How would you describe the brightness of the Sun?

Given data

*The given frequency is

*The another given frequency is

*The given speed of light is c = 3.0 × 10^8 m/s

(a)

The formula for the wavelength is given as

Substitute the known values in the above expression as

The another wavelength for the another frequency is calculated as

(b)

Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.

The ball would stationary at the maximum height and accelerated greatly as it falls until it comes to rest on the ground. Option B

The slope of the velocity-time graph represents the acceleration of the object. At the highest point of the object's trajectory, the acceleration is zero, as it is temporarily at rest. As the object starts to fall, its acceleration becomes negative, indicating that it is accelerating downwards due to the force of gravity.

The velocity-time graph is a useful tool for analyzing the motion of an object and understanding its velocity and acceleration at different points in time.

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Teleportation (artificial or natural over wormhole).

Answer:

6

Explanation:

120/30=6

The uterus lining is rebuilt by the end of the menstrual period. The rebuilding of the uterus lining starts after menstruation and the lining is typically completely rebuilt by day 14 of the menstrual cycle, which is when ovulation occurs and the uterus is preparing to potentially receive a fertilized egg.

The endometrium is the inner lining of the uterus, and it thickens every month to prepare for pregnancy. After menstruation, the endometrium grows and thickens to prepare for the implantation of a fertilized egg. The cells in the lining multiply and enlarge, and the glands in the lining begin to secrete mucus and other substances that help support the fertilized egg and promote its growth.

The rebuilding of the endometrium usually takes about two weeks after menstruation. This process is closely regulated by hormones such as estrogen and progesterone, which are produced by the ovaries and other parts of the body. These hormones help control the growth and development of the endometrium and other reproductive tissues.

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Friction affects the work done by machines by reducing the mechanical advantage of that machine.

MA = \(F_{o}\) / \(F_{i}\)

MA = Mechanical advantage

\(F_{o}\) = Output force

\(F_{i}\) = Input force

Mechanical advantage is the ratio of output force to input force in a system.

According to law of conservation of energy, input energy is equal to output energy. It is true in the machines also but some of the output energy is not necessarily asked of the machine. That energy which is not useful is heat produced due to friction.

Therefore, friction affects the work done by machines by reducing the mechanical advantage of that machine.

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Answer:

it is the dependent since it keeps changing over time get it :)

Explanation:

Lungs do not help in the perception and production of sound in humans.

Gaseous exchange occurs during inhalation and exhale during breathing. Main components of the human respiratory system include the nose, mouth, throat, larynx, trachea, bronchi, and lungs.

In humans and other vertebrates, the primary organs for respiration are the lungs. They are situated in the thoracic cavity of the chest, on either side of the heart. The lungs are spongy, anatomically speaking, with a total surface area that ranges from 50 to 75 square meters.

The lungs' main job is to make it easier for gases to move from the blood into the air. It's interesting to note that the right lung is significantly larger and heavier than the left.

Hence, lungs do not help in the perception and production of sound in humans.

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An electrically charged object can be used to attract any object with an opposite charge.

This is due to the fundamental principle that opposites attract and repel in physics.

Electric charge is a fundamental property of matter that gives rise to electromagnetic interactions. An electric charge, whether positive or negative, produces an electric field that surrounds it. This field exerts a force on any other charge in its vicinity that is either attracted to or repelled from it. Electric charge is a fundamental property of matter that produces a variety of electric phenomena. When the charge is concentrated in a localized region of space, the object is electrically charged. When there is a net accumulation of charge in an object, it becomes electrically charged. An electrically charged object produces an electric field in its vicinity, which exerts a force on other charged objects. An electrically charged object can be used to attract objects with an opposite charge or repel objects with the same charge.

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Answer:

6m/s

Explanation:

a = (v-u)/t

acceleration, a

initial velocity, u

final velocity, v

time, t

substitute values and you'll get the answer

Answer:

6 m/s

Explanation:

Answer:

i found this i hope it helps

Explanation:

The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.

The initial velocity of the ball when it left the table is 4.7 m/s.

The initial velocity of the ball is calculated by applying the following kinematic equation as shown below.

vf² = vi² + 2gh

where;

vi² = vf² - 2gh

vi = √(vf² - 2gh)

vi = √(6² - (2 x 9.8 x 0.68) )

vi = 4.76 m/s

Thus, the initial velocity of the ball when it left the table is a function of the final velocity when it hits the ground and the height of fall of the ball.

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The required diameter for certified-capacity liquid rupture discs for the given conditions are 6.08 inches for 500 gpm, 3.07 inches for 100 gpm, 1.29 inches for 5 m/s, and 1.60 inches for 10 m/s.

To calculate the required diameter for certified-capacity liquid rupture discs for the given conditions, we first need to determine the burst pressure for each case. The burst pressure is calculated using the following formula:
Burst Pressure = Set Pressure + Overpressure - Backpressure
Using the specific gravity of 1.2 for all cases, we can calculate the burst pressure for each scenario as follows:
a. 500 gpm: Burst Pressure = 100 psig + 50 psig - 10 psig = 140 psig
b. 100 gpm: Burst Pressure = 100 psig + 50 psig - 5 psig = 145 psig
c. 5 m/s: Burst Pressure = 10 barg + 1 barg - 0.5 barg = 10.5 barg
d. 10 m/s: Burst Pressure = 20 barg + 2 barg - 1 barg = 21 barg
Once we have the burst pressure, we can use the specific gravity and the following formula to calculate the required diameter of the rupture disc:
Diameter = (Flow Rate * 60 * Specific Gravity) / (Burst Pressure * 0.8 * 3.14)
Where:
Flow Rate = Liquid flow in gallons per minute (gpm) or meters per second (m/s)
Specific Gravity = 1.2
Burst Pressure = Calculated burst pressure in psig or barg
Using the above formula, we can calculate the required diameter for each scenario as follows:
a. 500 gpm: Diameter = (500 * 60 * 1.2) / (140 * 0.8 * 3.14) = 6.08 inches
b. 100 gpm: Diameter = (100 * 60 * 1.2) / (145 * 0.8 * 3.14) = 3.07 inches
c. 5 m/s: Diameter = (5 * 60 * 1.2) / (10.5 * 0.8 * 3.14) = 1.29 inches
d. 10 m/s: Diameter = (10 * 60 * 1.2) / (21 * 0.8 * 3.14) = 1.60 inches
Therefore, the required diameter for certified-capacity liquid rupture discs for the given conditions are 6.08 inches for 500 gpm, 3.07 inches for 100 gpm, 1.29 inches for 5 m/s, and 1.60 inches for 10 m/s.

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Answer:

The second Continental Congress started the Continental Army

Explanation:

The Smithsonian was established by the continental congress

Answer:

C. precipitation

Explanation:

if clouds store too much water from evaporation, it will rain which is precipitation

Answer:

wheels

Explanation:

Answer:

Wheels

Explanation:

I know it says check all that apply so you might think it's more than one, but trust me it's right. I took the test :)

Answer:

Alice works with natural rubber and Julio works with vulcanised rubber.

Explanation:

Answer:

B. Alice works with natural rubber, and Julio works with vulcanized rubber.

Explanation:

I just took the test and got 100 percent.

I hope this helps you!!!!

Please mark my answer the Brainiset. Thank You!!!!!

The approximate distance to the galaxy is 78.7 million light-years.

The shift in the absorption line wavelength can be attributed to the Doppler effect, specifically the redshift caused by the expansion of the universe. We can use Hubble's law to estimate the distance to the galaxy. Hubble's law states that the recessional velocity of a galaxy is proportional to its distance from us. The equation is v = H0 * d, where v is the recessional velocity, H0 is the Hubble constant, and d is the distance. Rearranging the equation, we have d = v / H0. The redshift of the absorption line corresponds to the recessional velocity of the galaxy. By knowing the redshift and the Hubble constant, we can calculate the approximate distance. Considering the redshift from the given wavelength shift and using a Hubble constant of 70 km/s/Mpc, we find that the approximate distance to the galaxy is 78.7 million light-years.

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Answer:

In an ideal pulley system is assumed as a perfect system, and the efficiency of the pulley system is taken as 100% such that there are no losses of the energy input to the system through the system's component

However, in a real pulley system, there are several means through which energy is lost from the system through friction, which is converted into heat, sound, as well as other forms of energy

Given that the mechanical advantage = Force output/(Force input), and that the input force is known, the energy loss comes from the output force which is then reduced, and therefore, the Actual Mechanical Advantage (AMA) is less than the Ideal Mechanical Advantage of an "ideal" pulley system

The relationship between the actual and ideal mechanical advantage is given by the efficiency of the pulley system as follows;

\(Efficiency \, \% = \dfrac{AMA}{IMA} \times 100\)

Explanation:

The wavelength of the second line in the Balmer series is 304 nm and fourth line is 1093.7 nm.

The Balmer series in the hydrogen spectrum has spectral lines that are in the visible spectrum.

The wavelength is determined using the Balmer-Rydberg equation.

Wavelength for any two selected lines from the Balmer series of the spectra of hydrogen,

1 / λ = R (1/ n₁² - 1/ n₂²)

Where,

λ is the wavelength,

R is the Rydberg constant (1.0974 x 10⁷ m⁻¹),

n₁ and n₂ are integers where n₂ > n₁.

First, let us choose n₁ = 2, which is the second energy level and we will calculate the wavelength of the second line.

n₂ = 3λ = R(1/2² - 1/3²)

λ = R (4/36 - 1/9)

λ = R (1/36) = (1.0974 x 10⁷ m⁻¹) / 36

λ = 3.04 x 10⁻⁷ m = 304 nm

The wavelength of the second line in the Balmer series is 304 nm.

Now, we will calculate the wavelength of the fourth line.

n₂ = 5n₁ = 2λ = R (1/2² - 1/5²)

λ = R (4/100 - 1/25)

λ = R (3/100) = (1.0974 x 10⁷ m⁻¹) / 100 x 3

λ = 1.0937 x 10⁻⁷ m = 1093.7 nm

The wavelength of the fourth line in the Balmer series is 1093.7 nm.

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Answer:

Acceleration and velocity Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In the simplest case, a force applied to an object at rest causes it to accelerate in the direction of the force.

The position with respect to the horizon would change significantly if the Earth were only 200 miles in diameter, while there would be minimal change if the Earth were 80,000 miles in diameter.

If the Earth were only 200 miles in diameter, the position of objects with respect to the horizon would change significantly. Due to the small size of the Earth, the curvature of the planet would be extremely pronounced. As a result, objects located only a short distance away would appear to be close to the horizon or even below it. The horizon itself would be much closer, and the overall view would be limited.

On the other hand, if the Earth were 80,000 miles in diameter, the position of objects with respect to the horizon would hardly change. With such a large diameter, the Earth's curvature would be less noticeable, and objects at various distances would still appear at or near the horizon.

The change in position with respect to the horizon is determined by the curvature of the Earth. When the Earth is smaller, the curvature is more pronounced, causing objects to appear closer to the horizon. When the Earth is larger, the curvature is less noticeable, resulting in little change in the position of objects with respect to the horizon.

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Answer:

micronutrients.

Explanation:

To calculate the total charge on a finite sheet 0≤x≤1, 0≤y≤1 on the z=0 that has a charge density of rho s=xy(x 2+y 2+25) 2 3 n C/m 2. First, we need to use the formula Q=∫s ρs ds where ds=dx dy.  the total charge on the sheet is 111.31 nC.

Where ρs is the charge density and s is the surface area of the sheet. The surface area of the sheet is given by s=∫∫dx dy.

Therefore, Q=∫s ρs ds=∫∫ρs dx dy.

From the question, ρs=xy(x2+y2+25)^2/3

Therefore,

Q=∫∫x y(x2+y2+25)2/3dxdy = ∫01∫01xy(x2+y2+25)2/3dx dy

Separating out the terms containing y, we obtain;

Q=∫01ydy∫01x(x2+25)2/3dx + ∫01ydy∫01xy2(x2+25)2/3dx ∫01ydy∫01y(x2+y2+25)2/3dx

On integrating, we get;

Q =1/4 [(14+245)(5/3)+(14+245)(5/3)(2/5)+(14+245)(5/3)(2/5)]

=111.31 n C

Therefore, the total charge on the sheet is 111.31 nC.

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To find the Thevenin voltage (VTh) without using Kirchhoff's voltage law (KVL) or Kirchhoff's current law (KCL), we can apply the voltage divider rule. The voltage divider rule states that the voltage across a resistor in a series circuit is proportional to its resistance.

In Figure 8-82, we need to determine the current through the load RL. To do this, we first find the Thevenin voltage (VTh) which is the open-circuit voltage across the load terminals. Here's how we can find it using the voltage divider rule:

Identify the two resistors in series: The 5.6 kQ resistor and the 15 kQ resistor.
Calculate the total resistance (RT) of the series combination: RT = 5.6 kQ + 15 kQ = 20.6 kQ.
Identify the resistor across which you want to find the voltage: In this case, it is the 15 kQ resistor.
Apply the voltage divider rule: \(VTh = (R2 / (R1 + R2)) * VSource\).
  - Substitute the values: \(VTh = (15 kQ / (5.6 kQ + 15 kQ)) * 32 V\).
  - Simplify the expression:\(VTh = (15 kQ / 20.6 kQ) * 32 V\).
  - Calculate VTh:\(VTh ≈ 23.44 V\).
Therefore, the Thevenin voltage (VTh) is approximately 23.44 V.
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Answer:

5.5Ω

Explanation:

The circuit diagram shown is a parallel arrangement. To solve this problem for the equivalent resistance,

  R1  = 10Ω

  R2  = 20Ω

 R3 = 30Ω  

For circuits in parallel, equivalent resistance is ;

   \(\frac{1}{Rt}\)   = \(\frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3}\)  

 Now insert the parameters and solve;

    \(\frac{1}{Rt}\)  = \(\frac{1}{10} + \frac{1}{20} + \frac{1}{30}\)  

    \(\frac{1}{Rt}\)   = \(\frac{6 + 3 + 2}{60}\)  

    \(\frac{1}{Rt}\)   = \(\frac{11}{60}\)  

    Rt  = 5.5Ω

At a distance of approximately 1949.64 meters from the 18 MW point source of electromagnetic waves, the electric field amplitude will be 0.030 V/m.

To find the distance from an 18 MW point source of electromagnetic waves where the electric field amplitude is 0.030 V/m, you can follow these steps:

1. Calculate the power of the source in watts: 18 MW * 10^6 = 18,000,000 W

2. Use the formula for the intensity (I) of the electromagnetic waves: I = Power / (4 * π * distance²)

3. Substitute the given electric field amplitude (E) and calculate the intensity using the formula: I = E² / (2 * μ₀ * c), where μ₀ is the permeability of free space (4 * π * 10^(-7) Tm/A) and c is the speed of light (3 * 10^8 m/s).

I = (0.030²) / \((2 * (4 * π * 10^(-7)) * (3 * 10^8)\)) ≈ 1.1953 W/m²

4. Solve for the distance in the intensity formula.  1.1953 = 18,000,000 / (4 * π * distance²)
  distance² ≈ 18,000,000 / (4 * π * 1.1953) ≈ 3,804,099.39
  distance ≈ √3,804,099.39 ≈ 1949.64 m

At a distance of approximately 1949.64 meters from the 18 MW point source of electromagnetic waves, the electric field amplitude will be 0.030 V/m.

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