,300 mL, with a pressure of 932 mmHg and 3.51 moles?
Answer:
The preceding temperature is equivalent to approximately 9.6 K => -263.5 °C
Explanation:
Given the provided problem, the formula may be substituted by the corresponding values:
Pressure (P)= 932 mmHg ==> 1.2 atm
Volume (V) = 2,300 mL ==> 2.31 L
Moles (n) = 3.51 moles ==> 3.51 mol
Proportional constant of ideal gas constant: (R) = 0.08206
Therefore, we can equate the following:
T= (PV)
nR
T= (1.2 atm · 2.31 L)
(3.51 mol · 0.08206)
T= 9.6 K ==> -263.5 °C
Thus, the cumulative temperature given the substituents/substance is equivalent to -263.5 °C.
How is s,p,d,f blocks related to the type of element and its properties?
grouping elements into s, p, d, and f blocks allows us to predict the chemical and physical properties of elements based on their electron configurations and periodic table positions.
The periodic table's s, p, d, and f blocks refer to the arrangement of electrons in the atom's outermost energy level (valence shell), and they are related to the element's type and properties in several ways.
Atomic size increases from right to left within a period and from top to bottom within a group.
Ionization Energy: The energy required to remove an electron from an atom is referred to as ionisation energy.
Electronegativity: The ability of an atom to attract electrons towards itself in a chemical bond is measured by electronegativity.
Reactivity: An element's reactivity is determined by the number of valence electrons it possesses. Because the s-block elements have one or two valence electrons, they are extremely reactive.
Chemistry: Ionic compounds are formed by s-block elements with nonmetals, whereas covalent compounds are formed by p-block elements.
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All ions and isotopes of an atom share the same____
A)atomic number
B)mass number
C)radio waves
D)charge
Answer:
A atomic number
Explanation:
not too sure
what is structural formula for potassium hydrogen phthalate
The structural formula for potassium hydrogen phthalate (C8H5KO4), also known as KHP or potassium acid phthalate, is shown in the image attached.
This formula shows the atoms and bonds in the molecule, with the potassium ion (K+) and the hydrogen phthalate anion ([C8H5O4]−) separated by a dot. The phthalate anion is composed of two benzene rings connected by a carboxylic acid group (COOH) and a single carboxylate group (COO−) from the potassium hydrogen phthalate salt.
Potassium hydrogen phthalate (KHP) is a white crystalline powder that is commonly used as a primary standard for volumetric analysis, specifically for acid-base titrations. It is also used in the calibration of pH meters and in the preparation of buffer solutions.
KHP is a weak acid, and its chemical formula is C8H5KO4. It is the potassium salt of phthalic acid, which is a diprotic acid with two carboxylic acid groups. In water, KHP dissociates to form potassium ions (K+) and hydrogen phthalate anions ([C8H5O4]−), which can donate a proton to water molecules and act as a weak acid.
The use of KHP as a primary standard is based on its high purity, stability, and accurate molar mass, which allows precise determination of the concentration of a solution by titration. In an acid-base titration, a known volume of a standard solution of KHP is titrated with a solution of an unknown concentration of an acid or base until the equivalence point is reached. At the equivalence point, the moles of acid and base are equal, and the concentration of the unknown solution can be calculated from the known concentration and volume of the standard solution.
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a buffer is prepared by mixing 86.4 ml of 1.05 m hbr and 274 ml of 0.833 M ethylamine (C2H5NH2, Kb = 4.5 x 10-4, pKb = 3.35). What is the pH of the buffer after 0.068 mol NaOH are added to the previously prepared buffer? Assume no change in the volume with the addition of the NaOH. Report your answer to two decimal places.
When, a buffer will be prepared by mixing 86.4 ml of 1.05 m hbr and 274 ml of 0.833 M ethylamine. Then, the pH of the buffer after 0.068 mol NaOH is added is 5.72.
To solve this problem, we use the Henderson-Hasselbalch equation;
pH = pKa + log([base]/[acid])
First, we need to find the concentrations of the acid and base in the buffer solution;
[acid] = 1.05 M (HBr)
[base] = 0.833 M (ethylamine)
The pKa of HBr is -9, so we can assume that the concentration of H⁺ions is equal to the concentration of HBr. Therefore, the pH of the buffer before adding NaOH is;
pH = -log[H⁺] = -log(1.05) = 0.978
To calculate pH after adding 0.068 mol NaOH, we need to determine the new concentrations of the acid and base. We know that 0.068 mol NaOH will react with some of the HBr in the buffer, so we calculate how much HBr will be left.
1 mol HBr reacts with 1 mol NaOH, so 0.068 mol NaOH will react with 0.068 mol HBr. The amount of HBr remaining in the buffer is;
0.068 mol HBr - 0.068 mol NaOH = 0.054 mol HBr
The concentration of HBr is now;
[acid] = 0.054 mol / 0.3604 L = 0.1499 M
To calculate the concentration of the conjugate base, we need to determine how much of the ethylamine will react with the remaining H⁺ ions. Since ethylamine is a weak base, we need to use the \(K_{b}\) equation;
\(K_{b}\) = [BH⁺][OH⁻] / [B]
We can assume that all of the remaining H⁺ ions will react with the ethylamine to form the conjugate acid. The amount of ethylamine that reacts can be calculated using the stoichiometry of the reaction;
C₂H₅NH₂ + H⁺ → C₂H₅NH₃⁺
1 mol C₂H₅NH₂reacts with 1 mol H⁺, so 0.054 mol H⁺ will react with 0.054 molC₂H₅NH₂. The amount of C₂H₅NH₂ remaining in the buffer is;
.833 mol - 0.054 mol = 0.779 mol
The concentration of the conjugate base is;
[base] = 0.779 mol / 0.3604 L = 2.160 M
Now we use the Henderson-Hasselbalch equation to calculate the pH;
pH = pKa + log([base]/[acid])
pH = 9 - log(2.160/0.1499)
pH = 5.72
Therefore, the pH of the buffer after 0.068 mol NaOH is added is 5.72.
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Based on your knowledge of the groups in the Periodic Table, would you expect a reaction is chlorine gas was bubbled into a Potassium Iodide solution? Explain your answer
Iodine ions are oxidized to form iodine when the chlorine gas is bubbled in the solution of potassium iodide.
Reaction of some chlorineWhen chlorine gas is bubbled into a solution of potassium iodide, some amount of the iodide ions are oxidized and changed into iodine which leads to the formation of beautiful violet color of iodine. This colour can be seen as the iodine dissolves in the carbon tetrachloride layer.
Reaction with concentrated chlorine gasWhile on the other hand, when the high concentration of chlorine is bubbled into the solution of potassium iodide, the iodine reacts and formed iodine monochloride which is ruby red so we can conclude that iodine ions are oxidized to form iodine when the chlorine gas is bubbled in the solution of potassium iodide.
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A student is given an object and is asked to identify its density. The object has a volume of 3 cubic centimeters and a mass of 6 grams. Which of the following equations correctly sets up the formula for density?
Density =mass/volume
=6/3
=2