How much work is done when an 18 N force moves a block 6m?

Answer:

Explanation: We need to calculate the average force needed to change the velocity of the ball from 20m/s ( forward ) to -40m/s ( Backwards ), the equations used are as follows:

Here, in the (1) and (2) the unknows and knowns are as follows:

Plugging in the knowns in the (2) the acceleration is calculated as follows, and subsequently the force as well:

Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

It consists of a bulb containing mercury attached to a glass tube of narrow diameter, the volume of mercury in the tube is much less than the volume in the bulb. The space above the mercury may be filled with nitrogen gas or it may be at less than atmospheric pressure, a partial vacuum.

Answer:

mass and distance

Explanation:

dont need to summary this

Answer:

B. mass and distance

Explanation:

Answer:

headlight of vehicles use less energy and gives light to very limited area hence electricity can be conserved by doing this

\(\large\boxed{Formula: I= \frac{Q}{t}}\)

Let's solve!

The formula is given above.

Let's substitute the values according to the formula.

We'll have to divide the measure of charge by the given time.

\(I= \frac{40}{10}\)

Final answer:

\(\large\boxed{= 4 \: Amps \: (A)}\)

Hence, the current is 4 amps.

Answer:

Granite

Explanation:

Trust me I learned this 2years ago

Answer:

 ΔV = -2.1 L

Explanation:

To solve this exercise we can use the ideal gas equation for two points

         PV = nRT

          P₁V₁ = P₂ V₂

where point 1 is on the surface and point 2 is at the desired depth,

          V₂ = \(\frac{P_1}{P_2} \ V_1\)

let's calculate

           V₂ = ( \(\frac{1 atm}{2.5 atm}\) ) 3.5 L

            V₂ = 1.4 L

this is the new volume, the change in volume is

          ΔV = V₂ -V₁

          ΔV = 1.4-3.5

          ΔV = -2.1 L

Answer:

overtone- one over the first

n skips by twos

4 antinodes

500 Hz

Explanation: Hope this helps :)

Answer:

18 m/s

Explanation:

Range of a projectile on level ground is:

R = v₀² sin(2θ) / g

14.3 m = v₀² sin(2×13°) / 9.8 m/s²

v₀ = 17.9 m/s

Rounded to two significant figures, the launch speed was 18 m/s.

If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.

Given:

The initial shot was fired at an angle of 50 degrees above ground.

The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.

Let the angle of the projectile is x,

The horizontal component of velocity can be calculated as follows:

\(v(x) = v * cos(x)\)

We can write:

since the horizontal part of velocity remains constant:

\(v(x1) = v(x2)\)

\(cos(50) = cos(x)\)

\(50 = x\)

Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.

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The correct response is given when the angle is asked a question.

Answer:

Below

Explanation:

Adding salt to the water will make it CONDUCTIVE and the bulb will then have a complete circuit and possibly glow

Steven sets up an experiment as per the diagram and the bulb is not glowing, so he should mix a few teaspoons of salt into the water. Hence, option B is correct.

Charged material experiences a force when exposed to an electromagnetic field because of the fundamental characteristic of electric charge. It's conceivable for electrical ions to be positive or negative. Two charges that are opposed to one another repel one another.

An object with no net charge is said to be "neutral." Classical electrodynamics refers to the older theory of how charged particles interact, and it is still valid for problems that do not necessitate accounting for quantum phenomena.

The net charge of an isolated system, which is the total of the negative and positive charges, cannot change since electrical current is a conserved property. Electric charge is carried by subatomic particles.

The bulb is not glowing because the conduction of electricity does not take place through pure water, so he needs to put some teaspoons of salt into the water due to which the conduction of electric will take place and the bulb be glowed.

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Answer:

\(a=1.96m/s^2\)

Explanation:

From the question we are told that

Mass of cart =20kg

Mass of block =5kg

Magnitude of acceleration M_a= 5 kg

Generally Force on the 20kg mass in the \(\bar X\) is mathematically given as

\(\sum F=ma\\t=(20kg)a\)

Generally Force on the 2kg in the\(\bar Y\) mass is mathematically given as

\(\sum F=ma\\(5kg)(9.8m/s^2)-(5kg)a\)

Therefore

\((20kg)a=(5kg)(9.8m/s^2)-(5kg)a\)

\(a=\frac{5kg)(9.8m/s^2)-(5kg)}{25}\)

\(a=1.96m/s^2\)

Answer:

Assumption: there is no object between this point charge and the observer.

Explanation:

The electric field of a point charge is inversely proportional to the square of the distance from that point charge.

Let \(k\) denote Coulomb's constant (\(k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}\).) Let the magnitude of that point charge be \(q\). At a distance of \(r\) from this charge, the electric field due to this charge would be:

\(\displaystyle E = \frac{k \cdot q}{r^{2}}\).

Convert the magnitude of the point charge in this question to standard units:

\(q = 1\; \rm nC = 10^{-9}\; \rm C\).

Apply that equation to find the magnitude of the electric field due to this point charge:

\(r = 1\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 2\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}\).

\(r = 3\; \rm m\):

\(\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}\).

The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.

Because the \((+1\; \rm nC)\) point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this \((+1\; \rm nC)\!\) point charge at any point in the field would point away from this charge.

Answer: A. frequency

Explanation:

If it’s not wavelength then it has to be frequency

Answer:

Explanation:

Power in the circuit must balance

Voltages about any loop must add to zero

Current through any node must add to zero

p1 has 5V and 8 Amps leaving the + terminal

This means that (5)(8) = 40 W is being supplied by p1 ergo -40W

p2 has 2V and 8 amps entering the + terminal

2(8) = 16 W absorbed by p2

p4 has 3V and 5 amps entering the + terminal

3(5) = 15 W absorbed by p4

Balance of power shows that p3 must absorb

15 + 16 + P3 - 40 = 0

P3 = 9 W absorbed

Answer:

\(\Delta T=38.95^{\circ} C\)

Explanation:

Given that,

Heat measured, Q = 81500 J

Mass of water, m = 0.5 kg

The specific heat of water is 4,184 J/kg °C

We need to find the change in temperature. The heat measured is given by :

\(Q=mc\Delta T\)

Where

\(\Delta T\) is the change in temperature

\(\Delat T=\dfrac{Q}{mc}\\\\\Delat T=\dfrac{81500}{0.5\times 4184 }\\\\\Delta T=38.95^{\circ} C\)

So, the change in temperature is \(38.95^{\circ} C\).

Reflection of light is when light waves bounce off a surface.

Reflection occurs when light traveling through one material bounces off a different material. The reflected light continues to travel in a straight line, but in a different direction.

The incident light ray that land on the surface is called the reflected off the surface while the ray that bounces back is called the reflected ray.

For example, if an individual looks at a bird, light has reflected off that bird and traveled in nearly all directions. If some of that light enters the individual's eyes, it hits the retina at the back of the eyes. An electrical signal is passed to the person's brain, and the brain interprets the signals as an image.

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Answer:

C. Table

A organized collection of records is called a database table. The main key that uniquely identifies each row in the table. Since no two rows may have the same instantaneous value thanks to a unique key, it is simple to choose a row by its main key. A table can also contain several columns, each of which can hold a distinct kind of data. The information stored is verified using the column name and data type.  

The table name is the linguistic component of a database table. It can represent expressions or variable items, and it must be typed exactly. Square brackets denote a need for the item, whereas curly braces denote an optional element. An alternate choice is indicated by a vertical bar. A main key is a single field, and a secondary key might be a combination of many fields. This kind of information is crucial.

Any field in the data table can be referenced by the secondary key. A database's data field may be a string, a number, a date, or a time. A table's first field should always be the main key, followed by any foreign keys. Actual data should never be present in a primary key. Since the immediate key value is derived from external sources, it is crucial to use it properly. Otherwise, data input mistakes may occur.

The information kept in the database table is referred to as a secondary key. This kind is a primary key, which implies it is a secondary key. A primary key can be used as an alternate key to distinguish between different records in a table and to uniquely identify a record inside a database. Multiple fields that can be either main or alternative make up a composite key.

Depending on the type of data being stored and its intended use, a database table may have a single row or several. The main key determines the number of rows, which might be 50 or more. A secondary key can be used to establish connections between various tables and to distinguish between various data types in a database. A data table also includes a secondary key, which is essential for data retrieval and is separate from the primary key.

You can have local or global database tables. The two types of tables differ in terms of names, availability, and visibility. A global table is accessible to all users and may be utilized by any other user, while a local table is only visible to the present user. It is distinct from a typical table and requires more effort to build than a straightforward one does. Its main function is to maintain a database and store data.

Rows in a database table can be of any size. A table's rows can include any number of columns. A database table's rows can be arranged in any way. The number of rows on a data page might range from one to thousands. Each row may consist of a clustered index, a row, or both. A list of columns may also be present in a row. A clustered index can only contain information in a particular sequence.

A table can be set up in  two different ways. The information-containing row of data is its main key. The data column that contains the values for a row is known as a secondary key. A database that employs rows is the third form of table. Multiple primary keys are possible for a data row, and a secondary key is a secondary key that refers to a row column. A database will have a foreign key if it is formed with a single primary key.

There is no limit to the amount of rows and columns in a database table. Up to 1,024 rows are allowed in a typical user-defined table. The server's storage capacity determines how many rows can fit in a database table. A table can have characteristics added to it in addition to the column and row. A restriction can stop a row from having empty fields. The connection between two tables can be established via an important control.

Answer:

A.

Explanation:

Im in 10th grade so i just know this stuff

Answer:

a. 1.56 × 10¹⁸ electrons per second

b. The electrons in wire 3 flow into the junction.

Explanation:

Here is the complete question

Three wires meet at a junction. Wire 1 has a current of 0.40 A into the junction. The current of wire 2 is 0.65 A out of the junction. (a) How many electrons per second move past a point in wire 3? (b) In which direction do the electrons move in wire 3 -- into or out of the junction?

Solution

(a) How many electrons per second move past a point in wire 3?

Using Kirchhoff's current law, at the junction, i₁ + i₂ + i₃ = 0 where i₁ = current in wire 1 = 0.40 A, i₂ = current in wire 2 = 0.65 A and  i₃ = = current in wire 3,

So, i₃ = -(i₁ + i₂)

taking current flowing into the junction as positive and those leaving as negative, i₁ = + 0.40 A and i₂ = -0.65 A

So, i₃ = -(i₁ + i₂)

i₃ = -(0.40 A + (-0.65 A))

i₃ = -(0.40 A - 0.65 A)

i₃ = -(-0.25 A)

i₃ = 0.25 A

Since i₃ = 0.25 C/s and we have e = 1.602 × 10⁻¹⁹ C per electron, then the number of electrons flowing in wire 3 per second is i₃/e = 0.25 C/s ÷ 1.602 × 10⁻¹⁹ C per electron = 0.1561  × 10¹⁹ electrons per second = 1.561  × 10¹⁸ electrons per second ≅ 1.56 × 10¹⁸ electrons per second

(b) In which direction do the electrons move -- into or out of the junction?

Given that i₃ = + 0.25 A and that positive flows into the junction, thus, the electrons in wire 3 flow into the junction.

Answer:

Answer:  YES

Explanation: The main difference between flood and tsunami  is that the flood is overflow of water that submerges land and tsunami is a series of water waves caused by the displacement by large volume of a volume of water

Answer:

WEEEEEEEEEEEEEEEEEEEEEEEEE

Explanation:

a) The value of t u = 140/t`b.

b) The y position of the cannonball at the time t is  55.5 mc.

c) The initial speed of the projectile is 52.4 m/s.

Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.

a. To find the value of t:Here, we have to use the formula of distance

i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`

Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is

(2H) = 2 × 55.5

= 111 m`2H/g

= 111/9.8`

= 11.32653 s

From equation (1),u×t = 140u = 140/t

Therefore, `u = 140/t`b.

b)To find the y position of the cannonball at the time t:

Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,

Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².

We have already calculated the time taken by the cannonball to hit the ground in the previous step.`

y = 140 - (1/2) × 9.8 × t²`

On substituting the value of t as `t = 11.32653`,

we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.

c)  To find the initial speed of the projectile:

To calculate the initial speed of the projectile, we need to use the formula of range of projectile

.i.e.,R = u²sin2θ/g

Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)

u² = R × g/sin2θ

   = 140 × 9.8/sin0°  

   = 2744m²/s²u  

   = \(\sqrt(2744m^2/s^2)\)

   = 52.4 m/s

Hence, the initial speed of the projectile is 52.4 m/s.

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The expression "velocity as a function of time" refers to the change in an object's velocity over time, which can be observed by graphing the velocity against time on a graph.

Speed and time are related in the first equation of motion. V = u + at represents the first motion equation. Here, u denotes the starting velocity, a the acceleration, and t the duration, whereas v denotes the end velocity. The derivative of x with respect to time, or v(t)=ddtx, represents the instantaneous velocity of an object. It is the limit of average velocity as the time approaches zero (t). V (t) equals d d t x (t). Instantaneous velocity has a dimension of length per time, just like average velocity does.

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Answer:

4.9 km

Explanation:

\(\sqrt{4.2^2+2.6^2}=4.9 km\)

Answer:

B. 2.5

not 2.5m because IMA is unitless.

The identical mechanical advantage of the inclined plane is 2.5.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Length of the inclined plane; d = 5 m.

Height of the inclined plane; h = 2 m.

So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane

= 5 m/2 m

= 2.5.

Hence, the  identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.

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Answer:

.0000004

Explanation:

The mass of a brick with a volume of 0.0006 m³ and a density of 1600 kg/m³ is 0.96kg.

The mass of a substance can be calculated by multiplying the density of the substance by its volume. That is;

Mass = density × volume

According to this question, the density of brick is 1,600 kg/m3 and it has a volume of 0.0006m³. The mass is calculated as follows:

Mass = 0.0006 × 1600

Mass = 0.96kg

Therefore, the mass of a brick with a volume of 0.0006m³ and a density of 1600 kg/m³ is 0.96kg.

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