How would the calculation change if a typical comet in the Oort cloud is only 1 km in diameter?

The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

include the statements pls so i can choose wich one it is and tell you

Explanation:

Answer:

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.

Given:

The initial shot was fired at an angle of 50 degrees above ground.

The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.

Let the angle of the projectile is x,

The horizontal component of velocity can be calculated as follows:

\(v(x) = v * cos(x)\)

We can write:

since the horizontal part of velocity remains constant:

\(v(x1) = v(x2)\)

\(cos(50) = cos(x)\)

\(50 = x\)

Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.

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The correct response is given when the angle is asked a question.

The increase in the gas's internal energy as a result of this process is energy=+110 cal.

Scientists refer to energy as the ability to work. Human civilization is feasible because people have discovered how to convert energy from one form to another and use it to complete activities.

Energy is a major factor in our everyday routines because it is an fundamental need for humans. Energy not only heats but also cools the structures that humans have built. You need energy to raise your hand get out of bed, or even just walk down the street.

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Answer:In the case of two proton beams the protons repel one another because they have the same sign of electrical charge. There is also an attractive magnetic force between the protons, but in the proton frame of reference this force must be zero! Clearly then the attractive magnetic force that reduces the net force between protons in the two beams as seen in our frame of reference is relativistic. In particular the apparent magnetic forces or fields are relativistic modifications of the electrical forces or fields. As such modifications, they cannot be stronger than the electrical forces and fields that produce them. This follows from the fact that switching frames of reference can reduce forces, but it can’t turn what is attractive in one frame into a repulsive force in another frame.

In the case of wires the net charges in two wires are zero everywhere along the wires. That makes the net electrical forces between the wires very nearly zero. Yet the relativistic magnetic forces and fields will be of the same sort as in the case of two beams of charges of a single sign. This is true even in the frame of reference of what we think as the moving charges, that is, the electrons. In the frame of reference moving at the drift velocity of these current-carrying electrons, it is the protons or positively charged ions that are moving in the other direction. Consequently in any frame of reference for current-carrying wires in parallel, the net electrical force will be essentially zero, and there will be a net attractive magnetic force

Explanation:                                                                              

Explanation:

Particles with similar charges (both positive or both negative) will always repel each other, regardless of their speed or direction.

a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.

bi) the acceleration of the system is 0.4 m/s^2

bii)  the tension in the string is 0.8 N.

Net force = ma

Net force = T - F_friction

where T is the tension force and F_friction is the frictional force.

Substituting the given values, we have:

T - F_friction = ma

T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)

T - 6.0 N = 10.0 kg a

(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:

Net force = ma

where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:

Net force = T

Substituting the given values, we get:

T = ma

T = 2.0 kg x a

To solve for T, we need to find the acceleration of the system.

To find both a and T, we can use the equations we derived above and solve them simultaneously:

T - 6.0 N = 10.0 kg a (equation 1)

T = 2.0 kg x a (equation 2)

Substituting equation 2 into equation 1, we get:

2.0 kg x a - 6.0 N = 10.0 kg a

Solving for a, we get:

a = 0.4 m/s^2

Substituting a into equation 2, we get:

T = 2.0 kg x 0.4 m/s^2 = 0.8 N

Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.

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Answer: 4 s

Explanation:

Given

The ball leaves the hand of student with a speed of \(u=19\ m/s\)

When the hand is \(h=2.5\ m\) above the ground

Using the equation of motion we can write

\(h=ut+\dfrac{1}{2}at^2\)

Substitute the values

\(\Rightarrow 2.5=-19t+0.5\times 9.8t^2\\\Rightarrow 4.9t^2-19t-2.5=0\\\\\Rightarrow t=\dfrac{19\pm \sqrt{(-19)^2-4\times 4.9\times (-2.5)}}{2\times 19}\\\Rightarrow t=4.0049\quad [\text{Neglecting the negative value of }t]\)

Thus, the ball will take 4 s to hit the ground.

Answer:

Condenses on dust

Explanation:

Pls brainiest

Answer:

condenses on dust

Explanation:

(a) The circuit diagram is in the image attached.

(b) The current flowing through the resistor is 0.003 A.

(c) The power dissipated by the resistor is  0.135 W.

(b) The current flowing through the resistor is calculated by applying Ohm's law as follows;

V = IR

I = V/R

where;

I = 45 V / 15,000Ω

I = 0.003 A

(c) The power dissipated by the resistor is calculated as follows;

P = IV

where;

P = 0.003 x 45 V

P = 0.135 W

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The numbers of minutes that were played in a men's Water Polo match is option A: four 7-minute quarters

A water polo game for men comprises of four quarters with each one spanning for 8 minutes of effective play time. Between the initial and subsequent quarters, there is a breather of two minutes, followed by a halftime of five minutes, and then a two-minute interlude between the third and fourth quarters.

The clock ceases to tick during breaks, upon scoring a goal, when the ball is beyond the limits, or when the referee whistles for an offense. The overall duration of a men's water polo game can fluctuate based on the number of interruptions that take place during the match.

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A soccer ball, kicked from ground level at an angle of 64.0° above horizontal, is in the air for 3.40 s. The initial speed, in m/s, just after it was kicked will be 76.07 m/s

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

given

v = 0

g = 9.8 m/\(s^{2}\)

t = 3.40 s

u = ?

cos(theta) = 64°

v = u*cos(theta) - g*t

0 = u * cos(64) - 9.8*(3.40)

u = 76.07 m/s

The initial speed, in m/s, just after it was kicked will be 76.07 m/s

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Answer:

Explanation:

1 gal = 231 in³

231 in³ (2.54³ cm³/in³) = 3,785.411784 cm³

3,785.411784 cm³ (0.01³ m³/cm³) = 0.003785411784 m³

0.003785411784 m³ / 25 m² = 0.00015141647136 m

or approximately 0.15 mm

Answer:

True

Explanation:

The time taken for the ball to reach its maximum height is 1 second.

To calculate the time taken for the ball to reach its maximum height, we can use the kinematic equation for vertical motion. The equation is:

v = u + at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the ball is thrown vertically upwards, so the initial velocity (u) is 10 m/s (considering upwards as positive) and the acceleration (a) is -10 m/s² (negative because it opposes the motion).

The final velocity (v) at the maximum height will be zero because the ball momentarily comes to a stop before reversing its direction. Therefore, we can rewrite the equation as:

0 = 10 - 10t

Simplifying the equation, we get:

10t = 10

Dividing both sides by 10, we find:

t = 1 second

Therefore, the time taken for the ball to reach its maximum height is 1 second.

During this time, the ball covers the distance required to reach the maximum height, overcoming the gravitational acceleration. After reaching the maximum height, it will start to descend towards the ground due to the gravitational pull.

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Since the cruise ship makes its way from one island to another. The ship is in motion is compared with the reference point of option C. a lighthouse on a nearby island.

Sine the cruise ship from one Island  is relocating, the lengthy duration by the passengers within the ship makes it simple to detect the ship motion.

The skipper is the only one who is aware of the ship's direction and speed. Even though the cargo loads are stable and related to the ship's course, we cannot take them into account when calculating the traveling distance of the ship.

Since it is in the sea and relatively close to it, the lighthouse on the island can be used to calculate the distance traveled by ships. Due to its stability, we can use it as a reference point in the water that can be seen from a great distance.

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See full question below

A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

A.

the passengers on the ship

B.

the captain of the ship

C.

a lighthouse on a nearby island

D.

the cargo inside the hull of the ship

Answer:

5.3 hours

Explanation:

(3180 km) / (600 km/h) = 5.3 hours

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

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The magnetic field in the region is into the paper and has a magnitude of 60 mT and the tension in either wire is 0.096 N.

To find the tension in either wire, we can apply the equation for the force experienced by a current-carrying wire in a magnetic field.

The force experienced by a current-carrying wire in a magnetic field is given by the equation F = B * I * L * sin(θ), where B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

In this case, the wire is suspended horizontally by two vertical wires, and the magnetic field is into the paper. Since the wire is horizontal, the angle between the wire and the magnetic field is 90 degrees, so sin(θ) = 1.

The force experienced by the wire due to the magnetic field is F = B * I * L.

Given:

Current (I) = 8.0 A

Magnetic field (B) = 60 mT = 60 * 10^(-3) T

Length of the wire (L) = 40 cm = 40 * 10^(-2) m

Substituting the given values into the equation, we get:

F = (60 * 10^(-3) T) * (8.0 A) * (40 * 10^(-2) m)

Simplifying the expression, we find:

F = 0.192 N

Since the wire is suspended by two vertical wires, the tension in each wire will be half of the total force. Therefore, the tension in either wire is 0.192 N / 2 = 0.096 N.

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The diameter of the smaller end of the pipe is approximately 0.78 meters.

To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.

The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity

Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2

Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2

Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30

Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30

0.36 * 13 = (diameter2/2)^2 * 30

4.68 = (diameter2/2)^2 * 30

Dividing both sides by 30:
0.156 = (diameter2/2)^2

Taking the square root of both sides:
0.39 = diameter2/2

Multiplying both sides by 2:
0.78 = diameter2

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Answer:

Power = Work / Time

P = m g h / t = 80 kg * 9.8 m/s^2 * 15 m / 39 s = 320 N m/ s = 392 J / s

= 392 Watts

The magnitude of power the monkey demonstrated is equal to 392 J/S.

To measure the power of a given body, one must relate its weight, the displacement performed and the time in which the movement was performed, in such a way:

                                              \(P = \frac{m\times g\times d}{t}\)

Thus, applying the values ​​given by the statement we have:

                                          \(P = \frac{80 \times 9.8 \times 15}{30}\)

                                           \(P = 392 J/s\)

So, the power performed by the monkey climbing 15 meters is equal to 392J/s.

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AnswerHM???

Explanation:

I dONT KNOW

Answer:

Distance: 21km

Displacement: ~16.76km

Answer:

4.3 g/cm³ or 4.3g/cc

Explanation:

Volume(V) = Height × Length × Width

= 5cm × 3cm × 2cm

= 30cm³

Mass(m) = 129gram

So,

Density = m/V

= 129g/30cm³

= 4.3g/cc or 4.3g/cm³

Answer:

Good conductor of heat

Explanation:

Because metals are shiny, ductile, malleable, sonorous, good conductors of heat and electricity and have high melting and boiling points

Answer: mine is different so im sorry im here for points

Explanation:

Answer:

C. R^2

Explanation:

A cyclotron is a particle accelerator which employs the use of electric and magnetic fields for its functioning. It consists of two D shaped region called dees and the magnetic field present in the dee is responsible for making sure the charges follow the half-circle and then to a gap in between the dees.

R is denoted as the radius of the final orbit then the final particle energy is proportional to the radius of the two dees. This however translates to the energy being proportional to R^2.

Solution :

Owing to the continuous attraction and repulsion force caused by the magnet or the electromagnet around the core of the motor produces a unidirectional torque whose direction is given by the Lorentz force, \($F=q(\vec v \times \vec B)$\), and thus the torque causes the rotation of the electric motor.

Removing half the insulation from the coil makes it to rotate just half a turn. When the half insulation is removed, the coil turns half and the rest of the time the connection terminates. The rest half turn will be provided by the angular momentum. Now after this half turn by the angular momentum, the connections will again be connected and again the torque will work on it to rotate the half turn. This continues and the motor rotates.