how to use Lcd in this problem? [a-2. -_1_ =_3_]find Lcd [ a+3 1 a-2]. (a+3)(a+2). multiply all neumerator to (LCD) a-2 - 1= 3 ___ _ a/+3. a+/2 (a-6 )(a+6) - 1 (a+2)(a+3)(a+2/)/*) negative a +positive2: distribuet: (a(a+3)++2. = (a+3)​

Answer:

9 out of 16 chances three red marbles are gonna come out

Answer:

the answer would be (7,5)

Answer:

Step-by-step explanation:

1)  DE = 6/sin63 = 6.7

DF = 6/tan63 = 3.1

m∠E = 180 - 90 - 63 = 27°

2)  tan30 = 1/√3 = UV / (27√10)

UV = (27√10) / √3 · (√3/√3) = (27√30) / 3 = 9√30

3)  cosV = 3/8

cos⁻¹(3/8) = 68

m∠V = 68°

Answer:

C. x=-5 or x=20

Step-by-step explanation:

Factor \(x^{2}\)-15x−100 using the AC method

(x-20)(x+5)=0

If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0

x−20=0

x+5=0

Set x−20 equal to 0and solve for x

x=20

Set x+5 equal to 0 and solve for x

x=−5

The final solution is all the values that make (x−20)(x+5)=0 true. The multiplicity of a root is the number of times the root appears.

x=20(Multiplicity of 1)x=−5 (Multiplicity of 1)

The solutions to the equation x² - 15x - 100 = 0 are:

x = 20 and x = -5.

Solutions are the values of an equation where the values are substituted in the variables of the equation and make the equality in the equation true.

We also find the solution in a system of equations using the substitution or elimination method.

Example:

2x + 4 = 8

The solution is x = 2.

We have,

To use the zero product property to solve the equation:

x² - 15x - 100 = 0.

Factor the left-hand side of the equation:

(x - 20)(x + 5) = 0

Apply the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero:

x - 20 = 0 or x + 5 = 0

Solve for x in each equation:

x - 20 = 0

x = 20

x + 5 = 0

x = -5

Therefore,

The solutions to the equation x² - 15x - 100 = 0 are:

x = 20 and x = -5.

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Step-by-step explanation:

what is missing is the definition that QS is the height and therefore standing at a right angle (90°) at PR.

then this can be solved.

we use Pythagoras

c² = a² + b²

c being the Hypotenuse (the side opposite of the 90° angle), a and b are the legs.

let's start with the triangle PQS.

21² = 15² + QS²

441 = 225 + QS²

QS² = 216

QS = sqrt(216) = sqrt(36×6) = 6×sqrt(6) = 14.69693846...

now for triangle QSR

(5x - 16)² = (3x - 4)² + QS²

25x² - 160x + 256 = 9x² - 24x + 16 + 216

16x² - 136x + 24 = 0

2x² - 17x + 3 = 0

the solution to a quadratic equation

ax² + bx + c = 0

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = (17 ± sqrt(17² - 4×2×3))/(2×2) =

= (17 ± sqrt(289 - 24))/4 = (17 ± sqrt(265))/4

x1 = (17 + 16.2788206...)/4 = 8.319705149...

x2 = (17 - 16.2788206...)/4 = 0.180294851...

but using x2 in side lengths 3x - 4 or 5x - 16 gives us negative side lengths. that does not make any sense for actual side lengths.

so, x1 is our solution :

x = 8.319705149...

Solution

Step 1:

The domain of a function is the set of input or argument values for which the function is real and defined.

Step 2

The positive values of logs: x > 4

Final answer

The function domain

x > -4

Answer:

-7/4

Step-by-step explanation:

we can see that every time the value of x increases by 4, the value of y decreases by 7.

let's pick two sets of coordinates (first two will be fine).

that is (-4, 6) and (0, -1)

Slope = (change in y values) / (change in x values)

= (-1 - 6) / (0 - -4)

= -7 / (0 + 4)

= -7/4.

so our slope (gradient) is -7/4

Answer: Yes They are

Step-by-step explanation:

The dashes show that they are congruent they both are the same

Answer:

a. 67°

b. 3.9 ft

Step-by-step explanation:

a) the angle formed by the ladder and the level ground = sin`¹ 0.92 = 67°

b) the distance between the foot of the ladder and the foot of the building = 10× cos 67°

= 10 × 0.39 = 3.9 ft

The surface area of the base ball to the nearest whole number is 26 in²

A sphere is defined as the set of all points in three-dimensional Euclidean space that are located at a distance.

The area occupied by a three-dimensional object by its outer surface is called the surface area.

The surface area of a sphere is expressed as;

SA = 4πr²

where r is the radius and it's calculated as;

C = 2πr

9 = 2πr

r = 4.5/π =

SA = 4 π × (4.5/π)²

SA = 81/π

SA = 26 in²( nearest whole number)

Therefore the surface area of the sphere is 26 in²

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The length of the arc CD is 14.13 centimeters.

Remember that for an arc defined by an angle a in a circle of radius R, the length of the arc is given by:

L  = (a/360°)*2*pi*R

Where pi = 3.14

Here the angle is a = 45°

And R = 18cm, so we can replace that in the formula above to find the length.

L = (45°/360°)*2*3.14*18cm = 14.13cm

That is the length of the arc CD.

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The sales tax rate is 2%.

The probabilities are given as follows:

3. P(rides bus|owns a car) = 1/3.

4. P(red|organic) = 3/5.

The probability of an event in an experiment is obtained as the number of desired outcomes of the experiment divided by the number of total outcomes of the experiment.

For item 3, the outcomes are given as follows:

Hence the probability is:

P(rides bus|owns a car) = 8/24 = 1/3.

For item 4, the outcomes are given as follows:

The error was in identifying the total outcomes, and the probability is:

P(red|organic) = 18/30 = 3/5.

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(-3, 3) and (4, -1) are the points that can be used to form a right triangle to derive the distance formula to find the length of the line segment

Given the line on the xy-plane, we are to determine the points on the line that can be used to determine the distance between the two points.

The required points on the line will be the two endpoints on the line. The end points are (-3, 3) and (4, -1). The distance between this points is expressed as:

D = √(-1-3)²+(4+3)²
D = √14 + 49
D = √63

Hence the points that can be used to form a right triangle to derive the distance formula are (-3, 3) and (4, -1)

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Answer: It’s -1,-3

Step-by-step explanation:

got 100 on the test

1) We can find the slant asymptotes by working with limits. So let's begin with that, by calculating the side limits of this function to check its behavior.

Note that here we performed some limits properties, a bit simplified due to the time. But the point here is the behavior of this function.

2) As we know the slant asymptotes are y=6x and y=-6x so we cn

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

Brian is constructing figures inscribed in circle C.

Equilateral triangle MNQ inscribed in circle C:

This option is possible since the points M, N, and Q are labeled and they lie on circle C.

Equilateral triangle ANP inscribed in circle C:

This option is not possible. The points A and P are labeled, but the third vertex of the equilateral triangle is not specified.

Regular hexagon AMNBPQ inscribed in circle C:

This option is possible since the points A, M, N, B, P, and Q are labeled and they lie on circle C.

Square MNPQ inscribed in circle C:

This option is not possible based on the given information. The label points do not form a square.

Square ANBQ inscribed in circle C:

This option is not possible . The points A, N, B, and Q are labeled, but they do not form a square.

The correct options that could be constructed by Brian using his straightedge to draw some chords of circle C are:

Equilateral triangle MNQ inscribed in circle C

Regular hexagon AMNBPQ inscribed in circle C

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Answer:

Step-by-step explanation:

Assuming that the given dimensions of 13, 13, 13 refer to the base of the rectangular pyramid, we can calculate the surface area of the pyramid as follows:

First, we need to calculate the area of the rectangular base, which is simply length x width:

Area of rectangular base = 13 x 13 = 169 square units

Next, we need to calculate the area of each triangular face of the pyramid. Since the rectangular base has two sets of parallel sides, there are two types of triangular faces: the isosceles triangles on the sides and the right triangles on the front and back.

To calculate the area of the isosceles triangles, we need to first find the length of the slant height, which can be found using the Pythagorean theorem:

a² + b² = c²

where a and b are the base and height of the triangle (both equal to 13 in this case), and c is the slant height.

13² + 13² = c²

338 = c²

c ≈ 18.38

Now that we have the slant height, we can calculate the area of each isosceles triangle using the formula:

Area of isosceles triangle = (1/2) x base x height

Area of isosceles triangle = (1/2) x 13 x 18.38

Area of isosceles triangle ≈ 119.14 square units

To calculate the area of each right triangle, we need to use the same slant height of 18.38, along with the height of the pyramid, which is also 13. Then we can use the formula:

Area of right triangle = (1/2) x base x height

Area of right triangle = (1/2) x 13 x 18.38

Area of right triangle ≈ 119.14 square units

Since there are two of each type of triangular face, the total surface area of the pyramid is:

Surface area = area of rectangular base + 2 x area of isosceles triangle + 2 x area of right triangle

Surface area = 169 + 2 x 119.14 + 2 x 119.14

Surface area = 546.28 square units

Therefore, the surface area of the rectangular pyramid with base dimensions of 13 x 13 and height of 13 is approximately 546.28 square units.

The value for differential equation is found as -

\(\frac{dP}{dt} =\frac{d}{dt} (\frac{c_1e^t}{1+c_1e^t})\\\)

\(\frac{dP}{dt} - (\frac{c_1e^t}{(1+c_1e^t)} )(1-\frac{c_1e^t}{(1+c_1e^t)^2})\\ =(\frac{c_1e^t}{(1+c_1e^t)^2} )-(\frac{c_1e^t}{1+c_1e^t})(1-\frac{c_1e^t}{1+c_1e^t})=0\)

What is differential equation?

Any equation with one or more terms and one or more derivatives of the dependent variable with respect to the independent variable is referred to as a differential equation.

The equation given is - \(P=\frac{c_1e^t}{1+c_1e^t}\)

Take derivative with respect to t -

\(\frac{dP}{dt} =\frac{d}{dt} (\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =\frac{d}{dt}c_1 (\frac{e^t}{1+c_1e^t})\)

By Quotient rule \(\frac{d}{dt} \frac{u}{v} =\frac{v\frac{du}{dt}- u\frac{dv}{dt}}{v^2}\) -

\(\frac{dP}{dt} =c_1 (\frac{(1+c_1e^t)\frac{d}{dt}(e^t)-(e^t)\frac{d}{dt}(1+c_1e^t)}{(1+c_1e^t)} )\\\frac{dP}{dt} =c_1 (\frac{(1+c_1e^t)(e^t)-(e^t)(0+c_1e^t)}{(1+c_1e^t)} )\)

(\(\frac{d}{dx} e^t=e^t\) and \(\frac{d}{dx} c_1=0\) here \(c_1=\)constant)

\(\frac{dP}{dt} =c_1e^t (\frac{(1+c_1e^t-c_1e^t)}{(1+c_1e^t)^2} )\\\frac{dP}{dt} = (\frac{(c_1e^t)}{(1+c_1e^t)^2} )\)

Now, \(\frac{dP}{dt} =P(1-P)\) -

\(\frac{dP}{dt} - (\frac{c_1e^t}{(1+c_1e^t)} )(1-\frac{c_1e^t}{(1+c_1e^t)^2})\\ =(\frac{c_1e^t}{(1+c_1e^t)^2} )-(\frac{c_1e^t}{1+c_1e^t})(1-\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1}{1+c_1e^t}-1+\frac{c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1-(1+c_1e^t)+c_1e^t}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{1-1-c_1e^t+c_1e^t}{1+c_1e^t})\\\)

\(\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(\frac{0}{1+c_1e^t})\\\frac{dP}{dt} =(\frac{c_1e^t}{(1+c_1e^t)} )(0)\\\frac{dP}{dt} =0\)

Therefore, the value is \(\frac{dP}{dt} =0\).

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The highest height for the daily rainfall were for 5 and 6 inches

Dot plots are used to present data in the form of points or small circles. It is similar to a simplified histogram or bar graph in that the height of the bar made up of points represents the numerical value of each variable. Dot plots are used to represent small amounts of data.

From the given dot plot, we see the number of times for each height of rainfall.

Thus, we see that the highest number of times of rainfall height was from that of 5 and 6 inches.

Thus, we conclude those were the highest heights for the daily rainfall.

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Answer:

  C = (18, 6)

Step-by-step explanation:

You have ...

  AB : BC = 1 : 1/3 = 3 : 1

  (B -A) / (C -B) = 3/1 . . . . . another way to write the distance relation

  B -A = 3(C -B) . . . . . . . . . multiply by (C-B)

  4B -A = 3C . . . . . . . . . . . add 3B

  C = (4B -A)/3 . . . . . . . . . divide by 3 to get an expression for C

  C = (4(14, 4) -(2, -2))/3 = (54, 18)/3

  C = (18, 6)

Answer: 14%

Step-by-step explanation: To find the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade, we divide the number of members who meet both criteria (14) by the total number of members (100) and multiply by 100 to get a percentage. Therefore, the probability is approximately 14%.

- Lizzy ˚ʚ♡ɞ˚

Certainly! The problem can be solved using the Pythagorean theorem,

which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

In this case, the ladder acts as the hypotenuse, and we need to find the length of the vertical side (height) it reaches up the wall.

The ladder forms the hypotenuse, and its length is given as 12 meters. The distance from the foot of the ladder to the base of the wall represents one side of the triangle, which is 4.5 meters.

By substituting the given values into the Pythagorean theorem equation: (12m)^2 = h^2 + (4.5m)^2, we can solve for the unknown height 'h'.

Squaring 12m gives us 144m^2, and squaring 4.5m yields 20.25m^2. By subtracting 20.25m^2 from both sides of the equation, we isolate 'h^2'.

We then take the square root of both sides to find 'h'. The square root of 123.75m^2 is approximately 11.12m.

Therefore, the ladder reaches a height of approximately 11.12 meters up the wall.

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Step-by-step explanation:

2 3/4 gallons in 3 2/3 minutes

equal to :

11/4 ÷ 11/3 =

11/4 × 3/11 =

3/4 gallons per minutes

or

0.75 gpm

Speed

The 90% confidence interval for the true mean weight of the gray squirrels is 467.51 g and 492.49 g.

The confidence Interval = sample mean ± z * standard deviation / √N

Based on the given data:

sample mean = 480 g

standard deviation = 70 g

N is the number of samples = 85

z at 90% confidence level = 1.645

The confidence interval = 480 ± 1.645 * 70 / √85

The confidence interval = 480 ± 12.49

The 90% confidence interval = 467.51 g and 492.49 g

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The expression 163.28 + 75.459 is a sum expression, and the result of 163.28 + 75.459 is 238.739

The expression is given as:

163.28 + 75.459

The expression is best solved using a calculator.

However, in the absence of a calculator, the following steps can be applied.

Expand each term

163.28 + 75.459 = 163 + 0.28 + 75 + 0.459

Reorder the terms

163.28 + 75.459 = 163 + 75+ 0.28  + 0.459

Add the decimals and integers

163.28 + 75.459 = 238.739

Hence, the result of 163.28 + 75.459 is 238.739

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M = 270,000 * (0.5833% * (1 + 0.5833%)^240) / ((1 + 0.5833%)^240 - 1).  Calculating this equation will give us the monthly mortgage payment for Abigail and Curtis Siebert.

Abigail and Curtis Siebert have a $270,000 mortgage at an interest rate of 7% for a term of 20 years.

To calculate the monthly mortgage payment, we can use the formula for an amortizing mortgage:

M = P * (r * (1 + r)^n) / ((1 + r)^n - 1),

where M is the monthly mortgage payment, P is the principal amount (loan amount), r is the monthly interest rate, and n is the total number of monthly payments.

First, we need to convert the annual interest rate to a monthly interest rate. Since there are 12 months in a year, the monthly interest rate is 7% divided by 12, which is approximately 0.5833%.

The total number of monthly payments is the term of the mortgage multiplied by 12. In this case, it's 20 years * 12 months, which equals 240 months.

Now, we can substitute the values into the formula:

M = 270,000 * (0.5833% * (1 + 0.5833%)^240) / ((1 + 0.5833%)^240 - 1).

Calculating this equation will give us the monthly mortgage payment for Abigail and Curtis Siebert.

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Answer:

3072

Step-by-step explanation: you just need to multiply .32 by 9600.

Answer:

4( x+6) (x-1)

Step-by-step explanation:

4x^2+20x-24

Factor out the greatest common factor

4(x^2 +5x-6)

What 2 numbers multiply to -6 and add to 5

6*-1 = -6

6+-1 = 5

4( x+6) (x-1)

Answer:

\(4(x-1)(x+6)\)

Step-by-step explanation:

→Take out the GCF (Greatest Common Factor), which is 4:

\(4x^2+20x-24\)

\(4(x^2+5x-6)\)

→Split the middle term into two numbers that can be added to get 5 and multiplied to get 6:

\(4(x-1)(x+6)\)