How will the positions of the police car and the truck compare when they have the same speed and why?

Answers

Answer 1

Answer:

Two cars of equal weight and braking ability are travelling along the same road but combined with other factors it could mean the difference between life.


Related Questions

Rex flips a coin vertically upwards with an initial velocity of 2.62m/s. Determine the height to which the coin will rise above the initial height. At what velocity is the coin moving when the coin returns to Rex's hand and he catches it.

Answers

Givens.

• The initial velocity is 2.62 m/s.

It's important to notice that the velocity of the coin at its maximum height point is zero because the coin will stop instantaneously to then go down. Also, the acceleration due to gravity is g = 9.8 m/s^2.

Use a formula that relates, initial velocity, final velocity, gravity, and height.

\(v^2_f=v^2_0+2gh_{}_{}\)

Where v_0 = 2.62 m/s, v_f = 0, and g = 9.8 m/s^2.

\(\begin{gathered} 0=(2.62\cdot\frac{m}{s})^2+2(-9.8\cdot\frac{m}{s^2})h_{\max } \\ 0=6.86\cdot\frac{m^2}{s^2}-19.6\cdot\frac{m}{s^2}\cdot h_{\max } \\ -6.86\cdot\frac{m^2}{s^2}=-19.6\cdot\frac{m}{s^2}\cdot h_{\max } \\ h_{\max }=\frac{-6.86\cdot\frac{m^2}{s^2}}{-19.6\cdot\frac{m}{s^2}} \\ h_{\max }=0.35m \end{gathered}\)

Therefore, the height is 0.35 meters.

At the moment the coin is in Rex's hand again, the velocity is 2.62 m/s because the movement is symmetrical, which means the movement downwards develops the same magnitudes but in opposite direction.

a) A bus of mass 760 kg requires 120 m to reach certain velocity value Vf. Ignore friction and drag forces and assume the bus engine exerts a constant forward force F. When the bus is towing a 330-kg small car, how long distance needed to reach same Vf? b) If the Vf of the bus is 28 m/s, what is the tension in the tow cable between bus and small car?

Answers

Answer:

Given :  A bus of mass 760 kg requires 120 m to reach certain velocity value Vf.

the bus engine exerts a constant forward force F.

To Find : When the bus is towing a 330-kg small car, how long distance needed to reach same Vf?

Solution:

V²  - U² = 2aS

V = Vf

U = 0

S = 120 m

=> Vf² - 0 = 2a(120)

=> Vf² = 240a

m = 760  kg

Force = F

F = ma

=> F =760 a

=> a = F/760

Vf² = 240F/760

Case 2  :When the bus is towing a 330-kg small car,

m = 760 + 330 = 1090 kg

a = F/1090

Vf²  = 2aS

=> 240F/760  = 2 (F/1090) S

=> S = 120 x 1090 /760

=> S = 172.1   m  

172.1   m   distance needed to reach same Vf

Explanation:

a student measured the length of awire four times using ameter rule and obtained the following reading 18.6,18.5,18.6,18.5 determine the length

Answers

A student measured the length of a wire four times using a meter rule, then average length will be 18.55 cm

A student measured the length of a wire four times using a meter rule and obtained the following reading 18.6,18.5,18.6,18.5.

To determine the length of the wire, we need to calculate the average of the four measurements.

Wadding up all the readings and dividing by the number of readings.

Average length = (18.6 + 18.5 + 18.6 + 18.5) / 4

Average length = 74.2 / 4

Average length = 18.55 cm

Therefore, the length of the wire is approximately 18.55 cm.

The question is incomplete and the complete question is

'' A student measured the length of a wire four times using a meter rule and obtained the following readings: 18.6 cm; 18.5 cm and 18.6 cm. Determine the length the length the student should record''.

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When vectors B+A=5i-j and B-A=i-7j, what is the magnitude and direction of vector A?

Answers

Answer:

2i-j, if b+a = 5i-j then b-a -b+a will give you a

Kevin takes his dog out for a walk every day after work. He parks his car behind his home and uses the back door to get in. His dog waits for him every afternoon by the back door, knowing that Kevin will take him for a walk when he returns from work. Kevin's wife usually uses the front door to get in and out of the house. However, one afternoon, Kevin's wife arrives from work early and decides to home into the house using the back door. As she starts opening the back door, the dog starts running around like crazy, thinking its time for his walk. In this scenario, the CR is

Kevin takes his dog out for a walk every day after work. He parks his car behind his home and uses the

Answers

Answer:

In this scenario, the CR (conditioned response) is the dog's behavior of running around like crazy upon hearing the sound of the back door opening. This behavior has been conditioned by the repeated pairing of the back door opening with Kevin taking the dog for a walk. The dog has learned to associate the sound of the back door opening with the upcoming walk, which causes the conditioned response of excitement and anticipation.

Explanation:

The conditioned response (CR) in this scenario is the dog running around like crazy when Kevin's wife starts opening the back door. The dog has learned to associate Kevin's return from work with going for a walk, and the sound of the back door opening has become a conditioned stimulus (CS) that elicits the CR of excitement and anticipation for the walk. When Kevin's wife opens the back door, the dog responds with the same CR, even though it's not Kevin returning from work.

A ball is thrown horizontally from the roof of a building 55 m tall with a speed of 3.8 m/s. how much later does it hit the ground?

Answers

The horizontal distance is given by x is 209m.Horizontal acceleration of a projectile is always 0 since nothing can accelerate a projectile in that direction.

How does a ball being thrown horizontally affect its velocity?Gravity causes a vertical acceleration that has a value of 9.8 m/s/s downward and a constant horizontal velocity of a projectile (a value that never changes). The horizontal motion of a projectile is unrelated to its vertical motion, which changes by 9.8 m/s each second.Horizontal acceleration of a projectile is always 0 since nothing can accelerate a projectile in that direction.As x = V t x = V t x=Vt, one can write the horizontal distance. Using the equation y = - 1 2 g t 2 y = - frac 1 2 g t 2 y=-21gt2, where g is the acceleration due to gravity and h is an elevation, one can calculate one's vertical distance from the ground.

Explanation:

The horizontal distance x = vt = (3.8 m/s)(55s) = 209 m.

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2 A rectangular storage tank 4 m long by 3 m wide is filled with paraffin to a depth
of 2 m. Calculate:
a the volume of paraffin
c the weight of paraffin
b the mass of paraffin
d the pressure at the bottom of the tank due
to the paraffin
1m

Answers

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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The gravitational potential energy of a 4 kg book is 98 J. what is its height​

Answers

The height of the 4 kilograms book with a gravitational potential energy of 98 Joules is approximately 2.5 meters.

How to determine the height of an object with a gravitational potential energy?

Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.

It is expressed as;

U = m × g × h

Given that:

Gravitational potential energy of the book U = 98 Joules

Mass of the book m = 4 kilograms

Acceleration due to gravity g = 9.8 m/s²

Height h = ?

Plug these values into the above formula and solve for height.

U = m × g × h

h = U / ( m × g )

h = 98  / ( 4 × 9.8 )

h = 98/39.2

h = 2.5 meters

Therefore, its height is 2.5 meters.

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What is the ratio of the earth's gravitational force on you, to your gravitational force on the earth?

Answers

Answer: 10%

Explanation:

n this case, if the earth' mass goes up by 10%, then the force of gravity on you, or your weight, will increase by the same amount, that is 10%

9. F = 12 N
m = 50 kg
a=

Answers

Answer:

The answer is 0.24 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{F}{m} \\ \)

where

F is the force

m is the mass

a is the acceleration

So we have

\(a = \frac{12}{50} = \frac{6}{25} \\ \)

We have the final answer as

0.24 m/s²

Hope this helps you

What’s the atomic number for magnesium

Answers

Answer:

12

Explanation:

Symbol: Mg

Atomic mass: 24.305 u

Atomic number: 12

Density: 1.738 g/cm³

A baseball pitcher throws a fastball at a speed of 44 m/s. The acceleration occurs as the pitcher holds the ball in his hand and moves it through an almost straight-line distance of 3.5 m. Calculate the acceleration, assuming it is uniform. Compare this acceleration to the acceleration due to gravity.

Answers

v = s/t

44 m/s = 3.5 m/t

t = 3.5 m : 44 m/s

t = 0.08 s

a = v/t

a = 44 m/s/0.08 s

a = 550 m/s²

a : g = 550 m/s² : 10 m/s²

a : g = 55 : 1

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Help me please I need it as soon as possible

Help me please I need it as soon as possible

Answers

Answer: B im sorry if its wrong

Explanation:

I think the answer would be D


Jibari walks 40.0 meters east in 120.0 seconds. He then walks 30.0 meters west in 60.0 seconds. What is his average velocity for the trip?

Answers

Answer:

0.1667 meters/second.

Explanation:

To find Jibari's average velocity for the trip, we need to first calculate his average velocity for each leg of the trip. To do this, we need to divide the distance he traveled by the time it took him to travel that distance.

For the first leg of the trip, Jibari walked 40.0 meters east in 120.0 seconds. His average velocity for this leg of the trip is therefore 40.0 meters / 120.0 seconds = 0.3333 meters/second east.

For the second leg of the trip, Jibari walked 30.0 meters west in 60.0 seconds. His average velocity for this leg of the trip is therefore 30.0 meters / 60.0 seconds = 0.5000 meters/second west.

To find Jibari's average velocity for the entire trip, we need to add the velocities for each leg of the trip, taking into account their direction. Since the first leg of the trip was east and the second leg was west, we can simply add the two velocities together to find the overall average velocity.

Jibari's overall average velocity for the trip is therefore 0.3333 meters/second east + 0.5000 meters/second west = 0.1667 meters/second.

Therefore, Jibari's average velocity for the trip was 0.1667 meters/second.

Jibari's average velocity for the trip is 0.7 m/s east.

To solve for Jibari's average velocity, we will first need to find his total displacement. We can do this by adding the magnitudes of his eastward and westward displacements. The magnitude of Jibari's eastward displacement is 40.0 meters, and the magnitude of his westward displacement is 30.0 meters. So, his total displacement is

40.0 - 30.0 = 10.0 meters east.

We can then find Jibari's average velocity by dividing his total displacement by the total time it took him to complete the trip. The total time it took Jibari to complete the trip is

120.0 + 60.0 = 180.0 seconds.

So, his average velocity is

10.0 / 180.0 = 0.7 m/s east.

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An object is spun in a circle of radius 1.5m with a frequency of 6.0Hz. what is it’s velocity ?

Answers

Answer:

56.55 m/s

Explanation:

Frequency=1/T

1/6 = 0.1666666

V=(2*pi*1.5)/0.166666

Which of the following would you expect to be a strong electrolyte in solution?

Answers

The following would expect to be a strong electrolyte in solution (b) KCI is correct option.

When dissolved in water, a strong electrolyte produces a large concentration of ions in solution by totally dissociating into ions.  The following compounds are typically strong electrolytes in solution according to this definition:

Al(OH)₃ (aluminum hydroxide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.KCl (potassium chloride) is a strong electrolyte. It completely dissociates into potassium ions (K⁺) and chloride ions (Cl⁻) in solution, resulting in a high concentration of ions and a high electrical conductivity.PbI₂ (lead(II) iodide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.

These substances readily dissociate into ions in water and exhibit high electrical conductivity, making them strong electrolytes in solution.

Therefore, the correct option is (b).

The complete question is,

Which of the following would be a strong electrolyte in solution?

a) Al(OH)₃ b) KCI c) Pbl₂

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words for blanks: Spread out, spin, slowing, acceleration, heats, cools, increased, decreased.
a. The extra density in some areas ------------ the gravitational pull, --------- and then reversing the expansion that occurred due to the cosmological expansion, forming protogalactic gas clouds. The gas cloud begins to form stars, but the star formation does not use up all the gas.
b. The angular momentum of the original gas cloud causes the gas cloud to ------- and flatten out as it collapses, gas particles collide, and the gas , ------------thereby forming the disk of a spiral galaxy out of the leftover gas.

Answers

a.) Increased, heats, acceleration. b.) cools, decreased, slowing

Why does the universe expand?

The early expansion of the cosmos was powered by energy from the Big Bang. Since that time, a cosmic tug of war has been going on between gravity and dark energy. The force of gravity draws galaxies together. Which force—gravity or dark energy—dominates determines whether the cosmos is expanding or contracting.

What does the cosmic expansion law entail?

Edwin Hubble found in the 1920s and 1930s that the Universe is expanding and that galaxies are separating from one another at a speed determined by an equation known as Hubble's Law: v = H*r.

How quickly is the cosmos expanding?

According to a report in The Astrophysical Journal, scientists who have used the seasoned space telescope have calculated that the Universe is expanding at a rate of 73 kilometers per second per megaparsec plus.

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i want to quit guitar how should I tell my parents

Answers

Answer:

You should tell them that your just not interested in it anymore and that you would like to do something else besides playing guitar you should probably explain to them why you dont want to play anymore. I hoped this helped- Best of luck.

Explanation:

Answer:

You should tell them that your just not interested in it anymore and that you would like to do something else besides playing guitar you should probably explain to them why you dont want to play anymore. I hoped this helped- Best of luck.

Explanation:

If enough experimental data supports a hypothesis, then it:
A. Is accepted as true until proven false.
B. Becomes an Observational Law
C. Is proven 100% true.
D. Is falsified.

Answers

If enough experimental data supports a hypothesis, it is considered a well-supported scientific theory, but it is not considered to be 100% true or proven. Scientific theories are always open to further investigation and revision based on new evidence. Therefore, option C ("Is proven 100% true") is incorrect.

Option A ("Is accepted as true until proven false") is also incorrect because scientists do not accept a hypothesis as true until it has been rigorously tested and supported by a large body of evidence. Even then, scientists recognize that any scientific theory is subject to revision or falsification if new data or evidence emerges that contradicts it.

Option B ("Becomes an Observational Law") is also incorrect because scientific laws are typically descriptive, rather than explanatory. They describe what happens in a given set of circumstances, but they do not explain why it happens. Hypotheses and theories, on the other hand, attempt to explain why certain phenomena occur, and they are supported by experimental evidence.

Therefore, none of the options are completely accurate, but the most appropriate answer is that the hypothesis becomes a well-supported scientific theory.

An electric car can go 150 km on a test track at a constant speed of 100 km/hr on one charge of its batteries. The test track is an oval with no stops or other cars. You can assume that air resistance is the only form of friction. How far can it go on the test track if it moves at a constant speed of 50 km/hr?

Answers

Answer:

75km

Explanation:

First we need to understand for how long the battery can work. We can do that by dividing the total distance traveled by the speed of the race car. Since we do have both measurements required we can find the time. And so we get......

\(\frac{150km}{100km/hr} = 1.5 hours\)

Now in order to find distance traveled by an object we need to multiply its speed by the time it traveled. Now since we have both of this measurements  we can fin the traveling distance.  We do ......

\(\frac{50km}{1hour}\) x \(1.5 hours\) = \(75km\)

And just like this we get the answer 75km

a good ____ does not transfer heat easily

Answers

Answer:

a good insulator does not transfer heat easily.

An insulator does not conduct heat easily and does not leave the heat energy or else say transfer the heat quickly; also referred as poor conductors of heat.

Answer:

good insulater

Explanation:

Insulater just less transfers the heat and stores the heat in itself.All non metals are good insulaters and poor conductorsOnly graphite is a non metal which conduct electricity

The kinematic equations can describe phenomena other than motion through space and time. Suppose x represents a person’s bank account balance. The units of x would be dollars ($), and velocity v would give the rate at which the balance changes (in units of, for example, $/month). Acceleration would give the rate at which v changes. Suppose a person begins with ten thousand dollars in the bank. Initial money management leads to no net change in the account balance so that v0 5 0. Unfortunately, management worsens over time so that a 5 22.5 3 102 $/month2 . Assuming a is constant, find the amount of time in months until the bank account is empty.​

Answers

We can use the kinetic equation that combines velocity, acceleration, and time to calculate the number of months until the bank account is empty:

\(v = v_0 + at\)

Since initially there is no net change in the account balance, the initial velocity \((v_0)\)in this case is 0. 22.5 * $102 per month expressed as Acceleration (a). The moment (t) at which the account balance reaches zero must be determined.

We can arrange the equation to solve for time as follows:

\(0 = 0 + (22.5 * 10^2) * t\)

When we simplify the equation, we get:

2250t = 0

After 0 months the account balance will be zero as the result of the calculation will be 0. This shows that the bank account is currently empty or will be empty soon.

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A ball is launched vertically upward from ground level with an initial velocity of 30 m/s. How much time does it take before it lands on the ground?

Answers

This problem has to be broken down into two parts: the trip up and the trip down. Using the equation Vf^2=Vi^2+2(a)(d) we can substitute the following values:
Vf= 0m/s
Vi= 30m/s
a= -10m/s (use 9.81 for regents physics)
d=?
t=?

we can now solve the equation-
(0m/s)=(30m/s)+(-10m/s^2)(t)

giving us t=3sec

this is the time for the trip up only, however we know that the trip up= the trip down, so the time is 6 seconds.

Hope this helps!

) An object travels 20 m in 4 s heading south. What is its' velocity? ating very wed and is as velocity as to the change in 3 What is the expects relation​

Answers

Answer:

Velocity become 5 m/s south,

I didnt get from second line.....

How much charge must pass by a point in a wire in 1.5 s for the current inb the wire to be 2.0 A?

Answers

Answer:

3 Coulombs

Explanation:

Q = Current x time

Q = 2.0 x 1.5

Q = 3 Coulombs

Question 13 of 25
Which of the following best describes the function of an electric motor?
29
о A. Converts stored potential energy into mechanical energy
B. Converts mechanical energy into electrical energy
о C. Converts electric energy into mechanical energy
D. Converts the voltage of an alternating current source
SUB

Answers

An electric motor converts electric energy into mechanical energy. So, the right option is C.

In contrast to an electric generator, an electric motor transforms electrical energy into mechanical energy.

They function according to electromagnetism's principles, which demonstrate that a magnetic field's electric current exerts a force.

In the magnetic field, this force produces a torque that spins a loop of wire, causing the motor to function.

Fans, power tools, appliances, electric vehicles, and hybrid vehicles are just a few examples of the many uses for electric motors.

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A 375 N unbalanced force was applied to a 45 kg object at rest. How far would this object travel after 7 seconds?

Answers

Answer:204.2

Explanation:

F = 375 N

M = 45 KG

T = 7 SECONDS

U = 0

S = ?

F = ma

a = F/M

= 8.33m/s

from second equation of motion

s = ut + 1/2at^2

S = 204.166....

why is nut-cracker 2nd class lever?​

Answers

2nd class leaver refers to such leaver in which load lies between effort and fulcrum.In a nut cracker too load is in between effort and fulcrum.Thus, nut cracker is a 2nd class leaver.......

A 1 000 kg car is pulling a 300 kg trailer. Together, the car and trailer move forward with an acceleration of 2. 15 m/s². Ignore any force of air drag on the car and all friction forces on the trailer. Determine (a) the net force on the car​

Answers

(a) A 1 000 kg car is pulling a 300 kg trailer, together the car and trailer move forward with an acceleration of 2. 15 m/s² the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

To determine the net force on the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The total mass of the car and trailer combined is the sum of their individual masses: 1,000 kg + 300 kg = 1,300 kg.

The acceleration of the car and trailer system is given as 2.15 m/s².

Using Newton's second law:

Net force = mass × acceleration

Net force = 1,300 kg × 2.15 m/s²

Net force ≈ 2,795 N

Therefore, the net force acting on the car (and trailer) is approximately 2,795 Newtons (N).

This net force is responsible for accelerating the combined mass of the car and trailer in the forward direction. It represents the sum of all external forces acting on the system, such as the force exerted by the car's engine and the tension in the connection between the car and trailer.

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how long would it take for a resultant upward force of 100 N to increase the speed of 50 Kg object from 100 m/s to 150 m/s ?

With explanations please....and the very ways..

Answers

Answer:

\(force = mass \times acceleration \\ 100 = 50 \times a \\ a = 2 \: {ms}^{ - 2} \\ from : \: \: v = u + at \\ 150 = 100 + (2 \times t) \\ 50 = 2t \\ time = 25 \: seconds\)

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