Answer:
A) aₓ = -0.717 m / s² , B) a_{y} = -1.024 m / s², C) x = 11.77 m , D) y = -4.6 m ,
E) d = 12.64 m
Explanation:
For this exercise we will use trigonometry to decompose the acceleration, we are told that
a = 1.25 m /s² with an angle tea = 125º in a clockwise direction
A) cos θ = aₓ / a
aₓ = a cos θ
aₓ = 1.25 cos (-125)
aₓ = -0.717 m / s²
B) sin θ = \(a_{y}\) / a
a_{y} = a sin θ
a_{y} = 1.25 sin (-125)
a_{y} = -1.024 m / s²
C) The displacement component
x = v₀ₓ t + ½ aₓ t²
let's calculate
x = 5 3 + ½ (-0.717) 3²
x = 11.77 m
D) the y component of the displacement
y = \(v_{oy}\) t + ½ \(a_{y}\) t²
in this case the initial velocity is zero
y = 0 + ½ (-1,024) 3²
y = -4.6 m
E) Let's use the Pythagorean theorem
d =√ (x² + y²)
d = √ (11.77² + 4.6²)
d = 12.64 m
An engineer wants to design a go-kart that can reach an acceleration of 20 m/s2. If the cart has a mass of 75 kg and can hold one person with a mass of 80 kg, the engineer must design an engine that can produce a force of
newtons.
The engineer must design an engine that can produce a force of over 3,100 Newtons.
What is a Force?A force is an energy that can cause change of motion. It can be a push or a pull. It also has both magnitude and direction, making it a vector quantity.
From the question;
total mass = mass of person + mass of cart
total mass = 80kg + 75kg
total mass = 155kg
acceleration = 20m/s²
The formula to be used;
F = m x a
F = 155kg x 20m/s²
F = 3,100N
In conclusion, the engineer needs a minimum force of 3,100 N in the engine to be able to power the cart.
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A 0.15 kg arrow is shot at +44 m/s. It hits an apple (m = 0.49 kg), and goes through the apple, leaving with a velocity of +28 m/s.
What is the velocity of the apple after the arrow leaves it?
On a drive from your home to town, you
wish to average 60 mph. The distance from
your home to town is 78 miles. However,
at 39 miles (half way), you find you have
averaged only 45 mph.
What average speed must you maintain in
the remaining distance in order to have an
overall average speed of 60 mph?
Answer in units of mph.
On a drive from your home to town, you wish
to average 33.6 mph. The distance from your
home to town is 90 miles. However, at 45 miles
(half way), you find you have averaged only
25.2 mph.
What average speed must you maintain in
the remaining distance in order to have an
overall average speed of 33.6 mph?
Answer in units of mph
let the speed be x
total average = 33.6
An example of conservation of angular momentum is jumping on a Merry-Go-Round. Watch this video (it starts part way through but the only thing you miss is the people pushing the Merry-Go-Round) to see someone jumping on a Merry-Gr-Round in motion like this problem. You can model the Merry-Go-Round as a solid disk with a radius of 2.70 m and a mass of 77.0 kg. Initially the Merry-Go-Round has an angular velocity 7.40 radians / second. Then the person jumps on and change the Moment of Inertia of the system. The person lands on the outer edge of the Merry-Go-Round and has a mass of 58.0 kg. What is the final angular velocity of the system after the person jumps on
Answer:
ωf = 2.95 rad/sec
Explanation:
Assuming no external torques acting while the person jumps on, total angular momentum must be conserved.Angular momentum for a rotating rigid body can be expressed as follows:\(L = I * \omega (1)\)
where I = moment of inertia regarding the rotating axis, and ω= angular velocity.Since total angular momentum must be conserved, this means that the following equality must be satisfied:\(L_{o} = L_{f} (2)\)
The initial angular momentum, taking into account that the Merry-Go-Round can be modeled as solid disk, can be expressed as follows:\(L_{o} = I_{o} * \omega_{o} = \frac{1}{2}* M* R^{2}* \omega_{o} =\\ \frac{1}{2} * 77.0 kg* (2.70m)^{2}* 7.40 rad/sec = 2076.92 kg*m2*rad/sec (3)\)
The final angular momentum, is just the product of the new moment of inertia times the final angular velocity.The new moment of inertia, is just the sum of the original moment of inertia I₀ and the moment of inertia due to the person that jumps on.Assuming that we can treat him as a point mass, his moment of inertia is just the product of his mass times to the distance to the axis of rotation (the radius of the Merry-Go-Round) squared.So, we can write the new moment of inertia If as follows:\(I_{f} = I_{o} +( m_{p} * R^{2}) = (\frac{1}{2} * M* R^{2}) + ( m_{p} * R^{2}) =\\ (\frac{1}{2} * 77.0 kg* (2.70m)^{2}) +( 58.0 kg * (2.70m)^{2}) = \\ 280.67 kg*m2 + 422.82 kg*m2 = \\ 703.49 kg*m2 (4)\)
The final angular momentum can be written as follows:\(L_{f} = I_{f} * \omega_{f} (5)\)
Since (3) and (5) must be equal each other, replacing If by its value from (4) in (5), we can solve for ωf, as follows:\(\omega_{f} = \frac{L_{o} }{I_{f}} = \frac{2076.92kg*m2*rad/sec}{703.49kg*m2} = 2.95 rad/sec (6)\)
If the average hang time of a professional football kick is 4.4s, then determine the average maximum height.
The average highest height of a professional football kick is 189.728 m if the hang time is 4.4 seconds on average.
What is meant by hang time?A person or an object's total duration in the air after leaving the ground is known as their "hang time." From the time anything leaves the ground until it returns, it is measured.
We know,
y= gt²
Here,
y = Average maximum height
g = acceleration due to gravity
t = Average hang time
Given,
Average hang time (t) = 4.4s
Acceleration due to gravity (g) = 9.8 m/s² (assuming)
Inserting these values in the given equation,
y = gt²
= 9.8×4.4×4.4
= 189.728 m.
Hence, the average maximum height of the football is 189.728 m.
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g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to mention: What is the underlying model (equation) that you can use to determine the mass from your measurements
Answer:
m = \(\frac{k}{g}\) x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = \(\frac{k}{g}\) x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass
In an experiment to measure the wavelength of light using a double slit, it is found that the fringes are too close together to easily count them. To spread out the fringe pattern, one could
Answer:
halve the slit separation
Explanation:
As we know that
In YDS experiment, the equation of fringe width is as follows
\(\beta = \frac{\lambda D}{d}\)
where,
D denotes the separation in the middle of screen and slits
d denotes the distance in the middle of two slits
And to increase the Δx we have to decrease the d i.e, the distance between the two slits
Hence, the first option is correct
The
is located 12 to 50 kilometers from Earth’s surface.
Both the
get colder as altitude increases.
The ozone in the
protects people from ultraviolet (UV) radiation.
The
has the highest temperature of any layer in Earth’s atmosphere.
The thermosphere has the highest temperature of any layer in Earth’s atmosphere.
What is the atmosphere?The term troposphere is the region that is found 12 to 50 kilometers from Earth’s surface. This region is found to be the region where you can find a lot of gases.
Both the Troposphere and the stratosphere get colder as altitude increases. However, the ozone in the stratosphere protects people from ultraviolet (UV) radiation.
The thermosphere has the highest temperature of any layer in Earth’s atmosphere.
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A piece of lead with a specific heat capacity of 126J/kg°C is given 5000J of energy to heat it from 20°C to 250°C. What was the mass of the piece of lead?
Answer:
m = 0.172 [kg]
Explanation:
To solve this problem we must use the expression of thermal energy that relates the heat to the mass, the specific heat, and the temperature differential.
Q = m*Cp*(T_f - T_i)
where:
m = mass [kg]
Cp = specif heat = 126 [J/kg*C]
Q = 5000 [J]
T_f = final temperature = 250 [C]
T_i = initial temperature = 20 [C]
m = Q/ (Cp*(T_f - T_i))
m = 5000/ (126*(250 - 20))
m = 0.172 [kg]
A substance is soluble in water. It is added into the water and dissolves. More solute continues being added until it reaches a point where the newly added solute begins to sit on the bottom of the container without dissolving. What has happened? A. The solute has become a solvent. B. The solute was not actually soluble to begin with. C. The solute has become saturated. D. The solution has become saturated.
Answer:
option D
Explanation:
also to add.... there exists a solubility equilibrium between solid solute and the solution.
The newly added solute begins to sit on the bottom of the container without dissolving this represents that the solution has become saturated, Therefore the correct answer is D.
What is a Saturated Solution?It is a type of solution in which no more amount of solute can be dissolved any further, The saturated solution already contains the maximum amount of solute that can be dissolved within it.
The solution reached a point where the newly added solute starts to sit on the bottom this means the solution has become saturated.
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10 N
30 N
4kg
net force =
a=f/m=
Answer:
\(a=5\ m/s^2\)
Explanation:
Two forces are 10 N and 30 N. Let us assume that two forces are acting in opposite directions. Net force will be :
F = 30 N - 10 N = 20 N
Now,
F = ma
⇒ a = F/m
So,
\(a=\dfrac{20}{4}\\\\a=5\ m/s^2\)
So, the acceleration of the object is \(5\ m/s^2\).
What is the potential energy of a 2500 g object suspended 5 kg above the earth's surface?
kilograms.
Answer:
\(potential \: energy = mgh \\ = ( \frac{2500}{1000} ) \times 10 \times 5 \\ = 125 \: newtons\)
if height is 5 m
The surface of the exit road is horizontal, not banked. (See figure.) If the static
friction between the tires and the surface of the road is us = 0.688 and the
maximum speed with which the car can exit the highway safely without sliding is
25.2 m/s, what is the radius of curvature of a highway exit, r?
The radius of curvature of the highway exit is approximately 220 km.
To find the radius of curvature of the highway exit, we can use the centripetal force equation:
F = mv^2 / r
where F is the maximum static friction force, m is the mass of the car, v is the maximum safe speed, and r is the radius of curvature.
We can solve for r by rearranging the equation:
r = mv^2 / F
Substituting the given values, we have:
r = (1000 kg)(25.2 m/s)^2 / (0.688)
r = 2.20 x 10^5 m
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The figure shows a cube resting on top of a table . If the table rotates and moves the cube in a counterclockwise circle at a constant speed , describe the direction of the acceleration experienced by the cube .
Answer:
Forwarded
Explanation:
By how many decibels does the intensity level of a sound decrease when you triple your distance from a source of sound?.
The intensity level of a sound decreases by approximately 6 dB every time you double your distance from the source. Therefore, when you triple your distance from the source, the intensity level of the sound will decrease by approximately 18 dB.
What is source?Intensity level is a measure of the strength of a stimulus, stimulus being anything that causes a reaction in an organism or system. It is a quantitative measure of the magnitude of a physical phenomenon, such as sound or light. It is most commonly expressed as a numerical value and is typically measured in decibels (dB). Intensity level is an important concept in fields such as audio engineering, physics, and sensory science, as it is used to measure the strength of a stimulus and to compare different stimuli. For example, the intensity level of a sound is a measure of how loud it is, while the intensity level of light is a measure of how bright it is.
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can someone please answer this for me ❤️
Answer:
I don't understand the question
Explanation:
sorry I cant help because I am just a first former
1. Materials through which electricity pass easily are called?
a. Conductors
b. Insulators
c. Non-conductor
d. Metallic
c. Non-conductor
2. Materials that do not transmit electricity and heat are called?
d. Metallic
a. Conductor
b. Insulator
3. When a certain material is considered an insulator? If it
a. Allows the free electrons to tow easily through it.
b. Doesn't allow the tree electron to flow easily through it.
c. Protects the excess electron from getting very hot
d. Gives rise to the production of more electrons
4. How do we describe a conductor of electricity? It is a material that
a. Allows the free electrons to flow easily through it.
b. Has extra free electrons on its surfa
c. Has no free electrons that can move freely
d. Prevents the flow electrons from moving out of the wire.
5. Which of the following group of materials are good conductors of heat and electricity?
a. Copper, silver, gold, glass
b, Iron, copper, silver, gold
c. Wood, paper, cloth, plastic
d. Gold, paper, leather, plastic
6. Why metals are considered good conductors of heat and electricity? Because
a. they are very hard
b. they are heavy
c. they can speedily transfer heat
d. they are smooth
7. Why is copper wire, which is a good conductor covered with rubber?
a. so that it will not melt
b. so that it will look beautiful
c. to make it stronger
d. so that it will not be harmful
8. Which of the following group of materials are good conductors of
electricity?
a. copper, silver, gold, glass, and zinc
b. wood, paper, leather, and plastic
C. iron, copper, silver, gold, and nickel
d.gold, paper, cloth, and plastic
9. Which of the following is most likely to conduct electricity the lastest?
a. wood
b. plastic
d. rubber
C. iron grills
10. The following are good conductors of heat and electricity except.
a. silver spoon
b.golden ring
C. cotton
d. iron bar
Answer:
1. A
2. B
3. B
4. A
5. B
6. C
7. D
8. C
9. C
10. C
Materials through which electricity pass easily are called conductors and material which do not transmit electricity and heat are insulators. Insulators doesn't allow the flow of electrons through it.
What are conductors ?Based on the conductivity of a material, there are three types of materials, namely conductors, semi-conductors and insulators. Conductors are conducting electricity and heat at room temperature. Semi conductors only conduct at higher temperatures or on doping.
The materials which does not conduct electricity and heat are called insulators. Hence, option b is correct. They will never allow the flow of electrons through them and thus why considered as insulators.
Whereas, conductors allow free electrons to flow through them easily. Among the groups , the group of good conductors are Iron, copper, silver, gold.
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on landing the plane touches a runaway with a speed of 65 m/s the figure shows the of the speed of the plane after one second. calculate the acceleration of the plane during its landing
Answer:
Correct option is B)
Given, initial velocity is u=0m/s
Final velocity is v=88.3m/s and traveled distance, d=1365m
Let a be the acceleration of the plane.
Using v
2
−u
2
=2ad
∴ (88.3)
2
−0
2
=2a(1365)
⟹ a=2.86m/s
2
Solve any question of Motion in a Straight Line with:-
Explanation:
hope it helps
To solve this we must be knowing each and every concept related to acceleration. Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
What is acceleration?Acceleration is the rate during which velocity varies over time, both in terms of speed and direction. A point or object travelling in a straight path is accelerated if something accelerates or decelerates.
Regardless of whether the speed remains constant, motion on such a circle gets accelerated because of direction is always changing. Both tangential to acceleration in all other types of motion.
initial velocity u=0m/s
Final velocity v=88.3m/s
distance, d=1365m
v²-u²=2as
substituting all the given values in the above equation, we get
88.3²-0²=2×1365×a
a=2.86m/s²
Therefore, the correct option is option B. The acceleration of the plane during its landing is 2.86m/s².
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Which value is equivalent to 178 centimeters?
Answer:
5.8399
Explanation
work:
176cm
1cm=0.39 in
1cm=0.39x178=178cm=70.07in
70.0787/12=5.8399
Answer:
1.78 meters
Explanation:
It's what you get when you convert it to meters in search
I need help with these four problems.. anyone??
please someone help me !!
Answer:
D
Explanation:
because if the solvent is more than the solvent then we can't resolve it.
so our product will be suspended
If a third resistor is added in a parallel to the other 2 resistors, How will that affect the brightness of the original 2 light bulbs?
The original two light bulbs will appear brighter when the third resistor is added in parallel.
When a third resistor is added in parallel to the other two resistors in a circuit, it will have an impact on the overall brightness of the original two light bulbs.
In a parallel circuit, each resistor has its own branch connected to the power source. The current flowing through each branch is inversely proportional to the resistance of that branch. Adding a third resistor in parallel means an additional path for current to flow.
The introduction of the third resistor reduces the total resistance of the circuit. As a result, the total current drawn from the power source increases, as per Ohm's Law (I = V/R). The increased current is distributed among the parallel branches, including the original two light bulbs.
Since the current through the bulbs is now greater, their brightness will also increase. This is because the brightness of an incandescent light bulb is directly proportional to the current passing through it.
It's worth noting that the specific effect on brightness depends on the resistance values of the resistors and the characteristics of the light bulbs. However, in general, adding a resistor in parallel reduces the overall resistance, increases the current, and subsequently enhances the brightness of the light bulbs in the circuit.
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A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C. At what temperature would the sphere begin to float in glycerine
A hollow glass sphere has a density of 1.3g/cm at 20 C. Glycerine has a density of 1.26 g/cm at 20 C.
To determine the temperature at which the hollow glass sphere begins to float in glycerine, we need to calculate the density of glycerine at various temperatures and compare it to the density of the glass sphere.
The density of glycerine changes with temperature, so we need to use a density-temperature chart or equation to determine the density of glycerine at different temperatures.
Assuming the hollow glass sphere has a uniform wall thickness, we can calculate its volume by subtracting the volume of the hollow interior from the volume of the whole sphere
Volume of sphere = (4/3)π\(r^{3}\)
Volume of hollow interior = (4/3)π\((r-t)^{3}\)
Volume of glass wall = (4/3)π(\(r^{3}\) - \((r-t)^{3}\)), where t is the thickness of the glass wall.
From the density and volume of the glass sphere, we can determine its mass
Mass of glass sphere = Density of glass sphere x Volume of glass sphere
Next, we can use Archimedes' principle to determine the volume of glycerine displaced by the glass sphere when it is submerged in the glycerine
Volume of glycerine displaced = Mass of glass sphere / Density of glycerine at the given temperature
When the glass sphere floats, the volume of glycerine displaced will be equal to the volume of the glass sphere. Thus, we can set the two volumes equal to each other and solve for the temperature at which the density of glycerine matches the density of the glass sphere
Volume of glass sphere = Volume of glycerine displaced
(4/3)π\(r^{3}\) - (4/3)π\((r-t)^{3}\) = Mass of glass sphere / Density of glycerine at the given temperature
Hence, for the temperature requires knowing the radius and thickness of the glass sphere and the mass of the sphere.
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eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,
The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.
What are the golden rules for reporting results?The five golden rules for reporting results are:
Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.Using these rules, identify the mistakes in the given results as:
(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.
(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.
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Which statement is true about the theory of plate tectonics and the theory of continental drift?
A) The theory of plate tectonics proves the theory of continental drift completely wrong.
B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.
C) The theory of plate tectonics gives the method by which continents can move as part of plates.
D) The theory of plate tectonics does not explain how continental movements could occur.
The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .
What is theory of plate tectonics and the theory of continental drift ?According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.
The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.
According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.
Therefore, option C is correct.
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Gases have a definite shape and volume. O A. True O B. False
Answer:
FALSE
Explanation:
What is convectional current?.... .
Answer:
Convection is the transfer of heat from one place to another along with the motion of the object's particles. Water is a poor conductor. However, when the bottom water is heated, it turns out that the top water is also hot. This means that there is another way of transferring heat to the water, namely convection.
Explanation:
A convectional current is a process that involves the movement of energy from one place to another.
Love, which can't be observed or measured directly, is an example of a psychological construct.
Please select the best answer from the choices provided
О Тrue
O False
Answer:
True
Explanation:
A psychological construct can't be observed and you can feel this,
Example: anxiety, anger, sadness
Select ALL the
correct answers.
Which two examples describe ways that corporations can give large donations to presidential candidates?
A corporation leader makes
direct payment to the candidate.
A corporation creates another company to accept candidate contributions
A corporation collects moneys from its employees to contribute to
A corporation contributes to a Super PAC that
a PAC
accepts contributions
for a candidate,
Reset
Next
Answer: Hope this helps ;) don't forget to rate this answer !
Explanation:
There are two correct answers:
A) A corporation leader makes direct payment to the candidate.
D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.
Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.
Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.
I hope this helps! Let me know if you have any other questions.
8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at the
same temperature for at least 1 minute. This means the thermometer is at the same temperature as the
mixture.
9. Record the temperature.
10. Stir the ice-water mixture occasionally for another 5 minutes. Then, record its temperature.
Table B: Part 2 Observations
Initial temperature (in "C) of the room-temperature water
Initial temperature (in "C) of the warm water
Temperature (in "C) of mixed warm water and room-temperature water
Temperature (in "C) of mixed warm water and room-temperature water after 5 min
Temperature (in "C) of mixed warm water and room-temperature water after 10 min
Initial temperature (in "C) of the ice
Temperature (in °C) of mixed ice and room-temperature water
Temperature (in "C) of mixed ice and room-temperature water after 5 min
Physical Science page
The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.
The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.
When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.
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